Cellular respiration and photosynthesis similar is both processes break down glucose
Photosynthesis converts carbon dioxide and water into oxygen and glucose and glucose is used as food by the plant and oxygen in a byproduct whereas cellular respiration converts oxygen and glucose into water and carbon dioxide and both processes break down glucose and both are processes within the cell which make chemical energy available for life
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Why can't you use the equation Q = mc∆T to calculate how much thermal energy is needed to melt or boil a substance?
We can't you use the equation Q = mc∆T to calculate how much thermal energy is needed to melt or boil a substance because this equation is to calculate for heat energy transferred between two objects where m is the mass of each object and c is the specific heat capacity
Thermal energy refers to the energy contained within a system that is responsible for its temperature and for thermal energy for melt any substance is latent heat and during boiling of any substances the heat energy supplied is used in increasing the energy of the water molecule which changes its state from liquid to gaseous
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how many milliliters of 3.0m naoh are required to react with 0.5g of cu 2 to form cu(oh)2? ( hint: write the net ionic equation for reaction 2, to get correct mole ratio) ( answer should be written in decimal form)
The number of milliliters of 3.0m NaOH required to react with 0.5g of Cu2+ to form Cu(OH)2 is 5.249 ml
The reaction is as follows;
2NaOH + Cu2+ ------------> Cu(OH)2 + 2Na+
From the balanced chemical reaction, 0.5 g of Cu2+ = 0.5/63.5 = 7.874x10-3 moles (molar mass of Cu2+ = 63.5 g)
Thus, moles of NaOH required = 2*moles of Cu2+ = 0.01575
Now, moles of NaOH = molarityxvolume in litres
or, 3*volume in litres = 0.01575
or, volume in litres = 5.249*10-3 litres = 5.249 ml
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A 24.20 g sample of a metal displaces 1.26 mL of water. Calculate the density of the metal.
19.2g/cm³
D = m / V
24.20g / 1.92ml = 19.2g/cm³
a certain first order reaction has a half-life of 41.3 s. how long will it take (in s) for the reactant concentration to decrease from 6.50 m to 2.06 m? give your answer to three sig figs
The time needed to decrease reactant concentration based on its half-life is 68.47 seconds.
We need to know about the half-life of the radioactive elements to solve this problem. The radioactive element will decay over time and follow the equation
N = No(1/2)^(t/t'')
where N is the final quantity, No is the initial quantity, λ is the decaying constant, t is time and t'' is the half-life of a radioactive element.
From the question above, we know that
t'' = 41.3 s
No = 6.5 m
N = 2.06 m
By substituting the given parameters, we can calculate the time taken
N = No(1/2)^(t / t'')
2.06 = 6.5 . (1/2)^(t / 41.3)
0.32 = (1/2)^(t / 41.3)
⁰'⁵log(0.32) = t / 41.3
1.66 = t / 41.3
t = 68.47 seconds
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Hey, this is basically almost a free point (just multiple choice of 1 pressure)
Answer:
1st option
Explanation:
At sea level, atmospheric pressure is high, and water boils at 100 °C (212 °F)
Answer:
the third one ;)
Explanation:
what is the difference between an element and an isotope? an isotope is an element with a different number of electrons. an isotope is an element with a different number of neutrons. an isotope is an element with a different number of protons.
Answer:
different number of neutrons
The greatest about of transpiration will occur over _____________.
Group of answer choices
a mountain top covered in snow
a large river with a high discharge
the ocean
a large forest with mature trees.
The greatest about of transpiration will occur over a large forest with mature trees.
Transpiration is described because the physiological lack of water in the form of water vapor, especially from the stomata in leaves, but also thru evaporation from the surfaces of leaves, plants, and stems.
Transpiration is the system wherein plants release the water interior it inside the shape of moisture or water vapor. Roots eat some quantity of water from the soil and the rest evaporates inside the atmosphere. elements of plants consisting of stems, small pores on leaves, and plants evaporate the water to the environment.
Leaf stomata are the primary web sites of transpiration and encompass two defend cells that form a small pore on the surfaces of leaves. The defend cells control the opening and last of the stomata in reaction to various environmental stimuli and may alter the fee of transpiration to reduce water loss.
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WHAT IS THE SIZE OF MY D\
Answer:get a ruler and find out
Explanation:
measure from tip to tip and post a picture to see
Answer:baby carrots
Explanation:
measure with baby carr
find values of the intrinsic carrier concentration n. for silicon at -55°c, 0°c, 20°c, 75°c, and 125°c. at each temperature, what fraction of the atoms is ionized? recall that a s
The intrinsic carrier concentration and the fraction of ionized atoms of silicon at -55℃, 0℃, 20℃, 75℃, 125℃ is calculated below.
