find the components of each vector

The increase in the temperature of the water, given that 115000 J of heat energy was supplied to it is 50.95 °C

From the question given above, the following were obtained:

The increase in the temperature of the water can be obtained as follow:

Q = MCΔT

115000 = 0.54 × 4180 × ΔT

115000 = 2257.2 × ΔT

Divide both sides by 2257.2

ΔT = 115000 / 2257.2

ΔT = 50.95 °C

From the above calculation, we can conclude that the temperature increase of the water is 50.95 °C

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An object under uniform circular motion experiences a centripetal acceleration, directed towards the center of the circular trajectory.

Therefore, the correct option is:

We are told that an elevator falls freely, which means that the only force acting upon it is its weight. The weight is defined as:

Where "m" is the mass and "g" is the acceleration of gravity. Replacing the given values:

Therefore, the force that acts upon the elevator is 1000N.

a) The kinetic energy of the spring is 0.2 J

b) Speed of the dart  is 2.8 m/s

Let us recall that work is said to be done when the force that is applied moves a distance in the direction of the force. Now we know that if we compress a spring, then the spring would have a potential energy called the elastic potential energy.

Let us now answer the questions;

a) Given the fact that energy is neither created nor destroyed but is converted from one form to the other, the kinetic energy of the dart is  0.2 J. This is from the law of the conservation of energy as we all know it.

b) Recall that;

KE = 1/2mv^2

KE = kinetic energy

m = mass of the object

v = speed of the object

v = √2KE/m

v =  √2 * 0.2/0.05

v = 2.8 m/s

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Answer:

the value of ksp is 7.8×18

The initial speed of the Snow Leopard was 35m/s if it jumped at an angle of 35 degrees.

When a leopard jumps. It's path will be a parabola which is corresponding to a projectile.

The angle at which the leopard jumped is 35°.

The horizontal range of the projectile is 96 meters.

We can use the formula for horizontal range R of the projectile,

R = U²sin2A/g

Where,

U is the initial velocity of leopard,

A is the angles at which the leopard jumped.

g is acceleration due to gravity having value 9.8m/s².

Putting all the values,

96 = U²sin(70°)/9.8

U² = 96×9.8/0.77

U² = 1222

U = 34.9 m/s

Nearly 35 m/s.

The initial speed of leopard is 35m/s.

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Answer: C. Determine how long the reaction will take.

ANSWER

Wave A = Lowest volume with the lowest pitch

Wave B = Highest volume with the lowest pitch

Wave C = Lowest volume with the highest pitch

Wave D = Highest volume with the highest pitch

EXPLANATION

We want to attach the correct option to the correct figure.

From the question, the amplitude is proportional to volume, and frequency is given to be perceived as pitch.

On a wave graph, the amplitude is represented on the y-axis while the period is represented on the x-axis.

The relationship between period and frequency is an inverted relationship, which means that for a wave, the higher the period, the lower the frequency, and vice versa.

This means that from the figures given, we can conclude that:

Wave A = Lowest volume with the lowest pitch

Wave B = Highest volume with the lowest pitch

Wave C = Lowest volume with the highest pitch

Wave D = Highest volume with the highest pitch

That is the answer.

Answer:

Explanation:

From the given information if we assume that the runner didn't  come back to her original position.

Her initial velocity = 0 m/s

Final Velocity = 9.6 m/s

Time Taken = 2 seconds

She started from rest therefore her initial time would be 0 seconds.

We know that,

Average acceleration = (final velocity - initial velocity)/(final time - initial time)

=(v-u)/t1-t0

=(9.6 - 0)/(2-0) m/s^2

=4.8 m/s^2

A. The acceleration of the electron is 5.71×10¹⁴ m/s²

B. The time taken for the electron to reach the grid is 7.01×10⁻⁹ s

C. The net force of the electron is 5.20×10⁻¹⁶ N

A. How to determine the acceleration of the electron

The acceleration can be obtained as illustrated below:

v² = u² + 2as

(4.0×10⁶)² = 0² + (2 × a × 0.014)

(4.0×10⁶)² = 0 + 0.028a

(4.0×10⁶)² = 0.028a

Divide both side by 0.028

a = (4.0×10⁶)² / 0.028

a = 5.71×10¹⁴ m/s²

B. How to determine the time

The time taken for the electron to reach the grid can be obtained as follow:

a = (v – u) / t

5.71×10¹⁴ = (4.0×10⁶ – 0) / t

5.71×10¹⁴ = 4.0×10⁶ / t

Cross multiply

5.71×10¹⁴ × t = 4.0×10⁶

Divide both sides by 5.71×10¹⁴

t = 4.0×10⁶ / 5.71×10¹⁴

t = 7.01×10⁻⁹ s

C. How to determine the net force

Net force = mass × acceleration

Net force = 9.11×10⁻³¹ × 5.71×10¹⁴

Net force = 5.20×10⁻¹⁶ N

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1) The time taken is  6.37 s

2) The velocity at maximum height is 0 m/s

3) The initial velocity is 62.4 m/s.

