Figure 1) is a snapshot graph at t = 0 s of two waves on a string approaching each other at 1 m/s.
1. List the values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s.

The things would which would be needed to survive the mesosphere include the following below:

This is refereed to as the third layer of the atmosphere which is present above the stratosphere and directly below the thermosphere.

It has a low density of gas and water vapor present in the area which is why it is no place for human life as there is a shortage of oxygen and other gases needed for some biochemical reactions in the ecosystem. This is therefore the reason why things such as food, water and oxygen supply is neeeded tio survive in the mesosphere.

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Answer:

5/18 is used to convert km/hr into m/s

1 km = 1000 m

1 hr = 3600 sec

1 km/hr to m/s

1*1000/1*3600

1000/3600metre/sec

10/36metre/sec

5/18 metre/sec

Explanation:

srry if this is wrong!

Answer:

The opposition offered by the conductor to the current flowing through it is known as resistance.

we know,

Resistance is directly proportional to the length of the conductor.Hence,the resistance offered by the long wire will be more than that of the short wire.

Also, Resistance is inversely proportional to the area of cross section of conductor.So,The Resistance in the thick wire will be less than that of the thin wire.

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Answer:

The power is 57.6 watts

Explanation:

We can use the Electric Power Equation to evaluate the power.

Electric Power Equation

[tex]P=IV[/tex]

[tex]P[/tex] is the power in watts

[tex]I[/tex] is the current in amps

[tex]V[/tex] is the voltage in volts

Our lightbulb has current of 0.480 A and a voltage of 120.0 V.

[tex]I=0.480\\V=120.0[/tex]

Now we can evaluate power.

Substitute our values in for the variables.

[tex]P=0.480*120[/tex]

[tex]P=57.6[/tex]

1 N*m = 1 Joule

40 N*m = 40 joules

Answer:

Conduction

Explanation:

Conduction is a process whereby heat is transfer through solid state.

The change in temperature of the 600 g of water, given that the water aborbs 5200 J of heat energy is 2.07 °C

First, we shall list out the given parameters from the question. This is given below:

Calorimetry suggest the following formula:

Q = MCΔT

Where

Using the above formula, the change in temperature of the water can be obtained as follow:

Note: Specific heat capacity of water (C) = 4.184 J/gºC

Q = MCΔT

5200 = 600 × 4.184 × ΔT

5200 = 2510.4 × ΔT

Divide both sides by 2510.4

ΔT = 5200 / 2510.4

ΔT = 2.07 °C

Thus, we can conclude from the above calculation, that the change in temperature of the water is 2.07 °C

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Answer:

2 nitrogen and 1 oxygen,

Explanation:

N2=2 nitrogen

O= a single element

Answer:

3rd image, 2nd image, 1st image, 4th image

Explanation:

Not an easy question, tricky one

Electric potential energy is proportional to the magnitude of the charges (the higher the charges, the stronger the Electric potential energy(EPE)) and inversely proportional to the distance between the charges(the longer the distance, the smaller the EPE).  U = kQq/r

EPE is positive in this case due to unlike charges.

Between distance and magnitude of the charges, magnitude of charges play a more significant effect than distance (due to Qq , both the magnitude of Q and q affect the EPE)

Hence. zoom in on the magnitude first.

3rd image has the largest + and -, hence greatest magnitude of charges, therefore highest EPE.

Between 1st and 2nd images, charges have the same magnitude, distance now comes to play. Distance between the charges is smaller for image 2 and the charges experience greater EPE. 1st image, the charges are further, hence smaller EPE.

For the fourth image, the magnitude of the charges is the smallest, hence smallest EPE.

Answer:

800J

Explanation:

W = Fs, Work equals force times displacement

in this case, the force is 400N and the displacement is 2 meters.

The regular SI unit for work is joules

Proxima Centauri otherwise known as Alpha Centauri C, is the closest star to our solar system, located about 4.24 light-years away. It was discovered in 1915 by Robert Innes, the director of the Union Observatory in South Africa. Innes identified Proxima Centauri as a possible member of the Alpha Centauri system after noticing that the star had a similar proper motion to Alpha Centauri A and B.