The intrinsic carrier concentration in intrinsic material is the number of electrons found in the conduction band or holes in the valence band. This quantity of carriers is determined by the material's band gap as well as its temperature.
Because the number of holes equals the number of electrons, the concentration of each is equal to some amount, ni, and this quantity is known as the intrinsic carrier concentration, and the pure semiconductor material is referred to as intrinsic material.
Given:
B = 5.4 x [tex]10^{31}[/tex]
[tex]E_G[/tex] = 1.12 ev for silicon
K = 8.62 x [tex]10^{-5}[/tex]
Silicon crystal = 5 x [tex]10^{22}[/tex] atoms/[tex]cm^3[/tex]
To find:
Intrinsic carrier concentration, ni = ?
Fraction of ionized atom = ?
Formula:
[tex]ni^2 = BT^3 e^{\frac{-E_G}{KT}[/tex]
Fraction of ionized atom = ni / 5 x [tex]10^{22}[/tex]
Calculations:
(a) For -55℃:
T = -55 + 273 = 218K
ni = [tex]5.4 * 10^{31} * 218^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 218})}[/tex]
ni = 2.7018 x [tex]10^6[/tex] carriers/[tex]cm^3[/tex]
Fraction of ionized atom = 2.7018 x [tex]10^6[/tex] / 5 x [tex]10^{22}[/tex]
Fraction of ionized atom = 5.403 x [tex]10^{-17}[/tex] atoms/[tex]cm^3[/tex]
(b) For 0℃:
T = 0 + 273 = 273K
ni = [tex]5.4 * 10^{31} * 273^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 273})}[/tex]
ni = 1.53 x [tex]10^9[/tex] carriers/[tex]cm^3[/tex]
Fraction of ionized atom = 1.53 x [tex]10^9[/tex] / 5 x [tex]10^{22}[/tex]
Fraction of ionized atom = 3.07 x [tex]10^{-14}[/tex] atoms/[tex]cm^3[/tex]
(c) For 20℃:
T = 20 + 273 = 293K
ni = [tex]5.4 * 10^{31} * 293^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 293})}[/tex]
ni = 8.65 x [tex]10^9[/tex] carriers/[tex]cm^3[/tex]
Fraction of ionized atom = 8.65 x [tex]10^9[/tex] / 5 x [tex]10^{22}[/tex]
Fraction of ionized atom = 1.73 x [tex]10^{-13}[/tex] atoms/[tex]cm^3[/tex]
(d) For 75℃:
T = 75 + 273 = 348K
ni = [tex]5.4 * 10^{31} * 348^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 348})}[/tex]
ni = 3.724 x [tex]10^{11}[/tex] carriers/[tex]cm^3[/tex]
Fraction of ionized atom = 3.724 x [tex]10^{11}[/tex] / 5 x [tex]10^{22}[/tex]
Fraction of ionized atom = 7.449 x [tex]10^{-12}[/tex] atoms/[tex]cm^3[/tex]
(e) For 125℃:
T = 125 + 273 = 398K
ni = [tex]5.4 * 10^{31} * 398^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 398})}[/tex]
ni = 4.75 x [tex]10^{12}[/tex] carriers/[tex]cm^3[/tex]
Fraction of ionized atom = 4.75 x [tex]10^{12}[/tex] / 5 x [tex]10^{22}[/tex]
Fraction of ionized atom = 9.51 x [tex]10^{-11}[/tex] atoms/[tex]cm^3[/tex]
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Living things need __________ for thinking, eating and moving
Answer:
Living beings need survive for thinking,eating,and moving.
Answer:
Brain, mouth and legs
Explanation:
the following are needed for the above questions
If an Oreo cookie is 0.69 cm thick (1 cookie = 0.69 cm), how many Oreos does it take to reach the moon if the moon is 3.84 x 10^8 m away from earth?
It takes 5.89 x 10¹⁰ Oreos to reach the moon.
The average distance from the Earth to the moon is 385 000.6 km.
