Chris, this is the solution to the exercise:
• Point 1 = (7, 6)
,• Point 2, (0, 2)
Now, let's use the formula to calculate the distance between the two points, as follows:
d = √(0 - 7)² + (2 - 6)²
d = √-7² + (-4)
d = √49 + 16
d = √65
d = 8.0622
d = 8.1 (rounding to the nearest tenth)
I don’t know the rest of the definition of my vocabulary
Step 1
Given;
Step 2
Two angles are called supplementary when their measures add up to 180 degrees.
Two angles are called complementary when their measures add to 90 degrees.
The two angles are said to be adjacent angles when they share the common vertex and side. The endpoint of the rays, forming the sides of an angle, is called the vertex of an angle. Adjacent angles can be complementary angles or supplementary angles when they share the common vertex and side.
Answer;
Two angles are called supplementary when their measures add up to 180 degrees.
Two angles are called complementary when their measures add to 90 degrees.
The two angles are said to be adjacent angles when they share the common vertex and side.
find the value or measure. Assume all lines that appear to be tangent are tangent. X=
According to the secant-tangent theorem, we have the following expression:
[tex](x+3)^2=10.8(19.2+10.8)[/tex]Now, we solve for x.
[tex]\begin{gathered} x^2+6x+9=10.8(30) \\ x^2+6x+9=324 \\ x^2+6x+9-324=0 \\ x^2+6x-315=0 \end{gathered}[/tex]Then, we use the quadratic formula:
[tex]x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Where a = 1, b = 6, and c = -315.
[tex]\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}[/tex]Hence, the answer is 15 because lengths can't be negative.11 to the power of 2
When a number is raised to a power, it simply refers to the number of times that number is multiplied by itself.
Applying that logic here, 11 to the power of 2 is simply
[tex]11\times11[/tex]and the answer is
[tex]=121[/tex]Therefore, 11 to the power of 2 is 121.
A boy gets #2.00 per week as pocket money. His sister gets only #1.60 per week
Find the ratio of the boy's allowance to his sister's. If his sister gets 20 k more per week,what will be the new ratio?
The Ratio of the boy's allowance to his sister's is 5 : 4.
The new Ratio is 1 : 10000.
What is definition of ratio?The quotient of two mathematical expressions, 1a. b: the proportion between two or more items in terms of quantity, amount, or size.What does the arithmetic term "ratio" mean?An ordered pair of numbers a and b, represented as a / b, is a ratio if b is not equal to 0. A proportion is an equation that sets two ratios at the same value. For instance, if there is 1 boy and 3 girls, you may express the ratio as 1: 3 (there are 3 girls for every boy), meaning that there are 1 in 4 boys and 3 in 4 girls.To learn more about :Ratio
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;
Jackson is comparison shopping for orange juice. He created a table to help him decide which package was the best deal.
Verify
REmember that the best deal is the deal with the less unit rate
so the order is
89 0z bottle is the best deal
64 oz cartoon
59 oz bottle
case of 24 10 oz bottles
10 oz bottle
therefore
Jason is not correct
Walter is a waiter at the Towne Diner. He earns a daily wage of $50, plus tips that are equal to 15% of the total cost of the dinner he serves. What was the total cost of the dinners he served if he earned $170 on Tuesday?
Jason, this is the solution:
Walter's daily wage = $ 50
Tips = 15% of the total cost of the dinner he serves
Tuesday earnings = $ 170
Therefore,
Tips = 170 - 50
Tips = 120
For finding the cost of the dinners, we use Direct Rule of Three, as follows:
Percentage Cost
15 120
100 x
_____________________
120 * 100 = 15 * x
12,000 = 15x
Dividing by 15 at both sides:
15x/15 = 12,000/15
x = 800
The total cost of the dinners Walter serverd on Tuesday was $ 800
I don’t know how to find the median and the mode HELPP
First, let's write the data set in crescent order:
[tex]35,35,44,50,50,50,56,60,65,70,86,90,110[/tex]The mean is given by the sum of all values divided by the number of values:
[tex]\begin{gathered} mean=\frac{35+35+44+50+50+50+56+60+65+70+86+90+110}{13}\\ \\ mean=\frac{801}{13}\\ \\ mean=61.62 \end{gathered}[/tex]The median is given by the central value of the set in crescent order. Since this set has 13 values, the median is the 7th value:
[tex]median=56[/tex]The mode is the value that repeats the most. Looking at the set, the value that repeats the most (three times) is 50, so the mode is 50.
