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How does the scientist know that the substance goes through a change of state during the time period labeled B on the graph?
a.the temperature remains the same
b.the temperature increases gradually
c.the particles start slowing down
d.the particles start moving faster

Answer:

B) 0.500 m/s West

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Answer:

(C) 9 mAs

Explanation:

The computation of the new mAs is shown below:

Let us assume the New mAs be x

For adjusting the factors of exposure basically we compared the old one with the new one i.e. presented below:

6 ÷ x = 4 ÷ 6

where

6 = old mAs

4 = old grid factor

x = new mas

6 = new grid factor

Now solve this above equation with the help of cross multiplication

4x = 36

x = 9 mAs

Here we used the 16:1 ratio grid

Hence, the correct option is C. 9 mAs

Answer:

Use

[tex]t = \: \sqrt{2h \div g } [/tex]

[tex]x = u \times \sqrt{2h \div g} [/tex]

Answer:

Symbol: I unit: A

Explanation:

the formula for current is I = v/r

I: Current

V: voltage

R; Resistance

Symbol and unit of measurement are used for the electric current are symbol: I; unit: A

"Electric Current is the rate of flow of electrons in a conductor. The SI Unit of electric current is the Ampere. Electrons are minute particles that exist within the molecular structure of a substance. Sometimes, these electrons are tightly held, and the other times they are loosely held."

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Answer:

A) E = 4.96 x 10³ eV

B) E = 4.19 x 10⁴ eV

C) E = 3.73 x 10⁹ eV

Explanation:

A)

For photon energy is given as:

[tex]E = hv[/tex]

[tex]E = \frac{hc}{\lambda}[/tex]

where,

E = energy of photon = ?

h = 6.625 x 10⁻³⁴ J.s

λ = wavelength = 0.25 nm = 0.25 x 10⁻⁹ m

Therefore,

[tex]E = \frac{(6.625 x 10^{-34} J.s)(3 x 10^8 m/s)}{0.25 x 10^{-9} m}[/tex]

[tex]E = (7.95 x 10^{-16} J)(\frac{1 eV}{1.6 x 10^{-19} J})[/tex]

E = 4.96 x 10³ eV

B)

The energy of a particle at rest is given as:

[tex]E = m_{0}c^2[/tex]

where,

E = Energy of electron = ?

m₀ = rest mass of electron = 9.1 x 10⁻³¹ kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

[tex]E = (9.1 x 10^{-31} kg)(3 x 10^8 m/s)^2\\[/tex]

[tex]E = (8.19 x 10^{-14} J)(\frac{1 eV}{1.6 x 10^{-19} J})\\[/tex]

E = 4.19 x 10⁴ eV

C)

The energy of a particle at rest is given as:

[tex]E = m_{0}c^2[/tex]

where,

E = Energy of alpha particle = ?

m₀ = rest mass of alpha particle = 6.64 x 10⁻²⁷ kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

[tex]E = (6.64 x 10^{-27} kg)(3 x 10^8 m/s)^2\\[/tex]

[tex]E = (5.97 x 10^{-10} J)(\frac{1 eV}{1.6 x 10^{-19} J})\\[/tex]

E = 3.73 x 10⁹ eV

A) The energy in electron volts for a particle with this wavelength if the particle is a photon is; .E = 4969.5 eV or 4.9695 keV

B) The energy in electron volts for a particle with this wavelength if the particle is an electron is; E = 23.58 eV

C) E = 0.003306 eV

A) The formula for the energy here is;

E = hc/λ

where;

h is planck's constant = 6.626 × 10⁻³⁴ J.s

c is speed of light = 3 × 10⁸ m/s

λ is wavelength = 0.25 nm = 0.25 x 10⁻⁹ m

Thus;

E = (6.626 × 10⁻³⁴ × 3 × 10⁸)/(0.25 x 10⁻⁹)

79.512 × 10⁻¹⁷ J

converting to eV gives;

E = (79.512 × 10⁻¹⁷)/(1.6 × 10⁻¹⁹)

E = 4969.5 eV or 4.9695 keV

B) Formula for the energy if the particle is an electron is;

E = h²/(2mλ²)

where m = 9.31 × 10⁻³¹ kg

E = (6.626 × 10⁻³⁴)²/(2 × 9.31 × 10⁻³¹ × (0.25 x 10⁻⁹)²)

E = 37.726 × 10⁻¹⁹ J

Converting to eV gives;

E = (37.726 × 10⁻¹⁹)/(1.6 × 10⁻¹⁹)

E = 23.58 eV

C) Mass of alpha particle is; m = 6.64 × 10⁻²⁷ kg

E = h²/(2mλ²)

where m = 6.64 × 10⁻²⁷ kg

E = (6.626 × 10⁻³⁴)²/(2 × 6.64 × 10⁻²⁷ × (0.25 x 10⁻⁹)²)

E = 52.896 × 10⁻²³ J

Converting to eV gives;

E = (52.896 × 10⁻²³)/(1.6 × 10⁻¹⁹)

E = 0.003306 eV

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Answer: ionosphere

Explanation: aurora boreal is is caused by the ionosphere which is a part of the thermosphere

Answer:

Explanation:(1) a constitution is a supreme law of the land, (2) a constitution is a framework for government; (3) a constitution is a legitimate way to grant and limit powers of government officials. Constitutional law is distinguished from statutory law.

Answer:

Explanation:

Frictional force acting on the box = 35 N

If μ₁ be the coefficient of static friction and μ₂ be the kinetic friction

μ₁ mg = 35

μ₁ = 35 / 6 x 9.8

= .6

b )

net force acting on box to produce acceleration of .6 m /s²

= 6 x .6 = 3.6 N

net  force acting on the box when it is accelerating

= 35 - μ₂ mg

35 - μ₂ x 6 x 9.8 = 3.6

35 - μ₂ x 58.8 = 3.6

μ₂ = .53

Answer:

tA is three times tB

Explanation:

tA is three times tB

Referring to the sketch of a planet around the sun, Area A is three times that of Area B. Compare the times required for the planet to travel from Point 1 to Point 2 and from Point 3 to Point 4 and select the letter of the correct answer.

Answer:

centripetal and of constant magnitude

Explanation:

The acceleration of an object traveling on a circular path at constant speed is directed towards the center of the circle (centripetal) and of constant magnitude equal to the square of the object's speed divided by the radius of the circle.

Answer:

3

Explanation:

Carcinoma refers to a malignant neoplasm of epithelial origin or cancer of the internal or external lining of the body. Carcinomas, malignancies of epithelial tissue, account for 80 to 90 percent of all cancer cases. Epithelial tissue is found throughout the body.

Answer:

C

Explanation:

Answer:

I believe its C

Explanation:

Answer:

C-An object weighs about two times as much on Jupiter as on Neptune.

Explanation:

on edg

Answer:

The first law states that a body at rest will stay at rest until a net external force acts upon it and that a body in motion will remain in motion at a constant velocity until acted on by a net external force. Inertia is the tendency of a body in motion to remain in motion.

Explanation:

Answer:

Explanation:

given

Mass of cart= 150kg

mass of each wheel=45kg

mass of 4 wheels= 180kg

angle of the track=  17 ∘

distance of track= 27m

The height  of the tracl is calculated thus:

sin 17° = h / 27

h = sin 17*27

h=7.89m

"Potential energy at top = kinetic energy of cart and wheels at bottom + rotational energy of wheels at bottom "

1. Potential energy at top= (M+4m)gh

2. kinetic energy of cart and wheels at bottom= 1/2 (M+4m) v²

3. rotational energy of wheels at bottom= 4(1/2 Iω²)

The total is expressed as

(M+4m)gh = 1/2 (M+4m) v² + 4(1/2 Iω²) -------------1

we know that  I = mr² / 2

Put I= mr² / 2

(M+4m)gh = 1/2 (M+4m)v² + 4(1/2 (mr² / 2) ω²)

(M+4m)gh = 1/2 (M+4m)v² +  m r² ω²

we know that  v²= r² ω²

(M+4m)gh = 1/2 (M+4m)v² +  m v²

(M+4m)gh = v² (M/2 + 2m + m)

(M+4m)gh = v² (M/2 + 3m)

v = √[(M+4m)gh / (3m + M/2)]

v = √[(150 + 4*45) * 9.8 m/s² * 7.89 m / (3*45 + 150/2)]

v=√25516.26/142.5

v=√179.06

v = 13.4 m/s

Answer:Well toasting it makes it a solid so that’s a chemical change that happens! Hope this helped!

Answer:

The time for the rock to reach the bottom is 4.02 seconds.

Explanation:

Given;

mass of the rock, m = 5 kg

height of the rock fall, h = 79 meters

The time to drop to the given height is given by;

[tex]t = \sqrt{\frac{2h}{g} }[/tex]

where;

t is the time to fall to the bottom

g is acceleration due to gravity = 9.8 m/s²

[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2*79}{9.8} }\\\\t = 4.02 \ s[/tex]

Therefore, the time for the rock to reach the bottom is 4.02 seconds.

Answer:

2 m/s².

Explanation:

The following data were obtained from the question:

Mass (m) of hammer = 5 Kg

Mass (m) of nail = 0.25 kg

Force (F) applied = 10 N

Acceleration (a) of nail = 40 m/s².

Acceleration (a) of hammer =?

From Newton's third law which states that to every action, there is an equal but opposite reaction. This implies that the force applied by the hammer on the nail is exactly the force applied by the nail on the hammer. Thus, we can obtain the acceleration of the hammer as follow:

Mass (m) of hammer = 5 Kg

Force (F) applied = 10 N

Acceleration (a) of hammer =?

F = ma

10 = 5 × a

Divide both side by 5

a = 10/5

a = 2 m/s²

Thus, the acceleration of the hammer is 2 m/s².

Answer:

a) 0.3 m

b) 3.3 diopters

Explanation:

Given that

Object distance is 26cm from the eye.

Image distance is 105 cm

From the above, we will use the formula

1/f = 1/v + 1/u

where

f is the focal length of the lens,

v is the image distance,

u is the object distance.

Since the image is a virtual image, we will give our v a negative sign. So, on calculating, we have

1/f = 1/25 - 1/151

1/f = 0.0333

f = 1/0.0333

f = 30.03 cm

f = 0.3 m

b) The power of the needed corrective lens is the reciprocal of the focal length in metres;

1/0.3 = 3.3 diopters

This is usually in diopters

Answer:

The beaker that is matt black heats more quickly because black attracts more heat.

Explanation:

Three beakers are of identical shape and size, one beaker is pained matt black, one is dull white and one is gloss white . The beakers are filled with boiling water. The water in the matt black beaker cools more quickly.

The rate of cooling of an object is influenced by its surface properties and color. In this case, the matt black beaker will cool the water more quickly compared to the dull white and gloss white beakers.

The reason behind this lies in the concept of thermal radiation. Darker colors, such as matt black, absorb and emit thermal radiation more efficiently than lighter colors. When the boiling water is placed in the matt black beaker, the black surface absorbs a greater amount of thermal radiation from the water and its surroundings. This increased absorption accelerates the transfer of heat energy from the water to the beaker, leading to faster cooling.

On the other hand, the dull white and gloss white beakers reflect more thermal radiation, absorbing and emitting less heat. As a result, the water in these beakers cools at a slower rate compared to the matt black beaker.

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Answer:

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

Explanation:

We notice that block-spring system depicts a Simple Harmonic Motion, whose equation of motion is:

[tex]y(t) = A\cdot \cos \left(\sqrt{\frac{k}{m} }\cdot t +\phi\right)[/tex] (1)

Where:

[tex]y(t)[/tex] - Position of the mass as a function of time, measured in meters.

[tex]A[/tex] - Amplitude, measured in meters.

[tex]k[/tex] - Spring constant, measured in newtons per meter.

[tex]m[/tex] - Mass of the block, measured in kilograms.

[tex]t[/tex] - Time, measured in seconds.

[tex]\phi[/tex] - Phase, measured in radians.

The spring is now calculated by Hooke's Law, that is:

[tex]k = \frac{m\cdot g}{\Delta y}[/tex] (2)

Where:

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta y[/tex] - Deformation of the spring due to gravity, measured in meters.

If we know that [tex]m=1.65\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta y = 0.260\,m[/tex], then the spring constant is:

[tex]k = \frac{(1.65\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{0.260\,m}[/tex]

[tex]k = 62.237\,\frac{N}{m}[/tex]

If we know that [tex]A = 0.130\,m[/tex], [tex]k = 62.237\,\frac{N}{m}[/tex], [tex]m=1.65\,kg[/tex], [tex]x(t) = 0\,m[/tex] and [tex]\phi = 0\,rad[/tex], then (1) is reduced into this form:

[tex]0.130\cdot \cos (6.142\cdot t)=0[/tex] (1)

And now we solve for [tex]t[/tex]. Given that cosine is a periodic function, we are only interested in the least value of [tex]t[/tex] such that mass reaches equilibrium position. Then:

[tex]\cos (6.142\cdot t) = 0[/tex]

[tex]6.142\cdot t = \cos^{-1} 0[/tex]

[tex]t = \frac{1}{6.142}\cdot \left(\frac{\pi}{2} \right)\,s[/tex]

[tex]t \approx 0.255\,s[/tex]

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

The time taken for the spring to reach new equilibrium position is 0.26 s.

The given parameters;

The general wave equation is given as;

[tex]y(t) = A\ cos(\omega t \ + \phi)[/tex]

The angular frequency is given as follows;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\[/tex]

The spring constant is calculated as;

[tex]F = mg\\\\kx = mg\\\\k = \frac{mg}{x} \\\\k = \frac{1.65 \times 9.8}{0.26} \\\\k = 62.2 \ N/m[/tex]

The angular frequency is calculated as follows;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{62.2}{1.65} }\\\\\omega = 6.14 \ rad/s[/tex]

The time taken for the spring to reach new equilibrium position is calculated as follows;

[tex]y(t) = A \ cos(\omega t)\\\\0 = 0.13 \times cos(6.14t)\\\\6.14t = cos^{-1}(0)\\\\6.14t = 1.57 \ rad\\\\t = \frac{1.57 \ rad}{6.14 \ rad/s} \\\\t = 0.26 \ s[/tex]

Thus, the time taken for the spring to reach new equilibrium position is 0.26 s.

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Answer:

He concluded the fact that most alpha particles went straight through the foil is evidence for the atom being mostly empty space. A small number of alpha particles being deflected at large angles suggested that there is a concentration of positive charge in the atom.

Explanation:

Answer:

1) 0.0806 m/s

2) External forces don't act on the system during the jump

Explanation:

velocity of ball ( Vbf )= 15 m/s

mass of quarter back ( Mq )= 80 kg

mass of football ( Mb ) = 0.43 kg

A) How fast will be be moving backward just after releasing the ball

we can determine this speed with the use of conservation of momentum equation

= Mb ( Vbf - Vbi ) = Mq ( Vq )

where Vq = Mb ( Vbf - Vbi ) / Mq

                 = 0.43 ( 15 m/s - 0 ) / 80 kg

                 = 0.0806 m/s

B) External forces don't act on the system during the jump

Answer:

24g

Explanation:

mass of the product is 40g.

The mass of the first reactant is 16g

The mass of the second reactant  = ?

  Let the first reactant  = A

   Let the second reactant  = B

  Let the product  = C

Equation of reaction;

           A   +  B    →  C

           16g              40g

The mass of B must be  = 40 -16  = 24g

Answer:

omparing the values ​​of the strung density, the one that is closest to carbon is number 2

Explanation:

In this exercise we are given the mass and volume of a body, we are asked to calculate the density, using the equation

          ρ = m / V

in the third and fourth column of the table is the density and the substance with the closest value

#    mass   volume  density   material

        (gr)      (cm³)       (gr/cm³)

1      6.95      4.0          1.74       magnesium

2     4.54      2.0          2.27       carbon

3     5.40      3.0          1.80        phosphorus

4    10.35      5.0         2.07        sulfur

When comparing the values ​​of the strung density, the one that is closest to carbon is number 2

This question involves the concept of the orbital period.

The period of revolution of the second satellite is "3.95 x 10⁶ s".

First, we will consider the orbital period of the first satellite:

[tex]T_1=\sqrt{\frac{4\pi^2 r_1^3}{GM}}[/tex]

where,

Therefore,

[tex]1\ x\ 10^6\ s=\sqrt{\frac{4\pi^2(8\ x\ 10^6\ m)^3}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(M)}}\\\\M = \frac{4\pi^2(8\ x\ 10^6\ m)^3}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1\ x\ 10^6\ s)^2}\\\\M = 3.03\ x\ 10^{20}\ kg[/tex]

Now, we find out the orbital period of the second satellite:

[tex]T_2=\sqrt{\frac{4\pi^2 r_2^3}{GM}}[/tex]

where,

Therefore,

[tex]T_2=\sqrt{\frac{4\pi^2(2\ x\ 10^7\ m)^3}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(3.03\ x\ 10^{20}\ kg)}}[/tex]

T₂ = 3.95 x 10⁶ s

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Answer:

x is vertical and y is horizontal

Explanation:

Answer:

Explanation:

Initial kinetic energy of particle

= 1/2 m V²

= .5 x .208 x 1.26²

= .165 J

Work done by force = force x displacement

= .766 x .195

= .149 J

This energy will be added up .

Total final kinetic energy

= initial kinetic energy + work done on the particle

= .165 + .149 J

=  .314 J .

Answer:

High and low tides are caused by the Moon. The Moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the Moon and the side farthest from the Moon. These bulges of water are high tides.

Explanation: