The moles of water produced by the reaction of 1.1mol of ammonia with oxygen gas will be 1.65moles.
According to given reaction in the question,
2NH₃(g) + 5/2O₂ --- 2NO(g) + 3H₂O(g)
1.1mole
We know,
mole of H₂O ÷ coefficient of H₂O = mole of NH₃ ÷ coefficient of NH₃
mole of H₂O ÷ 3 = 1.1 ÷ 2
moles of H₂O = 1.65 or 1.6 moles
Therefore, the moles of water produced by the reaction of 1.1mol of ammonia with oxygen gas will be 1.65moles.
When the gaseous ammonia reacts with the oxygen we obtain nitrogen monoxide and water vapour. This reaction is a combustion reaction as well as a red-ox reaction.
Moreover, it is an exothermic process as a large amount of heat is liberated.
An oxidation-reduction(redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species.
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- Correct answer to multiple choice = marked, rated to max& thanked
If 0.250 mol of red phosphorus reacts with 0.625 mol of yellow sulfur , what is the empirical formula of the product
Answer:
P2S5
Explanation:
This answer is pretty much asking for two numbers that are mutually prime and have a ratio of 0.25 to 0.625
0.25 = 1/4
0.625 = 5/8
the ratio of 0.25 to 0.625 would thus equal 1/4:5/8 which is 0.4
So, two numbers that are mutually prime and divide to 0.4
Set up the equation:
x/y = 0.4 where x is the moles of red phosphorus and y is the moles of sulfur.
With some trial and error, it's easy to find out that 2 and 5 are the solutions.
Since x = 2 and y = 5, the subscripts for the PxSy compounds are found.
P2S5 would be the empirical formula
Convert 1.54 x 10^25 molecules of water into moles.
The moles of water = 0.25×[tex]10^{2}[/tex]
Given Molecules= 1.54×[tex]10^{25}[/tex] molecules
Avogadro number = 6.02×[tex]10^{23}[/tex] molecules
Number of Moles= Number of Molecules ÷ Avogadro Number
Number of moles = 1.54×[tex]10^{25}[/tex]÷6.02×[tex]10^{23}[/tex]
= 0.25×[tex]10^{2}[/tex] moles
Therefore number of moles are 0.25×[tex]10^{2}[/tex] moles
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Particle X has 16 protons, 17 neutrons and 18 electrons. Particle X
an atom of a metal
an atom of a noble gas
an anion
a cation
Find the energy in kJ for an x-ray photon with a frequency of 2.4 X 1018 s-1.
The energy for the x-ray photon is 1.619x10⁻³³ kJ.
Describe energy.The quantitative characteristic that is conveyed to a body or to a physical system in physics is called energy. Energy can be observed in the performance of labor as well as in the form of heat and light. Energy is a limited resource that can only be changed from one form to another and cannot be created or destroyed, in accordance with the principle of energy conservation.
The SI's (International System of Units) unit of energy measurement is the joule (J). Common types of energy include the kinetic energy of a moving object, the potential energy of a stationary object, the elastic energy of a stationary object, the chemical energy associated with chemical reactions, the radiant energy of electromagnetic radiation, and the internal energy of a thermodynamic system.
Given, frequency of photon (v) = 2.4x1018 s⁻¹
Planck's constant (h) = 6.63x10⁻³⁴ J s
Energy (E) = h x v = 6.63x10⁻³⁴ x 2.4x1018
= 1.619x10⁻³⁰ J
= 1.619x10⁻³³ kJ
Hence, the energy for the x-ray photon with a frequency of 2.4x1018 s⁻¹ is 1.619x10⁻³³ kJ.
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Calculate the mass of NaCl in 450g of NaCl solution containing NaCl w/w%
Answer:
MM of Nacl is 58.5
1000=450
58.5=26.325g
Chromium has three naturally-occurring isotopes. It is 80% Chromium-52, 14% Chromium-53, and 6% Chromium-51. What is the average atomic mass?520.80 amu 5208 amu 52.08 amu 79.62 amu
PLEASE HELP
The average atomic mass of chromium with three isotopes is 52.08amu (option C).
How to calculate average atomic mass?Average atomic mass is the weighted average of the atomic masses of the naturally occurring isotopes of an element.
