Hey guys can you help me with this problem it's giving me a headache. "If 2500 kg roller coaster car begins its descent from 500m above above the first hill. What is its kinetic energy at the bottom of the hill."

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[tex] \pink{false}[/tex]

Answer:

False

Explanation:

I hope this helped have a great day!!!

Answer:

b. the Paleozoic Era

Explanation:

The first vertebrates to appear are primitive fish in the Cambrian Period, but bony fishes with actual bony vertebratae didn't appear for another 100 million years. The Cambrian Period is the first of three periods in the Paleozoic Era. The Cambrian explosion was an event when practically all major animal phyla started appearing in the fossil record.

Answer:

A closed organ pipe is λ/4  (node-antinode) long.

λ = speed / frequency = 331.5 / 259.6 = 1.28 m

λ/4 = .319 m     length of closed pipe

An open pipe has a fundamental wavelength of A-N-A or λ/2

The second harmonic would be A-N-A-N-A   or   λ = 1.28 m for the second harmonic   331.5 / 259.6 = 1.28  (the fundamental would be 331.5 / .628

Assuming each trial represents 1000years, and rock samples were found, the rock sample will be given half-life of

We know that the parent Isotope remaining is given by the expression

[tex]\frac{1}{2}^n[/tex]

where,

n = number of half lives passed

From the question, the parent Isotope remaining is [tex]25\%[/tex] lokium

[tex]0.25 = \frac{1}{4} = \frac{1}{2^2} = \frac{1}{2}^2[/tex]

Therefore,

[tex]\frac{1}{2}^2[/tex] means 2 half lives have passed.

If from the question,

1 half life = 1000years

Therefore,

The rock sample's age = [tex]2*1000 = 2000years[/tex]

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Answer:

Answers A and D are the correct solution.

Explanation:

Both pots have the same mass and the same velocity vector.

the only difference between A and D is the selection of the reference frame positive direction.

The equation (A) and equation (D) correctly model the momentum of the two-cactus system.

The product of a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction.

According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.

Given that: mass of each cactus: m = 5 kg.

And they slide down a sagging shelf in the same direction with the same speed.

In equation (A), both velocities of two cacti are in positive direction whereas, in equation (B), both velocities of two cacti is in negative direction.  Hence, equation (A) and equation (D) correctly model the momentum of the two-cactus system.

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The ball was kicked with a speed of 38.4 m/s.

Using s = ut + 1/2gt², we find the time it takes the ball to reach the ground. Where

Substituting the values of the variables into the equation, we have

s = ut + 1/2gt²

75 m = (0 m/s)t + 1/2 × 9.8 m/s² × t²

75 m = 0 m + (4.9 m/s²) t²

75 m = (4.9 m/s²)t²

Dividing both sides by 4.9, we have

t² = 75 m/4.9 m/s²

t² = 15.306 s²

Taking square-root of both sides, we have

t = √15.306 s²

t = 3.91 s

The horizontal distance covered by the ball d = vt where

Since we require v, we make it subject of the formula.

So, v = d/t

Given that d = 150 m and t = 3.91 s, substituting these into v, we have

v = d/t

v = 150 m/3.91 s

v = 38.4 m/s

So, the ball was kicked with a speed of 38.4 m/s.

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Answer:

the wind carries abrasive materials

Explanation:

such as sand and salt over time theses small particles slowly strip way at the land form sculpting it by eroding the softer layers first

Answer:

Explanation:

F = ma

a = F/m

a = 75/25

a = 3 m/s²

Answer:

Explanation:

30 m/s • 3 hr •3600 s/hr / 1000 m/km = 324 km west

Answer:

1. friction, gravity,

Explanation:

Answer:

Is called an Ion

Explanation:

Answer:

An electrically charged atom is called an ion

Answer:

3 v

Explanation:

Answer:

[tex]v^2=\frac{T}{M}[/tex]

where v = transverse wave velocity, T = tension in the string, M = mass per unit length.

Explanation:

Dimensional analysis is where you just look at the units and see how they fit within each other.

In this case, all relationships are made using the MLT comparisons, where M stands for Mass, L stands for Length, and T stands for time.

For example, for velocity, we know the SI unit for velocity is [ms⁻¹] which is L¹T⁻¹, we can do the same thing for tension = [N = Kgms⁻²] = M¹L¹S⁻², and for the mass per unit length which we can think of as [Kgm⁻¹] = M¹L⁻¹.

If you play around a little with the powers, you can find a relationship:

[tex]v^2=\frac{T}{M}[/tex]

since:

[L¹T⁻¹]² = L²T⁻² = M¹L¹T⁻² ÷ M¹L⁻¹ = M¹⁻¹L¹⁻⁽⁻¹⁾T⁻² = M⁰L²T⁻² = L²T⁻²

An artistic statement should be written from your own perspective.

An artist's statement, also known as an artist statement, is a written summary of their creative output. The brief essay serves as an explanation of and a defense of their own work for the spectator. As a result, it is didactic, descriptive, or reflective in nature and seeks to inform, connect with an artistic environment, and reveal the inspiration behind the work.

The writing created by the artist aims to contextualize, justify, extend, and/or explain their body of work. It situates—or tries to situate—the piece in relation to art history, art theory, the contemporary art scene, and the times. The statement also demonstrates that the artist is aware of their aims, their practice, its place within the parameters of art, and the debate that surrounds it.

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Answer:

V= A ω      maximum KE of object in SHM

V2 / V1 = .958     ratio of amplitudes since ω is constant

KE2 / KE1 = 1/2 m V2^2 / (1/2 m V1^2) = (V2 / V1)^2

KE2 / KE1 = .958^2 = .918

So KE2 = .918 KE1 and .082 = 8.2% of the energy is lost in one cycle

Answer:

a. democracy

Explanation:

beacouse the government control of their members

When the cart was at Table

Now acceleration due to gravity acting on the gravity.

