Number of moles of water originally present in the compound is 0.060 mol
Mole is the SI unit of amount of substance of a specified elementary entity
Here given reaction is
CuSO₄ ⋅ 5H₂O → CuSO₄ + 5H₂O
And given data is CuSO₄ = 9.60 g
So we have to find number of mole of water originally present in the compound = ?
So number of mole = mass of substance/mass of one mole
Number of mole = 9.60 g/159.6
Number of mole = 0.060 mol
Water originally present in the compound is 0.060 mol
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8. You are on in-line skates at the top of a small hill. Your potential energy is equal to
The last time you checked, your mass was 60.0 kg.
a. What is the height of the hill?
b. If you start rolling down this hill, your potential energy will be converted to kinetic
energy. At the bottom of the hill, your kinetic energy will be equal to your potential
energy at the top. Calculate your speed at the bottom of the hill.
The hill is 1.7 metres high (Approx.)
Knowing that;
Energy potential = 1000 J
Weight = 60 kg
mgh = potential energy
1,000 = [60][9.8][h]
h = 1.7 m
At the peak of its climb, how much potential energy does the ball still have?The whole amount of energy will be in the form of potential energy since the ball's kinetic energy will be equal to zero. As a result, when the ball reaches the peak of its climb, its potential energy will be 450 J. As a result, the ball will soar as high as 45.91 metres.
An enormous amount of potential or stored energy exists in a rock that is at rest on a hill. The boulder's potential energy transforms into kinetic energy, the energy of motion, when it falls.
The automobile drives faster as it goes down the hill, which results in an increase in kinetic energy and a decrease in potential energy.
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which 5 systems help u change from a child to a adult
The five systems that helps us grow from a child to adult are excretory, integumentary, digestive, respiratory and cardiovascular system.
What are body systems?The body systems are the combination two or more systems located in the body that helps in the maintenance of hemostasis of the body.
Examples of body systems include the following:
Excretory system: This is the system that contains organs that helps in the removal of metabolic wastes from the body.The integumentary system: This is the system that protects the delicate internal organs of the body.The digestive system: This is the system that helps in the breaking down of food substances for body use.The respiratory system: This is the system that helps in the oxygenation of blood.The cardiovascular system: This is the system that helps in the pumping of blood throughout the body.Learn more about body systems here:
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Using an id reader to check ids can make it easier to
Display data associated with the ID such as age and other information.
Glassy unfocused eyes slow speech and movement or difficulty with small motor skills indicate a slow reaction. State ID cards, passports military ID cards, and driver's licenses are acceptable forms of ID in most states. Permanent Resident Cards may be accepted in some areas, but check with your administrator.
When a liquor store has carefully examined the identity of a customer before serving alcoholic beverages and reached a reasonable conclusion. Even if it turns out to be a fake ID and the appearance of the minor suggests the minor may be over the age of 21 or doing things she normally wouldn't. It is legally permissible even if it suggests that it is sexual. This can be a behavioral sign of addiction. Delayed reaction time Your body reacts and acts slower.
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When subjected to heat and pressure, a chemical sedimentary rock can be changed into which rock type?
Responses
foliated igneous rock
clastic sedimentary,
metamorphic
non-foliated igneous
Methane CH_4 is a simple organic molecule that is used as a fuel—it is the major component of natural gas. The bottom of the ocean contains large amounts of methane hydrate (also called methane ice or methane clathrate), enough that it has been suggested as a major source of fuel. The methane hydrate contains 6 moles water for each mole of methane.
What percentage of methane hydrate is methane? =
What percentage is water?=
The percentage of methane is 12.9% and percentage of water is 87.09% in methyl hydrate.
It is given that for every methane molecule, 6 moles of water is present. Then the chemical formula of methane hydrate would be CH₄.6H₂O.The molecular mass of CH₄.6H₂O would be,
Molecular mass of CH₄.6H₂O = 12 + 4 + 6(2 +16)
= 124g/mol
To find the mass percentage of Methane, the following formula is to be used:
Mass percentage of CH₄ = (Mass of methane / Molecular mass of methane hydrate)x100
On substituting the values of mass of CH₄ and mass of CH₄.6H₂O we get,
Mass percentage = (16/124)100
Mass percentage of CH₄ = 12.9%
Therefore the mass percentage of CH₄ in CH₄.6H₂O is 12.9%
Similarly, to find the mass percentage of 6H₂O in methyl hydrate, the following formula is used:
Mass percentage of water = (Mass of 6H₂O/Molecular mass of CH₄.6H₂O)x100
On substituting the values of mass of 6.H₂O and CH₄.6H₂O we get,
Mass percentage of 6H₂O = (108/124)x100
Mass percentage of 6H₂O = 87.09%
Therefore the mass percentage of water in methyl hydrate is 87.09%
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look at the picture
Answer:
Determining the melting point of a substance.
