Answer:
[tex]3 {( \frac{1 - x}{2}) }^{2} = 3 \times {(1 - x)}^{2} \div {2}^{2} \\ =3 \times (1 - 2 \times 1 \times x + {x}^{2}) \div 4 \\ = 3 \times (1 - 2x + {x}^{2} ) \div 4 \\ = \frac{3}{4} (1 - 2x + {x}^{2})[/tex]
[tex] \bold \pink{ \underline{hope \: it \: helps}}[/tex]
12 - (8x - 20) < 12
Plz answer question
[tex]12 - (8x - 20) < 12 <=> 12- 8x+20<12<=> -8x <12-20-12 \\<=>-8x <-20<=>8x>20<=>x>\frac{20}{8}=\frac{5}{2}[/tex]
ANSWER: x > 5/2
Ok done. Thank to me :>
Answer:
[tex]x = \frac{5}{2} [/tex]
Step-by-step explanation:
12-(8x-20)<12
12-8x+20<12
-8x<12-12-20
-8x<-20
divide both by negetive 8
x>5/2
x> 2.5
QUESTION 7
Find the slope of the line passing through the points (8, 3) and (9,7).
A. 4
B. -4
C. 1/4
D. -1/4
I got the X and Y wrong, its 4. Sorry! mark the other answer instead
Reason:
9 - 8 = 1
7 - 3 = 4
Because that 7 and 3 are Y, 4 goes over. so it makes a whole number
Answer:
A. 4
Step-by-step explanation:
yeah-ya............. right?
solve the inequality z + 9 > 6 z > ?
( Equations and Inequalities )
Answer:
You have to switch sides so the answer is x<z+9
Step-by-step explanation:
how many degrees is 37 degrees warmer than -13
how many is 38 degrees warmer than -20
Answer:
98.6° Fahrenheit ( i did it in celsius sorry if i got it wrong)
Step-by-step explanation:
The table below shows the number of tadpoles in a pond after a certain number of months.
PLEASE HELP
===================================================
Explanation:
x = number of monthsy = number of tadpolesHighlight the rows that correspond to 6 months and 10 months.
This leads to the two points (6,330) and (10,460).
Apply the slope formula. This is because the slope is the average rate of change.
m = (y2-y1)/(x2-x1)
m = (460-330)/(10-6)
m = 130/4
m = 32.5
This is the average rate of change from month 6 to month 10.
Let A = 32.5 so we can compare it later.
---------------------------
Now let's focus on months 4 and 8
We get the two points (4, 300) and (8, 410)
Use the slope formula again
m = (y2-y1)/(x2-x1)
m = (410-300)/(8-4)
m = 110/4
m = 27.5
Let B = 27.5
--------------------------
For the third answer choice, we have the points (2,240) and (8,410)
Once again, use the slope formula.
m = (y2-y1)/(x2-x1)
m = (410-240)/(8-2)
m = 170/6
m = 28.33 approximately
Let C = 28.33
--------------------------
Lastly for choice D we have the points (4,300) and (10,460)
So,
m = (y2-y1)/(x2-x1)
m = (460-300)/(10-4)
m = 160/6
m = 26.67 approximately
Let D = 26.67
--------------------------
To recap everything, we found these four average rates of change for choices A through D
A = 32.5B = 27.5C = 28.33 (approximate)D = 26.67 (approximate)We see that A is the largest of that group. Therefore, the greatest average rate of change of that group is from month 6 to month 10. This is why choice A is the final answer.
May someone help me with this please?
Answer:
the first one
Step-by-step explanation:
plz give brainliest
When z=−6, evaluate −2(z+9)−(−5) and −2⋅z−2⋅9+5 to show that −2(z+9)−(−5)=−2⋅z−2⋅9+5
Ignore this, I posted the wrong answer and I don't know how to delete it.
Answer:
Yes/true
Step-by-step explanation:
-2(z+9)-(-5)=-2⋅z-2⋅9+5
sostituisco la lettera dandogli un valore
=-2(-6+9)-(-5)=-2⋅(-6)-2⋅9+5
calcolo e tolgo le parentesi
=-2⋅3+5=12-18+5
Elimino i termini uguali
=-2⋅3=12-18
Somma e moltiplicazione tra i numeri
=-6=-6
Put these fractions in order from greatest to least:
Answer:
[tex]\dfrac 34 , \dfrac 23 , \dfrac 35[/tex]
Step-by-step explanation:
[tex]\dfrac 34 >\dfrac 23 >\dfrac 35[/tex]
-12/5+3/10/11/14-(-9/14)
Answer:
-6/5
Step-by-step explanation:
I hope it helps, bye
three hundred two times one hundred fifty three
302×153
Answer:
46,206
Step-by-step explanation:
simple math
Answer:
the answer is 46,206
Step-by-step explanation:
Good luck!!!!