If the proportion of the total disposable income spent on consumer goods and services is 91.6 percent and if consumers spend 82.0
percent of each additional dollar, what is
Instructions: Round your responses to three decimal places.
a. the APC?
b. the APS?
c. the MPC?
d. the MPS?
a) The Average Propensity to Consume (APC), rounded to three decimal places, is 0.916.
b) The Average Propensity to Save (APS), rounded to three decimal places, is 0.084.
c) The Marginal Propensity to Consume (MPC), rounded to three decimal places, is 0.820.
d) The Marginal Propensity to Save (MPS), rounded to three decimal places, is 0.180.
What do these economic indexes mean?The average propensity to consume is the ratio of consumption expenditures to the total consumers' disposable income.
The average propensity to save is the inverse of the APC. It shows the rate of or total disposable income reserved instead of being consumed.
The marginal propensity to consume is the ratio of consumption based on additional income.
The marginal propensity to save is the inverse of the MPC, showing the percentage of the additional income saved instead of being consumed.
APC = 91.6%
= 0.916
APS = 1 - APC
= 0.084 (1 - 0.916)
MPC = 82%
= 0.820
MPS = 1 - MPC
= 0.180 (1 - 0.820)
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Determine whether the following graph can represent a normal curve.
The correct options regarding whether the graph can represent a normal curve are given as follows:
C. Yes, because the graph may not satisfy all of the criteria for a normal curve, but it satisfied at least one of them.D. No, because the graph is not always greater or equal to zero.What are the characteristics of a normal curve?The characteristics of a normal curve are defined as follows:
Single peak at the center of the distribution, which is also the mean of the distribution.The function is symmetric.The values of the tails at the distribution are close to 0.The values are all equal or greater to zero.In the context of this problem, these two first options are satisfied. However, the distribution contains negative values, meaning that the graph is not always greater or equal to zero.
Hence, options C and D are correct.
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Solve the problems fill in the blanks show you work I NEED HELP!
The fill in the blanks (that uses division) can be filled as -1.2([tex](\frac{2}{5} )[/tex] ÷ -2, -0.48÷-2 and 0.24.
According to the question,
We have the following information:
-1.2 [tex](\frac{2}{5} )[/tex] ÷ -2
Now, we have to solve this problem and fill the blanks at the same time.
Now, the first step would be to write the question.
So, for the first blank we have:
-1.2 [tex](\frac{2}{5} )[/tex] ÷ -2
Now, the required number is (2/5).
Now, the next step is to multiply -1.2 with 2/5:
-2.4/5
-0.48
So, the second blank can be filled by -0.48.
Now, the third step would be to divide -0.48 by -2:
-0.48÷-2
0.24
So, the next blank can be filled by 0.24.
Hence, the numbers in the blanks are [tex]\frac{2}{5}[/tex], -0.48 and 0.24 respectively.
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How many gallons of gas will Justin need to drive 120 miles? Use a table or proportionas
As you can see, both variables are directly proportional.
Thus, the given line should have the form:
[tex]y=kx[/tex]Where k is the proportionality constant.
To find the number of gallons of gas needed to drive 120 miles, we should find k first.
Notice that we need 1 gallon of gas to drive 25 miles and 2 gallons of gas to drive 50 miles. The rate of change (k) between these variables is:
[tex]\frac{50-25}{2-1}=25\frac{gallons}{\text{mile}}[/tex]This means that it takes 25 gallons to drive each mile.
Now, we could replace:
[tex]\begin{gathered} 120=25x \\ x=\frac{120}{25}=4.8\text{gallons} \end{gathered}[/tex]Therefore, Justin needs 4.8 gallons to drive 120 miles.
Find the volume of the following triangular prism. *15 points5 in6,1 in13 in7 in215.5 cubic inches220.5 cubic inches225.5 cubic inches227.5 cubic inches
Given:
The length of the base of the triangular base of the prism, b=7 in.
The altitude of the triangular base, l=5 in.
The height of the prism, h=13 in.
