H2S + CuSO4--->
Complete the equation?

Answers

Answer 1
H2S + CuSO4 → H2SO4 + CuS

Related Questions

HELP WITH MY 2 QUESTION

1-What type of packaging is used for milk?

2-How do the physical and chemical properties (material, reactivity, shape, hardness, color)

Answers

Answer:

Answer to number one

Explanation:

Polyethylene terephthalate (PET) is a plastic material used for milk packaging.

Use the drop-down menus to classify each of the following as an addition, substitution, elimination, or
condensation reaction.
CH3CHO+H2O → CH3OCH3
CH,CICH CI + Zn → C2H4 + ZnCl2
CH3CH3Br + OH – CH3CH3OH + Br
2CH2COOH
>>
(CH3CO)20 + H20

Answers

Answer:

CH3CHO+H2O → CH3OCH3 - addition

CH,CICH CI + Zn → C2H4 + ZnCl2 - elimination

CH3CH3Br + OH – CH3CH3OH + Br - substitution

2CH2COOH >>(CH3CO)20 + H20 - condensation

Explanation:

An addition reaction is a reaction in which a specie is added across the double bond as we can see in CH3CHO+H2O → CH3OCH3.

In an elimination reaction, a small molecule is lost from a saturated compound to form the corresponding unsaturated compound as in CH,CICH CI + Zn → C2H4 + ZnCl2

In a substitution reaction, a chemical moiety replaces another in a molecule as in; CH3CH3Br + OH – CH3CH3OH + Br .

A condensation reaction is in which two molecules are joined together to form a bigger molecule as in; 2CH2COOH >>(CH3CO)20 + H20.

Answer:

addition

elimination

substitution

condensation

The pH for several solutions is given below. After filling in each blank with the correct number, arrange the substances mentioned at the beginning of each sentence in order from most acidic to most alkaline.
a. Black coffee has a pH of 5, therefore its H+ concentration is __________times greater than a solution with a pH of 10
b. Urine has a pH of 6, therefore its H+ concentration is ________times greater than a solution with a pH of 9.
c. Household ammonia has a pH of 11, therefore its H+ concentration is__________ times less than a solution with a pH of 7 .
d.Grapefruit juice has a pH of 3, therefore its H+ concentration is_______ times greater than a solution with a pH of 5 .
2
100
1000000
4
100000
10
3
100,000
1000
5

Answers

how

the

Way

of

it's

the Base

What is leukemia
A
B
C
D

Answers

C. Cancer that affects the blood

Hope I could help!

A typical dollar bill is 15.50 cm by 6.50 cm.
Calculate the surface area in square meters, square centimeters and square nanometers

Answers

Answer:

0.010075 m²100.75 cm²1.0075x10¹⁶ nm²

Explanation:

As the measurements are given to us in centimeters, let's start by calculating the surface area in square centimeters:

Area = 15.50 cm * 6.50 cm = 100.75 cm²

Now we convert 100.75 cm² to m², as follows:

100.75 cm² * [tex](\frac{1m}{100cm}) ^2[/tex] = 0.010075 m²

Finally we convert 0.010075 m² to nm², as follows:

0.010075 m² * [tex](\frac{1nm}{1x10^{-9}m}) ^2[/tex] = 1.0075x10¹⁶ nm²

in
What are common features in
relation to electron arrangement
across a period and down a group
Igor s elements on the periodic
table.​

Answers

Answer:

The order of sub-energy levels ( s » p » d » f )

The number of orbitals ( s » 2 ), ( p » 6), ( d» 10), ( f » 14 )

A 29.00 mL sample of an H2SO4 solution of unknown concentration is titrated with a 0.1122 M KOH solution. A volume of 43.22 mL of KOH was required to reach the equivalence point.
What is the concentration of the unknown H2SO4 solution? Express your answer using four significant figures.

Answers

Answer: The concentration of the unknown [tex]H_{2}SO_{4}[/tex]  solution is 0.167 M.

Explanation:

Given: [tex]V_{1}[/tex] = 29.00 mL,     [tex]M_{1}[/tex] = ?

[tex]V_{2}[/tex] = 43.22 mL,       [tex]M_{2}[/tex] = 0.1122 M

Formula used to calculate concentration of the unknown [tex]H_{2}SO_{4}[/tex] solution is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\M_{1} \times 29.00 mL = 0.1122 M \times 43.22 mL\\M_{1} = 0.167 M[/tex]

Thus, we can conclude that concentration of the unknown [tex]H_{2}SO_{4}[/tex]  solution is 0.167 M.

Look at the equation CO2 + H2 = CO + H20.

CO is a ________

reactant and a product

reactant

product​

Answers

Answer:

CO is considered as a product.

Explanation:

A general chemical equation for a combination reaction follows:

To write a chemical equation, we must follow some of the rules:

The reactants must be written on the left side of the direction arrow.

A '+' sign is written between the reactants, when more than one reactants are present.

An arrow is added after all the reactants are written in the direction where reaction is taking place. Here, the reaction is taking place in forward direction.

The products must be written on the right side of the direction arrow.

A '+' sign is written between the products, when more than one products are present.

For the given chemical equation:

are the reactants in the reaction and  are the products in the reaction.

Hence, CO is considered as a product.

Radioactive radon-222, found in many homes, is a potential health hazard. The half-life of radon-222 is 3.82 days. If you begin with 35.3 mg of this isotope, what mass remains after 10.1 days have passed

Answers

Answer:

5.65mg of the isotope remains

Explanation:

The radioactive decay follows the equation:

Ln[A] = -kt + ln[A]₀

Where [A] is amount of the isotope after time t, k is decay constant, and [A]₀ is initial amount of the isotope.

k = ln 2 / Half-life

k = ln 2 / 3.82 days

k = 0.18145days⁻¹

Replacing:

Ln[A] = -0.18145days⁻¹*10.1days + ln[35.3mg]

ln[A] = 1.7312

[A] = 5.65mg of the isotope remains

With the temperature held constant at 300 K, use the Select mass slider to place weights on the lid. Record the pressure and volume of the gas for each added mass.
Added mass on the lid Total mass Pressure Volume
(Lid + added mass)
0 kg 10 kg
10 kg 20 kg
20 kg 30 kg
30 kg 40 kg

Answers

Solution :

When the temperature is held constant at 300 K, we can use the Select mass slider in order to place the weights on the lid. And we record the pressure and also the volume of the gas for each of the added mass.

Added mass  on the lid       Total mass               Pressure             Volume

          0 kg                                10 kg                    98.1 [tex]N/m^2[/tex]         [tex]2.54 \ m^3[/tex]

          10 kg                               20 kg                   [tex]196.2 \ N/ m^2[/tex]          [tex]1.27 \ m^3[/tex]

          20 kg                              30 kg                   [tex]294.3 \ N/ m^2[/tex]          [tex]0.85 \ m^3[/tex]

          30 kg                               40 kg                   [tex]392.4 \ N/ m^2[/tex]          [tex]0.43 \ m^3[/tex]

As the pressure increases at a constant temperature, the volume of the gas decreases.

Thus we can see that the pressure is inversely proportional to the volume.          

Which of the following compounds is composed of Al,Si,O and H

A.Epsom salt

B.Limestone

C.Clay

D.Urea

Answers

Explanation:

the answer is clay as seen from the picture

aluminum chloride and bubbles of hydrogen gas are produced when metallic aluminum is placed in hydrochloride acid. what is a balanced equation for this reaction?

Answers

Answer:

AlCl3 + HCl ===> AlCl4 +H-

In this lab, you will be making solutions of potassium permanganate (KMnO4), which has a formula weight of 158.04 g/mole. Remember to show your calculations and include tne Correct unnits in your answers
a) How many grams of KMnO4 would you need to make 1 L of a 2M solution?
b) How many grams of KMnO4 would you need to make 350 mL of a 0.75 M solution?
c) How many grams of KMnO4 would you need to make 80 mL of a 0.01 M solution?

Answers

Answer:

A. Mass of KMnO₄ = 316.08 g

B. Mass of KMnO₄ = 41.49 g

C. Mass of KMnO₄ = 0.13 g.

Explanation:

A. Determination of the mass of KMnO₄

We'll begin by determining the number of mole of KMnO₄ in the solution. This can be obtained as follow:

Volume = 1 L

Molarity = 2 M

Mole of KMnO₄ =?