Proxima Centauri was first observed through telescopes, which allowed scientists to study the star's spectra and estimate its distance from Earth. In the following decades, scientists continued to study Proxima Centauri through telescopes, including the Hubble Space Telescope, which provided high-resolution images of the star.

In 2016, the European Southern Observatory announced the discovery of an exoplanet orbiting Proxima Centauri, called Proxima Centauri b. This discovery was made using the radial velocity method, which measures the star's small wobbles caused by the gravitational pull of an orbiting planet.

Despite the advances in our understanding of Proxima Centauri, no spacecraft have ever reached this star. The distance between Proxima Centauri and Earth is so vast that it would take tens of thousands of years to reach the star using current propulsion technology.

One potential solution to this problem is the use of interstellar travel, which would allow humans to travel to Proxima Centauri within a human lifetime. There are several proposed methods for interstellar travel, including using a starship propelled by fusion engines or a massive light sail pushed by a beam of lasers. However, these technologies are still in the theoretical stage and have not yet been developed.

There are also many other challenges that must be overcome in order for humans to travel to Proxima Centauri. For example, humans would need to find a way to protect themselves from the high levels of radiation that they would be exposed to during the journey. They would also need to find a way to provide enough food, water, and other resources to sustain themselves for the duration of the trip.

Overall, while it is theoretically possible for humans to travel to Proxima Centauri, it would be a massive undertaking that would require significant technological advancements and the development of new solutions to many challenges.

Sources of Works Cited include:

"Proxima Centauri." Wikipedia, Wikimedia Foundation, 5 Jan. 2021,

"Proxima Centauri b." Wikipedia, Wikimedia Foundation, 20 Nov. 2020,

"Interstellar Travel." Wikipedia, Wikimedia Foundation, 4 Jan. 2021,

Therefore, the correct answer is as given above

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The magnitude of the frictional force that must be overcome is 42.04 N.

The magnitude of the frictional force that must be overcome is calculated by applying Newton's second law of motion as follows;

Mathematically, the formula for the frictional force is given as;

F = μmg

where;

The magnitude of the frictional force that must be overcome is calculated as;

F = 0.39 x 11 kg  x  9.8 m/s²

F = 42.04 N

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The work done to the mower is the product of force and the distance covered by the object which is equal to 40,811 Joules.

Work done can be defined as the product of external force and the distance over which the force is being applied. Work is done on an object when a force is applied to an object and the object is moved through a particular distance.

From this we can see that:

X-Component:

cos(θ) = x/F

Then,

X= F cos(θ).…..(1)

Now putting the values of F and θ in equation (1) we get,

X = 72 N × cos(40)

X = 72 N × 0.766

X= 55.15 N this is the x-component force

The work done to the mower is:

W = F × d

W = 55.15 × 740

W = 40,811 Joules

The work done to the mower is 40811 Joules.

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The reason that Silent Spring was so influential at the time is option D: It was the first time that the public was being made aware of the long-term impacts of pollution.

Silent Spring, a book written by Rachel Carson and published in 1962, was influential at the time because it was the first book to bring awareness to the negative impacts of pesticides on the environment and human health.

Therefore, The book provided evidence and detailed accounts of the harmful effects of pesticides on wildlife and ecosystems, and it argued that the widespread use of pesticides was unsustainable and could have long-term consequences for the environment and human health.

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The true statement is " this situation does not show a closed system" because the linear momentum is not conserved.

option A is the correct answer.

The principle of conservation of linear momentum states in a closed or isolated system, the total momentum of the system is always conserved.

Mathematically, the formula for the conservation of linear momentum is given as;

Pi = Pf

where;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

The given momentum of the toy cars before and after collision;

                 Momentum Before                     Momentum After

Car 1                9 g m/s                                              -2 g m/s

Car 2              -6 gm/s                                               4 g m/s

Sum of the momentum before the collision = 9 gm/s - 6 g m/s = 3 g m/s

Sum of the momentum after the collision = -2 gm/s + 4 gm/s = 2 g m/s.

