Find the area of the circle. Round your answer to the nearest tenth.

Answer:

Area of given figure = 60.8 mm² (Approx.)

Step-by-step explanation:

Given:

Length of figure = 9.3 mm

Width of figure = 7.8 mm

Height of triangular cut = 3 mm

Find:

Area of given figure

Computation:

Area of given figure = [(Length)(Width)] - Area of triangle

Area of given figure = [(9.3)(7.8)] - [(1/2)(b)(h)]

Area of given figure = [(9.3)(7.8)] - [(1/2)(7.8)(3)]

Area of given figure = [(9.3)(7.8)] - [(1/2)(7.8)(3)]

Area of given figure = [72.54] - [(1/2)(7.8)(3)]

Area of given figure = [72.54] - [11.7]

Area of given figure = 60.8 mm² (Approx.)

9514 1404 393

Answer:

  (9/34)√34 ≈ 1.543

Step-by-step explanation:

The second equation can be rewritten as ...

  6x -10y -12 = 0

  3x -5y -6 = 0

  3x -5y = 6

__

The formula for the distance from point (x, y) to line ax+by+c=0 is ...

  d = |ax+by+c|/√(a²+b²)

Then the distance from a point to the first line is ...

  d = |3x -5y +3|/√(3² +(-5)²)

We know from the rearrangement of the second equation that points on its line satisfy (3x-5y) = 6. Substituting this value for (3x -5y) in the distance formula gives ...

  d = |6 +3|/√34

Simplifying and rationalizing the denominator gives a distance of ...

  d = (9/34)√34 ≈ 1.543

Answer:

x = -4, y = 6.

x = 0, y = 7.

x = 4, y = 8.

x = 8, y = 9.

Step-by-step explanation:

We are given the following rule:

[tex]y = \frac{x}{4} + 7[/tex]

To solve this question, we replace x by the asked values.

When x = -4

[tex]y = \frac{-4}{4} + 7 = -1 + 7 = 6[/tex]

So x = -4, y = 6.

When x = 0

[tex]y = \frac{0}{4} + 7 = 0 + 7 = 7[/tex]

So x = 0, y = 7.

When x = 4

[tex]y = \frac{4}{4} + 7 = 1 + 7 = 8[/tex]

So x = 4, y = 8.

When x = 8

[tex]y = \frac{8}{4} + 7 = 2 + 7 = 9[/tex]

So x = 8, y = 9.

Answer:

The answer is 7,953.

Step-by-step explanation :

When you divide like this you are basically being asked how many times something can go into something else. In this case, we are being asked to calculate how many times 1000 can go into 7,953,000. You can use basic math skills or do long division.

I'm going to go with the easier way, basic math skills.

There are three 0's in the back of the number 7,953,000, and notice 1000 has three 0's as well in the back. When you divide those three 0's in the back of both numbers basically cancel out. Well, what does that leave us with?

7953 is what were left with. The answer is 7,953.

Answer:

berg river

Step-by-step explanation:

it has good environmental health

Answer:

B

Step-by-step explanation:

Find the area of the circle with r = 36/2     Area1 =  π r²

divide Area1 by two since the upper part of the figure is a semi-circle

then finally add and area of the rectangle   Area2 = (18)(36)

Total area = Area 1 + Area 2

Answer:

1156.7 cm^2

Step-by-step explanation:

for finding area of semi circle

diameter=36 cm

radius=diameter/2

=36/2

=18 cm

area of semi circle=πr^2/2

=3.14*(18)^2/2

=3.14*324/2

=1017.36/2

=508.68 cm^2

area of rectangle=length*breadth

=18 cm *36 cm

=648 cm^2

area of the figure=area of semi circle + area of rectangle

=508.68 + 648

=1156.68

=1156.7 cm^2

Answer:

The three sides are 27 feet, 15 feet, 13 feet

Step-by-step explanation:

Let second side of a triangle be = a

Let one side be 12 feet shorter than the second side = (a - 12)

Let the third side be 2 feet shorter than the second side= (a - 12) - 2 =(a - 14)

Perimeter of triangle = Sum of length of all 3 sides

55 = a + (a - 12) + (a - 14)

55 = a + a + a - 12 - 14

55 = 3a - 26

55 + 26 = 3a

81 = 3a

a = 27

Length of one side, a - 12 = 27 - 12 = 15 feet

Length of second side, a = 27 feet

Length of third side, a - 14 = 27 - 14 = 13 feet

The answer is attached. I hope this helps answer your question!

