Evan performed an experiment testing how different wind speeds affect how fast a small cart will roll down a ramp. His data from the experiment is shown in the graph below.

Answer:

Like trees, houses, and people, anything outside is at risk of being struck by lightning when thunderstorms are in the area, including cars. The good news though is that the outer metal shell of hard-topped metal vehicles does provide protection to those inside a vehicle with the windows closed.

Answer: Depends

Explanation:

You should be good if you have proper shelter and protection to maintain safety.

If it's hail, it's probably best to find shelter and I recommend putting a thick blanket on the windows so they don't burst.

The velocity of the ball just before it strikes the floor is -6.18 m/s. The velocity of the ball just after it leaves the floor is 5.3 m/s. Acceleration during contact with the floor is 3280 m/s^2. The compression of the ball during its collision with the floor is -9.42*10^-4 m

(a) The ball dropped from a height 1.95 meters. The velocity just before it strikes the floor is calculated by the kinematic equation. The initial velocity is zero.

v^2 = u^2 + 2aS

v^2 = 0 + 2*-9.8*(0-1.95)

V = -sqrt(38.22) = -6.18 m/s

(b) The velocity just after it leaves the floor on its way back up.  The initial velocity is zero in this case. The ball rebounds to a height of 1.44 m.

v^2 = u^2 + 2aS

v^2 = 0 + 2*-9.8*(1.44-0)

v = sqrt(28.22) = 5.3 m/s

(c) The acceleration during contact with the floor is calculated where time is 3.50 ms.

Time in seconds = 3.5/1000 = 0.0035

a = change in velocity/time

a = (5.3 m/s - -6.18 m/s)/0.0035

a = 11.48/0.0035 = 3280 m/s^2

(d) Assuming the floor is absolutely rigid. The amount which the ball compress during its collision with the floor is given as,

v^2 = u^2 + 2aS

S = (v^2 - u^2)/2a

S = (-6.18 m/s - 0)/2*3280 m/s^2

S = -9.42*10^-4 m

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Answer:

Explanation:

In mathematics, the common logarithm is the logarithm with base 10. It is also known as the decadic logarithm and as the decimal logarithm. Natural logarithm of 379 is 5.9375362050824 Decimal logarithm of the number 379 is 2.5786392099681 Sine of 379 is 0.9055655749933. Cosine of the number 379 is -0.42420630521841. Tangent of the number 379 is -2.1347291727006

The Common logarithm for the 379 using a scientific calculator is 2.58. It means that 2.58 is the value of [tex]log_{10}[/tex] ( 379 ).

[tex]log_{a}[/tex] ( x ) = [tex]log_{10}[/tex] ( x ) / [tex]log_{10}[/tex] ( a )

This is how it should be calculated using a scientific calculator if you want to find the value of x for a different base. The commonly used base is 10 because in olden days logarithmic tables were used instead of calculators.

In order to reduce the calculations to basic formats such as addition and subtraction, base 10 was used. So calculators were designed in such a way that if you use log of any number it is the value of log with a base of 10.

Therefore, the Common logarithm for the 379 using a scientific calculator is 2.58. It means that 2.58 is the value of [tex]log_{10}[/tex] ( 379 ).

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Weight is the gravitational force with which the earth pulls an object towards it whereas, Mass is a quantity representing the amount of matter in a particle or object.

hope this helps and you need a chair for sitting xD -,-

Answer: The direction of the resultant can be determined by finding the angle that the resultant makes with either the north-south or the east-west vector. The diagram at the right shows the angle theta (Θ) marked inside the vector addition triangle. This angle theta is the angle that the resultant makes with west.

Explanation: Hope this helps.

Answer:

Magnitude=25.5    

Direction=-60.4

Explanation:

[tex]\sqr\sqrt{ x^{2} +y^{2} \\\\[/tex]=m

[tex]Tan^{-1} (y/x)[/tex] = D

(D) The electric potential at the point P is +1.6 kQ/R.

The electric potential of a given charged body is the work done in bringing the charge from a point to a given location in the electric field.

