Given the following skeleton equation, what are the coefficients for the chemicals in the reaction? __ FeSO4 + __ Al(OH)3 → __ Al2(SO4)3 + __ Fe(OH)2

Answer:

A: True

Explanation:

Statement is true because chrysanthemic acid is formed naturally as a result of production of two molecules of dimethylallyl diphosphate which forms pyrophosphate ester.

Thus, it belongs to the pyrethrum family

Explanation:

Well i mean clothes so cells make tissues which help organs clothes can technically help you if you fall it has layers so it woulf be as a cell?

Answer:

6.37

Explanation:

Answer:

high ph

Explanation:

if you have high conc of H+ ph is low therefore acidic but if vice versa basic

high ph

Answer:

A.................. I think the answer

Answer:

Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.

Explanation:

Answer:

Yes, Pb3(PO4)2.

Explanation:

Hello there!

In this case, according to the given balanced chemical reaction, it is possible to use the attached solubility series, it is possible to see that NaNO3 is soluble for the Na^+ and NO3^- ions intercept but insoluble for the Pb^3+ and PO4^2- when intercepting these two. In such a way, we infer that such reaction forms a precipitate of Pb3(PO4)2, lead (II) phosphate.

Regards!

Answer:

I think it's A. I'm pretty sure.

Explanation:

Answer:

Coal, oil and natural gas are called _________A. fossil fuels

Answer:

No you have to use a new email unless you delete the other accaount

Explanation:

hope that helps

Answer:

χsolvent = 1.0000 - 0.1000 = 0.9000

Use Raoult's Law:

Psolution = (χsolvent) (P°solvent)

x = (0.900) (25.756)

x = 23.18 mmHg (to four sig figs)

The vapor pressure of an aqueous solution is  x = 23.18 mmHg (to four sig figs)

χsolvent = 1.0000 - 0.1000 = 0.9000

Use Raoult's Law:

P solution = (χsolvent) (P°solvent)

x = (0.900) (25.756)

x = 23.18 mmHg (to four sig figs)

An aqueous answer is one in which the solvent is liquid water. that is, solute (dissolved) ions and molecules are surrounded by water molecules and integrated into the network of bonds within the water. The dissolved species then spread in the course of the water.

A solution wherein water is the solvent is called an aqueous solution. although water is an exceptional solvent, now not the whole thing dissolves comfortably in the water.

Aqueous' in a chemical equation suggests that the cloth dispersed in water (an answer in water). As an example, when we pour sodium hydroxide answer into dilute hydrochloric acid, we get an aqueous solution of sodium chloride. The liquid is used to signify the formation of liquid materials in response.

Learn more about the aqueous solution here: https://brainly.com/question/19587902

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Answer:

P has a formal charge of 0

Explanation:

Essentially P is in the middle of that ion, and its valence electrons are being used with the 4 Os. Hope that makes sense or helps at least. There's good videos that talk about how this works but I can't link them in brainly

Answer:  [tex]K_a[/tex] for the acid is [tex]5.75\times 10^{-5} [/tex]

Explanation:

[tex]C_6H_5COOH\rightarrow H^+C_6H_5COO^-[/tex]

 cM                    0             0

[tex]c-c\alpha[/tex]        [tex]c\alpha[/tex]          

So dissociation constant will be:

[tex]K_a=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]

Give c= 0.341 M and = 2.351

[tex]K_a=?[/tex]

[tex]pH=-log[H^+][/tex]

[tex][H^+]=10^{-2.351}=0.0044[/tex]

[tex][H^]=c\alpha=0.0044[/tex]  

[tex]K_a=\frac{(0.0044)^{2}}{0.341-0.0044}[/tex]  

[tex]K_a=5.75\times 10^{-5} [/tex]

Thus [tex]K_a[/tex] for the acid is [tex]5.75\times 10^{-5} [/tex]

Answer:

3.54 mol

Explanation:

Step 1: Given data

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 45.00°C + 273.15 = 318.15 K

Step 3: Calculate the number of moles (n) of argon gas

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 2.50 atm × 37.0 L/(0.0821 atm.L/mol.K) × 318.15 K = 3.54 mol

Answer:

a) 2Cu(s) + S(s) → Cu₂S(s)

b) 2SO₂(g) + O₂(g) → 2SO₃(g)

c) 4HCl(aq) +  MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

d) C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

Explanation:

First, we have to write the chemical formulas for reactants and products. Then, to identify which is the state of matter of each compound (liquid: l, solid: s, aqueous: aq, gas: g). Finally, we write the equation and balance the atoms.

a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide.

Reactants: solid copper (Cu(s)) and solid sulfur (S(s)). Product: copper(I) sulfide (Cu₂S) because sulfur anion has two negative charges (S⁻²) and we need two copper ions with one positive charge (Cu⁺) to obtain the neutral compound.

The balanced requires a coefficient of 2 for Cu(s) to balance the 2 Cu atoms on the products side:

2Cu(s) + S(s) → Cu₂S(s)

(b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas.

