giving brainiest to correct answer.
Imagine a 0.2 kg ball moving at 5 m/s colliding with a 0.3 kg ball moving at 2 m/s in the same direction. After the collision the 0.2 kg green ball stops moving and the 0.3 kg purple ball continues moving in the same direction.
giving brainiest to correct answer.

Using Newtons Second Law:

F = m×a

F = (0.25 kg)(-2 m/s²)

F = -0.5 N

A force may cause an object to turn about a pivot. The turning effect of a force is called the moment of the force. Moments act about a pivot in a clockwise or anticlockwise direction.

Answer:

A force may cause an object to turn about a pivot. The turning effect of a force is called the moment of the force. Moments act about a pivot in a clockwise or anticlockwise direction.

Explanation:

Explanation:

wavelength =200cm=2m

frequency is reciprocal of wavelength

f=1/2

f=0.5Hz or 1/s

The frequency of the wave with a Wavelength of 200 cm should be considered as the f=0.5Hz or 1/s.

Since the wavelength is 200 cm or 2m

Also we know that

frequency is reciprocal of wavelength

So,

f=1/2

f=0.5Hz

Hence, The frequency of the wave with a Wavelength of 200 cm should be considered as the f=0.5Hz or 1/s.

Learn more about frequency here: https://brainly.com/question/24470698

Answer:

Wave B has the longest wavelength

Explanation:

The wavelength of a wave is the distance between two consecutive points that are in phase.

The wavelength of a wave is also defined as the distance between successive crests or troughs along the z-axis.

A crest is the point of maximum upward displacement whereas a trough is a point of maximum downward displacement.

Comparing the three waves A, B and C over a unit distance.

Wave A:

Wave A has three crests and two troughs. The wave begins and ends at the rest position. There are 2½ successive points in phase in wave A

Therefore, the wavelength = 1/2.5 = 0.4

Wave B:

Over a unit distance, wave B has two crests and one trough. The wave begins at the rest position and ends at the top of a crest. There are 1¼ successive points in phase in wave B

Therefore, the wavelength = 1/1¼ = 0.8

Wave C:

Over a unit distance, wave C has four crests and four troughs. The wave begins and ends at the rest position.

There are 4 successive points in phase in wave B

Therefore, the wavelength = 1/4 = 0.25

Therefore, wave B has longest wavelength

Answer:

What is the question though?

Explanation:

Answer:

Enamel is used to coat the wires, it is the thinnest possible insulator. The coils are made up of large number of turns and enamel makes it possible to cram a lot of wires (coils) in much smaller space.

Answer:

The following factors could be responsible for size of an Impact Crater:

Hope it helps!<3

Answer:

t = 6 s

Explanation:

Given that,

A chair is thrown upward from a balcony that's 96 ft in the air, d = 96 ft

The initial velocity of chair, u = 16 ft/s

We need to find how many seconds does the chair take to reach its highest height. Let the time is t.

[tex]t=\dfrac{d}{v}\\\\t=\dfrac{96\ ft}{16\ ft/s}\\\\=6\ s[/tex]

Hence, the chair take 6 seconds to reach its maximum height.

Answer:

miami dolphins.

Explanation:

......

Answer:

miami :(

Explanation:

Answer: ⇒  Answer is 3

"A small force may produce a large change in momentum by acting on a very massive object".

THEY HAVEN'T GIVEN US THE TIME PERIOD NOR THE DISTANCE TRAVELED. THEREFORE WE CANNOT ACTUALLY DECIDE IF THE FORCE IS KEPT FOR A LONG TIME OR SHORT TIME. ANYWAYS SINCE THE MASS IS GIVEN AS MASSIVE , THE  MOMENTUM SHOULD BE DEFINITELY HIGH.

WHY I SAY OTHERS ARE WRONG:

1) For a small force to give a large change in momentum, it should act for a long time interval.

2) By applying a large force for a short time interval, the change of momentum should be large.

3) Correct answer.

4) Acting over a short distance can be the same as acting over a short period of time.Therefore the distance should be large in order for a larger momentum.

I HOPE IT HELPS!

The true statement is required.

The true statement is A large force the change in momentum may be small acting over a short time interval.

Force is given by

[tex]F=ma[/tex]

m = Mass of object

a = Acceleration = [tex]\dfrac{v-u}{t}[/tex]

t = Time

So, force is

[tex]F=m\dfrac{v-u}{t}\\\Rightarrow F=\dfrac{mv-mu}{t}\\\Rightarrow F=\dfrac{\Delta p}{t}[/tex]

[tex]\Delta p[/tex] = Change in momentum.

