Given Eo = -0.268 V for the PbCl2/Pb couple and -0.126 V for the Pb2+/Pb couple, determine Ksp for PbCl2 at 298 K.

Answers

Answer 1

The Ksp for PbCl₂ at 298 K is approximately [tex]1.12 \times 10^{(-5)}[/tex].

To determine the Ksp (solubility product constant) for PbCl₂ at 298 K, we can use the Nernst equation and the standard reduction potentials of the PbCl₂/Pb and Pb²⁺/Pb couples.

The balanced half-reactions for the two couples are as follows:

PbCl₂ + 2e⁻ → Pb + 2Cl⁻

Pb²⁺ + 2e⁻ → Pb

Given that the standard reduction potentials (Eo) for the PbCl₂/Pb and Pb²⁺/Pb couples are -0.268 V and -0.126 V, respectively, we can calculate the standard cell potential (E°cell) using the equation:

E°cell = E°reduction + E°oxidation

E°cell = -0.268 V + (-0.126 V)

E°cell = -0.394 V

Now, we can use the Nernst equation to relate the cell potential to the Ksp:

Ecell = E°cell - (RT / nF) ln(Q)

Since the reaction quotient (Q) for the precipitation of PbCl2 is equal to the concentration of Pb²⁺ and Cl⁻ ions, and assuming standard conditions (T = 298 K, n = 2, and F is the Faraday constant), we can simplify the equation to:

Ecell =E°cell - (0.0592 / 2)log10(Q)

Since the reaction is at equilibrium, the cell potential (Ecell) is zero. Therefore, we can rewrite the equation as:

0 = E°cell - (0.0592 / 2) log10(Ksp)

Solving for Ksp, we have:

[tex]Ksp = 10^{(\frac {E^{0}cell}{\frac {0.0592}{2}})}[/tex]

[tex]Ksp = 10^{(\frac {-0.394}{\frac {0.0592}{2}})}[/tex]

Calculating this expression gives us:

Ksp ≈ [tex]1.12 \times 10^{(-5)}[/tex]

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Related Questions

Which two elements on the periodic table share the same period and are both gases?

A. Hydrogen and Helium

B. Fluorine and Bromine

C. Lithium and Potassium

D. Xenon and Argon

Answers

A
Hydrogen and Helium are the only elements in the periodic table that share the same period and are based

The particles of a substance lose energy and change from
a disordered structure with large distances between the particles to
a loosely ordered state.
Which change of state is described?

Answers

Answer:

A Liquid

Explanation:

structure with large distance (gas) than goes to a loosely ordered state (liquid)

I hope this helps

If a radioactive isotope has a half-life of 400 million years, how long will it take for 50% of the material to change to the daughter product?

Answers

If a radioactive isotope has a half-life of 400 million years, it will take 400 million years for 50% of the material to change to the daughter product.

How long it takes for half of the radioactive atoms to decay is known as the half-life of the isotope. A radioactive isotope's half-life is the amount of time it takes for half of the parent material to decay to the daughter product. It's worth noting that a half-life isn't a fixed amount of time for each radioactive isotope.

The following formula can be used to calculate the amount of radioactive isotope remaining after a given period of time:

t=ln(N₀/N) / λ

Where:

t= time elapsedN₀= initial quantity of isotopeN= quantity of isotope after a given timeλ= decay constant

For this problem, we need to solve for the time (t) at which 50% of the radioactive isotope has decayed:

0.5N₀ = N₀ e^(-λt)

0.5 = e^(-λt)

t = ln(0.5) / (-λ)

We know that the half-life of this isotope is 400 million years, which means that λ is equal to:

ln(2) / (400,000,000 years)

λ = 0.00000000017 / year

Substituting that value into the formula:

t = ln(0.5) / (-0.00000000017 / year)

t ≈ 400,000,000 years

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Consider the vaporization of liquid water to steam at a pressure of 1 atm. In what temperature range is it a spontaneous process?

Answers

The vaporization of liquid water to steam is a spontaneous process when the temperature is above its boiling point at a pressure of 1 atm.