Reactants: sulfur dioxide (SO₂) and oxygen gas (which is a diatomic molecule: O₂). Products: sulfur trioxide gas (SO₃(s)).

The balanced equation is:

2SO₂(g) + O₂(g) → 2SO₃(g)

We need a coefficient of 2 for SO₂ and SO₃ to balance O and S atoms.

(c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas.

Reactants: aqueous hydrochloric acid (HCl(aq)) and solid manganese (IV) oxide (MnO₂(s), because we need two oxygen anions O²⁻ to neutralize 4 positive charges in Mn IV). Products: aqueous manganese(II) chloride (MnCl₂, because we need two chloride ions Cl⁻ to neutralize two positive charges in Mn(II)), liquid water (H₂O), and chlorine gas (Cl₂, because it is a diatomic molecule).

The balanced chemical equation is:

4HCl(aq) +  MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

(d) Liquid benzene (C₆H₆) reacts with gaseous oxygen to form carbon dioxide and liquid water.

Reactants: benzene (C₆H₆) and gaseous oxygen (O₂). Products: carbon dioxide (CO₂, because C has valence IV) and liquid water (H₂O).

The balanced chemical equation is:

C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

In this case, we need a coefficient of 15/2 for O₂ because on the product side there are 15 atoms of O (12 in CO₂ and 3 in H₂O).

Answer:

The correct answer to this is C. Trigonal Planner

Explanation:

I got it right..

Answer:

The answer is the C. Photic zone.

Explanation:

I wish you good luck! :>

Answer: C photic zone

Explanation:

Answer:

Explanation:

The molarity of a solution when given the number of moles the substance and it's volume can be found by using the formula

[tex]c = \frac{n}{v} \\ [/tex]

n is the number of moles

v is the volume in L

We have

[tex]c = \frac{0.4}{9.79} \\ = 0.04058...[/tex]

We have the final answer as

Hope this helps you

Answer:

answer is D

Explanation:

3B

Answer:

B

Explanation:

to find the new rate when the concentration of reactants changes

Answer: 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} S=\frac{100g}{32g/mol}=3.125moles[/tex]

The balanced chemical equation is:

[tex]2Al+3S\rightarrow Al_2S_3[/tex]  

According to stoichiometry :

3 moles of [tex]S[/tex] require = 2 moles of [tex]Al[/tex]

Thus 3.125 moles of [tex]S[/tex] will require=[tex]\frac{2}{3}\times 3.125=2.08moles[/tex]  of [tex]Al[/tex]  

Mass of [tex]Al=moles\times {\text {Molar mass}}=2.08moles\times 27g/mol=56.2g[/tex]

Thus 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.

Answer:Occluded fronts usually form around areas of low atmospheric pressure. There is often precipitation along an occluded front from cumulonimbus or nimbostratus clouds. Wind changes direction as the front passes and the temperature either warms or cools.

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 976.5 \ Joules}}[/tex]

Explanation:

We are asked to find the heat energy. Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:

[tex]q=mc\Delta T[/tex]

Where m is the mass, c is the specific heat, and ΔT is the change in temperature.

We know this is a 35.0 gram piece of wire, the temperature changes from 21 °C to 52°C and the specific heat is 0.900 J/ g °C.

Therefore,

Substitute these values into the formula.

[tex]q= (35.0 \ g)(0.900 \ J/g \ \textdegree C)(31 \textdegree C)[/tex]

Multiply the first two values. The grams will cancel each other out.

[tex]q=31.5 \ J/ \textdegree C (31 \textdegree C)[/tex]

Multiply again. This time, the degrees Celsius cancel each other out, so the final units are Joules.

[tex]q=976.5 \ J[/tex]

976.5 Joules of energy were required to heat the piece of metal.

Answer: Well "ordinary ice" is made from water (as we all know) and dried ice is made from carbon dioxide gas

Explanation:

•Hope this helps•

Answer:

True

Explanation:

In an alpha decay, the isotope of an element releases two protons and two neutrons. An alpha particle or helium has two protons and two neutrons and hence, in an alpha decay an alpha particle is released.

Hence, the given statement is true

Answer:

I think

Explanation:

N for nitrogen

P for phosphorus

Br for bromine

K for potassium

Mg for magnesium

Answer:

1) increase

2) increase

Explanation:

Entropy is the degree of disorderliness or randomness of a system. It is the measure of the unavailable energy in a system.

Entropy increases with increase in the number of particles. If the number of particles in a system increases from left to right, the entropy of the system increases accordingly.

In reaction 1, the number of particles from left to right increased from two to three hence the entropy was increased.

In reaction 2, the number of particles from left to right increased from three to five hence the entropy was increased.

Answer:

0.67 cm³

Explanation:

We can solve this problem by using the definition of density:

We can rearrange the equation and isolate volume:

As we are given both the mass and the density, we can now calculate the volume:

Answer:

m = 200.6 gr

Explanation:

CH2COOH : n = 3.4 mol

Mr = 12 + 2 + 12 + 2×16 + 1 = 59

n= m / Mr => m = n× Mr => m = 3.4×59 => m = 200.6 gr