Finding Angle Measures When Parallel Lines Are Cut By a Transversal

Please help i keep asking because i need help and i need to bring my math grade up please help this is urgent!!!!!!!!!!!!

Finding Angle Measures When Parallel Lines Are Cut By A TransversalPlease Help I Keep Asking Because

Answers

Answer 1

Answer: Angles 6,2,3 are the same and are all 112 degrees.

Angles 1,4,5,8 are the same and are all 68 degrees.

Step-by-step explanation:

Angles 6,2,3 are all 112 degrees because of diagonal angle rule.

Angles 1,4,5,8 are 180-112=68 degrees because we can use 180 degree angle rule.

Hope this helped, If you have any questions or clarifications, comment below!

Please rate!


Related Questions

Use the diagram to find the measure of angle 2

Answers

The measure of angle 2 is 75°

From the question, we have

∠1= 105°

∠2= 180°- 105° (Linear pair)

∠2=75°

Subtraction:

Subtraction represents the operation of removing objects from a collection. The minus sign signifies subtraction −. For example, there are nine oranges arranged as a stack (as shown in the above figure), out of which four oranges are transferred to a basket, then there will be 9 – 4 oranges left in the stack, i.e. five oranges. Therefore, the difference between 9 and 4 is 5, i.e., 9 − 4 = 5. Subtraction is not only applied to natural numbers but also can be incorporated for different types of numbers.

The letter "-" stands for subtraction. Minuend, subtrahend, and difference are the three numerical components that make up the subtraction operation. A minuend is the first number in a subtraction process and is the number from which we subtract another integer in a subtraction phrase.

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Find the length of YZ when Y is the midpoint of XZ
X
20+2a
Y
8 +6a
Z
XZ=

Answers

The length of the line YZ is 26 units

The Y is the mid point of the line XZ

The length of the line XY = 20 + 2a

The length of the line YZ = 8 + 6a

When Y is the mid point of the line XZ, then the length of the line XY is equal to the length of the line YZ

The length of the line XY = The length of the line YZ

Substitute the values in the equation and find the value of a

20 + 2a =  8 +6a

Rearrange and group the like term

6a - 2a = 20 - 8

4a = 12

a = 12 / 4

a = 3

The length of the YZ = 8 +6a

= 8 + 6×3

= 8 + 18

= 26 units

Hence, the length of the line YZ is 26 units

The complete question is:

Find the length of YZ when Y is the midpoint of XZ, if XY = 20+2a and YZ = 8+6a.

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A machine in a factory make 3 1/2 pound of nail in 1 1⁄4 hour. At what rate, in pound per hour, doe the machine make nail?

Answers

Answer:

2.8 pounds per hour

Step-by-step explanation:

[tex] \frac{3.5}{1.25} = \frac{350}{125} = \frac{14}{5} = 2.8[/tex]

Find the equation of the parabola with the given x-intercepts and point on the graph. Use y = a(x-p)(x-q).

3. x-int: (-4,0) , (7,0)
P (3,8)

Answers

Answer:

y = -2/7(x + 4)(x - 7)

=============================

Given

x- intercepts (-4, 0) and (7, 0),Point P (3, 8).

Solution

The given translates as:

p = -4, q = 7, x = 3, y = 8

Use given x - intercepts to get the equation:

y = a(x + 4)(x - 7)

Use the coordinates of P to find the value of a:

8 = a(3 + 4)(3 - 7)8 = a*7*(-4)8 = - 28aa = 8 / - 28a = - 2/7

The equation of this parabola is:

y = - 2/7(x + 4)(x - 7)

Answer:

[tex]\textsf{Intercept form}: \quad y=-\dfrac{2}{7}(x+4)(x-7)[/tex]

[tex]\textsf{Standard form}: \quad y=-\dfrac{2}{7}x^2+\dfrac{6}{7}x+8[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{6 cm}\underline{Intercept form of a quadratic equation}\\\\$y=a(x-p)(x-q)$\\\\where:\\ \phantom{ww}$\bullet$ $p$ and $q$ are the $x$-intercepts. \\ \phantom{ww}$\bullet$ $a$ is some constant.\\\end{minipage}}[/tex]

If the x-intercepts are (-4, 0) and (7, 0) then:

p = -4q = 7

Substitute the values of p and q into the formula:

