The ordered pairs are a linear equation if the graph plotted is the straight line.
A linear equation can be represented by a graph in the Cartesian coordinate system as a straight line. If the equation is in the form of "y = mx + b" where m and b are constants, it is a linear equation. The ordered pairs of a linear equation will always satisfy this equation, and when plotted on a graph, will fall on a straight line. To check if a set of ordered pairs is a linear equation, you can plot them on a graph and see if they form a straight line or can substitute the x- and y-values of the ordered pairs into the equation "y = mx + b" and see if they make the equation true.
So, if the graph plotted is the straight line, then the ordered pairs are of a linear equation.
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The scale drawing of a building has a height of 10 centimeters. The actual building is 20 feet high. How many centimeters in the scale drawing represent one foot on the actual building?
a. 1/2
b. 30
c. 10
d. 2
Answer: 1/2
Step-by-step explanation:
The question is asking you to find how many centimeters in the scale drawing equal 1 foot on the actual building. The answer will be 1/2 because 1 centimeter is equal to 2 feet in reality. But since we want to know the answer of how many centimeters is in 1 foot, we will divide that in half, to get an answer of 1/2 centimeter, or A.
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What is the reflection point of (- 3/4 across the line y 2?
According to the following graph, the reflection point of (-3,4) across the line y = 2 is (-3,0).
The term reflection point in math is defined as
Here we need to find the reflection point of (-3, 4) across the line y = 2.
Here first we have t plot the point on the graph, and then we have to plot the line equation y = 2 on the graph,
Here in order to find the reflection of a point along the x-axis, then we have to keep the abscissa constant and see the reflection of ordinate along the x-axis.
Based on these rule, the resulting graph is obtained as follows.
Through the graph we have identified that the resulting reflection point is (-3,0).
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0.2(x+50)-6=0.4(3x+20)
Answer:
2
Step-by-step explanation:
0.2(x+50)-6=0.4(3x+20) multiply both sides by 10 to clear the decimals
2(x + 50) = 4(3x + 20) distribute across the terms in the parentheses
2x + 100 = 12x + 80 subtract 80, 2x from both sides
20 = 10x divide both sides by 10
x=2
In the diagram, two circles, each with center $D$, have radii of $1$ and $2$. The total area of the shaded region is $\frac5{12}$ of the area of the larger circle. How many degrees are in the measure of (the smaller) $\angle ADC$
Angle ADC = 120 degrees.
What is area of sector?A certain portion of a circle that is created based on two radius of the same circle and one arc. Area of sector for a circle with radius r is given by π r²Ф/ 360°
What is the angle of ADC in the smaller circle?
Given, two circles of radius 1 unit and 2 unit which have same center D.
We know area of a circle = π r²
Area of larger circle = π 2² = 4π
it is said that the total area of the shaded region that means area of a particular sector is 1/12 of the area of the larger circle.
area of sector, ACD = 1/12 ×4π
as per the question, the ACD sector is located in the smaller circle that has radius 1 unit.
formula for area of sector ACD = π r² ×Ф/360°
where,Фis the central angle of ACD sector
and Ф = ADC
from the above statement, 4π/12 = π r² ADC/360
ADC = 1/3×360°
ADC = 120 degrees
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What is step 3 in problem solving?
Step 3 is Define the problem Goals.
there are 8 steps, which are as follows,
1- Define the Problem
2- Clarification of the Problem
3- Define the problem Goals
4- Identify main Cause of the Problem
5- Develop a Action Plan
6- Execute that Action Plan
7- Analyze the Results
8- Continuous Improvements
Problem solving
Problem solving is the method of determining the problem and then clarify the doubts and prepare a action plan and then execute the action plan and find out the desired results and if the results are not appropriate then improve the action plan and your way of doing until you get the desired results.