4) The maximum height is  198.66 m

Let us recall that in this case, we have to use the equation of the motion that occurs under gravity In this case we have to take into account the the upwards motion is negative in the opposite direction as gravity and the down wards motion is positive and in the same direction as gravity.

1) Given that;

time is the same as the time taken to go up and come down thus the time taken to reach the maximum height is 12.74 seconds/2 = 6.37 s

2) The velocity of the rocket at the maximum height is zero because it momentarily comes to rest.

3) The initial velocity of the rocket is;

v = u - gt

At the maximum height v = 0 m/s

u = gt

u = 9.8 m/s^2 *  6.37 s

u = 62.4 m/s

4) The maximum height is obtained from;

v^2 = u^2 - 2gh

v = 0 m/s

u^2 = 2gh

h = u^2/2g

h = (62.4 m/s)^2/2 * 9.8 m/s^2

h = 198.66 m

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Answer:

according to me the fourth one is the right answer

The acceleration of children will be 0.136m/s²

We are given that,

The first child exert force= F₁ =  75.0 N  

The second child exerts force = F₂ = 90.0N

The friction force = Fₓ = 12.0 N

The mass of the third child = m = 22.0 kg

The first child & second child exert force 75 N and 90 N which are acting in opposite direction.

Therefore, the net force = F₂ - F₁ = 90 - 75 = 15 N

Friction force Fₓ would be act in the direction opposite to the direction of net force. So that the friction force will act in the direction in which the first child F₁  (75 N) is acting .

Total force acting in the direction of the second child= F₁+ Fₓ=75+12= 87 N

Net force acing on the third child F = 90 - 87 = 3 N  

Therefore, the acceleration of the child can be calculated by the Newton's second law of motion i.e.

F = ma

a = F /m

a = 3N /22kg

a = 0.136 m/s²

Thus, the acceleration of the child will be  0.136 m/s²

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The magnitude of the linear acceleration is zero for all points on the chain. The angular accelerations of the two sprockets can be related as  α[tex]_{Front}[/tex] / α[tex]_{Rear}[/tex] = ω[tex]_{Front}[/tex] * t[tex]_{Rear}[/tex] / ω[tex]_{Rear}[/tex] * t[tex]_{Front}[/tex]

There are two set of point that is needed to be taken into consideration. The points in between the two sprockets and points in which the chain is in contact with the sprocket. In the former set of points, the linear velocity is constant. So its linear acceleration will be zero. In the latter set of points, the tangential velocity ( Linear velocity in circular motion ) is constant. So the tangential acceleration ( Linear acceleration in circular motion ) will be zero.

Since the chain is constantly changing direction while on the sprocket, it will always have angular acceleration.

α = ω / t

α = Angular acceleration

ω = Angular velocity

t = Time

α[tex]_{Front}[/tex] / α[tex]_{Rear}[/tex] = ω[tex]_{Front}[/tex] * t[tex]_{Rear}[/tex] / ω[tex]_{Rear}[/tex] * t[tex]_{Front}[/tex]

Therefore,

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The arrow be released at an angle of 18 degrees to hit the bull's-eye if its initial speed is 36.0 m/s. The arrow go over the branch.

The path of the arrow is projectile when it is launched by the archer.

The horizontal distance to be covered by the arrow is 77 meters.

The initial velocity is 36m/s while releasing.

(a) We can use the formula,

R = U²sin2A/g

Where,

U is the initial velocity of leopard,

A is the angles at which the leopard jumped.

g is acceleration due to gravity having value 9.8m/s².

Putting all the values,

77 = (36)²sin(2A)/9.8

Sin(2A) = 77×9.8/36×36

Sin(2A) = 0.58

2A = 36°

A = 18°

The angles at which the arrow should be launcher is 18°.

(b) The length of the branch of the tree is 3.5 meters.

Whether is should come it the way or not,

We have to find the height of the arrow.

H = U²Sin(A)/2g.

Where H is the height,

H = 36×36Sin(18°)/2×9.8

H = 36×36×0.3/2×9.8

H = 19.38 meters.

The height of arrow is more than of the height of branch of tree. So it will go over the branch.

