AnswerNegative Partial Charge on: Se, O, O. O-Te is most polar.
Explanation:
O, Se, and Te are all in the same group on the periodic table, which makes this question easier because there is a periodic trend for electronegativity going up and down groups. The more you go down the periodic table, the more shielding affect there is where the electrons closest to the nucleus of an atom block the protons’ positive charge from reaching other electrons. So, O is the most electronegative here, followed by Se, and then Te. So in a bond with O and either of the other two, O will always have a partial negative charge. Se in a bond with Te will also have a partial negative charge, but the difference in electronegativity is biggest between O and Te, and so that is the most polar bond.
According to the electronic configuration and difference in electronegativity, the most polar bond is O-Te.
What is electronic configuration?Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.
Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.
Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.
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Be sure to answer all parts.
What is the concentration in parts per million of DDT in each of the following?
a. 3 x 10^-4 g in 2.3 kg minnow tissue
Ppm DDT
b. 717 µg in 1.5 kg breast milk
ppm DDT
The concentration in parts per million of DDT are as follow:
3 x 10^-4 g in 2.3 kg minnow tissue PPM DDT is 0.13 ppm and in 717 µg in 1.5 kg breast milk is 0.478 ppm.
ppm DDT
What is PPM?PPM is defined as parts per million. It represents the lower concentration of the given solution. It also help in representing 0.001 gram or a milligram in the 1000 mL, which is equivalent to the 1 mg per liter.
Given,
A sample size of2.3 kg contained 3 x 10^-1 mg DDT
It means, 2.3 L sample contained 3 x 10^-1 mg DDT
Therefore, we can say that,
in part per million
= 3 x 10^-1 mg/ 2.3 L
= 0.13 mg/L
=0.13 ppm
A sample size of 1.5 kg contained 717 µg DDT
It means, 1.5 L sample contained 717 x 10^-3 mg DDT
Therefore, we can say that,
in part per million
= 717 x 10^-3 mg/ 1.5 L
= 0.478 mg/L
=0.478 ppm
Thus, we concluded that the concentration in parts per million of DDT are as follow:
3 x 10^-4 g in 2.3 kg minnow tissue PPM DDT is 0.13 ppm and in 717 µg in 1.5 kg breast milk is 0.478 ppm.
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Step 2: Determine the scaling factor.
What is the scaling factor if the molar mass of
the compound is 150 g/mol?
empirical formula mm = 30.03 g/mol
molecular formula mm = 150.0 g/mol
The molecular formula is (CH2O)5 when the scale factor is 5 and the empirical formula is CH2O.
Considering the question given above, the following data were obtained:
Empirical formula = CH₂O
Molar mass of compound = 150 g/mol
Scaling factor (n) =?
Empirical formula × n = molar mass
[CH₂O]n = 150
[12 + (2×1) + 16]n = 150
[12 + 2 + 16]n = 150
30n = 150
Divide both sides by 30
n = 5
Therefore, the scaling factor is 5
A scale factor is a ratio between corresponding measurements of an object and a representation of that object.In chemistry, the empirical formula of a chemical compound is the simplest whole-number ratio of atoms present in a compound. .Learn more about empirical formula at:
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The half-life of carbon-14 is 5715y. How long will it be for one-half of carbon-14 in a
sample to remain?
0.0001212598 is a long will it be for one-half of carbon-14 in a sample to remain.
How is half-life determined?A reaction's half-life is the amount of time needed for the reactant concentration to drop to half its initial value. The rate constant for a first-order reaction and its half-life are connected by the constant t1/2 = 0.693/k.
How much time does it take carbon-14 to complete one half-life?The half-life of carbon-14 is 5,730 40 years, meaning that during the following 5,730 years, half of the radioisotope that is present at any particular time will spontaneously disintegrate.
Carbon-14's 5715-year half-life
The decay constant needs to be determined.
We know the half-life equation.
t[tex]\frac{1}{2}[/tex] = 0.693/λ
where,
t1/2 is the half-life and λ is the decay constant
so,
λ = 0.693 / 5715 = 0.0001212598
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What is the volume in liters of 5.75 moles of CO₂ at standard temperature and pressure (STP)?
The volume in liters of 5.75 moles of CO₂ at standard temperature and pressure (STP) is 128.88L.
