How do you find torque with force and distance?

Answers

Answer 1

Torque =   force x distance from point of rotation

Torque is a measure of the turning effect of an applied force about a specific point or axis. It is calculated by multiplying the force applied to an object by the distance from the point of rotation to the point where the force is applied. The greater the force or the longer the distance from the point of rotation, the greater the torque. The unit of torque is typically Newton-meters (N·m) in the International System of Units (SI) or pound-feet (lb·ft) in the imperial system. Torque is essential in various fields such as physics, mechanics, engineering and robotics.

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Related Questions

Is there any difference between antimatter, dark matter, dark energy, and degenerate matter?

Answers

Yes. Antimatter, dark matter, dark energy, and degenerate matter are all distinct entities that actually exist in our universe, despite their names sounding hazy and almost fictitious.

Is there a distinction between dark energy and dark matter?

Dark energy and dark matter are not the same, despite the name. The only difference is that both are invisible. Galaxies are pushed apart by dark energy, while dark matter holds them together.

Which of the three kinds of dark matter exists?

Candidates for dark matter can be either baryonic or non-baryonic, or a combination of the two. Most of the time, the non-baryonic forms fall into two categories: Hot Dark Matter (HDM) and Cold Dark Matter (CDM).

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two students are sitting next to each other on chairs with wheels. They push each other and separate in opposite directions. The student with a mass of 48 kg moves to the left with a velocity of 1.8 m/s. How fast and in what direction does the other student with a 59-kg mass move?

Answers

The student with a 59-kg mass moves to the right with a velocity of 1.46 m/s.

What is law of conservation of momentum?

According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced.

The student with a mass of 48 kg moves to the left with a velocity of 1.8 m/s.

Let the student with a mass of 59 kg moves to the left with a velocity of v m/s.

As no external force applied,

48 kg × 1.8 m/s + 59 kg × v = 0

v = - 1.8 × (48/59) m/s

= - 1.46 m/s.

Hence, the velocity of the second bay is 1.46 m/s in right direct.

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Two springs have spring constants of 10.0 N/cm and 15.0 N/cm. Which spring is more difficult to stretch

Answers

The spring with the higher spring constant (15.0 N/cm) will be more difficult to stretch than the spring with the lower spring constant (10.0 N/cm).

This is because the spring constant is directly related to the amount of force required to stretch the spring. Therefore, the higher the spring constant, the more force that is required to stretch the spring.

The spring constant is a measure of how difficult it is to stretch or compress a spring. It is determined by the stiffness of the spring material, its shape and size, and how much the spring is compressed or stretched.

The higher the spring constant, the more force is required to stretch or compress the spring. The lower the spring constant, the less force is required to stretch or compress the spring.

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In the above situation, what is the net torque on wire 2 due to wire 1?
a. Up b. Down
c. Into the screen d. Out of the screen e. Zero

Answers

In the above situation the net torque on wire 2 due to wire 1 is Zero.

Which way is the force acting on the wire?

Fleming's left-hand rule identifies the force's direction on a current-carrying wire when it is placed in a magnetic field. It always runs counter to how the magnetic field and electric current are moving.

Directional torque: what is it?

Torque is a vector quantity by definition. The direction is determined as part of the torque computation. The direction is parallel to both the force and the radius from the axis. It is customary to choose it along the rotational axis in the right-hand rule direction.

When rotating clockwise, is torque negative?

a force that is applied that results in a positive counterclockwise torque A negative torque rotates an object in a clockwise direction.

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When charging by induction using grounding, if a negative rod is used, the object will acquire a ______ charge

Answers

When a positively charged rod becomes grounded it becomes neutral. The electrons come from the ground to your hand, then from your hand to the rod making the rod become neutral.

What is happening when a negatively charged rod becomes grounded?

Both of the charged objects receive the same kind of charge when charging through conduction. Both things acquire a negative charge when a negative object is used to charge a neutral object.

The neutral sphere needs electrons from the negatively charged rod in order to become negative. 3. To demonstrate how charging by contact works, we'll first look at the scenario of charging a neutral needle electroscope with a negatively charged metal spherical.

Understanding the process necessitates an understanding of how like charges resist one another and have a strong desire to spread out as widely as possible in order to lessen their repulsions. The extra electrons in a negatively charged metal sphere repel one another and move as far apart from one another as possible.

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When charging by induction using grounding, if a negative rod is used, the object will acquire a  positive charge.

What is charging by induction?A charging technique called induction charging involves charging a thing without actually contacting it to another charged object. The charged particle is held close to an uncharged substance which is conductive  also, that is grounded on a neutrally charged material during the charging by induction process.This method of charging involves using a charged object to help a neutral object become charged without actually touching the objects. The neutral or uncharged conductor, which is grounded on a neutrally charged substance, is brought closer to the charged particle. If a charge is transferred between two objects, an oppositely polarized charge will emerge in the uncharged conducting material.

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. Two spherical objects have masses of 8,000 kg and 5.0 kg. Their centers are separated by a distance
of 1.5 m. Find the gravitational attraction between them.

Answers

Two spherical objects have masses of 8000 KG and 1500 KG their centers are separated by a distance of 1.5 M, the gravitational attraction between them is 3.56 × 10⁻⁴N.

How does gravitational force work?

The gravitational force, also known as gravity, pulls objects with mass in the same direction. We frequently think about the Earth's gravitational pull. This force is firmly holding your body in place. But every mass-bearing object attracts other mass-bearing objects toward it through gravity.

Using the formula of gravitational attraction

F = G× M₁M₂/d²

where G = 6.67 × 10⁻¹¹ Nm²Kg⁻²

M₁ = 8000Kg

M₂ = 1500 Kg

F =  6.67 × 10⁻¹¹ × 8000 × 1500 / (1.5)²

F = 3.56 × 10⁻⁴ N

The gravitational force of attraction between them is 3.56 × 10⁻⁴ N.

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A 74 kg student, starting from rest, slides down an 11.8 meter high water slide. What is his kinetic energy at the bottom of the slide

Answers

The kinetic energy of the student at the bottom of the slide with a velocity of 15.21 m/s is 8,557.36 J

The mass of the student = 74 kg

The distance of the slide = 11.8 m

The final velocity at the bottom of the slide can be found using

             v² = u² + 2ax

where v is the final velocity

          u is the initial velocity

          a is the acceleration due to gravity

          x is the distance

Let us substitute the known values,

            v² = 0 + 2 x 9.8 x 11.8

            v² = 231.28

                = √231.28

             v = 15.21

Therefore, the kinetic energy at the bottom of the slide is

         K.E = 1/2mv²

                = 1/2 x 74 x 231.28

                = 8,557.36 J

The kinetic energy of the student is 8,557.36 J

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A baseball bat strikes a ball resting on a tee with a force with a magnitude of 2. 0x10^4 newtons. If the bat stays in contact with the ball for a distance of 5. 0x10^-3 meter, what kinetic energy will the ball acquire from the bat?

Answers

The kinetic energy will the ball acquire from the bat is 1.0x10^1 joules or 100 joules. This calculation is based on the equation Energy = Force x Distance, which is a fundamental equation of physics.

The kinetic energy of the ball is equal to the work done by the bat on the ball. The work done by the bat on the ball is equal to the force applied by the bat multiplied by the distance the bat stays in contact with the ball. Therefore, the kinetic energy of the ball would be equal to 2.0x10^4 newtons multiplied by 5.0x10^-3 meters, which is equal to 1.0x10^1 joules or 100 joules.

This calculation is based on the equation of  Energy which is  Force x Distance. Additionally, this equation can be rearranged to solve for any of the variables, depending on what is known and what needs to be calculated. In this case, the known variables were the force applied by the bat and the distance the bat stayed in contact with the ball, and the variable that needed to be calculated as the kinetic energy of the ball.