Metres = 385 000.6 km × (1000 m/1 km ) = 385 000 600 m
Centimetres = 38 500 060 000 m × (100 cm/1 m) = 38 500 060 000 cm
Oreos = 38 500 060 000 cm × (1 Oreo/0.654 cm) = 58 900 000 000 Oreos
= 5.89 x 10¹⁰ Oreos
Its diameter is around one-quarter that of the Earth (comparable to the width of Australia). The Moon is the Solar System's fifth-largest satellite. It is the largest (and most massive) satellite relative to its home planet and is larger than any other known dwarf planet. [f] According to geophysical criteria, the Moon is a planetary-mass object that became a differentiated rocky body, making it a satellite planet. There is no atmosphere, hydrosphere, or magnetic field. Its surface gravity is around one-sixth that of Earth (0.1654 g). Io, Jupiter's moon, has the highest surface gravity and density of any satellite in the Solar System.
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i will give brainliest please help
1. A compound has an empirical formula of CO4 and a mass of 228 g/mol. What is the molecular formula?
2. What is simplest form (empirical formula) of C4H24O12?
The molecular formula is [tex]\rm C_2O_8[/tex]. The empirical formula is [tex]\rm C_2H_1_2O_6[/tex] which is the simplest from.
What is molecular formula?Molecular formula is defined as a chemical formula that gives the total number of atoms of each element in each molecule of a substance.
It can also be defined as a formula derived from molecules that indicates the total number of individual atoms in the molecule of a compound.
Empirical formula is defined as a chemical formula that depicts the simplest elemental ratio of a compound rather than the total number of atoms in the molecule.
Molecular formula = n - empirical formula
Thus, the molecular formula is [tex]\rm C_2O_8[/tex]. The empirical formula is [tex]\rm C_2H_1_2O_6[/tex] which is the simplest from.
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Identify the hybridization of the N atoms in N2H4
All of the nitrogen in the N2H4 molecule hybridizes to Sp3.
How does hybridization work?The combining of two atomic orbitals to create a whole new class of hybridized orbitals is the notion of hybridization in chemistry. Hybrid orbitals with completely distinct energies are often the outcome of this mixing. In hybridization, the same-energy level atomic orbitals are crucial. However, as long as they have an equivalent amount of energy, both fully and partially filled orbitals can participate in this process.
All of the nitrogen in the N2H4 molecule hybridizes to Sp3. N2H4 has a dipole moment of 1.85 D and is polar in nature. The nitrogen atoms in N2H4 have no formal charge. The N2H4 molecule has a trigonal molecular geometry (shape).
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Calculate the volume occupied by 5.44 g of oxygen gas (O2) at a pressure of 0.881 atm and a temperature of 27.4 C
After thoroughly calculating, we have come to find that, the volume occupied by 5.44 g of oxygen gas (O2) at a pressure of 0.881 atm and a temperature of 27.4 C is 4.76 L.
What is ideal gas law?The equation of state of an ideal gas, also known as the general gas equation, is the ideal gas law. Even though it has a number of restrictions, it is a good approximation of the behaviour of many gases under a variety of conditions. T
he empirical Boyle's law, Charles' law, Avogadro's law, and Gay-law Lussac's were all combined in Benoît Paul Émile Clapeyron's first formulation of it in 1834. Often, the empirical form of the ideal gas law is used:
PV is equal to nRT where n is the quantity and R is the ideal gas constant, where p, V, and T are the pressure, volume, and temperature. As accomplished by August Krönig in 1856 and Rudolf Clausius in 1857, it can also be derived from the microscopic kinetic theory.
To find the volume we will use the ideal gas law
PV = nRT
Where.
P = pressure
V = volume
n = amount of substance
R = ideal gas constant
T = temperature
Here, we have give pressure of 0.881 atm
Temperature of 27.4 C = (27.4+273) = 300.4 K
5.44 g of O₂ gas convert it into moles
Mass/Molar mass = No. of moles
5.44/32 = 0.17 mol
R = 0.0821 L atm K⁻¹ mol⁻¹
We need to find volume that is
V = nRT/P
= (0.17 × 0.0821 × 300.4)/ 0.881
= 4.76 L
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Balance the equations.
MgO + HBr → MgBr₂ + H₂O
Answer:
Since there is an equal number of each element in the reactants and products of MgO + 2HBr = MgBr2 + H2O, the equation is balanced.
The only transition metal that is a liquid at room temperature
(21 °C) is named
Answer:
mercury
Explanation:
mercury is a metal on the periodic table which is liquid at room temperature
4. which parts of the amino acids x and y are involved in the formation of a peptide bond between them? assume that w is the first amino acid in the polypeptide chain, x is the second, and y is the third.
In a polypeptide chain, to generate an amide, the peptide bond connects the carboxyl group of one amino acid (x) to the amino group of the subsequent amino acid (y).