If cos x = sin(20 + x)° and 0° < x < 90°, the value of x is what?
we can change cos to sin by saying cosx=sin(90-x)
now we drop sin and make the angles equal (nothing needs to be added or subtracted since its in the first quadrant)
90-x=20+x+k.360.......kEZ (k is an element of set of integers) (we say k.360 if it's cos and sin and k.180 if it's tan)
-x-x=20-90+k.360........kEZ
-2x=-70+k.360.........kEZ
divide all terms by -2
x=35-k.180.......kEZ
Answer:
x=35°
Step-by-step explanation:
If cos x = sin(20 + x)° and 0° < x < 90°, the value of x is 35°.
Simplify the square root of 5 times the cube root of 5.
I know the answer is, five to the five sixths power but I would like to know the steps to solve it.
Please help me with it, I'm not doing so well right now, and I need help.
Answer:
Step-by-step explanation:
$5.15 per 5-pound bag
Answer: 1 pound = 1.03
Step-by-step explanation:
not sure what you wanted from this but here are possible answer
Hey there!
When you hear or see the word “per” in math, think of the question/word problem telling you to find the “for each”. This basically mean you’re dividing. So, let’s divide your numbers from each other.
$5.15/5 lb
= 5.15 ÷ 5 lb
= 5.15 ÷ 5 lb
= $1.03
Therefore, your answer SHOULD be: $1.03
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Help help hep help help math
Answer:
Angle 5
Step-by-step explanation:
SOMEONE HELP ME PLEASE <3
Answer:
A.90
Step-by-step explanation:
thank me later
Set A = 3, 4, 7
Set B = 4, 8, 9
What is the union of sets A and B?
Answer:
Step-by-step explanation:
A∩B = 4
Please can u help me with this question
[tex]a) \\\\\dfrac {2x}{3} =8 \\\\\implies 2x = 8 \times 3 = 24\\\\\implies x = \dfrac{24}2 = 12\\\\b)\\\\\dfrac{3x}2 = 6\\\\\implies 3x = 6\times 2 = 12\\\\\implies x = \dfrac{12}3 =4[/tex]
Windstrong has an elevation of -28.7 feet, and Kennington has an elevation of 28.7 feet. Which of the following is true?
A.
Windstrong's elevation < Kennington's elevation
B.
Windstrong's elevation = Kennington's elevation
C.
Windstrong's elevation > Kennington's elevation
Answer:
b
Step-by-step explanation:
help as soon as possible
The greatest common factor of y^4. y^6 and y^5 is
Answer:
Answer:GCF: y^4
Step-by-step explanation:
Factors of:
y^4= (y) (y) (y) (y) = y^4 (1)
y^5 = (y) (y) (y) (y) (y) = y^4 (y)
y^6 = (y) (y) (y) (y) (y) (y) = y^4(y^2)
(8,4) and has a slope of 5/2
13. Jay has 12 classic cars in his garage. He paid
$3,500 for each car 5 years ago. The cars are
currently worth $4,200 each. How much more
must the average value of the cars rise for the
combined value of these 12 cars to be exactly
$10,800 more than Jay paid for them?
A. $200.00
B. $700.00
C. $800.50
D. $ 841.67
E. $958.33
(May need worked out, please!?)
Answer:
I believe the answer would be A. $200.00
Step-by-step explanation:
This is because if jay has 12 cars that he paid 3,500$ each for, the total cost would have been $42,000.
And the current price is 4,200$ for each car.
If you add 200$ to each 4,200$ car, you get 4,400$
After, you take the amount for each car (4,400) and multiply it by 12 (the amount of cars purchased) and you get 52,800.
You then need to subtract the recent cost of 12 cars (52,800) by 42,000$ (the original cost for 12 cars) and you will get $10,800.
52,800-42,000=10,800
therefore, A.$200.00 would be the correct answer
I'm not sure if all calculations are correct, but I hope this helps! :)
The average value of the cars must rise by $200 for the combined value of the 12 cars to be exactly $10,800 more than what Jay paid for them. Therefore, the correct answer is A. $200.00.
To find out how much more the average value of the cars must rise for the combined value to be $10,800 more than what Jay paid for them, we need to calculate the difference between the current combined value and the total price Jay paid, and then divide it by the number of cars.
Given:
Number of cars (n) = 12
Price Jay paid for each car (P) = $3,500
Current worth of each car (W) = $4,200
Total price Jay paid (T) = n * P = 12 * $3,500 = $42,000
Current combined value of the cars (C) = n * W = 12 * $4,200 = $50,400
Difference in value = C - T = $50,400 - $42,000 = $8,400
Additional increase needed = $10,800 - $8,400 = $2,400
To find the average increase needed per car, we divide the additional increase by the number of cars:
Average increase per car = Additional increase / Number of cars = $2,400 / 12 = $200
Therefore, the average value of the cars must rise by $200 for the combined value of the 12 cars to be exactly $10,800 more than what Jay paid for them.