What is the formula for osmium decobromide
Answer:
OsBr2.
Explanation:
Osmium decobromide is the same as osmium bromide. This is the result of the reaction between osmium hydroxide (Os(OH)2) and hydrobromic acid (HBr) to form water and a salt (osmium bromide):
[tex]Os(OH)_2+2HBr\rightarrow OsBr_2+2H_2O.[/tex]So, osmium bromide has the formula: OsBr2.
Calculate the theoretical yield in grams All from the complete reaction of 18.3
grams Al according to the following balanced chemical equation:
2 Al(s) + 3 (s) →→
2 All(s)
(s)→ 2
The theoretical yield of aluminum iodide according to the reaction would be 276.5 grams.
Stoichiometric problemWe are looking to get the theoretical yield of aluminum iodide. This can be achieved by first getting the balanced equation of the reaction:
[tex]2Al + 3I_2 --- > 2AlI_3[/tex]
The mole ratio of Al that reacts and the [tex]AlI_3[/tex] that is produced is 1:1.
Recall that: mole = mass/molar mass.
18.3 grams of aluminum completely reacts:
Molar weight of aluminum = 26.98 g/mol
Mole of 18.3 g aluminum = 18.3/26.98
= 0.6782 mole
Since the mole ratio of Al and [tex]AlI_3[/tex] is 1:1, the equivalent mole of [tex]AlI_3[/tex] will also be 0.6782 mole.
Recall that: mass = mole x molar mass
Molar mass of [tex]AlI_3[/tex] = 407.695 g/mol
Mass of 0.6782 [tex]AlI_3[/tex] = 0.6782 x 407.695
= 276.5 grams
In other words, the theoretical yield of [tex]AlI_3[/tex] according to the reaction is 276.5 grams.
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Sir Isaac Newton reasoned that the attractive force that keeps planets in their orbits around the Sun is due to two factors, one of which is the distance between the planet and the Sun. Which law was the result of his observations and calculations?
A) The law of Superposition
B) The law of Universal Gravitation
C) The law of Conservation of Mass
D) The law of Conservation of Energy
Answer:
The law of Universal Gravitation.
What statement best describes why a chemical change. is different from a physical change?
Answer: a physical change is something we can see, but a chemical change is not always something that we can see.
Explanation: Physical changes show a change in appearance.
There are chemical changes when two aqueous solutions are added together and the product is still two aqueous solutions, so we would not see any change and no precipitate is formed.
So a physical change is something we can see, but a chemical change is not always something that we can see.
14) Identify which types of acid-base reactions are reversible and which ones are
irreversible.
Acid-base reactions are reversible and which ones are irreversible then the 1st reaction is HA + H₂O ↔ A⁻ + H₃O⁺ is the reversible reaction and in the 2nd reaction MOH → M⁺ + OH⁻ is the reversible reaction and 3rd reaction is HA+H₂O → A⁻ + H₃O⁺ is the irreversible reaction
Acid base reaction is the chemical reaction that occur when acid and base are mixed together called acid base reaction and irreversible reaction means they can occur only in one direction the reactants can change to the products but the products cannot change back to the reactants and reversible reaction means chemical reaction occur in both direction the reactants can change to the products and the products can also change back to the reactants and in that given reactions
1st reaction is HA + H₂O ↔ A⁻ + H₃O⁺ is the reversible reaction because it goes in the both direction called as reversible reaction2nd reaction MOH → M⁺ + OH⁻ is the reversible reaction because in that reaction product can also back to the reactant called as reversible reaction 3rd reaction is HA+H₂O → A⁻ + H₃O⁺ is the irreversible reaction because in that reaction acid are treated with water that's why it is called irreversible reactionKnow more about reversible irreversible
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Suppose 87.1 mL of a 0.190 M solution of Na2SO4 reacts with 143 mL of a 0.311 M solution of MgCl2 to produce MgSO4 and NaCl as shown in the balanced reaction Na2SO4(aq)+MgCl2(aq)⟶MgSO4(s)+2NaCl(aq)
1. Calculate the mass of MgSO4 that can be produced in the given reaction.
2. Only 0.212 g of MgSO4 are isolated after carrying out the reaction. Calculate the percent yield of MgSO4
a. The mass of MgSO₄ that can be produced in the given reaction is 1.985 grams.
