Find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8

1. Isolate x in the first equation:

2. Substitute the value for x into the second equation:

3. Solve for y:







4. Substitute y into either original equation:

5. Write the solution as an ordered pair:





x = 7 – 3y

2(7 – 3y) + 4y = 8

14 – 6y + 4y = 8

14 – 2y = 8

–2y = –6

y = 3

x + 3(3) = 7

(, )

Answer:

The solution to the system of equation is: (-2,3)

Step-by-step explanation:

We need to find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8

I am placing steps for each point given

1. Isolate x in the first equation:

First equation is:

x+3y=7

Isolating x:

x=7-3y

2. Substitute the value for x into the second equation:

Second equation is:

2x+4y=8

Putting value of x: x=7-3y

2(7-3y)+4y=8

3. Solve for y:

2(7-3y)+4y=8

Multiply 2 with terms inside the bracket

14-6y+4y=8

-2y=8-14

-2y=-6

y=-6/-2

y=3

So, we get value of y: y=3

4. Substitute y into either original equation:

Putting value of y: y=3 in equation 1

x+3y=7

x+3(3)=7

x+9=7

x=7-9

x=-2

So, we get value of x: x=-2

5. Write the solution as an ordered pair:

After solving the equation we get:

x = -2 and y = 3

The ordered pair is: (-2,3)

Answer:

-2,3

Step-by-step explanation:

Isolate x in the first equation:

Substitute the value for x into the second equation:

Solve for y

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