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What is the intensity of 60 dB sound?

Answers

The intensity of 60 dB sound is 10⁻⁶ W/m².

A common conversation between two persons seated at a distance of around one meter (3 14 feet) is as loud as 60 dB. It is equivalent to the typical noise level in a restaurant or office.

The decibel scale is a logarithmic one rather than a linear one. Accordingly, 10 dB denotes a sound that is 10 times louder than 0 dB, which represents no sound at all. Now, a sound at 20 decibels is 100 times louder than one at 0 decibels. And so on until a sound that is 100 decibels is 1 billion times louder than total silence (0 decibels).

A sound at 60 dB is therefore 100 times louder than a sound at 40 decibels and 1000 times louder than a sound at 30 decibels, while being 10 times louder than a sound at 50 decibels.

The formula for sound volume is L = log(I/I₀), or (I/I₀) = 10^L.

Given that L = 60dB = 6bel and that we know that I₀ = 10⁻¹² W/m²,

I/I₀ = 10⁶.

or I = 10⁻¹² × 10⁶ = 10⁻⁶ W/m²

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The sum of kinetic energy and potential energy
of the particles in a material is blank

Answers

The sum of kinetic energy and potential energy of the particles in a material is known as mechanical energy.

What is Kinetic energy?

The energy that an object has as a result of motion is known as kinetic energy. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

What is potential energy?

Due to its position, an object has the ability to store energy. For instance, when a demolition machine's heavy ball is held in an elevated position, it is storing energy. Potential energy is the name for this positional energy that has been stored. Similar to how a drawn bow can store energy due to its posture, There is no energy in the bow while it is in its normal position, or when not drawn. The bow can yet store energy when its position is changed from its normal equilibrium position because of its position. Potential energy is the name for this positional energy that has been stored. Potential energy is the energy of position that a thing has stored inside it.

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01) When operating a simple machine an effort of 60N is used to lift the load of 240 N. Find the mechanical advantage.

02) When operating the same machine the effort arm moves 4m while load moves 1m. Find velocity ratio

03) In the same machine find work input.

04) In the same machine find work output.

05) Find the efficiency of this simple machine.

Useless answers will be reported!

Answers

Answer:

1 MA= load/effort

MA= 240/60

MA=4

2.VR=Distance moved by effort/ Distance moved by Load

VR=4/1

= 4

5. Efficiency= MA/VR

4/4*100/1

=100%

Please help! 50 points.

A student conducts an experiment to test how the temperature affects the amount of salt that can dissolve in water. In the experiment, she uses 150 milliliters of water in each trial and stirs for five minutes each time.

What is the dependent variable in this experiment?

the temperature of the water

the amount of water

the amount of salt

the time stirred

Answers

Answer:

i think its time stirred, double check. i hope it helped ;)

Explanation:

A Shuttle astronaut is sent to repair a defective relay in a 600. 00- kg satellite that is traveling in space at 17 00. 0 m/s * a * w * a * y Suppose the astronaut and his Manned Maneuvering Unit ( MMU) have a mass of 400. 00 kg and travel at 17 010. 0 m/s toward the satelliteWhat is the combined velocity when the astronaut grabs hold of the satellite?

Answers

A Shuttle astronaut is sent to repair a defective relay in a 600. 00- kg satellite that is traveling in space. The combined velocity when the astronaut grabs hold of the satellite is 17,004.4 m/s.

The combined velocity of the astronaut and the satellite when the astronaut grabs hold of the satellite is the relative velocity between the two objects. The relative velocity can be calculated using the principle of conservation of momentum. The principle states that the total momentum of an isolated system remains constant if no external forces act on it.

The initial momentum of the satellite is

= (600.00 kg) * (17,000.0 m/s)

= 10,200,000 kg*m/s

The initial momentum of the astronaut and the MMU is

= (400.00 kg) * (17,010.0 m/s)

= 6,804,400 kg*m/s

The final momentum of the combined system is

= (600.00 kg + 400.00 kg) * v,

where v is the final velocity of the combined system.

The conservation of momentum equation:

=> initial momentum = final momentum

= 10,200,000 kgm/s + 6,804,400 kgm/s

= (1000 kg) * v

= v

= (10,200,000 + 6,804,400) / 1000

= v

= 17,004.4 m/s

So, the combined velocity of the astronaut and the satellite when the astronaut grabs hold of the satellite is 17,004.4 m/s.

It's important to note that the relative velocity is the same in both directions, this is a vector quantity and direction is important.

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A 3.70 -uF capacitor that is initially uncharged is connected in series with a 6.20 -kohms resistor and an emf source with E=130V negligible internal resistance.
A) Just after the circuit is completed, what is the voltage drop across the capacitor?
B) Just after the circuit is completed, what is the voltage drop across the resistor?
C) Just after the circuit is completed, what is the charge on the capacitor?
D) Just after the circuit is completed, what is the current through the resistor?
E) A long time after the circuit is completed (after many time constants) what is the voltage drop across the capacitor?
F) A long time after the circuit is completed (after many time constants) what is the voltage drop across the resistor?
G) A long time after the circuit is completed (after many time constants) what is the charge on the capacitor?
H) A long time after the circuit is completed (after many time constants) what is the current through the resistor?

Answers

A long time after the circuit is completed (after many time constants), the voltage drop across the capacitor is 104.8V, the voltage drop across the resistor is 25.2V, the charge on the capacitor is -7.5μC, and the current through the resistor is 1.6mA.

A) Just after the circuit is completed, the voltage drop across the capacitor is 0V.

B) Just after the circuit is completed, the voltage drop across the resistor is 130V.

C) Just after the circuit is completed, the charge on the capacitor is 0C.

D) Just after the circuit is completed, the current through the resistor is 20.8mA.

E) A long time after the circuit is completed (after many time constants), the voltage drop across the capacitor is 104.8V.

F) A long time after the circuit is completed (after many time constants), the voltage drop across the resistor is 25.2V.

G) A long time after the circuit is completed (after many time constants), the charge on the capacitor is -7.5μC.

H) A long time after the circuit is completed (after many time constants), the current through the resistor is 1.6mA

Just after the circuit is completed, the voltage drop across the capacitor is 0V, the voltage drop across the resistor is 130V, the charge on the capacitor is 0C, and the current through the resistor is 20.8mA. A long time after the circuit is completed (after many time constants), the voltage drop across the capacitor is 104.8V, the voltage drop across the resistor is 25.2V, the charge on the capacitor is -7.5μC, and the current through the resistor is 1.6mA.

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What does an increases in concentration do to a material?

Answers

Answer:

it will increase the frequency of collisions between the two reactants

Explanation:

mark brainliest?

There is a bell on top of a tower that is 45 meters high. The bell has a mass of 20 kg. Calculate its potential energy.

Answers

Answer:

9000 Joules

Explanation:

Potential energy = mass x acceleration due to gravity x height

mass = 20kg

acceleration due to gravity = 10m/s2

height = 45 meters

20 x 10 x 45 = 9000 Joules

A 5-ft3 rigid tank contains 5 lbm of water at 20 psia. Determine (a) the temperature, (b) the total enthalpy, and (c) the mass of each phase of water

Answers

After that, we will calculate the temperature, total enthalpy, and masses of each water phase using the steam table.

What are temps and what is its unit?

Given the water's initial mass and pressure, we can determine whether it is superheated or saturated by utilizing a steam table. On a variety of scales, including the Fahrenheit and Celsius systems, temperature is a unit that is used to denote hotness or coolness.

Heat energy will logically go from a hotter (body with a higher temperature) to a colder (body with a lower temperature) according to temperature (one at a lower temperature).

A comparison of a substance's temperature to a set of hot and cold reference values can be used to determine its temperature. The letter "T" stands for "temperature," which is denoted by the SI unit of "°C."