At 1 atm, the boiling point of water is 100 degrees Celsius or 212 degrees Fahrenheit. When the temperature of the water reaches or exceeds this value, the average kinetic energy of the water molecules increases, allowing more molecules to overcome the intermolecular forces and escape into the gas phase. At temperatures below the boiling point, water molecules have lower average kinetic energy, and the intermolecular forces between the water molecules are stronger. In this case, the rate of evaporation is slower, and the process is non-spontaneous. However, it is important to note that even at temperatures below the boiling point, water molecules with higher kinetic energy can still evaporate from the surface. Above the boiling point, the kinetic energy of the water molecules is sufficient to overcome the intermolecular forces completely, and the evaporation process becomes more rapid and spontaneous. The water molecules have enough energy to transition into the gas phase without requiring additional external energy input. It is crucial to maintain a temperature within the appropriate range to ensure a spontaneous vaporization process. If the temperature falls below the boiling point, the process may slow down or stop altogether. Conversely, if the temperature rises significantly above the boiling point, it may result in superheating, where the water remains in the liquid state despite being above the boiling point. This can be unstable and potentially lead to a sudden, explosive boiling known as a "bump." Therefore, maintaining a temperature within the range of the boiling point of water at 1 atm pressure ensures a spontaneous and controlled vaporization process.

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What happens in a redox reaction?

Answers

Electrons are transferred from one reactant to another and the oxidation states/oxidation number of certain atoms are changed

In a heat engine, 500 J of heat enters the system, and the piston does 300 J of work. What is the final internal (thermal) energy of the system if the initial energy is 1500 J?

200 J
800 J
1300 J
1700 J

Answers

Answer:

200J

Explanation:

This is because 500J - 300J = 200J

I hope this helps!!!

Answer:

1700 Joules. I Took the test.

Explanation:

what is the mass of 2.31 x 10^23 formula units of SrF2?

Answers

Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 40.51 g is the mass of 2.31x10²³ formula units of SrF[tex]_2[/tex].

What is mole?

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. It measure the number of elementary entities of a given substance that are present in a given sample.

Given number of atoms= 2.31x10²³atoms

we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number

mole =given number of atoms ÷ 6.022×10²³(Avogadro number)

Substituting the values

mole= 2.31x10²³÷ 6.022×10²³

mole = 0.38 moles of SrF[tex]_2[/tex]

mass of SrF[tex]_2[/tex]= moles of SrF[tex]_2[/tex] × Molar mass of SrF[tex]_2[/tex]

mass of SrF[tex]_2[/tex]= 0.38  × 106.6184

mass of SrF[tex]_2[/tex] = 40.51 g

Therefore, 40.51 g is the mass of 2.31x10²³ formula units of SrF[tex]_2[/tex].

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A reaction yields 6.26 grams of a CuCl2. What is the percent yield of CuCl2 if the theoretical yield is 18.81g?
% Yield = (Actual Yield/Theoretical Yield) x 100

Answers

Answer:

33% yield

Explanation:

6.26/18.81 =0.33280170122 = 33%

What is the absolute magnitude of the rate of change for [NH₃] if the rate of change for [H₂] is 8.70 m/s in the reaction 2 NH₃(g) → N₂(g) + 3 H₂(g)?
a. 4.35 m/s
b. 8.70 m/s
c. 17.40 m/s
d. 26.10 m/s

Answers

Given, the balanced chemical equation is:

2 NH₃(g) → N₂(g) + 3 H₂(g)

The absolute magnitude of the rate of change for [NH₃] is 4.35 m/s.

Therefore, option A is the correct answer.

Given, the balanced chemical equation is:

2 NH₃(g) → N₂(g) + 3 H₂(g)

The rate of change for H2 is 8.70 m/s.

To find the absolute magnitude of the rate of change for [NH₃], we have to use the stoichiometric coefficient in the balanced chemical equation. From the balanced chemical equation, 2 mol NH₃ reacts with 3 mol H₂

We can write,

Rate of change of NH₃ (in m/s) = -1/2 * rate of change of H₂ (in m/s)

So,Rate of change of NH₃ = -1/2 * 8.70 m/s= -4.35 m/s

The absolute magnitude of the rate of change for [NH₃] is 4.35 m/s.

Therefore, option A is the correct answer.

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which statement best describes the reflection of a wave?

Answers

The best statement that describes the reflection of a wave is: When a wave reflects off a surface, it retains its characteristics and changes direction.

A wave is defined as a disturbance that moves through space and matter with the transfer of energy from one place to another. When the wave moves from one medium to another, it reflects off the surface. Reflection of a wave is described as the change in the direction of the wave when it bounces back from the surface on which it strikes.

When a wave reflects off a surface, the angle of incidence is equal to the angle of reflection, which is known as the law of reflection. The normal line, which is perpendicular to the surface, splits the incident and reflected waves at the point of incidence. The angle between the normal line and the incident wave is the angle of incidence, and the angle between the normal line and the reflected wave is the angle of reflection.

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Consider atoms of the following elements. Assume that the atoms are in the ground state.
(A) S (B) Ca (C) Ga (D) Sb (E) Br
1. The atom that contains exactly two unpaired elec¬trons
2. The atom that contains only one electron in the highest occupied energy sublevel

Answers

(A) Sulfur (S) is the atom that contains exactly two unpaired electrons, and (E) Bromine (Br) is the atom that contains only one electron in the highest occupied energy sublevel.

(A) Sulfur (S) has an electron configuration of 1s² 2s² 2p⁶ 3s² 3p⁴. The highest energy level, or valence shell, for sulfur is the third energy level (n = 3). The 3p sublevel has four electrons (3p⁴), and among them, two are unpaired. These two unpaired electrons in the 3p sublevel make sulfur the atom that contains exactly two unpaired electrons.

(E) Bromine (Br) has an electron configuration of 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵. The highest occupied energy level for bromine is the fourth energy level (n = 4). The highest energy sublevel within the fourth energy level is the 4p sublevel. In the 4p sublevel, there are five electrons (4p⁵), and only one electron is needed to complete the sublevel. Thus, bromine contains only one electron in the highest occupied energy sublevel.

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What is the herbivore in the following food chain: algae → fish → herons?

Answers

Answer:

algae

Explanation:

fish and herons arent herbivores

Herbivores are typically tagged as animals that feeds directly on the plants in a food chain.

In the given food chain, Fish is the herbivore

As stated, Fish in the food chain is the herbivore as it feeds directly on the plants. The algae in this case is the producer. While the herons are the carnivore that feeds directly on the flesh of the fish but indirectly on the algae.

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calculate the percent by mass of a solution made from 17 g nacl (the solute) and 59 g water.

Answers

The percent by mass of the solution made from 17 g sodium chloride, NaCl (the solute) and 59 g water is 22.4%

How do i determine the percent by mass of the solution?

First, we shall obtain the mass of the solution. Details below:

Mass of NaCl = 17 gramsMass of water = 59 gramsMass of solution = ?

Mass of solution = Mass of NaCl + mass of water

Mass of solution = 17 + 59

Mass of solution = 76 grams

Finally, we shall determine the percent by mass of the solution. Details below:

Mass of NaCl = 17 gramsMass of solution = 76 gramsPercent by mass =?

Percent by mass = (mass of NaCl / mass of solution) × 100

= (17 / 76) × 100

= 22.4%

Thus, the percent by mass of the solution is 22.4%

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Compound X has molecular formula C5H10. In the presence of a metal catalyst, compound X reacts with one equivalent of molecular hydrogen to yield 2-methylbutane.
a. Suggest three possible structures for compound X.
b. Hydroboration-oxidation of compound X yields a product with no chirality centers. Identify the structure of compound X.

Answers

The structure of compound X is likely 2-Methyl-1-butene (CH3CH=C(CH3)CH2CH3) to yield a product without chirality centers during hydroboration-oxidation.

a. Suggesting three possible structures for compound X (C5H10) can involve considering different isomers of pentane and pentene. Here are three possibilities:

Pentane: CH3CH2CH2CH2CH3

2-Methylbutane: CH3CH(CH3)CH2CH3

2-Methyl-1-butene: CH3CH=C(CH3)CH2CH3

These structures satisfy the molecular formula C5H10 and represent different isomeric possibilities for compound X.

b. Hydroboration-oxidation of compound X yields a product with no chirality centers. This suggests that compound X must be an alkene with a symmetric or non-chiral structure. Among the three possible structures suggested above, the alkene 2-Methyl-1-butene (CH3CH=C(CH3)CH2CH3) would result in a product with no chirality centers when subjected to hydroboration-oxidation.

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How many mL of water to be added to 10 mL of 0.5M solution to make 0.2 M solution?

Answers

Answer:

0.7 is the right

Explanation:

A compound is found to be made up of 3.21 g Carbon and 1.02 g Oxygen. Determine the percent composition from this data?

Answers

Given :

A compound is found to be made up of 3.21 g Carbon and 1.02 g Oxygen.

To Find :

The percent composition from this data.

Solution :

We know, percentage composition is given by :

[tex]\%mass = \dfrac{mass}{mass of compound}\times 100[/tex]

So, percentage composition of Carbon is :

[tex]\%Carbon = \dfrac{3.21}{3.21+1.02}\times 100\\\\\%Carbon = \dfrac{3.21}{4.23}\times 100\\\\\%Carbon = 75.89 \%[/tex]

Since, compound is made up of Carbon and Oxygen.

So, %Oxygen is ( 100 - 75.89 )% = 24.11%

Hence, this is the required solution.

