Find the magnitude of the buoyant force on the block. The acceleration of gravity is 9.8 m/s 2 . Answer in units of N.

Answer:

3311N

Explanation:

r = radius = 600m

V = speed = 150m/s

Mass = weight = 70kg

The weight of pilot when calculated due to circular motion

W = tv

Fv = mv²/r

Fv = 70x150²/600

Fv = 79x22500/600

= 15750000/600

= 2625N

Real Weight of the pilot = m x g

= 70 x 9.8

= 686N

The apparent Weight is calculated by

Mv²/r + mg

= 2625N + 686N

= 3311 N

Therefore the apparent Weight is 3311N

Answer:

Extensive property

Explanation:

Answer:

Extensive property

Explanation:

Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.

Answer:

true

Explanation:

Answer:

3m/s

Explanation:

Given parameters:

Initial speed  = 2m/s

Acceleration  = 0.5m/s²

Time  = 2s

Unknown:

Final speed  = ?

Solution:

To solve this problem, we apply the right motion equation;

     V  = U + at

V is the final speed

U is the initial speed

a is the acceleration

t is the time

      V = 2  + (2 x 0.5)

      V = 2 + 1

      V = 3m/s

Answer:

Explanation:

given

initial velocity u = 4.45m/s

Height = 0.6m

g = 9.8m/s²

Required

final velocity v

Using the equation of motion;

v² = u²-2gH (upward motion of the fish makes g to be negative)

v² = 4.45²-2(9.8)(0.6)

v² = 19.8025-11.76

v² = 8.0425

v = 2.84 m/s

Hence the speed of the fish as it passes a point 0.6 m above the water is 2.84m/s

To get the time, we will use the formula

v = u - gt

2.84 = 4.45 - 9.8t

2.84-4.45 = -9.8t

-1.61 = -9.8t

t = 1.61/9.8

t = 0.164secs

Hence the time taken is 0.164secs

Answer:

approximately 13.77 m

Explanation:

We use the kinematic equations for the horizontal motion which is a uniform non-accelerated motion, and with initial velocity equal to 16 * cos(55). This is described by the equation:

[tex]x=16 * cos(55^o) * t = 9.177 * t[/tex]

then at t = 1.5 seconds, the covered distance becomes:

x = 9.177 * (1.5) = 13.7655  m

Round the answer to the number of decimals that the problem asks.

Answer:

[tex]38.3\ \text{m/s}[/tex]

[tex]32.14\ \text{m/s}[/tex]

6.55 seconds

[tex]52.65\ \text{m}[/tex]

[tex]254.84\ \text{m}[/tex]

Explanation:

u = Initial velocity of rock = 50 m/s

[tex]\theta[/tex] = Angle of throw = [tex]40^{\circ}[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Horizontal component is given by

[tex]u_x=u\cos\theta\\\Rightarrow u_x=50\times \cos40^{\circ}\\\Rightarrow u_x=38.3\ \text{m/s}[/tex]

The horizontal component of the velocity is [tex]38.3\ \text{m/s}[/tex]

Vertical component is given by

[tex]u_y=u\sin\theta\\\Rightarrow u_y=50\times \sin40^{\circ}\\\Rightarrow u_y=32.14\ \text{m/s}[/tex]

The horizontal component of the velocity is [tex]32.14\ \text{m/s}[/tex]

Time of flight is given by

[tex]t=\dfrac{2u\sin\theta}{g}\\\Rightarrow t=\dfrac{2\times 50\sin40^{\circ}}{9.81}\\\Rightarrow t=6.55\ \text{s}[/tex]

The hang time of the rock is 6.55 seconds

Maximum height is given by

[tex]h=\dfrac{u^2\sin^2\theta}{2g}\\\Rightarrow h=\dfrac{50^2\sin^240^{\circ}}{2\times 9.81}\\\Rightarrow h=52.65\ \text{m}[/tex]

Maximum height is [tex]52.65\ \text{m}[/tex]

Range is given by

[tex]d=\dfrac{u^2\sin2\theta}{g}\\\Rightarrow d=\dfrac{50^2\sin(2\times40)^{\circ}}{9.81}\\\Rightarrow d=254.84\ \text{m}[/tex]

The range is [tex]254.84\ \text{m}[/tex]

Answer: Motion

Explanation:

Answer:

9. qulitative(spell check)

10. false

11. true

Explanation:

Answer:The amount of energy carried by radio waves is enough to provide images but not enough to kill cells.