Mathematically, electric potential is given as;

V = kq/r

where;

The distance of each of the negative charge to point P is calculated as follows;

r = √(R² + R²)

r = √(2R²)

r = R√2

The electric potential from each negative charge to point P;

V = -kQ/(R√2)

For the two charges = - 2kQ/(R√2)

The electric potential from 3Q

V = (k3Q) / R

V = (3kQ)/R

The total electric potential;

V(net) =  (3kQ)/R - 2kQ/(R√2)

V(net) =  (3kQ)/R - (1.414kQ)/R

V(net) = +1.6 kQ/R

Thus, we can conclude that the sum of the sum of the electric potential at point must be positive since it is directed to the positive y-direction.

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The output voltage of a step-up transformer is 2550volts.

A transformer is an electrical energy transfer device that steps up or steps down the voltage from one alternating-current circuit to one or more other circuits.

We are given that,

The primary voltage of a transformer = V₁ = 170V

The number of turns of coils of primary transformer = N₁ = 10turns

The number of turns of coils of secondary  transformer = N₂ = 150 turns

Thus , to get the output voltage V₂ of  a step-up transformer, we can use the formula,

[tex]\frac{V_{2} }{V_{1} } = \frac{N_{2} }{N_{1} }[/tex]

Where, V₁ is primary voltage of a transformer , V₂ is the output voltage (secondary) of a transformer , N₁ & N₂ are the number of turns of  coils primary and secondary transformer.

Therefore , after putting the values in above equation we can get,

[tex]V_{2} = \frac{N_{2} }{N_{1} } V_{1}[/tex]

[tex]V_{2} =[/tex] [tex]\frac{150}{10} 170volts[/tex]

[tex]V_{2} =[/tex] [tex]2550 volts[/tex]

Therefore, the output voltage of the step-up transformer would be 2550 volts.

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Answer:

Explanation:

40 km/h

The Direction of the vector sum of the two vectors V and W is resulted as 240.84 m toward + x.

A vector is a quantity or phenomenon with independent components of magnitude and direction. The expression can also be used to describe a quantity's geometric or mathematical representation.

The following are the x and y axes for the supplied vector:

Vector V in x direction;

[tex]$$\begin{aligned}&\mathrm{V}_{\mathrm{x}}=\mathrm{V} \cos \theta \\&\mathrm{V}_{\mathrm{x}}=448 \cos \left(224^0\right) \\&\mathrm{Vx}=-322.26\end{aligned}[/tex]

Vector V in y direction;

[tex]\begin{aligned}&V_y=V \sin \theta \\&V_y=448 \times \sin 224^0 \\&V_y=-311.2\end{aligned}[/tex]

Vector W in x direction;

[tex]W_x = 336 \times cos(74.9^0)[/tex]

[tex]W_x = 81.86[/tex]

Vector W in y direction;

[tex]\begin{aligned}&\mathrm{W}_{\mathrm{y}}=336 \times \sin 75.9 \\&\mathrm{W}_{\mathrm{y}}=325.88\end{aligned}[/tex]

The resultant vector in the x direction is;

[tex]\begin{aligned}&\Sigma X=-322.26+81.86 \\&\Sigma X==-240.4\end{aligned}[/tex]

The resultant vector in the y direction is;

[tex]\begin{aligned}&\Sigma Y=-311.2+325.88 \\&\Sigma Y=14.68\end{aligned}[/tex]

The resultant vector is found as;

[tex]\begin{aligned}&\mathrm{R}=\sqrt{(-240.4)^2+(14.68)^2} \\&\mathrm{R}=240.84 \mathrm{~m}\end{aligned}[/tex]

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If there are six water molecules, the following applies;

A molecule is the smallest particle of a specific element or compound that retains the chemical properties of that element or compound i.e. two or more atoms held together by chemical bonds.

Atoms of an element are usually shown in the chemical or molecular formula, which is a notation indicating the number of atoms of each element present in a compound.

According to this question, six water molecules are given as follows: 6H₂O

This means that there are 6 × 2 = 12 atoms of hydrogen and 6 × 1 = 6 atoms of oxygen in the 6 molecules of water.

Electrolysis is the chemical change produced by passing an electric current through a conducting solution or a molten salt.

If six molecules of water undergoes electrolysis, there would be 12 atoms of hydrogen and 6 atoms of oxygen.