Think about a wooden chair and a balloon. What do these two objects always have in common?


Both are made of atoms.


Both have the same physical properties.


Both are made of the same kind of atom.

Both are made of the same number of atoms.

Answers

Answer:

both are made of atoms. .

Answer:

Both are made of atoms.

Explanation:

Calcular la masa de Mg que se necesita hacer reaccionar con CuSO4 para formar 1.89 g de Cu2O según la siguiente ecuación: Mg + CuSO4 + H2O MgSO4 + Cu2O + H2

Answers

Answer:

0.642 g

Explanation:

La ecuación balanceada es:

2Mg + 2CuSO₄ + H₂O → 2MgSO₄ + Cu₂O + H₂

Primero convertimos 1.89 g de Cu₂O en moles, usando su masa molar:

1.89 g ÷ 143.09 g/mol = 0.0132 mol Cu₂O

Después convertimos moles de Cu₂O en moles de Mg, usando los coeficientes estequiométricos:

0.0132 mol Cu₂O * [tex]\frac{2molMg}{1molCu_2O}[/tex] = 0.0264 mol Mg

Finalmente convertimos moles de Mg en gramos, usando la masa molar de Mg:

0.0264 mol Mg * 24.305 g/mol = 0.642 g

For the Experiment, 10 mL of a DIVA Sciences’ White Vinegar sample will be dispensed and diluted to 100 mL in a 100-mL Volumetric Flask. Determine the range of initial concentrations.
Diluted DIVA Sciences’ White Vinegar (5%) Solution = ____________________ M
Diluted DIVA Sciences’ White Vinegar (8%) Solution = ____________________ M

Answers

To determine the range of initial concentrations, we need to consider the dilution process and the given information.

The initial volume of the vinegar sample is 10 mL, and it is diluted to a final volume of 100 mL. Therefore, the dilution factor is calculated by dividing the final volume by the initial volume:

Dilution factor = Final volume / Initial volume = 100 mL / 10 mL = 10

The diluted solutions are prepared by adding 10 mL of the vinegar sample to a 100 mL volumetric flask and filling it up to the mark with water. So, the final volume of each diluted solution is 100 mL.

Given that the diluted solutions are prepared from the original vinegar sample, we can infer that the percentage concentration refers to the mass/volume percentage. In this case, the percentages (5% and 8%) represent the mass of acetic acid (the main component of vinegar) present in 100 mL of the original sample.

To calculate the molarity of the diluted solutions, we need to know the molar mass of acetic acid, which is approximately 60.05 g/mol.

For the 5% solution:

Mass of acetic acid in 100 mL = (5 g / 100 mL) × 100 mL = 5 g

Using the molar mass, we can convert the mass of acetic acid to moles:

Moles of acetic acid = Mass of acetic acid / Molar mass = 5 g / 60.05 g/mol

Now, we can calculate the molarity:

Molarity (5% solution) = Moles of acetic acid / Final volume (in liters) = (5 g / 60.05 g/mol) / 0.1 L

For the 8% solution, we follow the same steps:

Mass of acetic acid in 100 mL = (8 g / 100 mL) × 100 mL = 8 g

Moles of acetic acid = Mass of acetic acid / Molar mass = 8 g / 60.05 g/mol

Molarity (5% solution) ≈ 0.833 M (rounded to three decimal places)

Molarity (8% solution) ≈ 1.333 M (rounded to three decimal places)

Therefore, the range of initial concentrations is approximately 0.833 M to 1.333 M for the diluted DIVA Sciences' White Vinegar solutions.

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Numbers 15-21

HELP PLEASE!!

Answers

I wish I could help you, but I cannot see your paper. Please re-upload so I can help you : )
Re upload the pic I can’t see it ://

Which of the following cannot be metabolized to make molecules that can enter the citric acid cycle? a. carbohydrates b. lipids c. proteins
d. metal ions

Answers

The one that cannot be metabolised to make molecules that can enter the citric acid cycle is d. metal ions.

Carbohydrates, lipids, and proteins can all be metabolized to produce molecules that can enter the citric acid cycle (also known as the Krebs cycle or TCA cycle). These molecules can be converted into acetyl-CoA, a key intermediate in the citric acid cycle, through various metabolic pathways.

Carbohydrates can be broken down into glucose, which can then undergo glycolysis to produce pyruvate. Pyruvate can be further converted into acetyl-CoA, which enters the citric acid cycle.

Lipids (fats) can be hydrolyzed to release fatty acids and glycerol. Fatty acids are broken down through beta-oxidation, resulting in the production of acetyl-CoA. Glycerol can also be converted into glyceraldehyde-3-phosphate, an intermediate in glycolysis that can generate pyruvate and subsequently acetyl-CoA.

