Answer:
A. g(x) = -x^2 - 3.
Step-by-step explanation:
If we reflect f(x) over the x -axis we get -f(x) which is the mirror image of f(x)
To get g(x) we then translate the image 3 units down,
g(x) = -x^2 - 3.
Given the function graphed below, find the average rate of change over the
interval x= 2 to x = 4. I’ve been stuck on this question for a little bit . Can’t seem to wrap my head around it
Answer:
Approximately 0.3.
Step-by-step explanation:
I can only estimate the value of the function when x = 2. it looks like it's about 2.4.
Average rate of change = [(f4) - f(2)] / (4 - 2)
= (3 - 2.4) / 2
= 0.6/2
= 0.3.
i'll give brainliest and points to whomever answers these two questions, thank you so much in advance!
Q8- what's the S.S of the inequality: x² + 4 > 2
a) R
b) ∅
c) R-
d) R+
Q9- if x + yi = (1 + i)⁴ , then x + y = ......
a) 4
b) - 4
c) 2
d) - 2
an explanation for future reference would be GREATLY appreciated, thank you again T^T
Answer:
8 Answer is a) R
9 Answer is b) -4
Step-by-step explanation:
Answer of your Question bro and good evening and please mark me as brainliest and thank u
what is the solution of 9 (x-8) = 3 (4x-12)
() = Exponents The things in perenthacys are exponents
Solving as exponents
[tex]\\ \rm\Rrightarrow 9^{(x-8)}=3^{(4x-12)}[/tex]
[tex]\\ \rm\Rrightarrow 3^{2(x-8)}=3^{2(x-6)}[/tex]
[tex]\\ \rm\Rrightarrow 2(x-8)=2(x-6)[/tex]
[tex]\\ \rm\Rrightarrow 2x-16=4x-12[/tex]
[tex]\\ \rm\Rrightarrow -2x=4[/tex]
[tex]\\ \rm\Rrightarrow x=-2[/tex]
Answer:
[tex]x=-2[/tex]
Step-by-step explanation:
Given equation:
[tex]9^{x-8}=3^{4x-12}[/tex]
Rewrite 9 as 3²:
[tex]\implies (3^2)^{x-8}=3^{4x-12}[/tex]
[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]
[tex]\implies 3^{2(x-8)}=3^{4x-12}[/tex]
[tex]\implies 3^{2x-16}=3^{4x-12}[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):[/tex]
[tex]\implies 2x-16=4x-12[/tex]
Subtract 2x from both sides:
[tex]\implies 2x-16-2x=4x-12-2x[/tex]
[tex]\implies -16=2x-12[/tex]
Add 12 to both sides:
[tex]\implies -16+12=2x-12+12[/tex]
[tex]\implies -4=2x[/tex]
Divide both sides by 2:
[tex]\implies \dfrac{-4}{2}=\dfrac{2x}{2}[/tex]
[tex]\implies x=-2[/tex]
Select the equation of the line in slope-intercept form: 4x + 9y = 36
Answer:
y= -4x/9+4
Step-by-step explanation:
4x+9y=36 (move 4x)
9y=-4x+36 (divide by 9)
y= -4/9x+36/9
y= -4x/9+4
please help with this
Answer:
F = 53.1°
Step-by-step explanation:
When you consider F as your angle
cos F = adjacent / hypotaneous
or, cos F = EF/DF
We do not have DF right now,
so DF² = DE² + EF²
DF = √ (12² + 9²)
DF = 15
cos F = adjacent / hypotaneous
or, cos F = EF/DF
cos F = 9 / 15
F = cos ⁻¹ (9/15)
F = 53.1°
Factor fully. Show all work.
a) 27m²−3
b) 10x³+5x²−50xy−25y
Answer:
A=
[tex]3(3m + 1)(3m - 1)[/tex]
Step-by-step explanation:
[tex] {27m}^{2} - 3[/tex]
Factorise
[tex]3( {9m}^{2} - 1)[/tex]
Rewrite it
[tex]3(( {3m)}^{2} - {1}^{2} )[/tex]
[tex]3(3m + 1)(3m - 1)[/tex]
Find the value of x.
Answer:
Step-by-step explanation:
Comment
The general formula for a tangent and secant is
tangent^2 = external segment * full length of the secant.