The above does not show conservation of linear momentum, hence the system is closed because of the momentum is lost.

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The gravitational potential energy of a body is determined by the equation U=mgh, where m is the body's mass, g is its gravitational force, and h is its height. The relationship between mechanical energy and gravitational potential energy is described by the equation E=U+K.

KE= 1/2 m v2

The relationship between kinetic energy and an object's mass and square of its velocity is direct: K.E. = 1/2 m v2.

It provides information on how a substance's mass impacts its velocities. Take this as a case study. A lorry and a sleek vehicle powered by the same engine cannot go at the same pace because to their different designs.

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After solving the equation the wave is traveling at a velocity of 3 m/s.

Velocity is a vector quantity that describes the rate at which an object changes its position. It is a measure of both the speed and the direction of an object. Velocity is typically expressed in terms of meters per second (m/s). When an object is in uniform motion, its velocity is constant, meaning that it is not changing in magnitude or direction. If an object is accelerating, its velocity is changing over time, either in magnitude, direction, or both.

The velocity of the wave can be calculated using the following equation:
Velocity = Wavelength x Frequency
In this case, the wavelength is 0.5 m and the frequency is 6 Hz (6 cycles per second). So, the velocity of the wave is:
Velocity = 0.5 m x 6 Hz = 3 m/s
This means that the wave is traveling at a velocity of 3 m/s.

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The degree of data stability when the measurement is replicated under identical circumstances is known as reproducibility or reliability.

Reproducibility determines how an entire study an experiment can be replicated, whereas repeatability assesses the variation in data made by a single equipment or human under similar circumstances.

Science needs reproducibility because it enables more in-depth investigation, and replication validates our findings. There are several investigations and experiments, which result in a wide range of variables, unforeseen, and things that are either outside your influence or you cannot guarantee.

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The points in order of increasing value of the velocity can be ranked as:

B < C < A ≡ F < E < D.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

According to the figure:

The points in order of increasing value of the velocity can be written as:

B < C < A ≡ F < E < D.

As the displacement becomes from positive to negative near point B, it has the lowest velocity and  as the displacement becomes from negative to positive near point D, it has the highest velocity

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Explanation:

Mass of the football = 0.49 kg

Initial velocity of the ball ,u= 0 m/s

Final velocity of the ball ,v= 44 m/s

time of contact ,t = 0.028 seconds

First law of motion:

v=u+at

44 m/s=0+a\times 0.028 sec44m/s=0+a×0.028sec

a=1,571.42 m/s^2a=1,571.42m/s

2

force=mass\times acceleration=0.49 kg\times 1,571.42 m/s^2=769.99Nforce=mass×acceleration=0.49kg×1,571.42m/s

2

=769.99N

The magnitude of the force exerted by the ball on the kicker's foot is of 769.99 Newtons.

Answer:

24.4

Explanation:

you would add all the numbers , 25.5+24.4+24.2= 73.1/3=24.36 and you round up you get 24.4

Explanation:

it takes the earth 24 hours to spin on it's axis once

A unit vector must have length equal to 1. By calculating the length of (1, 1), we discover that (12 + 12) = 2 = 1.414, which is not the same as 1, is the length.

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Yes! The second one is one of the constant acceleration equations. We know that our X and Y values are independent of each other, which is why Y doesn't matter here. We only care about the X position value since X and Y are independent! (This is an extremely important rule, trust me)

Therefore, we don't need to calculate a Y velocity or anything like that. We only need Y because we need to find time t. We can use Y to calculate time because although X and Y are independent of each other, they do share the same time traveled!

We know that [tex]V_{0,y}[/tex] = 0, since the car wasn't moving vertically initially. We also know Y initial is 100 and Y final is 0 when it hits the ground! The last thing we know is that the acceleration of any item in free fall is (usually) -9.81. Therefore, using the original Y equation that your teacher gave, we can plug things in and solve for time!