How to calculate volume?The volume of a given gas at STP can be calculated using the following formula;
PV = nRT
Where;
P = pressure (atm)V = volume (L)n = number of molesR = gas law constantT = temperatureAccording to this question, 5.75 moles of CO₂ at standard temperature and pressure (STP). The volume of this gas can be calculated as follows;
At STP, the following applies;
T = 273KP = 1 atm1 × V = 5.75 × 0.0821 × 273
V = 128.88L
Therefore, 128.88L is the volume of the gas.
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suppose you measure the absorbance of a yellow dye solution in a 1.00 cm cuvette. The absorbance of the solution at 427 nm is 0.20. If the molar absorptivity of yellow dye at 427 nm is 27400 M-1cm-1, what is the concentration of the solution?
The concentration of the solution is obtained as 7.3 * 10^-6 M.
What is the Beer Lamberts law?We know that one of the ways by which we are able to obtain the concentration of substances especially those that are colored is by the use of spectrophotometry. In a spectrophotometer, there is a wavelength of maximum absorption that could be used to measure the concentration of the solution as we can see in the question.
By the use of the Beer Lambert's law we have;
A = εcl
A = Absorption
ε = molar absorptivity
c = concentration
l = path length
Thus we would have;
0.2 = 27400 M-1cm-1 * c * 1.00 cm
c = 0.2/27400 M-1cm-1 * 1.00 cm
c = 7.3 * 10^-6 M
We would have from the calculation that we have a solution whose concentration is 7.3 * 10^-6 M.
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A student investigated heat transfer using a bottle of water. The student placed the bottle in a room at 20.5°C.
The student measured the temperature of the water in the bottle at 7 a.m. and again at 3 p.m. The data from the
investigation are shown in the table below.
Mass
of
Water
(g)
800.
Water Bottle Investigation Data
7 a.m.
3 p.m.
Temperature
(°C)
12.5
Mass
of Temperature
(°C)
Water
(g)
800.
20.5
3) Based on the given data, show a numerical setup for calculating the change in the thermal energy of the
water in the bottle from 7 a.m. to 3 p.m.
Answer:
Q = mcΔT
Q = (800. g)(4.186 J/g°C)(8.00°C)
Q = 26,800 J
Explanation:
To calculate the thermal energy of the water, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = thermal energy (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°C)
-----> ΔT = T₂ - T₁ = change in temperature (°C)
"T₁" represents the initial temperature and "T₂" represents the final temperature. The specific heat capacity of water is 4.186 J/g°C. You can plug the given values and the constant into the equation and solve for "Q" to find the thermal energy. The final answer should have 3 sig figs like the given values.
Q = ? J c = 4.186 J/g°C
m = 800. g ΔT = T₂ - T₁ = 20.5°C - 12.5°C = 8.00°C
Q = mcΔT <----- Given equation
Q = (800. g)(4.186 J/g°C)(8.00°C) <----- Insert values
Q = 26,800 J <----- Multiply
The numerical setup for calculating the change in the thermal energy of the water in the bottle from 7 a.m. to 3 p.m. is: ΔQ = (800 g) * (4.18 J/g·°C) * (8°C) = 26,528 J
To calculate the change in thermal energy of the water in the bottle from 7 a.m. to 3 p.m., you can use the formula:
ΔQ = mcΔT
where:
ΔQ is the change in thermal energy,
m is the mass of the water,
c is the specific heat capacity of water, and
ΔT is the change in temperature.
Given data:
Mass of water (m) = 800 g
Specific heat capacity of water (c) = 4.18 J/g·°C
Initial temperature (T1) at 7 a.m. = 12.5°C
Final temperature (T2) at 3 p.m. = 20.5°C
Now, plug in the values into the formula:
ΔQ = (800 g) * (4.18 J/g·°C) * (20.5°C - 12.5°C)
Simplifying the expression:
ΔQ = (800 g) * (4.18 J/g·°C) * (8°C)
ΔQ = 26,528 J
Therefore, the numerical setup for calculating the change in the thermal energy of the water in the bottle from 7 a.m. to 3 p.m. is:
ΔQ = (800 g) * (4.18 J/g·°C) * (8°C)
= 26,528 J
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What are Smooth E.R. and Cell Membrane Relationship?
The relationship that exists between smooth endoplasmic reticulum and cell membrane is that lipids are produced in the smooth endoplasmic reticulum which is the major product used for the synthesis of cell membrane.
What is Cell membrane?The cell membrane is defined as part of the cell that is semi permeable which surrounds the cells and controls the passage of substances in and out of the cell.
The endoplasmic reticulum is a membrane bound organelle that are of two types namely:
Smooth endoplasmic reticulum and Rough Endoplasmic reticulum.The smooth endoplasmic reticulum is defined as the type of endoplasmic reticulum that is involved in the synthesis of lipids such as cholesterol and phospholipids.
A relationship exists between the cell membrane and the smooth endoplasmic reticulum because the lipids required for the synthesis of cell membrane are being produced by the smooth endoplasmic reticulum.
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20. Which of the following products could form in a chemical reaction between sulfuric acid and
calcium carbonate? Use the models they provided to complete the chart below.
Calcium sulfate, carbon dioxide, and water are produced when sulfuric acid and calcium carbonate interact.
What results from the reaction of calcium carbonate and sulfuric acid?The insoluble in water free lime (CaCO3) interacts with sulfuric acid. It takes only a few minutes for sulfuric acid and lime to react and produce gypsum. H2SO4 + Lime CaCO3 = CaSO4 (gypsum).
What occurs when calcium and sulfuric acid are combined?Each of these metals forms a layer of insoluble sulfate when exposed to sulfuric acid, which slows or stops the reaction altogether. A white precipitate of calcium sulfate and a small amount of hydrogen are formed in the calcium case.
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How many liters of hydrogen gas can form at STP when 0.500 L of 2.00M HCl solution reacts with excess magnesium?
The answer is 11.2 L but can someone show the process
Taking into account the reaction stoichiometry, 11.2 liters of hydrogen gas can form at STP when 0.500 L of 2.00M HCl solution reacts with excess magnesium.
Reaction stoichiometryIn first place, the balanced reaction is:
Mg + 2 HCl → H₂ + MgCl₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Mg: 1 moleHCl: 2 molesH₂: 1 moleMgCl₂: 1 moleDefinition of molarityMolarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
STP conditionsThe STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Liters of H₂ formedFirst of all, you know that react 0.500 L of 2.00M HCl. Taking into account the definition of molarity. It is possible to calculate the number of moles that react as follows:
moles of HCl= 0.500 L× 2 M
moles of HCl= 1 mole
To calculate the number of moles H₂ formed, the following rule of three can be applied: if by reaction stoichiometry 2 moles of HCl form 1 mole of H₂, 1 mole of HCl form how many moles of H₂?
moles of H₂= (1 mole of HCl× 1 mole of H₂)÷ 2 moles of HCl
moles of H₂= 0.5 moles
Finally, to calculate the liters of H₂ formed, you can apply the following rule of three: if by definition of STP conditions 1 mole of H₂ occupies a volume of 22.4 liters, 0.5 moles occupies how much volume?
volume= (0.5 moles× 22.4 L)÷ 1 mole
volume= 11.2 L
In summary, 11.2 liters of hydrogen gas can be formed at STP.
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When 2.00 moles of ammonia are introduced into a 1.00 liter flask, it reacts as follows 2NH3(g)->3H2(g)+N2(g). At equilibrium 1.25 moles of ammonia remain. Calculate Kc
Answer:
Kc = 0.101 or 1.01*10^-1
Explanation:
Set up ICE table
2NH3 -> 3H2 + N2
I: 2 moles, 0 moles, 0 moles
C: -x moles +y moles +z moles
E: 1.25 moles 0+y moles 0+z moles
We know that x is 0.75 moles, since 2-0.75 is 1.25
for every mole of NH3 consumed, 1.5 moles of H2 are produced, and 0.5 moles of N2 are produced. If 0.75 moles of NH3 are consumed, then 1.5 * 0.75 moles of H2 are produced, and 1.5*0.5 moles of N2 are produced
so, y equals 1.5 * 0.75, which is 3/2 * 3/4, or 3/8, or 0.375 moles of H2 produced
z equals 1.5 * 0.5, which is 0.75 moles of N2 produced
Kc equals [tex]\frac{[N_2][H_2]^3}{[NH_3]^2}[/tex]
N2 = 0.75, N2 = 0.375, and NH3 = 1.25
So, Kc equals
(0.375 * 0.75^3)/(1.25^2), which equals 0.10125
Round to 3 sig figs to get 0.101
What is the mass of an proton?
