Find the volume of the figure

Answer:708

Step-by-step explanation:

Answer:

5cm, 9cm, 10cm

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Area of right angle Triangle:

6.5 * 9 * 1/2 = 29.25

2nd way to find area:

1/2 * base * height

Since we have area and base:

1/2 * 11.1 * h = 29.25

= 5.27m

= 5m (nearest tenth)

The height h of the roof to the nearest tenth is 5.3 m

Right angle triangle has one of its angles as 90 degrees. The triangles are likewise similar and can be used to find the height h of the roof.

Therefore,

cross multiply

11.1 h = 9 × 6.5

11.1 h = 58.5

divide both sides by 11.1

11.1 h / 11.1 = 58.5 / 11.1

h = 5.27027027027

h = 5.3 m

learn more on right triangle here: https://brainly.com/question/4280778

Answer:

f(6) =34

Step-by-step explanation:

f(x) = 5x + 4

Let x= 6

f(6) = 5*6 +4

     = 30 +4

     = 34

Answer:

11.383

Step-by-step explanation:

the third place is the thousandths.

By rounding 11.3826 to the nearest thousand, we get 11.383.

The number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.

Example: 0.2358 rounded to the nearest thousand is 0.236.

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.

Example: 0.7231 rounded to the nearest thousand is 0.723.

Given number is 11.3826.

Rounding to nearest thousand, we get:

11.3826 ⇒ 11.383.

Learn more about rounding a number to nearest thousand here: https://brainly.com/question/24234983

#SPJ2

Answer:

12.4

Step-by-step explanation:

[tex]AL= 2r\pi (\frac{angle}{360} )[/tex]

[tex]AL= 2(7.9)(\pi )(\frac{90}{360})\\[/tex]

Answer:

uhururfjfhfufjfjfjfjfjfif

Answer:

I believe the first one is 250

the second one I haven't got a clue

Answer:

0.41

Step-by-step explanation:

All probability equals 1. So if the probability that something will happen is x, then the probability that it will not happen is 1-x

The second difference of this quadratic pattern is 2.

The first term of this quadratic pattern is 10.

A sequence of numbers has a quadratic pattern when its sequence of second differences is constant. Therefore,

let the first and fourth term be a and b.

Therefore,

first difference:

1 - a; - 6 - 1 = -7; b + 6; -14 - b;

Second difference:

The second difference is constant . Therefore,

-7  - (1 - a) = -8 + a; b + 6 + 7 = b + 13; -14 - b - b - 6 = -2b - 20;

Therefore,

b + 13 = -8 + a

b  - a = -21

Then,

-2b - 20  = b + 13

-3b = 33

b = 33 / -3

b = - 11

Therefore,

- 11 - a = - 21

-a = -21 + 11

-a = -10

a = 10

Hence, the second difference = b + 13 = -11 + 13 = 2

First term = a

Therefore,

a = 10

learn more on quadratic pattern here:https://brainly.com/question/21517782

Answer:

0.7517 = 75.17% probability that the mean IQ of the 3 North Catalina students is at least 5 points higher than the mean IQ of the 3 Chapel Mountain students

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

North Catalina:

Population has mean 130 and standard deviation 8 points. Sample of 3. This means that:

[tex]\mu_{N} = 130, s_{N} = \frac{8}{\sqrt{3}} = 4.6188[/tex]

Chapel Mountain:

Population has mean 120 and standard deviation 10 points. Sample of 3. This means that:

[tex]\mu_{C} = 120, s_{C} = \frac{10}{\sqrt{3}} = 5.7735[/tex]

What is the probability that the mean IQ of the 3 North Catalina students is at least 5 points higher than the mean IQ of the 3 Chapel Mountain students?

We want that: [tex]N - C > 5[/tex]

Distribution N - C:

The mean is:

[tex]\mu = \mu_N - \mu_C = 130 - 120 = 10[/tex]

The standard deviation is:

[tex]s = \sqrt{s_N^2+s_C^2} = \sqrt{4.6188^2+5.7735^2} = 7.3937[/tex]

This probability is 1 subtracted by the pvalue of Z when X = 5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{5 - 10}{7.3937}[/tex]

[tex]Z = -0.68[/tex]

[tex]Z = -0.68[/tex] has a pvalue of 0.2483

1 - 0.2483 = 0.7517

0.7517 = 75.17% probability that the mean IQ of the 3 North Catalina students is at least 5 points higher than the mean IQ of the 3 Chapel Mountain students

Answer:

uhm im really sorry about this but i really need points i would help but id get it wrong im bad aat math

Step-by-step explanation:

I think the area is 63. Sorry if it is incorrect.