Givens
tangent length = x
external segment = 7
secant length = 7+ 21
Formula
x^2 = 7 * (7 + 21) Remove brackets
x^2 = 7 * 28 Combine
x^2 = 196 Take the square root of both sides
√x^2 = √196
x = 14
Answer: x = 14
help with these 10th grade geometry angle problems? will reward brainliest!
Answer:
Step-by-step explanation:
What are the domain and range of f (x) = log (x minus 1) + 2?
domain: x > 1; range: y > 2
domain: x > 1; range: all real numbers
domain: all real numbers; range: y > 1
domain: all real numbers; range: all real numbers
Answer:
domain: x > 1; range: all real numbers
Step-by-step explanation:
Given function: [tex]f(x)=\log(x-1)+2[/tex]
Logarithms are not defined for zero or negative numbers.
[tex]\implies (x-1) > 0 \implies x > 1[/tex]
Therefore:
domain (input values): [tex]x > 1[/tex]range (output values): all real numbersAnswer:
B on edge
Step-by-step explanation:
Just took the test :)
Find the value of X
Answer:
x = 14
Step-by-step explanation:
By tangent secant theorem[tex] x^2 = 7(7+21)[/tex][tex]\implies x^2 = 7(28)[/tex][tex]\implies x ^2=196[/tex][tex]\implies x=\pm\sqrt{196}[/tex][tex]\implies x=\pm 14[/tex]x can not be negative[tex]\implies x=14[/tex]Someone help me.............asap
Answer:
11 h
Step-by-step explanation:
1/2 h
11h 1/2 will be need for a bike
i really need help on this. can you please solve
Answer:
371/999
Step-by-step explanation:
all repeating numbers like that just go over nines. Two repeating? Over 99. Four repeating? Over 9,999
the bill at an electronics store was $52 before tax.
tax is 5 percent. what is the total price with tax?
Answer:
$54.6
Step-by-step explanation:
To solve the question, we need to find how much 5% of 52 is
For questions where we need to calculate the percentage, we will multiply the number by given percentage and then divide it by the whole, 100%
52*5/100 = 2.6
Now the price before the tax was 52 and the tax is 2.6
the total price:
2.6 + 52 = 54.6
2 x (6÷2 +8) -4 Help me
Answer:
22x-4
Step-by-step explanation:
2x(3+8)−4
Simplify 3+8 to 11.
2x×11−4
Simplify 2x times 11 to 22x.
22x−4
Envision Geometry 10-1 Circles 22. page 425
The segment area of the circle that's given in the envision geometry is 2.568.
How to calculate the segment area?It should be noted that the segment area is given as:
= (a/360)π × R² - Area of triangle
= (90/360)π × 3² - (1/2 × 3²)
= 9π/4 - 9/2
= 2.568
In conclusion, the segment area of the circle that's given in the envision geometry is 2.568.
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The sum of two numbers is 40 and the difference is 8. What are the numbers?
Answer:
24 and 16.
Step-by-step explanation:
They both are in between the sum of the two numbers.
A guest was on holiday before going to the wedding at 6 o’ clock. He had to travel 120km to get to the venue. He travelled at an average of 100km/h . Verify if He will reach the dance on time if he leaves at 16:40
He will reach the dance before time if he leaves at 16:40.
What is speed- distance formula?The formula for speed is speed = distance ÷ time.
To work out what the units are for speed, you need to know the units for distance and time. In this example, distance is in metres (m) and time is in seconds (s), so the units will be in metres per second (m/s).
Given distance= 120 Km, speed= 100 km/h
For this speed,
time= distance/ speed
= 120/100
= 1.2 hours
If the guest leave at 4:40 p.m. then by the speed of 100 km/h he will reach the venue at 06:00 p.m.
Hence, he will reach before the time at wedding.
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Find the equation of the line shown
Answer: y = 1/2x + 1/2
The inside of a baking pan is to be lined with tinfoil. the pan is 12 inches long, 9 inches wide, and 1.5 inches tall. how many square inches of tinfoil are needed?
The inside of a baking pan is to be lined with tinfoil. Then the amount of tinfoil needed will be 171 square inches.
What is a rectangle?It is a polygon with four sides. The total interior angle is 360 degrees. A rectangle's opposite sides are parallel and equal, and each angle is 90 degrees. Its diagonals are all the same length and intersect in the center.