Explanation:

The reason of MRI should be useful is that the energy amount that should be carried out via the radio waves.

It refers to the medical imaging technique that should be applied in the radiology to create the pictures with respect to the anatomy and the process of physiological with related to the body.

Also, it is applied for strong the magnetic field, gradient related to the magnetic field, also the radios waves for produce image in the body organs.

Learn more about wave here: https://brainly.com/question/12734041

Answer:

Mass is constant everywhere,

But weight is different,

If earth g = 10 then moon's is 1.6666667

Now billie's weight in moon is 41.6667

Answer:

R = 98304.75 m = 98.3 km

Explanation:

The density of an object is given as the ratio between the mass of that object and the volume occupied by that object.

Density = Mass/Volume

Now, it is given that the density of Earth has become:

Density = 1 x 10⁹ kg/m³

Mass = Mass of Earth (Constant) = 5.97 x 10²⁴ kg

Volume = 4/3πR³ (Volume of Sphere)

R = Radius of Earth = ?

Therefore,

1 x 10⁹ kg/m³ = (5.97 x 10²⁴ kg)/[4/3πR³]

4/3πR³ = (5.97 x 10²⁴ kg)/(1 x 10⁹ kg/m³)

R³ = (3/4)(5.97 x 10¹⁵ m³)/π

R = ∛[0.95 x 10¹⁵ m³]

R = 98304.75 m = 98.3 km

having a plan and listening to your coach

Answer:

-2R

Explanation:

The focal length can be calculated using this formula

1/f = (n1/n2-1)(1/r1-1/r2)

1/f = (1/1.33-1)(1/r + 1/r)

= -0.133/1.33(2/R)

F = -2R

The focal length is this

Answer:

Since there is no motion yet, there is no kinetic energy. This means that the work needed to get up the hill is the potential energy at the top. Once you have coasted down the hill and are at the bottom, all of the energy is kinetic.

Explanation:

.

Answer:

The cell theory

Explanation:

Answer:

The cell theory

Explanation:

Answer:

natural motion and violent motion

Explanation:

Answer:

D. ? Its the only one talking about color

Answer:

Triangle law of vector addition is one of the vector addition laws. Vector addition is defined as the geometrical sum of two or more vectors as they do not follow regular laws of algebra. The resultant vector is known as the composition of a vector

Explanation:

if it helps great if that still doesn't help thats the best i can do

Answer:

the a.

Explanation:

because if you compute you can't know the distance

The S wave vibrates both side to side and up and down whereas P wave is the first to arrive during an earthquake

During the eathquake, two types of seismic waves are generated , P wave and S wave.

The S waves produces vibrations to the ground in a shearing force perpendicular to the direction of propagation of the wave, moving the ground up and down or from side to side. S waves are called secondary waves because arrive after P waves.

The P waves is analogous to longitudinal vibrations, producing vibrations to the ground to compress and expand in the direction of propagation f the wave. They are called primary waves because they are the first type of wave to arrive at seismic recording stations.

Learn more about seismic waves:

https://brainly.com/question/13062627?referrer=searchResults

Answer:

i got it right so chillllll :)

Explanation:

Select the correct responses to the questions from the drop-down menus.

Which type of wave vibrates both side to side and up and down?

✔ S wave

Which type of wave is the first to arrive during an earthquake?

✔ P wave

Which type of wave may make the ground roll?