Answer:
1.67262192 × 10-27 kilograms
The mass of a proton is 1.6726219 × 10-27 kilograms.
What do protons do?
Protons are the positively charged particles that make up an atom's nucleus.Through his well-known experiment with gold foil in 1909, Ernest Rutherford discovered the proton.Proton properties:
Proton Mass: One proton has the same mass as a hydrogen atom. A proton and a electron together make up a hydrogen atom. The mass of a hydrogen atom is equal to the mass of a proton because the mass of an electron is thought to be negligible. An electron weighs 1840 times as much as a proton.
Proton mass is equal to 1.676 x 1027 kilograms, or 1.676 x 1024 grams.
Charge of Proton - A proton's charge is equal to and in the opposite direction of an electron's. Because of this, it has a unit positive charge.
A proton has a charge of +1.602 10-19 coulombs.
Hence, The mass of a proton is 1.6726219 × 10-27 kilograms.
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Regarding nomenclature, what is the name of the formula NaNO?
The nomenclature name of NaNO is Sodium Nitrite or could also be said as Sodium Nitrate.
Sodium nitrite or sodium nitrate is a chemical compound with Sodium cation and nitrate anion. So the combination of these two ions gives us Sodium nitrite.
It is a white, ionic, solid crystalline compound that is used as a food preservative and additive.
Sodium nitrite and sodium nitrate are both inorganic compounds with the chemical formula NaNO₃.
They are both white, crystalline solids that are highly soluble in water. Sodium nitrite is the active ingredient in many curing agents used to preserve meats, and it is also used as a color fixative in smoked fish. Sodium nitrate is used as a fertilizer and as an oxidizing agent in pyrotechnics.
Therefore the nomenclature name of the chemical compound is Sodium Nitrite or Sodium nitrate depending upon the anion NO₂ or NO₃
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How many formula units make up 26.4 g of magnesium chloride ( MgCl2 )?
The number of formula units that make up 26.4g of magnesium chloride is 1.67 × 10²³ units.
How to calculate formula units?Formula units is the empirical formula of an ionic compound (that does not possess individual molecules) for use in stoichiometric calculations.
The number of formula units of a substance can be calculated by multiplying the number of moles of the substance by its number of moles as follows:
no of formula units = no of moles × 6.02 × 10²³
First, we convert the mass of magnesium chloride to moles by dividing by its molar mass. Molar mass of magnesium chloride is 95.211 g/mol.
moles = 26.4g ÷ 95.211g/mol = 0.277moles
no of formula units = 0.277moles × 6.02 × 10²³
no of formula units = 1.67 × 10²³ units
Therefore, 1.67 × 10²³ units is the number of formula units of magnesium chloride.
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(PLEASE HELP) Would you allow a plane to take off in -20 degrees Celsius weather if it were de-iced with a solution of 30% ethylene glycol. Explain.
Answer: No.
Explanation:
The freezing point if 30% ethylene glycol is around -14.7°C, so the plane cannot take off even if it was de-iced. Jet fuel has a very low freezing temperature of around -40°C, but the fuel cannot be the only thing unfrozen for the plane to continue on successfully. If you alter the ethylene glycol concentration to 60%, however, the freezing point drops to -60°C, which would be perfect for this scenario. This happens because the hydrogen bonds that have to form between the water molecules to freeze are interrupted by ethylene glycol molecules, and vice versa.
According to the following reaction, how many moles of copper(II) nitrate will be formed upon the complete reaction of 0.912 moles silver nitrate with excess copper?
silver nitrate (aq) + copper (s) copper(II) nitrate (aq) + silver (s)
__________ moles copper(II) nitrate
According to the reaction illustrated, the amount, in moles, of copper (II) nitrate that will be formed is 0.456 mole.
Stoichiometric problemThe equation of the chemical reaction when silver nitrate reacts with copper is expressed as follows:
[tex]2AgNO_3 + Cu --- > Cu(NO_3)_2 +2 Ag[/tex]
The copper was in excess. This means that silver nitrate is the limiting reactant.
And 0.912 moles of the silver nitrate were reacted.
The mole ratio of silver nitrate and copper (II) nitrate according to the balanced equation of the reaction is 2:1. In other words, for every 1 mole of silver nitrate that reacts, 0.5 moles of copper (II) nitrate is formed.