Now, the volume of the prism can be calculated as,
[tex]\begin{gathered} V=\text{ Base Area}\times height \\ =\frac{1}{2}bl\times h \\ =\frac{1}{2}\times7\times5\times13 \\ =227.5\text{ cu. in} \end{gathered}[/tex]Therefore, the volume of the triangular prism is 227.5 cu. in.
The investment you make into a start-up company is also known as ____.
The investment you make into a start-up company is also known as Venture capital.
Answer: Venture capital
Solve the following Let f(x) = | 1-7x /3 | find all of x for which f (x) = 3
Given:
[tex]f(x)=|\frac{1-7x}{3}|[/tex]To find the values of x when f(x)=3, we apply below absolute rule:
If |u|=a, a>0 then, u=a or u= -a
Based on the above rule, our equations would be:
[tex]1-\frac{7x}{3}=3[/tex]And,
[tex]1-\frac{7x}{3}=-3[/tex]Next, we find x for 1-7x/3=3:
[tex]\begin{gathered} 1-\frac{7x}{3}=3 \\ \text{Simplify and rearrange:} \\ \frac{7x}{3}=1-3 \\ \frac{7x}{3}=-2 \\ 7x=-2(3) \\ 7x=-6 \\ x=-\frac{6}{7} \end{gathered}[/tex]Then, we find x for 1-7x/3=-3:
[tex]\begin{gathered} 1-\frac{7x}{3}=-3 \\ \text{Simplify and rearrange} \\ \frac{7x}{3}=1+3 \\ \frac{7x}{3}=4 \\ 7x=4(3) \\ 7x=12 \\ x=\frac{12}{7} \end{gathered}[/tex]Therefore, the answer is A. The solution set is
[tex]\lbrace-\frac{6}{7},\frac{12}{7}\rbrace[/tex]What is the graph of the solution to the following compound inequality?5x - 1 < 19 and -3- X+1s1
on5x - 1 < 19
To solve this inequality add 1 to both sides
[tex]\begin{gathered} 5x-1+1<19+1 \\ 5x<20 \end{gathered}[/tex]Now divide both sides by 5
[tex]\begin{gathered} \frac{5x}{5}<\frac{20}{5} \\ x<4 \end{gathered}[/tex]The solutions lie in the area left to the number 4
For the second inequality
[tex]-3-x+1\leq1[/tex]Add first we will add the like terms in the left side
[tex]\begin{gathered} (-3+1)-x\leq1 \\ -2-x\leq1 \end{gathered}[/tex]Now add 2 for both sides
[tex]\begin{gathered} -2+2-x\leq1+2 \\ -x\leq3 \end{gathered}[/tex]We need to divide both sides by -1, but we should reverse the sign of inequality
[tex]\begin{gathered} \frac{-x}{-1}\ge\frac{3}{-1} \\ x\ge-3 \end{gathered}[/tex]We reversed the sign of inequality when divides it by -ve number
Since 2 < 3
Then if we divide both sides by -1, then it will be
-2 < -3 which is wrong -2 greater than -3, then we should reverse the sign of inequality if we multiply or divide it by a negative number
Then the solutions of the 2nd inequality lie right to -3
Let us draw them
The red part is the solution to the 1st inequality
The blue par is the solution to the 2nd inequality
The area with the 2 colors is the area of the common solution of both inequalities
Which expression is equal to log(xy / z) ?
The expression that can be said to as equal to log(xy / z) is the expression logx + logy - logz and this can be found out through the logarithmic identities.
What is the basic log function?The “basic” logarithmic function can be seen as the the function, y=logbx, where x, b>0 and b≠1.
What are the 3 types of logarithms?In the kind of complex analysis that we come across three types of logarithms namely ln, log and Log are used.
In mathematics log tends to always mean the natural log.
Log is often seen as the main and principal branch that comes under the complex logarithm.
Why do we use log functions?Logarithmic functions are said as important only largely because of their relationship to the kind of exponential functions. Logarithms can also be used to solve any kind of exponential equations and thus help to explore the properties of exponential functions.
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The length of the smaller rectangle is 8 inches and the width is x inches. The length of the larger rectangle is 10 inches and the width is 5 inches. What is the width of the smaller rectangle?
The width of the smaller rectangle is 4 inches.
What is the width of a rectangle?A rectangle has four sides, but because the sides are paired, it only has two distinct dimensions. The width is traditionally the shortest of these two dimensions, but when the rectangle is shown lying on its side, the horizontal side is commonly referred to as the width.
Given:
The dimensions of the smaller rectangle are:
Length = 8 inches
Width = x inches
The dimensions of the larger rectangle are:
Length = 10 inches
Width = 5 inches
Using proportion we determine the value of x,
[tex]\frac{8}{x} = \frac{10}{5}[/tex]
Cross-multiply the terms,
8 × 5 = 10x
x = 40/10 = 4
Therefore, the width of the smaller rectangle is 4 inches.
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(a) Describe in words a sequence of transformations that maps AABC to
AA"B"C".
(b) Write an ordered-pair rule for each transformation in the sequence.
Answer:
(x, y) ⇒ (-x, -y) . . . . . . . reflection across the origin(x, y) ⇒ (x +3, y +1) . . . translation 3 right a 1 upStep-by-step explanation:
You want a sequence of transformations that maps ∆ABC to ∆A'B'C' where the vertices are A(-5, 3), B(-2, 3), C(-4, 1), A'(8, -2), B'(5, -2), and C'(7, 0).
Orientation and scalingSegment AB is a 3-unit line segment directed to the right. Segment A'B' is a 3-unit line segment directed to the left. This means there is no dilation involved in the transformation. At least, the figure has been reflected left-to-right.
Point C is below segment AB, while point C' is above segment A'B'. This means the figure has also been reflected top-to-bottom.
Together these reflections can be accomplished by either of reflection across the origin, or rotation 180° about the origin.
TranslationThe reflected figure would leave A' at (5, -3). Its location at (8, -2) means the figure has also been translated to the right and up.
Translation to the right has been by 8 -5 = 3 units.
Translation up has been by -2 -(-3) = 1 unit.
(a) Description of transformationsTriangle ABC can be transformed to triangle A'B'C' by ...
reflection across the origintranslation 3 units right and 1 unit up(b) Transformation rulesThe corresponding ordered-pair rules for these transformations are ...
reflection: (x, y) ⇒ (-x, -y)translation: (x, y) ⇒ (x +3, y +1)__
Additional comment
The single transformation that will accomplish the mapping is ...
(x, y) ⇒ (3 -x, 1 -y) . . . . . reflection across the point (3/2, 1/2)
For j(x) = 4x − 2, find j of the quantity x plus h end quantity minus j of x all over h period
If j(x) = 4^(x - 2), the solving the given expression [j(x + h) - j(x)]/h gives;
[j(x + h) - j(x)]/h = (4^(x - 2))(4^(h) - 1)]/h
How to utilize laws of exponents?We are given the function as;
j(x) = 4^(x - 2)
Now, we want to solve the expression;
[j(x + h) - j(x)]/h
This gives us;
j(x + h) = 4^(x - 2 + h)
Thus, our expression is now;
[j(x + h) - j(x)]/h = [4^(x - 2 + h) - 4^(x - 2)]/h
Now, according to laws of exponents, we know that;
y³ × y² = y³ ⁺ ²
Thus;
4^(x - 2 + h) = 4^(x - 2) × 4^h
Therefore;
[4^(x - 2 + h) - 4^(x - 2)]/h = (4^(x - 2))(4^(h) - 1)]/h
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Need some guidance and reassurance because I am not getting full points on my homework. Thanks.
