Draw the net force arrow on the diagram and state the direction. Net force direction​

The balanced chemical equation for this reaction is:

HCl + NaOH = NaCl + H2O

1.46 g of HCl is equal to 0.0400 moles of HCl. (1.46/36.458). (36.485 being the molar mass of HCl in grams/mole).

2.9 g of NaOH is equal to 0.0725 moles of NaOH. (2.9/39.997). (39.997 being the molar mass of NaOH in grams/mole).

- From the reaction we can infer that it takes one mole of HCl and one mole of NaOH to form one mole of water. Therefore the limiting reactant in this case will simply be the one that we have the least amount of. So HCl is the limiting reactant.

- As stated previously, it takes one mole of HCl to produce one mole of H2O so that would mean that 0.0400 moles of HCl would produce 0.0400 moles of H2O.

0.0400*18.01 (18.01 being the molar mass of water in grams/mole) will give you the grams of H2O produced in this reaction.

Answer: 0.720 grams of H2O

The pressure at which balloon bursts is 3.07 psi , when expands and bursts after ascending until the temperature is -35 degree celsius.

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Atom A will have a greater share of electrons and will have a slight negative charge according to Polar Covalent bond

What is Polar Covalent Bond ?
A specific type of covalent link is known as a polar bond. It is also the point at which an ionic bond and a pure covalent bond begin to form, according to another definition. A polar covalent bond, on the other hand, is a link that exists between two atoms and is made up of electrons that are scattered unevenly if we want to define it more precisely. The molecules have a tendency to have an electrical dipole moment in which the two ends are slightly positive or negative as a result of this state.

The many forms of covalent bonding are mostly determined by the electronegativity of the material. The propensity of an atom to draw a shared pair of electrons to itself is known as electronegativity. It is a trend and has no units. Polar covalent bonds are those created between two atoms in molecules with an electronegative difference.

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The concentration of the 27.7 mL H₃PO₄ solution is 0.323 M

We'll begin by writing the balanced equation for the reaction. This is given below:

H₃PO₄ + 3NaOH —> Na₃PO₄ + 3H₂O

From the balanced equation above, we obatined:

CaVa / CbVb = nA / nB

(Ca × 27.7) / (0.609 × 44.1) = 1 / 3

(Ca × 27.7) / 26.8569 = 1 / 3

Cross multiply

Ca × 27.7 × 3 = 26.8569

Ca × 83.1 = 26.8569

Divide both side by 83.1

Ca = 26.8569 / 83.1

Ca = 0.323 M

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Answer:

Al2S3

Explanation:

Al2S3 has ions which have a higher magnitude of charge compared to BeCl2. This higher charge creates stronger attractive forces between molecules, holding them together even at high temperatures. Another simple way to compare the melting points is to multiply the charges of the ions together and compare those values. BeCl2 would be 2*1 because of Be2+ and Cl (1)-. Al2S3 would be 2*3 because of S2- and Al3+. Since 2*3 is more than 2*1, Al2S3 has a higher melting point. I think this is a repeat question

The temperature raised is 11.9 degrees as the heat capacity is 340J

What is heat capacity ?

Heat Capacity is the quantity of energy needed to raise a substance's temperature by one degree Celsius. It can also be thought of as the proportion of energy transmitted to an item to the rise in temperature that follows.

The heat capacity measurement is in Joules per degree Celsius as well. Because it is based on the object's mass. Additionally, it is frequently stated in terms of 100 grammes in order to facilitate comparisons between objects of similar mass.

Q = m*c*T

Q = heat energy

m = mass of substance

c = specific heat capacity

T = temperature

Q = 6.8*4.2*T

T = 340/6.8*4.2

T =11.90 celsius

The temperature raised is 11.9 degrees as the heat capacity is 340J

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40.4417g of PbS is formed from 55.11g of Pb(C2H3O2)2 and excess amount of H2S .

Given,

balanced chemical equation is ,

Pb(C2H3O2)2 (s) + H2S (g) ⇒ PbS (s) + HC2H3O2 (g)

to making the chemical equation balanced , we have to make sure that all the molecules on the left hand side and in the right hand side should be equal .

thus to making it equal 1st see that the number of carbon , oxygen and hydrogen is doubled in the left side than that of right side .

so we have to multiply HC2H302 by 2 .

Pb(C2H3O2)2 (s) +H2S(g) ⇒ PbS(s) + 2 HC2H3O2 (g)

so now the given chemical equation is balanced that we can say , 1 mol of       Pb(C2H3O2)2 produces 1 mol of PbS .