[tex]\implies y=a(x-(-4))(x-7)[/tex]

[tex]\implies y=a(x+4)(x-7)[/tex]

To find a, substitute the given point on the curve P (3, 8) into the equation:

[tex]\implies 8=a(3+4)(3-7)[/tex]

[tex]\implies 8=a(7)(-4)[/tex]

[tex]\implies 8=-28x[/tex]

[tex]\implies a=\dfrac{8}{-28}[/tex]

[tex]\implies a=-\dfrac{2}{7}[/tex]

Substitute the found value of a into the equation:

[tex]\implies y=-\dfrac{2}{7}(x+4)(x-7)[/tex]

Expand to write the equation in standard form:

[tex]\implies y=-\dfrac{2}{7}(x^2-3x-28)[/tex]

[tex]\implies y=-\dfrac{2}{7}x^2+\dfrac{6}{7}x+8[/tex]

consider following recurrence relation. what will be the number next in series in place of question mark? 0, 3, 8, 15, 24, 35, 48, ?

Answers

The number that will be next in the series will  be  63 .

In the question ,

a recurrence relation is given that is  0, 3, 8, 15, 24, 35, 48, ? .

we have to find the number that will come in place of question mark .

On carefully examining the series , we can see that

3 - 0 = 3

8 - 3 = 5

15 - 8 = 7

24 - 15 = 9

35 - 24 = 11

48 - 35 = 13

we can se that increments 3,5,7,9,11,13,... form an Arithmetic Progression

with first term as 3 and common difference as 2 ,

So ,the next increment will be 13+2 = 15

let the next term be "x" .

x - 48 = 15

x = 15 + 48 = 63

the number in place of ? is 63 .

Therefore , The number that will be next in the series will  be  63 .

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Which of the following rules describes the function graphed below? On a coordinate plane, points are at (negative 1, 1), (1, 2), (3, 3), (5, 4). a. Output = Input c. Output = (0.5)(Input) + 1.5 b. Output = (2)(Input) – 3 d. Output = (1.5)(Input) + 3

Answers

The rule that describes ( -1, 1), (1, 2), (3, 3), (5, 4) is c. Output = (0.5)(Input) + 1.5

What is a function?

A function can be defined as the outputs for a given set of inputs.

The inputs of a function are known as the independent variable and the outputs of a function are known as the dependent variable.

Given, On a coordinate plane, points are at ( -1, 1), (1, 2), (3, 3), (5, 4).

By observing the given options we conclude that it is Output = (0.5)(Input) + 1.5 to confirm let's put the values.

Given when input is - 1 output is 1.

∴ 1 = 0.5(-1) + 1.5.

1 = - 0.5 + 1.5.

1 = 1  ( satisfied).

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The perimeter of an isosceles triangle is 380 cm and it’s unequal side is 150 find the area of triangle (by Heron’s formula)

Answers

Answer:

A ≈ 6538.35 cm²

Step-by-step explanation:

Calculating the area (A) using Heron's formula

A = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]

where s is the semi perimeter and a, b, c the 3 sides

here

s = 380 ÷ 2 = 190

given perimeter = 380 and unequal side is 150 , then

equal sides = (380 - 150) ÷ 2 = 230 ÷ 2 = 115 cm

then a = 150, b = 115 , c = 115

A = [tex]\sqrt{190(190-150)(190-115)(190-115)}[/tex]

   = [tex]\sqrt{190(40)(75)(75)}[/tex]

   = [tex]\sqrt{42750000}[/tex]

   ≈ 6538.35 cm² ( to 2 dec. places )

can someone please help me with this

Answers

Answer:

B

Step-by-step explanation:

given 1 pound = 16 ounces , then

5 pounds = 5 × 16 = 80 ounces

since 1 pound is 16 oz, u would multiply 16 by 5 to get the answer. Answer is 80 oz

at the lone butte ranch 6 goats and 5 sheep sell for 305 while 2 goats and 9 sheep sell for 285. Find the cost of a single goat and a single sheep.

Answers

By solving a system of equations we can see that each goat costs $30 and each sheep costs $25.

How to find the cost of each animal?

Let's define the variables:

x = cost of a goat

y = cost of a sheep.

