Find the median mode and mean for each data set

Answer:

Step-by-step explanation:

Formula

speed = distance / time

Givens

speed = ?

distance = 162 miles.

Time = 3 hours.

Solution

speed = 162 / 3

speed = 54 miles per hour.

Answer:

∠ T = 76°

Step-by-step explanation:

RSTU is a cyclic quadrilateral

the opposite angles of a cyclic quadrilateral sum to 180°

∠ T + ∠ R = 180°

∠ T + 104° = 180° ( subtract 104° from both sides )

∠ T = 76°

Veremos que de los 20 intentos, Mariana metio 16 canastas.

Sabemos que ella tiro 20 veces, y sabemos que ella ha errado 1/5 de los tiros.

Entonces los otros 4/5 tiros entraron. Para obtener el numero de canastas que ha metido, debemos multiplicar la fracción por la cantidad total de tiros al aro:

C = 20*(4/5) = 16

Así, podemos concluir que Mariana ha metido 16 canastas.

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Answer:

I can help, but can you label which is base, height, and length

Step-by-step explanation:

Answer:

5/9

Step-by-step explanation:

Solution

The gradient of the line ment when two segment given (X1, Y1) and (X2, Y1) is points

m =

[tex] \frac{y2 - y1}{x2 - x1 } [/tex]

Here two points given, (-5,-2) and (4,3)

gradient (m):

[tex] \frac{3 - ( - 2)}{4 - ( - 5)} [/tex]

The true statements are:

Given:

To find the large size meals that came with milk,

71-55= 16.

Therefore, the total number of large size meals ordered was:

16+22+86 = 124.

Hence, options A, D and E are correct.

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x = -2/3 or -4

see the attachment for solution

hope it helps...!!!

Answer:

Company "A"

Step-by-step explanation:

its the highest line on the graph from the 300 point.

There are 300 different sundaes possible with the given choices of 20 ice cream flavors, 5 toppings, and 3 sizes at the make-your-own sundae bar.

To find the total number of different sundaes possible, we need to multiply the number of choices for each category: ice cream flavors, toppings, and sizes.

Number of ice cream flavors = 20

Number of toppings = 5

Number of sizes = 3

Total number of sundaes = Number of ice cream flavors × Number of toppings × Number of sizes

Total number of sundaes = 20 × 5 × 3

Total number of sundaes = 300

There are 300 different sundaes possible with the given choices of 20 ice cream flavors, 5 toppings, and 3 sizes at the make-your-own sundae bar.

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The function that has the same minimum value as fx= 3x³ is f(x) = x + 3.

It should be noted that a function simply means a relation or expression that involves two or more variables.

In this case, the function that has the same minimum value as the expression of 3x³ is f = x + 3.

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Answer:

B. f(x) = /x/ + 3

Step-by-step explanation:

edg 22'

Answer:

x^2 -6x + 9

Step-by-step explanation:

(x-3) (x-3) = x^2 - 6x + 9

Step-by-step explanation:

k has to be replaced by k+1.

so,

4 / ((k+1)(k+1 + 3)) = 4 / ((k+1)(k+4))

I am not sure how far your teacher expects you to go with this.

just in case, I will do also the full multiplications

4 / ((k+1)(k+4)) = 4 / (k² + 4k + k + 4) = 4 / (k² + 5k + 4)

and if you need the factor to go from Pk to Pk+1 :

Pk+1 / Pk = (4/((k+1)(k+4))) / (4/(k(k+3)) =

= (4/((k+1)(k+4))) × (k(k+3))/4 =

= (k(k+3)) / ((k+1)(k+4))

The value of a and b given that the opposite side are equal are 17 and 6 respectively

The kite is a quadrilateral with 4 sides and the opposite side of the side are equal. If they are, then;

2a - 4 = 30
2a = 34

a = 17

Similarly

3b+6 = 24

3b = 18
b = 6

Hence the value of a and b given that the opposite side are equal are 17 and 6 respectively

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Answer:

26.7

Step-by-step explanation:

Answer:

10.16

Step-by-step explanation:

average change =  9.16 - 4.35 / 2020 - 1996  = 0.2

Cost = 9.16 + (2025 -2020) x 0.2 = 10.16

So the answer is $10.16

The inequality that represents this situation is x ≤ 6. On the other hand, the parents can ship only the tennis rackets.

