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Mark has 1.5 times more collectible cards than Jacob. If Mark
gives Jacob 11 cards, they will have the same number of
collectible cards. How many cards do they have?

Answer:

does not have a solution because √-0.75 ≠ R

Step-by-step explanation:

x^2 - 5x + (5/2)^2 = -7

x^2 - 5x + 6.25 = -7 + 6.25

(x - 2.5)^2 = -0.75

(x - 2.5) = √-0.75

does not have a solution because √-0.75 ≠ R

Answer:

x = (1/2)(5 ± i√3)

Step-by-step explanation:

x² - 5x + 7 = 0

subtract 7 from both sides

x² - 5x = -7

Use half the x coefficent, -5/2, as the complete the square term

(x - 5/2)² = -7 + (-5/2)²

(x - 5/2)² = -7 + 25/4

(x - 5/2)² = -3/4

Take the square root of both sides

x - 5/2 = ±(√-3) / 2

x - 5/2 = ±(i√3) / 2

Add 5/2 to both sides

x = 5/2 ± (i√3) / 2

factor out 1/2

x = (1/2)(5 ± i√3)

Answer:

Assuming normal distribution, the mean number of calls for a n-hour day is of [tex]m = n\mu[/tex], in which [tex]\mu[/tex] is the mean number of calls per hour, and the standard deviation is [tex]s = \sqrt{n}\sigma[/tex], in which [tex]\sigma[/tex] is the standard deviation of the number of calls per hour.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

N-instances of a normal variable:

For n-instances of normal variable, the mean of the distribution is: [tex]m = n\mu[/tex], and the standard deviation is [tex]s = \sqrt{n}\sigma[/tex]

What is the mean and standard deviation of the number of calls it receives for ​n-hour ​day?

Assuming normal distribution, the mean number of calls for a n-hour day is of [tex]m = n\mu[/tex], in which [tex]\mu[/tex] is the mean number of calls per hour, and the standard deviation is [tex]s = \sqrt{n}\sigma[/tex], in which [tex]\sigma[/tex] is the standard deviation of the number of calls per hour.

Answer:

2

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\frac{-2}{3}*\frac{3}{5}+\frac{5}{2}-\frac{3}{5}*\frac{1}{6}=\frac{-2}{5}+\frac{5}{2}-\frac{1}{5*2}\\\\= \frac{-2}{5}+\frac{5}{2}-\frac{1}{10}\\\\=\frac{-2*2}{5*2}+\frac{5*5}{2*5}-\frac{1}{10}\\\\=\frac{-4}{10}+\frac{25}{10}-\frac{1}{10}\\\\=\frac{-4+25-1}{10}\\\\=\frac{20}{10}\\\\= 2[/tex]

Answer:

Approximately 46.29 feet

Step-by-step explanation:

Answer:

0.75 points per minute

Step-by-step explanation:

9/12 is 0.75

Answer:

18.28 m

Step-by-step explanation:

Given the flower garden in the question :

The shape is composite and can be divided into 2 semicirles and rectangle

The perimeter of a semicircle is the Circumference of the semicircle = πr

Hence, 2 semicirles = 2πr

Radius of semicircle = 2/2 = 1

Perimeter = 2 * 3.14 * 1² = 2 * 3.14 * 1 = 6.28 m

The perimeter of rectangle; length and width are 6m and 2 m respectively :

Perimeter of rectangle = 2(l + w) = 2(4+2) = 2(6) = 12m

Tve perimeter of garden = 6.28 + 12 = 18.28 m

Answer:

x< 4/7

Step-by-step explanation:

See image below:)

Answer:

The desired data-set is: {12,12,12,12,12,12,12}

Step-by-step explanation:

n = 7

Data set of 7 elements.

x = 12

Mean of 12

S = 0

Standard deviation of 0.

Desired data-set:

Since the desired standard deviation is 0, all the elements in the data-set will be the same. Since the mean is 12, all elements is 12. 7 elements.

The desired data-set is: {12,12,12,12,12,12,12}

Answer:

Step-by-step explanation:

a= 2qr^3 quotent 6p^2

Answer:

Terry has 1500 sweets.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the number of sweets Terry has.

y is the number of sweets Alex has.

If Terry gives 30% of his sweets to Alex,they will have the same number of sweets.

This means that:

[tex](1 - 0.3)x = y + 0.3x[/tex]

[tex]0.7x = y + 0.3x[/tex]

[tex]y = 0.4x[/tex]

If Terry gives 750 of his sweets to Alex,then Alex will have 80% more sweets than Terry.

This means that:

[tex]y + 750 = 1.8(x-750)[/tex]

We want to find x, and since [tex]y = 0.4x[/tex]

[tex]y + 750 = 1.8x - 1350[/tex]

[tex]0.4x + 750 = 1.8x - 1350[/tex]

[tex]1.4x = 2100[/tex]

[tex]x = \frac{2100}{1.4}[/tex]

[tex]x = 1500[/tex]

Terry has 1500 sweets.

