Answer:
Newton's universal law of gravitation predicts how mass can distort light, so we can apply Newton's law to determine the mass of the cluster. ... The lensing allows us to determine the orbital speeds of galaxies in the cluster, so that we can determine the mass of the cluster from the orbital velocity law.
Explanation:
which research model refers to the study of an individual group or community over a predetermined period
Developing Psychological Theories: Mastery Test
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Hope this helps :)
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what is the horse power of an electric motor which can do by 1250 joule of work in 5 seconds
Block A has a mass of 2kg and a speed of 50 m/s along the positive x axis.
Block B has a mass of 4 kg and a speed of 25 m/s along the negative x axis.
The two blocks collide head-on in a perfectly elastic collision.
Determine the velocity of each mass after the collision.
Momentum is conserved, so
(2 kg) (50 m/s) + (4 kg) (-25 m/s) = (2 kg) v₁' + (4 kg) v₂'
where v₁' and v₂' are the velocities of the two blocks after the collision. Simplifying this gives
100 kg•m/s - 100 kg•m/s = (2 kg) v₁' + (4 kg) v₂'
0 = (2 kg) v₁' + (4 kg) v₂'
v₁' = -2v₂'
Energy is also conserved, so
1/2 (2 kg) (50 m/s)² + 1/2 (4 kg) (-25 m/s)² = 1/2 (2 kg) (v₁')² + 1/2 (4 kg) (v₂')²
Simplifying yields
2500 J + 1250 J = (1 kg) (v₁')² + (2 kg) (v₂')²
3750 J = (1 kg) (v₁')² + (2 kg) (v₂')²
Substitute v₁' = -2v₂' and solve for v₂' :
3750 J = (1 kg) (-2v₂')² + (2 kg) (v₂')²
3750 J = (6 kg) (v₂')²
(v₂')² = 625 J/kg = 625 m²/s²
v₂' = 25 m/s
Then the first block has final velocity
v₁' = -2 (25 m/s)
v₁' = -50 m/s
Which are examples of perfectly inelastic collisions? Check all that apply.
a baseball bouncing off a bat
bumper cars bumping off of each other
a cue ball hitting an eight ball and stopping
a plane landing on an aircraft carrier
rain sticking to a window
two train cars coupling together
Answer:
D. a plane landing on an aircraft carrier
E. rain sticking to a window
F. two train cars coupling together
Explanation:
0. Kedija walked 300m from A to B and returned back and walked 200m and then stopped at 'C', what
is her change in position from A to in the figure below
300m
200m
A
С
B
C/-500m
D 100m
B/ -100m
A Soom
Answer:
100
Explanation:
Displacement is the shortest line between the starting point and the ending point
so , the starting point is "A"
,the ending point is "C"
so "AC" = AB - CB = 300 - 200 = "100"
A truck moves 60 kilometers east from point A to point B. At point B, It turns back west and stops 15 kllometers away from point A. What are the
total distance and total displacement of the truck?
Answer:
a). The truck's distance covered for the trip is
(60) + (60 - 15) = 105 kilometers .
b). Its displacement for the whole trip is the distance
and direction from the start-point to the end-point.
15 kilometers east .
Explanation:
Construct an explanation for the fact that we don’t see the same amount of energy coming out at the end of these transformations as we did at the beginning. *
Answer:
When energy is transformed from one form to another, or moved from one place to another, or from one system to another there is energy loss.
Explanation:
Hope this helps! :)
Given that 1 pound is equal to 4.45 newton’s what is the weight of a 500N child in pounds?
Answer:
112.36 pounds
Explanation:
Since 1 pound = 4.45 Newtons, a 500N child in pounds = 500÷4.45 = 112.36 pounds (approximately).
How many cm3 are there in 1 dm3?
The answer is in the picture.
Juliana was late to physical science class and missed the beginning of the notes, including the title. These are the notes she took. -Makes up everything -Can be solid, liquid, or gas -Is made up of atoms, or tiny particles that are the smallest unit of matter What would be the best title for her notes? Atoms Matter Mass Weight.
The correct option to the question is Matter.
Matter makes up everything. matter can be solid, liquid, or gas. matter is made up of atoms, or tiny particles that are the smallest unit of matter.
Moreover, Matter can be described as,
Matter is anything that has occupies space (has mass and volume).
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Answer:
Matter
Explanation:
I took the test Edge 2022
A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
Answer:
0.184 m/s
Explanation:
Momentum is conserved. If the velocity of the 0.24 kg mass is positive, then ...
m1v1+m2v2 = m3v3
(0.24 kg)(0.60 m/s) +(0.26 kg)(-0.20 m/s) = (0.24 +0.26 kg)(v)
v = (0.144 -0.052 kg·m/s)/(0.50 kg) = 0.184 m/s
The speed of the combined masses is 0.184 m/s.