✔ surface wave

Answer:

w_bear = 7175.95 N ,   m = 732.24 kg

Explanation:

Let's analyze the situation a bit, the ice block is in equilibrium with the thrust given by Archimedes' law that is directed towards the bottom, the weight of the ice and the weight of the bear.

           B -W_ice - w_bear = 0

           w_bear = B - W_ice

The thrust is given by

           B = ρ g V

           B = 1025 9.8 6.78

           B = 68 105.1 N

Note that we use the total volume of the block since the problem indicates that it is submerged.

The weight of the ice is

           W_ice = m g

the density is

          ρ_ice = m_ice / V

          m_ice = rho_ice V

we substitute

          W_ice = ρ_ice g V

           W_ice = 917 9.8 6.78

           W_ice = 60929.15 N

we substitute in the first equation

             w_bear = 68105.1 - 60929.15

              w_bear = 7175.95 N

the mass of this bear is

               w_bear = m g

               m = w_bear / g

               m = 7175.95 / 9.8

               m = 732.24 kg

Answer:

The magnitude of the force between the two parallel wires is 0.0111 N.

Explanation:

Given;

length of the two parallel wires, L = 42 m

distance between the two wires, r = 0.03 m

current in both wires, I₁, I₂ = 6.3 A

Therefore, the magnitude of the repulsive force between the two parallel wires is given by;

[tex]F = \frac{\mu_0 I_1I_2l}{2\pi r}\\\\where;\\\mu_0 \ is \ permeability \ of \ free \ space = 4\pi *10^{-7} \ T.m/A \\\\F = \frac{(4\pi *10^{-7})(6.3)^2(42)}{2\pi (0.03)}\\\\F = 0.0111 \ N[/tex]

Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.

Answer:

a) 2*10^9 J

b) 764.8 kg

Explanation:

Given that

Energy of charge, q = 20 C

Potential difference, ΔV = 1*10^2 MV = 1*10^2 * 10^6 V = 1*10^8 V

a)

To find the energy dissipated, we use the formula

ΔU = qΔV

ΔU = 20 * 1*10^8

ΔU = 2*10^9 J

b)

Change in temperature, ΔT = 100 - 15°

ΔT = 85° C

Change in energy, ΔU = 2*10^9 J

Specific heat of water, C = 4180 j./Kg.K

Latent heat of vaporization, L(v) = 2.26*10^6 J/Kg

Q1 = mcΔT

Q2 = mL(v)

Net energy needed, U = Q1 + Q2

U = mcΔT + mL(v)

U = m (cΔT + L(v))

m = U /[cΔT + L(v)]

Being that we have all the values, we then substitute

m = 2*10^9 / [(4180 * 85) + 2.26*10^6]

m = 2*10^9 / (3.553*10^5 + 2.26*10^6]

m = 2*10^9 / 2.615*10^6

m = 764.8 kg

c)

Having 765 kg of steam at the temperature would have extreme effect on the tree, damaging it permanently. Possibly even blowing it to pieces

Answer:

12552 J or 3000 calories

Explanation:

Q = m × c × ∆T

Where;

Q = amount of heat energy (J)

m = mass of water (g)

c = specific heat capacity (4.184 J/g°C)

∆T = change in temperature

For 50mL of water, there are 50g, hence, m = 50g, c = 4.184 J/g°C, initial temperature = 0°C, final temperature = 60°C.

Q = m × c × ∆T

Q = 50 × 4.184 × (60 - 0)

Q = 209.2 × 60

Q = 12552 J

Hence, the amount of heat energy used to heat the water is 12552 J or 3000 calories

Answer:

v = 6.3 m/s

Explanation:

       [tex]E_{i} = K_{i} + U_{i} = 0 + U_{i} (1)[/tex]

       [tex]m*g* h = 2*\frac{1}{2}*m*v^{2} (2)[/tex]

       [tex]v = \sqrt{g*h} =\sqrt{9.8m/s2*4.0m} = 6.26 m/s (3)[/tex]

Answer:

816m

Explanation:

70^2m/s=2(3m/ss)(x)

x=816