It is given that , we can take H2S is in excess means the Pb(C2H3O2 )2 acts as limiting agent .

We know , molecular mass of Pb(C2H3O2)2 is 325.29g

325.29g contains 1mole

55.11g contains 55.11/325.29 = 0.169 moles

thus ,the mole of PbS formed from 55.11g of Pb(C2H3O2)2 is 0.169moles.

We know ,

molecular mass of PbS is 239.3g

1mole of PbS is 239.3g

0.169moles pf PbS is 239.3×0.169 = 40.4417 g

Hence , 40.4417g of PbS is formed from 55.11g of Pb(C2H3O2)2 and excess amount of H2S .

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The following  reactions is balanced and shows complete combustion are

A)2C₅H₁₂   +   11O₂  ----->   10CO  +   12H₂O

D) C₅H₁₂   +   8O₂  ----->   5CO₂  +   6H₂O

A) 2C₅H₁₂   +   11O₂  ----->   10CO  +   12H₂O

In this reaction,

              Reactants                 products

C                   10                            10

H                   24                           24

O                   22                           22

Reactants and products have same no. of atoms .

therefore this reaction is balanced and shows complete combustion.

B) 2C₅H₁₂   +   11O₂  ----->   12CO  +   10H₂O

                  Reactants             Products

C                        10                        12

H                         24                      20

O                         22                      22

this reaction is not balanced.

C) C₅H₁₂   +   8O₂  ----->   6CO₂  +   5H₂O

                   Reactants             Products

C                         5                             6

H                         12                            10

O                         16                            18

This reaction is not balanced,

D) C₅H₁₂   +   8O₂  ----->   5CO₂  +   6H₂O

                     Reactants             Products

C                           5                          5

H                           12                         12

O                           16                           16

Reactants and products have same no. of atoms .

therefore this reaction is balanced and shows complete combustion.

Thus, The following  reactions is balanced and shows complete combustion are

A)2C₅H₁₂   +   11O₂  ----->   10CO  +   12H₂O

B) C₅H₁₂   +   8O₂  ----->   5CO₂  +   6H₂O

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Answer:

D

Explanation:

I got the answer right

Answer:

400CaO and 0g C02

Explanation: 400 has more moiul

The reaction they give us is balanced. We must determine the moles of aluminum that are equivalent to that 45 g, for this, we will use the molar mass of aluminum equal to 26.98g/mol

Now, in the reaction, we can see that for every 2 moles of aluminum, 1 mole of aluminum sulfate is produced. We can also use the molar mass of aluminum sulfate (101.96g/mol) to calculate the grams of aluminum sulfide produced.

The grams of aluminum sulfate produced is 85g

The percent yield is calculated with the next equation:

Percent yield=134%

This is not experimentally possible

The number of the moles of the P₂H₄ is equal to 1.734 moles, which will generate 1.76×10²³ molecules of P₄.

The equation in which the total mass of substances on the reactant side is equal to the total mass of substances on the product side is known as a balanced chemical equation.

The law of conservation of mass must obey by a balanced chemical equation. The given balanced chemical reaction of the reaction of P₂H₄ is :

6 P₂H₄  → 8 PH₃  +   P₄

The number of molecules of the phosphorous  P₄ formed = 1.76 × 10²³

The number of moles of  P₄ = 1.76 × 10²³/(6.022 × 10²³) = 0.292 mol

One of the phosphorous P₄ is formed from  P₂H₄ = 6 mol

Then  0.292 mol of P₄ will form from  P₂H₄ = 6× 0.292 = 1.734 mol

Therefore, the 1.734 moles of P₄ are required to form 1.76×10²³ molecules of P₂H₄.

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When a potent acid, like hydrochloric acid, HCl, is combined with a potent base, such sodium hydroxide, NaOH, the result can be complete neutralization. Strong bases and acids dissociate entirely into their individual ions when they dissolve in water.

An element's valency is its capacity for combination. The periodic table groups have identical elements with the same valency.. How many electrons make up the outer shell of an element determines its valency. The group number.

Valency is simply the amount of electrons that an element's atom gains, loses, or shares to obtain the closest configuration to that of a noble gas. The valency of sodium (Na), magnesium (Mg), chlorine (Cl), and other elements, for instance, is 1.

When there are equal moles of strong acid and strong base, the strong acid and strong base completely neutralize one another. An aqueous solution with a pH of 7 is the end product.