Proteins can be broken down into amino acids through protein digestion and cellular processes such as proteolysis. Amino acids can enter various metabolic pathways, some of which lead to the production of intermediates that can feed into the citric acid cycle.

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If the Earth did not have internal energy, explain what would happen to the carbon cycle and why?

Answers

Answer: Carbon cycle wouldn't be able to create rock formation. Respiration, consumption, combustion (such as fossil burning) are all part of the carbon cycle. They would all be possible without internal energy. Except rock formation.

Explanation:

Using standard heats of formation, calculate the standard enthalpy change for the following reaction. Fe(s) + 2HCl(aq)FeCl2(s) + H2(g) ANSWER: ___ kJ

Answers

The standard enthalpy change for the given reaction is approximately -156.87 kJ.

To calculate the standard enthalpy change (ΔH°) for the given reaction using standard heats of formation, the balanced equation for the reaction is:

Fe(s) + 2HCl(aq) → [tex]FeCl_2[/tex](s) + [tex]H_2[/tex](g)

The standard heats of formation (ΔH°f) for the compounds involved are as follows:

Fe(s): 0 kJ/mol

HCl(aq): -92.31 kJ/mol (source: NIST Chemistry WebBook)

[tex]FeCl_2[/tex](s): -341.49 kJ/mol (source: NIST Chemistry WebBook)

[tex]H_2[/tex](g): 0 kJ/mol

Now, let's calculate the standard enthalpy change (ΔH°):

ΔH° = Σ(ΔH°f products) - Σ(ΔH°f reactants)

ΔH° = [ΔH°f([tex]FeCl_2[/tex]) + ΔH°f([tex]H_2[/tex])] - [ΔH°f(Fe) + 2ΔH°f(HCl)]

ΔH° = [-341.49 kJ/mol + 0 kJ/mol] - [0 kJ/mol + 2(-92.31 kJ/mol)]

ΔH° = -341.49 kJ/mol + 2(92.31 kJ/mol)

ΔH° = -341.49 kJ/mol + 184.62 kJ/mol

ΔH° = -156.87 kJ/mol

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An amphoteric species is neither an acid nor a base. True or False

Answers

Answer: False

Explanation: just took on edge

2. Below is a chemical reaction in which two solutions are combined:
CdSO. (aq)+KS(aq) → CdS(s)+ K₂SO4(aq)
a) What does the (s) mean?
b) For the reactants, cadmium sulfate and potassium sulfide, write a chemical equation showing that each of these dissolve in water.
c) On the products side, potassium sulfate is aqueous and cadmium sulfide is solid. What is the difference? How can you observe this difference in the lab?
d) What is the name for this type of reaction?

Answers

The reaction between CdSO₄ and K₂S is a precipitation reaction where cadmium sulfide precipitates as a solid, while potassium sulfate remains in the aqueous form.

a) The "(s)" in the chemical equation CdS(s) represents that cadmium sulfide is a solid precipitate. It indicates that the product formed in the reaction is solid.

b) The chemical equation for the dissolution of cadmium sulfate (CdSO₄) in water is:

CdSO₄(s) → Cd²⁺(aq) + SO₄²⁻(aq)

The chemical equation for the dissolution of potassium sulfide (K₂S) in water is:

K₂S(s) → 2K⁺(aq) + S²⁻(aq)

c) The difference between potassium sulfate being aqueous (K₂SO₄(aq)) and cadmium sulfide being a solid (CdS(s)) lies in their solubility in water. Potassium sulfate is soluble in water, meaning it dissolves and dissociates into its respective ions (K⁺ and SO₄²⁻) in the solution. On the other hand, cadmium sulfide is insoluble in water and forms a solid precipitate, indicating that it does not dissolve but instead forms solid particles.

In the lab, the difference can be observed by visual inspection. When the reaction between CdSO₄ and K₂S takes place, a yellow precipitate of cadmium sulfide will form, indicating the presence of the solid. The potassium sulfate, being in an aqueous form, will remain dissolved and not form any visible solid.

d) The name for this type of reaction is a precipitation reaction or double displacement reaction. In this reaction, the ions from two compounds exchange to form an insoluble solid (precipitate) and a soluble compound.

In the given reaction between CdSO₄ and K₂S, cadmium sulfide (CdS) is the insoluble solid (precipitate), and potassium sulfate (K₂SO₄) is the soluble compound formed in solution.

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how much water, in grams, can be made from 3.58 × 1024 hydrogen molecules? answer in units of g.

