friction and normal force are examples of

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Answer 1

Answer:

Friction is a force that tends to oppose the relative motion between two bodies in contact. Frictional force always acts on a moving body from the direction opposite to the direction of motion. It opposes the motion, and therefore, helps to reduce the speed of the moving object. It is a contact force.


Related Questions

How can you use a simple model to describe a wave and its features?

Answers

Answer:

Explanation:

Use mathematical representations to describe a simple model for waves that includes how the amplitude of a wave is related to the energy in a wave. Patterns can be used to identify cause and effect relationships.

A vector consists both?

Answers

Answer:

magnitude and a direction

Explanation:

Why does the size of a white dwarf affect its visual luminosity?

Answers

Answer:

A typical white dwarf has a carbon and oxygen mass similar to the Sun, but is much smaller in size (similar to the Earth). It is much hotter (25,000 K), but because of its small size its luminosity is low. ... Some very nearby white dwarf stars can be observed directly through telescopes, though they are extremely faint.

Explanation:

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(answer choices: applied force, normal force, friction, electrical force, magnetic force and gravitational force)

(question in picture)

Answers

Answer:

3

Explanation:

because they are pushing a body

why is it less air pressure up in the sky and why does it affect our ears

Answers

Answer:

When you in a airplane you are in high altitude and thats where air density drops. Thats where ear pops come from.

Explanation:

A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energies of the diver and complete the statements below.

Where m = mass (kg), g = 9.8 m/s2, v = velocity (m/s), h = height (m), KE = kinetic energy (J), and GPE = gravitational potential energy (J).
Use the equations above to answer the following questions.

A diver with a mass of 90 kg is at a height of 10 m, and he has not jumped off of the board yet (v = 0 m/s). When the diver reaches a height of 5 m (Point C), his gravitational potential energy is

A. 1350 J

B. 8820 J

C. 4410 J

D. 0 J

and his velocity is

E. 4.5 m/s

F. 0 m/s

G. 3.2 m/s

H. 9.9 m/s

Please help will mark brainliest

Answers

Mass of the diver (m) = 90 Kg.Height of the board from the ground (h) = 10 m.Acceleration due to gravity (g) = 9.8 m/s^2.Height of the diver from the ground when he reaches point C (x) = 5mInitial velocity (u) = 0 m/sWe know, gravitational potential energy of a body = mass × acceleration due to gravity × height.Therefore, the gravitational potential energy of the diver when he reaches point C (GPE) = mg(h - x)or, GPE = [90 × 9.8 × (10-5)] Jor, GPE = [90 × 9.8 × 5] Jor, GPE = 4410 JFor a freely falling body,v^2 - u^2 = 2ghor, v^2 = 2ghWe know, kinetic energy of a body = 1/2 mv^2Therefore, kinetic energy of the diver when he reaches point C (KE) = 1/2 m(2gx)Here, 2gx = (2 × 9.8 × 5) = 98 (m/s)^2We have already seen v^2 = 2gh or, v = √2ghSo, the velocity of the diver = √2gx = √98 m/s = 9.9 m/s

Answers:

The gravitational potential energy of the diver when he reaches point C is 4410 J.

The velocity of the diver is 9.9 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

h=10m-5m=5mm=90Kgg=9.8m/s^2

[tex]\\ \sf\longmapsto PE=mgh[/tex]

[tex]\\ \sf\longmapsto PE=90(5)(9.8)[/tex]

[tex]\\ \sf\longmapsto PE=4410J[/tex]

Now

It's converted to kinetic energy while reaching ground.

[tex]\\ \sf\longmapsto K.E=4410[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{2}mv^2=4410[/tex]

[tex]\\ \sf\longmapsto 90v^2=8820[/tex]

[tex]\\ \sf\longmapsto v^2=98[/tex]

[tex]\\ \sf\longmapsto v=9.9m/s[/tex]

The body weighs 15N. What is the mass of that body?

