General kinematics problem.
"Anna is returning from vacation driving down the Sunshine Highway. She travels for a stretch (SA) at a speed of 110 km/h. Then, due to an increase in traffic, Anna is forced to reduce her speed by travelling the second part of the journey (SB) at 60 km/h. The total distance and duration of the trip are 350 km and 4.0 hours respectively.
-> Calculate the time intervals needed to travel SA and SB
-> Calculate the distances covered in the two sections SA and SB".
The results I should get by doing the exercise are in the attached picture.
If you could explain the various steps in the problem you would be doing me a huge favor. Thanks!
Answers
Explanation:
What we know:
Sa + Sb = 350 km
Ta + Tb = 4h
S = Vt
With these equations above we can write a system of equations and find Tb, as you see in the picture(s).
After having Tb you can easily find Ta and then Sa and Sb. Hopefully it was clear.
Related Questions
A 0.15 kg baseball moving at 20 m/s is stopped by a player in 0.010 s. What is the average force of the ball?
Answers
Answer: 300N
Explanation:
Impulse= Mass * Velocity
F.T = M * V
F= MV/T
F= (0.15*20)/ 0.01
F= 300N
nitrogen dioxide is a major component of smog which type of chemical reaction creates this product?
a. synthesis reaction
b. replacement reactions
c. combustion reactions
d. decomposition reaction
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Answer:
A.synrhesis reaction
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How do you un rewrap something?
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the breaks on a 15,680 N car exert a stopping force of 640 N.
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a convex lens has a focal length of 0.5 it is combined with a second lens so combination has power 2.5 diopter which of the following could be second lens
A) concave lens focal length 2m
B) convex lens focal length 0.5m
C) concave lens 0.5m
D) convex lens 2m
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Answer:
concave lens focal length 2m
Two forces that act on very small distances (smaller than you can see ) are
Answers
Forces are needed to make a car do which of these?
slow down
speed up
stay on the ground
all of the above
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if your car is on a steep hill it needs force to stop moving and to speed up
The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)
Answers
We are given –
Mass of earth,m = 5.98×10²⁴ kgMass of sun, M= 1.99×10³⁰ kgDistance between Earth andSun, r= 1.5×10¹¹ m
G = 6.67×10⁻¹¹ Nm²/kg²We are asked to find the gravitational attraction between the sun and the earth.
By Universal Law of Gravitation, we know that –[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\sf F = \dfrac{GMm}{r²}}[/tex]
Substituting values, we get –
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}\times 5.98×10^{24}\times 1.99×10^{30}}{(1.5×10^{11})^2}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}×5.98×10^{24}×1.99×10^{30}}{2.25×10^{22}}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = 35.27×10^{21}[/tex]
[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf F = 3.53×10^{22} N}[/tex]
Henceforth ,gravitational attraction between the sun and the earth. is 3.53×10²²N .______________________________________________
Classify the statement below as either Speed or Velocity?
A jeep was driving 40 mph
heading to the grocery store.
Answers
Answer:
Hello There!
It is Speed.
[tex]\Large\bold\red{Reason}[/tex]
Because in the question it is said that at which speed car is travelling.
Speed is a scalar quantity.
If it is velocity then first know this that it is a vector quantity.
It must include both magnitude and direction.
If it is velocity then it would be 40 mph east or west or north or south.
I hope it is helpful to you...Cheers!_____________PLEASE HELP I WILL MARK BRAINLIST!!
The diagram shows a swinging pendulum. Which best explains what happens to the motion of the pendulum due to the law of conservation of energy?
The pendulum will slow down and eventually stop moving as the mechanical energy transforms to thermal energy.
The pendulum will slow down and eventually stop moving as the mechanical energy disappears.
The pendulum will continue moving at the same speed because mechanical energy is created as the pendulum moves.
The pendulum will slow down but will not stop moving because some of the mechanical energy is destroyed.
Answers
The mechanical energy transforms to thermal energy as the pendulum slows and eventually stops moving.
Hope this helps!
Brainliest is much appreciated!