Answer:

35 ft^2

Step-by-step explanation:

A = wl

A = 7 * 5

A = 35

Step-by-step explanation:

what is your question please

Answer: GIVEN : f(x)= -3x+1

f(x)= -5

REQUIRE:  x=?

CALCULATION:

f(x)= -3x+1

As, given f(x)= -5.

Hence,

-5= -3x+1

OR

-3x+1= -5

-3x= -5-1

-3x=-6

x= -6/-3

x= 2

Answer:

Your measurements; Area = 216.108 cm²

Another student's measurements; Area = 216.9404 cm²

- Difference in area could be as a result of human error or perhaps that they made use of different measuring tools.

Step-by-step explanation:

For Your measurements;

Length of rectangle = 20.70 cm

Width of rectangle = 10.44 cm

Area of rectangle is given by; A = length × width = 20.7 × 10.44 = 216.108 cm²

For Another student's measurements;

Length of rectangle = 20.74 cm

Width of rectangle = 10.46 cm

Area = 20.74 × 10.46

Area = 216.9404 cm²

The areas they both obtained are not of equal values and this could be as a result of human error or perhaps that they used different measuring tools.

dogs alpha an 125789 SMS Skoda Eloisa 124579 harm Occam

Answer:

48

Step-by-step explanation:

correct on Edge 2021

Answer:

.216165788

.582225057

.417774943

Step-by-step explanation:

We need to use a binomial distribution here

A.

10C5*.58⁵*(1-.58)⁵= .216165788

B.

I honestly think the fastest way to solve this is adding the probabiblity of exactly 6,7,8,9,10

which means we write

10C6*.58⁶*(1-.58)⁴+10C7*.58⁷*(1-.58)³+10C8*.58⁸*(1-.58)²+10C9*.58⁹*(1-.58)+10C10*.58¹⁰= .582225057

C.

To solve this just take the compliment of answer B

1-.582225057= .417774943

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

[tex]\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right][/tex]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Answer:

D. a line that shows only one solution to the equation

Step-by-step explanation:

I hope this helps uwu.

Answer:

0.12

Step-by-step explanation:

Total number of questions in the book = 10

Number of questions answered correctly by Alice = 6

Number of questions answered correctly by Bob = 8

Probability of Alice answering a question correctly = 0.6

Probability of Alice answering a question incorrectly = 1- 0.6 = 0.4

Probability of Bob answering a question correctly = 0.8

Probability of Bob answering a question incorrectly = 1- 0.8 = 0.2

Probability that there exists at least one question on the test which is answered correctly by Alice but not by Bob = 0.6 *0.2 = 0.12

Answer:

A = [tex]\frac{3}{4}[/tex] [tex]\sqrt[3]{B}[/tex]

Step-by-step explanation:

Given A varies directly as [tex]\sqrt[3]{B}[/tex] then the equation relating them is

A = k [tex]\sqrt[3]{B}[/tex] ← k is the constant of variation

To find k use the condition A = 3 when B = 64 , then

3 = k [tex]\sqrt[3]{64}[/tex] = 4k ( divide both sides by 4 )

[tex]\frac{3}{4}[/tex] = k

A = [tex]\frac{3}{4}[/tex] [tex]\sqrt[3]{B}[/tex] ← equation of variation

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Given:

[tex]\to x^2+y^2=49[/tex]

When

 [tex]x=0\\\\0^2+y^2=49\\\\y^2=49\\\\y= \pm 7[/tex]

So, order pass [tex](0,\pm 7)[/tex]

Similarly When  

[tex]y=0\\\\x^2+0^2=49\\\\x^2=49\\\\x= \pm 7[/tex]

So, order pass [tex](\pm 7,0)[/tex]  

[tex]x \ \ \ \ \ \ \ 7 \ \ \ \ \ \ \ -7\ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ 0 \\\\y \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ 7 \ \ \ \ \ \ \ -7 \\\\[/tex]

Answer:

[tex]{ \tt{3 \frac{4}{9} \div (5 \frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{31}{12} ) + \frac{59}{10} }} \\ \\ { \tt{ = \frac{4}{3} + \frac{59}{10} }} \\ \\ { \bf{ = \frac{217}{30} }} \\ \\ { \boxed{ \tt{answer : 7 \frac{7}{30} }}} \\ \\ { \underline{ \blue{ \tt{becker ⚜jnr}}}}[/tex]