We can write the system of equations with the given info:

6*x + 5*y = 305

2*x + 9*y = 285

If we subtract 3 times the second equation from the first one, we get:

(6*x + 5*y) - 3*(2*x + 9*y) = 305 - 3*285

-22*y = -550

y = -550/-22 = 25

Now that we know the value of y we can try to find the value of x:

2*x +9*25 = 285

2*x = 285 - 9*25 = 60

x = 60/2 = 30

These are the costs of each animal.

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How many solutions does 5 + x/3 = x/3 + 6 + x/9

A. Infinitely many solutions
B. Two solutions
C. No solutions
D. One solution

Answers

Answer:   D)  one solution

========================================================

Explanation:

A thing that jumps out at me right away is the presence of x/3 on both sides. When subtracting x/3 from both sides, these terms cancel out and we're left with this equation

5 = 6 + (x/9)

Let's say w = x/9. We now have this equation 5 = 6 + w. Subtract 6 from both sides to isolate w and you should get w = -1

Then plug in w = x/9 and solve for x.

w = -1

x/9 = -1

x = 9*(-1)

x = -9

We get exactly one solution and it is x = -9

--------------

Check:

5 + x/3 = x/3 + 6 + x/9

5 + (-9)/3 = (-9)/3 + 6 + (-9)/9

5 - 3 = -3 + 6 - 1

2 = 3 - 1

2 = 2

We get the same thing on both sides, which leads to a true statement. This causes a domino effect to lead the first equation to be true when x = -9. Therefore, the solution is confirmed.

5a<−35 or a−14>1

Algebra 1, high school

Answers

Answer:156

Step-by-step explanation:

What expressions represents the multiplex version of the expression below ?
(6x^2 +5) (2x^3+3)

Answers

Answer:

12x^5+18x^2+10x^3+15

Step-by-step explanation:

first you apply the distribution property (FOIL) and you get

12x^5+18x^2+10x^3+15

help pls what are the number of hours i need this before 11/20/22

Answers

a. Creating a system of equations, the length of each plan A's workout is 3/4 hour, while the length of each plan B's workout is 3/4 hour.

b. x = -8, y = 2.

How to Solve a System of Equations?

Write equations of a system that represents the information given and solve accordingly.

Let the length of plan A = x

Length of plan B = y

Equation for Monday would be:

9x + 7y = 12 --> eqn. 1

Equation for Tuesday:

3x + 5y = 6 --> eqn. 2

Multiply eqn. 1 by 3 and eqn. 2 by 9

27x + 21y = 36 --> eqn. 3

27x + 45y = 54 --> eqn. 4

Subtract the equations:

-24y = -18

y = -18/-24

y = 3/4

Plan B's length of workout is: 3/4 hour.

Substitute y = 3/4 into equation 2:

3x + 5(3/4) = 6

3x + 15/4 = 6

3x = 6 - 15/4

3x = 9/4

12x = 9

x = 9/12

x = 3/4

Length of plan A's workout is: 3/4 hour.

b. 2x + 4y = -8 --> eqn. 1

-2x + 3y = 22 --> eqn. 2

Add both equations together:

7y = 14

y = 2

Substitute y = 2 into equation 1:

2x + 4(2) = -8

2x + 8 = -8

2x = -8 - 8

2x = -16

x = -16/2

x = -8

The solution is: x = -8, y = 2.

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When 6 less than 3 times a number is increased by 2 it's at least 5 times the same number decreased by 8

Answers

Answer: 2>=n

Step-by-step explanation:

3n-6 +2 >= 5n-8

3n-4 >= 5n-8

-4>= 2n -8

4>=2

2>=n

Hope this helped!!

The average annual rainfall for a town is 43.2 inches. The average monthly rainfall for the previous 9 months was 4 inches. Did the town exceed its average annual rainfall? If so, by how much?

Answers

Answer:

Yes, the town exceeded the average annual rainfall by 0.4 inches

Step-by-step explanation:

The average annual rainfall for a town is 43.2 inches.

This is converted to average monthly as:

43.2 in / 12 = 3.6 in

The difference is:

4 in - 3.6 in = 0.4 in

Answer:

Yeah, they exceeded by 0.4 inches.