The pendulum bob slow down and eventually stop as it loses it energy due to friction or air resistance. All its kinetic energy has been transformed to potential energy. None of the options is correct
OSCILLATORY MOTIONThe to and fro movement of an object or particle is known as oscillatory motion. Such motion repeats itself. Examples are;
Pendulum boba diving boardthe strings of a plucked guitarthe prongs of a tuning fork struck with a hard objectthe vertical movement of a disturbed mass on a spiral spring.The given diagram shows a swinging pendulum. And the option which best explains what happens to the motion of the pendulum due to the law of conservation of energy is
The pendulum will slow down and eventually stop moving when it loses energy because of friction or air resistance as the kinetic energy transforms to potential energy
The mechanical energy involve are potential and kinetic energy. Both energies reduce as they gradually lost some of their energies due to air friction between the bob and the air. Some of the lost energies may be transformed to thermal energy.
The pendulum bob slow down and eventually stop because it loses its mechanical energy due to air resistance or friction.
Therefore, the option A which state that "The pendulum will slow down and eventually stop moving as the mechanical energy transforms to thermal energy" can be considered. But none of the option best explain what happens to the motion of the pendulum.
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Given that 1 pound is equal to 4.45 newton’s what is the weight of a 500N child in pounds?
Answers
Answer:
112.36 pounds
Explanation:
Since 1 pound = 4.45 Newtons, a 500N child in pounds = 500÷4.45 = 112.36 pounds (approximately).
Connor rode an inner tube down a river. For 4.6 minutes, he moved downriver at 15 meters per minute. During this time, how far did he move?
answers:
3.26 meters
3.26 minutes
69 meters
69 minutes
Answers
Answer:
69 meters
Explanation:
The definition of energy is the ability to ___________.
(Hint: one word)
Answers
[URGENT] A swimmer wants to end up at a dock due north of her starting position on the south shore of a river. In still water her maximum speed is 1.25m/s. The river has a current flowing 0.35m/s [E].
a.) calculate the direction that she must aim herself through the water to arrive at the dock.
b.) how long will it take for the swimmer to cross the river, if the distance from the starting point to the dock is 300 m?
Please show all your work, thanks
Answers
Explanation:
As you can see in the picture, we want the swimmer to go on a straight line, so the speed of the water must be equal to the speed of the swimmer along the x-axis. We also know the value of v, so we can calculate the of the cosine of the angle (alpha) between Vx and V. Thanks to the fundamental relation of gioniometry (cos^2(x) + sin^2(x) = 1) we can find the sine of alpha and calculate Vy. With Vy we can calculate the time that the swimmer will use for reaching the dock: s = Vy * t => t = s/(Vy).
I'll let you do all the calculations, you just have to plug in values.
a)The direction that she must aim herself through the water to arrive at the dock will be 73.7°.
b)The time it takes for the swimmer to cross the river will be 240 seconds.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.
Given data;
The maximum speed of the swimmer In still water,v=1.25m/s.
Speed of river = 0.35m/s [E]
α is the direction that she must aim herself through the water to arrive at the dock.
t is the time it takes for the swimmer to cross the river
The distance from the starting point to the dock is,s = 300 m
If the swimmer were to swim straight, the water's speed along the x-axis would have to match that of the swimmer.
[tex]\rm v_w = v_x = 0.35 \ m/sec[/tex]
α is the angle between vx and v
The value of the
[tex]\rm cos \alpha = \frac{v_x}{v} \\\\ \alpha = cos ^{-1}(\frac{0.35}{1.25} )\\\\ \alpha = 73.7 ^0[/tex]
The time that the swimmer will use for reaching the dock;
s = V×t
t = s/(v)
t=300 m / 1.25 m/sec
t = 240 seconds
Hence, the direction that she must aim herself through the water to arrive at the dock. and it takes for the swimmer to cross the river will be 73.7° and 240 seconds respectively.
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18 through 22 multiple choice please help
Answers
Answer:
18:equilibrium
19:10.8
20:separating the surfaces with a layer of air
21:it remains motionless
22:cm/s
Please please help
Matter is made up of particles which
are too small to see without the aid of
a microscope. What do scientists call
these particles?