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Given data

*Alec is rising towards the surface of the water is u = 6.0 m/min

*The given distance is d = 8.4 m

The formula for the time taken by the Alec to rise is given as

Substitute the values in the above expression as

Hence, the time is taken by Alec to rise is t = 1.4 minutes

The average acceleration during the time interval t=0 to t=10s is 1.67 m/s².

The average acceleration of an object is the rate of change of velocity of an object with time.

Mathematically, the average acceleration of an object is given as;

a = Δv/Δt

a = (v₂ - v₁)/(t₂ - t₁)

where;

From the graph,

the initial velocity at time of 0 second = 0 km/h

the final velocity at time of 10 seconds = 60 km/h = 16.67 m/s

the initial time = 0 s

the final time = 10 s

The average acceleration of the car is calculated as follows;

a = (16.67 m/s - 0 m/s) / (10 s - 0 s)

a = 1.67 m/s²

Thus, the average acceleration of the car increases with increase in the rate of change of displacement with time.

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The Sun’s effect on Earth change if the Sun was half its mass, the pull of gravity from the Sun would only be half as strong and is denoted as option A.

This is referred to as the universal force of attraction which acts on all matters and is dependent on some parameters such as mass etc.

The increase in mass denotes a corresponding increase in gravity and vice versa which is therefore the reason why if the Sun was half its mass, then the pull of gravity from the Sun would only be half as strong.

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A geostationary orbit can be achieved only at an altitude very close to 35,786 kilometres (22,236 miles) and directly above the equator. This equates to an orbital speed of 3.07 kilometres per second (1.91 miles per second) and an orbital period of 1,436 minutes, one sidereal day.

The force applied to the ball from bat if the ball is in contact with the ball for only 0.0007 s is 34.29 KN

J = F * t

J = Impulse

F = Force

t = Time

J = 24 N s

t = 0.0007 s

F = J / t

F = 24 / 0.0007

F = 34.29 KN

Impulse is the rate of change of momentum in an object. It can simply be defined as force acting on an object over a period of time to change the object's momentum. So,

J = Δp = F Δt

Therefore, the force applied to the ball from bat is 34.29 KN

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According to the given statement the charge Q is 6 coulomb that requires of energy to be moved through a potential difference .

Note that whenever a voltage is stated, it refers to the difference in potential between two places. Every battery, for instance, has two terminals, and its voltage seems to be the difference in potential between them.

The voltmeter is a tool used to measure potential difference. Some varieties, like voltmeters, feature a pointer on a dial, but digital displays are more common. To detect the potential difference across a circuit element, you must connect a voltmeter in parallel, unlike an ammeter.

W is work done

V is potential difference

Work done

W = 96J

V = 16

W=Q×V

Q=W÷V

Q =  96 ÷ 16

Q =  6 Coulomb.

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Answer:

I am not understanding your question

Potential energy of a child at the top is 490 J.

Potential energy, U = mgh

U = potential energy

m  = mass of an object, given = 25kg

g = acceleration due to gravity, given = 9.8 m/[tex]s^{2}[/tex]

h = height of an object, given = 2 meter

Put the values in potential energy formula, U = mgh

U = mgh

U = 25 × 9.8 × 2

U = 490 J

Hence, Potential energy of a child at the top is 490 J.

Potential energy is the  type of energy, which is product of mass of an object, acceleration due to gravity and height of an object where it is placed. Its S.I. unit is joule and is represented by J.

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Making progress by conducting studies for research, project or article and presenting this progress to scientists represent a category that belongs to Science (Option A).

Sciences can be defined as a body of empirical knowledge whose development is based on the presentation of results from experiments in peer-reviewed publications and the generation of projects to investigate different issues of the real world.

Therefore, we can conclude that Science is a body of info based on the transference of knowledge which involves developing projects or writing scientific articles (Option A).

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Answer:

a) V ≈ 125 m/s;  b) Δt = 13.24 s;  c) ΔS ≈ 1450 m

Explanation:

a) We have just to calculate the vector resultant.

V² = 106² + 66.2²

V² = 15618.44

V ≈ 125 m/s

b) The time of flight is equal to the time to reach the maximum height summed to the time to reach the land.

In vertical:

V = V₀ + a * t

V = 66.2 - g * t

0 = 66.2 - 9.8 * t

t ≈ 6.76 s

So: Δt = 13.24 s

c) In horizontal:

V = ΔS / Δt

106 = ΔS / 13.52  ⇒  ΔS = 106 * 13.52

ΔS = 106 * 13.52

ΔS = 1433,12

ΔS ≈ 1450 m

9.14 s long it will take a cyclist to bring a bicycle with an initial speed of 12.8 m/s to a complete stop.

Depending on whether an object is moving much faster, slower, or in a different direction, its speed may change. Examples of acceleration include a falling apple, the moon orbiting the earth and a car which has stopped at a stop sign.

Uniform acceleration, non-uniform acceleration, and average acceleration are the three different forms of accelerated motions.

a = -1.4 m/s²

v[tex]_i[/tex] = 12.8 m/s²

v[tex]_f[/tex] = 0

Δt = ?

We use formula

a = v[tex]_f[/tex] - v[tex]_i[/tex]/t

-1.4 = 0 - 12.8/t

t = 9.14 s

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A load of 24N must be placed on the spring balance for an extension of 8cm and the value of spring constant is calculated as 3N[tex]cm^{-1}[/tex].

The lengthened portion of an object, such as a spring, is known as its extension.

F = ke

The force in newtons is F. (N)

The “spring constant” (k) is expressed in newtons per meter (N/m).

E is the length in meters (m)

This equation is valid as long as the proportionality limit is not exceeded.

The extension for a particular spring and other elastic items is inversely proportional to the applied force. For instance, the extension doubles if the force does.

Kx = 15N

K = 15/x

= 15/5

K = 3N[tex]cm^{-1}[/tex]

dx = 8cm

The value of spring constant is = 3N[tex]cm^{-1}[/tex]

So, 3(8) = 24

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Answer:

m V^2 / R = G M m / R^2

M = R V^2 / G            balancing forces

V = 2 pi R / T         speed of craft

M = 4 pi^2 R^3 / (G * T^2)       substituting for V

M = 4 pi^2 * 52E21 / (6.67E-11 * 1.30E7) = 39.5 * 52 / (6.67 * 1.3) * 10^25 kg

M = 2.37E27 kg

note mass of earth = 5.98E24 kg - should check mass obtained

This answer which is currently written is not complete because solving a vector problem, we should also mention the direction correctly, but here the direction is not mentioned.

A vector is a quantity or phenomenon that has two impartial houses, value and course. The term also denotes the mathematical or geometrical illustration of the sort of quantity. Examples of vectors in nature are pace, momentum, pressure, electromagnetic fields, and weight. A vector may be located in a square coordinate device, as illustrated here. The square coordinate notation for this vector.

vector, in physics, is a quantity that has each importance and course. it's far usually represented via an arrow whose direction is similar to that of the amount and whose period is proportional to the quantity's magnitude. although a vector has magnitude and direction, it does not have a function.

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Answer:

birr i am not smart i d know what to do

Explanation:

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The temperature increase of the ball is 1.63 ⁰C.

The potential energy possessed by the ball at the given height is calculated as follows;

P.E = mgh

where;

P.E = (10) x (9.8) x (150)

P.E = 14,700 J

If half of the energy of the ball is converted into heat energy, then the amount of heat capacity is calculated as follows;

Q = 0.5(P.E)

Q = 0.5 x 14,700

Q = 7,350 J

The increase in the temperature of the temperature of the ball is calculated as follows;

Q = mcΔθ

where;

Δθ = Q/mc

Δθ = (7350) / (10 x 450)

Δθ = 1.63 ⁰C

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A 30.0-mg oil drop carrying a charge of +3.2 μC passes undeflected through a region in which there is a uniform, constant electric field. The Electric field is mathematically given as

98 N/C

This is further explained below.

Generally, Generally, the equation for Electric field the is mathematically given as

q E=m g

Therefore

[tex]&\left(3 \times 10^{-6} \mathrm{C}\right) E=\left(30 \times 10^{-6} \mathrm{~kg}\right)\left(9.8 \mathrm{~m} / \mathrm{s}^2\right) \\[/tex]

E=98N/C

In conclusion, The force of gravity always pulls in a downward direction; hence, the electric field will be exerted in an upward direction. As a result, the value is positive.

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