Step-by-step explanation:

It is given that,

→ the average monthly rainfall for the previous 9 months was 4 inches.

The monthly rainfall in 12 months,

→ 43.2 inches ÷ 12 months

→ 43.2/12

→ 3.6 inches

Then the difference will be,

→ 4 inches - 3.6 inches

→ 4 - 3.6

→ 0.4 inches

Hence, the difference is 0.4 inches.

Barbara drew a scale drawing of a game room. The scale she used was 2 inches : 1 foot. If the actual length of the pool table is 6 feet, how long is the pool table in the drawing?​

Answers

If the actual length of the pool table is 6 feet , then the length of the pool table in the drawing is 12 inches   .

In the question,

it is given that ,
Barbara drew an scale drawing of the game room.

the scale that she used is 1 feet in the actual length is represented by 2 inches in the drawing ,

which means ,

1 feet = 2 inches

to find the length of 6 feet in the drawing ,

6 feet = 6 × 2 inches

= 12 inches

Therefore , If the actual length of the pool table is 6 feet , then the length of the pool table in the drawing is 12 inches   .

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Raman purchased books and stationery items and paid the total amount of rupees 963 if he paid 7% tax what was the net value of the item purchased.

Answers

The net value of the items purchased is ₹ 900.

Raman purchased books and stationery items and paid the total amount of rupees 963.

Paid tax = 7%

Let the net value of the items purchased be `x.

VAT = 7%

Selling price = ₹x + (7% of x)

                    = ₹x+ ₹ ( 7/100 * x)  

                    =₹( x +7 x /100)

                    = ₹ 107 x /100

But Raman purchased books and stationery items for ₹963.

107x/100 = ₹963

               x =  963 x 100/107

               x = 900

Hence the answer is the net value of the items purchased is ₹ 900.

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A person who weighs 150 pounds weighs 25 pounds on the Moon. Suppose an object weighs 80 pounds on the Moon. What’s the objects weight on the Earth?

Answers

Answer:

480 lbs

Step-by-step explanation:

First, find the ratio of weight on the moon to weight on the earth. I will put the two known values in a fraction like this:

[tex]\frac{25}{150}[/tex]

Now, I can create a proportion, making sure to keep the same types of measurements in the numerator and denominator. I will use w for the unknown weight on earth.

[tex]\frac{25}{150}=\frac{80}{m}[/tex]

Now, I will simplify the fractions as much as I can.
[tex]\frac{1}{6}=\frac{80}{m}[/tex]

Now, I can see a correlation. 1 times 80 is 80, so 6 times 80 is m. Simplified, here is the answer!

[tex]6*80=m\\480=m\\m=480[/tex]

Answer:

480 pounds

Step-by-step explanation:

we times for objects on earth and divide for objects on the moon by the same number

150

[tex]150 \div x = 25[/tex]

150/-25=-x

-6/-1= -x/-1

6=x

[tex]150 \div 6 = 25[/tex]

so when in object is on earth you multiple by x Wich 6

[tex]80 \times 6 = 480[/tex]

you can also cross multiply

A group entering a zoo purchased 32 admission tickets for a total of $148. Adult tickets cost $7. 50, and tickets for children cost $3. 50. How many of each type of ticket were purchased?.

Answers

23 tickets are purchased for children and 9 tickets are purchased for adults.

Given,

In the question:

A group entering a zoo purchased 32 admission tickets for a total of $148. Adult tickets cost $7. 50, and tickets for children cost $3. 50.

To find the how many of each type of ticket were purchased?

Now, According to the question:

It is given in the question that 32 tickets are purchased by group which cost total $148.

Let the number of children of the group who are entering the zoo be x. Then the number of adults will be 32- x

Now cost of one ticket for adult = $7.50

Total amount spent on adult tickets = 7.50 × (32-x)

Similarly, cost of one ticket for child= $3.50

Total amount spent on children tickets = 3.50 × x =3.5x

Total amount spent by group on tickets =  $148

⇒ 7.5 × (32-x) + 3.5x = 148

⇒ 240 - 7.5x + 3.5x = 148

⇒ 7.5x - 3.5x = 240 - 148

⇒ 4x = 92

⇒ x = 23

Children = 23

Adults = 32-x = 32-23 = 9

Hence, 23 tickets are purchased for children and 9 tickets are purchased for adults.