The inside of a baking pan is to be lined with tinfoil. the pan is 12 inches long, 9 inches wide, and 1.5 inches tall.
Then the amount of the tinfoil will be
The surface area of the rectangle with an open lid is given as
Surface area = 2(LH + WH) + LW
Then the surface area of the tinfoil will be
Surface area = 2(12 x 1.5 + 9 x 1.5) + 12 x 9
Surface area = 2 (18 + 13.5) + 108
Surface area = 2 x 31.5 + 108
Surface area = 63 + 108
Surface area = 171 square inches
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Find the slope of the line through
the points (1, 4) and (7, 1).
A
1
2
B
-2
1
2
D
2.
I need the the number
y=3x+3
Step-by-step explanation:
The m is 3 because it is rise over run. For every 3 up it goes one over (3/1) or just 3. The b is 3 because b is where x equals 0 and it is at 3.
Dexter is thinking of a number, x. Two more than three times his number is the same value as thirteen less than five times his number. Write this information as an equation in x. Solve your equation to find the value of x.
Dexter is thinking of a number, x. Two more than three times his number is the same value as thirteen less than five times his number. The number which he is thinking is 7.5.
What is equation?Two or more expressions with an equal sign is called as Equation.
Given that Dexter is thinking of a number, x. Two more than three times his number is the same value as thirteen less than five times his number.
Let the number which Dexter is thinking be x.
Two more than three times his number.
It means value two is added to the product of 3 and the number which he is thinking x.
3x+2
thirteen less than five times his number
It means value thirteen is subtracted from the product of 5 and the number which he is thinking x.
5x-13.
It is given Two more than three times his number is the same value as thirteen less than five times his number
3x+2=5x-13
Take the like terms to one side
13+2=5x-3x
15=2x
Divide both sides by 2.
x=7.5
Hence the value of x is 7.5.
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Nico is planting grass in his backyard. He is using 1 foot grass squares and has to cover an area that is 24 feet long and 20 feet wide.
How many 1 foot squares does Nico need?
pls help! Ill give brainly if possible! :)
The number of the grass squares of 1 square foot will be 480.
What is the area?The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the rectangle in a two-dimensional plane is called as the area of the rectangle.
The total area covered by the grass will be:-
A = L x W
A = 24 x 20 = 480 square feet
Number of the grass squares having an area of 1 square foot:-
N = Total area / area of one grass square
N = 480 square feet / 1 square feet
N = 480
Therefore the number of the grass squares of 1 square foot will be 480.
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Explain how you would graph the inequality, "b ≤ 0
Answer:
the inequality, b ≤ 0 has interval Notation of -∞,0
Step-by-step explanation:
the inequality, b ≤ 0 has interval Notation of -∞,0
A. Determine the length of Seneca between Mesa and La Paz Dr.
Round your answers to the nearest foot. Show all your work and explain each step of your solution.
B. Determine whether the driver on Seneca Street was traveling within the speed limit.
Round your answers to the nearest foot. Show all your work and explain each step of your solution.
C. Determine the maximum length of the skid marks left on Seneca Street by a car that travels within the speed limit.
Round your answers to the nearest foot. Show all your work and explain each step of your solution.
SHOW YOUR WORK!
The length of Seneca between Mesa and La Paz Dr is = 144ft.
The driver of the Seneca Street was driving at 0.75 mi/hr therefore he was with the speed limits.
The maximum length of the skid marks left of Seneca Street by a car that travels within the speed limit is = 144ft
Calculation of car speed limitsTo determine the length of Seneca, the various lengths of Mesa and La Paz Dr is used;Length of Mesa (a)= 308ft
Length of La Paz Dr (c)= 340ft
Length of Seneca =b
Using Pythagorean theorem,
c²= a² + b²
340²= 308² + b²
make b the subject formula,
b² = 340² - 308²
b² = 115,600 - 94,864
b²= 20736
b = √20736
b = 144ft.
To determine the if the driver at Seneca Street was driving at speed limit;The speed limit within the Seneca road(s) = 50mi/h
The coefficient of friction (f) based on the surface material = 0.7 (asphalt).
The distance covered by the car = 144ft to miles = 144/5280 = 0.027.
Therefore the speed of car(s)
=√30fd
= √30 × 0.7× 0.027
= √0.567
=0.75 mi/hr
To determine the maximum length of the skid marks left of Seneca Street by a car that travels within the speed limit is the same with the length of Seneca. which is = 144ft.Learn more about speed here:
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PLEASe help math ...