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        A magnetic core made of a magnetic material, such as iron, that is encircled by a wire coil. The core is magnetized by an electric current that is passed through the coil.

    Permanent magnets are not the same as electromagnets. Coils of wire with electricity running through them make up electromagnets. An electromagnet's wire coils act like magnets when an electric current flows through them because moving charges produce magnetic fields.

      Electrons are pushed and pulled by moving magnetic fields. Electrons in metals like copper and aluminum are slackly held. The electrons in the wire are pushed by rotating a coil of wire around a magnet, or vice versa, and an electrical current is produced.

     Electromagnets are a component of every machine with an electric motor. Hairdryers, CD players, power drills, electric saws, and electric mixers are a few further examples. 

   Magnets produced by electric fields are known as electromagnets. The fact that they can be turned on and off gives them an edge over normal magnets. By wrapping a wire around an iron nail and passing current through it, electromagnets can be made.

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The equivalent resistance for the entire circuit is equal to 1830 Ω.

In a series combination of resistors, the resistors are connected end-to-end. Assume two resistors, R₁ and R₂ which are connected with each other in a series then their effective resistance:

Total Resistance, R =  R₁ + R₂

In a parallel combination of resistors, the resistors are connected parallel to each other.

[tex]\displaystyle \frac{1}{R} =\frac{1}{R_1} +\frac{1}{R_2}[/tex]

The resistance in parallel, R₁ = 60 Ω , R₂ = 60 Ω , R₃ = 30 Ω

The equivalent resistance for the entire circuit will be given by:

[tex]R_{eq} =R' + R_3[/tex]

[tex]\displaystyle R_{eq} = \frac{R_1R_2}{R_1+R_2} + R_3[/tex]

[tex]\displaystyle R_{eq} = \frac{60\times 60}{1+1} + 30[/tex]

R = 3600/2 +30

R = 1800 +30

R = 1830 Ω ​

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Answer:

A

Explanation:

What is the Ksp expression for Ni3(PO4)2(s) in water? A) Ksp = [Ni2+]3[PO4]2(s) B) Ksp = [Ni2+]2[PO43-13 C) Ksp= (3x[Ni2+])(2x[PO43-]) C) Ks

Answer 0 votes

Answe

A) Ksp = [Ni2+]3[PO4]2(s)

Answer:

F=ma

=(4,91kg)(3,37m/s)

=16,55N

Explanation:

Free body diagram- the only 2 forces that are acting on the bucket is the tension in the rope and the weight

The tension in the rope could also be called "Force applied" and is acting upwards since it's pulling the bucket upwards.

There also has to be a force acting downwards on the bucket and that is the Weight.

Yes, if one follows the mentioned steps, they could determine the toy car's acceleration from the data of time taken in the video.

a = v / t

v = d / t

a = Acceleration

v = Velocity

d = Distance

t = Time

d = 1 m

Let the video time recorded from the video be x s.

t = x s

v = 1 / x

a = 1 / x / x

a = 1 / x² m / s²

Velocity is the rate of change of distance. Its unit is m / s. It is denoted as v. Acceleration is defined as the rate of change in velocity with respect to time. Its unit is m / s². It is denoted as a.

Therefore, if I follow steps given, I could determine the acceleration of the toy car as 1 / x² m / s²

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A substance that gains an electron in a reaction is called as oxidizing agent.

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If you are on 4.16 Chemical Reactions and have 18 questions, then go to the following on Quizlet for further help. Thanks and good luck!

Quizlet - "4.6 Chemical Reactions UT"

h t t p s : / / q u i z l e t . c o m / _ c 7 3 1 u j ? x = 1 q q t & i = 3 8 n a a s

The resultant force of the two teams in the tug of war obtained by adding the vectors is 10 N.

The resultant force of two or more forces is the single force that will produce the same affect as the two forces acting together.

The resultant force of the two teams performing tug of war is calculated as follows;

R = Rb - Rr

where;

Substitute the given parameters and solve for the resultant force.

R = 30 N - 20 N

R = 10 N

Graphically, we can present the resultant force as follows;

------10 N------>          =   ---------30 N-------------------->  -  <-----20 N---------------

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ANSWER:

39.2 m/s^2

STEP-BY-STEP EXPLANATION:

We have to acceleration due to gravity at the surface of planet:

Where,

Mp = mass of planet

ρp = density of planet

Rp = radius of planet

Given:

ρp = 2ρe, Rp = 2Re

where,

ρe = density of earth

Re = radius of earth

Replacing:

Therefore the acceleration due to gravity on the planet is 39.2 m/s^2

The motion of an object with constant acceleration exists defined by a set of equations comprehended as the kinematic equations. The distance of the drone with respect to the ground exists 13.95886 m/s.