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Who can solve these equations?
let's hmmm hmmm multiply both sides by the LCD of all denominators, that way we do away with the denominators and see what "x" is
[tex]\cfrac{x+1}{2}+\cfrac{x+2}{3}=3-\cfrac{x+3}{4}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{12}}{12\left( \cfrac{x+1}{2}+\cfrac{x+2}{3} \right)=12\left( 3-\cfrac{x+3}{4} \right)} \\\\\\ (6x+6)+(4x+8)=36-(3x+9)\implies 10x+14=36-3x-9 \\\\\\ 10x+14=27-3x\implies 10x=13-3x\implies 13x=13 \\\\\\ x=\cfrac{13}{13}\implies x=1 \\\\[-0.35em] ~\dotfill[/tex]
[tex]\cfrac{1-4x}{10}-\cfrac{2x+1}{2}=\cfrac{5x+1}{5}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{10}}{10\left( \cfrac{1-4x}{10}-\cfrac{2x+1}{2}\right)=10\left( \cfrac{5x+1}{5} \right)} \\\\\\ (1-4x)-(10x+5)=10x+2\implies 1-4x-10x-5=10x+2 \\\\\\ -14x-4=10x+2\implies -4=24x+2\implies -6=24x \\\\\\ \cfrac{-6}{24}=x\implies -\cfrac{1}{4}=x[/tex]
How do you explain irrational numbers to children?
The irrational numbers to children can be explained as the numbers that can be written as a nonrepeating or nonterminating decimal .
What are Irrational Numbers ?
The real numbers that can be represented as a nonrepeating or a nonterminating decimal but not as a fraction, and the decimal that goes on forever without repeating.
For Example : [tex]\sqrt{2} , \sqrt{5} , \sqrt{7}[/tex] are few example of irrational numbers .
In simpler words : the irrational number is a number that is not rational. which means It is a number which cannot be written as a ratio of two integers or cannot be written as fraction.
and If a fraction has a 0 in the denominator , it is an irrational number .
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What number would you need to multiply the first equation by to eliminate the y variable when solving the system of equations by elimination?
We would need to multiply the first equation by -4 to eliminate the y variable when solving the system of equations by elimination.
The first equation is: 3x + 4y = 5
To eliminate the y variable when solving the system of equations by elimination, we need to multiply the first equation by -4. This is because when two equations are multiplied by the same number, any terms that have the same variable will be eliminated when the equations are added together.
Formula:
3x + 4y = 5
-4(3x + 4y = 5)
3x + 4y = 5
-12x - 16y = -20
Thus, we would need to multiply the first equation by -4 to eliminate the y variable when solving the system of equations by elimination.
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what are the properties of rational exponents and how are they used to solve problems
The properties of the rational exponents are given and a rational equation is of the form b = aˣ
What are the laws of exponents?When you raise a quotient to a power you raise both the numerator and the denominator to the power. When you raise a number to a zero power you'll always get 1. Negative exponents are the reciprocals of the positive exponents.
The different Laws of exponents are:
mᵃ×mᵇ = mᵃ⁺ᵇ
mᵃ / mᵇ = mᵃ⁻ᵇ
( mᵃ )ᵇ = mᵃᵇ
mᵃ / nᵃ = ( m / n )ᵃ
m⁰ = 1
m⁻ᵃ = ( 1 / mᵃ )
Given data ,
Let the rational exponent equation be A
Now , the properties of the exponent equations are
mᵃ×mᵇ = mᵃ⁺ᵇ
The powers of the exponents are added together
mᵃ / mᵇ = mᵃ⁻ᵇ
The powers of the exponents are subtracted together
( mᵃ )ᵇ = mᵃᵇ
The powers of the exponents are multiplied together
mᵃ / nᵃ = ( m / n )ᵃ
m⁰ = 1
Any number raised to the power of 0 is 1
m⁻ᵃ = ( 1 / mᵃ )
Hence , the exponents are solved
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How do you plot 1 3 on a graph?
By drawing a number line and then marking it as 0 and 1, and by dividing the distance in 3 equal parts we can graph 1/3 on the number line, where each part will be equal to the 1/3.
A number line is a diagram of a graded straight line used to represent real numbers in introductory mathematics. It is assumed that every point on a number line corresponds to a real number, and that every real number corresponds to a point.
A horizontal line with evenly spaced numerical increments is referred to as a number line. How the number on the line can be answered depends on the numbers present.
For drawing 1/3 on a number line, we will follow the following steps:
We will first draw a line and mark 0 and 1 on it.
In between 0 and 1, we will divide the total distance into 3 equal parts, where one part will represent (1/3)th portion.
Hence. by marking there we can locate 1/3 on the number line.
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The correct question may be like:
How do you plot 1/3 on a graph.
18 9/10 + 8 3/10 ?????.....
27 2/10
or
27 1/5
----------------------------------
There are 7 1/2 pounds of potatoes. 1/6 of the potatoes are rotten. What is the weight of good potatoes. Fraction form
Answer:
6 1/4 pounds
Step-by-step explanation:
There are 7 1/2 pounds of potatoes, which is equivalent to 7 1/2 = 7.516=120
120 ounces of potatoes.
If 1/6 of the potatoes are rotten, then 1/6*120 = 20
20 ounces of potatoes are rotten.
Thus, the weight of the good potatoes is 120-20 = 100
100 ounces.
Converting this back to pounds, we get
100/16 = 6 1/4
6 1/4 pounds.
Fill in the blank question.
Miss Wade's science class of 20 students is going on a field trip to the zoo. Each student will also take a train ride around the zoo. Mr. Sexton's class of 25 students is going on a field trip to the state park and will take a canoe trip. Admission to the zoo is twice that of the state park's entry fee as shown in the table. Each group will spend the same total amount of money.
Answer:
The total cost of the science class trip to the zoo is $1200
Step-by-step explanation:
The cost of the science class trip to the zoo is $1200, and the cost of Mr. Sexton's class trip to the state park is $1000.
How do I do this ? Because I’m having trouble with problems like this .
Answer:
[tex]\sqrt[3]{x^{9} x}[/tex]
Step-by-step explanation:
When you are multiplying powers that have the same bases (in this case x) you add the exponents. If you do not see an exponent, the exponent is 1.
9 + 1 = 10
A salesperson at a jewelry store earns 9% commission each week. Last week, sold $750
worth of jewelry. How much did make in commission? How much did the jewelry store make from sales?
The amount made in commission is $67.5.
The amount made in sales by the store is $682.5.
What is a percentage?The percentage is calculated by dividing the required value by the total value and multiplying by 100.
Example:
Required percentage value = a
total value = b
Percentage = a/b x 100
Example:
50% = 50/100 = 1/2
25% = 25/100 = 1/4
20% = 20/100 = 1/5
10% = 10/100 = 1/10
We have,
Amount sold last week = $750.
Commission = 9%
The amount of commission.
= 9/100 x 750
= $67.5
The sales made last week by the store.
= 750 - 67.5
= $682.5
Thus,
$67.5 was made in commission.
$682.5 was made from sales.
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The sun of a number, x, and 1/2 is equal to 4. What set of equations correctly repaints x
The set of equations correctly representing x are as follows:
(x + 1/2) and (x = 7/2).
What exactly is a set or group of equations?A set or group of equations that you solve all at once is referred to as a "system" of equations. The simplest linear system is one that has two equations as well as two variables. Linear equations (those that graph as straight lines) are easier to understand than non-linear ones.
What is the name of an equation system?Systems of equations in mathematics are a collection of relationships between different unknown variables that can be stated in terms of algebraic expressions. They are also known as simultaneous equations. Graphing, substitution, as well as elimination by addition, are methods that can be used to find the solutions to a basic system of equations.
According to the given information:Sum means addition (+).
Given that sum of a number, x and 1/2 is 4.