b. The percent yield of MgSO₄ is 10.68%
The complete balanced chemical equation is,
Na₂SO₄(aq)+MgCl₂(aq)⟶MgSO₄(s)+2NaCl(aq)
We know,
Molarity(M) = number of moles(n)/per litres solution.
So,
Number of moles of Na₂SO₄ = Molarity × volume.
Moles of Na₂SO₄ = 0.190×0.0871
Moles of Na₂SO₄ = 0.016549 moles.
Moles of MgCl₂ = 0.311×0.144
Moles of MgCl₂ = 0.044473 moles.
As we can see, moles of Na₂SO₄ are present in less amount,
So Na₂SO₄ will be Limiting reagent and it will control the reaction.
So,
Moles of Na₂SO₄ = Moles of MgSO4
Moles of MgSO₄ = 0.016549 moles.
As we know,
Moles = Mass produced/molar mass
Molar mass of MgSO₄ = 120grams/mole
Putting the values,
0.016549 = mass of Mg produced/120
Mass of MgSO₄ produced = 1.985 grams.
b. Percentage yield formula,
Percentage yield = experimental mass/theoretical mass×100
Theoretical mass = 1.985 grams
Experimental mass = 0.212 grams.
Percentage yield = 0.212/1.985×100
Percentage yield of MgSO₄ = 10.68%
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If you dissolved 54 grams of ammonia in 100 grams of water at 400C would it be considered saturated, unsaturated, or supersaturated? Why?
If you dissolved 54 grams of ammonia in 100 grams of water at 400°C then the solution is saturated
A saturated solution is a solution that has dissolved as much solute as it is capable of dissolving and in a saturated solution no more solute can be dissolved at a given temperature and we can make an saturated solution by keep on dissolving solute until no more solute can be dissolved
Here given data is dissolved 54 grams of ammonia in 100 grams of water at 400°C then the ammonia is totally dissolved in this 100 ml water
NH₃ + H₂O → NH₄OH
So, here ammonium hydroxide are formed which is saturated solution and when ammonia is dissolved in water the water molecule donate the proton to the NH₃ molecule and the solubility of ammonia decreases with the increases in of water solvent that's why when we dissolved 54 grams of ammonia in 100 grams of water at 400°C the solution is saturated
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I am not sure what the answer would be.
If 22.2 g of iodine reacts with excess hydrogen gas, the amount, in grams, of hydrogen iodide that would be formed is 44.75 grams.
Stoichiometric problemFrom the balanced equation of the reaction, as shown in the illustration, the mole ratio of the iodine that reacts and the hydrogen iodide that forms is 1:2.
22.2 g of iodine reacted.
Recall that: mole = mass/molar mass
Molar mass of iodine = 126.9 g/mol
Mole of iodine that reacted = 22.2/126.9
= 0.1749 moles
From the mole ratio, the equivalent mole of hydrogen iodide that will be produced is:
0.1749 x 2 = 0.3499 moles
Recall that: mass = mole x molar mass
Molar mass of hydrogen iodide = 127.9 g/mol
Mass of 0.3499 mole hydrogen iodide = 0.3499 x 127.9
= 44.75 grams
Thus, the amount of hydrogen iodide that will be produced is 44.75 grams.
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How mamy liters of a 0.500 M sucrose, C12H22O11 solution contain 1.5 kg of sucrose?
Answer:
10.0 g C12H22O11 (mol/342.34 g) (1/0.500 L) = 0.06 M C12H22O11 => 1 sig.
Explanation:
According to molar concentration,0.00876 liter of 0.500 M sucrose contain 1.5 kg of sucrose.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.
Volume is obtained by using molar concentration formula, 0.500×342.3/1.5×10³=114.1×10[tex]^-3[/tex]=1/V
Thus,volume=1/114.1×10[tex]^-3[/tex]=0.00876 M.