Answer:
21.6 units² (nearest tenth)
Step-by-step explanation:
[tex]\textsf{Area of a trapezoid}=\dfrac{1}{2}(a+b)h \quad \textsf{(where a and b are the bases and h is the height)}[/tex][tex]\textsf{Area of a semicircle}=\dfrac12 \pi r^2 \quad \textsf{(where r is the radius)}[/tex]
Given:
a = 2b = 8h = 4r = 2 ÷ 2 = 1[tex]\begin{aligned}\textsf{Area of figure} & =\textsf{area of trapezoid + area of semicircle}\\& = \dfrac{1}{2}(a+b)h+\dfrac{1}{2} \pi r^2\\& = \dfrac{1}{2}(2+8)(4)+\dfrac{1}{2} \pi (1)^2\\& = 20+\dfrac{1}{2} \pi\\& = 21.6\: \sf units^2 \:(nearest\:tenth)\end{aligned}[/tex]
Area of the trapezium
1/2(Sum of parallel sides)×Height1/2(2+8)(4)2(10)20units²Area of semicircle
π(2/2)²/2π/21.57units²Total area
20+1.5721.6units²(Rounded)What is the Surface area of a rectangle with a length of 3 width of 2 and a height of 12
How to do 2/5 = (x-3)/(7x+15)
Answer:
[tex]x = - 5 [/tex]
Step-by-step explanation:
To work out this question you have to first cross multiply.
[tex] \frac{2}{5} = \frac{(x - 3)} {(7x + 15)} \\ \\ 2(7x + 15) = 5(x - 3)[/tex]
When you cross multiply you will get the equation above. Therefore
[tex](2 \times 7x) + (2 \times 15) = (5 \times x) \\ - (5 \times 3) \\ \\ 14x + 30 = 5x - 15 \\ \\ 14x - 5x = - 30 - 15 \\ \\ 9x = - 45[/tex]
Therefore
[tex] \frac{9}{9} x = \frac{ - 45}{9} \\ \\ x = - 5[/tex]
Answer:
x = -5
Step by step:
multiply both side by 7x + 15.
2/5 (7x+15)= x − 3
Simplify 2)5 (7x+15) to 2(7x+15)/5.
2(7x+15)/5= x - 3
multiply both sides by 5.
2(7x+15)= 5x - 15
Expand.
14x+30= 5x - 15
subtract 5x from both sides.
14x+30−5x= − 15
Simplify 14x + 30 - 5x14x + 30−5x to 9x + 309x + 30.
9x+30= - 15
Subtract 30 from both sides.
simplify
x = -5
Which is equivalent to cos-1(0)? give your answer in radians.
If cos90 is equivalent to zero, hence the cos inverse of 0 is 90 degrees which is equivalent to pi/2 in radians
Inverse of trigonometry functionInverse of a function are the opposite of the function. Given the inverse of cosine function as shown:
[tex]cos^{-1}x[/tex]
If x = 0, hence;
[tex]cos^{-1}{0[/tex]
If cos90 is equivalent to zero, hence the cos inverse of 0 is 90 degrees which is equivalent to pi/2 in radians
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A number y increased by 5 is at least -21
- - - - - - - - - - - - - - - - - - - - - - - - -- - - - - - - - - -
[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Given question:-}}}}[/tex]
❖ A number y increased by 5 is at least -21.
[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}[/tex]
❖ First, if you come across the word "increased" it means we
"increase" a number, or add something to that number, like
y increased by 5 [tex]\longmapsto[/tex] [tex]\sf{y+5}[/tex]
Now, we are also given that this expression is at least -21, which means it can't be -21; it can be -21 or it can be greater than -21.
So we have
[tex]\longmapsto\sf{y+5\geq -21}}[/tex]
Solving for y
Subtract 5 on both sides:-
[tex]\longmapsto\sf{y\geq -21-5}[/tex]
[tex]\longmapsto\sf{y\geq -26}[/tex]
So the values of y greater than or equal to -26 will make this inequality true.
Good luck with your studies.[tex]\rule{300}{1}[/tex]
Answer:
y >= - 26
Step-by-step explanation:
your equation at first looks like this
y + 5 >= -21
then you subtract 5 to both sides
y >= -26