A.bonds
B.mixtures
C.energy
D.atoms
Answers
Answer:
D
Explanation:
an airplane flies with a constant speed of 620 miles per hour. how far can it travel in 3 1/2 hours?
Answers
Answer:
hi there !
1 hour -------> 620 miles
3 1/2 ---------> ?
the number of miles the airplane travels in 3 1/2 hours
= 3 1/2 × 620 = "2170" miles
Block A has a mass of 2kg and a speed of 50 m/s along the positive x axis.
Block B has a mass of 4 kg and a speed of 25 m/s along the negative x axis.
The two blocks collide head-on in a perfectly elastic collision.
Determine the velocity of each mass after the collision.
Answers
Momentum is conserved, so
(2 kg) (50 m/s) + (4 kg) (-25 m/s) = (2 kg) v₁' + (4 kg) v₂'
where v₁' and v₂' are the velocities of the two blocks after the collision. Simplifying this gives
100 kg•m/s - 100 kg•m/s = (2 kg) v₁' + (4 kg) v₂'
0 = (2 kg) v₁' + (4 kg) v₂'
v₁' = -2v₂'
Energy is also conserved, so
1/2 (2 kg) (50 m/s)² + 1/2 (4 kg) (-25 m/s)² = 1/2 (2 kg) (v₁')² + 1/2 (4 kg) (v₂')²
Simplifying yields
2500 J + 1250 J = (1 kg) (v₁')² + (2 kg) (v₂')²
3750 J = (1 kg) (v₁')² + (2 kg) (v₂')²
Substitute v₁' = -2v₂' and solve for v₂' :
3750 J = (1 kg) (-2v₂')² + (2 kg) (v₂')²
3750 J = (6 kg) (v₂')²
(v₂')² = 625 J/kg = 625 m²/s²
v₂' = 25 m/s
Then the first block has final velocity
v₁' = -2 (25 m/s)
v₁' = -50 m/s
Objects 1 and 2 attract each other with a gravitational force
of 18.0 units. If the mass of Object 1 is doubled mass of object 2 is tripled AND the
distance separating Objects 1 and 2 is halved, then the gravitational force will be
new gravitational force will be
units.
Answers
The new gravitational force of the two objects will be 432 N.
The given parameters:
Force between object 1 and object 2, F = 18 NLet the mass of object 1 = m1Let the mass of object 2 = m2Let the distance between the two object = rThe gravitational force between the two objects is calculated by applying Newton's law of universal gravitation;
[tex]F = \frac{Gm_1m_2}{r^2} \\\\G = \frac{Fr^2}{m_1m_2}\\\\G = \frac{Gm_1m_2}{r^2} \\\\G = \frac{18r^2}{m_1m_2}[/tex]
when the mass of the object 1 = 2m1mass of the object 2 = 3m2distance between the two object = ¹/₂r[tex]\frac{18r^2}{m_1 m_2 } = \frac{F_2(\frac{1}{2}r)^2 }{2m_1 \times 3m_2} \\\\\frac{18r^2}{m_1 m_2 } = \frac{F_2 \times r^2}{4 \times 2m_1 \times 3m_2} \\\\\frac{18r^2\times 4 \times 2m_1 \times 3m_2}{m_1 m_2\times r^2 } = F_2\\\\432 \ N = F_2[/tex]
Thus, the new gravitational force of the two objects will be 432 N.
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What are the rest of the blanks?
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Which statement accurately describes how the acceleration of an object in free fall changes?
O A. It accelerates downward at a constant rate.
O
B. It accelerates downward at an increasing rate.
C. It accelerates downward at an irregular rate.
D. It accelerates downward at a decreasing rate.
Answers
Answer: A
Explanation: An object in free fall only is affected by gravity, so the acceleration is 9.8 m/s²
A 100 g mass of tungsten at 100.0°C is placed in 200 g of water at 20.0°C. The
mixture reaches equilibrium at 21.6°C. Calculate the specific heat of tungsten
Answers
If you,
q= 100g x 4.186 j/g*degrees C * (21.6 degrees C- 20.0 degrees C) which equals to 1.6.
So q= 100g * 4.186 j/g*deg C * 1.6
The specific heat capacity of tungsten given the data from the question is 0.17 J/gºC
Data obtained from the questionMass of tungsten (M) = 100 g
Temperature of tungsten (T) = 100 °C
Mass of water (Mᵥᵥ) = 200 g
Temperature warm water (Tᵥᵥ) = 20 °C
Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
Equilibrium temperature (Tₑ) = 21.6 °C
Specific heat capacity of tungsten (C) = ?
How to determine the specific heat capacity of tungstenHeat loss = Heat gain
MC(T – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
100 × C × (100 – 21.6) = 200 × 4.184(21.6 – 20)
100 × C × 78.4 = 1338.88
Divide both sides by 100 × 78.4
C = 1338.88 / (100 × 78.4 )
C = 0.17 J/gºC
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How to do this question plz
Answers
Answer:
Let L be the length of the wire.
N λ = M L where N is the number of wavelengths λ. Also, M and are integers and L is the length of the wire
There must be nodes at the ends of the wire and anti-nodes at the points of zero displacement - λ/2, λ, 3λ/ 2, etc.
The simplest would be 2 λ = L or L = λ / 2
In such a situation one would have
N-A-N or node-antinode-node
There is a 180 degree phase change upon reflection of the wave creating the standing wave
The distance between nodes or anti-nodes must be λ/2 and there must be nodes at the ends of the wire
Your mother asks you to carry a load of wood to the fireplace and lower it to the hearth. In doing this you have used your arms as levers. Which statement describes this as a class three lever?
Question 13 options:
The wood in your hands was the fulcrum, the load your elbow, and the effort (input force) was supplied by your arm muscles.
The wood was the load in your hands, the fulcrum was your elbow and the effort (input force was supplied by your arm muscles.
The fulcrum was the muscles in your arms, the load was the wood in your hands and the effort (input force) was the elbow.
Answers
Answer: The correct answer is the weight of the wood.
Explanation:
Hope this helps
A 3.1 kg carton's GPE was increasing by 7.8 J as it was lifted above the ground. How high was it lifted?
Answers
Answer:it was lifted
Explanation:
by me lifting it because i can life it very high
you push on a 24.5kg bag of sand and give it an acceleration of 2.30 m/s ^s. what is the magnitude of the force the bag returns …
Answers
Answer:
Below in bold.
Explanation:
Newton's Second Law:
Force = mass * acceleration
So
Force = 24.5 * 2.3
= 56.35 Newtons.
What force is responsible for how magma flows and rocks stack up on top of one another?
Question 6 options:
Electroweak and Strong
Nuclear
Electromagnetic
Gravitational
Answers
Gravitational force is responsible for how magma flows and rocks stack up on top of one another.
Gravitational force is the force hat attracts all objects to the center of the earth. The force of gravity accounts for the fact that when an object is thrown up, it falls back to the earth.The force that is responsible for how magma flows and rocks stack up on top of one another is the gravitational force.Hence, it is the gravitational force that is responsible for how magma flows and rocks stack up on top of one another.
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A roller coaster
produces acceleration due
to changes in both speed
and direction. Applying
Concepts Describe the
acceleration occuring at this
instant on the
rollercoaster ride.
Answers
Answer:
the answer is the rollar coster
Explanation:
because the rollar coster is
why we use light-years in space verses other units of distance?
Answers
Answer:
The light year is used to measure distances in space because the distances are so big that a large unit of distance is required.
When dribbling a ball, the ______________ should control the direction and downward motion of the ball.
Answers
Answer:
gravity
Explanation:
keeps the ball down on the surface
When dribbling a ball, the gravity should control the direction and downward motion of the ball.
What is projectile motion?When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's centre (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.
Two distinct rectilinear motions occur simultaneously in a projectile motion:
Uniform velocity along the x-axis is what causes the particle to move horizontally (ahead).Uniform acceleration along the y-axis is what causes the particle to move vertically (downwards).When a ball is sent into the air at a certain speed, the only force acting on it is the acceleration caused by gravity (g).
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