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A scale on a map is 1 200 000. Work out the distance on the map, in cm, if the real distance is 10 km 15 km 4 km​

Answers

The distance on the map, in cm, given the real distances, and the scale of the map are:

10 km = 5 cm15 km  = 7.5 cm4 km = 2 cm

How to find the distance on the map?

A scale of 1 : 200, 000 means that every 1 cm on the map is 200, 000 cm on the ground.

To find the distance on the map of 10 km, first convert it to cm:
= 10 km x 100, 000 cm per km

= 1, 000, 000 cm

The distance on the map is therefore:

= 1, 000, 000 / 200, 000 cm scale

= 5 cm on map

The distance of 15 km on the map is:

= (15 km x 100, 000) / 200, 000

= 7.5 cm

The distance of 4 km is:

= (4 x 100, 000) / 200, 000

= 2 cm

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which of the following ratios are connected to 5/20?

multiple choice

a 1/5

b1/4

c 20/100

d 25/100

Answers

Answer:

which of the following ratios are connected to 5/20?

multiple choice

a 1/5

c 20/100

d 25/100

d is the option 25/100 and

b 1/4

Determine whether the following sequence is arithmetic, geometric, or neither. 12,17,22,27

Answers

Answer:

Arithmetic

Step-by-step explanation:

The difference between consecutive terms is 5. Thus, this is an arithmetic sequence with a common difference of 5.

Solve 2y + x + 3 = 0 and 3y - x + 1 = 0 graphically using -4 ≤x ≤ 2


help pls​

Answers

Answer:

Step-by-step explanation:

We have to the graph from x = -4 to x = 2

2y + x + 3 = 0

Rearrange the equation to make y the subject

2y = -x - 3

y = (-1/2)x -3/2

-3/2 is the y intercept

the gradients is -1/2

since the value is negative, the graph will be sloping downwards

Point your pen at y = -3/2 on the y axis (-3/2 is -1.5)

go 1 point down and 2 points to the right, make a point and connect these 2 dots and make a line across the graph.

Do the same with the other equation:

3y - x + 1 = 0

3y = x - 1

y = (1/3)x -1/3

y intercept is -1/3

gradient is 1/3

point your pen at -1/3 on the y axis, go 1 point up and 3 points to the right

and mark this point and connect these 2 points and make a line across the graph.    

The graph to the right is the uniform probability density function for a friend who is x minutes late
(a) Find the probability that the friend is between 25 and 30 minutes late.
(b) It is 10 A.M. There is a 10% probability the friend will arrive within how many minutes?

Answers

(a)The probability that the friend is between 25 and 30 minutes late is 1/2.

(b) It is 10 A.M. There is a 10% probability the friend will arrive within 1 minute.

What is probability?

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events.

Uniform distribution

a = 0

b = 10

a) P(friend is between 25 and 30 minutes late) = (30 - 25)/(b - a)

= 5/(10-0)

= 1/2

b) Let the time for arrival be A minutes

(A - 0)/(b-a) = 0.10

A = 0.10 x (10 - 0)

A = 1 minute

Hence, The probability that the friend is between 25 and 30 minutes late is 1/2 and It is 10 A.M. There is a 10% probability the friend will arrive within 1 minute.

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for the function g(x)=-1/5 x^2 + 4x+1, find the range of g(x)

Answers

Plotting the graph of the quadratic function  g(x)=-1/5x^2 + 4x + 1 the range is

y ≥ -19

How to determine the range of the quadratic function

The range of the quadratic function is seen at the vertex were the maximum or minimum y value is seen

The graph of the function  g(x)=-1/5x^2 + 4x + 1 is plotted and attached

From the graph the vertex coordinates is v(-10, -16). The y coordinates of the vertex is -19 and this is the minimum values for y

Therefore the range is y ≥ -19

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Andrew has picked out some party favors. He calculates that they will cost $7 per guest.
Write an equation that shows how the total cost of the party favors, y, depends on the number of guests, x
Do not include dollar signs in the equation. what does y equal?

Answers

Answer:

Step-by-step explanation:

y=7x is the equation that shows how the total cost of the party favors, y, depends on the number of guests, x

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

Given,

Andrew has picked out some party favors.

