Using the gravitational force of F= G(m1*m2/r^2)
m1= 5.97 x 10^24 kg (Earth)
m2= 1.99 x 10^30 kg (Sun)
r= 1.48 x 10^11 m
G is a known value, it is 6.672 x 10^-11
All units are proper. Therefore plug in the values and you get 3.16 x 10^22 N.
Let me know if I calculated this wrong and it is something else so I can delete this. Thank you. I don't want to make other students put down the wrong answer.
Answer:
[tex]\boxed {\boxed {\sf F_g \approx 3.62 *10^{22} \ N}}[/tex]
Explanation:
We are asked to find the gravitational force between Earth and the Sun. Use the following formula:
[tex]F_g= \frac{Gm_1m_2}{r^2}[/tex]
G is the universal gravitational constant. One mass (m₁) is the Earth and the other (m₂) is the Sun. r is the distance between the planets.
G= 6.67 * 10⁻¹¹ N*m²/kg²m₁ = 5.97 * 10²⁴ kg m₂= 1.99 * 10³⁰ kg r= 1.48 *10¹¹ mSubstitute the values into the formula.
[tex]F_g = \frac{ (6.67*10^{-11} N*m^2/kg^2)(5.97*10^{24} \ kg)(1.99*10^{30} \ kg) }{ (1.48 *10^{11} \ m)^2}}[/tex]
Multiply the numerator. The units of kilograms cancel.
[tex]F_g = \frac {7.9241601 *10^{44} \ N*m^2}{ (1.48 *10^{11} \ m)^2 }[/tex]
Solve the exponent in the denominator.
[tex]F_g= \frac {7.9241601 *10^{44} \ N*m^2}{ 2.1904*10^{22} \ m^2}[/tex]
Divide. The units of meters squared cancel.
[tex]F_g=3.61767718 *10^{22} \ N[/tex]
The original values all have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.
[tex]F_g \approx 3.62 *10^{22} \ N[/tex]
The gravitational force between Earth and the Sun is approximately 3.62 *10²² Newtons.
the acceleration of a train moving from rest and its speed reaches 36m/sec in 9 sec
Answer:
4 m/s^2
Explanation:
The acceleration is defined as: Δv/Δt (the difference of the velocity over a time period in which happens that difference).
Remember that a difference is calculated by subtracting the initial value of a physical quantity from its final value.
In our case:
Δv = Vfinal - Vinitial = 36m/s - 0 m/s = 36m/s
Δt = 9s
a = Δv/Δt = 36m/s / 9s = 4m/s^2
The force of gravity can also be referred to as the force of _____________.
Answer:
Gravitational.
Explanation:
In Earth, everything have a volume and mass, or downward force of gravity, which Earth's mass exerts on them.
imagine that you’re riding in a car. the car suddenly begins to accelerate forward (positive acceleration). what do you feel as you sit in the seat
Answer:
Because the car is accelerating forward, you will feel your body push backwards, into the back of the seat.
What is the equivalent resistance of a 12-ohm resistor wired in parallel with a 4-ohm resistor?
А
0.06 ohms
B
0.33 ohms
С
3.0 ohms
D
16.0 ohms
[tex]R=\frac{R1.R2}{R1+R2} = \frac{12.4}{12+4}=\frac{48}{16}=3<ohms>[/tex]
The answer is : C. 3.0 ohms
Ok done. Thank to me :>
A new moon is discovered orbiting Neptune with an orbital speed of 9.3 x103 m/s. Neptune's mass is 1.0 x1026 kg. A) What is the radius of the new moon's orbit? B) What is the orbital period? Assume that the orbit is circular. (G = 6.673 x10-11 N-m²/kg?
The density of air is 1.3 kg/m'. Calculate the mass of air in the room.
Answer:
The density of air is 1.3 kg/m'. Calculate the mass of air in the room.
A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of this wave?
Answer:
109.52 HzExplanation:
The frequency of the wave when given it's velocity and wavelength only can be found by using the formula
[tex]f = \frac{c}{ \lambda} \\ [/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in meters
From the question we have
c = 230 m/s
[tex] \lambda[/tex] = 2.1 m
[tex]f = \frac{230}{2.1} = 109.523809... \\ [/tex]
We have the final answer as
109.52 HzHope this helps you
how much brighter is Vega than the Sun? (astronomy)
Answer: 60 times brighter
This is not meant to be a long, mathematically-intensive problem. If you find yourself going down that road, you might want to rethink your approach.
Answer:
rethink your approach to what?
Explanation:
N
Select the correct answer.
In which situation is no work considered to be done by a force?
A.
when the angle between the force and displacement is 180°
OB.
when the angle between the force and displacement is 90°
Ос.
when the angle between the force and displacement is 45°
OD.
when the angle between the force and displacement is 0°
Draw a diagram that represents how a mechanical wave interacts with a particular material.
Create a diagram and include reflection, absorption, and transmission.
Write a brief description (3+ sentences) of the interaction of the mechanical waves and the material. Include an explanation of how the amplitude and frequency of the wave are affected.
85 POINTS!!
When mechanical waves interact with material, it transfer its energy to the material.