This means the adding two numbers
x+1/2=4
Now make x the subject of formula,
x=4-1/2
Finding the L.C.M = 8-1/2
x=7/2
∴ x=3 1/2
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Barrett earns $15 per hour cutting grass and $10 per hour tutoring reading. In one month, Barrett
needs to save at least $400 for a new lawnmower but does not want to work more than 35 hours.
Part A: Let x represent the hours cutting grass and y represent the hours tutoring. Given x ≥ 0 and
y ≥ 0, select all the inequalities that represent the situation.
A. x + y ≥ 35
B. 15x + 10y ≤ 400
C. x + y ≤ 35
D. 15x + 10y ≥ 400
E. 25x + 25y ≤ 400
F. 15x + 10y ≤ 35
Part B: Determine whether each point is a viable or nonviable solution according to the above scenario.
Viable Nonviable
(10, 25)
(10, 20)
(20, 12)
(35, 0)
(20, 20)
The inequalities that represent the situation are 15x + 10y ≥ 400 and x + y ≤ 35 and the viable solutions are (10, 25), (20, 12), (35, 0) and (20, 20)
The inequalities that represent the situation.From the question, we have the following parameters that can be used in our computation:
Earnings from cutting = $15Earning from tutoring = $10Number of hours = not more than 35Total earnings = At least $400These parameters above mean that
15x + 10y = Total earnings
x + y = Number of hours
So, we have
15x + 10y ≥ 400
x + y ≤ 35
The above represent the inequalities of the situation
The viable solutionsIn (a), we have
15x + 10y ≥ 400
x + y ≤ 35
Next, we test the options
(10, 25)
15 * 10 + 10 * 25 ≥ 400 ⇒ 400 ≥ 400
10 + 25 ≤ 35 ⇒ 35 ≤ 35
True
(10, 20)
15 * 10 + 10 * 20 ≥ 400 ⇒ 350 ≥ 400
10 + 20 ≤ 35 ⇒ 30 ≤ 35
False
(20, 12)
15 * 20 + 10 * 12 ≥ 400 ⇒ 420 ≥ 400
20 + 12 ≤ 35 ⇒ 32 ≤ 35
True
(35, 0)
15 * 35 + 10 * 0 ≥ 400 ⇒ 525 ≥ 400
35 + 0 ≤ 35 ⇒ 35 ≤ 35
True
(20, 20)
15 * 20 + 10 * 20 ≥ 400 ⇒ 500 ≥ 400
20 + 20 ≤ 35 ⇒ 40 ≤ 35
False
Hence, the viable solutions are (10, 25), (20, 12), (35, 0) and (20, 20)
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Solve.
7 Jordan shoots 100 3-point shots per basketball practice.
She makes 44 of these shots. What decimal represents the
number of shots she makes?
8 At a county fair, 9 people out of 1,000 earned a perfect score
in a carnival game. What decimal represents the number of
people who earned a perfect score?
Answer:
7. .44
8. .009
Step-by-step explanation:
7. 44 ÷ 100 = .44
8. 9 ÷ 1000 = .009
What are the 3 types of terms in quadratic equation?
The 3 types of terms in quadratic equation:
1) quadratic term,
2) linear term,
3) constant term.
We know that the second degree algebraic equation in x is a quadratic equation.
The standard form of quadrtic equation is ax^2 + bx + c = 0, where a, b, c are integers.
As thise is a quadratic equation, the value of a can not be zero. a ≠ 0
The term ax^2 is called the quadratic term.
From this term, the name given to the equation(quadrtic equation)
The term bx is called the linear term.
And the term c is called the constant term.
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What is the factor of 3x² 12xy?
The factor of expression 3x² 12xy is 3x². To find the factor, we need to divide 12xy by 3x². We start by dividing the coefficients, 12 divided by 3 is 4. Then we divide the x terms, x divided by x is 1. Finally, we divide the y terms, y divided by y is 1. Therefore, the factor of 3x² 12xy is 3x².
