how do you draw this

The calculate value of Mass flow rate = 0.00414 kg/s while the rejected heat is 1.32 Kw

We have to use the properties of the enthalpies from the pressure table

At p4 = 100 kpa

hf = 17.28 kj / kg

hfg = 217.16 kj / kg

enthalpy at the state 1

= 17.28 + 2*217.16

= 60.712 kj / kg

T1 = - 26 degrees celsius

enthalpy of vapor = 234.44 kj / kg

a. The mass flow rate

Ql = 1.2 x 600

= 720 watts

convert to Kw

= 0.72 KW

We have to find the mass flow rate

This is given as the formula

Ql  / h1 - h4

we would have

0.72 / 2344 - 60.712

Mass flow rate = 0.00414 kg/s

b. We have to find the rejection of the heat through the use of the number 1 law of thermodynamics

Qh = Ql + W

= 0.72 + 0.6

= 1.32 Kw

Hence the mass flow rate is 0.00414 and the rejected heat rate is 1.32 kW

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The thing that happens when a capacitor is connected to a DC source is that Capacitors charge up until the voltage across the capacitor is equal to the externally applied voltage when they are linked across a direct current DC supply voltage.

Capacitors slowly charge in a DC circuit until the charging voltage of the capacitor is equal to the supply voltage. The capacitor will not permit any extra charges to travel through it after it has been fully charged.

Note that the link between a capacitor and voltage and current can be summarized as follows: the capacitance and the rate of rise or fall of the voltage determine how much current flows through a capacitor. A strong positive current will be produced through a capacitor if the voltage across the capacitor rises quickly.

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This failure is usually caused by someone who does not install the U-joint in the correct orientation in the drive shaft. The front U-joint of a drive shaft must be installed so the driving torque compresses the U-joint lube fitting.

The U-joint that connects the differential and drive shaft. It may even enable two drive shafts to connect to one another in some situations when the drive shaft is connected to the transmission. Drive shafts can be moved up and down with the suspension while they are in motion thanks to universal joints, which enable power to be transferred even when the drive shaft is not in a straight line between the transmission and drive wheels. U-joints or universal joints are located at the ends of the drive shaft of rear-wheel-drive automobiles. Normally, the drive shaft has two u-joints that need to be replaced. A double-cardan joint, which consists of two u-joints, can be found on some driveshafts' front. When letting off and pressing the accelerator, in particular, a poor u-joint might make your car jolt or make a loud noise while you're driving. At certain speeds, vibration from the center or back of the car can also be caused by a damaged u-joint.

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Answer:

True

Explanation:

Ture, the indemnity protects.

Answer: The correct choice is True

The greatest moment produced by these loads  at c is 16.53 K.ft and the greatest positive shear by the load at c is 1.267 K.

A force's moment is a measurement of how likely it is to make a body rotate around a certain point or axis. This differs from a body's propensity to translate or move in the direction of the force. A body must experience the force in such a way that it starts to twist before a moment may emerge. This happens each time a force is applied so that it misses the body's centroid. When a force does not have an equal and opposing force acting immediately across its path of action, a moment results. Consider two individuals attempting to open a door at the doorknob from opposing sides. There is an equilibrium state if they are both pushing with the same amount of force. If one of them suddenly leaped back from the door, the other person's push would be met with no resistance, and the door would swing away. A pause was caused by the door-pusher who persisted in doing so.

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At f=1MHZ is the frequency gain reduced to ‐2 v/v and integer time constant is 0.079μs in op-amp based inverting integrator.

The number of waves that pass a fixed point in a unit of time is known as frequency in physics. It is also the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.  A simple harmonic motion is also seen under angular velocity. If one cycle or vibration takes half a second to complete, the frequency is two per second; if it takes a full hour, the frequency is one hundred per hour. Divide the number of times the event occurs by the amount of time to find frequency. The number of times someone blinks their eyelids in a minute, or frequency, is 47. The definition of frequency, expressed in hertz, is the number of oscillations of a wave per unit of time (Hz). The relationship between frequency and pitch is straightforward. Frequencies between 20 and 20000 Hz are audible to humans.

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The pressure exerted on hydraulic system is 1.49 lbs/in² and the force needed to raise the load is 18.75 lbs.

We need to know about pressure to solve the hydraulic system. Pressure is a unit that describes how much force is applied on a surface area. It can be determined as

P = F / A

where P is pressure, F is force and A is area.

In hydraulic lift piston, the pressure of both pistons will same

P1 = P2

From the question above, we know that

r1 = 8 in

r2 = 2 in

F1 = 300 lbs

Calculate the pressure exerted on the large piston

P1 = F1/A1

P1 = 300 / (πr1²)

P1 = 300/ (π. 8²)

P1 = 1.49 lbs/in²

Calculate the force needed

P1 = P2

1.49 = F2 / (πr1²)

1.49 = F2 / (π2²)

F2 =  18.75 lbs

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Answer:

Explanation:

code in the curly braces is treated as regular body and will be executed normally

Answer: the type of battery, refrigerator.