[tex]y_f=y_i+v_it+\frac{1}{2}at^2\\0=100+(0)t+\frac{1}{2}(-9.81)t^2\\-100=-4.905t^2\\t^2=20.39\\t=4.52[/tex]t = 4.52s

(Your teacher simplified the Y equation a little, so it may look slightly different from mine. I started at the original Y equation)

Now we have time! So now we can use the other equation your teacher provided. Again, remember, even though the car is now traveling through the air vertically, that does not affect its x velocity! The car is still traveling at 50m/s!

Therefore, we can just plug and chug!:

x = vt

x = (50)(4.52)

x = 226m

I hope this helps!

The value of mA is the equation of conservation of linear momentum is determined as mA = [ mB (vBi - vBf) ] / [  (vAf - vAi ) ].

The principle of conservation of linear momentum states that in a closed or isolated system, the total momentum of the system is always conserved.

Mathematically, the formula for the principle of conservation of linear momentum is given as;

Pi = Pf

where;

mAvAi + mBvBi = mAvAf + mBvBf

where;

To find the value of mA, we will make mA the subject of the formula as follow;

mAvAf  - mAvAi = mBvBi - mBvBf

mA (vAf - vAi ) = mB (vBi - vBf)

mA = [ mB (vBi - vBf) ] / [  (vAf - vAi ) ]

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Total distance covered by Brandon is 18 km and total displacement covered by him is 13.41 km.

The definition of displacement is the changing of an object's position. It has a magnitude and direction and is a vector quantity. It is shown as an arrowhead that travels from the initial location to the end. An object's position changes, for instance, if it moves from position A to position B.

Distance covered by Brandon is-

12 + 6 = 18 km

Displacement covered by Brandon is-

d²= 12² + 6²

= 144 + 36

d²= 180

d = √180

d = 13.41 km.

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The following which is not a safety tip for outdoor activities is to go alone for a sense of oneness with nature and is therefore denoted as option A.

This is referred to as the condition of being protected from harm or other danger and it involves the use of various methods and activities and an example is to ensure that a  basic first aid kit is available so as to help in the incident of an injury.

However going alone for a sense of oneness with nature is not a safety tip as should in case any issue arises there will be no one to support and rescue such individual.

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The full question is:

Which of the following is not a safety tip for outdoor activities

a. go alone for a sense of oneness with nature

b. bring a basic first aid kit

c. bring a flashlight or headlamp

d. pack plenty of water and energy-dense food

A horizontal force of 10.0 N is acting on a 10 kg box that is sliding to the right along the floor with velocity v.

Most people make the common assumptions of rigid body action and ignoring air resistance and friction. In statics, all forces and moments must balance to zero; if they don't, the body is accelerating and the laws of statics do not apply, according to the physical interpretation.

The specific situation and the presumptions used will determine how many forces and moments are displayed. Most people make the common assumptions of rigid body action and ignoring air resistance and friction.

In statics, all forces and moments must balance to zero; if they don't, the body is accelerating and the laws of statics do not apply, according to the physical interpretation. The resultant forces and moments in dynamics can have non-zero values.

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If an object is moving and the sum of all the vector forces on it is zero, then the object will move at a constant speed. The correct option is c.

A force's magnitude and direction are both represented by a force vector. This contrasts with expressing the force's magnitude alone, which is known as a scalar quantity.

Typically, a vector is represented by an arrow that points in the direction of the force and has a length proportionate to the strength of the force.

Therefore, the correct option is c, move at a constant speed.

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The net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.

When a force acts on a body at rest or at uniform motion in a straight line, then it starts to accelerate.

Given that, the velocity is 5.0

Time is 2 sec

The given mass is 2.0 kg

First, we calculate the acceleration

Acceleration = v / t = 10 / 5.0 = 2

From Newton's second law, we know that

force = mass x acceleration

F = ma

F = 2.0 x 2 = 4.0 m/s

Therefore, the net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.

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The question is incomplete. Your most probably complete question is given below:

What net force is needed to accelerate a 2.0 kg mass from rest to a velocity of 10 m/s in 5.0 s?