The factor of expression 3x² 12xy is 3x². To find the factor, we need to divide 12xy by 3x². We start by dividing the coefficients, 12 divided by 3 is 4. Then we divide the x terms, x divided by x is 1. This means that the x part of the factor is 3x. Next, we divide the y terms, y divided by y is 1. This means that the y part of the factor is y. When we combine the two parts, 3x and y, we get the factor of 3x². Therefore, the factor of 3x² 12xy is 3x². This means that 3x² is a factor of 12xy, which can be seen by multiplying 3x² by 4y, which results in 12xy. This shows that 3x² is a factor of 12xy.
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this diagram shows 3cm x 5 cm x 4 cm cubiod
find ac give your answer in 2 decimal place
The length AC will be 5.83 and the angle ACD will be 34.45°.
What is trigonometry?The branch of mathematics that sets up a relationship between the sides and the angles of the right-angle triangle are termed trigonometry.
The trigonometric functions, also known as a circular, angle, or goniometric functions in mathematics, are real functions that link the angle of a right-angled triangle to the ratios of its two side lengths.
The length AC will be calculated as,
AC² = 5² + 3²
AC = √ ( 25 + 9 )
AC = √34
AC = 5.83
The angle ACD will be,
tanθ = P / B
θ = tan⁻¹ = ( 4 / 5.83)
θ = 34.45°
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Can you help me with this
Answer: slope=2
Step-by-step explanation:
using y=mx+b, we know the equation of the line is y=2x. The slope is the m term so we know that the slope is 2.
Write a rule to describe each transformation.
J(2, 2), (3, 4), H(4,3), G(3,0)
to
J'(-1,2), I'(0, 4), H'(1, 3), G'(0, 0)
The only difference is a -2 in x in 1 transformation in 2 transformation. The function is shifted up by b units with f (x) + b.
what are transformations ?Transformations can be divided into four categories: translation, reflection, rotation, and dilation. Rotate, reflect, or translate the geometric figures on a coordinate plane. The label given to a function, f, that maps to itself is the transformation, or f: X X. The pre-image X is transformed into the picture X after the transformation. It is possible to utilize any operation, or a combination of operations, in this transformation, including translation, rotation, reflection, and dilation.
given
J(2, 2), (3, 4), H(4,3), G(3,0) to J'(-1,2), I'(0, 4), H'(1, 3), G'(0, 0)
in 2 transformation as the only change is that -2 in x in 1 transformation
The function is shifted up by b units with f (x) + b.
The function is shifted downward by b units when f (x) b.
The function is moved left by b units when f (x + b) is used.
The function is moved right b units by the expression f (x b).
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n^2-2n-3=0 complete the square method
Answer:
n = - 1 , n = 3
Step-by-step explanation:
n² - 2n - 3 = 0 ( add 3 to both sides )
n² - 2n = 3
to complete the square
add ( half the coefficient of the x- term)² to bpth sides
n² + 2(- 1)n + 1 = 3 + 1
(n - 1)² = 4 ( take square root of both sides )
n - 1 = ± [tex]\sqrt{4}[/tex] = ± 2 ( add 1 to both sides )
n = 1 ± 2
Then
n = 1 - 2 = - 1
n = 1 + 2 = 3
Find the gradients of lines A and B.
Answer: The Gradient of line A and B are
2 and -1
Step-by-step explanation:
For the given two points A(x1, y1) and B(x2, y2)
The gradient of the line AB is y2-y1/x2-x1
So the gradient of line A is
5-1/2-0
2
the gradient of line B is
5-0/0-5
-1
two cards are drawn from a shuffled deck of 52 cards. what is the probability that the first card is a king and the second is a heart
On solving the provided question, we can say that the required probability is = 13/204.
What is probability?Probability theory, a subfield of mathematics, gauges the likelihood of an occurrence or a claim being true. An event's probability is a number between 0 and 1, where approximately 0 indicates how unlikely the event is to occur and 1 indicates certainty. A probability is a numerical representation of the likelihood or likelihood that a particular event will occur. Alternative ways to express probabilities are as percentages from 0% to 100% or from 0 to 1. the percentage of occurrences in a complete set of equally likely possibilities that result in a certain occurrence compared to the total number of outcomes.
probability of 1st card = 1/4
since the card is not replaced
total number remaining cards = 51
second card 13/51
the required probability is = 13/204
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I need help with polynomials
Here is the equation
The solution to the polynomial is x = -1, x = 1/2 and x = -1
How to solve the polynomial expressionFrom the question, we have the following parameters that can be used in our computation:
2x³ - x² - 2x + 1
Expand
2x³ - x² - 2x + 1 = 2x³ - x² - 2x + 1
Factorize the expression
This gives
2x³ - x² - 2x + 1 = x²(2x - 1) - 1(2x - 1)
Factor out 2x - 1
2x³ - x² - 2x + 1 = (x² - 1)(2x - 1)
Express x² - 1 as difference of two squares
2x³ - x² - 2x + 1 = (x - 1)(x + 1)(2x - 1)
So, we have
(x - 1)(x + 1)(2x - 1) = 0
Solve for x
x = 1, x = -1 and x = 1/2
Reorder the solutions
x = -1, x = 1/2 and x = -1
Hence, the solution is x = -1, x = 1/2 and x = -1
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Find a basis for the eigenspace corresponding to each listed eigenvalue of A below.
A = 4 0 -1 14 5 -10 2 0 1 λ=5,2,3
A basis for the eigenspace corresponding to λ = 5 is { }. (Use a comma to separate answers as needed.) A basis for the eigenspace corresponding to λ = 2 is { }. (Use a comma to separate answers as needed.) A basis for the eigenspace corresponding to λ = 3 is . { }. (Use a comma to separate answers as needed.)
The basis for the eigenspace corresponding to lambda=5,1,4 are None,[tex]\left[\begin{array}{c}-1 \\\frac{1}{2} \\0\end{array}\right][/tex] and [tex]$\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]$[/tex]
[tex]$$A=\left[\begin{array}{ccc}5 & -12 & 10 \\0 & 7 & -3 \\0 & 6 & -2\end{array}\right]$$[/tex]
Eigenspace corresponding to lambda=5,1,4
The eigenspace E_lambda corresponding to the eigenvalue lambda is the null space of the matrix a [tex]\mathrm{A}-(\lambda) \mathrm{I}"[/tex]
for lambda=5
[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-5 \mathrm{I})$$[/tex]
Reducing the matrix A-5I by elementary row operations
[tex]$$\begin{aligned}A-5 I & =\left[\begin{array}{ccc}5-5 & -12 & 10 \\0 & 7-5 & -3 \\0 & 6 & -2-5\end{array}\right] \\& =\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 2 & -3 \\0 & 6 & -7\end{array}\right] \\& \sim\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_2 \rightarrow \frac{R_2}{2} \\& \sim\left[\begin{array}{ccc}1 & 0 & -8 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_1 \rightarrow R_1+2 R_2\end{aligned}$$[/tex]
[tex]\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 2\end{array}\right] R_3 \rightarrow R_3-6 R_2$$\\\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] R_3 \rightarrow \frac{\mathrm{R}_3}{2}$$\\\sim\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+8 \mathrm{R}_3$[/tex]
[tex]$\sim\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right] R_2 \rightarrow R_2+\frac{2 R_3}{2}$[/tex]
The solutions x of A-5I=0 satisfy x_1=x_2=x_3=0 that is, the null space solves the matrix
[tex]$$\left[\begin{array}{lll}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]
Hence The null space is [tex]\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right] E_5[/tex] has no basis
[tex]$$\begin{aligned}& \text { case: } 2 \\& \text { for } \lambda=1 \\& \mathrm{E}_5=\mathrm{N}(\mathrm{A}-(1) \mathrm{I})\end{aligned}$$[/tex]
we reduce the matrix A-I by elementary row operations as follows.