Hence.

[tex]\\ \sf\Rrightarrow F_{net}=0N[/tex]

Answer:

Impulse = change in momentum w bounce

There are 2 impulses acting. Recoil of the fan going the negative direction and the impulse of the air bouncing off the sail. The greater impulse will bounce so the direction will be to the right moving the craft.

The relationship between variables might be either directly porportional to each other or inversely proportional to each other. For instance, the current flowing is _directly_ proportional to the potential difference across it.

---------------------

Since I do not have the graph, I will propose two potential options and I will describe each of them.

I suggest you to choose the one that matches the shape of graph 3.

The current flowing through this component is __DIRECTLY__ proportional to the potential difference across it.

If this is the case of your graph, you should see the straight line crossing from the left inferior quadrant to the right superior one.

The direction of the line suggests that one of the variables increases as the other one increases too. The current increases as the potential increases.

This is the case of the Ohm's law.

The current flowing through this component is __INVERSELY__ proportional to the potential difference across it.

If this is the case of your graph, you should see the straight line crossing the right quadrant from the superior left corner to the inferior right one.

The direction of the line suggests that the variable represented in the Y ax decreases as the other one increases.

For instance, The current decreases as the potential increases. Or the potential decreases as the current increases.

In the attached files you will find graphs of both options.

-------------------------

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Answer: The relationship between variables might be either directly proportional to each other or inversely proportional to each other. For instance, the current flowing is directly proportional to the potential difference across it.

Explanation:

Answer:

41.6m/s

Explanation:

P=mv

2500kg × 25m/s = 62500kgm/s

62500kgm/s ÷ 1500 kg = 41.6m/s

Answer:

its sort of like how Pounds are measured in lbs

Explanation:

Pounds are measured in lbs when they dont sound anything similar, same thing applies to gun technology.

Hi there!

We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.

[tex]\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}[/tex]

There is NO initial vertical velocity, so:

[tex]\large\boxed{\Delta d= \frac{1}{2}at^2}}[/tex]

Rearrange to solve for time:

[tex]2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}[/tex]

Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)

[tex]t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s[/tex]

Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:

[tex]\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}[/tex]

Answer:

Explanation:

Terminal speed is

2 m/s²(3 s) = 6 m/s

30 m / 6 m/s = 5 s

total sink time is

3 + 5 = 8 s

The total time taken by the rock to sink would be 8 seconds

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

The acceleration of the rock for the first three seconds = 2 meters/second²

The time taken to reach the terminal velocity = 3 seconds

terminal velocity = 2 ×3

                           = 6 meters/second²

The time for which the rock sink at terminal velocity = 30 /6

                                                                                       = 5 seconds

total time is taken by the rock to sink = 3 + 5

                                                           =8 seconds

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Answer:False

Explanation:

the intensity of the sound wave decreases with increasing distance from the source.

The answer is:

That they are switched on

Answer:

The net force on the hanging mass is thus

2 T Mg     18 6.6 N 11.4 N

, enough to accelerate it upward at

17 m/s2

. The angular acceleration of the pulley is thus

   

2 2

Explanation:

The tension in the rope on both sides of the pulley 20.21N.

To solve this problem, we'll need to consider the forces acting on both sides of the pulley and apply Newton's second law of motion. Let's break it down step by step:

(a) Is the tension in the rope the same on both sides of the pulley?

No, the tension in the rope is not the same on both sides of the pulley. The side with the greater mass attached will experience a greater tension in the rope.

(b) Find the tension in the rope on both sides of the pulley:

Calculate the gravitational force on each mass:

Gravitational force on the pulley: Fpulley = mpulley * g, where mpulley is the mass of the pulley and g is the acceleration due to gravity (approximately 9.8 m/s²).

Gravitational force on the hanging mass: Fhanging = mhanging * g, where m_hanging is the mass of the hanging mass.

Calculate the net force on the pulley:

Net force on the pulley is the difference between the tension forces on either side: Fnet = TLeft - Tright.

Apply Newton's second law to the pulley:

For the pulley, Fnet = mpulley * a, where a is the acceleration of the pulley. Since the pulley is assumed to be massless, we can use the relationship a = α * r, where α is the angular acceleration and r is the radius of the pulley.

Use the relationship between linear acceleration and angular acceleration:

α = a / r.

Equate the torque due to the tension to the moment of inertia times the angular acceleration:

τ = I * α, where τ is the torque, I is the moment of inertia of the pulley, and α is the angular acceleration.

Substitute the expression for α and solve for the net tension:

Tnet = (τ / r) = (I * α) / r = (1/2 * mpulley * r² * α) / r = (1/2 * mpulley * r * a).

Now, substitute the expression for a from step 3 and solve for the net tension:

Tnet = (1/2 * mpulley * r * α) = (1/2 * mpulley * r * (a / r)) = (1/2 * mpulley * a).

Substitute the expression for a from step 2 (Fnet = mpulley * a) and solve for the net tension:

Tnet = (1/2 * Fnet).

Now, you can find the tensions on each side of the pulley:

Tleft = Tnet + Fhanging

Tright = Tnet - Fpulle

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Answer:

An electron tube from which all air has been removed. The vacuum ensures transparency inside the tube for electric fields and moving electrons. Most electron tubes are vacuum tubes; cathode-ray tubes, which include television picture tubes and other video display tubes, are the most widely used vacuum tubes

Explanation:

hope it help