Graph this function using intercepts:
36x–20y=–1,800

Answer:

(-6, 1)

Step-by-step explanation:

y = 1 is the equation of a horizontal straight line that passes through (x, 1), where x can be any number.  Four points are given.  y = 1 for only one of them:  (-6, 1).  Answer "Yes" for this one point (the one in the second row).

Answer:

x = 8

Step-by-step explanation:

3 ln 4 = 2 ln x

By using property of logarithm:

ln = ln

Cancel ln on both sides

=

64 =

x =

x = 8

The solution to the equation 3ln4 = 2lnx is {-8, 8}

Given the expression

3 ln 4 = 2 ln x.

We are to find the solution for the variable "x"

Applying the rule of logarithm, the equation will become:

ln4^3 = lnx^2

4^3 = x^2

x^2 = 64

x = 8 and -8

Hence the solution to the equation is {-8, 8}

Learn more on logarithm here: https://brainly.com/question/25710806

Answer:

it is B

Step-by-step explanation:

Answer:

Option B

Step-by-step explanation:

It's a linear equation but not a parallel line to any axis

The general form is

m is rate of change.

Hence y is directly proportional to x if m is kept constant

So option B is correct

Answer:

See below.

Step-by-step explanation:

x-2y=-4

 *-2  *-2

x+y=8

-x     -x

y=-x+8

-hope it helps

Answer:

y = 1/2x + 2⠀

Answer:

1 ofc

Step-by-step explanation:

Think of it:

1% is pretty much [tex]\frac{1}{100}[/tex]

so the equal to that is 1

I hope this answers your question :) If you want to mark me as brainliest (its ok if not :) im just trying to get enough to unlock messages

Answer:

33°

Step-by-step explanation:

9.17% = 9.17/100

[tex]\dfrac{9.17}{100}*360=0.917*36=33.012[/tex]

= 33°

Answer:

33

Step-by-step explanation:

0.917×36=33.012

[tex] \\ \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \\ \\ [/tex]

So as we know he already has $54

Equation formed to find value of x :-

[tex] \leadsto \sf9x = 171[/tex]

[tex] \\ [/tex]

[tex] \leadsto \sf x = \dfrac{171}{9} [/tex]

[tex] \\ \\ [/tex]

[tex] \leadsto \sf x = \dfrac{3 \times 3 \times 19}{9} [/tex]

[tex] \\ \\ [/tex]

[tex] \leadsto \sf x = \dfrac{ \cancel3 \times 3 \times 19}{ \cancel9} [/tex]

[tex] \\ \\ [/tex]

[tex] \leadsto \sf x = \dfrac{ \cancel3 \times 19}{ \cancel3} [/tex]

[tex] \\ \\ [/tex]

[tex] \leadsto \bf x = 19[/tex]

[tex] \\ \\ [/tex]

[tex]\therefore \underline {\textsf{\textbf{No. of hours required is equal to\red{ 19 hours}}}}[/tex]

Answer:

15$ a day would be the estimate for 1 day

Step-by-step explanation:

Part a)

The diagonal line goes through (0,15) and (2,20)

Find the slope based on those points

[tex](x_1,y_1) = (0,15) \text{ and } (x_2,y_2) = (2,20)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{20 - 15}{2 - 0}\\\\m = \frac{5}{2}\\\\m = 2.5\\\\[/tex]

The y intercept is b = 15 because this is where the line crosses the y axis.

We go from y = mx+b to y = 2.5x+15.

Now plug in x = 1 to find the cost of renting for one day.

y = 2.5x+15

y = 2.5*1+15

y = 17.5

Another way to get the answer is to start at 1 on the x axis number line. Draw a vertical line upward until you reach the curve. From there, draw a horizontal line toward the y axis (refer to the diagram below). You should land somewhere between 15 and 20. The midpoint of which is 17.50

=====================================================

Part b)

We can do the reverse idea of the previous part.

Start at y = 25 on the y axis. Draw a horizontal line toward the curve. After reaching the curve, draw a vertical line down until you hit the x axis. You should arrive at x = 4.