Answer:

I'll setup the problem and you can compute the answer

Step-by-step explanation:

The formula for simple:

I = P*r*t

I = interest

P = loan amount

r = interest rate per period (period = days)

n = number of periods

P = 10,170

r = .0764/365

t = 272

Answer:

[tex]95 - \frac{3}{4} [/tex]

[tex] = \frac{95}{1} - \frac{3}{4} [/tex]

[tex] = \frac{380}{4} - \frac{3}{4} [/tex]

[tex] = \frac{380 - 3}{4} [/tex]

[tex] = \frac{377}{4} [/tex]

[tex] = 376\frac{1}{4} [/tex]

I assume you meant to say "a differentiable function f has the values ..." and not g.

Since f is differentiable, the mean value theorem holds, so you can approximate

f ' (2.5) ≈ (f (2.6) - f (2.4)) / (2.6 - 2.4) = (24 - 18) / (0.2) = 30

I.)

1.) 7N = 50

2.) 35 - 16 = N

3.) 2P + 8 = 24

4.) R/5 = 9

5.) 30 - 10 = 20

II.)

1.) Twinity increased by eight times N

2.) D decreased by eleven

3.) The quotient of X and nine is K

4.) Five times X

5.) Three times a decreased by 5 is thirteen

6.) Nothing

7N = 50

35 - 16 = N

2P + 8 = 24

R/5 = 9

30 - 10 = 20

Twenty increased by eight times N

D decreased by eleven

The quotient of X and nine is K

Five times X

Three times a decreased by 5 is thirteen

Answer:

Step-by-step explanation:

Hope this helps u!!

Answer:

The answer is below

Step-by-step explanation:

Similar triangle are triangles with the same shape, equal pair of corresponding angles. Also they have the same ratio of the corresponding sides.

From the diagram attached, we can see that triangle ABC and triangle CEF are similar triangles. Hence:

AB/BC = CF/EF

Given that BC = 1 km = 1000 m, CF = 2 m - 1.5 m = 0.5 m, EF = 2.5 m.

Hence:

AB/1000 = 0.5/2.5

AB = (0.5/2.5) * 1000 = 200 m

The height of the building = AB + height of Steve = 200 m + 2 m

The height of the building = 202 m

Answer:

[tex](4x - 3)(5x - 8) = 20x^2 -47x + 24[/tex]

Step-by-step explanation:

Given

[tex](4x - 3)(5x - 8)[/tex]

Required

Identify and correct error

The error is when the inner and outer terms are multiplied. i.e.

[tex]4x * -8 = -32x[/tex] not 32x

[tex]-3 * 5x = -15x[/tex] not 15x

So, the expression is:

[tex](4x - 3)(5x - 8) = 20x^2 - 32x -15x + 24[/tex]

[tex](4x - 3)(5x - 8) = 20x^2 -47x + 24[/tex]

Answer:

the answer is 3.

Step-by-step explanation:

Difference between means to subtract.

8 - 5 = 3

Answer:

8- a = 5

Step-by-step explanation:

Answer:

40 m

Step-by-step explanation:

158 · 2.54 = 401.32

401.32/100 = 40.132

40.132 ≈ 40

It was some mistake in previous one so i edited this one.

Answer:

d=23.43

Step-by-step explanation:

Given data

A(-6,8)

X1=-6

Y1=8

B(12, - 7)

X2=12

Y2=-7

The expression for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²

Substitute

d=√((12+6)²+(-7-8)²

d=√((18)²+(-15)²

d=√324+225

d=√549

d=23.43

I assume that the equation you mean is below:

[tex] \large \boxed{w + \frac{ {w}^{2} }{3} = 0}[/tex]

To find roots for this equation, we have to get rid of the denominator. We can do by multiplying both sides by 3.

[tex] \large{w(3) + \frac{ {w}^{2} }{3} (3) = 0(3)} \\ \large{3w + {w}^{2} = 0}[/tex]

Factor w-term out (common factor)

[tex] \large{w(3 + w) = 0} \\ \large{w = 0 \: \: \: or \: \: \: 3 + w = 0} \\ \large{w = 0, - 3}[/tex]

Answer

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines :  y = √x, y = 2, x = 0.

a) The x-axis

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) [tex]\int\limits^2_0 {ph} \, dy[/tex]

     = [tex]( 2\pi ) \int\limits^2_0 {y.y^2} \, dy[/tex]  

∴ Vol = 8π

b) The line y = 2  ( using the shell method )

p = 2 - y

h = y^2

vol = ( 2π ) [tex]\int\limits^2_0 {ph} \, dy[/tex]

     = [tex]( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy[/tex]

     = ( 2π ) * [ 2/3 * y^3  - y^4 / 4 ] ²₀

∴ Vol  = 8/3 π

c) The y-axis  ( using shell method )

h = 2-y  = h = 2 - √x

p = x

vol = [tex](2\pi ) \int\limits^4_0 {ph} \, dx[/tex]

     = [tex](2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx[/tex]

     = ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

d) The line x = -1    (using shell method )

p = 1 + x

h = 2√x

vol = [tex](2\pi ) \int\limits^4_0 {ph} \, dx[/tex]

Hence   vol = 176/15 π

attached below is the graphical representation of P and h

Answer:

5 hour and 25 mins

Step-by-step explanation: