Calculate the angle between the vector connecting the force's application point and the pivot point and the direction of the applied force. You may calculate the torque by multiplying r by F and sin.
How does physics explain torque?The force that can cause an object to revolve around an axis is measured in torque. Torque accelerates an object in an angular direction, much like force does in linear kinematics.
An easy explanation of torqueAn angular force known as a torque tends to produce rotation along an axis, which could be the center of mass or a fixed point. Torque can also be thought of as a thing's capacity in order to overcome turning resistance, such as a shaft or a gear, that is rotating.
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Ball A has a mass of 3 kg and moves at a velocity of 2 m/s. Ball B has a mass of 1 kg and rolls towards Ball A with a velocity of -4 m/s. After the collision, Ball A has a velocity of -1.5 m/s. What is the velocity of ball B after the collision?
Please show your work.
The velocity of ball B after the collision is 6.5 m/s.
What is law of conservation of momentum?According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced.
Before collision ,
ball A of mass of 3 kg has velocity = 2 m/s.
ball B of mass of 1 kg has velocity= -4 m/s.
After the collision,
Ball A has a velocity = -1.5 m/s.
Let Ball B has a velocity = v m/s.
Applying law of conservation of momentum,
Total initial momentum = total final momentum
3×2 +1×-4 = 3×-1.5 + 1×v
⇒ v = 3×2 +1×-4 - 3×-1.5
⇒ v = 6.5 m/s.
hence, the velocity of ball B after the collision is 6.5 m/s.
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A small rectangular object of unknown material is examined in the laboratory. Iron filings and a compass needle are not attracted to the object. The object is suspended from a light string and is free to swing but does not align itself with Earth’s magnetic field. A strong magnetic field is switched on perpendicular to the long axis of the object. The object changes its orientation so that it partially aligns with the magnetic field. After the field is switched off, the object and string eventually return to their original orientation. Once again, it is observed that iron filings and a compass needle are not attracted to the object. The object most likely is exhibiting the property of
The object is likely exhibiting the property of diamagnetism.
A small rectangular object of unknown material is examined in the laboratory. Iron filings and a compass needle are not attracted to the object. The object is suspended from a light string and is free to swing but does not align itself with Earth’s magnetic field. A strong magnetic field is switched on perpendicular to the long axis of the object. The object changes its orientation so that it partially aligns with the magnetic field. After the field is switched off, the object and string eventually return to their original orientation. Once again, it is observed that iron filings and a compass needle are not attracted to the object. The object most likely is exhibiting the property of Diamagnetism.
Diamagnetism is a type of magnetism that is exhibited by all materials, and it is the weakest type. It results in a repulsive force between the material and an external magnetic field. This repulsion is what caused the object to partially align with the magnetic field when it was switched on.
The lack of attraction between the iron filings and the compass needle indicates that the object is not ferromagnetic or paramagnetic, which are both stronger types of magnetism. When the magnetic field was switched off, the repulsive force between the object and the field was no longer present, allowing the object and the string to return to their original orientation.
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The wheel in the simplified engine of Figure 1 has radius of 0. 250 m and rotates so that the piston oscillates at angular frequency of 12. 0 rad/s. At = 0, the piston is located at =. Calculate the piston’s position, velocity and acceleration at = 1. 15 s.
The piston's position, velocity, and acceleration at t = 1.15 s are :
Position: 3.45 m
Velocity: 3 m/s
Acceleration: 0 m/s^2
To calculate the piston's position, velocity, and acceleration at t = 1.15 s, we need to know the angular position, velocity, and acceleration of the wheel.
The angular position of the wheel at t = 1.15 s is given by
θ = ωt + [tex]A_{0}[/tex]
where ω is the angular frequency, t is the time, and [tex]A_{0}[/tex] is the initial angular position.
Since the angular frequency is given as 12 rad/s and the initial angular position is 0, the angular position of the wheel at t = 1.15 s is
θ = 12 x 1.15 = 13.8 radians
The piston's position is given by
r = Rθ
where R is the radius of the wheel.
Substituting the value of R and θ,
r = 0.25 x 13.8 = 3.45 m
The velocity of the piston is given by
v = r' = Rθ' = Rω
Substituting the values
v = Rω = 0.25 x 12 = 3 m/s
Acceleration of the piston is given by
a = v' = Rθ'' = Rω' = R(ω^2)θ
As the angular frequency is constant, the angular acceleration is 0 so the linear acceleration is also 0.
Note: Linear acceleration is not equal to the derivative of linear velocity, it is equal to the derivative of velocity with respect to time, which is zero in this case.
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2. An airboat with mass 3.50 x 102 kg, including the passenger, has an engine that produces a net horizontal force of 7.70 x 102 N, after accounting for forces resistance. a. Find the acceleration of the airboat b. Starting from rest, how long does it take the airboat to reach a speed of 12.0 m/s2
The acceleration of the airboat which has a mass of 350 kg is 2.2 m/s²
The time the airboat takes to reach the speed of 12 m/s is 5.45 seconds
The mass of the airboat = 350 kg
The net horizontal force of the airboat = 770 N
The acceleration of the airboat can be found using the formula,
F = ma
where F is the force
m is the mass
a is the acceleration
Let us rearrange the above equation, we get
a = F/m
Let us substitute the known values in the above equation, we get
a = 770 / 350
= 2.2 m/s²
The time taken to reach the speed of 12 m/s is
a = v/t
where a is the acceleration
v is the velocity
t is the time taken
Let us rearrange the equation, we get
t = v/a
Let us substitute the known values in the above equation, we get
t = 12 / 2.2
= 5.45 seconds
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If an object was traveling horizontally off a cliff at 9 m/s for 7 seconds, how far did it go?
The object travelled 63 meters at 9m/s for 7 seconds.
What is distance travelled?The length of the trajectory taken between the initial and final positions of the moving body is the distance traveled.
To calculate the distance traveled by an object traveling horizontally off a cliff, you can use the formula:
d = v * t
where d is the distance traveled, v is the velocity (9 m/s), and t is the time (7 seconds).
By substituting the given values into the formula, we get:
d = 9 * 7 = 63 meters
So, the object traveled 63 meters horizontally before it hit the ground after being launched off the cliff at 9 m/s for 7 seconds.
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A 17-N falling object encounters 9 N of air resistance. The magnitude of the net force on the object is
The magnitude of the net force on the object is 8 N. This is because the force of gravity, which is 17 N, is being opposed by the force of air resistance, which is 9 N. Therefore, the net force is 17 N - 9 N = 8 N.
Force is a push or pull on an object that is caused by an interaction between two objects. It has both magnitude, which is the strength of the interaction, and direction, which is the direction in which the force is being applied.
Net force is the sum of all the forces acting on an object. It is calculated by adding up all the forces that are acting on the object, taking into account their directions. This can be used to calculate the acceleration of an object, as the greater the net force, the greater the acceleration.
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If a building is 44 m tall, how long would it take to fall off it?
Answer:
2.995 seconds
Explanation:
We can use this kinematics equation to evaluate time.
[tex]y=v_0t-\frac{1}{2}gt^2[/tex]
Lets solve for [tex]t.[/tex]
Combine [tex]\frac{1}{2}[/tex] and [tex]gt^2[/tex].
[tex]y=v_0t-\frac{gt^2}{2}[/tex]
Subtract [tex]y[/tex] from both sides.
[tex]0=v_0t-\frac{gt^2}{2}-y[/tex]
[tex]0=-\frac{gt^2}{2} -v_0t-y[/tex]
Multiply both sides of the equation by -1.
[tex]0=\frac{gt^2}{2} -v_0t+y[/tex]
Multiply both sides of the equation by 2.
[tex]0=gt^2 -2v_0t+2y[/tex]
Use the quadratic formula to solve for t.
[tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]
[tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]
[tex]a=-g\\b=2v_0\\c=-2y[/tex]
Solution 1 Steps
[tex]t=\frac{-2v_0+\sqrt{(2v_0)^{2} -4*-g*-2y} }{2*-g}[/tex]
[tex]t=\frac{-2v_0+\sqrt{4v_0^2 -4*-g*-2y} }{2*-g}[/tex]
[tex]t=\frac{-2v_0+\sqrt{4v_0^2 -8gy} }{-2g}[/tex]
Solution 2 Steps
[tex]t=\frac{-2v_0-\sqrt{(2v_0)^{2} -4*-g*-2y} }{2*-g}[/tex]
[tex]t=\frac{-2v_0-\sqrt{4v_0^2 -4*-g*-2y} }{2*-g}[/tex]
[tex]t=\frac{-2v_0-\sqrt{4v_0^2 -8gy} }{-2g}[/tex]
One of these solution will most likely lead to a negative answer. The solution that gives a positive answer is correct. Lets enter our values into both equations to see which one is correct.
We can assume the initial velocity is 0.
We are given
[tex]v_0=0\\g=-9.81\\y=44[/tex]
Lets try the first solution.
[tex]t=\frac{-2*0+\sqrt{(4*0^2) -(8*-9.81*44)} }{-2*-9.81}[/tex]
[tex]t=\frac{0+\sqrt{0 -(8*-9.81*44)} }{-2*-9.81}[/tex]
[tex]t=\frac{0+\sqrt{0 --3453.12} }{-2*-9.81}[/tex]
[tex]t=\frac{\sqrt{3453.12} }{19.62}[/tex]
[tex]t=2.995[/tex]
Our first solution was positive so there is no need to check the second solution.
Using the conductor sizing guide, what conductor ampacity is needed for a 10-horsepower, 230-volt, single-phase motor: a.50 A
b.60 A
c.62.5 A
d.87.5 A
The correct conductor ampacity for a 10-horsepower, 230-volt, single-phase motor is option c. 62.5 A.
The ampacity of a conductor is a measure of the maximum amount of electrical current that can flow through it safely. The ampacity required for a motor is based on the size of the motor and the voltage of the electrical system. There are standard methods for determining the minimum ampacity for a given motor and voltage, such as the National Electric Code (NEC) and the American National Standards Institute (ANSI). The NEC and ANSI both state that the minimum ampacity for a 10-horsepower, 230-volt, single-phase motor is 62.5 amperes. It's important to note that using a conductor with ampacity lower than the recommended one may cause the motor to overheat and fail, leading to damage or even fire hazard.
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an object moves 15 meters in 3 seconds. what is its velocity (in m/s)?
Important Formulas:
[tex]v=\dfrac{d}{t}[/tex]
velocity(measured in m/s) = distance(measured in meters) / time(measured in seconds)
__________________________________________________________
Given:
[tex]d=15m[/tex]
[tex]t=3s[/tex]
[tex]v=?[/tex]
__________________________________________________________
Finding velocity:
[tex]v=\dfrac{d}{t}[/tex]
[tex]v=\dfrac{15}{3}[/tex]
__________________________________________________________
[tex]\fbox{v = 5 m/s}[/tex]
What velocity must a 2. 25 kg croquet mallet have in order to have the same momentum as 1. 25 kg ball that has a momentum 6. 25 kg•m/s to the west
2.78 m/s to the west velocity must a 2. 25 kg croquet mallet have in order to have the same momentum as 1. 25 kg ball that has a momentum 6. 25 kg•m/s to the west.
Given,
Mass = 2.25kg
Momentum = 6.25 kg•m/s
To find,
Velocity
Formula used,
Momentum = Mass x velocity
Calculation,
6.25 kg•m/s = 2.25 kg x velocity
Velocity = 6.25/2.25
Velocity = 2.78 m/s
The conservation of momentum principle asserts that the quantity of momentum inside a problem domain remains constant; momentum is not generated nor destroyed, but only modified by the action of forces as defined by Newton's equations of motion.
Newton's third law says that for every force exerted by object A on object B, object B exerts an equal but opposite force in magnitude and direction. Newton utilised this concept to create the law of conservation of momentum.
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How much heat is required to be removed from a 8kg liquid water at 33 °C to be transformed into ice at 0 °C?
The Total heat required to transform 8 kg of liquid water at 33 °C to the ice at 0 °C is 13,019 J.
The heat required to be removed from a liquid to transform it into a solid is called the heat of fusion. For water, the heat of fusion is approximately 334 J/g. To calculate the amount of heat required to transform 8 kg of liquid water at 33 °C to the ice at 0 °C, we'll need to take into account both the heat of fusion and the heat required to lower the temperature of the water from 33 °C to 0 °C.
First, we'll calculate the heat required to lower the temperature of the water from 33 °C to 0 °C. This can be calculated using the formula:
Q = mcΔT
where Q is the heat required, m is the mass of the water (8 kg), c is the specific heat capacity of water (4.186 J/g·°C), and ΔT is the change in temperature (3temperature change
Q = (8 kg)(4.186 J/g·°C)(33 °C) = 10,347 J
Next, we'll calculate the heat of fusion by multiplying the heat of fusion of water (334 J/g) by the mass of the water (8 kg).
Q = (334 J/g)(8 kg) = 2672 J
To sum up, the total heat required to transform 8 kg of liquid water at 33 °C to ice at 0 °C, is equal to the heat required to lower the temperature + heat of fusion which is 10,347 J + 2672 J = 13,019 J
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A hunter shoots a bullet horizontally at a rock cliff wall that is 200 m away. They hear the sound of the bullet hitting the rock 0.85 seconds later. Knowing that the speed of sound was 340 m/s, what was the speed of the bullet
The fact is that the speed of the bullet plus the speed of sound is equal to the total distance traveled divided by the total time taken. Speed of bullet + Speed of sound = Total distance traveled / Total time taken.
Calculation-We know the speed of sound is 340 m/s, the distance traveled is 200 m, and the time taken is 0.85 seconds. We can use these values to find the speed of the bullet.
Speed of bullet = (Total distance traveled / Total time taken) - Speed of sound
By substituting the values, we get:
Speed of bullet = (200m / 0.85s) - 340m/s
Speed of bullet = 235.29 m/s
Therefore, the speed of the bullet was 235.29 m/s.
Is a bullet moving at the same rate as light?Nothing can travel faster than the speed of light, according to Einstein's special relativity theory, which was first published in 1905. According to Einstein, this speed is a basic constant of nature since it seems the same to all observers, regardless of where they are in space.
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1) Renatta Gass is out with her friends misfortune occurs and renatta and her Friends find themselves getting a workout. They apply a cumulative force Of 1580N to push the car 288m to the nearest fuel station. Determine the work done on the car.
Work is characterized as a force that causes an object to move or be displaced. The work done would be 455040.
What is Work?Work is the scalar product of the force acting on an object and the displacement that force causes when the force is constant.
Despite the fact that work lacks a direction due to the scalar product (or dot product) aspect of vector mathematics, force and displacement are both vector quantities.
"W" stands for work, "F" is the force, and "d" represents displacement (or the distance the object travels).
Therefore, Work is characterized as a force that causes an object to move or be displaced. The work done would be 455040.
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why are earthquakes hard to predict??
answer fast
Answer:
Reliable predictions require precursors – some kind of signal in the earth that indicates a big quake is on the way. The signal has to happen only before large earthquakes and it has to occur before all big quakes. At the moment seismologists have failed to find those precursors – if they even exist.
a race car is moving at a constant speed around a track.What about the race car is changing and why
A race car is moving at a constant speed around a track. The race car is changing its velocity as the direction of motion changes.
What is velocity?The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time is the definition of velocity.
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
As the race car is moving at a constant speed around a track, the magnitude of velocity remains same but during race it may changes its direction of motion, that is why, velocity of it, which depends on both magnitude and direction, may changes.
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You need to move a 117-kg sofa to a different location in the room. It takes a force of 109 N to start it moving. What is the coefficient of static friction between the sofa and the carpet
According to the question, the sofa and carpet have a static friction coefficient of 10.519.
Static Friction: What Is It?Static friction is defined as a force that maintains an object at rest. when someone tries to move a stationary thing across a platform without actually moving their body or the platform they were moving the object across, they face resistance.
Given:
Wight of sofa = 117 kg
Force= 109N
weight = mass × acceleration due to gravity 117 × 9.8 = 1146.6
the mass is given in kilograms, but work in newtons, thus we multiplied the mass by 9.8
acceleration = Zero
force = resistance
substitute force with 109N and resistance with 1146.6× μ
109 = 1146.6 × μ
μ = 1146.6/109
μ = 10.519
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A 10.0-g bullet is fired into a stationary block of wood having mass m 5 5.00 kg. The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 m/s. What was the original speed of the bullet
The original speed of the bullet was 300.6 m/s.
What is the best meaning of mass?A measure of the amount of matter contained in or constituting a physical body. In classical mechanics, the mass of an object is related to the force required to accelerate it and hence is related to its inertia, and is essential to Newton's laws of motion.
Given:
mV bi +MV wi =mV b +M Vwf
where m= mass of bullet =10 g=10^−2 ∣kg
M= mass of wood block =5 kg
V bI = initial mass of bullet
Vwi = initial mass of wood block and V bf =V wf
=0.06 m/s 10 −2 Vbi+0(10 −2 +5)0.6 V
bi = 10 −2 5.01×0.6 V
bi =300.6 m/s
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How do you find the value of T when a particle is at rest?
The value of T when a particle is at rest is 0. The velocity of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Velocity is the rate of change of velocity. At any point on a trajectory, the magnitude of the velocity is given by the rate of change of velocity in both magnitude and direction. Velocity of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of we can calculate. Hence by the primary information that we have we can formerly consider that the velocity which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point and the value of T when a particle is at rest is zero.
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The electric field near the surface of Earth points downward and has a magnitude of 140 N/C. A. Compare the upward electric force on an electron with the downward gravitational force. (upward force / downward force)b. What magnitude charge should be placed on a penny of mass 6 g so that the electric force balances the weight of the penny near Earth's surface?
The me = 9.1 x 10-31 kg the the upward electric force on an electron with the downward gravitational force. C = 0.42 mC is the magnitude charge should be placed on a penny of mass 6 g so that the electric force balances the weight of the penny near Earth's surface.
What is magnitude ?
According to the physics definition, magnitude is just "distance or quantity." It demonstrates how an object moves as it is moving, including whether the movement is absolute, relative, or of a particular size. It serves as a means of describing the size or scope of something. Physicists use the word "magnitude" to indicate size or distance.
What is gravitational force ?
The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of their distance, according to Newton's universal law of gravitation.
E = 140 N/C
qe = -1.6 x 10-19 C
me = 9.1 x 10-31 kg
A) Fe = qe.E = 1.6 x 10-19. 140 = 2.24 x 10-17 N ( upward )
Fw = me.g = 9.1 x 10-31.9.8 = 8.918 x 10-30 N (down ward )
Fe/Fw = 2.51 x 1012
B) mg = q.E
q = mg/E = (6 x 10-3.9.8) /140
q = 4.2 x 10-4 C = 0.42 mC
Therefore, me = 9.1 x 10-31 kg the the upward electric force on an electron with the downward gravitational force. C = 0.42 mC is the magnitude charge should be placed on a penny of mass 6 g so that the electric force balances the weight of the penny near Earth's surface.
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13. Shadrach, a form one student performed an experiment to investigate surface tension. he poured some water on a trough and allowed it to settle he then took a razor blade and gently placed it on the surface of the water in an attempt to make it float but failed give two possible reasons why the experiment failed
Answer:
this because the surface tension was lowered by using an impurity or rising the temp of the water
What is the acceleration when t 0?
The acceleration of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Acceleration is the rate of change of velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction. Acceleration of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of wee can calculate. Hence by the primary information that we have we can formerly consider that the acceleration which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
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What environmental factors can influence genetic variations?
Some harmful environmental factors can change the nucleotide sequence of a gene. UV rays, for example, can harm DNA strands.
What elements influence genetic variation?Genetic variations arise during meiosis as a result of mutation and recombination. Chemical or biological mutagens frequently result in mutations. The genetic diversity of organisms is also altered by accidental mating.
What are five examples of environmental variations?The length at which you want to wear your hair. Scars – from your own unique accidents. The strength of your muscles depends on how much exercise you get. Piercings, whether you decide to have them or not. Mutations are the primary cause of the emergence of genetic variation.
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Glands that excrete salt in the mangroves are examples of
Glands that excrete salt in the mangroves are examples of adaptions.
What is adaptions?The meaning of adaptation implies how a species changes its body and behaviour to better suit its natural environment. There are an estimated 8.7 million species currently living on earth. They are found across a wide and diverse natural environment, ranging from frozen and desolate Arctics to the sweltering sands of the Sahara.The natural environment is an ever-changing feature of planet earth. The process of adaptation ensures that the species which adapts the most, survive.Read on to explore plant and animal adaptations across the wide ranges of landscapes.In biology, adaptation has three related meanings. Firstly, it is the dynamic evolutionary process of natural selection that fits organisms to their environment, enhancing their evolutionary fitness. Secondly, it is a state reached by the population during that process.
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2. Why might it be beneficial for a photographer to have a polarizing filter for their camera when taking pictures outdoors
A polarizing filter can be beneficial for a photographer when taking outdoor pictures because it can reduce glare and reflections from surfaces such as water and glass.
it can also enhance colors, darken blue skies, and reduce the amount of light entering the lens, allowing for more even exposure. This can be especially useful in situations where the sun is very bright and can create harsh shadows and overexposed highlights. The polarizing filter can also reduce the amount of haze in the atmosphere, which can improve the overall clarity of the image. These effects can help a photographer capture more vivid and detailed images, making them stand out from the crowd.
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The piton in fig 2. 1. 15 i pulled out of the cylinder from piton x to piton y without changing the temperature of the air encloed if the original preure in the cylinder wa 1. 0 multiply by 10 calculate the air preure when the piton i at poition y
The pressure at position y to be 10.0, which is the air pressure when the piston is at position y.
If the original pressure in the cylinder was 1.0, and the piston is pulled out from position x to position y without changing the temperature of the enclosed air, the air pressure at position y will be increased. This is due to the change in volume of the cylinder as the piston is pulled out. As the volume increases, the number of air molecules inside the cylinder also increases, which causes an increase in the air pressure.
To calculate the air pressure when the piston is at position y, we can use the gas law known as Boyles' Law, which states that the pressure and volume of a gas are inversely proportional. Therefore, if the volume increases, the pressure will decrease, and if the volume decreases, the pressure will increase.
P₁V₁=P₂V₂Where P₁ is the initial pressure, V₁ is the initial volume, P₂ is the final pressure, and V₂ is the final volume.
By substituting the given values, we have:
1.0V₁ = P₂(V₁+V)Where V is the change in volume due to the movement of the piston.
Solving for P₂:
P₂= 1.0*V₁/(V₁+V)P₂= 1.0*1.0/(1.0+V)As we know, the original pressure is 1.0, and if we multiply it by 10, we will get the final pressure at position y to be 10.0, which is the air pressure when the piston is at position y.
This question is not written in a proper manner. The corrections are:
The piston in fig. 2. 1.15 is pulled out of the cylinder from piston x to piston y without changing the temperature of the air enclosed. If the original pressure in the cylinder was 1.0, multiply by 10 to calculate the air pressure when the piston is at position y.Learn more about piston–cylinder here: brainly.com/question/24884868
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Which of the following is not a drawback of using coal for energy production?
A. Mountaintop mining
B. Mercury in fly ash
C. Mining explosions
D. Difficult transportation due to instability
The statement that is not provide a drawback of using coal energy for energy production is (D) difficult transportation due to instability.
What is disadvantage of using coal for energy production?Coal is source of fossil energy created by dead plant drawn in swamp environments and subjected by geological pressure and forces of heat over hundreds of millions of years. The disadvantage using this source of energy are:
It use mountaintop mining that can contaminate water.It use combustion to create energy and the remaining after combusting has mercury that can fly in form of an ash. As to reminder, mercury can harm nerve when its being inhale.In the process of its mining, the coal commonly result an ash that can combust in the air. The accumulation can cause mining explosions.Learn more about coal mining here
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A 0.480 kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change the period to 2.05 s
The mass added to the object to change the period to 2.05 s is 0.42 kg
What is the time period of an oscillation?
The time taken for an oscillating particle to complete one cycle of oscillation is known as the Period of oscillating particle.
Given :
A 0.480-kg mass suspended from a spring oscillates with a period of 1.50 s.
The formula of the time period is given by:
[tex]T=2\pi \sqrt{m/K}[/tex] ------(1)
where m is the mass and K is the spring constant.
The new time period is given by:
[tex]T'=2\pi \sqrt{m^{'} /K[/tex]-----(2)
where m' is the total mass after the addition and K is the spring constant.
Dividing equation (1) by equation (2).
[tex]T/T'=\sqrt{m/m'}[/tex]
Now, substitute the known terms in the above expression.
[tex]\frac{1.50}{2.05} =\sqrt{0.480/m'}[/tex]
[tex]m'=\frac{0.480}{0.5329}[/tex]
[tex]m'=0.9[/tex] kg
Now, the mass added to the object to change the period to 2.05 s is given by:
m" = 0.9 - 0.480
m" = 0.42 Kg
Thus, 0.42kg of mass must be added to the object to change the period to 2.05s.
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(I know the velocity (1.6m/s) and now I want to find the angle of the vector. )
A rower intends to row his raft at its top speed of 1.5 m/s from the south bank of a river to a point
directly opposite on the north bank. He fails to recognise the river current which pulls a Jog west at
0.50 m/s, What is the raft's resultant velocity with respect to the bank?
Answer:
R = 1.5 to the northeast
C = .5 to the west
B = C + R adding vectors head to tail
Vector B will be straight north or directly across the river
B = (1.5^2 - .5^2)^1/2
B = 2^1/2 = 1.41
Adding the vectors as described shows that if the rower rows at 1.5 m/s in a northeasterly direction and the river carries the boat downstream at .5 m/s the net speed of the boat is 1.41 m/s straight north
You have a small globe, which is mounted so that it can spin on the polar axis and can be spun about a horizontal axis (so that the south pole can be on top).
Give the globe a quick spin about the polar axis, and then, before it stops, give it a spin about the horizontal axis. Are there any points on the globe that are at rest?
(A) There are two points, fixed on the globe, that are at rest,
(B) There are two points that are instantaneously at rest, but these two points move around the globe in an apparently random fashion,
(C) At some times two points are instantaneously at rest,
(D) There are no points at rest until the globe stops spinning
A globe is a miniature replica of the planet. We can see the size, shape, and placement of continents and oceans, which is helpful.
What is used to mount a globe?A globe's stand is attached to the meridian. Latitude (coordinate) markings can be found on several meridian lines. These markings range from 0° at the equator to 90° at the north and south poles.
The Unisphere is tipped at an angle of 23.5 degrees, which corresponds to the tilt of the Earth.
The globe makes it possible to see the entire planet at a glance. Along with their latitudes and longitudes, it displays many nations, continents, and oceans. The units of latitude and longitude are degrees and minutes.
Altazimuth and Equatorial mounts are the two main categories of astronomical telescope mounts. The simplest sort of mount, known as an altazimuth (sometimes spelled alt-az), has two motions: azimuth (horizontal) and altitude (vertical).
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A 2.0 kg book is lying on a 0.75-m-high table. You pick it up and place it on a bookshelf 2.3 m above the floor. During this process, your hand does _______ work on the book.
The weight of the book and your lifting power will be the only two forces operating, assuming that air resistance is minimal (gravity).
The book's displacement was x=(2.3-0.75)m=+1.55m.
The book weighs W= m(-g)= 2.0 kg(-10N/kg)= 20 N.
Therefore, the weight's work (energy delivered by the weight) is equal to W.x (-20N).
(+1.55m) = -31 Nm =-31 J.
This outcome, -31J, demonstrates that the weight caused the rising book to lose 31J of kinetic energy, increasing the gravitational potential energy of the book.
You lifted the book, which gave it kinetic energy from the chemical energy stored in your muscles. The weight is thereby decreasing the kinetic energy of the book while the lifting force from you increases it.
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