Answers

The equation you can use to find the mass is:

Weight = mass x gravity

Where you can rearrange the equation to find the mass.

Mass = weight/gravity

The known values are:
Weight = 15
Gravity = 9.81

Substitute the known values into the equation.

Mass = 15/9.81

Mass = 1.53kg (rounded to 2dp)

Explain how energy changes in the spring toy below when it goes downstairs.

Answers

Given what we know, we can confirm that the spring toy uses the transfer of potential gravitational energy into kinetic energy of motion in order to fall down the stairs.

How does the toy do this?The toy stores potential energy. It does this using gravity. Once it begins to fall, it uses the momentum from each fall to continue to do so. With each fall, its stored potential energy is transferred to kinetic energy.

Therefore, we can confirm that the spring toy uses its position at the top of each stair as a source of potential energy, which using the momentum from the last fall, it transfers into the kinetic energy of motion as it falls, all through the help of gravity.

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Select the correct answers from the list.(1 point) A black hole begins to form as an aging star abruptly collapses when it ceases__________ . This occurs after the star has consumed its component elements in this order___________.

Answers

A black hole forms as a star collapses when it ceases emitting radiation from fusion reactions. This occurs after the star has consumed hydrogen, helium, then through iron.

Star evolution refers to the process by which stars evolve (change) over time.

A black hole can be defined as a collapsed star where the gravitational field in its nucleus becomes greater than particles cannot escape from it.

In consequence, black holes are cosmic bodies in which gravity is so powerful that nothing (i.e., particles, radiation, light, etc.) can escape from them.

Nuclear fusion refers to the energy reactions produced by the fusion of hydrogen at the core of a star, thereby becoming helium.

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What two things related to sedimentary rocks do you see at the Grand Canyon ?

Answers

Answer:

sandstone and mudstone

Explanation:

These diagrams represent two types of tectonic plate boundaries

Answers

Convergent boundaries are caused by the collision of two plates and can originate volcanoes. Transforming boundaries produce fractures by displacement. The correct option is D. Type A boundaries have fewer volcanoes.

----------------------------------------

The crust -the outermost layer of the earth- is divided into many plates that move over the mantle.

These plates are limited by three types of ridges or borders that differ in the movement they produce.

Boundaries types:

I. Divergent:

This boundary occurs when two plates separate and molten material rises from the mantle creating a new crust.

The hot material creates a new seabed between the separating plates, expanding the sea bottom.

II. Convergent.

Collision area between two plates.

Two oceanic plates might collide, or one oceanic plate with a continental one.

In this last case, the oceanic crust sinks under the continental plate, and magma rises to the surface by crevices.

The thicker and older plate subduces under the other plate.

Collisions create volcanic arches and continental arches.

III. Transforming.

The plates slide laterally with each other, and they are usually called faults.

It is associated, in general, with the oceanic ridge, although it might also occur in the continental plate.

No rocky material is either destroyed or formed.

When the plates move and produce a displacement of one transforming limits from side to side, earthquakes occur.

The movement breaks the crust and originates pronounced fractures.

In the attached images, we can see

image A representing transforming boundaries, image B representing Convergent boundaries.

Image B is the one that can originate volcanoes because transforming boundaries only produce fractures.

So the correct option would be D.

--------------------------------

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Answer:

d

Explanation:

Compare and contrast synthesis and decomposition reactions.

Answers

Answer:

Synthesis reactions are chemical reactions where two elements combine to make a product. Decomposition reactions are chemical reactions where a reactant produces another product, usually two, or even more. This is when the bonds in the compound are broken apart to make new compounds.

Explanation:

What the number ??? Help Please

Answers

Answer:

first number is 113 and the second number is 15

Chapter Name :- Vector

Question :-

A car is moving at Vc speed. Rain is falling vertically at a speed of 10 m / s. What is the value of Vc in this case,if the front glass of the car will get wet?