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Answer:

I believe it is the last choice

Explanation:

Isotopes of a certain element must have the same atomic number(the # of protons). This is what differentiates the different elements. However, isotopes could have varying amounts of neutrons, therefore the atomic mass could vary as well.

hope this helps :)

please crown me brainliest!!!

All matter possesses the fundamental property of inertia, which can be quantified by mass. In essence, it's the resistance of a mass of matter to changing its direction or speed in reaction to the application of a force. A body's ability to resist change from applied forces increases with its bulk.

A three-dimensional space's volume can be calculated. Various imperial units or SI-derived units are routinely used to quantify it numerically. The link between length and volume is reciprocal.

The density of a substance is its mass per unit of volume. Density's sign - ρ, although it can alternatively be represented as the Latin letter D, is most usually written as. Density can be mathematically defined by dividing mass by volume.

Mass = Density * Volume

Mass = 2 * 120

Mass = 240g

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The number of moles of NO₂ formed when 10.2 moles of NO₃ reacts is 20.4moles.

According to this question, nitrogen IV oxide (NO₂) reacts with nitrogen II oxide (NO) to form nitrogen VI oxide (NO₃) as follows:

NO₃ + NO → 2NO₂

The number of moles of either the reactants or the products can be calculated stoichiometrically as follows:

Based on the above chemical equation, 1 moles of NO₃ reacts to form 2 moles of NO₂.

This means that if 10.2 moles of NO₃ reacts, 10.2 × 2 = 20.4 moles of NO2 will be produced.

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The molecule described below is known as :

2-pentene.

In the diagram below:

As a result, the compound is 2 pentene.

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First, we need to figure the reaction out.

Both reactants are ionic compounds, so their reaction is probably a double displacemente reaction.

The Cl has a charge of 1-, so Fe has a charge of 2+. Na has a charge of +1 and PO₄ has a charge of 3-.

To combine Fe²⁺ with PO₄³⁻, we will need 3 Fe²⁺ and 2 PO₄³⁻, so the compound becomes neutral.

Both Na and Cl have single charge, so their combination is simply 1 Na and 1 Cl.

So, the products are Fe₃(PO₄)₂ and NaCl, so the unbalanced reaction is:

To balance it, We can start by putting a coefficient of 2 on Na₃PO₄, so we have two PO₄³⁻ anions on both sides:

Now, we put a coefficient of 3 on FeCl₂ and 6 on NaCl to get the balanced equation:

Now, we first need to calculate the number of moles of each reactant, using their molar masses:

So:

Now, if the coefficient of FeCl₂ is 3, for each 3 FeCl₂ that reacts, one reaction occurs, so the number of reactions that will need to occur to consume all its number of moles is that amount over 3:

Similarly, we get the number of reactions that would occur if all Na₃PO₄ reacts by dividing its number of moles by its coefficient, that is 2:

This means that the amount we have of FeCl₂ is enough for only about 0.0605 mol of reactions while the amount we have of Na₃PO₄ is enought for about 0.1250 mol of reactions, which is more than the other reactant.

This means that the reactant that limits the amount of reaction that can occur is FeCl₂, so the limiting reactant is FeCl₂.

Answer:

1.06

Explanation:

One mole of nitrogen is 14.009, or the mass number and you divide 14.9 by 14.009 and get 1.06 for the amount of moles

Answer:

1.063753837 mol

Explanation:

14.9 * (1/14.007) = 1.063753837

Original grams * (1 mol/atomic weight of nitrogen) = 1.063753837

System and surroundings:

A system is defined as a matter or region on which analysis is done. The system is separated from the surroundings by the boundary. Everything external to the system is surrounding.

Specific heat function:

The amount of heat that must be added to one unit of mass of the substance in order to cause an increase of one unit in temperature.

Enthalpy changes:

We could say that it is equal to the difference between the energy used to break bonds in a chemical reaction and the energy gained by the formation of new chemical bonds in the reaction.

Standard enthalpy of formation: ​

It is a measure of the energy released or consumed when one mole of a substance is created under conditions from its pure elements.

The definition of density is the mass of a substance per unit of volume. The Latin letter D may also be used, however the symbol is most usually employed to denote density. Mass divided by volume gives the density value:

D = m/v

   = 250/300

   = 0.833 g/ml

A physical body's mass is its overall amount of matter. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured using this phrase. The strength of a body's gravitational pull on other bodies depends on its mass. The kilogram serves as the foundational mass unit in the SI.