A polypeptide chain is defined as a series of amino acids linked together by peptide bonds. Poly stands for numerous, while peptide stands for protein. A polypeptide chain is therefore a chain of protein or amino acid building components. Polypeptide chains are crucial because they are the building blocks of proteins.
The carboxyl group of the first amino acid, w binds with the amino group of the next amino acid, x. The carboxyl group of x binds with the amino group of the y amino acid. Thus, peptide bonds are formed between the w-x-y amino acids making them a polypeptide chain.
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a 0.692-g sample of glucose, c6h12o6, is burned in a constant volume calorimeter. the temperature rises from 21.70 °c to 25.22 °c. the calorimeter contains 575 g of water and the bomb has a heat capacity of 650 j/k. what quantity of heat is evolved per mole of glucose?
If a 0.692-g sample of glucose, c6h12o6, is burned in a constant volume calorimeter, then the amount of heat evolved per mole of glucose is 2.88 x [tex]10^{6}[/tex] J/mol
For the given reaction, the amount of heat evolved can be calculated by dividing the amount of heat evolved by the number of moles.
The formula for heat evolved is
[tex]q_{m}[/tex] = [tex]\frac{q}{n}[/tex]
Now use heat transfer equation to express q
q = [tex]mc_{w}[/tex]ΔT + [tex]c_{c}[/tex] ΔT
Where m is the mass, ΔT change of temperature and [tex]c_{w}[/tex] is the specific heat, and [tex]c_{c}[/tex] specific heat of calorimeter.
The number of moles and mass of glucose can be expressed as
n = [tex]m_{g} /MW[/tex]
We are given the following values:
m = 575 g
cw = 4.184 J/gK
ΔT = 25.33 − 21.70 = 3.63 K
[tex]c_{c}[/tex] = 650 J/K
MW = 180.156 g /mol
[tex]m_{g}[/tex] = 0.692 g
Now the solution will be
[tex]q_{m}[/tex] = q/n
m[tex]c_{w}[/tex]ΔT + [tex]c_{c}[/tex]ΔT/ [tex]\frac{m}{MW}[/tex]
[tex]q_{m}[/tex] = (575 g) (4.164 J/g ∘C) (3.63K) + (650 J/K)(3.63K)/[tex]\frac{0.692g}{180.56 g/mol}[/tex]
[tex]q_{m}[/tex] = 2.88 x [tex]10^{6}[/tex] J/mol
Thus the quantity of heat evolved per mole of glucose is 2.88 x [tex]10^{6}[/tex] J/mol
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True or False
1. An atom has no weight.
2An electron is the heaviest part of an atom
. 3. All protons weigh the same.
4.All atoms weigh the same.
5. All neutrons weigh the same.
6. An oxygen atom can weigh the same as a nitrogen atom
7.All oxygen atoms weigh the same.
8. To find the mass of an atom, we add the neutrons and electrons The atomic mass of Calcium is 40.08.
9.The rounded off mass is 41.
10Isotopes are atoms of the same element that have a different number of protons.
1. False, 2. True, 3. True, 4. False, 5. True, 6. False, 7. True, 8. False, 9. Incomplete and 10. True.
1. Atoms have no weight - False
Atomic mass is the total mass of an atom. This is roughly equal to the total number of protons and neutrons with a small addition of electrons.
2. The electron is the heaviest part of the atom - in fact
3. All protons have the same mass - True
4. All atoms have the same mass - False
The mass of each element depends on the number of protons and neutrons it contains.
5. All neutrons have the same mass. - True
6. An oxygen atom weighs as much as a nitrogen atom. - False
o2 has a molecular weight of 15.9994 g/mol, and the molar mass of nitrogen is 14.0067 g/mol.
7. All oxygen atoms have the same mass - True
8. If we add neutrons and electrons to find the mass of an atom, the atomic mass of calcium is 40.08 - False
The number of protons and neutrons in an element determines its mass number. Protons and neutrons are the mass numbers.
9. The circular mass is 41, which is not quite correct.
10. Isotopes are identical atoms with differing numbers of protons. - True
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a sampple sand was found to contain 2.81 G of silicon and 3.20 gram of oxygen show that the law of Definite proportion is illustrate.
16:32=1:2 hence the Law of Multiple Proportion holds true
According to the Law of Multiple Proportion, the mass of one element that is combined with a fixed mass of the second element will always be ratios of whole numbers when two components combine to generate more than one compound.