The average atomic mass of an isotopic element can be calculated as follows:
80% Chromium-5214% Chromium-536% Chromium-51Average atomic mass = (80% of 52) + (14% of 53) + (6% of 51)
Average atomic mass = 41.6 + 7.42 + 3.06
Average atomic mass = 52.08amu.
Therefore, 52.08amu is the average atomic mass of the chromium isotopes.
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Determine the molecular/formula masses of the following compound. Round the masses of the element from the periodic table to the nearest tenth of a gram Th(SO4)2
The question requires us to determine the molecular mass of the compound thorium sulfate (Th(SO4)2), considering the atomic masses to the tenth of a gram.
The atomic masses of the elements present in the molecule given are:
Th: 232.0 u
S: 32.1 u
O: 16.0 u
To obtain the molecular mass of the compound, we must consider the number of atoms of each element: there are 8 oxygen (O) atoms, 2 sulfur (S) atoms and 1 thorium (Th) atom, therefore we calculate the mass as:
molecular mass Th(SO4)2 = (1 * 232.0) + (2 * 32.1) + (8 * 16.0) = 424.2 g/mol
Therefore, the molecular mass of Th(SO4)2 is 424.2 g/mol.
A map showing the acidity of rain across the United States is provided. The pattern of acid rain is best explained by which of the following observations?
The patterns of acid rain is best explained on the basis of it's ph observations.
Rain or any other form of precipitation that is unusually acidic, is referred to as acid rain (low pH). The Northeastern United States contains the regions with the highest levels of acidity (lowest pH values). The Northeast's concentration of industrial and power facilities, numerous cities, and dense population are to blame for this trend of high acidity.
Infrastructure, marine life, and plants can all be harmed by acid rain. Sulfur dioxide and nitrogen oxide emissions cause acid rain by reacting with the water molecules in the atmosphere to create acids. It has been noted that acid rain also has negative effects on forests, freshwaters, and soils. It also kills insect and aquatic life-forms, damages structures, and has an effect on human health.
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Which types of orbitals are found in the principal energy level n=2?
The kind of orbitals precisely found in the principal energy level n=2 are the one 2s orbital and three 2p orbitals
Why the n=2 orbital has four orbitals?It follows that in the electronic configuration of elements describes the distribution of electrons of elements is shared into different energy levels through the orbitals.
In the second orbital, there are actually four different types of orbitals which are found here, these are:
The one 2s orbitalThe three 2p orbitals.The position of elements in the periodic table is largely based on the shared electrons of atoms which are being technically distributed at various level.
An element is a substance which cannot be split into different forms by ordinary means. Electrons revolve around the orbits of atoms of elements.
So therefore, from the given explanation above, it can be deduced that the the second energy level has four different orbitals.
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Nitrogen is collect over water at 40 Celsius . The partial pressure due to water vapor is 7.38 kPA at 40 Celsius , what is the partial pressure of nitrogen if the total pressure is 99.42 kPa?
There is a partial pressure for each gas in a mixture of gases, which is the pressure that would exist if that gas alone filled the whole volume of the initial combination at the same temperature.
One of two methods can be used to compute partial pressures:
Use PV = nRT to calculate the individual pressure of each gas in a mixture.
Utilizing the mole fraction of each gas, determine the proportion of pressure from the total pressure that may be ascribed to each individual gas.
When attempting to predict gas movement, partial pressure must be taken into account. Recall that the pressure of gases usually equalizes across nearby locations. From one area with a greater partial pressure to another with a lower partial pressure, a gas will move.
By dividing the mole fraction by the total pressure of a gas, one can calculate its partial pressure. Since it is based solely on the quantity of particles present rather than the nature of the gas, the Ideal Gas Equation remains true for mixes of gases just as it does for pure gases.
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What volume of 0.130 M HClO4 solution is needed to neutralize 44.00 mL of 8.50×10−2 M NaOH ?
It wants the answer in mL.
The volume of 0.130M HClO₄ required to react with 44ml of 8.5 x 10⁻²M NaOH to neutralize it is 28.76ml.
Let us first write the reaction of HClO₄ and NaOH,
HClO₄ + NaOH → NaClO₄ + H₂O
According to the reaction,
one moles of HClO₄ reacts with one mole of NaOH completely to form NaClO₄ and H₂O.