The amount of three-dimensional space that is occupied is measured in volume. Imperial or SI-derived units are frequently used in its mathematical expression. The concepts of volume and length are related.

Typically, there are two forms of density: absolute density and relative density. Relative density, also known as specific gravity, is the ratio of a substance's density to the density of a reference material. Water is frequently used as the reference material.

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The limiting reactant is lead(II) acetate the theoretical yield is 1.1909 g and the percent yield is 83.71 %.

The amount of the sample in a specific solution volume is known as its molarity (M). The molarity of a solute per liter of the a solution is known as molar ratio. The molar concentration in a solution is another name for molarity.

Molarity

= moles of solute/volume of the solution

or Moles

= Molarity * volume of solution

For potassium sulfate :

Molarity = 0.116 M

Volume = 56.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 56.0×10⁻³ L

Thus, moles of potassium sulfate:

Moles = 0.116 M * 56.0 * 10-3 moles

Moles of potassium sulfate  = 0.006496 moles

For lead(II) acetate :

Molarity = 0.102 M

Volume = 38.5 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 38.5×10⁻³ L

Thus, moles of lead(II) acetate :

Moles = 0.102 * 38.5 *10-3 moles

Moles of lead(II) acetate  = 0.003927 moles

According to the given reaction:

[tex]$\mathrm{K}_2 \mathrm{SO}_{4(a q)}+\mathrm{Pb}\left(\mathrm{C}_2 \mathrm{H}_3 \mathrm{O}_2\right)_{2(a q)} \rightarrow 2 \mathrm{KC}_2 \mathrm{H}_3 \mathrm{O}_{2(s)}+\mathrm{PbSO}_{4(a q)}$[/tex]

1 mole of potassium sulfate react with 1 mole of lead(II) acetate

0.006496 moles potassium sulfate react with 0.006496 mole of lead(II) acetate

Moles of lead(II) acetate = 0.003927 moles

Lead(II) acetate is limiting reagent. ( 0.003927 < 0.006496)

0.003927 mole of lead(II) acetate gives 0.003927 mole of lead(II) sulfate

Molar mass of lead(II) sulfate = 303.26 g/mol

Mass of lead(II) sulfate = Moles × Molar mass = 0.003927 × 303.26 g = 1.1909 g

Theoretical yield = 1.1909 g

Given experimental yield = 0.997 g

% yield = (Experimental yield / Theoretical yield) × 100 = (0.997/1.1909 g) × 100 = 83.71 %

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The number of nickel atoms that would be laid side by side to span a distance of 2.65 mm is 1.06 x 10⁷ atoms of nickel.

The diameter of the nickel atom is the line that divides the nickel atom into two equal halves. The diameter of an object is always double of the radius when the radius of the atom is known.

The diameter of the nickel atom is calculated as follows;

d = 2r

where;

d = 2 x 125 pm

d = 250 pm

d = 2.5 x 10⁻¹⁰ m

The number of nickel atoms that would be laid side by side to span a distance of 2.65 mm is calculated as follows;

n(2.5 x 10⁻¹⁰ m) = 2.65 mm

n(2.5 x 10⁻¹⁰ m) = 2.65 x 10⁻³ m

n = (2.65 x 10⁻³) / (2.5 x 10⁻¹⁰)

n = 1.06 x 10⁷ atoms of nickel

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INFORMATION:

We have the neutralization of a weak base and a strong acid, and we must determine what should be the product of the reaction

STEP BY STEP EXPLANATION:

To determine it, we need to know that:

- The neutralization of a strong acid and strong base has a pH equal to 7. The neutralization of a strong acid and weak base will have a pH of less than 7, and conversely, the resulting pH when a strong base neutralizes a weak acid will be greater than 7.

In our case, we have the neutralization of a weak base and a strong acid, so our product would have a pH of less than 7. Then, knowing that a pH less than 7 represents an acidic, we can state that the product of the reaction will be an acidic.

A strong acid and a weak base yield a weakly acidic solution, not because of the strong acid involved, but because of the conjugate acid of the weak base.

ANSWER:

d. acidic

If 2.2 mol Xe and 2.0 mol [tex]F_2[/tex] reacts to produce 0.25 mol [tex]XeF_4[/tex], the percent yield of the experiment will be 25%.

The percent yield of an experiment is the amount of the actual yield of the experiment relative to the theoretical yield of the same experiment.