The correct answer is A. $200.00.
To know more about average value, refer here:
https://brainly.com/question/32515383
#SPJ2
allison made a playlist that included 9/12 country songs. what are two equivalent fractions that represent the part of the play list that is country songs. explain why your fractions are correct?
Answer:
3/4,18/24
Step-by-step explanation:
You can mutiply the numerator and denominator by the same number or divide it by the same number as long as it is a whole number. Ex. (9/3) over (12/3)=3/4. Or (9x2)/(12x2)=18/24
A positive real number is 2 less than another. When 4 times the larger is added to the
square of the smaller, the result is 16. Find the numbers.
Answer:
by how i was taught its 2
Step-by-step explanation:
the simple interest on a sum of rs 5000 at 4% p.a. for one year is __________.
Answer:
Principal = Rs. 5000
Rate of Interest = 5%
Number of years = 2 y 3 m = 2 1/4 years
Interest = (P x N x R) / 100
ie (5000 x 9/4 x 5) /100= Rs. 562.50
Find the quotient. If possible, rename the quotient as a mixed number or a whole number. Write your answer in the simplest form
3/4 divided by 3
Step-by-step explanation:
3/4 ÷ 3
recall that the inverse of division is multiplication
=3/4 x 1/3
=1/4
A bus traveling at a constant rate of 50 miles per hour. At this rate, how far will the bus travel 3 1/4 hours?
First, let's do the easy part! Multiplying 50 by 3 will give us how far the bus would travel in 3 hours. 50 x 3 = 150.
Now let's do the quarter. 50 / 4 = 12.5. Simply add these two together now!
The bus will travel 162.5 miles!
Hope this helps :)
A test has twenty questions worth 100 points. The test consists True/False questions worth 3 points each and multiple choice questions worth 11 points each. Howmany multiple choice questions are on the test?
Multiple choice questions = 5
True questions = 15
Given that:
Total number of questions = 20
Total worth of point = 100
Multiple choice questions (M) = 11 points each
True false questions (T) = 3 points each
Hence,
M + T= 20 ____(1)
11M + 3T = 100 ____(2)
M = 20 – T
Using the relation in (2)
11(20 – T) + 3T= 100
220 – 11T + 3T= 100
220 – 8T = 100
-8Tf = 100 – 220
-8T = – 120
T = 120/8
T = 15
Mc = 20 – 15
Mc = 5
Multiple choice questions = 5
True false questions = 15
A jet can carry up to 200,000 liters of fuel.it used 130,000 liters of fuel during a flight. What percentage of the fuel capacity did it use on this flight
If 3 basketball game tickets and 4 football game tickets were purchased for $50.25, and if 5 basketball game tickets and 5 football game tickets were purchased for $71.25, what are the costs of basketball game tickets and football game tickets?
Answer:
Basketball: $6.75
Football: $7.50
Step-by-step explanation:
lmk if you want an explanation
The costs of basketball game tickets and football game tickets are $7.5 and $6.75 respectively.
What is a linear equation?It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
It is given that:
If 3 basketball game tickets and 4 football game tickets were purchased for $50.25, and if 5 basketball game tickets and 5 football game tickets were purchased for $71.25.
The linear equation can be framed:
3x + 4y = 50.25
5x + 5y = 71.25
Here x is the cost of basketball game tickets and y is the football game ticket.
After solving the above linear equation by substitution method,
5([50.25 - 4y]/3) + 5y = 71.25
y = $6.75
x = $7.5
Thus, the costs of basketball game tickets and football game tickets are $7.5 and $6.75 respectively.
Learn more about the linear equation here:
brainly.com/question/11897796
#SPJ5
identify which of the following in NOT equivalent to
[tex]2 \frac{2}{3} [/tex]
[tex]~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]
[tex]\boxed{A}\qquad \sqrt[4]{8}\implies \sqrt[4]{2^3}\implies 2^{\frac{3}{4}} \\\\\\ \boxed{B}\qquad \sqrt[4]{2^3}\implies 2^{\frac{3}{4}} \\\\\\ \boxed{C}\qquad 2^{\frac{1}{4}}\times 2^{\frac{1}{2}}\implies 2^{\frac{1}{4}+\frac{1}{2}}\implies 2^{\frac{1+2}{4}}\implies 2^{\frac{3}{4}} \\\\\\ \boxed{D}\qquad \left( 2^{\frac{1}{4}} \right)^{\frac{1}{2}}\implies 2^{\frac{1}{4}\cdot \frac{1}{2}}\implies 2^{\frac{1}{8}}\qquad \textit{\large \checkmark}[/tex]