He calculates that they will cost $7 per guest.

We need to find the equation that shows how the total cost of the party favors, y, depends on the number of guests, x

So y=7x where y is the total cost and x is the number of guests and 7 is the cost per guest.

If there are 2 guests then the total cost will be 14.

Hence y=7x is the equation that shows how the total cost of the party favors, y, depends on the number of guests, x

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I really need help! Can anyone please answer this!!

Answers

The function f has domain : [-4, 5], range : [0, 9], zero : (3, 0), the function is increasing in intervals at [-4, 0] U [3, 5], decreasing in intervals at (0, 3], the relative minimum values of f : (3, 0), and relative maximum values of f : (5, 9).

What are the domain and range of the function?

The domain of the function includes all possible x values of a function, and the range includes all possible y values of the function.

The function f is given in the graph.

According to the given function, the required solution would be as:

The domain and range of f will be :

domain : [-4, 5]

range : [0, 9]

The zero of f will be :

(x, y) = (3, 0)

The function is increasing in intervals at [-4, 0] U [3, 5]

The function is decreasing in intervals at (0, 3]

The relative minimum values of f : (3, 0)

The relative maximum values of f : (5, 9)

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PLEASE HURRY
I am having trouble

Answers

You got to set it up to boys to girls

Answer:

0,1

Step-by-step explanation:

simplest form

-4(w + 5) + 2w simplify

Answers

Answer:

-2w-20

Step-by-step explanation:

Giving brainliest to the person who give a right answer with a clear explanation​

Answers

Answer:

33.  AB = √45.  CD = √40.  Not congruent.  AB is greater.

34.  EF = 5.  GH = √41.  Not congruent.  GH is greater.

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Distance between two points}\\\\$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$\\\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.\\\end{minipage}}[/tex]

Question 33

Given endpoints:

A = (0, 2)B = (-3, 8)

Substitute the given endpoints into the formula and solve:

[tex]\begin{aligned}\overline{AB}&=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}\\&=\sqrt{(-3-0)^2+(8-2)^2}\\&=\sqrt{(-3)^2+(6)^2}\\&=\sqrt{9+36}\\&=\sqrt{45}\\& \approx 6.7\; \sf (1 \; d.p.)\end{aligned}[/tex]

Given endpoints:

C = (-2, 2)D = (0, -4)

Substitute the given endpoints into the formula and solve:

[tex]\begin{aligned}\overline{CD}&=\sqrt{(x_D-x_C)^2+(y_D-y_C)^2}\\&=\sqrt{(0-(-2))^2+(-4-2)^2}\\&=\sqrt{(2)^2+(-6)^2}\\&=\sqrt{4+36}\\&=\sqrt{40}\\& \approx 6.3\; \sf (1 \; d.p.)\end{aligned}[/tex]

Therefore, the segments at not congruent.

[tex]\textsf{As\; $\sqrt{45} > \sqrt{40}$ \; then \; $\overline{AB} > \overline{CD}$}.[/tex]

Therefore, the length of segment AB is greater.

Question 34

Given endpoints:

E = (1, 4)F = (5, 1)

Substitute the given endpoints into the formula and solve:

[tex]\begin{aligned}\overline{EF}&=\sqrt{(x_F-x_E)^2+(y_F-y_E)^2}\\&=\sqrt{(5-1)^2+(1-4)^2}\\&=\sqrt{(4)^2+(-3)^2}\\&=\sqrt{16+9}\\&=\sqrt{25}\\&=5\end{aligned}[/tex]

Given endpoints:

G = (-3, 1)H = (1, 6)

Substitute the given endpoints into the formula and solve:

[tex]\begin{aligned}\overline{GH}&=\sqrt{(x_H-x_G)^2+(y_H-y_G)^2}\\&=\sqrt{(1-(-3))^2+(6-1)^2}\\&=\sqrt{(4)^2+(5)^2}\\&=\sqrt{16+25}\\&=\sqrt{41}\\& \approx 6.4\; \sf (1 \; d.p.)\end{aligned}[/tex]

Therefore, the segments at not congruent.

[tex]\textsf{As\; $\sqrt{41} > 5$ \; then \; $\overline{GH} > \overline{EF}$}.[/tex]

Therefore, the length of segment GH is greater.

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