For illustration, suppose there are two molecules of CO (carbon monoxide) and CO 2. (carbon dioxide).
CO is equal to 12g of carbon and 16g of oxygen.
CO2 is made up of 12 grams of carbon and 32 grams of oxygen.
The two compounds are 16:32=1:2 in terms of the mass of oxygen.
This establishes the law of multiple proportions.
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What is the atomic mass of hafnium if, out of every 100 atoms, 5 have a mass of 176, 19 have a mass of 177, 27 have a mass of 178, 14 have a mass of 179, and 35 have a mass of 180. 0?.
The average atomic mass of the given isotopes of Halfnium is 178.55 amu
The average atomic mass of an element is equal to the sum of its isotope masses multiplied by it's own natural abundance (the decimal associated with the percent of atoms of that element for a given isotope).
In order to determine the weighted average, we must consider the % natural abundances of each isotope. The atomic mass of an element is the weighted average of the atomic masses of the element's naturally occurring isotopes. Determine the average atomic mass by using atomic masses and percentage abundances of each isotope. To convert each percentage abundance to decimal form, divide it by 100. Multiply this figure by the atomic mass of the isotope. To get the average atomic mass, add the atomic masses of each isotope together.
To determine the average atomic mass of Halfnium, the mass fractions of the isotopes multiplied by their respected atomic masses must all be added.
Using 100 atoms as the basis, calculate the mass fractions (m1, m2,...m5):
m1 = 5/100 = 0.05
m2 = 19/100 = 0.19
m3 = 27/100 = 0.27
m4 = 14/100 = 0.14
m5 = 35/100 = 0.35
Multiplying the mass fractions with the atomic masses of the respective isotopes.
Average atomic mass of Halfnium is:
Avg = (m1 x 176) + (m2 x 177) + (m3 x 178) + (m4 x 179) + (m5 x 180)
Avg = (0.05 x 176) + (0.19 x 177) + (0.27 x 178) + (0.14 x 179) + (0.35 x 180)
Avg = 178.55 amu
Therefore, the average atomic mass of Halfnium based on the data for its given isotopes is 178.55 amu.
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compared to human cells resulting from mitosis cell division, human cells resulting from mitosis cell division would have
A. twice as many chromosomes
B. the same number of chromosomes
C. one-half the number of chromosomes
D. one-quarter as many chromosomes
Many communities in the United States get some of their power from hydroelectric dams. These dams work by blocking the path of a river to create a large lake with water held back by the dam. The dam can then be opened to allow water to cross over the dam. The energy from the water is captured and transformed into electrical energy. What type of energy does a hydroelectric dam capture as the water passes through?
Kinetic energy does a hydroelectric dam capture as the water passes through
The most common type of hydroelectric power plant is an impoundment facility and an impoundment facility is a typically a large hydropower system and the uses a dam to store river water in a reservoir and the water released from the reservoir flows through a turbine and spinning it and which in turn activates a generator to produce electricity and then there are many types of hydropower facilities through they are all powered by the kinetic energy of flowing water as it moves downstream
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Answer:
mechanical energy
Explanation:
smart answer :)
when 56.6 g of calcium is reacted with nitrogen gas, 31.0 g of calcium nitride is produced. what is the percent yield of calcium nitride for this reaction? 3ca(s) n2(g)→ca3n2(s)
Calculation of percent yield requires the theoretical yield to be calculated first. Using that method, the percent yield of the reaction is 44%.
To calculate the percent yield of calcium nitride, we first need to calculate the theoretical yield. To do this, we need the molar mass of both calcium (40 g/mol) and calcium nitride (3 * 40 + 2 * 14) g/mol = 148 g/mol.
3 moles of calcium produce 1 mol of calcium nitride so the proportion we can make will look like this:
120 g of calcium : 148 g of calcium nitride = 56.6 g of calcium : X
X = 148 g of calcium nitride * 56.6 g of calcium / 120 g of calcium
X = 69.8 g of calcium nitride
This is the theoretical yield. Calculating the percent yield works like this - we divide the actual mass by the theoretical yield and then multiply that number (that is always supposed to be between 0 and 1) by 100%:
%yield = 100% * 31.0 g / 69.8 g = 44%
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Calculate the % yield of the rection between 6.00 grams of salicylic acid and excess acetic anhydride to form 3.12 grams od Aspirin:
Answer:
You identify the limiting reactant by calculating the moles of product that can be formed from each reactant.
Explanation: Then you calculate the theoretical yield of product from the amount of the limiting reactant.