As we know,
Molarity = number of moles of solute/volume of solution
Moles = Molarity x Volume
So, we can write,
Moles of HClO₄ = Moles of NaOH
V x 0.130 = 44 x 8.5 x 10⁻²
Here,
V is the volume of HClO₄ (in ml),
V = 44 x 8.5 x 10⁻²/0.130
V = 28.76ml
Amount of HClO₄ required is 28.76ml.
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a gas is contained in a thick walled ballon when the pressure changes from 417mm HG 576mm HG the volume changes from to 4.78L and the temputure changes from 4.78 and the tempurture 497 50 386
The volume of the gas will be 8.501 L
What is combined gas law?
The combined gas law combines the three gas laws: Boyle's Law, Charles' Law, and Gay-Lussac's Law. It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.
i.e.
P1V1/T1 = PV2/T2
Where P1 = Initial pressure
V1 = Initial volume
T1 = initial temperature
P2 = Final pressure
V2 = Final volume
T2 = Final temperature
In the question, we know
P1V1/T1 = PV2/T2
417 × V1 = 576 × 4.78
497 386
417 × 386 × V1 = 576 × 4.78 × 497
V1 = 576 × 4.78 × 497
417 × 386
V1 = 8.501 L
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The complete question is :
When the pressure changes from 417 mm Hg to 576 mm Hg, the volume changes from _______L to 4.78 L and the temperature changes from 497 K to 386 K.
Calculate the number of molecules of sugar present in 1 mL of 10% sugar solution having a density of 1.2 g
Molar mass - Number of Sugar molecules in 1mL of 10% sugar solution is 2.11 × 10²⁰
What is molar mass ?
Mass per mole is a definition of molar mass. In other terms, molar mass is the total mass of all the atoms in a substance that makes up a mole. It is measured in gram-per-mole units.
For elements or molecules, molar mass is displayed. The molar mass is simply the element's mass represented in atomic mass units in the case of single elements or individual atoms. To put it another way, an atom's atomic mass and molar mass are exactly equal. Molar mass can be used to determine a particle's identification because it is equivalent to atomic mass for individual atoms.
Molar mass of sugar (C₁₂H₂₂O₁₁) = (12×12 + 1×22 + 16×11) g mol⁻¹ = 342 g mol⁻¹
Mass of 1 ml of the solution = (1 ml) × (1.20 g ml⁻¹) = 1.20 g
Mass of sugar in 1 ml of the solution = (1.20 g) × 10% = 0.120 g
Moles of sugar in 1 ml of the solution = (0.120 g) / (342 g mol⁻¹) = 3.509 × 10⁻⁴ mol
Avogadro constant = 6.02 × 10²³ mol⁻¹
No. of sugar molecules = (3.509 × 10⁻⁴ mol) × (6.02 × 10²³ mol⁻¹) = 2.11 × 10²⁰
No. of Sugar molecules in 1mL of 10% sugar solution is 2.11 × 10²⁰
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3. The element with electronic configuration 2.8.6 *
To know the element with eletronic configuration 2.8.6 we need to:
First:
do the eletronic distribution - 1s² 2s² 2p⁶ 3s² 3p⁶
someone pls tell me what this is
Answer:
Rights
Explanation:
Every human has their rights such as those stated. These rights are what is protected by law.
If 6.95 mol of ethane (C2H6) undergo combustion according to the unbalanced equation C2H6 + O2 ——- CO2 + H2OHow many moles of O2 is required? Answer in units of mol.
Answer
24.325 mol
Explanation
The unbalanced equation is:
C₂H₆ + O₂ → CO₂ + H₂O
The balanced equation will be:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Given mole of ethane = 6.95 mol
From the balanced equation:
2 mol of C₂H₆ is required by 7 mol of O₂
Therefore, 6.95 mol of C₂H₆wills requir:
[tex]\frac{6.95\text{ mol }C_2H_6\times7\text{ mol }O_{2}}{2\text{ mol }C_2H_6}=24.325\text{ mol of }O_{2}[/tex]Hence, 24.325 mol of O2 is required.
Among the following travelling objects, which has the shortest de Broglie
wavelength?