The equality that represents this situation is x ≤ 6 because the number of pounds that can be added (x) has to be 6 or less than 6.

The parents can only ship the tennis rackets because these are 5 pounds which meets the criteria of the inequality.

The inequality would change to x ≤ 1 because the weight that could be added if he needs these producs changes to only 1 pound.

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Answer:  0.000039

Step-by-step explanation: i us calculator

Answer:

0.000039.

Step-by-step explanation:

3.9 / 100,000

Move the decimal point 5 places to the left ( as there are 5 0's in 100,000)

filling in the zeroes as you move alomg.

So its  0.000039

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

The given sequence is in Arithmetic progression, and we have to find its nth term ~

So, let's get it solved ~

First term of the sequence is :

Common difference is :

Now, if we have to write the 2nd Term with respect to first one, we can write :

similarly ~

Therefore, I similar pattern ~

[tex] \qquad \sf  \dashrightarrow \: nth \: term = a + (n - 1)d[/tex]

[tex] \qquad \sf  \dashrightarrow \: nth \: term = 2 + (n - 1)2[/tex]

[tex] \qquad \sf  \dashrightarrow \: nth \: term = 2(1 + (n - 1))[/tex]

[tex] \qquad \sf  \dashrightarrow \: nth \: term = 2(1 + n - 1)[/tex]

[tex] \qquad \sf  \dashrightarrow \: nth \: term = 2 n [/tex]

Feel free to ask your doubts, if you have any ~

Answer:

Step-by-step explanation:

from the number sequence above, each term except the first is generated by adding 2 to the term immediately preceding it.

the nth term of the sequence is usually designated Tn, and it's usually a function of n

from the number sequence

T1= 2

T2 = 2+2= 4

T3= 4+2= 6

T4= 6+2= 8

therefore, Tn= 2+2×(n-1)

= 2+2n-2

=2-2+2n= 2n

Answer:

[tex]\textsf{B.} \quad x=\dfrac{1}{2}[/tex]

Step-by-step explanation:

Log laws

[tex]\textsf{Product law}: \quad \log_ax + \log_ay=\log_axy[/tex]

[tex]\textsf{Equality law}: \quad \textsf{if }\: \log_ax=\log_ay\:\textsf{ then }\:x=y[/tex]

Therefore:

[tex]\large \begin{aligned}\log_6 x+ \log_6 3 & =\log_6 (x+1)\\\log_6 (3x) & =\log_6 (x+1)\\3x & =x+1\\2x & =1\\x & =\dfrac{1}{2}\end{aligned}[/tex]

Answer:

(x-3)(x+2)

Step-by-step explanation:

¹ you open brackets.

² you put the "x" in both brackets

³ you then check for factors, that will give you a "6" when you multiply them and give you the "x" when you add or subtract them.

Answer:

2√97

Step-by-step explanation:

BD² = BC² + DC²

⇒ BD = √BC² + DC²

= √(18)² + (8)²

= √324 + 64

= √388

Rewrite 388 as 2² · 97.

Factor 4 out of 388.

√4(97)

Rewrite 4 as 2².

√2² · 97

Pull terms out from under the radical.

2√97

The result can be shown in multiple forms.

Exact Form:

2√97

Decimal Form:

19.69771560...

Answer:

I am not too sure so I deeply apologize for any wrongs, but this is my thinking.

Joe bought each taco for 4 dollars, and bought an asada fry for 50 cents.

On the other hand-

Sam also bought 1 taco for 12 dollars, and bought 2 asada fries, one of them was 1 dollar, and one of them was 75 cents.

Answer:

[tex]\huge\boxed{\sf \$\ 205}[/tex]

Step-by-step explanation:

Work hours = 28 hours

Earning = $8 per hour

1 hour = $8

28 hours = $8 × 28

28 hours = $224

He has earned $224 last month.