Thus, the volume of sucrose solution is 0.00876 M.
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A buffer solution with a pH of 4.23 is prepared with the same volumes of 0.90 M HC₂H₂O₂ and .
O 1.2x10-9 M NaC₂H₂O₂. The K₂ of HC₂H₂O₂ is 1.8 - 105.
A buffer solution with a pH of 4.23 is prepared with the same volumes of 0.90 M HC₂H₂O₂ and O 1.2x10-9 M NaC₂H₂O₂ is 0.37.
A buffer answer is an aqueous answer along with an aggregate of a weak acid and its conjugate base, or vice versa. Its pH adjustments little or no when a small amount of sturdy acid or base is introduced to it.
Buffer solution is a water solvent based totally answer which includes a combination containing a vulnerable acid and the conjugate base of the vulnerable acid, or a vulnerable base and the conjugate acid of the vulnerable base. They withstand a trade-in pH upon dilution or upon the addition of small amounts of acid/alkali to them.
Buffer solutions resist an exchange in pH whilst small amounts of a robust acid or a strong base are added. a solution of acetic acid and sodium acetate CH3COOH + CH3COONa is an example of a buffer that includes a susceptible acid and its salt.
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Question 7 of 8
How many mL HCI of a 0.100 M HCI solution is needed to completely neutralize
25.0 mL of a 0.350 M NaOH solution according to the balanced chemical reaction:
HCl(aq) + NaOH(aq) → H₂O(l) + NaCl(aq)
The volume of HCl is needed to completely neutralize is 81.25 ml.
Formula of neutralization, M₁V₁ = M₂V₂
M₁ = concentration of HCl
V₁ = volume of HCl
M₂ = concentration of NaOH
V₂ = volume of NaOH
Put the value in M₁V₁ = M₂V₂
0.100 × V₁ = 25 × 0.325
V₁ = 25 × 0.325/ 0.100
V₁ = 81.25 ml
Hence, the volume of HCl is 81.25 ml.
In chemistry, neutralization or neutralization is a chemical reaction wherein acid and a base react quantitatively with every other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present inside the answer.
whilst a strong acid reacts with a strong base the ensuing salt is neither acidic nor primary in nature i.e. it's far impartial for instance whilst HCl, a strong acid, reacts with NaOH, a robust base, the resulting salt is sodium chloride and water.
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how many magnesium sulfate are in 2,5 magnesium sulfate?
Answer:
Each 2 ml ampoule contains 4 mmol Mg2+ (equivalent to 1 g magnesium sulfate heptahydrate). Each 10 ml ampoule contains 20 mmol Mg2+ (equivalent to 5 g magnesium sulfate heptahydrate). The concentrations of magnesium ions (Mg2+) in millimoles are given as approximate values.
an auto mechanic spills 88mL of 2.6M H2S04 solution from an auto battery. How many milliliters of 1.6M NaHCO3 must be poured on the spill to react competely with the sulfuric acid?
The volume (in mL) of the 1.6 M NaHCO₃ solution that must be poured on the spill to react completely is 286 mL
How to determine the volume of NaHCO₃We'll begin by writing the balanced equation for the reaction. This is given below:
H₂SO₄ + 2NaHCO₃ —> Na₂SO₄ + 2H₂O + 2CO₂
The mole ratio of the acid, H₂SO₄ (nA) = 1The mole ratio of the base, NaHCO₃ (nB) = 2The volume of NaHCO₃ can be obtained as follow:
Volume of acid, H₂SO₄ (Va) = 88 mL Molarity of acid, H₂SO₄ (Ma) = 2.6 MMolarity of base, NaHCO₃ (Mb) = 1.6 MVolume of base, NaHCO₃ (Vb) =?MaVa / MbVb = nA / nB
(2.6 × 88) / (1.6 × Vb) = 1 /2
228.8 / (1.6 × Vb) = 1 / 2
Cross multiply
1.6 × Vb = 228.8 × 2
1.6 × Vb = 457.6
Divide both side by 1.6
Vb = 457.6 / 1.6
Vb = 286 mL
Thus, the volume of the NaHCO₃ solution needed is 286 mL
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i need help with chemistry equation
From the given equation of reaction:
The maximum amount of ethane (C₂H₆ ) that can be formed is 9.15 gThe formula of the limiting reagent, hydrogen is H₂.The amount of the excess reagent that remains after the reaction is complete = 3.78 gramsWhat are limiting reagents?Limiting reagents refers to the reactants in a given reaction which is completely used up at the end of a reaction.