_____
Additional comment
The positive sign indicates the combined masses are moving in the direction of the original 0.24 kg mass.
can someone explain why is the answer 3.1?
i dont know Im sorry but why Im messaging is because when more people respond it usually is the first to pop up so someone else will see this and be able to help you Explanation:
why we use light-years in space verses other units of distance?
Answer:
The light year is used to measure distances in space because the distances are so big that a large unit of distance is required.
A 4000kg truck has a head-on inelastic collision with a 2500kg truck.
A. calculate the total momentum of the trucks before they collide.
B. Calculate their speed just after they collide.
Answer:it could be B
Explanation:
im not sure
( the answer only for points will be reported ) A crane lifts a load of 36000N to a height of 50 metre in 1 minute . What is the power of the crane ?
Answer:
- 30 kW
Explanation:
IDEA:
Power of an object that does work(source) is given by:
[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]
where work done is mostly shown as the Force applied on an object to Displace it through some distance in the same direction as the Force.
[tex] \boxed{ \mathsf{ work = force \times displacement}}[/tex]
___________________
INFORMATION:
In the question,
The source of power is the crane, while the object is a load of 36000N.
Note, what's given is the force, not the mass. Since, the SI unit of mass is kg and that of Force is Newton(N).
[The weight of the load is represented in Newton, since weight of an object is the amount of Force with which the Earth attracts that object]
I) work done
So,
Force = 36000NDisplacement = 50 m=> Work = 36000 × 50
= 1,800,000 J
(The SI unit of work is Joules(J)).
___________________
II) power
After getting the amount of work done, now we have to place it in the formula for power.
That is:
[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]
Note, During calculations, all quantities must be in their SI units.
SI unit for time is Seconds (s)
But the time we have is in minutes.
___________________
Converting time from minutes to Seconds:
1 minute = 60 Seconds.
Hence,
time = 60 s[tex] \implies \mathsf{power = \frac{1800000}{60} } \: [/tex]
=> power = 30,000 W
(SI unit of power is Watts(W))
To write four zeroes with a 3 and W is a lot of effort. So, we can look for simple expressions like kilowatts(kW) that can express bigger quantities in lesser terms.
1000 W = 1 kW
•°• 30,000 W = 30 kW.___________________
Direction and sign:
The crane displaces the load in an upward direction (from the term "lifts")
But, the Force is acting downwards, as the weight of the body is always towards the Earth.
Since, the directions of Force and displacement are opposite, a minus takes its place in front of both Work and power.
___________________
Therefore, the final answer will be:
Power of the crane = - 30 kWWhich would ba another example of newtons first law?
Forces are needed to make a car do which of these?
slow down
speed up
stay on the ground
all of the above
Object 1 has a mass of 7.0kg and a initial velocity of 17.0 m/s. Object 2 has a mass of 8.0kg and a initial velocity of -14.0 m/s. What are the final velocitys of each object. Please show work
[tex]\\ \sf\longmapsto m1v1+m2v2=(m1+m2)v3[/tex]
[tex]\\ \sf\longmapsto 7(17)+8(-14)=(7+8)v3[/tex]
[tex]\\ \sf\longmapsto 119-112=15v3[/tex]
[tex]\\ \sf\longmapsto 15v3=7[/tex]
[tex]\\ \sf\longmapsto v3=7/15[/tex]
[tex]\\ \sf\longmapsto v3=2.1m/s[/tex]
Explain Body Mechanics.
PLUS BRAINLY! and 50 Points
Answer Body mechanics is a term used to describe the ways we move as we go about our daily lives. It includes how we hold our bodies when we sit, stand, lift, carry, bend, and sleep. ... Good body mechanics means using the body's strength to the best mechanical advantage to do a task efficiently and without injury.
Explanation:
Plz help!
A person walks the path shown
below. The total trip consists of
four straight-line paths. At the end of the walk, what is the person's
resultant displacement measured from the starting point?
The analytical method for the sum of vectors allows to find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
The displacement is a vector quantity, therefore vector algebra must be used to perform the addition of vectors, in general there are two methods:
Graphic. In this case, the origin of a vector is placed at the tip of the previous one and the resulting vector goes from the origin of the first vector to the tip of the last, this method is not very precise. Analytical. In this method the vectors are decomposed into a coordinate system, the sum of the components is performed and the resulting vector is built, this method is very expensive.
Indicate in the graph a Cartesian coordinate system, let alone the West - East axis coincide with the x axis. Let's use trigonometry to decompose the vectors.
Vector A.
Aₓ = 100.0 m
Vector B.
B_y = -300.0 m
The negative sign indicates that it goes in the negative direction of the y-axis
Vector C.
We use trigonometry.
