Mathematics High School

Help! I will Mark Brainliest!
For the graphed function f(x) = (4)x − 1 + 2, calculate the average rate of change from x = 1 to x = 2.

−3
3
2
−2

Help! I Will Mark Brainliest!For The Graphed Function F(x) = (4)x 1 + 2, Calculate The Average Rate Of

Answers

Answer 1

Answer:

Your answer is B. I had some help from my mom.

Step-by-step explanation:

the average rate of change on the interval [1, 2] is found by computing

 (f(2) - f(1))/(2 - 1)

 = ((4^1+2) - (4^0+2)/1

 = (6-3)

 = 3

Related Questions

2-(x+1)/(x-2)-(x-4)/(x+2)can be written as a single fraction in the form (ax+b)/(x^(2)-4) where a and b are intergers

Answers

Answer:

a = 3, b = -18

Step-by-step explanation:

You can start by getting a common denominator in the fractions [tex]\frac{x+1}{x-2}[/tex] and [tex]\frac{x-4}{x+2}[/tex]. You can multiply the first one by [tex]\frac{x+2}{x+2}[/tex] to get [tex]\frac{(x+2)(x+1)}{x^2-4}[/tex]and you can multiply the second by [tex]\frac{x-2}{x-2}[/tex] to get [tex]\frac{(x-4)(x-2)}{x^2-4}[/tex]. You can simplify the fractions:

[tex]\frac{(x+2)(x+1)}{x^2-4}[/tex] - [tex]\frac{x^2+3x+2}{x^4-4}[/tex]

[tex]\frac{(x-4)(x-2)}{x^2-4}[/tex] - [tex]\frac{x^2-6x+8}{x^2-4}[/tex]

Now we can rewrite the equation:

[tex]2-\frac{x^2+3x+2}{x^2-4} -\frac{x^2-6x+8}{x^2-4}[/tex]

and combine the terms with the same denominator:

[tex]2+\frac{-x^2-3x-2-x^2+6x-8}{x^2-4}[/tex]

[tex]2+\frac{-2x^2+3x-10}{x^2-4}[/tex]

Now, to add the two into the fraction, we multiply it by [tex]x^2-4[/tex] to get [tex]2x^2 - 8[/tex].

[tex]\frac{2x^2-8-2x^2+3x-10}{x^2-4}[/tex]

And simplify:

[tex]\frac{3x-18}{x^2-4}[/tex]

a = 3, b = -18

The value of the integers a and b are 3 and - 18 respectively.

What do you mean by algebraic expressions ?

Algebraic expression is an equation which consists of variables and the arithmetic operations such as division , multiplication , etc.

Firstly , let's find out a common denominator in the fractions , [tex]\frac{x+1}{x-2}[/tex] and [tex]\frac{x-4}{x+2}[/tex] .

The first one can be written as :

= [tex]\frac{x+1}{x-2}[/tex] × [tex]\frac{x+2}{x+2}[/tex]

= [tex]\frac{(x+1)(x+2)}{x^{2} - 4}[/tex]

and the second one can be written as :

= [tex]\frac{x-4}{x+2}[/tex] × [tex]\frac{x-2}{x-2}[/tex]

= [tex]\frac{(x-4)(x-2)}{x^{2} - 4}[/tex]

The expression will be :

= 2 - [tex]\frac{x+1}{x-2}[/tex] - [tex]\frac{x-4}{x+2}[/tex]

= 2 - [tex]\frac{(x+1)(x+2)}{x^{2} - 4}[/tex] - [tex]\frac{(x-4)(x-2)}{x^{2} - 4}[/tex]

= [ 2 (x²- 4) - (x+1) (x+2) - (x-4) (x-2)]/ [(x²- 4)]

= [2x² - 8 - x² - 3x - 2 - x² + 6x - 8] / [(x²- 4)]

By simplifying it , we get :

= [tex]\frac{3x-18}{x^{2} - 4}[/tex]

If we compare it with the given form which is [tex]\frac{ax + b}{x^{2} -4}[/tex] we get :

[tex]\frac{3x-18}{x^{2} - 4}[/tex] = [tex]\frac{ax + b}{x^{2} -4}[/tex]

or

3x - 18 = ax + b

or

The values of a and b are :

a = 3 and b = -18.

Therefore , the value of the integers a and b are 3 and - 18 respectively.

Learn more about algebraic expressions here :

https://brainly.com/question/1382660

#SPJ2

-6 ( x – 8) = 60
Show steps

Answers

Answer:

-6(x-8)=60x-8= -10x= -10+8x= -2

hope it helps...

Answer:

-2

Step-by-step explanation:

-6 ( x - 8) = 60

• divide -6 on both sides

-6 and -6 cancel out and 60 ÷ -6 = -10

• your new equation is now x - 8 = -10

• add 8 to both sides x - 8 = -10

+8. +8

• x = -2

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Step-by-step explanation:

Answer:

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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