Hint. It is not necessary to calculate the wavelength for each object. The quickest
way to answer this question is to consider how the de Broglie wavelength depends
on the momentum (mass x speed).
ma
O
A Boeing 777 airplane (mass 2.5×105 kg) flying at a speed of 250 m/s (560 mph)
A bird of mass 2x10-2 kg flying at a speed of 10 m/s
A car of mass 2x10³ kg driving at a speed of 50 m/s
HADEMA kelaparas pasikei
E OS
KAMA MŪ
A person of mass 80 kg running at a speed of 3 m/s
A Neon atom (mass 3.4×10-26
danaume
para
kg) traveling at a speed of 3×10³ m/s
Among the following travelling objects, which has the shortest de Broglie wavelength, Neon atom (mass 3.4×10-26 kg) traveling at a speed of 3×10³ m/s.
What is de Broglie wavelength?
The de Broglie wavelength is an important term to understand when studying quantum mechanics. The de Broglie wavelength () is the wavelength () associated with an item in relation to its momentum and mass. The de Broglie wavelength of a particle is usually inversely related to its force.Matter is thought to have a wave-particle dual nature. De Broglie waves, named after the discoverer Louis de Broglie, are the characteristics of a material item that fluctuates in time or space while acting like waves. It is sometimes referred to as matter-waves. It is very similar to the dual nature of light, which has been empirically demonstrated to act as both a particle and a wave.
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Perform the following operation
and express the answer in
scientific notation.
5.0×10−5 +2.0×10-4
[ ? ]×10
The answer in scientific notation for the following operation is 2.5 × 10⁻⁴
What is scientific notation?
It is a way of writing very large or very small numbers. A number is written in scientific notation when number between 1 and 10 is multiplied by power of 10.
To determine the power or exponent of 10,
we must follow the rule listed below:
The base should be always a 10The exponent must be non-zero integer that means it can be either a positive or negative Coefficients can be positive or negative numbers including whole and a decimal numbers5.0×10⁻⁵ + 2.0×10⁻⁴
= 5×10⁻⁵ + 2×10⁻⁴
= [tex]\frac{5}{10^{5} } + \frac{2}{10^{4} }[/tex]
= [tex]\frac{5}{100000} + \frac{2}{10000}[/tex]
= 0.00005 + 0.0002
= 0.00025
= [tex]\frac{2.5}{10000}[/tex]
= [tex]\frac{2.5}{10^{4} }[/tex]
= 2.5 × 10⁻⁴
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A piece of barium has a volume of
4.00 cm3. The density of barium
is 3.62 g/cm3. What is the mass
of the sample of barium?
mass = [?] g
Record your answer to the hundredths place.
Mass (g)
Based on the volume and density of the barium sample, the mass
of the sample of barium mass 14.48 g.
What are the relationship between mass, volume, and density?The mass of a substance is the quantity of matter present in a substance.
The unit of mass is kg.
The volume of a substance is the amount of space covered by the substance. The unit for volume is a liter, cubic meter, or cubic centimeter.
The density of a substance is the ratio of the mass and volume of that substance.
Density = mass / volumeThe mass of the barium sample is calculated as follows:
The volume of the sample of barium = 4.00 cm³
The density of barium is 3.62 g/cm³
The mass of a substance = density * volumemass of the barium sample = 4.00 cm³ * 3.62 g/cm³
Mass of the barium sample = 14.48 g
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The equilibrium constant for the reaction 2 HF (g) ⇌ H₂ (g) + F₂ (g) is 0.270 at a particular temperature. What is the equilibrium constant for the equation ½ H₂ (g) + ½ F₂ (g) ⇌ HF (g)?
If the equilibrium constant for the reaction 2 HF (g) ⇄ H₂ (g) + F₂ (g) is 0.270 than equilibrium constant for the equation ¹/₂ H₂ (g) + ¹/₂ F₂ (g) ⇄ HF (g) is 1.924.
Initial equation is 2 HF (g) ⇄ H₂ (g) + F₂ (g)
Final equation is ¹/₂ H₂ (g) + ¹/₂ F₂ (g) ⇄ HF (g)
On reversing the equation of reaction, the equilibrium constant of the reversed reaction is inverse of the equilibrium constant of the forward reaction.
For reaction H₂ (g) + F₂ (g) ⇄ 2HF (g), equilibrium constant will be inverse of 0.270. Let the equilibrium constant of reaction H₂ (g) + F₂ (g) ⇄ 2HF (g) be K₁. Then, the Value of K₁ is given as
K₁ = 1 ÷ 0.270 = 3.7037
On changing the stoichiometric coefficient by a factor let's say x, then the equilibrium coefficient of the changed reaction is the equilibrium constant of the unchanged reaction raised to the power x.
According to the question, the value of x is ¹/₂. So, the equilibrium constant of reaction ¹/₂ H₂ (g) + ¹/₂ F₂ ⇄ HF (g), will root of K₁. Let the equilibrium constant of the reaction ¹/₂ H₂ (g) + ¹/₂ F₂ ⇄ HF (g) be K₂. Then, the value of K₂ can be given as
K₂ = √K₁
K₂ = √3.7037
K₂ = 1.924
Hence the value of the equilibrium constant for the final reaction ¹/₂ H₂ (g) + ¹/₂ F₂ ⇄ HF (g) is 1.924
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1.)What do you call a way of acquiring knowledge through experiment?
a.Academic method C.Scientific method
b.Experimental method d.Scietific notation
2.)What is the first method you must do in order to make a research theory?
a.Share the results c.Observe and question
b.Analyze and conclude d.Formulate a hypothesis
3.)Which of the following is the MOST important trait in the first step of scientific method,observe and question?
a.Senses C.Teamwork
b.Mathematical Formula d.Scientific Values
4.)What is the last step you must do in order to make a research theory?
a.Share the results c.Observe and question
b.Analyze and conclude d.Formula and a hypothesis
5.)Which of the following traits must you AVOID in making and analyzing a conclusion?
a.Be objective c.Be biased
b.Be sensible d.Include scientific values
Answer: B,C,not sure,A,C
Explanation:
When the equation, ___O2 + ___C 6H 14 →→ ___CO2 + ___H2O is balanced, the coefficient of O2 is:
Answer:
Explanations:
For a chemical reaction to be balanced, the total number of moles of elements at the reactant must be equal to the number of moles at the product.
Given the chemical reaction;
[tex]aO_2+bC_6H_{14}\rightarrow cCO_2+dH_2O[/tex]Equating the number of moles of elements on both sides:
For the oxygen element:
2a = 2c + d ................... 1
For the carbon element;
6b=c
For the Hydrogen element:
14b = 2d
7b = d .............................. 3
Assume a = 2;
Equation 1 becomes:
2(2) = 2c + d
4 = 2c + d ................,....4
From equation 2
b = c/6 .............................. 5
From equation 3:
b = d/7 ...................... 6
Equating 5 and 6
c/6 = d/7
7c = 6d
c = 6d/7 ........................... 7
Substitute equation 7 into 4 to have:
4 = 2c + d
4 = 2(6d/7) + d
4 = 12d/7 + d
4 = (12d+7d)/7
28 = 19d
d = 28/19
To get the value of b:
b = d/7
b = 28/19 * 1/7
b = 28/133
Which statement best describes the mass numbers of the atoms in the reaction?
OThere is one atom with a mass number of 1
O There are two atoms with mass numbers of 2.
OThere is one atom with a mass number of 2.
O There are two atoms with mass numbers of 1.
There are two atoms with mass numbers of 2 best describes the mass numbers of the atoms in the reaction
What is a Mass number ?The sum of protons and neutrons in an atomic nucleus is known as the mass number, often known as the atomic mass number or nucleon number. It roughly equates to the atom's atomic mass given in atomic mass units.
They are collectively referred to as nucleons since protons and neutrons are both present in the atomic nucleus. An atom of carbon, for instance, has 6 protons and 6 neutrons. Its mass number is therefore 12. All atoms of an element have the same number of protons, but their neutron counts can differ.Learn more about Mass number here:
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Perform the following operationand express the answer inscientific notation.9.2x107 = 3.7x109[][ ? ]x10?)Coefficient (green)Exponent (yellow)Enter
ANSWER
Coefficient = 2.49
Exponent = -2
STEP-BY-STEP EXPLANATION:
From the question provided, you are asked to simplified the below expression
[tex]9.2\cdot10^{7\text{ }}\div3.7\cdot10^9^{}[/tex]The expression can be re-arrange below as
[tex]\frac{9.2\cdot10^7}{3.7\cdot10^9}[/tex][tex]\begin{gathered} \text{ According to the 2nd law of indicies, recall that, } \\ x^a\text{ }\div x^b=x^{a\text{ - b}} \end{gathered}[/tex][tex]\begin{gathered} =\frac{9.2}{3.7}\cdot10^{7\text{ - 9}}^{} \\ =2.49\cdot10^{-2} \end{gathered}[/tex]Therefore, the coefficient is 2.49 and the Exponent is -2
H₂Se
# of Valence e" =
Lewis Structure:
Draw the Molecular Geometry
(using dashes and wedges):
Se
of e Groups =
Hybridization =
Electronic Geometry:
Molecular Geometry:
Polar or Nonpolar?