Answer :- Vc ≥ 10

I need Explanation! Please Don’t do copy from net! If you don’t know then no need to answer!

Answers

The value of the speed of the car, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].

The given parameters:

Speed of the car, = VcSpeed of the rain, = 10 m/s

The relative velocity of the car with respect to the falling rain is calculated as;

[tex]V_{C/R} = V_C- V_R[/tex]

If the speed of the car equals the speed of the rain, the rain will fall behind the car.If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.If the speed of the car is greater than speed of the rain, the rain will fall on the car.

Thus, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].

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how many kilojoules is this?

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Answer:

How to convert joules to kilojoules

One joule is equal to thousandth of a kilojoule:

1J = 0.001kJ

The energy in kilojoules E(kJ) is equal to the energy in joules E(J) divided by 1000:

E(kJ) = E(J) / 1000

Example

Convert 500 joules to kilojoules.

The energy E in kilojoules (kJ) is equal to 500 joules (J) divided by 1000:

E(kJ) = 500J / 1000 = 0.5kJ

Joules to kilojoules conversion table

Energy (J) Energy (kJ)

1 J 0.001 kJ

2 J 0.002 kJ

3 J 0.003 kJ

4 J 0.004 kJ

5 J 0.005 kJ

6 J 0.006 kJ

7 J 0.007 kJ

8 J 0.008 kJ

9 J 0.009 kJ

10 J 0.01 kJ

20 J 0.02 kJ

30 J 0.03 kJ

40 J 0.04 kJ

50 J 0.05 kJ

60 J 0.06 kJ

70 J 0.07 kJ

80 J 0.08 kJ

90 J 0.09 kJ

100 J 0.1 kJ

200 J 0.2 kJ

300 J 0.3 kJ

400 J 0.4 kJ

500 J 0.5 kJ

600 J 0.6 kJ

700 J 0.7 kJ

800 J 0.8 kJ

900 J 0.9 kJ

1000 J 1 kJ

2000 J 2 kJ

3000 J 3 kJ

4000 J 4 kJ

5000 J 5 kJ

6000 J 6 kJ

7000 J 7 kJ

8000 J 8 kJ

9000 J 9 kJ

10000 J 10 kJ

100000 J 100 kJ

hope it help u

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A pail of water of mass 2000 gm is rotated in a vertical circle of radius 1.00 m. What is the pail’s minimum speed at the top of the circle if no water is to spill out and the tension exerted by the string is 25 N?

Answers

The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

The given parameters:

Mass of the water, m = 2000 g = 2 kgRadius of the circle, r = 1 mTension on the string, T = 25 N

The net force on the pail of water at the top of the vertical circle is calculated as follows;

[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]

Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s

We are given;

Mass of the pail of water; m = 2000 g = 2kg

Radius of the circle; r = 1 m

Tension exerted by string; T = 25 N

To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;

W - T = ma

Where;

W is weight = mg

T is tension on the string

Now, in circular motion, we know that;

Acceleration is; a = v²/r

Thus;

mg - T = m(v²/r)

Making v the subject of the formula gives us;

v = √[(r(T + mg)/m)

Plugging in the relevant values gives;

v = √[(1(25 + (2 * 9.8))/2)

v = 4.722 m/s

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A weightlifter lifts a 350 N set of weights over his head a vertical distance of 2.5 meters above the floor. Calculate the work the athlete does on the weights, assuming he lifts them at a constant speed.

A. 525 J

B. 750 J

C. 1005 J

D. 700 N•m

E. 875 J

Answers

Answer: D) 700 N•m

Answer: Took that test already
The answer is E! I use a calculator and I did 350 divided by 2.5 and the answer was 875!!

What determines the amount of gravitational force between
objects?

Answers

Answer:

The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects.

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Explain briefly about viscous force ​

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The viscous force ​refers to the resistance of a fluid to flow.  It is measured in Newton-second per square meter.