Or you can use the algebraic approach since we know the cost equation

y = 2.5x+15

25 = 2.5x+15 ... plug in y = 25

25-15 = 2.5x

10 = 2.5x

2.5x = 10

x = 10/(2.5)

x = 4

Formula: Distance = rate * time

570 = (R+(R-18))*3

570 = (2R - 18)*3

190 = 2R-16

208 = 2R

R = 104

Eastbound Train: 86mph

Westbound Train: 104mph

Answer:

450,000

Step-by-step explanation:

The first digit has 9 choices

Digits 2 through 5 each have 10 choices

Digit 6 has 5 choices.

9 * 10 * 10 * 10 * 10 * 5 = 450,000

Answer:

Step-by-step explanation:

The shape is a trapezoid on top of a parallelogram. The areas of each of the figures can be found separately, then added together.

The area formula is ...

  A = 1/2(b1 +b2)h . . . . where b1, b2 are the base lengths and h is the height

  A = 1/2(12 +a)(7) = 3.5(12 +a) = 42 +3.5a

__

The area formula is ...

  A = bh

  A = (12)(9) = 108

__

The area of the figure is then ...

  total area = trapezoid area + parallelogram area

  172.75 = 42 +3.5a + 108

  22.75 = 3.5a . . . . . . . . . . . . subtract 150

  6.5 = a . . . . . . . . . . divide by 3.5

The length 'a' is 6.5 meters.

__

The perimeter is the sum of the side lengths. Opposite sides of the parallelogram are the same length. Clockwise from the bottom left, the sum of side lengths is ...

  P = 9.2 +7.8 +6.5 +7.3 +9.2 +12 . . . meters

  P = 52 . . . meters

The perimeter is 52 meters.

Answer:

0.027

Step-by-step explanation:

0.474 - 0.447

= 0.027

Answer:

0.027 or 0.447 is greater than 0.474

Step-by-step explanation:

Answer:

Hi ma bruddah

Step-by-step explanation:

Hi - ma - bru/dd/ah

Answer:

A.

Since it says no more than and d doesn't have that sign so yes hope this helps :D

Answer:

[tex]S_{60}=-4620[/tex]

Step-by-step explanation:

[tex]S_n=\frac{n}{2}[2a_1+(n-1)d]\\ \\S_{60}=\frac{60}{2}[2(100)+(60-1)(-6)] \\\\S_{60}=30[200+(59)(-6)]\\ \\S_{60}=30[200-354]\\ \\S_{60}=30[-154]\\\\S_{60}=-4620[/tex]

Answer:

14

Step-by-step explanation:

A sequence is given to us , which is ;

[tex]\longrightarrow 6,10,14,18,22 [/tex]

We need to find out the third term of the sequence . The third term is 14 which is itself given in the question . We can also find it as ,

The given sequence is in Arithmetic progression since a common number is added to get the next term of the sequence .

[tex]\longrightarrow d = 10 -6\\[/tex]

[tex]\longrightarrow d =4 [/tex]

Now we know that the general term of the sequence in an AP is given by ,

[tex]\longrightarrow T_n = a + (n-1)d [/tex]

The first term is 6 and common difference is 4 . On substituting the respective values ,

[tex]\longrightarrow T_3 = 6 + (3-1)4\\[/tex]

[tex]\longrightarrow T_3 = 6 + 2(4)\\[/tex]

[tex]\longrightarrow T_3 = 6 +8\\ [/tex]

[tex]\longrightarrow \underline{\underline{T_3=14}} [/tex]

This is the required answer!

Answer:

G-10

Step-by-step explanation:

because i dont have time to expalin

[tex] \sf \looparrowright \: 8 \frac{1}{6} - 5 \frac{5}{6} [/tex]

Convert the mixed fractions to improper fractions

[tex] \underbrace {8\frac{1}{6} = \frac{6 \times 8 + 1}{6} = \frac{49}{6} }[/tex]

[tex] \underbrace {5\frac{5}{6} = \frac{6 \times 5 + 5}{6} = \frac{35}{6} }[/tex]

[tex] \sf \looparrowright \: \frac{49}{6} - \frac{35}{6} [/tex]

Write the numerators above the common Denominator 6

[tex] \sf \looparrowright \: \frac{49 - 35}{6} [/tex]