What are mechanical waves?Mechanical waves are the type of waves that require a medium for transporting their energy from one region to another. Mechanical waves depend on particle interaction in order to transport their energy.
The amplitude and frequency of the wave are negatively affected due to the striking of mechanical waves with the material.
Learn more about waves here: https://brainly.com/question/75996
Answer:
i have a screenshot just use mine https:/ss27
Explanation:
A 50.0 kg crate is pulled 375 N of force applied to a rope. The crate slides without friction.
After being pulled 3.07 meters the crate has a velocity of 5.61 m/s. What is the angle (degrees) made by the rope with the horizontal?
Hi there!
We can use the work-energy theorem to solve.
Recall that:
[tex]\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}[/tex]
The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:
[tex]W = \frac{1}{2}(50)(5.61^2) = 786.8025 J[/tex]
Now, we can define work:
[tex]\large\boxed{W = Fdcos\theta}}[/tex]
Now, plug in the values:
[tex]786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta[/tex]
Solve for theta:
[tex]cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}[/tex]
Suppose you drop a 10-pound weight and a 5-pound weight on the Moon, both from the same height at the same time. What will happen? The 10-pound weight will hit the ground before the 5-pound weight. The 5-pound weight will hit the ground before the 10-pound weight. Both weights will float freely because everything is weightless on the Moon. Both will hit the ground at the same time.
Answer:
Both will hit the ground at the same time.
Where in an equation for photosynthesis does glucose belong? on the left, because it is a product on the left, because it is a reactant on the right, because it is a product on the right, because it is a reactant
Answer: The answer is on the right, because it is a product.
Explanation: During photosynthesis, light energy converts carbon dioxide and water (the reactants) into glucose and oxygen (the products).
Glucose belongs to the right side in photosynthesis equation because it is a product on the right.
What is Photosynthesis?Photosynthesis is the conversion of light energy into chemical energy by green plants and other organisms. Light energy is collected and utilized by green plants during photosynthesis to transform water, carbon dioxide, and minerals into oxygen and energy-rich organic molecules Glucose.photosynthesis equation can be written as6CO2 + 6H2O → C6H12O6 + 6O2.
Carbon dioxide + Water → Glucose + oxygen
Hence, the correct option is C.
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13. What are some ways that you can conserve energy?
Answer:
Adjust your day-to-day behaviors.
Replace your light bulbs.
Use smart power strips.
Install a programmable thermostat.
Use energy efficient appliances.
Reduce water heating expenses.
Install energy efficient windows.
Upgrade your HVAC system.
Turn Off Lights and Electronics When You Aren't Using Them. ...
Replace Traditional Light Bulbs with LEDs. ...
Get a Smart Thermostat. ...
Ensure Your Home is Properly Insulated. ...
Put Decorative Lights on a Timer. ...
Identify and Unplug Energy Vampires. ...
Reduce Appliance Use. ...
Use Less Hot Water.
Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a factor of five and the mass of object 2 is multiplied by a factor of two, what will the new gravitational force be between the objects?
A. F2
B. 1/2F
C. 0.1F
D. 2F/5
E. 5F
J. 10F
Please help will mark brainliest
If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is
F' = G (5m₁) (2m₂) / d²
F' = 10 Gm₁m₂ / d²
but this is really just F' = 10F. So J is the correct choice.
Hi there!
Using Newton's Law of Universal Gravitation:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]
Fg = Force of gravity (N)
G = Gravitational Constant
m₁ = mass of object 1 (kg)
m₂ = mass of object 2 (kg)
d = distance between the objects (m)
There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:
[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]
Thus, the correct answer is J. 10Fg.
How many protons are in C-14?
Answer:
56 proton sir
have a nice day
How does production and possibilities curve show efficiency grouth and opportunity cost
Answer:
The Production Possibilities Curve (PPC) is a model that captures scarcity and the opportunity costs of choices when faced with the possibility of producing two goods or services. Points on the interior of the PPC are inefficient, points on the PPC are efficient, and points beyond the PPC are unattainable.
Explanation:
Calculate the force of gravity of a 25kg block resting on the earth (M=5.97x10^24kg). The radius of the earth is 6.38x10^6m.
I already know...
[tex](6.67*10^{-11})(25)(5.97*10^{24} )/(6.38*10^6)^2[/tex]
But I don't understand what steps I have to take to solve that equation
From Newton's law of gravity, the force of gravity is 245 Newtons
To calculate the force of gravity of a 25kg block resting on the earth of mass M = 5.97x10^24kg with the radius r of the earth is 6.38x10^6m, let us first list out all the given parameters
Mass m = 25 kg
Mass of the earth M = 5.97x10^24kg
Radius r = 6.38x10^6m
Force F = ?
The formula to calculate the force of gravity is
F = (GMm)/[tex]r^{2}[/tex]
Where G = 6.67 x [tex]10^{-11}[/tex]
Substitute all the parameters
F = (6.67 x [tex]10^{-11}[/tex] x 5.97x10^24 x 25) / (6.38x10^6)^2
F = 9.9 x [tex]10^{15}[/tex] / 4.07 x [tex]10^{13}[/tex]
F = 244.56 N
F = 245 Newtons (approximately)
Therefore, the force of gravity is 245 Newtons
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An object with a mass of 5 kg is accelerated from rest by a 60 N*s impulse. What is the change in the object's velocity?
Hi there!
Using the Impulse-Momentum theorem:
I = Δp = mΔv
Where:
I = Impulse (Ns)
m = mass of object (kg)
Δv = change in velocity (vf - vi, m/s)
Plug in the given values and solve:
60 = 5Δv
Δv = 12 m/s
Someone answer? Please
12. Since the Clean Air Act was passed in 1970, why is the air still not clean?
Answer:
Congress designed the Clean Air Act to protect public health and welfare from different types of air pollution caused by a diverse array of pollution sources.
Explanation:
A digital stopwatch reading 0:13 37. Read the elapsed time on the stopwatch and answer the questions. In which digit is there the least amount of confidence? How many significant figures does this measurement have?.
The digit with the least amount of confidence can be seen in the second part which is 7.
The number of significant figures in the measurement of the stopwatch is 4.
An elapsed time is the difference between the time prior to the commencement of an event and the time at which the event has ended.
From the stopwatch, the elapsed time is given as:
0hour : 13 minutes : 37 seconds
The digit with the least amount of confidence can be seen in the seconds part is 7.
A significant figure is a real figure that is dependable and absolutely essential to convey the quantity of something.
The number of significant figures in the measurement of the stopwatch is 4.
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Answer: 7 and 4
Explanation: A digital stopwatch reading 0:13 37.
Read the elapsed time on the stopwatch and answer the questions.
In which digit is there the least amount of confidence?
7
How many significant figures does this measurement have?
4
Explain why stationary waves are seen only certain frequencies (3 marks)
Explanation:
The underlying physics give rise to periodic behavior. Usually, some resonance is involved, in which the media damps waves except those at a specific frequency.
__
Only waves at a specific frequency are recognized as being "stationary." If the frequency varies, the behavior is described as "chaotic." So, it's partly a matter of definition.
A projectile is fired with a velocity of 320 ms at an angle of 30 degree to a horizontal.1 Find the time to reach the maximum height. 2 it's horizontal range.
(a) The time taken for the projectile to reach the maximum height is 32.65 s.
(b) The horizontal range of the projectile is 9,049.1 m.
The given parameters:
Initial velocity of the projectile, u = 320 m/sAngle of projection, = 30 degreesThe time taken for the projectile to reach the maximum height is calculated as follows;
[tex]v_f = u- gt\\\\0 = 320 - 9.8t\\\\9.8t = 320\\\\t = \frac{320}{9.8} \\\\t = 32.65 \ s[/tex]
The horizontal range of the projectile is calculated as follows;
[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\R = \frac{320^2 \times sin(2\times 30)}{9.8} \\\\R = 9,049.1 \ m[/tex]
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free tingsssssssssss
Explanation:
yayyy thx u soo muchihuhuhu
Answer:
thx
Explanation:
Two Magnets are placed near each other on the space station orbiting earth. The south poles are facing each other which statement explains what what happen to the magnets.
A. They will be repelled because they are in each others magnetic field
B. They will be attracted because they’re magnetic fields will add together
C. They will not move because they are not in earths gravitational field.
D. They will not move because they do not have electric fields.
Explanation: A) They will be repelled because they are in each others magnetic field
Which of the following is true for gravitational force?
Group of answer choices
Decreases with decrease in distance
Increases with increase in distance
Decreases with increase in mass
Increases with increase in mass
Answer:
The gravitational force b) Increases with increase in mass.
Explanation:
The gravitational force between two objects is given by
F=G\frac{m_1 m_2}{r^2}F=Gr2m1m2
where
G is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the objects
From the equation, we notice that:
- The force is proportional to the masses, m1 and m2: so, if the masses increase, the force will increase, and if the masses decrease, the force will decrease
- The force is inversely proportional to the distance between the masses, r: so, if the distance increases, the force will decreases, and if the distance decreases , the force will increases
Therefore, the correct options is only:
Increases with increase in mass
Answer: The answer is b increases in increase of mass because the heavier the object is the more gravitional pull it will have.
Explanation: Which of the following is true for gravitational force?
Group of answer choices
Decreases with decrease in distance
Increases with increase in distance
Decreases with increase in mass
Increases with increase in mass
You slide towards the window when a car makes a sudden turn
Answer:
thats ummm
Explanation:
law of inertia
Newton’s 1 law
Simplicity of conducting the study is to ________ as ability to test large numbers of participants is to ________.
Simplicity of conducting the study is to archival research as ability to test large numbers of participants is to surveys.
What is Archival research?Archival research is a type of research which involves seeking out and extracting the evidence from archival records. These archival records may be held together either in the collection of institutions, such as libraries and museums, or in the custody of the organization that originally generated or accumulated them, or in that of a successor object.
Archival research can be contrasted with the secondary research, which involves identification and consulting the secondary sources related to the topic of enquiry; and with the other types of primary research and empirical investigation such as fieldwork and experiment.
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