Once the limiting reagent is used up, the reaction will stop.
Considering the given question and the data provided:
0.610 grams of hydrogen gas are allowed to react with 12.4 grams of ethylene (C₂H₄).
The equation of the reaction is as follows:
H₂ (g) + C₂H₄ (g) ---> C₂H₆ (g)
The mole ratio of the reactants is used to determine the limiting reactant.
Mole ratio of hydrogen to ethylene is 1 : 1
Moles of hydrogen = 0.610/2 = 0.305 moles
Moles of ethylene = 12.4/28 = 0.44 moles
The limiting reagent is hydrogen while the excess reagent is ethylene.
The maximum amount of ethane (C₂H₆ ) that can be formed is 0.305 moles.
mass of 0.305 moles of ethane = 0.305 * 30 grams
mass of 0.305 moles of ethane = 9.15 g
The moles of the excess reagent that remains after the reaction is complete = 0.44 - 0.305 = 0.135 moles
mass of 0.135 moles of ethylene = 0.135 * 28 = 3.78 grams
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15. If an airplane is in flight, where is the air pressure lower?
under
above
When an airplane is in flight, the air pressure at the under drops.
What is pressure?Pressure is defined as the force applied perpendicular to an object's surface per unit area over which that force is dispersed. Gauge pressure is the pressure in relation to the surrounding atmosphere. Pressure is expressed using a variety of units.
As air flows over an airplane wing, the form of the wing creates a low pressure over the wing surface. The low pressure creates lift, which allows the plane to fly.
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When 25.0 mL of 0.500 M AgNO, solution is mixed with 40.0 mL of 0.250 M Na SO4, solid Ag-SO4 precipitates out. What
mass of AgSO4 is formed?
(The molar mass of Ag:SO, is 311.8 g/mol.)
Answer:
Explanation:
yyyyyyyyyyyy
Draw the arrow(s) required to go from the left structure to the right structure.
Answer:
See image below
Explanation:
To convert the left structure to the right structure, one pair of electrons on the oxygen is pushed down onto the carbon-oxygen bond (resulting in a double bond). This results in too many electrons on the top carbon. The electrons from the adjacent double bond are subsequently pushed onto the second carbon.
Use words and arrows to draw a diagram that shows whether energy is added or removed during changes in state among solid, liquid, and gas.
Energy is added in the conversion of solid to liquids and then the conversion of liquids to gases.
What is change of state?We know that matter occurs in three states; Solid, liquid and gas. Now, we know that solid matter has its particles held together in place such that they do not move about from place to place. The particles of a liquid are not held so closely together hence they do not translate to a large extent. The molecules of a gas are very much free and move about freely from place to place.
Now, we know a solid can be converted to a liquid when it is heated such that the molecules of the solid receive more kinetic energy and move faster and the rigid intermolecular forces that hold them together are broken down thus heat is added.
When we add more heat to the liquid, the intermolecular forces also break down and the we have the gaseous state in which there are no bonds between the molecules.
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HW6.3. 221 PS6_1c molal sat balances
Moist air at atmospheric presure, 92 C and relative humidity 44% enters a cooler where it is cooled isobarically at 1 atm to a temperature of 21 C. (Isobaric means at constant pressure)
The Antoine equation with T in C and p in mm Hg has coefficients for water given by
0 to 60 C: A= 8.10765 B=1750.286 C=235.000
60 to 150 C : A=7.96681 B=1668.210 C= 228.000
At the specified temperature 92 C, the Antoine equation gives a vapor pressure p*=567.09 mm Hg, and at a temperature 21 C, the vapor pressure is p*=18.65 mm Hg.
What is the molal saturation of the moist entering air?
What is the molal saturation of the exiting air at 21 C
If the moist entering air contains 33.39 total moles which includes 22.43 moles of dry air; how many g's of water condenses in the cooler?
The molal saturation of the moist entering air is 10.96 mol, molal saturation of the exiting air at 21 C is 0.560 mol and 187.2g of water condenses in the cooler.