Answers

To determine the amount of water that can be made from a given number of hydrogen molecules, the molar ratio between hydrogen and water needs to be considered. Based on the balanced chemical equation for the formation of water, 2 moles of hydrogen molecules (H2) react to form 2 moles of water (H2O). Using the Avogadro's number and molar mass of water, the calculation can be performed to find the mass of water in grams.

The balanced chemical equation for the formation of water is:

2H2(g) + O2(g) → 2H2O(l)

From the equation, it can be observed that 2 moles of hydrogen molecules (H2) react to produce 2 moles of water (H2O).

Using Avogadro's number (6.022 × 10^23 molecules per mole), we can determine the number of moles of hydrogen molecules present in 3.58 × 10^24 hydrogen molecules:

Number of moles of hydrogen = (3.58 × 10^24) / (6.022 × 10^23) = 5.95 moles

Since the molar ratio between hydrogen and water is 2:2, we can conclude that 5.95 moles of hydrogen will produce 5.95 moles of water.

To find the mass of water, we need to multiply the number of moles of water by the molar mass of water. The molar mass of water (H2O) is approximately 18.015 g/mol.

Mass of water = 5.95 moles × 18.015 g/mol = 107.17 g

Therefore, approximately 107.17 grams of water can be made from 3.58 × 10^24 hydrogen molecules.

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Which statement correctly describes extreme weather?
O A. Extreme weather events follow normal climate patterns.
o O B. Extreme weather events are random occurrences.
O C. Extreme weather events started with global warming.
O D. Extreme weather events are unpredictable until they strike.

Answers

Answer: A

Explanation:

Extreme weather events follow normal climate patterns.

What is the oxidation number of bromine in the HBrO molecule? a. -1
b. +1 c. +2
d. -2

Answers

The oxidation number of bromine in the HBrO molecule is +1. Bromine usually has multiple oxidation states, and in HBrO, it has an oxidation state of +1, the correct answer is b.

This can be determined by assigning oxidation numbers to the other atoms in the molecule and applying the rules for assigning oxidation numbers. In HBrO, hydrogen (H) has an oxidation state of +1, and oxygen (O) typically has an oxidation state of -2. Since the sum of oxidation numbers in a neutral molecule is zero, the oxidation number of bromine (Br) is determined to be +1.

To further explain, oxidation numbers represent the hypothetical charge an atom would have if all the bonds were purely ionic. In HBrO, hydrogen (H) is typically assigned an oxidation state of +1, as it usually donates its one valence electron to form a single bond. Oxygen (O) is generally assigned an oxidation state of -2, as it commonly accepts two electrons to complete its valence shell. The sum of the oxidation numbers in HBrO is then +1 for hydrogen and -2 for oxygen, resulting in a net oxidation number of -1. Since the molecule is neutral, the oxidation number of bromine (Br) must be +1 to balance the charges and achieve a total oxidation number of zero. Therefore, the correct answer is b. +1.

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The atomic number of a made-up element is 413. What would you also know about this element with the given information?

Answers

Answer:

number of protons in the atom

Explanation:

Everything else has something to do with neutrons or weight, which you cannot know from just the atomic number. The atomic number is how many protons are in an element

50 POINTS PLEASE ANSWER CORRECTLY
What happens to the momentum of two cars when they collide?

A. The total momentum after the collision increases.

B. The total momentum after the collision decreases.

C. The total momentum after the collision is equal to the total momentum before the collision.

D. The total momentum before and after the collision is not conserved.

Answers

Answer: I honestly think it might be C

Explanation: Collisions between objects are governed by laws of momentum and energy. When a collision occurs in an isolated system, the total momentum of the system of objects is conserved. ... In the collision between the two cars, total system momentum is conserved.

Answer: C. The total momentum after the collision is equal to the total momentum before the collision.

Hope this helps

Explanation: Collisions between objects are governed by laws of momentum and energy. When a collision occurs in an isolated system, the total momentum of the system of objects is conserved. ... In the collision between the two cars, total system momentum is conserved.

Other Questions
You have four different books and are going to put two on a bookshelf. How many different ways can the books be ordered on the bookshelf?Group of answer choicesA. 4B. 8C. 32D. 6E.12F. 24 a. Suppose that two firms emit a certain pollutant. The marginal cost of reducing pollution for each firm is as follows: MC1 = 300E1 and MC2 =100E2, where E1 and E2 are the amounts (in tons) of emissions reduced by the first and second firms, respectively. Assume that in the absence of government intervention, Firm1 generates 100 units of emissions and Firm 2 generates 80 units of emissions. i. Suppose regulators decide to reduce total pollution by 40 units. In order to be cost effective, how much should each firm cut its pollution? ii. What emissions fee should be imposed to achieve the cost-effective outcome? How much would each firm pay in taxes? iii. Suppose that instead of an emissions fee, the regulatory agency introduces a tradable permit system and issues 140 permits, each of which allows the emission of one ton of pollution. Firm 1 uses its political influence to convince the regulatory agency to issue 100 permits to itself and only 40 permits to Firm 2. How many, if any, permits are traded between the firms? What is the minimum amount of money that must be paid (total) for these permits? By how many tons does each firm end up reducing its pollution? Do you agree that continuous improvement is the implementationof a large number of small, incremental improvements in all areasof the organization on an ongoing basis? Justify your answer. life chances refer to the number of near-death experiences a person has during his or her lifetime.true or false Which of the five senses bypasses the thalamus, taking sense directly to the cortex?SightTouchSmellHearing Which of the following microtubule behaviors is observed during anaphase?(+)-end polymerization(+)-end depolymerizationBoth (+)-end polymerization and depolymerizationNeither (+)-end polymerization nor depolymerization The Blinkelman Corporation has just announced that it plans to introduce a new solar panel that will greatly reduce the cost of solar energy. As a result, analysts now expect the companys earnings, currently (year 0) $1.00 per share to grow by 60 percent per year for the next three years, by 30 percent per year for the following 3 years, and by 7 percent per year thereafter. Blinkelman does not currently pay a dividend, but it expects to pay out 20 percent of its earnings beginning 2 years from now. The payout ratio is expected to become 45 percent in 5 years and to remain at that level. The companys marginal tax rate is 40 percent. If you require a 22 percent rate of return on a stock such as this, how much would you be willing to pay for it today? Use Table II to answer the question. Round your answer to the nearest cent. Jamal has a drawer containing 6 green socks, 18 purple socks, and 12 orange socks. After adding more purple socks, Jamal noticed that there is now a 60% chance that a sock randomly selected from the drawer is purple. How many purple socks did Jamal add?A 6B 9C 12D 18E 24 We collect the impact strength of five pieces of steel. Let "X" be their strengths in foot-pound/inch. Table 1: Impact Strength (ft-lb/in) 1 1 2 3 4 5 5 Point Values 55 56 55 50 46 O pt x-X 2.6 3.6 2.6 -2.4 -6.4 0.5 pt each 0.5 pt cach 6.76 12.96 6.76 5.76 40.96 Note: Carry at least 5 decimal precision for any intermediate calculations. Then, for all numeric entries, round your answer to 3 decimal precision - Leading Os don't count : 3 Part 1: (a) Fill in the missing table cells. (b) The Sum of Squares equals: 73.2 C) This variance equals: 18.3 D) The standard deviation equals: 4.278 E) The deviation for the first observations equals: 2.6 F) The Z-score for the fifth observation equals: -1.4961 Z- Part 2: We wish to convert from foot-pound/in to l/m, so let y be the strength in J/m. There is 1 ft-lb/in for every 53.35 J/m. Note that if Y = a*X+b, then y = a*x + b and sy = 32*sx G) - H) s2y = I) Sy = J) The Z-score for the fifth transformed observation is: Sheffield Corp. produces only one product. Monthly fixed expenses are $13000, monthly unit sales are 3000, and the unit contribution margin is $10. How much is monthly net income? O $30000 O $43000 O (q14) Ron is studying the income of people in a particular state. He finds out that the Lorenz curve for that state can be given as . Find the gini coefficient. Uning the Principle of Time Symmetry. what could you predict about the gravitational force you would experience if you traveled back in time to the age of the Dinosaurs? You would welche less than you do now You would always have the same weight as you do now You would wolph more than you do now Your weight could be calculated using Newton's Universal Law of Gravitation 0 You would love to ww to predict gravitational forces until you arrived on the planet he heat of vaporization of benzene is . calculate the change in entropy when of benzene boils at . be sure your answer contains a unit symbol. round your answer to significant digits. Sickle-cell anemia is a disease that occurs when a person is homozygous for a particular allele; $, and this condition is very often fatal. It might seem odd that there would be an allele that causes a fatal disease. You probably wonder why selection hasn 't gotten rid of this