Mole = Molarity × Volume

Mole of KMnO₄ = 2 × 1

Mole of KMnO₄ = 2 moles

Finally, we shall determine the mass of KMnO₄. This can be obtained as follow:

Mole of KMnO₄ = 2 moles

Molar mass of KMnO₄ = 158.04 g/mole

Mass of KMnO₄ =?

Mass = mole × molar mass

Mass of KMnO₄ = 2 × 158.04

Mass of KMnO₄ = 316.08 g

B. Determination of the mass of KMnO₄

We'll begin by determining the number of mole of KMnO₄ in the solution. This can be obtained as follow:

Volume = 350 mL = 350/1000 = 0.35 L

Molarity = 0.75 M

Mole of KMnO₄ =?

Mole = Molarity × Volume

Mole of KMnO₄ = 0.75 × 0.35

Mole of KMnO₄ = 0.2625 mole

Finally, we shall determine the mass of KMnO₄. This can be obtained as follow:

Mole of KMnO₄ = 0.2625 mole

Molar mass of KMnO₄ = 158.04 g/mole

Mass of KMnO₄ =?

Mass = mole × molar mass

Mass of KMnO₄ = 0.2625 × 158.04

Mass of KMnO₄ = 41.49 g

C. Determination of the mass of KMnO₄

We'll begin by determining the number of mole of KMnO₄ in the solution. This can be obtained as follow:

Volume = 80 mL = 80/1000 = 0.08 L

Molarity = 0.01 M

Mole of KMnO₄ =?

Mole = Molarity × Volume

Mole of KMnO₄ = 0.01 × 0.08

Mole of KMnO₄ = 0.0008 mole

Finally, we shall determine the mass of KMnO₄. This can be obtained as follow:

Mole of KMnO₄ = 0.0008 mole

Molar mass of KMnO₄ = 158.04 g/mole

Mass of KMnO₄ =?

Mass = mole × molar mass

Mass of KMnO₄ = 0.0008 × 158.04

Mass of KMnO₄ = 0.13 g

Choose the substance with the highest viscosity. Choose the substance with the highest viscosity. CF4 C7H16 C2H4I2 HOCH2CH2CH2CH2OH (CH3CH2)2CO

Answers

Answer:

C2H4I2

Explanation:

Viscosity of a fluid has to do with the internal friction between the internal layers of the fluid.

Molecular weight is found to be related to the viscosity of a fluid even though the relationship may not be strictly linear.

However, the greater the molecular weight of a substance, the greater the viscosity of the material.

Since C2H4I2 has the greatest molecular weight (281.86 g/mol), it is also expected to display the greatest viscosity among all the compounds listed in the question.

Consider the dehydration of 2-propanol in sulfuric acid: There is a scheme of a reaction where CH3 CH CH3 with an OH group attached to the second carbon atom dehydrated in the presence of H2SO4. Draw the structure for the product of the dehydration of 2-propanol.

Answers

Answer:

CH2=CH-CH3

Explanation:

One of the ways of preparing alkenes is by dehydration of alcohols using sulphuric acid. The sulphuric acid merely acts as a catalyst in the process.

It begins with the protonation of the -OH group. This is followed by loss of water molecule since water is a good leaving group.

Loss of a proton now completes the mechanism and regenerates the acid catalyst.

The mechanism of dehydration of 2-propanol as well as the product formed in the process is shown in the image attached to this answer.

An example of competition between members of two different species is
A) mold growing on a dead tree that has fallen in the forest
B) purple loosestrife plants growing in the same wet areas as cattail plants
C) a coyote feeding on the remains of a deer that died of starvation
D) two male turkeys displaying mating behaviors to attract a female turkey
Pls help

Answers

Answer:

B) purple loosestrife plants growing in the same wet areas as cattail plants

Explanation:

Competition between members of two species means that two different species are "fighting for" or desire the same resource. This resource could be shelter, food, territory, etc.

An organism cannot compete if it is already dead, so that eliminates answer choices A and C. Answer choice D is wrong because these are two organisms of the same species.

Answer choice B is correct because there are two different species competing for one area of land.