Given the parent function:
[tex]y=x^3[/tex]If y is shifted right by 7 units, we obtain:
[tex]Option\text{ D: }y=(x-7)^3[/tex]If y is compressed horizontally by a factor of 7, we have:
[tex]Option\; E\colon y=(7x)^3=7^3x^3[/tex]If y is stretched vertically by the factor 7, we obtain:
[tex]\text{Option H: }y=7x^3[/tex]A shift downwards by 7 units gives:
[tex]\text{Option A: }y=x^3-7[/tex]which anwser show the best approximation of [tex] \sqrt[]{53} [/tex]1. 7.72. 8.13. 7.34. 7.1
The Solution:
The given number is
[tex]\sqrt[]{53}[/tex]Finding the best approximation for the above number, we have
[tex]\sqrt[]{53}=7.28\approx7.3[/tex]Therefore, the best approximation of the given number is 7.3 (option 3)
Give the standard form of the given equation below. If it is a quadratic equation, then give the a, b, and c coefficients. 3x2-2x-5x(x-7)=(x-2)(x+4)+1
Answer:
[tex]\begin{gathered} -3x^2+31x+7=0 \\ a=-3 \\ b=31 \\ c=7 \end{gathered}[/tex]Step-by-step explanation:
The quadratic equation in standard form is represented by:
[tex]ax^2+bx+c=0[/tex]For the following equation;
[tex]\begin{gathered} 3x^2-2x-5x(x-7)=(x-2)(x+4)+1 \\ 3x^2-2x-5x^2+35x=x^2+4x-2x-8+1 \\ -2x^2-2x+35x=x^2+2x-7 \end{gathered}[/tex]Compute all the terms on the left side, equalizing 0:
[tex]\begin{gathered} -3x^2+31x+7=0 \\ \text{Then, the a,b and c coefficeints would be:} \\ a=-3 \\ b=31 \\ c=7 \end{gathered}[/tex]Find the zero of 3[2x-(3x-4)]-6(x-3)
First, simplify the expression:
[tex]\begin{gathered} 3\lbrack2x-(3x-4)\rbrack-6(x-3) \\ =3\lbrack2x-3x+4-6(x-3) \\ =3(2x)+3(-3x)+3(4)-6(x-3) \\ =6x-9x+12-6x+18 \\ =6x-9x-6x+12+18 \\ =-3x-6x+12+18 \\ =-9x+12+18 \\ =-9x+30 \end{gathered}[/tex]Then:
[tex]3\lbrack2x-(3x-4)\rbrack-6(x-3)=-9x+30^{}[/tex]To find the zero of the given expression, find the zero of -9x+30:
[tex]\begin{gathered} -9x+30=0 \\ \Rightarrow-9x=-30 \\ \Rightarrow x=\frac{-30}{-9} \\ \therefore x=\frac{10}{3} \end{gathered}[/tex]Therefore, the zero of the given expression is 10/3.
A line passes through the point (4,-7) and has a slope of -6 write an equation in slope intercept form for this line
What does origin mean? how can you find the origin in a graph?
Explanation
the origins mean the center of the cartessian plane, it is the point with coordinate
[tex](0,0)[/tex]Answer:
the origin is located at the intersection of the vertical and horizontal axes and the distance to all can be measured from this point..(0,0)
find the slope of the line that passes through (1,5) and (9,8)
The slope of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In this case, the line passes through the points (1,5) and (9,8), then its slope is:
[tex]m=\frac{8-5}{9-1}=\frac{3}{8}[/tex]I need help with this questionif a certain piece of music is written in 3/4 time, how many eighth notes are required per measure of music?
Solution
For this case we need to take in count that in music 3/4 time can be grouped into 3 groups of 2 eight notes and then the answer for this case would be:
6/8
Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows a compounded continuously model, we can determine the amount of substance left in Alexander Litvinenko's body at any given time. If Polonium-210 has a decay rate of .502%, then determine the amount of Polonium-210 left in his body after 190 days. Provide 3 decimal places and units in your answer.
We have
Initial mass of Polonium-210
[tex]N_0=10\text{ micrograms}[/tex]Decay rate, r = 0.502% = 0.00502
Time, t = 190 days
Then, We know that left amount is given by
[tex]N=N_0e^{-rt}[/tex]Solving
[tex]N=10e^{-0.00502(190)}=10e^{-0.9538}=3.853[/tex]Answer: 3.853 micrograms
If ac = 57 find the measure of ab
9
30
6
27
Step-by-step explanation:
3x+4x-6=57
7x=63
x=9
AB=3x=3*9
AB=27
what is the probability that a card drawn randomly from a standard deck of 52 cards is a nine? express your answer as a fraction
Given the question, we need to know that a standard deck contains 52 cards out of which there are 4 cards showing nine.
[tex]\text{Probability = number of possible outcomes/number of total outcomes}[/tex]To get the probability of randomly drawing a nine will be:
[tex]\begin{gathered} \frac{n\text{ (nine)}}{n\text{ (total cards)}} \\ pr(nine)=\frac{4}{52}=\frac{1}{13} \end{gathered}[/tex]Hence, the probability of drawing nine is 1/13