Answer:

I think its 72,000

Step-by-step explanation:

there's 144 months in 12 years and i just multiplied it by 500

Answer:

Step-by-step explanation:

Volume of water is the difference of volume of vase at 12 in height and the total volume of marbles.

Volume of cylinder up to water level:

Volume of marbles:

Volume of water:

Correct choice is C

Answer:

C. π(3in)2(12in) − 9(four over threeπ(1.5in)3)

Step-by-step explanation:

Vs = πr²h = π(6/2)²(12) = π×(3 in)²×(12 in)

Vm = 9(4/3πr³) = 9×(4/3×π(3/2)³) = 9×(4/3×π×(1.5 in)³)

Vw = Vs - Vm = π×(3 in)²×(12 in) - 9×(4/3×π×(1.5 in)³)

Correct choice is C

Answer:

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9[/tex]

Step-by-step explanation:

Given

[tex]tan\theta = 3[/tex]

Required

Find

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)[/tex]

Calculate [tex]tan(\theta + \pi) \ and\ tan(\theta+2\pi)[/tex]

Using tan rule

[tex]tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}[/tex]

So:

[tex]tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}[/tex]

[tex]tan(\theta + \pi) = \frac{tan\theta}{1 }[/tex]

[tex]tan(\theta + \pi) = \tan\theta[/tex]

[tex]tan(\theta+2\pi)[/tex]

[tex]tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}[/tex]

[tex]tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}[/tex]

[tex]tan(\theta + 2\pi) = \tan\theta[/tex]'

'So:

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)[/tex] [tex]= tan\theta +tan\theta +tan\theta[/tex]

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3[/tex]

[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9[/tex]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision    Variable        Constraint              Constraint

A                     65                          65                         100

B                     80                          80                         80

C                     90                         90                          90

                      14100                    300                        300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

                             A              B                  C                Unit price

Need of X          2                 1                   1                     $20

Need of Y           2                3                  2                    $30

Need of Z           2                2                  3                    $25

Price of  

manufac -      $200          $240            $220      

turing

Now,  for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.  

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160  

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit  --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

[tex]{(100 - A) + (80 - B) +(90 - C) } + \$40[/tex]

This should be subtracted from profit.

So, we have to maximize the profit  

[tex]Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};[/tex]

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

[tex]2A + B +C \le 300[/tex] due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

[tex]A \le 100[/tex]

[tex]B \le 80[/tex]

[tex]C \le 90[/tex]

and [tex]A, B, C \ge 0[/tex] because they are positive quantities

The objective is:

[tex]\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}[/tex]

A, B, C [tex]\to[/tex] Decision Varaibles;

Constraint are:

[tex]A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0[/tex]

Answer:

Round to the nearest tenth. 35 12. х x = [?] Enter​

Step-by-step explanation:

Answer:

96

Step-by-step explanation:

Answer:

96 cm

Step-by-step explanation:

Length + Width + Length + Width = Perimeter

Length + 74 cm + Length + 74 cm = 340 cm

74 + 74 = 148

340 - 148 = 192

192 ÷ 2

96

Check:

74cm + 96cm + 74cm + 96cm = 340 cm

Answer:

3 packages

Step-by-step explanation:

first we need to make this into a equation that we can solve!

x = 21/7

if we use our times tables then we know that

7 * 3

= 21

so knowing what we know, lets go back to the question/ equation!

21/7

= 3

( if you wanted, that could also be a way to double check you answer :)

hope this helped you and if you have any more questions then please ask me! :)

Answer:

B is the correct answer

Answer:

Step-by-step explanation:

Its c

Answer:

132 inches

Step-by-step explanation:

33 x 4 = 132 inches

Answer:

Robbert is 7

Step-by-step explanation:

because you already said it