The viscous force can be defined as the resistance that a fluid has to flow in a given space.

Viscous force is proportional to the fluid velocity, while this constant is called viscosity.

The viscous force can be measured in Newton-second per square meter (abbreviated as N s/m2).

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What is an example of bad energy efficiency but good energy conservation?

Answers

Answer:

Energy conservation relies on people cutting back on activities that consume energy—by turning off lights or driving less or using appliances less often.

Explanation:

hope this helps

Other than temperature, which property also has an effect on the rates of chemical reactions?
A.Color of reactants
B.Concentration of reactants
C.Solubility of reactants
D.Volume of reactants

Answers

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants. The correct answer is B

The rate of chemical reaction means how chemical react with respect to time or as a function of time. The rate of chemical reaction tells us the speed or how fast chemicals react.

There are many factors that can affect the rate of chemical reaction. Temperature is one of them. Increase in temperature will increase the rate at which chemical react.

The color of reactants, solubility of reactants and volume of reactants have nothing to do with the rate of chemical reaction.

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants.

Other factors affecting the rate of chemical reaction are:

the physical state of the reactants surface area temperature and the presence of a catalyst

Therefore, the correct answer is option B

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A 1.5 kg ball has a velocity of 12 m/s just before it strikes the floor. Find the impulse on the ball if the ball bounces up with a velocity of 10 m/s.

Answers

Hi there!

Recall:

Impulse = Change in momentum

I = Δp = mΔv = m(vf - vi)

Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.

Plug in the givan values:

Δp = 1.5(-10 - 12) = -33 Ns

**OR, the magnitude: |-33| = 33 Ns

Solve the science problem

Answers

Answer:

1.hydrogen

2.helium

3. lithium

4.beryllium

5.boron

6.carbon

7.nitrogen

8.oxygen

9.fluorine

10.neon

Please help my physics teacher cannot teach pls hurry pls help uwu

Answers

Hi there!

To find how much the spring stretches with the mass attached, we must find the spring's equilibrium point.

The equilibrium point satisfies the following:

[tex]\large\boxed{\Sigma F = 0}[/tex]

The two forces acting in this situation are the weight of the mass and the spring force.

The spring force (restoring force) is in the opposite direction of the weight, so:

[tex]\Sigma F = 0 = Mg- k\Delta x[/tex]

Mg = weight

k = Spring Constant (N/m)

Δx = distance to equilibrium point (m)

Now, we can set the two equal to each other:

[tex]Mg = k\Delta x\\\\544 = 1146\Delta x\\\\\boxed{\Delta x= .475 m}[/tex]

i do believe that i need help

Answers

WHAT IS THAT omg Helpppp

A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
bead collides elastically with a larger 0.60 kg bead initially at rest. After the collision the smaller
bead moves to the left with a velocity of 0.70 cm/s. Find the distance the larger bead moves along
the wire in the first 5.0 s following the collision?||

Answers

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4       ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28   momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

Describe the way that distance is changing in relation to tiMe

Answers

Answer:

DistaNcE chanGes iN relAtiOn tO TiMe Bc ThE fuRthEr yOu Go ThE mOrE TiMe goeS bY

Calculate the weight of the object of mass
20kg. (g= 10 m/s^2)

Answers

Answer:

mass= 20kg

g=10m/s2

weight is F=mg

F=20×10

F=200N

How many neutrons are in K-37?

Answers

Answer:

18 neutrons

Explanation:

Potassium is nuimber 19 on periodic table, so when the mass equals 37, you simply subtract 37-19 to get 18

potassium usually has a mass of 39, so when we have potassium 37, it is two less neutrons than normal

What is an object's mass if it accelerates at 5 m/s2 when a force of 0.5 N is applied?

Answers

Answer:

0.1kg

Explanation:

mass = force / acceleration

0.5 / 5

0.1kg

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