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Answer:

The magnitude of F when t=4 s=146.64 N

Explanation:

We are given that

Mass of crate,m=6.00 kg

Height of crate above its initial position is given by

[tex]y(t)=(2.80 m/s)t+(0.610 m/s^3)t^3[/tex]

We have to find the magnitude of F when t=4.00 s

Differentiate w.r.t t

[tex]\frac{dy}{dt]=2.8+3(0.61)t^2[/tex]

[tex]\frac{d^2y}{dt^2}=6(0.61)t[/tex]

[tex]a(t)=\frac{d^2y}{dt^2}=6(0.61)t m/s[/tex]

[tex]a(4)=6(0.61)(4)=14.64 m/s^2[/tex]

Now, magnitude of force

[tex]F=m(a+g)=6(14.64+9.8)=146.64N[/tex]

Hence, the magnitude of F when t=4 s=146.64 N

Answer:

80 m

Explanation:

From the question given above, the following data were obtained:

Speed = 8 m/s

Time = 10 s

Distance =?

Speed can be defined as the distance travelled per unit time. Mathematically, it can be expressed as:

Speed = Distance / time

With the above formula, we can obtain the distance travelled as illustrated below:

Speed = 8 m/s

Time = 10 s

Distance =?

Speed = Distance / time

8 = Distance / 10

Cross multiply

Distance = 8 × 10

Distance = 80 m

Therefore, the distance travelled is 80 m

Answer:

C. Y

Explanation:

From Newton's second law of motion, we know that:

       Force = mass x acceleration

So;

      acceleration  = [tex]\frac{Force }{mass}[/tex]  

 Therefore, to have the highest acceleration at a constant force, the mass must be low. Acceleration is inversely proportional to mass.

Y has the least mass and it will have the highest acceleration

Pulleys are powerful simple machines. They can change the direction of a force, which can make it much easier for us to move something. If we want to lift an object that weighs 10 kilograms one meter high, we can lift it straight up or we can use a pulley, so we can pull down on one end to lift the object up.

Answer:

Pulleys are powerful simple machines. They can change the direction of power, which can make it much easier for us to move something. If we want to lift an object that weighs 10 kilograms one meter high, we can lift it straight up or use a pulley, so we can pull one end down and lift the object.

Explanation:

Answer:

No. Touching a live electric current is never a good idea.

Answer:

false you would electrocute yourself

Explanation:

!!!!!!!!!!!     LOGICAL     !!!!!!!!!

Answer:

7.35 m/s

Explanation:

Using y - y' = ut - 1/2gt², we find the time it takes the ball to fall from the 1.2 m table top and hit the floor.

y' = initial position of ball = 1.2 m, y = final position of ball = 0 m, u = initial vertical velocity of ball = 0 m/s, g = acceleration due to gravity = 9.8 m/s² and t = time taken for ball to hit the ground.

So, substituting the values of the variables into the equation, we have

y - y' = ut - 1/2gt²

0 - 1.2 m = (0 m/s)t - 1/2(9.8 m/s²)t²

- 1.2 m = 0 - (4.9 m/s²)t²

- 1.2 m = - (4.9 m/s²)t²

t² = - 1.2 m/- (4.9 m/s²)

t² = 0.245 s²

t = √(0.245 s²)

t = 0.49 s

Since d = vt where d = horizontal distance ball moves = 3.6 m, v = horizontal velocity of ball = unknown and t = time it takes ball to land = 0.49 s.

So, d = vt

v = d/t

= 3.6 m/0.49 s

= 7.35 m/s

Since the initial velocity of the ball is 7.35 m/s since the initial vertical velocity is 0 m/s.

It is shown thus V = √(u² + v²)

= √(0² + v²)

= √(0 + v²)

= √v²

= v

= 7.35 m/s