If the time taken is small then the force will be large.

The change in momentum can also be small.

So, for a large force the change in momentum may be small acting over a short time interval.

Learn more:

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Answer:

yes I think

Explanation:

Solar energy systems refer to any technology that converts the sun's energy into another form of energy, such as heat or electricity. ... Solar power is a a subset of solar energy, a more narrow term that typically refers to the conversion of the sun's rays to electricity.

Answer:

The energy used by the iron is 0.2083 KWH.

Explanation:

Electric Energy

The energy consumed by an electrical appliance is given by:

E = P.t

Where:

P = Power consumed

t = Time the appliance is connected to the power supply

The power can be calculated as a function of the voltage V and the current I:

P = V.I

Therefore, the energy is:

E = V.I.t

The electric iron draws a current of I=5 A when connected to a V=250 V supply for t=10 minutes. The time must be expressed in hours, thus t=10/60=0.167 hours.

Thus, the energy is:

E = 250 V * 5 A * 0.167 H

E = 208.33 WH

Converting to KWH:

E = 208.33/1000 = 0.2083 KWH

The energy used by the iron is 0.2083 KWH

Answer:

see attached file

Explanation:

Answer:

m1 ÷ m2 = 1 ÷ 2

Explanation:

The ratio of their masses is as follows:

As it is given that the mass m1 is twice of mass m2

So the equation could be written as

[tex]\frac{1}{2} m1 v1 v1 = 2 \times \frac{1}{2} m2 v2 v2\\\\\frac{m1}{m2} = \frac{2 v2 v2}{v1 v1} ..........(1)[/tex]

Here we used the  conservation of momentum

Prior to the explosion, the object is in rest so the momentum would be zero but after the explosion the total momentum would be  m1v1 + m2v2,  that is also zero.

So,

[tex]m1 v1 + m2 v2 = 0\\\\m1 v1 = - m2 v2\\\\\frac{m1}{m2} = \frac{- v2}{v1}[/tex]

Now squaring to the both sides

m1 m1 ÷ (m2 m2) = v2 v2 ÷ (v1 v1) ........(2 )

Solved both the equations

After solving it, the ratio is

m1 ÷ m2 = 1 ÷ 2

Answer:d

Explanation: oil would form droplets but only tiny ones because it’s surface tension is lower than that of water

Both water and vegetable oil would made droplets but Oil would form  only very tiny droplets because its surface tension is lower than that of water.

Surface tension is the propensity for liquid surfaces that are at rest to condense into the smallest surface area. Razor blades and insects (like water striders), which have a higher density than water, can float on the surface of the water without even becoming partially buried because to surface tension.

Surface tension at liquid-air contacts originates from the liquid molecules' stronger attraction to one another due to cohesion than to the air molecules (due to adhesion).

As the surface tension of the oil is lower than that of water, it forms droplets will smaller size.

Learn more about  surface tension here:

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#SPJ5

First we calculate the acceleration of the cart:

a = (v₂ - v₁) / (t)

a = (7 m/s - 3 m/s) / (8 s)

a = 4 m/s / 8 s

a = 0.5 m/s²

Using the Newtons Second Law:

F = m×a

F = (10 kg)(0.5 m/s²)

F = 5 N

Answer:

e

Explanation:

Answer: E B

Explanation:

This question is incomplete, the complete question is;

A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors

a) (In2)R

b) 4R

c) R/(In2)

d) 2R

e) R

Answer: Option e) R is the correct answer.

Explanation:

Given that;

Inner radius = a

Outer radius = b

Conical Cylinder

∫dR = ∫(edr/2πrL)

R = e/2πL In e |ᵇₐ

R = e/2πL In(b/a) ------------- let this be equation 1

Taking a look at the second cone

a' = 2a

b' = 2a

R' = e/2πL In(2b/2a)

{L = L'}

R' = e/2πL In(b/a) -------let this be equation 2

now lets compare the two equation

R = e/2πL In(b/a)

R' = e/2πL In(b/a)

so R' = R

Therefore Option e) R is the correct answer.

Answer:

The value is  [tex]v = 2 \ m/s[/tex]

Explanation:

From the question we are told that

   The velocity of the each of the three cars is [tex]u_1 = u_2 = u_3 = 2 \ m/s[/tex]

    The velocity of the fourth car is  [tex]u_4 = 4 \ m/s[/tex]

    The initial velocity of the fifth car [tex]u_5 = 0 \ m/s[/tex]

Generally from the law of momentum conservation we have that

    [tex]m_1 u_1 + m_2 u_2 + m_3 u_3 +m_4u_4 + m_5u_5 = [m_1 + m_2 + m_3 +m_4+ m_5]v[/tex]

Given that the cars are identical then their mass will be the same

i.e

    [tex]m_1 =m_2 = m_3 = m_4 = m_5 = m[/tex]

=>   [tex][u_1 + u_2 + u_3 +u_4 + u_5]m = 5mv[/tex]

=>   [tex]2+ 2 + 2 +4 + 0 = 5v[/tex]

= >   [tex]v = 2 \ m/s[/tex]

Answer:

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

Explanation:

By the Principle of Energy Conservation we understand that the minimum speed needed by the ball is that speed such that maximum height reached is equal to the diameter of the vertical circle, that is:

[tex]K =U_{g}[/tex] (1)

Where:

[tex]K[/tex] - Translational kinetic energy, measured in joules.

[tex]U_{g}[/tex] - Gravitational potential energy, measured in joules.

By definitions of translational kinetic and gravitational potential energies, we expand the equation above and clear the initial speed of the ball:

[tex]\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g\cdot h[/tex]

[tex]v = \sqrt{2\cdot g\cdot h}[/tex] (2)

Where:

[tex]m[/tex] - Mass, measured in kilograms.

[tex]v[/tex] - Initial speed, measured in meters per second.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]h[/tex] - Maximum height of the ball, measured in meters.

If we know that [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]h = 5\,m[/tex], then the initial speed of the ball is:

[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]

[tex]v\approx 9.903\,\frac{m}{s}[/tex]

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

Answer;

2.6

Explanation;

Answer:

c. because A will land first becuase its heavier :)

Explanation:

Answer:

The minimum coefficient of static friction required, µ = 0.10

Note. The question is incomplete. The complete question is given below:

While hauling a log in the back of a flatbed truck, a driver is pulled over by the state police. Although the log cannot roll sideways, the police claim that the log could have slid out the back of the truck when accelerating from rest. The driver claims that the truck could not possibly accelerate at the level needed to achieve such an effect. Regardless, the police write a ticket anyway and now the driver court date is approaching.

The log has a mass of m = 929 kg; the truck has a mass of M = 8850 kg. According to the truck manufacturer, the truck can accelerate from 0 to 55 mph in 23.0 seconds, but this does not account for the additional mass of the log. Calculate the minimum coefficient of static friction μs needed to keep the log in the back of the truck.

Explanation:

First, velocity in mph is converted to m/s

1 mph = 0.447 m/s

55 mph ≈ 24.6 m/s

The acceleration of the empty truck is a = v/t = 24.6 / 23 = 1.07 m/s²

Force that can be generated by the truck, F = ma

F = 8850kg * 1.07 m/s² = 9469.5 N

However, with the added mass of the log on it, the acceleration of the truck will become;

a = F / m = 9469.5 N / (8550+929)kg = 0.97 m/s²

Frictional force between the log and the truck = 0.97 m/s² * 929 kg = 901.13 N

Normal reaction on the truck due to the weight of the log, R = mg

R = 929 kg * 9.8m/s² = 9104.2 N

Coefficient of static friction, µ = F/R

µ = 901.13/9104.2

µ = 0.098 ≈ 0.10

Therefore, the minimum static friction required is µ = 0.10

Answer:

If gravity on Earth is increased, this gravitational tugging would have influenced the moon's rotation rate. If it was spinning more than once per orbit, Earth would pull at a slight angle against the moon's direction of rotation, slowing its spin. If the moon was spinning less than once per orbit, Earth would have pulled the other way, speeding its rotation.

i think correct answer is b

Answer:

Explanation:

Answer:

Pressure = Force/Area

347 = 1300/Area

Area = 1300/347

area= 3.47m2

Answer:

I hope the above pic will help you

I will always help you understanding your assingments have a great day

#Captainpower

Answer: net primary productivity

Explanation: i just took my test and this was correct!

Answer:

the amplitude of the sequence oscillation=

ASO = length × velocity

= 9.8 × 0.2 = 19.6

ASO = 19.6

Answer:

ertdhrsg

Explanation:

gesrgsg