EXAMPLE Aspirin is prepared by the reaction between acetic anhydride and salicylic acid.
acetic anhydride + salicylic acid → aspirin + acetic acid
C 4 H 6 O 3 + C 7 H 7 O 3 → C 9 H 8 O 4 + C 2 H 4 O 2 m m A m l + m B m m → m l l C m l l + m l D
What is the theoretical yield of aspirin ( C ) if you reacted 4.32 g of acetic anhydride ( A ) with 2.00 g of salicylic acid ( B )?
Solution :
The molar masses are
Acetic anhydride = A = C 4 H 6 O 3 = 102.1 g/mol
Salicylic acid = B = C 7 H 6 O 3 = 138.1 g/mol
Aspirin = C = C 9 H 8 O 4 = 180.2 g/mol
Identify the limiting reactant We calculate the moles of each reactant and then use the molar ratios from the balanced equation to calculate the moles of aspirin.
Moles of aspirin from A = 4.32 g A × 1 mol A 102.1 g A × 1 mol C 1 mol A = 0.0423 mol C
Moles of aspirin from B = 2.00 g B × 1 mol B 138.1 g B × 1 mol C 1 mol B = 0.0145 mol C B gives the smaller amount of aspirin, so B is the limiting reactant.
Calculate the theoretical yield 0.0145 mol C × 180.2 g C 1 mol C = 2.61 g C
Heat can bring about chemical reactions and chemical reactions can produce heat. is this also true for light and heat? give an example to illustarte each case.
Yes, there are chemical reactions that are brought about through the use of light (such as free radical halogenation) and there are chemical reactions that produce light (chemiluminescence).
Numerous reactions use light as an initiator. For example, in various examples of free radical halogenation (a reaction between a hydrocarbon and a halogen molecule, where alkyl halides are formed), light is needed to break the bond between the bromine atoms in order to form bromine radicals that then initiate the chain reaction leading to the formation of the product.
The phenomenon of producing light through a chemical reaction is called chemiluminescence. It is relatively rare, but not unheard of. One example is the reaction between luminol and hydrogen peroxide, which forms 3-aminophthalate and releases light.
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major difference between crystallisation and evaporation to dryness
one major clear and major difference
Difference between crystallization and evaporation to dryness : crystallization is the formation of solid crystal from liquid whereas evaporation is the formation of vapor from liquid.
Crystallization is defined as the the process in which pure solid separates in the form of crystal from solution .
Evaporation to dryness is used to separate solute thermally when soluble solid does not decompose on heating. crystallization is better than evaporation to dryness because in the process of evaporation some solid in the mixture get decomposed leaving impurities. during the process of evaporation.
The major difference is that in crystallization is the formation of solid crystal from liquid whereas evaporation is the formation of vapor from liquid.
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Students will design an experiment to find out if brand X fertilizer will affect the growth of Lily
plants. Remember a fair experiment only has ONE (1) Independent Variable. In this experiment,
The independent variable as we can see from the experiment that have been described in this case is the brand of fertilizer that was used in the study.
What is an experiment?When we talk about an experiment, we are talking about the way by which the relation ship between the dependent and the independent variable could be studied. In the experiment, there is a dependent variable which would change values when the variable that is under study in the particular experiment changes value. We have to know that in the realm if science, it is only by the means of experiments that we can be able to establish cause and effect relationships.
In this case, we can see that the experiment that the students were working on has to do with trying to actually find out if brand X fertilizer will affect the growth of Lily plants. This means that they were studying the effect of a fertilizer brand on the growth of the crops.
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in the laboratory you dilute 4.59 ml of a concentrated 6.00 m hydrobromic acid solution to a total volume of 175 ml. what is the concentration of the dilute solution?
The concentration of the dilute solution when in the laboratory you dilute 4.59 ml of a concentrated 6.00 m hydrobromic acid solution to a total volume of 175 ml is 0.157 M
Now, using the formula, we get
Substituting the values, we get
M=6.00
V=4.59 mL=4.59x10^-3 L
n=6.00x(4.59x10^-3L)
n=27.54x10^-3 L
The new molarity is Mnew=n/Vnew
Mnew= 27.54x10^-3 V=175 mL=175x10^-3 L
Mnew=27.54x10^-3 mol/175x10^-3 L
Mnew=0.157 M
Molarity is the moles per liter of solution.It is the amount of a substance in a certain volume of solution.It is used to measure the concentration.To learn more about molarity visit:
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Which is NOT a transition metal?
a tin
b copper
c gold
d rhodium