Now, if 0.912 moles of silver nitrate is involved, the equivalent amount of moles of copper (II) nitrate that will be formed can be calculated as follows:
2 moles silver nitrate = 1 mole copper (II) nitrate
0.912 moles silver nitrate = 0.912 x 1/2
= 0.456 mole
In other words, according to the reaction given, if 0.912 moles silver nitrate is reacted with excess copper, 0.456 mole copper (II) nitrate will be formed.
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What is the percent yield for the reaction below when 364 g SU2 and 42.0 g
O₂ produce 408 g SO3?
2SO₂(g) + O₂(g) → 2SO3(g)
O A. 97.1%
OB. 51.5%
O C. 89.7%
OD. 100%
SUBMIT
The percent yield for the reaction below when 364 g SO₂ and 42.0 g O₂ produce 408 g SO₃ is 51.5 %.
The reaction is given as :
2SO₂(g) + O₂(g) ------> 2SO₃
mass of SO₂ = 364 g
mass of O₂ = 42 g
mass of SO₃ = 408 g
moles of SO₂= mass / molar mass
= 364 / 64
= 5.68 mol
moles of O₂ = mass / molar mass
= 42 / 32
= 1.31 mol
1 mole of O₂ react with = 2 mole of SO₂
1.31 mole of O₂ react with = 2 × 1.31 = 2.62 mol of SO₂
this means O₂ is limiting reagent.
1 mole of O₂ produce 2 mole of SO₃
1.31 mole of O₂ = 2 × 1.31 = 2.62 mol of SO₃
mass of SO₃ = 2.62 × 80
= 209.6 g
Percent yield =( actual yield / theoretical yield ) × 100 %
= (209.6 / 408) × 100 %
= 51.5 %
Thus, The percent yield for the reaction below when 364 g SO₂ and 42.0 g O₂ produce 408 g SO₃ is 51.5 %.
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Sodium reacts with water according to the equation shown below. If 4.6g of sodium is used, what mass of hydrogen gas will be produced? You may need some of the data in the table.
0.4g of Hydrogen will be produced when 4.6g of Sodium is used to provide Sodium Hydroxide.
The balanced equation for the formation of Sodium Hydroxide is given below:
2Na + 2H₂O ------> 2NaOH + H₂
It is shown that 2 moles of Na produce 2moles of Hydrogen. We know that the atomic mass of Sodium is 23g/mol. Then the number of moles present in 4.6g of Sodium would be,
Moles of Sodium = 4.6/23
Moles of Sodium = 0.2mol
Therefore,4.6g of Sodium has 0.2mol. Therefore, then 0.2 mol of sodium reacts to give out 0.2 mol of Hydrogen gas
The mass of hydrogen gas could be computed by the product of the mass of hydrogen gas and moles of hydrogen which is given by,
Mass of 2 atoms of hydrogen = 2x1x0.2
Mass of 2 atoms of hydrogen= 0.4g
Therefore, for every 0.2mol of Sodium, 0.1 mol of Hydrogen is produced which is equal to 0.4g of Hydrogen.
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What is the force of gravity needed to make a 13kg ball fall on earth? I need the formula, variables, work with unit
The force of gravity needed to make a 13kg ball fall on Earth is 127.53N.
How to calculate force of gravity?Force of gravity is a force that attracts any two objects with mass. The force of gravity is the weight of an object on Earth.
The weight of the force on an object due to the gravitational attraction between it and the Earth (or whatever astronomical object it is primarily influenced by).
The weight of an object can be calculated by multiplying the force of the object by acceleration due to gravity on Earth as follows:
Weight = force × 9.81m/s²
Weight = 13kg × 9.81m/s²
Weight = 127.53N.
Therefore, 127.53N is the weight of the ball on Earth.
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what size will the kids tongue be? normal or long
The mom has two capital t's
The dad has two lowercase t's
the mom has a long tongue and the dad has a normal tongue
picture is the punnet square
25 cm³ of a sample of vinegar (CH3COOH) was pipetted into a volumetric
flask and the volume was made up to 250 cm³. This solution was placed in a
burette and 14.2 cm³ were required to neutralise 25 cm³ of 0.1 mol dm-3
NaOH. Calculate the molarity of the original vinegar solution and its
concentration in g dm-³, given that it reacts with NaOH in a 1:1 ratio.
The concentration of the solution originally was 1.8 M.
What is the concentration?We know that the concentration of the solution is obtained from the formula of the neutralization reaction which is;
CAVA/CBVB = NA/NB
CA = concentration of the acid
CB = concentration of the base
VA = volume of acid
VB = volume of base
NA = number of moles of acid
NB = number of moles of base
Then
CAVANB = CBVBNA
CA = CBVBNA/VANB
CA = 0.1 * 25 * 1/14.2 * 1
= 0.18 M
Using the formula;
C1V1 = C2V2
25 * C1 = 0.18 * 250
C1 = 0.18 * 250/25
C1 = 1.8 M
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Te equation in question 19 is an example of which type of reaction?
Answer:
algebraic reaction is the answer of this question
You work in a museum that has a huge, beautiful stamed-glass window: Each gamell dints the light a different coice. Recenty up a table m front of the wmdiow: Plant 1 is im fiont of a biue stained glass, Plant 2 is in font of a purgie you tall the museum directur to move so it doesnit became maicurshed?You work in a museum that has a huge, beautiful, stained-glass window. Each panel tints the light a different color. Recently a new exhibit showcasing plants from around the world has set up a table in front of the window. Plant 1 is in front of a blue stained glass, Plant 2 is in front of a purple stained glass, and Plant 3 is in front of a green stained glass. Which plant should you tell the museum director to move so it doesn't become malnourished?
A. Plant 2
B. Plant 1
C. Plant 3
D. All three plants
The plant that should be moved here to protect from malnourishment is plant 3. The correct option is C.
What is visible spectrum?The visible light spectrum is the portion of the electromagnetic spectrum that can be seen by the human eye. Simply put, this range of wavelengths is known as visible light.
The visible spectrum, also known as the optical spectrum, is the portion of the electromagnetic spectrum whose radiation consists of photons capable of sensitizing a normal person's human eye. The corresponding visible light radiation range is identified.
That being said, plant 3 is situated in front of a green stained glass window.
Plants have chlorophyll pigment that reflects back green light, making green light less effective for photosynthesis and causing them to die as quickly as if they were kept in the dark.
Thus, the correct option is C.
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How many atoms of phosphorus are in 4.70 mol of copper(II) phosphate?
The number of atoms of phosphorus that would be in 4.70 mol of copper (II) phosphate is 56.61 x [tex]10 ^{23[/tex] atoms.
Avogadro's numberAccording to an established rule, 1 mole of any substance contains one Avogadro's number, which is 6.022 x [tex]10 ^{23[/tex] atoms.
Copper (II) phosphate contains atoms of copper, phosphorus, and oxygen. In ion form, the compound ionizes according to the following equation:
[tex]Cu_3(PO_4)_2 --- > 3 Cu^2^+ + 2P^4^+ + 8O^2^-[/tex]
This means that every 1 mole of copper (II) phosphate contains 2 moles of phosphorus. The equivalent mole of phosphorus in 4.70 mol of copper (II) phosphate would be:
= 4.70 x 2
= 9.4 mol of phosphorus.
We said 1 mole of any substance = 6.022 x [tex]10 ^{23[/tex] atoms.
Hence, 9.4 moles of phosphorus will contain:
9.4 x 6.022 x [tex]10 ^{23[/tex] atoms
= 56.61 x [tex]10 ^{23[/tex] atoms
In other words, 4.70 mol of copper (II) phosphate will contain 56.61 x [tex]10 ^{23[/tex] atoms of phosphorus.
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How many grams of RbOH are present in 31.0 mL of a 5.60 M RbOH solution?
17.79 g
The number of grams of RbOH present in the solution can be found by using the formula
[tex]c = \frac{m}{M \times v} \\ [/tex]
where
m is the mass in grams
M is the molar mass in g/mol
v is the volume in L or dm³
making m the subject we have
m = c × M × V
First of all we have to find the molar mass of RbOH
M(RbOH) = 85.5 + 16 + 1 = 102.5 g/mol
v = 31 ml = 0.031 dm³ or 0.031 L
c = 5.6 M
Substituting it into the formula we have
m = 5.6 × 102.5 × 0.031 = 17.79 g
We have the final answer as
17.79 gHope this helps you
10.0 g sample of an unknown ionic compound is dissolved, and the solution is treated with enough AgNO3to precipitate all the chloride ion and 30.1 g of AgClare recovered. Which of the following compounds could be the unknown?
The reaction is a double displacement reaction, a precipitate of silver chloride, AgCl, is obtained, and the unknown compound is barium chloride, BaCl₂
What are double displacement reactions?Double displacement reactions are reactions that occur when two soluble ionic compounds are mixed together, and a precipitate is formed as a result of the exchange of radicals between the metallic ions in the ionic compounds.
An example of a double displacement reaction is the reaction between barium chloride and silver nitrate, where a precipitate of silver chloride is obtained. The equation of the reaction is given below:
BaCl₂ (aq) + AgNO₃ (aq) ---> Ba(NO₃)₂ (aq) + AgCl₂ (s)
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Convert 1.57 x 1024 atoms of carbon to moles of carbon.
1.57 x 10²⁴ atoms of carbon to moles of carbon is 6.72 mole
Mole is the SI unit of amount of substance of a specified elementary entity
Here given data is
Atoms of carbon = 1.57 x 10²⁴
We have to calculate moles of carbon = ?
So one mole of carbon specifies 6.022×10²³ individual carbon atom that is mole of carbon
Then 1.57 × 10²⁴ atoms/6.022×10²³C×atom×mol⁻¹
Moles of carbon = 6.72 mole
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For reaction B, also analyze the possible hydrolysis of the salt in the aqueous solution, the change in the pH of the medium, and the reaction of the metal with the acid or alkali formed by the hydrolysis. Write electron equations for all oxidation-reduction reactions, indicate the oxidizing agent and the reducing agent.
B) al+na2s(aq)->
The redox reaction as it has been written can not be able to hold.
What is the redox reaction?We know that a redox reaction is the kind of reaction that involves the oxidation and the reduction of a specie. In this case, we can see the reaction that occurs between the aluminum ion and sodium sulfide.
We know that that reaction can not be able to hold because the reduction potential of the aluminum ion is -1.66 V while the reduction potential of sodium is -2.71 V.
as such, sodium is more reducing than aluminum hence it can not be displaced by it.
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When you are walking, your foot exerts a force that is ___ on the ground.
a. downward
b. sideward
c. upward
Patrick is a 16 year old boy whose body has stopped producing osteoclasts. What does this mean for his bones? What other parts of
his body will be affected by this?
Patrick is a 16 year old boy whose body has stopped producing osteoclasts this means for his bones that his bones will become weak and brittle and other part of his body like the hip and wrist and spine will be affected by this
Osteoclast weaken brittle bones and making them prone to breaking from even minor stresses like coughing or stopping and the most frequent location for fracture caused by osteoclasts are the hip writ and spine and bone is a living tissue that constantly degrade and is replaced and by increasing their resorptive activity and destroying bone to initiate normal bone repair and the cell known as osteoclasts mediate bone loss in pathogenic circumstances
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Hoping for help with at least the top one but potentially both. I have a hard time understanding if the subscripts go to the other elements or not.
The theoretical yield of the precipitate is 1185 g and the balanced reaction equation is; [tex]3Pb(NO_{3} )_{2} (aq) + Ni_{2} (SO_{4}) _{3} (aq) -------- > 2Ni(NO_{3} )_{3}(aq) + 3PbSO_{4}(s)[/tex]
What is a balanced reaction equation?We know that the term chemical reaction equation has to do with the interaction that exists between reactants and product. Now we know that a balanced reaction equation ought to have the same number of atoms of each of the elements that were combined in the reaction.
We have the balanced reaction equation as;
[tex]3Pb(NO_{3} )_{2} (aq) + Ni_{2} (SO_{4}) _{3} (aq) -------- > 2Ni(NO_{3} )_{3}(aq) + 3PbSO_{4}(s)[/tex]
Now;
Number of moles of nickel III sulfate = 531 g/406 g/mol = 1.31 moles
Number of moles of lead II nitrate = 3.91 moles
Since 3 moles of nitrate reacts with 1 mole of the sulfate
x moles of the nitrate reacts with 1.31 moles of the sulfate
x = 3.93 moles
Thus lead II nitrate is the limiting reactant.
If 3 moles of the nitrate produces 3 moles of the precipitate then
Theoretical yield = 3.91 moles * 303 g/mol
= 1185 g of precipitate
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