Spent = $19

Left:

= Earning - Spent

= $224 - $19

= $205

[tex]\rule[225]{225}{2}[/tex]

[tex]\left( \sqrt 3 + \sqrt 7\right) \left( \sqrt 3 - \sqrt 7\right)\\\\=\left(\sqrt 3 \right)^2 - \left(\sqrt 7 \right)^2\\ \\=3-7\\\\=-4[/tex]

Answer:

- 4

Step-by-step explanation:

([tex]\sqrt{3}[/tex] + [tex]\sqrt{7}[/tex] )([tex]\sqrt{3}[/tex] - [tex]\sqrt{7}[/tex] )

each term in the second factor is multiplied by each term in the first factor.

[tex]\sqrt{3}[/tex] ([tex]\sqrt{3}[/tex] - [tex]\sqrt{7}[/tex] ) + [tex]\sqrt{7}[/tex] ([tex]\sqrt{3}[/tex] - [tex]\sqrt{7}[/tex] ) ← distribute parenthesis

= 3 - [tex]\sqrt{21}[/tex] + [tex]\sqrt{21}[/tex] - 7 ← collect like terms

= - 4

Answer: y  - 6x +46

Step-by-step explanation:

y + 4- 6(x +7)

y + 4 - 6x +42

y  - 6x +46

Using a system of equations, it is found that Teresa's password in the 7th day of the month is of 98.

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

The rule for her password is defined as follows: A whole number that is equal to four times the fourth power of the day of the month divided by two times the square day of the month. Hence, considering n as the day of the month, the equation is given by:

[tex]P = \frac{4n^4}{2n^2} = 2n^2[/tex]

Hence, for the 7th day, the password is given by:

P = 2 x 7² = 98.

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

P(3 and 4)= 1/6×1/6

                =1/36

Answer:

504 combos

Step-by-step explanation:

Cannot use digits twice and last is '7'

 9 digits for first place choice  

     8 digits for second place

         7 digits for third place

               only  '7' for fourth place       9 x 8 x7 = 504 combos

You can use the rule of product from combinatorics to find out how many ways can the remaining digits be chosen.

The remaining digits for the given condition can be chosen in 504.

Option B: 504

If a work A can be done in p ways, and another work B can be done in q ways, then both A and B can be done in   ways.

Remember that this count doesn't differentiate between order of doing A first or B first then doing other work after the first work.

Thus, doing A then B is considered same as doing B then A

Since 7 is already fixed and there is constraint that no two digits can be used, thus, we initially have only 10-1 = 9 digits.

For first place, we can chose 1 digit out of 9 digits in ways,

⁹C₁ = 9 ways

For second place, as one of the digit is used, thus, 1 digit out of 8 digits can be chosen in ways,

⁸C₁ = 8 ways

For third place, as two of the digits is used, only 7 digits are remaining to chose from. Thus, 1 digit out of 7 remaining digits can be chosen in ways.

⁷C₁ = 7 ways

Using product rule, we get:

Total possible number of choices for choosing digits for first, second and third position of lock with given constraints is given as

= 9 x 8 x 7

= 504 ways

Thus, The remaining digits for the given condition can be chosen in,

Option B: 504

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[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]

the following expression can be solved as follows ~

[tex] \frac{x}{3} + 1 = \frac{x}{8} + \frac{1}{11} \\ [/tex]

Taking LCM on both the sides ,

[tex] \frac{x + 3}{3} = \frac{11x + 8}{88} \\ [/tex]

On cross multiplying ,

[tex]( x + 3)88 = (11x + 8)3 \\ \\ \implies \: 88x + 264 = 33x + 24[/tex]

let's now gather the like terms at either sides of the equation and solve ~

[tex]88x - 33x = 24 - 264 \\ \\ \implies \: 55x = - 240 \\ \\ \implies \: x = \cancel\frac{ - 240}{55} \\ [/tex]

on further simplifying ,

[tex]\implies x = \frac{ - 48 }{ 11} \\ [/tex]

hope helpful ~