Explanation: The battery since the first and second generation ones overheat more and do not have too much electricity, causing it to turn off faster than the current ones.

The refrigerator that is the little avaniquito that is inside the computer with the function of refrigerating and refreshing the battery and the components avoiding overheating and making the batteries last longer.

There is a lot of information on the Internet today, with billions of web pages available. Search engines make it easy to discover this information. Let's go through the fundamentals of utilizing a search engine, as well as some troubleshooting tips for getting better search results.

1. Keywords - Create a list of keywords that characterize your topic; these will serve as your search phrases.

Key terms here might include wind, power, Iran, and electricity.

2. Use quotation marks around specific terms, such as "wind power," to find online sites that include that phrase. There will be fewer sites than if we searched individually for wind and power.

3. Boolean searching: To refine your search, use + and -.

"wind energy" +Iran"wind energy" AND "Iran"

To include all terms, use + or AND.

"wind power" + "jobs in Iran" "wind energy" AND "Iran" NOT WORK

To eliminate terms you don't want, use - or NOT.

It is to be noted that one must not use a space between the + and - signs and the search phrase, for example, -jobs rather than -jobs.

4. Advanced search function

To limit your search by date, country, amount, language, or other criteria, click the Advanced Search option at the bottom of the Search engine's start or results page.

5. Internet Explorer History

It's convenient to discover web pages you've already utilized or discarded.

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The reason for more risk and sensitivity to swings in the capital cycle with real estate is that there is increased leverage in real estate,  illiquidity, the changes in terms of local markets, as well as the need for a helping hand from expert.

Risk is said to be anything that makes the projected or actual returns on a property or portfolio volatile in the context of commercial real estate investing.

Therefore, note that most shrewd investors not only evaluate their profits but also they do carry out cash flow estimates as well as efficiently manage any form of risk.

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The ratio of the force being applied divided by the unit area that causes the material to extend or stretch.

The opposite of compression, which tends to shorten a material, is tensile load, which tends to lengthen a material. Tensile stress is another name for tensile load. One of the main categories or types of load cells frequently seen in the weighing business is a tension load cell. Other varieties include single-point, compression, and beam, for instance. As their name implies, tension load cells are typically employed to measure tension or pulling force. A force that stretches anything is tension. A force that squeezes things together is called compression. Only materials that can withstand forces are helpful.

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The center of gravity that has been calculated in the question that we have here is given as 0.1594

We have the following data to answer the questions with

r = 0.5 m,

d=0.04 m,

L=4.5 m

γ = 14 kN/m

γ=77kN/m.

v1 = 4/3πr³

= 4 / 3 * π * 0.5³

= 0.5236

v2 = π / 4 d² L

= π / 4 * 0.04² * 4.5

= 0.7857 * 0.0016 * 4.5

= 0.005857 m³

y1v1 = 14 x 0.5236

= 7.3304 kN

y2v2 = 77 x 0.005857

= 0.45098

center of gravity

= 7.3304 x 0+ 0.45098 (0.5 + 4.5/2) ÷ 7.3304 + 0.45098

= 1.2402 / 7.78138

= 0.1594

This is the term that is used to represent the point in physics that is the point that refers tp where the average location of objects would have to appear. It can simply be referred to as the point of balance of all objects where their masses are said to be located.

The calculated center of gravity is given as 0.1594

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For applications involving fire resistance and the insulation of high-temperature pipelines and machinery, calcium silicate (CalSil) is employed. Prefabricated block, preformed pipe, and board are the three distinct ways it is produced and offered for sale.

Calcium silicate's insulating properties are due to the millions of microscopic air holes that are separated by crystalline walls with low thermal conductivity. It is a good high-temperature insulation material since very little infrared radiation may flow through it. To achieve fire endurance, calcium silicate, often known as "calsil," is used to insulate high temperature pipes and equipment. Prefabricated block, preformed pipe, and board are the three distinct ways it is produced and offered for sale. Table salt and other foods are prepared with calcium silicate as an anti-caking agent and as an antacid.

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Class A IP addresses have a default mask of 255.0.0.0 (or /8 in CIDR), and their ranges are 1.0.0.0 to 127.255.255.255. Accordingly, Class A addressing may support a maximum of 128 (27) networks with a total of 16,777,214 (224-2) useable addresses per network.

510 host IP addresses are available, which is 512 minus 2. This would surely work for a network of 20 users today and 300 hosts in the future. With that knowledge, we can conclude that the network's most effective subnet mask is 255.255.254.0. Number of total subnets: The value 248 (11111000) of the subnet mask 255.255.255.248 shows that 5 bits are utilized to identify the network.

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Split-phase motors are induction motors used in applications that operate in the fractional horsepower range, such as fans and compressors in capillary tube systems.

Another name for the split phase motor is the resistance start motor. It contains a single cage rotor and two windings in its stator, referred to as the main winding and starting winding. The positions of both windings differ by 90 degrees. The starting winding has a high inductive reactance and a very low resistance, while the main winding has a high resistance and a low inductive reactance. With the auxiliary winding, a resistor is connected in series. The two windings' respective currents are not equal, and as a result, the rotating field is not even. As a result, the beginning torque is low, typically 1.5 to 2 times the reported running torque. Both windings are parallel connected when the motor first starts.

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Answer:

Let's flip the equations about the equal sign so what we have in the first equation is the sum of forces in the x-direction is equal to the mass times the acceleration.

The reinforcement must be stored in such a manner as to prevent: deterioration and corrosion.

Concrete reinforcement is accomplished by inserting deformed steel bars or welded wire fabric inside newly cast concrete. The goal of reinforcing is to give strength to concrete where it is required.

All exposed reinforcing surfaces should be carefully cleaned of loose mortar, corrosion, and other pollutants. To prevent overbuilding and limit bond development loss at rebar deformations, the high-performance protective coating should be placed at a thickness of 305 microns.

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Full Question:

What are the words that complete the sentence below:

The reinforcement must be stored in such a manner as to prevent:

This prompt is about Prince George's Wood Innovation Design Center. The building was erected as a model to highlight the possibilities of wood innovation and a departure from conventional concrete and steel architecture and building engineering models.

The Wood Innovation Design Centre (WIDC) is a meeting space for researchers, educators, and design professionals who are brainstorming new ways to use wood. The bottom floors of the building are dedicated to Integrated Wood Design instruction.

The Wood Innovation and Design Centre is located in Prince George, British Columbia. Michael Green Architecture ("Wood Innovation and Design Centre" n.p.) designed the 97-foot-tall, eight-story (six-story includes mezzanine and penthouse) structure.

The building's sleek, contemporary box shape is purposefully simple. Its simplicity serves as a canvas for the beauty of the numerous kinds of wood and their features, which include Douglas-fir, western red cedar, hemlock, pine, and spruce from British Columbia's sustainable forests.

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The heat generated within the wire is 1.05 x 10¹⁰ W/m³ with a maximum temperature of  589.5 K.

Heat is the energy that has a correlation with the resistivity of the material. Resistivity depends on the resistance and wire dimension where the resistance of the material can be written as

R = ρ.L/A

where R is resistance, ρ is resistivity, L is the length of the wire and A is surface area.

The given parameters from this question are

σ = 14 W/m.K

ρ = 45 x 10¯⁸ Ωm

I = 120 A

d = 1 mm

r = 0.5 mm = 5 x 10¯⁴ m

Calculate the surface area

A = πr²

A = π(5 x 10¯⁴)²

A = 7.86 x 10¯⁷ m²

In 1 m³, the length of wire should be

V = A . L

1 = 7.86 x 10¯⁷ . L

L = 1272727.273 m

Find the resistance of wire per m³

R/V = ρ.L/A

R/V = 45 x 10¯⁸ . 1272727.273 / 7.86 x 10¯⁷

R/V = 728925.62 Ω/m³

Find the heat generated per m³ by using power

P/V = I² . R

P/V = 120² . 728925.62

P/V = 1.05 x 10¹⁰ W/m³

Find the heat generated per m by using power

P/L = P/V

P/L = P/V . A

P/L = 1.05 x 10¹⁰ . 7.86 x 10¯⁷

P/L = 8253 W/m

Find the maximum temperature

T = (P/L) / σ

T = 8253 / 14

T = 589.5 K

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The groove has been machined a fully corrected endurance limit is = 1.792. Simply maintain all stress amplitudes below the fatigue limit if you wish to design for unlimited life, as was previously suggested.

Life will continue to exist indefinitely as long as even the highest stress amplitude is below the exhaustion limit. The "infinite life" zone for ferrous materials is bounded by a "endurance limit." The endurance limit of a material is a specified stress level below which fatigue damage from stress cycles will not be accumulated.

Given that D=2.1, d(diameter)=1.892, and r=0.17

The material's maximum endurance is 60 kpsi.

Using the Goodman relation, nf equals 0.833.

Safety factor yielding equation: ny= Sy/max= 66/36.828 ny= 1.792

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Given that the rod is initially in an unstressed state, finding the compressive force that is created in ABC as the temperature rises by 55°C yields a value of 156.902 kN.

Portion AB's size is 7.0695 X 10⁴ m².

BC portion's size is 1.96373 X 10³ meters.

505.725 X 106m for free thermal expansion is equal to (0.25)(11.7 X 106)(55) + (0.3)(20.9 X 106)(55).

Induced compressive force-induced shortening P= = 1.7682 X 10⁹ P + 1.455 10⁹ P = 3.2232 X 10⁹ P

3.2232 X 10⁹P = 505.725 X 10⁶ P = 156.902 X 103 N = 156.902 kN with zero net deflection.

As a result, ABC is subjected to a compressive force of 156.902 kN.

An action that seeks to preserve, modify, or deform a body's motion is called applying force.

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The absolute permeability of the soil is 5.1016*10^{-6} cm^{2}

The absolute permeability of the soil is calculate using the formula:

Absolute permeability=(Hydraulic conductivity*Viscosity of water)/Density of water

Hydraulic conductivity=0.56

Density of water=1

Viscosity of water=[tex]0.0911*10^{-4}[/tex]

We are now finding absolute permeability:

Absolute permeability=(0.56*0.0911^-4)/1

Absolute permeability=[tex]5.1016*10^{-6} cm^{2}[/tex]

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The maximum negative moment at E is -22500lb-ft

The maximum positive shear at E is 4750lb

Given the following:

Dead load=500

Single concentrated force=5k

Part a

Maximum negative moment at E

To get maximum negative moment at E, place the point load at B:

Moment=(1/2*4.5*18*500)-(1/2*4.5*18*500)-(5000*4.5)

               =20250-20250-22500

                =-22500lb-ft

Part b

Maximum positive shear at e

To get maximum positive shear at E, place the vertical load either B or right of E:

Shear=(1/2*0.5*18*500)-(1/2*0.5*9*500)+(1/2*0.5*9*500)+(5000*0.5)

           =2250-1125+1125+2500

            =2250+2500

             =4750

Shear at E=4750lb

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The compressive stress of the test specimen is  2.22k x 10¯⁵ N/inch².

We need to know about compressive stress to solve this problem. The compressive stress to solve this problem. The compressive stress is the force applied per unit area. It can be written as

σ = k . x / A

where σ is compressive stress, F is force and A is surface, k is the force constant as (N/inch) and x is displacement.

From the question above, we know that

A = 6 . 9 = 54 inch²

x = 0.0012 inch

By substituting the given parameters, we get

σ = k . x / A

σ = k . 0.0012 / 54

σ = 2.22k x 10¯⁵ N/inch²

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The load-carrying capacity of a system above and above what the system actually supports is a safety factor. Ultimate Load (Strength)/Allowable Load = Factor of Safety (Stress).

All structures, including bridges, buildings, safety gear, and fall protection, begin with a factor of safety. The safety factor, defined simply, is how much more robust a system is than necessary. In mechanical engineering, the ratio of material strength to allowed stress is known numerically as the factor of safety. For instance, let's say that a shaft needs to be able to support a 100 kg load. However, if our shaft is built to support a 200 kg load. The value of the Shaft safety factor is "two." When a structure or component has a FoS of 1, it signifies that it will fail exactly at the design load and cannot support any additional load.

The complete question is- The steel pipe is supported on the circular base plate and concrete pedestal. The applied force is 500 KN and the normal failure stresses for steel and concrete. The thickness of the pipe is t = 5 mm and the base plate has a radius of 150 mm. a) Determine the factor of safety against failure of the steel. b) Determine the factor of safety against failure of the concrete.

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When an object is subjected to a force such that the force's direction of action passes via the object's center of gravity or a fixed axis of rotation.

Only linear motion is caused by central force. In the straight section of the tracks, it is a force that affects a bobsleigh54. Eccentric force is an outside force57 whose vector line does not pass through the body's center of gravity. Eccentric force alters both rotary and linear motion. Torque, often known as a moment of force, is the turning result of an eccentric force. The product of the force's magnitude and the angle between its direction and the rotational axis determines the torque about any given point.

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The cutting blade's bevel angle on a pair of snips typically measures is option A. 90 degrees.

These are said to be left- or right-cutting forged steel snips have 90-degree-angled jaws for that of convenient grasping while cutting sheet metal overhead or in a place that is said to be a constricted locations.

Therefore, note that a pair snips is said to be a little pair of shears that is known to be used for cutting sheet metal.

Hence, based on the above, option A is correct.

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It is important to keep welders properly tuned because it "Reduces air pollution" (Option A).

Welding machinery, welding guns, and welders are among the most important items for a welding expert to have. Welding machines provide heat that melts steel pieces, allowing them to be bonded.

Most welders also use an angle grinder to smooth out joints, wire brushes to clean or abrade steel surfaces before welding etc.

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Full Question:

Why is it important to keep portable welders properly tuned?

a-Reduce air pollution

b-So they run quieter

c-To produce smoother welding current

d-All of the above