The three scales that are most frequently used to measure temperature are the Celsius scale, the Fahrenheit scale, and the Kelvin scale.

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A 1070-kg car starts from rest at the bottom of a drive way and has a speed of 3.00 m/s at a point where the drive way has risen a vertical height of 0.600 m. Friction and the drive force produced by the engine are the only two nonconservative forces present. Friction does -2870 J of work. How much work does the engine do

Answers

In the question the only nonconservative forces in play are friction and the engine's motive force. Work done by friction is -2870 J. The work done by the engine is 1285 J.

The work done by an engine can be determined by the change in kinetic energy of the car. The work-energy principle states that the net work done on an object is equal to its change in kinetic energy. The initial kinetic energy of the car is 0 J (at rest) and the final kinetic energy of the car is 1/2mv^2, where m is the mass of the car and v is its final speed. The work done by the engine is equal to the change in kinetic energy of the car, which is the final kinetic energy minus the initial kinetic energy.Work_engine = change in kinetic energy = (1/2)mv^2 - 0

Work_engine = (1/2)(1070)(3)^2 = 4155 J. The work done by friction is -2870 J, which is negative because it is opposing the motion of the car. The net work done by nonconservative forces is the sum of the work done by the engine and the work done by friction. Net work = Work_engine + Work_friction = 4155 J + (-2870 J) = 1285 J. Therefore, the work done by the engine is 1285 J.

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A unitormly dense, spherical
planet has a mass of 4×1026 kg, as well
as a radius of 53,000 km. It also
happens to also be hollow in the
following way shown. What is the
magnitude of the gravitational field of
the planet at the point P, in N/kg?
Round your answer to two decimal
places.

Answers

The magnitude of the gravitational field of the planet depends on its mass and distance from the object being affected by it.

What is Gravitational field?

Gravitational field is a region of space where a mass or object experiences a force of gravity. It is caused by the presence of a massive object, such as a planet or star, which exerts a gravitational pull on other objects within its vicinity. The strength of the gravitational field is determined by the mass of the object and its distance from other objects.

The gravitational field of the planet at Point P can be calculated by using the equation,

g = G*M/r2

where G is the gravitational constant (6.67 x 10-11 Nm2/kg2), M is the mass of the planet (4 x 1026 kg), and r is the distance from the center of the planet to Point P (53,000 km).

Plugging in the values,

g = (6.67 x 10-11 Nm2/kg2) x (4 x 1026 kg) / (53,000 km)2

g = (6.67 x 10-11 Nm2/kg2) x (4 x 1026 kg) / (2.8409 x 1012 m2)

g = (6.67 x 10-11 Nm2/kg2) x (14.1636 x 1015 kg)

g = 9.5 x 10-5 N/kg

Therefore, the magnitude of the gravitational field of the planet at Point P is 9.50 x 10-5 N/kg.

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How does the flux of light from an isotropic source depend on the distance r from the source?
A. r 2
B. r -2
C. r -1
D. r 1
E. r 1/2
F. none of the above

Answers

The flux of light from an isotropic source depend on the distance r from the source by  r-2.

What is isotropic source?

An isotropic source is a source of radiation or sound that emits energy in all directions equally. This type of source is usually assumed to have uniform power density in all directions, making it a simplifying assumption when analyzing a system. Examples include a point source in free space, such as a light bulb, or a sound source in a room.

The flux of light from an isotropic source (a source that radiates uniformly in all directions) decreases as the inverse square of the distance from the source. This means that the flux of light from the source decreases according to the equation F = 1/r2, where F is the flux of light, and r is the distance from the source. Therefore, the flux of light from an isotropic source decreases with the distance r from the source according to the equation F = r-2.

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20 points! I was thinking B.) Scatter plot but want to check.

A student collected data about the speed of an object over time.

Which type of graph should the student use to represent the data?

Responses

circle graph
scatterplot

histogram

bar graph

Answers

You would definitely be using a scatter plot to measure the speed of an object over time. You will never see a velocity vs time graph as anything other than that. The other options are more the type of graphs you will see in studies or statistic classes.

A worker uses a pulley (Links to an external site.) system to raise a 225 N carton 16.5 m. A force of 129 N is exerted and the rope is pulled 33.0 m. What is the IMA of the system

Answers

Answer: 1.74

Explanation: “How do you calculate the mechanical advantage of a block and tackle pulley?To calculate the mechanical advantage, we can either divide the weight of the object being lifted by the force required to lift it or we can divide the amount of rope we have to pull by the distance the object moves."If we use the rope method the mech advantage is  33.0/16.5 = 2   now if we use the forces   MA = 225/129 =1.74 <==== this is not equal to '2' as we first found due to energy being lost to friction/deformation of rope etc.              SO I would say the truemechanical advantage = 1.74  Efficiency =  1.74/2 = 87%

What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 204 km above Earth's surface

Answers

According to the question linear speed must an Earth satellite have to be in a circular orbit at an altitude of 204 km above Earth's surface is 30.682× [tex]10^{10}[/tex].

What does orbit mean?

Astronomically speaking, an orbit is the curved path—typically elliptical—that a planet, satellite, comet, etc. takes when it revolves around another celestial body as a result of gravitation.

By Newton's second law

GMm/[tex]r^{2}[/tex] m[tex]v^{2}[/tex] /r.

Since the radius of Earth is 6.37 × [tex]10^{6}[/tex] m,

the orbit radius is r=(6.37×[tex]10^{6}[/tex] m+204×[tex]10^{3}[/tex] m)=1.3×[tex]10^{3}[/tex] m.

The solution for v is

v= [tex]\sqrt{\frac{GM}{r} }[/tex]​ ​ = (6.67×[tex]10^{-11}[/tex]× 5.98×[tex]10^{24}[/tex]/1.3×[tex]10^{3}[/tex])^1/2

⇒ v= 30.682× [tex]10^{10}[/tex]

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A weight of 10 N hangs motionless from a spring. The spring is stretched 0.286 m from its original length. What is the force constant for the spring?

a-2.8 N/m

b-22 N/m

c-35 N/m

d-43 N/m

Answers

Answer:

C. -35N/m

Explanation:

Using Hooke's Law, we know that the elastic constant of a spring can be found with this formula:
[tex]F=-kx[/tex]

where:

[tex]F[/tex] is the force ( in Newtons)
[tex]k[/tex] is the constant ( in Newtons per meter)
[tex]x[/tex] is the extension ( in meters)

thus, by rearranging the formula we can get:
[tex]k=-\frac{F}{x}[/tex]

[tex]k = -\frac{10}{0.286}[/tex]

[tex]k=-34.96503N/m[/tex]

Rounding off the answer, we get -35N/m

A bicyclist maintains a constant velocity of

4. 0 m/s for a distance of 480 m. How long does it take the bicyclist to travel this distance?

A8s

B 120s C 476s D 1920s

Answers

The bicyclist will need to ride for a total time of 120 seconds in order to cover 480 meters of distance at a constant velocity of 4.0 meters per second.

In this scenario, we are provided with:

The distance of the ride is 480 meters.

The velocity is four meters per second

In order to calculate the time, we can use the following formula:

Time = Distance : Velocity

= 480 meters : 4.0 meters per second

= 120 seconds

Therefore, the amount of time a cyclist needs to travel would be 120 seconds.

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What is the equation for torque used for lever arm and F for force?

Answers

The required equation for torque used for lever arm r and F for force is given as τ = |r| |F| sinθ.

A simple way to calculate the magnitude of the torque is to first determine the lever arm and then multiply by the times of applied force.

The lever arm is described as the perpendicular distance from axis of rotation to the line of action of force.