allele, and we're going to help you figure that out. Follow the steppingstones. A The Hardy-Weinberg Equilibrium is: 1 = (p? + 2pq + q). Please define each of the four terms in the equation (1,p' , 2pq, 4); what does each represent? p: the frequency of the m allele: q: the frequency of the e allele 1: the total possibility p2: the frequency of the homozygous dominant genotype Zpq: the frequency of the heterozygous genotype 92: the frequency of the recessive genotype B. Now let'$ dig into the sickle-cell problem. Let '$ assume that a small proportion of the homozygote SS individuals do survive and reproduce, but on average they 'produce only 10% aS many offspring as homozygote SS and heterozygote Ss individuals Clearly they are experiencing strong negative selection. Let'$ also assume that the SS and Ss types don't differ from each other in their reproductive success. Finally, let'$ specify that the starting frequencies of the S and $ alleles (p and 9) are 0.7 and 0.3,respectively: Given these values, please solve for p' and q' (the frequencies of S and $ gfter one generation of selection) " After one generation, has anything changed? Does that answer make sense? Please showour_workl p'= p2 + 0.5*(2pq) = 0.49 + 0.21 = 0.74 9'= 92 + 0.5*(2pq) = 0.09 + 0.21 = 0.3 (here jcnochanoe after one goneration C: If selection were t0 operate in this same way for many generations, what would be the eventual frequency of the (recessive) $ allele? The eventual frequency of the recessive allele will still be 0.3 base on the Hardy-Weinberg Equilibrium. D. Now let '$ add a key real-world observation: Heterozygote individuals (who have one copy of the $ allele) have some resistance to malaria, an insect-transmitted disease which can also be fatal. Let '$ Say that in a particular area where malaria is common, these heterozygotes (Ss) have the highest reproductive success; SS individuals still only do 10% aS well as the heterozygotes; but now SS homozygotes also suffer (from malaria) and do only 40% as well as the heterozygotes: In other words; selection is acting against both homozygotes, though not with equal: intensity: Start with the same initial frequencies of S and $ aS in question IB (0. and 0.3). In this case what will the frequencies of S and $ be after one generation of selection? Please showyour_workl 0.6(p?) 2pq + 0.9(q2)=0.6*0.49+0.21+0.9*0.09-0.585 E. Under this new selective regime (heterozygote superiority) would your answer to question IC change? How and why? Yes; the natural selection can affect the frequency of alleles F. Given that malaria is a tropical disease, transmitted by tropical mosquitoes, and comparing your answers to IC and IE, do you expect sickle-cell anemia to be more common in West Africa Or in Siberia? Why? two cars are traveling at the same speed and hit the brakes at the same time. one car has double the deceleration of the other. by what factor does the time required to stop that car compare with that for the other car? question 1 options: it takes half as long to stop. it takes twice as long to stop. they stop at the same time. none of the above. Identify each of the following as either sexism or androcentrism. oWomen do a disproportionate amount of housework and childcare. oWomen are paid less, on average, than men. oTeachers tend to identify boy students as smarter than girl students.oBoys who are interested in ballet tend to face teasing and other forms of regulation and punishment.oWomen who get ahead are perceived as more masculine.oMen are more constrained in their behavior because they avoid being perceived as feminine A running balance is the total in the account from last period.true or false consider the cell: ni(s) | ni2 (aq, ?m) || cu2 (aq, 0.136 m) | cu(s) ni2 (aq)/ni(s) e = -0.257 v cu2 (aq)/cu(s) e = 0.340 v the measured potential of the cell is 0.621 v. what is [ni2 ] at 25 c? from a consideration of the masses of water measured in part c, and given that the density of water is 1 glml, which is the most acurate method of volume measurement--cylinder, pipet, or buret Casinos attain a profit by collecting the bets/wagers placed by guests, but giving back on average a % of revenues as winnings for the customers and incurring costs of running the operations in a casino utilizing various resources. In a typical month, the casinos gambling area (excluding the food, beverages and lodging) had the following revenues and expenses: There were 500,000 guests. You can assume that all guests will wager the average amount always.Revenues (wagers by guests) $10,000,000Winnings given back to Guests $3,000,000 (as a % of revenues)Labor Costs (salaries) $1,000,000Commissions for employees $700,000 (as a % of revenues)Utilities (unrelated to the number of guests) $600,000Utilities (related to the number of guests) $300,000Depreciation on Casino buildings $2,000,000 and equipmentOther monthly admn. and facility costs $400,000The casino pays combined state and federal taxes equal to 25% of profit before taxes.1. What is the breakeven in dollars?2. How many Diamond Jubilee guests are needed or how much should be the total wagers by guests in a month for the casino to earn an after-tax income of $2,000,000?3. What is the operating leverage in a typical month? What will be the operating leverage if the number of guests were to drop by 50% because of an outbreak?