the correct answer is electrons
What is the molecular geometry of CF4
The molecular geometry of CF4 is tetrahedral because it has all fluorine atoms in the surrounding.
Over time, a crusty deposit of calcium carbonate forms on the heating element inside a kettle.
Use your understanding of acids and bases to suggest a way to remove the deposit
Calcium carbonate deposits in heating elements can be eliminated by way of cleansing these with an acid (like vinegar or lemon juice). This acid will react with the calcium carbonate to provide salt, water, and carbon dioxide gas.
Calcium carbonate is a nutritional supplement used whilst the amount of calcium taken in the weight loss plan is not enough. Calcium is needed via the frame for healthful bones, muscle groups, anxious devices, and the heart. Calcium carbonate also is used as an antacid to relieve heartburn, acid indigestion, and a disillusioned stomach.
Calcium carbonate is the salt of a sturdy base (due to the presence of the calcium ion) and a vulnerable acid (because of the presence of the carbonate ion, generally derived from carbonic acid). consequently, this salt is mildly basic in nature.
Calcium carbonate reacts with water that is saturated with carbon dioxide to shape the soluble calcium bicarbonate. This response is essential in the erosion of carbonate rock, forming caverns, and results in difficult water in lots of regions.
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A sample of neon gas occuples a volume of 7.5L at 35 °C. If the temperature is increased to 45°C, what is the new volume? K=273+•C
Assuming the pressure remains same, we can use Charles' Law here
i.e.
[tex]\frac{V1}{T1}=\text{ }\frac{V2}{T2}[/tex]Here, V1 = 7.5 l, T2 = 35 +273= 308 K
T2= 45+273 = 318 K, we need to find V2
[tex]\frac{7.5}{308}=\text{ }\frac{V2}{318}[/tex][tex]So,\text{ V2 = 7.74 L}[/tex]
A new element (E) has been discovered to have two naturally occurring isotopes, E216 and E
219. If the average isotopic mass of E is 217.00 grams/mol, what is the percent abundance of each isotope?
I need help please?
Let the percent abundance of E216 be x. Then, the percent abundance of E219 is 100-x. It follows that:
[tex]216x+219(100-x)=2170.00\\\\216x+21900-219x=21700.00\\\\-3x+21900=21700.00\\\\-3x=-200\\\\x=\frac{200}{3} \approx 66.6\%[/tex]
So, the percent abundance of E216 is 66.6%, and the percent abundance of E219 is 33.3%.
Isotopes exists atoms that stood part of the exact element and have the same atomic number Z but a different mass number A. The percent abundance of E216 exists 66.6 %, and the percent abundance of E219 exists 33.3 %
What is meant by isotope?Isotopes are two or more different atom types that share the same atomic number and place in the periodic table but contain various quantities of neutrons in their nuclei, resulting in various nucleon numbers.
A chemical element's isotope is any of two or more species of atoms that share the same atomic number, position in the periodic table, and virtually identical chemical behavior, but differ in atomic mass and physical characteristics. There are one or more isotopes for each chemical element.
Isotopes are atoms that are part of the same element and have the same atomic number Z but a different mass number A. For instance, three isotopes of the element carbon, with respective masses of 12, 13, and 14, are carbon-12, carbon-13, and carbon-14.
Let the percent abundance of E216 be x. Then, the percent abundance of E219 is 100-x. It follows that:
216x + 219 (100 - x) = 2170.00
simplifying the above equation, we get
216x + 21900 - 219x = 21700.00
-3x + 21900 = 21700.00
-3x = -200
x = 200/3 ≈ 66.6 %
Therefore, the percent abundance of E216 exists 66.6 %, and the percent abundance of E219 exists 33.3 %.
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