Antoine equationThe Antoine equation can be stated as a class of semi-empirical correlations describing the exact relation between vapor pressure and temperature for pure substances.
it is seen that
humidity = 44%
Ptotal = 1 atm = 760 mm Hg
[tex]P_{H2O}[/tex] = RH/100 X [tex]P^{*} _{H2O}[/tex] = 52/100 X 567.09
= 294.88 mmHg
Molal saturation = [tex]\frac{P_{H2O} }{P_{T} -P_{H2O} }[/tex]
= 294.88/ (760 - 294.88)
= 0.6361
Exit air = 100% (after cooling)
[tex]P_{H2O}[/tex] = [tex]P^{*} _{H2O}[/tex] at 21°C = 18.65
Hm2 = 18.67/ (760 - 18.65)
= 0.025
Mole of water that enters = mole of total moist - mole of total dry
= 33.39 - 22.43
= 10.96
mole of water exits after cooling
n2 = Hm2 x (mole of dry air)
= 0.025 x 22.43
= 0.560
water condenses = n1 - n2
=10.96 - 0.560
=10.4 mol
=10.4 x 18 g
= 187.2 g
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Which statement is correct in the process of balancing the equation?
CH4+O2 = CO2+2H2O
.Do nothing, the equation is already balanced.
Add coefficient 2 to O2 on the left side of the equation.
Remove coefficient 2 in front of H2O on the right side of the equation.
Add coefficient 4 to O2 on the left side of the equation.
Correct statement in the process of balance the equation CH₄+O₂ → CO₂+2H₂O then add coefficient 2 to O₂ on the left side of the equation
Balance reaction is the chemical reaction in which number atom is arranged specific manner which reaction is balanced means all elements in the reaction are balanced with specific number
And the given reaction is
CH₄+O₂ → CO₂+2H₂O then,
Place a coefficient of 2 in front of the O₂ we now have 4O atoms on both sides CH₄+2O₂ → CO₂+2H₂O
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Write the ions present in a solution of NaC2H3O2.
Balance the given equations by inserting the appropriate coefficients.
chemical equation=p4+O2
The reaction equation that is balanced is obtained as; [tex]P_{4} + 5O_{2} ----- > 2P_{2} O_{5}[/tex]
What is reaction equation?We know that it is common to use a chemicals reaction equation to show what is going on in a reaction system. The chemical reaction equation would include the symbols of the elements that are combined in the reaction equation.
The first rule that must be observed when we are writing a balanced reaction equation is that the number of atoms of each element on the reactant side must be the same as the number of atoms of the same element on the left hand side. This is what we call an atom count. If the atom count is not complete it then follows that the reaction equation is not balanced as written
Having said this let us now attempt to write the balanced reaction equation between phosphorus and oxygen molecules which are both poly atomic.
The balanced reaction equation is; [tex]P_{4} + 5O_{2} ----- > 2P_{2} O_{5}[/tex]
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The smooth ER differs from the rough ER in that:
A. The rough ER contains no ribosomes, the smooth ER contains ribosomes.
B. The smooth ER produces carbohydrates and lipids, rough ER produces proteins.
C. The smooth ER produces proteins, rough ER produces lipids.
D. The rough ER is the site of mRNA transcription, smooth ER is the site of protein translation.
The smooth ER differs from the rough ER in that the smooth ER produces carbohydrates and lipids, whereas the rough ER produces proteins. (Option B)
What distinguishes the smooth Endoplasmic reticulum from the rough Endoplasmic reticulum?The manufacture, folding, quality assurance, and shipment of some proteins take place in the rough ER, which is dotted with millions of membrane-bound ribosomes.
The production of steroid hormones, lipid (fat) synthesis, and metabolism are all heavily correlated with SER. It also serves as a detoxifier. The production of proteins is greatly aided by the rough endoplasmic reticulum.
The fundamental distinction between the rough endoplasmic reticulum and the smooth endoplasmic reticulum is that the RER contains ribosomes, which give it its rough appearance and enable protein synthesis.
Ribosomes cover the rough endoplasmic reticulum, which is important in the synthesis and creation of proteins.
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how many atoms are in a tetrahedral molecule?
Answer:
There would be 4 atoms in a tetrahedral molecule.
Explanation:
Answer: 4 atoms
Explanation: