help me please I will be thankful

Answer:

105 degrees

Step-by-step explanation:

You need to understand the properties of corresponding angles and supplementary angles.

Answer:

12.6 cm

Step-by-step explanation:

Answer:

4 x’s for 1/4

2 x’s for 2/4

1 x for 3/4

2 x’s for 1

Step-by-step explanation:

Answer:

Question 1: A

Question 2: D

Step-by-step explanation:

I hope it helps

Rewrite the fractions to have a common denominator:

1/3 = 10/30

4/6 = 20/30

1/5 = 6/30

Now compare the numerators and list from smallest to largest:

6/30, 10/30, 20/30

The order would be:

1/5, 1/3, 4/6

Answer:

1/5, 1/3, 4/6

Step-by-step explanation:

The bigger the fraction denominator the smaller is.

Answer:

0.045 kg of cookies

Answer: 0.045

Step-by-step explanation:

Answer:120 Degrees

Step-by-step explanation:

Angle M and N add up to 180 degrees so,

180= 11x-40 (Since 3x+8x would be 11x)

220=11x (Add 40 to both sides)

X=20 (divided 220 by 11)

Answer:

(-19/2, -5)

Step-by-step explanation:

Given the two equivalent equations

4x – 9y = 7 .... 1

–4x + 6y = 8 ....2

Adding both equations

-9y + 6y = 7+8

-3y = 15

y = -15/3

y = -5

Substitute y = -5 into 1

From 1; 4x - 9y = 7

4x - 9(-5) = 7

4x + 45 = 7

4x = 7 - 45

4x = -38

x = -38/4

x = -19/2

Hence the solution is (-19/2, -5)

Answer:

it's a bit blurry but if I aint wrong it's the 2nd one that say 2/5

Answer:

2.5 kilograms of chocolate

Step-by-step explanation:

Answer:

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

Step-by-step explanation:

For each race, there are only two possible outcomes. Either the person has a crash, or the person does not. The probability of having a crash during a race is independent of whether there was a crash in any other race. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

A certain performer has an independent .04 probability of a crash in each race.

This means that [tex]p = 0.04[/tex]

a) What is the probability she will have her first crash within the first 30 races she runs this season

This is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

When [tex]n = 30[/tex]

We have that:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{30,0}.(0.04)^{0}.(0.96)^{30} = 0.2939[/tex]

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2939 = 0.7061[/tex]

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

Answer:

I believe it's 15,000//B

Answer:

18 x 6 =108. she spent 108 minutes reading.

Step-by-step explanation:

Answer:

I dont even know lol

Step-by-step explanation:

Answer:

Like when its in a file? They just like to take your points

Step-by-step explanation:

Answer:

B - obtuse

D - acute

Step-by-step explanation:

Answer:

I think angle B is an obtuse angle and D is an acute angle. I'm not sure.

Hope this helps :)

Answer:64 Meters

Step-by-step explanation:

Answer:

G

Step-by-step explanation:

Answer:

its G

Step-by-step explanation:

Answer:

m=8

Step-by-step explanation:

Divide each term in

7

m

=

56

7

m

=

56

by

7

7

.

7

m

7

=

56

7

7

m

7

=

56

7

Cancel the common factor of

7

7

.

Tap for more steps...

m

=

56

7

m

=

56

7

Divide

56

56

by

7

7

.

m

=

8

m

=

8

Step-by-step explanation:

7m=56

you have to have m by itself so to do that divide 7 on both sides.

7m/7=56/7

the 7 gets cancels on the left side so now you have

m=56/7

you divide

you get m=8

Answer:

C

Step-by-step explanation:

what was a similarty between the united states troops sent to the spanish- american war and troops sent to fight in world war 1

Answer:

c

Step-by-step explanation:

Answer: D. -7x-5y=-48

Step-by-step explanation:

The slope of AB is [tex]\frac{-1-4}{-3-4}=\frac{5}{7}[/tex]. Since perpendicular lines have slopes that are negative reciprocals, the slope of BC is -7/5.

Substituting into point-slope form,

[tex]y-4=-\frac{7}{5}(x-4)\\\\5y-20=-7(x-4)\\\\5y-20=-7x+28\\\\\boxed{-7x-5y=-48}[/tex]

Answer:

x= 29°

y= 73°

z= 102°

Step-by-step explanation:

x is on the opposite side of the 29° which means it is equal to 29°

In order to find y we can add 29°+78° and subtract it from 180° since all triangles add up to 180°.

This makes y = 73°

In order to find z, we can subtract 78 from 180 since all straight lines are 180 degrees.

This makes z = 102°

Answer:

b. Tan A = 5/12

Step-by-step explanation:

Recall: SOHCAHTOA.

Since the trigonometric function we are to find is Tan A, we would use TOA, which is:

Tan θ = Opp/Adj

θ = A

Opp = 20

Adj = 48

Thus:

Tan A = 20/48

Simplify the fraction

Tan A = 5/12

Answer:

10×2+ 5÷2

=20+2.5

=22.5

Answer:

Feet and yards; the 1 whole strip could represent 1 yd. and the [tex]\frac{1}{3}[/tex] strip could represent feet.

Answer:

4,500

Step-by-step explanation:

just cause

Median of the given set of price is $4500

The median is the value separating the higher half from the lower half of a data sample, a population, or a probability distribution

Given set of data = $7000, $2000, $9000, $3000, $5000, $4000

Order the values from low to high

$2000, $3000, $4000, $5000, $7000, $9000

Find the middle term

Here number of terms = 6

It is even number  

Then find [tex]\frac{n}{2}[/tex] and [tex]\frac{n}{2}+1[/tex] terms

[tex]\frac{n}{2}=\frac{6}{2}=3[/tex]

[tex]\frac{n}{2}+1=3+1=4[/tex]

Median is the mean of the 3rd value and 4th value

Median =[tex]\frac{4000+5000}{2}=4500[/tex]

Hence, the median of the given set of price is $4500

Learn more about Median here

https://brainly.com/question/15923434

#SPJ2

Answer:

The mean absolute deviation is 2.25. Hope this helps

Step-by-step explanation:

2+4+6+9 divided by 4=5.25

5.25-2=3.25

5.25-4=1.25

6-5.25=0.75

9-5.25=3.75

3.25+1.25+0.75+3.75=9 divided by 4=2.25

By the polynomial remainder theorem, the remainder is

f (2) = 2⁵ + 5×2³ + 4 = 32 + 40 + 4 = 76

(The theorem says a polynomial p(x) has remainder p(c) upon dividing it by x - c.)

Answer:

[tex](a)\ g(x) = \frac{2}{3}(x+1)[/tex]

[tex](b)\ h(y) = \frac{1}{3}[1 + 4y][/tex]

[tex](c)[/tex] [tex]P(x>0.5) =\frac{5}{12}[/tex]

Step-by-step explanation:

Given

[tex]f(x,y) = \left \{ {{\frac{2}{3}(x+2y)\ \ 0\le x \le 1,\ 0\le y\le 1} \right.[/tex]

Solving (a): The marginal density of X

This is calculated as:

[tex]g(x) = \int\limits^{\infty}_{-\infty} {f(x,y)} \, dy[/tex]

[tex]g(x) = \int\limits^{1}_{0} {\frac{2}{3}(x + 2y)} \, dy[/tex]

[tex]g(x) = \frac{2}{3}\int\limits^{1}_{0} {(x + 2y)} \, dy[/tex]

Integrate

[tex]g(x) = \frac{2}{3}(xy+y^2)|\limits^{1}_{0}[/tex]

Substitute 1 and 0 for y

[tex]g(x) = \frac{2}{3}[(x*1+1^2) - (x*0 + 0^2)}[/tex]

[tex]g(x) = \frac{2}{3}[(x+1)}[/tex]

Solving (b): The marginal density of Y

This is calculated as:

[tex]h(y) = \int\limits^{\infty}_{-\infty} {f(x,y)} \, dx[/tex]

[tex]h(y) = \int\limits^{1}_{0} {\frac{2}{3}(x + 2y)} \, dx[/tex]

[tex]h(y) = \frac{2}{3}\int\limits^{1}_{0} {(x + 2y)} \, dx[/tex]

Integrate

[tex]h(y) = \frac{2}{3}(\frac{x^2}{2} + 2xy)|\limits^{1}_{0}[/tex]

Substitute 1 and 0 for x

[tex]h(y) = \frac{2}{3}[(\frac{1^2}{2} + 2y*1) - (\frac{0^2}{2} + 2y*0) ][/tex]

[tex]h(y) = \frac{2}{3}[(\frac{1}{2} + 2y)][/tex]

[tex]h(y) = \frac{1}{3}[1 + 4y][/tex]

Solving (c): The probability that the drive-through facility is busy less than one-half of the time.

This is represented as:

[tex]P(x>0.5)[/tex]

The solution is as follows:

[tex]P(x>0.5) = P(0\le x\le 0.5,0\le y\le 1)[/tex]

Represent as an integral

[tex]P(x>0.5) =\int\limits^1_0 \int\limits^{0.5}_0 {\frac{2}{3}(x + 2y)} \, dx dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 \int\limits^{0.5}_0 {(x + 2y)} \, dx dy[/tex]

Integrate w.r.t. x

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 (\frac{x^2}{2} + 2xy) |^{0.5}_0\, dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 [(\frac{0.5^2}{2} + 2*0.5y) -(\frac{0^2}{2} + 2*0y)], dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 (0.125 + y), dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}(0.125y + \frac{y^2}{2})|^{1}_{0}[/tex]

[tex]P(x>0.5) =\frac{2}{3}[(0.125*1 + \frac{1^2}{2}) - (0.125*0 + \frac{0^2}{2})][/tex]

[tex]P(x>0.5) =\frac{2}{3}[(0.125 + \frac{1}{2})][/tex]

[tex]P(x>0.5) =\frac{2}{3}[(0.125 + 0.5][/tex]

[tex]P(x>0.5) =\frac{2}{3} * 0.625[/tex]

[tex]P(x>0.5) =\frac{2 * 0.625}{3}[/tex]

[tex]P(x>0.5) =\frac{1.25}{3}[/tex]

Express as a fraction, properly

[tex]P(x>0.5) =\frac{1.25*4}{3*4}[/tex]

[tex]P(x>0.5) =\frac{5}{12}[/tex]

Answer:

1 = -48

2 = 9

3 = -6

4 = - 4

Step-by-step explanation:

Hello there!

For each problem we are going to want to plug in the value of x (which is given) and find the total value of the expression

For #1

8(-4) + 4(-4)

8 * - 4 = -32

4*-4=-16

-32+(-16)=-48

So the answer to #1 is -48

For #2

9(3)-18

9*3=27

27-18=9

so the answer to #2 is 9

For #3

-2(8)+10

-2*8=-16

-16+10=-6

so the answer to #3 is -6

For  #4

5(-3)+11

5*-3=-15

-15+11=-4

So the answer to #4 is -4