[tex]$$\begin{aligned}A-1 & =\left[\begin{array}{ccc}5-1 & -12 & 10 \\0 & 7-1 & -3 \\0 & 6 & -2-1\end{array}\right] \\& =\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 6 & -3 \\0 & 6 & -3\end{array}\right] R_1 \rightarrow \frac{R_1}{4} \\& \sim\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 1 & -\frac{1}{2} \\0 & 6 & -3\end{array}\right] R_2 \rightarrow \frac{R_2}{6}\end{aligned}[/tex]
[tex]$$$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 6 & -3\end{array}\right] R_1 \rightarrow R_1+3 R_2$\\$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right] R_3 \rightarrow R_3-6 R_2$[/tex]
Thus, the solutions x of (A-I) X=0 satisfy
[tex]$\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\ x_2 \\ x_3\end{array}\right]=\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right]$[/tex]
x_3=t
[tex]$\Rightarrow \mathrm{x}_1=-\mathrm{t}, \mathrm{x}_2=\frac{\mathrm{t}}{2}$[/tex]
[tex]$\vec{x}=\left[\begin{array}{c}-t \\ \frac{t}{2} \\ t\end{array}\right]=\left[\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right] t$[/tex]
The Basis for the nullspace A-I will be: [tex]$\left.\left(\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right]\right)$[/tex]
case:3
lambda=4
[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-(4) \mathrm{I})$$[/tex]
we reduce the matrix A-4I by elementary row operations as follows.
[tex]$\begin{aligned} A-4 \mid & =\left[\begin{array}{ccc}5-4 & -12 & 10 \\ 0 & 7-4 & -3 \\ 0 & 6 & -2-4\end{array}\right] \\ & =\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 3 & -3 \\ 0 & 6 & -6\end{array}\right] \\ & \sim\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] R_2 \rightarrow \frac{R_2}{3}\end{aligned}$[/tex]
[tex]$\begin{aligned} & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+12 \mathrm{R}_2 \\ & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 0 & 0\end{array}\right] \mathrm{R}_3 \rightarrow \mathrm{R}_3-6 \mathrm{R}_2\end{aligned}$[/tex]
Thus, the solutions x of (A-4IX)=0 satisfy
[tex]$$\left[\begin{array}{ccc}1 & 0 & -2 \\0 & 1 & -1 \\0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]
x_3=t
[tex]$\Rightarrow \mathrm{x}_1=2 \mathrm{t}, \mathrm{x}_2=\mathrm{t}$[/tex]
[tex]$$\vec{x}=\left[\begin{array}{c}2 t \\t \\t\end{array}\right]=\left[\begin{array}{l}2 \\1 \\1\end{array}\right] t$$[/tex]
The Basis for the nullspace A-4 I will be [tex]\left(\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]\right)[/tex]
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please help:
find BP
Answer:
so i will be honest I've done this before and it may be 64 or 120
Step-by-step explanation:
It may be one of these answers I'm doing as much as I can to help
What is the estimated perimeter of an ellipse if the major axis has a length of 15 ft and the minor axis has a length of 7.5 ft
The estimated perimeter of an ellipse if the major axis has a length of 15 ft and the minor axis has a length of 7.5 ft id found to be 37.3 feet .
Perimeter is calculated as
= 2*pi*r*r
= 2 *3.14 * sqrt (15/2² +7.5/2²)/2
= 6.28 x sqrt (56.25+14.0625/2 6.28) *sqrt (35.15625) 6.28 * 5.929270613
= 37.235 feat
An ellipse is the locus of all the points on a plane whose distances from two fixed points in the plane are always same. The fixed points, which are encompassed by the curve, are known as foci , singular of focus.
The constant ratio is the eccentricity of the ellipse and the fixed line is directrix. Eccentricity is an element of ellipse which denotes elongation and is symbolized by the letter 'e'.
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