Calculate the difference

[tex] \sf \looparrowright \: \frac{14}{6} [/tex]

Reduce the fraction with 2

[tex] \sf \looparrowright \frac{7}{3} [/tex]

Answer:

Answer: cos(A)

Step-by-step explanation:

» From trigonometry,

[tex]{ \tt{ \sin( \theta) = \frac{opposite}{hypotenuse} }} \\ [/tex]

[tex]{ \tt{ \red{ \sin(B) = \frac{AC}{AB} }}} \\ [/tex]

» For cosine:

[tex]{ \tt{ \cos( \theta) = \frac{adjacent}{hypotenuse} }} \\ \\ { \red{ \tt{ \cos(A) = \frac{AC}{AB} }}}[/tex]

» Therefore, sinB = cosA

Answer:

Not enough information

explanation:

Taking sin here:

∠A + ∠B + ∠C = 180°

∠A + ∠B + 90 = 180°

∠A + ∠B = 90°

sin(A) + sin(B) = sin(90)

sin(B) = 1 - sin(A)

Taking cos here:

∠A + ∠B + ∠C = 180°

∠A + ∠B + 90 = 180°

∠A + ∠B = 90°

cos(A) + cos(B) = cos(90)

cos(A) + cos(B) = 0

cos(B) = -cos(A)

Answer:

A closed circle on -4, going to the right.

Step-by-step explanation:

15x ≥ −60

/15     /15

x ≥ -4

This is a closed circle on -4, going to the right.

Hope that helps!

[tex]691 \: 513 \: = > nearest \: to \: thousands \\ = > \: \: \: \: \: \: \: \: 692 \: 000[/tex]

Answer:

the quotient is 12 and there is no remainder

Step-by-step explanation:

Answer:

AC = 2.96

Step-by-step explanation:

Use the trigonometric ratio cosine:

cosine = adjacent ÷ hypotenuse

cos(65°) = AC ÷ 7

[tex]cos(65) = \frac{AC}{7}[/tex]

Multiply both sides by 7:

7(cos(65)) = AC

(Note: Set your calculator to degrees!)

And plug 7(cos(65)) into your calculator to get:

AC ≈ 2.96

Answer:

a. y = -x

b. Area = xy

c. x = -y

Step-by-step explanation:

a. The perimeter of the garden is the distance all the way around, in this would be x+y+x+y, or 2x + 2y. To solve for y, we’re trying to isolate it on one side. We need to subtract 2x to get 2y = -2x. Divide by 2 to get y = -x.

b. Area is length times width, so x • y, or xy.

c. To express in terms of x, we can take the equation y = -x and multiply it by -1 to get x = -y

Answer:

The time to hit the target is simply the period the arrow gets to the target from the arch.

The time to hit the target is 0.35 seconds

Answer:

Height (h) = 1.6

Step-by-step explanation:

Area  of trapezoid = [(base1+base2)/2] * height

now we sub the values in the formula

7.36 = [(3.4+5.8)/2]* h

h= (7.36*2)/(3.4+5.8)

h = 1.6

Answer:

slope = - 7

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

y - 4 = - 7(x - 6) ← is in point- slope form

with slope m = - 7

Answer:

M= -7

Step-by-step explanation:

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

y - 4 = - 7(x - 6) ← is in point- slope form

with slope m = - 7

pls branliest

Answer:

C) 136 yd²

Step-by-step explanation:

[tex]\textsf{\large Area of a triangle:}\ \dfrac{1}{2}\cdot b \cdot h[/tex]

Given:

Substitute the given values into the formula.

[tex]\begin{aligned}A\triangle&=\dfrac{1}{2}(16)(17)\\ &=8(17)\\&=\boxed{136}\end{aligned}[/tex]

The area of the triangle is 136 yd².

Answer:

1. Circle A: 1 right angle

Circle B: 2 pairs of parallel sides, 2 pairs of sides with equal length

2. 2 pairs of parallel sides

2 pairs of sides with equal length

3. 2 sides of equal length

Step-by-step explanation:

1. Circle A: 1 right angle

Circle B: 2 pairs of parallel sides, 2 pairs of sides with equal length

2. 2 pairs of parallel sides

2 pairs of sides with equal length

3. 2 sides of equal length