For a phase change, H0 = 2 kJ/mol and A S0 = 0.017 kJ/(K•mol). What are
AG and the spontaneity of the phase change at 500 K?

Answers

Answer:

ΔG = -6.5kJ/mol at 500K

Explanation:

We can find ΔG of a reaction using ΔH, ΔS and absolute temperature with the equation:

ΔG = ΔH - TΔS

Computing the values in the problem:

ΔG = ?

ΔH = 2kJ/mol

T = 500K

And ΔS = 0.017kJ/(K•mol)

Replacing:

ΔG = 2kJ/mol - 500K*0.017kJ/(K•mol)

ΔG = 2kJ/mol - 8.5kJ/mol

ΔG = -6.5kJ/mol at 500K

The reduction of carbon dioxide by hydrogen gas takes place at 420°C to produce water vapor and carbon monoxide. The equation for
this reaction at equilibrium is shown below.
H2(g) + CO2(g) = H2O(g) + CO(g)
Which of the following changes in concentration occur when more water vapor is added to the system under equilibrium conditions?
O A [Hz] decreases, [CO] decreases, [CO] increases
OB (H) increases, (CO2) increases, [CO] decreases
OC [Hz, increases, [CO2, increases, [CO] increases
D. [H2, decreases, [CO] decreases, [CO] decreases

Answers

C try it and see if it works

HELP WITH MY 2 QUESTION
1-What type of packaging is used for milk?
2-How do the physical and chemical properties (material, reactivity, shape, hardness, color)
of each packaging type help create new and better product?

Answers

Answer:

1. Milk comes in a range of sizes and forms, and is packaged in a range of materials. Glass bottles, plastic coated paper board, blow mold nonreturnable polyethylene containers, plastic pouches, and returnable rigid polycarbonate containers are among the commercial containers available.

Dont know the answer to the second one sorry :(

NO2 (nitrogen dioxide) is a Greenhouse Gas that can be produced in car engines. The average diesel truck produces 80g of NO2 for every 1000 kilometers it drives. How many moles of NO2 are in 80g of NO2?

Answers

Answer:

[tex]1.74molNO_2[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to perform mole-mass relationships by using the molar mass of the involved substance, in this case NO2, which is 46.0 g/mol; then we just set up a conversion factor like the one shown below:

[tex]80g*\frac{1mol}{46g}\\\\1.74molNO_2[/tex]

Regards!

A molecule or ion that donates the hydrogen in a hydrogen bond is a hydrogen bond donor

a. True
b. False

Answers

Answer:

True

Explanation:

Hydrogen bonding is a type of intermolecular interaction that occurs when hydrogen is bonded to a highly electronegative atom.

We define the term ''hydrogen bond donor'' as the molecule that supplies the hydrogen atom in the hydrogen bond.

Hence, it is true that the molecule or ion that donates the hydrogen in a hydrogen bond is a hydrogen bond donor

g The activation energy for diffusion depends on the strength of atomic bonds. Higher strength bonds result in higher activation energies. How do you predict the activation energy for self diffusion will be related to melting temperature

Answers

Answer:

Yes, the activation energy for self diffusion is related to melting temperature.

Explanation:

The activation energy for self diffusion is related to melting temperature because bonds result due to activation energies and we know that bonds are break down when the temperature is increases and as a result the solid substance melts and change into liquid state. When the bonds between atoms are broken down with the use of heat energy the state of matter changes so we can say that activation energy is related to temperature.

A solution made by dissolving 9.81 g of a nonvolatile, nonelectrolyte in 90.0 g of water boiled at 100.37 °C at 760 mm Hg. What is the molar mass of the substance? [kp = 0.51 °c/m]

Answers

Answer:

151 g/mol

Explanation:

In order to solve this problem we need to keep in mind the formula for the boiling point elevation:

ΔT = Kb * m * i

Where:

ΔT is the temperature difference between the boiling point of the solution and that of pure water. 100.37 °C - 100.00 °C = 0.37 °C.m is the molarity of the solutioni is the van't Hoff factor. As the solute is a nonelectrolyte, the factor is 1.

Input the data and calculate m:

0.37 °C = 0.51 °C/m * m * 1 m =0.72 m

We now can calculate the number of moles of the substance, using the definition of molarity:

molarity = moles of solute / kg of solvent

In this case kg of solvent = 90.0 g / 1000 = 0.090 kg

0.72 m = moles / 0.090 kgmoles = 0.065 mol

Finally we calculate the molar mass, using the number of moles and the mass:

9.81 g / 0.065 mol = 151 g/mol

Question 8 (5 points)
(08.02 MC)
A 10 M concentrated stock solution of NaCl was used to prepare 5 liters of diluted 1 M solution. Which of the following statements is true about
the
process used to achieve this required dilution? (5 points)
O a
The volume of stock solution used was less than 0.4 liters.

The volume of stock solution used was more than 5 liters.
Ос
The volume of the solvent used was less than 0.4 liters.
Od
The volume of the solvent used was less than 5 liters.

Answers

Answer:

d . The volume of the solvent used was less than 5 liters.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the volume of the stock (initial) solution by using the following equation:

[tex]M_1V_1=M_2V_2[/tex]

Thus, we solve for, V1, which stands for the aforementioned volume of stock solution:

[tex]V_1=\frac{M_2V_2}{M_1}[/tex]

Then, we plug in to obtain:

[tex]V_1=\frac{5L*1M}{10M}\\\\V_1=0.5L[/tex]

Now, since the final volume was 5 L, we can infer that the volume of solvent is 4.5 L and that of the stock solution 0.5 L for a total of 5 L of diluted solution; therefore, the correct reasoning is d . The volume of the solvent used was less than 5 liters.

Regards!

Answer:

The volume of the solvent is less than 5

Explanation:

El agua del mar contiene aproximadamente un 3,0 % m/v de sal (NaCl, 58,44 g/mol), (asuma que es la única fuente de cloruros) si una fábrica de baterías para carro provoca un derrame de material con plomo(II). La concentración máxima (en g/L) de plomo(II) que puede contener el agua marina es:_______________
Kps=1,6x10^5

Answers

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

[tex]PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)[/tex]

Lo cual hace que la expresión de equilibrio se calcule como:

[tex]Ksp=[Pb^{2+}][Cl^-]^2[/tex]

Y que en términos de la solubilidad molar, s, se resuelve como:

[tex]1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L[/tex]

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

[tex]s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L[/tex]

¡Saludos!

what is the enthalpy of the overall chemical reaction

Answers

Answer:

For a chemical reaction, the enthalpy of reaction (ΔHrxn) is the difference in enthalpy between products and reactants; the units of ΔHrxn are kilojoules per mole

Which is most likely the reason the U.S government made such an investment

Answers

Answer:

The U.S government made such an investment because they're most likely to reduce harmful emissions.

For the reaction...
H2 (g) + Cl2 (g) <=> 2HCl (g) + heat
If the pressure in the system is increased, the equilibrium position will _______.

a)shift to the left
b)shift to the right
c)not shift position at all as 2 mol gas <=> 2 mol gas

Answers

Answer:

A: Shift to the left

Explanation:

The reaction would try to use up the added heat by making more H 2 and Cl 2.

For an aqueous solution of sucrose (C12H22O11), determine:

the number of moles of sucrose in 1.50 L of this solution

Answers

Answer:WHAT GRADE WORK IS THIS ?

Explanation:

The reaction of bromine gas with chlorine gas, shown here, has a Keq value of 7.20 at 200°C. If a closed vessel was charged with the two reactants, each at an initial concentration of 0.200 M, but with no initial concentration of BrCl, what would be the equilibrium concentration of Br2, Cl2 and BrCl(g)?
Br2(g) + Cl2(g) ↔ 2BrCl(g) K = 7.20

Answers

Answer:

[tex][Cl_2]=[Br_2]=0.856M[/tex]

[tex][BrCl]=0.229M[/tex]

Explanation:

Hello there!

In this case, for this chemical equilibrium problem, it turns out possible for us to solve for the equilibrium concentrations by firstly setting up the equilibrium expression:

[tex]Keq=\frac{[BrCl]^2}{[Cl_2][Br_2]}[/tex]

Thus, by plugging in an ICE chart, in terms of x (reaction extent), we can write:

[tex]7.20=\frac{(2x)^2}{(0.200-x)^2}[/tex]

And could be solved for x as follows:

[tex]\sqrt{7.20} =\sqrt{\frac{(2x)^2}{(0.200-x)^2} } \\\\2.68=\frac{2x}{0.200-x} \\\\x=0.1146M[/tex]

Therefore, the equilibrium concentrations turn out to be:

[tex][Cl_2]=[Br_2]=0.200M-0.1146M=0.856M[/tex]

[tex][BrCl]=2*0.1146M=0.229M[/tex]

Regards!

Other Questions
A small part of a current loop consisting of a very, very large triangular conductor in the x-y plane is shown below, with the current i=39.30 A.12 10 4 2 1 0 1 2 3 4 5 6 7 8 9 10 11 12 x (cm)Calculate the magnitude of the B-field at point 'p'. PLZ HELP ME!!!! how much water must be evaporated from 32 ounces of a 4% salt solution to make an 8% salt solultion? What is the ordered pair for Point T?A. (1,5)B. (0,5)C. (5,0)D. (5, 5 What angle is Framed below60 The Albany Congress believed that under the Albany Plan of Union, the colonies would Calculate the standard enthalpy change for the reaction 2A+B2C+2D Use the following data: Substance Hf (kJ/mol) A -235 B -413 C 193 D -493 Diane Corporation is preparing its year-end balance sheet. The company records show the following selected amounts at the end of the year: Total assets $ 550,000 Total noncurrent assets 352,000 Liabilities: Notes payable (8%, due in 5 years) 21,000 Accounts payable 51,000 Income taxes payable 14,000 Liability for withholding taxes 4,000 Rent revenue collected in advance 9,000 Bonds payable (due in 15 years) 100,000 Wages payable 9,000 Property taxes payable 5,000 Note payable (10%, due in 6 months) 14,000 Interest payable 600 Common stock 250,000 Required: 1-a. What is the amount of current liabilities The passage below contains testimony from the commander of Auschwitz, given at a war crimes trial in 1946.DR. KAUFMANN: Is it furthermore true that Eichmann stated to you that in Auschwitz a total sum of more than 2 million Jews had been destroyed?HSS: Yes.DR. KAUFMANN: Did you yourself ever feel pity with the victims, thinking of your own family and children?HSS: Yes.DR. KAUFMANN: How was it possible for you to carry out these actions in spite of this?HSS: In view of all these doubts which I had, the only one and decisive argument was the strict order and the reason given for it by the Reichsfhrer Himmler.How did Rudolf Hss defend his actions to the court?He believed he was doing what was right for Germany.He stated that the number of people killed by Germans was exaggerated.He testified that he did not personally kill anyone.He said he was just following orders match the given circuit parts to their appropriate functions. write only the letter of the correct answer on your paper1.source a.an appliance/device that uses electricity2.switch source like bulbs,computers.3.wire b.it is a safety device made from materials 4.load that easily melt even before the wires 5.fuse carry too much current. c.it is where electricity came from like batteries and generators. d.it is the pathway of electricity from the resources to the load . e.it controls the flow of electricity from the source. it is used to turn on/off a load. Find the value of x in the triangle shown below. Which of the following represents a constant from the expression given?15x2 + 2x + 9 what is the correct answer There are 1,099 souvenir paperweights that need to be packed in boxes. Each box will hold 11 paperweights. How many boxes will be needed? What happened after the Battle of Gettysburg? To perform a certain type of blood analysis, lab technicians must perform two procedures. The first procedure requires either one, two, or three steps. The second procedure requires either one or two steps. Answer the first and second questions using this information.List the experimental outcomes associated with performing the blood analysis. (Hint: The first procedure has three possible outcomes (steps needed), the second procedure has two possible outcomes (steps needed)). below is a table showing the investment and the investment period of Help please, its for average rate of change. En un curso, el 40 % de los alumnos reprob un examen. Si el curso tiene 45 alumnos. Cuntos alumnos aprobaron Early settlers had to choose a location that would meet their most basic needs. Therefore, the early settlers of Mesopotamia, Egypt, India, China, and Rome all settled near Explain two ways in which beliefs about creation influence christians today