The motion of an object with constant acceleration exists defined by a set of equations comprehended as the kinematic equations. Integrals, derivatives, and rates of change must all be understood in order to solve kinematics problems.

A branch of physics named kinematics, which originated in classical mechanics, described how points, bodies, and systems of bodies move without taking into account the forces that exists responsible for their motion.

If a drone flies 13.8 m/s due East with respect to the wind and the wind is blowing 2.1 m/s due North, the speed of the drone with respect to the ground is its displacement.

Displacement is calculated using Pythagoras theorem.

d² = 13.8 ² + 2.1²

simplifying the above equation, we get

d² = 190.44 + 4.41

d² = 194.85

Square root both sides, we get

√d² = √194.85

d = 13.95886 m/s

Therefore, the distance of the drone with respect to the ground is 13.95886 m/s.

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(1) Concurrent forces give one net resultant force. (TRUE)

(2) Newton’s first law of motion is the principle of momentum. (FALSE)

(3) In Newton’s second law, F = m * a, F is measured in Newton. (TRUE)

(4) Mass and weight are interchangeable. (FALSE)

(5) The product of mass and velocity for an object gives us its momentum.

(6) The force of gravity on an object determines its weight.

If the forces applied to a body are such that their lines of action meet at a single point, then they are called concurrent forces.

Concurrent forces give one net resultant force. (true)

The Newton's second law of motion states that, the force applied to an object is directly proportional to the change in momentum of the object.

F ∝ Δmv

F = mv/t

F = m(v/t)

F = ma

Newton’s first law of motion is the principle of momentum. (false)

In Newton’s second law, F = ma, F is measured in Newton. This statement is true.

Mass is the quantity of matter contained in a body while weight is the measure of the effect of gravitation force on an object.

Mass and weight are interchangeable. (false)

The product of mass and velocity for an object gives us its momentum.

The force of gravity on an object determines its weight.

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The rock possesses potential energy for gravitation. Fundamentally, gravity could cause the rock to tumble.

Height gain (h) and gravitational acceleration (g) serve as symbols for the change in gravitational potential energy (PEg). Any item close to the planet's surface has gravitational potential energy that is determined by its location within the mass-Earth system.

The rock possesses potential energy for gravitation. Fundamentally, gravity could cause the rock to tumble.

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Divide 66 words by 3 minutes to find the typing rate per minute. Then, multiply the typing rate by 5 minutes and 10 minutes to find how many words she can type during those time intervals, respectively.

Typing rate:

Words typed in 5 minutes:

Words typed in 10 minutes:

Therefore, Tia can type 110 words in 5 minutes and 220 words in 10 minutes.

36.8 (m) are the x- and y-components of the rocket's velocity 12.2 s after it is fired.

0.41 m / s³ is the position vector of the rocket 12.2 s after it is fired

Any process where the velocity varies is referred to as acceleration. There are only two ways to accelerate: increasing your speed or changing your direction, or altering both. This happens because speed is both a speed and a guidance.

This is an exercise in kinematics in two dimensions, the easiest way to solve it is to work each axis independently

To find the other two constants we must know the acceleration formula,

a = dv / dt = d²v / dt²

vₓ = dx / dt = 2Bt

d²x / dt² = 2B

aₓ = 2B= dy / dt = 3D t2

d²y / dt² = 6D t

They give us the acceleration for time t = 1.20s

aₓ = 2B = 3.30 m / s2

B = 1.65 m / s²

ay = 6D t = 2.50

D = 3.00 / 6 1

D = 0.41 m / s³

The acceleration vector is

a = aₓ i ^ +  j ^

a = 3.3 i ^ + 2.5 t j ^

v = vx i ^ + vyj ^

v = 3.3 t i ^ + 1.25 t²

velocity for t= 12.2 s

v = 3.3 t i ^ + 1.25 t²

v = 3.3 10 i^ + 1.5 10² j^

v= (33 i^ + 150 j^ ) m/s

Position for t = 12.2 s

x = 1.65 t² = 7 10²

x = 165 m

y = 36.8 +0.41 t³ = 36.8 + 0.41 10³

y = 446.8 m

D = (165 i ^ + 446.8 j ^) m

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Answer:

vf=vi+at

Explanation:

downwards is positive

vf=vi+at

=10+9,8×2,5

=34,5m/s

The magnitude and direction of the plane's total displacement are 7.66 km and angle of 26.2 degree respectively.

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