Answer:

[tex]7 \frac{7}{30}[/tex]

Step-by-step explanation:

[tex]3 \frac{4}{9} \div ( 5\frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10}\\\\\frac{31}{9} \div (\frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} \\\\\\Solving \ using \ BODMAS\\\\First \ Solve \ expression \ inside \ Bracket \\\\\frac{31}{9} \div (\frac{(16 \times 4) - ( 11 \times 3)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div (\frac{64- 33)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div \frac{31}{12} + \frac{59}{10} \\\\\\ \\\\\\Next \ solve \ Dvision \\\\\frac{\frac{31}{9}}{\frac{31}{12}} + \frac{59}{10}\\\\[/tex]

[tex](\frac{31}{9}} \times {\frac{12}{31}) + \frac{59}{10}[/tex]

[tex]\frac{4}{3} + \frac{59}{10}\\\\ Now \ solve \ final \ expression \\\\\\\frac{(4 \times 10) + ( 59 \times 3)}{30}\\\\\frac{40 + 177}{30}\\\\\frac{217}{30}\\\\7 \frac{7}{30}[/tex]

Answer:

[tex]\sigma_x = 2000[/tex]

Step-by-step explanation:

Given

[tex]\sigma = 4000[/tex]

[tex]n = 4[/tex]

Required

The sample standard deviation

The sample standard deviation cannot be calculated directly. However, we can use the value of standard error because standard error approximates to sample standard deviation.

So, we have:

[tex]\sigma_x = \frac{\sigma}{\sqrt n}[/tex]

[tex]\sigma_x = \frac{4000}{\sqrt 4}[/tex]

[tex]\sigma_x = \frac{4000}{2}[/tex]

[tex]\sigma_x = 2000[/tex]

Hence, the sample standard deviation is 2000

Answer:

84 sq meters

Step-by-step explanation:

1. Approach

In order to solve this problem, one will have to divide the figure up into simple shapes. A picture is attached showing how the shape is divided up for this answer. Find the area of each region, then add up the results to find the total area.

2. Area of Region 1

As one can see, the length of (Region 1), as given is (6), the width is (3). To find the area multiply the length by the width.

Length * width

6 * 3

= 18

3. Area of Region 2

In (Region 2), the length is given, (12). However, one must find the width, this would be the size of the total side, minus the width of (Region 1). Multiply the length by the side to find the area.

Length * width

= 12 * (8 - 3)

= 12 * 5

= 60

4. Area of Region 3

In (Region 3), the length of the figure is (2), the width is (3). To find the area, multiply the length by the width.

Length * width

= 2 * 3

= 6

5. Total area

Now add up the area of each region to find the total rea,

(Region 1) + (Region 2) + ( Region 3)

= 18 + 60 + 6

= 84

Answer:

x = 5 is a vertical line at x = 5

Answer:

the slope is 8/7 and the y-intercept is 300

Step-by-step explanation:

The y-intercept is 300 because that is where the estimated line of bets fit (the red line) crosses the y-intercept.

9514 1404 393

Answer:

  C = 9x +2280

Step-by-step explanation:

The 2-point form of the equation for a line can be a place to start.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  C = (4800 -3000)/(280 -80)(x -80) +3000 . . . . . use given values

  C = 1800/200(x -80) +3000 . . . . simplify some

  C = 9x -720 +3000 . . . . eliminate parentheses

  C = 9x +2280

Answer:

3.5h-3.1d-14

Step-by-step explanation:

6h+​(−8.1d​)−14+5d−2.5h

Combine like terms

6h -2.5h  -8.1d +5d  -14

3.5h-3.1d-14

r should be 4/7. You're comparing the given series to a geometric series that converges. By the limit comparison test, you have

[tex]\displaystyle\lim_{n\to\infty}\frac{\frac{4^n+7}{7^n}}{\frac{4^n}{7^n}}=\lim_{n\to\infty}\frac{4^n+7}{4^n}=\lim_{n\to\infty}\left(1+\frac7{4^n}\right)=1[/tex]

and since this limit is positive and finite, and the series you're comparing to is convergent, then the first series must also be convergent.