Mathematically; percent yield = actual yield/theoretical yield x 100%

In the illustrated experiment, the mole ratio of Xe and  [tex]F_2[/tex]  is 1:2. With 2.2 mol Xe reacting against 2.0 mol  [tex]F_2[/tex] , it means  [tex]F_2[/tex]  is limited in availability with Xe being excessive.

The mole ratio of  [tex]F_2[/tex] and [tex]XeF_4[/tex] is 2:1. Thus, the mole of [tex]XeF_4[/tex] that should be theoretically produced would be half of the mole of [tex]F_2[/tex] that reacts.

Thus, mole of  [tex]XeF_4[/tex] = 2/1

                                   = 1

But only 0.25 mol of  [tex]XeF_4[/tex] were produced.

Percent yield = 0.25/1 x 100%

                      = 25%

The percent yield of the experiment is, therefore, a paltry 25%.

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The new pressure is .67 atm (atmospheric pressure at sea level)

What is pressure?
The force applied perpendicularly to an object's surface per unit area over which that force is distributed is known as pressure (symbol: p or P). : 445 The pressure relative to the surrounding air is known as gauge pressure, also spelled gauge pressure. Pressure is expressed using a variety of units. Some of these come from dividing a unit of force by a unit of area; the traditional unit of pressure in the imperial and U.S. customary systems is the pound-force per square inch (psi), which is equivalent to one newton per square metre (N/m²) in the SI. The atmosphere (atm), which is equal to this pressure, can also be used to describe pressure. The torr is defined as 1/760 of this.

PV = nRT
P₁V₁ = P₁V₁

P₁ = 0.92 atm

V₁ = 20.5 L

T₁ = 23.0°C

P₂ = ?

V₂ = 340.6L

T₂ = 12.0°C

P₂ = (P₁V₁/T₁)(T₂/V₂)

P₂ = .92(20.5/23)(12/340.6)

P₂ = .67 atm

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Answer: It is false

Explanation:

Answer: The correct option is ○ O₂

Explanation:

All the other options denote that they are not a single element theyare  

in compound form. Only the oxygen is in element form.

Taking into account definition of percent yield, the percent yield of the reaction if 3.35 g of N₂H₄ reacts with excess oxygen and produces 0.350 L of N₂ is 13.82%.

In first place, the balanced reaction is:

N₂H₄ + O₂ → N₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield= (actual yield÷ theoretical yield)× 100%

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

In this case, you know:

Replacing in the ideal gas law:

1 atm×0.350 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K

Solving:

n= (1 atm×0.350 L) ÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K)

n= 0.01447 moles

Finally, the actual yield of N₂ is 0.01447 moles.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of N₂H₄ form 1 mole of N₂, 3.35 grams of N₂H₄ form how many moles of N₂?

moles of N₂= (3.35 grams of N₂H₄× 1 moles of N₂)÷ 32 grams of N₂H₄

moles of N₂= 0.1047 moles

Finally, the theoretical yield of N₂ is 0.1047 moles.

In this case, you know:

Replacing in the definition of percent yield:

percent yield= (actual yield÷ theoretical yield)× 100%

Solving:

percent yield= (0.01447 moles÷ 0.1047 moles)× 100%

percent yield= 13.82%

Finally, the percent yield for the reaction is 13.82%.

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Based on the balanced chemical equation, the volume of 0.250 M  K₂S₂O₃ (aq) needed to completely react with 37.32 mL of 0.125 M KI₃ (aq) is 37.32 mL.

The reaction between K₂S₂O₃ (aq) and KI₃ (aq) is a redox reaction.

The balanced chemical equation of the reaction is given as follows:

2 S₂O₃²⁻ (aq) + I₃⁻ (aq) ---> S₄O₆²⁻ (aq) + 3 I⁻ (aq)

Based on the balanced equation of the reaction:

2 moles of K₂S₂O₃ (aq) are required to react with one mole KI₃ (aq).

Moles of KI₃ (aq) in  37.32 mL of 0.125 M solution;

Moles of  KI₃ (aq) = 37.32 * 0.125 M

Moles of  KI₃ (aq) = 4.665 mmoles

Moles of K₂S₂O₃ (aq) required = 2 *  4.665 mmoles

Moles of K₂S₂O₃ (aq) required = 9.33 mmoles

Volume of K₂S₂O₃ (aq) required =moles / molarity

The volume of K₂S₂O₃ (aq) required = 9.33 / 0.25

The volume of K₂S₂O₃ (aq) required = 37.32 mL

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Answer:

Demonstrative evidence