The equation used to calculate torque is , τ = r × F = |r| |F| sinθ

where,

r is the magnitude of lever arm

F is the magnitude of force vector

θ is the angle between lever arm and force vectors

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CAN SOMEONE PLEASE ANSWER THESE 4 QUESTIONS I WILL NEED IT IN A FEW HOURS , YOU WILL GET BRAINLIEST!!

1.) Compare reflection and refraction. How are they similar and how are they different?

2.) In your own words, describe how ray diagrams can be used to describe if light rays are being reflected or refracted.

3.) What is the formula for the Law of Reflection? Define the variables and explain what it tells us about the motion of light.

4.) What is the formula for Snell's? Define the variables and explain what it tells us about the motion of light.

Answers

Answer:

1.)Reflection is the act of light reflecting back when it hits a medium on a plane. Refraction is the process by which light shifts its path as it travels through a material, causing the light to bend. Thus, this is the key difference between reflection and refraction. This phenomenon usually occurs in mirrors.

2.)ray diagrams are a visual representation of the propagation of light. They can help us to understand and visualise multiple situations, such as light being reflected off of a mirror or changing its direction while moving through a lens.

3.)Reflection: The process of sending back the light rays which fall on polished surface is called reflection of light.

Laws of reflection:

(i) The angle of reflection is always equal to the angle of incidence.

(ii) The incident rays, reflected rays and the normal, all lie in the same plane.

4.)Snell’s law formula is expressed as: μ= sin i/sin r

, where i is the angle of refraction, r is the angle of refraction and μ is known as the refractive index of the second medium with respect to the first medium.

Why do we calculate torque?

Answers

Torque is one of the key ideas to comprehend in order to solve problems with rotational motion. Torque is the tendency of a force to produce or change rotational motion.

Why is torque calculation important?

Torque is a measure of an engine's capacity to control a load and generate a certain level of power to turn the engine on its axis. which is an important part of an automobile engine's power-generating process. Per foot (ft) of rotation about a single point, the force is expressed in pounds (lb).

Why does the torque exist?

The force that can cause an object to revolve around an axis is measured in torque. In linear kinematics, force causes an item to accelerate, and torque causes an object to produces the angular acceleration of an object. A vector quantity is a torque.

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Dina is observing a sample of copper metal after it was removed from a flame. She noticed that the temperature decreased. What conclusions could she draw from this observation?

a-The average kinetic energy decreased.

b-The average kinetic energy remained the same.

c-The motion of the particles increased.

d-The motion of the particles stayed the same.

Answers

Answer:

A. The average kinetic energy decreased.

Explanation:

When an object gains heat, which is a form of energy, the atoms within the object would in turn gain energy in the form of kinetic energy. Similarly, as the temperature of an object decreases, in other words losing heat energy, the atoms within the object would lose kinetic energy as a result.

replace the force system acting on the post by a resultant force and couple moment at point o

Answers

By replacing the force system acting on the post with a resultant force and a couple of moments at point o we get total momentum of 1478.85 ft-lb.

As per the figure we have 3 forces: At the top 300lb left side 150lnb and at the middle 200lb.

first, we have to break down the forces into x and y components.

Now calculating each force separately:

∑Fₓ=300lb+cos 30°-150×4/3+200

=259.81-120+200

∑Fₓ=339.81lb.

Now, calculate the sum of y components.

∑Fy=300 sin 30°+150×3/5

∑Fy=300 sin 30°+90

∑Fy=240lb

Now we have to x and y components by these values we can find the actual force.

|F|=√Fx²+Fy²

|F|=√(339.81)²+(240)²                     α=tan⁻¹(∑Fₓ/∑Fy)

|F|=√115470.83+57600                      α=tan⁻¹(339.81/240)

|F|=√173070                                       α=35.23°

|F|=416.02 and 35.23°

the sum of moments at O

∑Mo=-Fx₃×2+Fx₂×4-Fx₁×6

∑Mo=-200(2)+4/5 150*4-3000cos30°(6)

∑Mo=-400+480-277.65

         =1478.85ftlb

∑Mo=1478.85ftlb

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