The angle measured from the positive side of the x-axis counterclockwise is
θ = 180 + 30 = 210
sin 210 = [tex]\frac{C_y}{C}[/tex]
cos 210 = [tex]\frac{C_x}{C}[/tex]
C_y = C sin 210
Cₓ = C cos 210
C_y = 150.0 sin 210 = -75.0 m
Cₓ = 150.0 cos 210 = -129.9 m
Vector D.
The angle from the positive side of the x-axis counterclockwise.
θ = 180-60 = 120º
sin 120 = [tex]\frac{D_y}{D}[/tex]
cos 120 = [tex]\frac{D_x}{D}[/tex]
D_y = D sin 120
Dₓ = D cos 120
D_y = 200.0 sin 120 = 173.2 m
Dₓ = 200.0 cos 120 = -100.0 m
we add the component with algebraic sum.
x = Aₓ + Cₓ + Dₓ
y = B_y + C_y + D_y
x = 100 - 129.9 -100 = -129.9 m
y = -300 - 75.0 + 173.2 = -201.8 m
We construct the resulting vector.
We use the Pythagorean theorem for the Modulus.
[tex]R+ \sqrt{x^2 +y^2}[/tex]
R = [tex]\sqrt{129.9^2 + 201.8^2 }[/tex]
R = 239.99 m
We use trigonometry for the angle.
tan θ = [tex]\frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{201.8}{129.9}[/tex]tan-1 (201.8 / 129.9)
θ = 57.2º
Since the two coordinates are negative, this angle is in the third quadrant; to measure it from the positive side of the x-axis.
θ = 270 - θ'
θ = 270 - 57.2
θ = 212.8º
In conclusion using the analytical method for the sum of vectors we can find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
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I need it in the next hour or so!
A sports car with a mass of 650 kg is accelerating at +3 m/s2. The force of friction is 200 N, the forward force from the engine is 3100 N. What must the force of air resistance on the car be? - Show your work - Include a unit with your answer
The car is accelerating at 3 m/s² in the positive direction (to the right). By Newton's second law, the net force on the car in this direction is
∑ F = F[a] - F[f] - F[air] = ma
3100 N - 200 N - F[air] = (650 kg) (3 m/s²)
Solve for F[air] :
F[air] = 3100 N - 200 N - (650 kg) (3 m/s²)
F[air] = 3100 N - 200 N - 1950 N
F[air] = 950 N
me (5) A taxi is travelling at 15. m/s. Its driver accelerates with acceleration 3 m/s for 4 s. What is its new velocity? A car accelerates from 20 m/s to 30 m/s in 10 (a) Calculate the car's acceleration using v=utat. (b) Draw a velocity-time graph to show the car's motion. Find the distance it travels by calculating the area under the graph. (c) Check your answer by using the equation s = ut + hat Grade 9
Answer:
5)
Solution
initial velocity = 15 m/s
acceleration = 3m/s^2
time = 4 s
final velocity = 15+3×4
=15+12
=27m/s
A car accelerates from 20m/s to 30m/s in 10 second
T9 be honest I think some part of the second question is missing
PLEASE HELP I WILL MARK BRAINLIST!!
The diagram shows a swinging pendulum. Which best explains what happens to the motion of the pendulum due to the law of conservation of energy?
The pendulum will slow down and eventually stop moving as the mechanical energy transforms to thermal energy.
The pendulum will slow down and eventually stop moving as the mechanical energy disappears.
The pendulum will continue moving at the same speed because mechanical energy is created as the pendulum moves.
The pendulum will slow down but will not stop moving because some of the mechanical energy is destroyed.
The pendulum bob slow down and eventually stop as it loses it energy due to friction or air resistance. All its kinetic energy has been transformed to potential energy. None of the options is correct
OSCILLATORY MOTIONThe to and fro movement of an object or particle is known as oscillatory motion. Such motion repeats itself. Examples are;
Pendulum boba diving boardthe strings of a plucked guitarthe prongs of a tuning fork struck with a hard objectthe vertical movement of a disturbed mass on a spiral spring.The given diagram shows a swinging pendulum. And the option which best explains what happens to the motion of the pendulum due to the law of conservation of energy is
The pendulum will slow down and eventually stop moving when it loses energy because of friction or air resistance as the kinetic energy transforms to potential energy
The mechanical energy involve are potential and kinetic energy. Both energies reduce as they gradually lost some of their energies due to air friction between the bob and the air. Some of the lost energies may be transformed to thermal energy.
The pendulum bob slow down and eventually stop because it loses its mechanical energy due to air resistance or friction.
Therefore, the option A which state that "The pendulum will slow down and eventually stop moving as the mechanical energy transforms to thermal energy" can be considered. But none of the option best explain what happens to the motion of the pendulum.
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a bullet is fired out of a gun up at an angle with the horizontal. if its initial horizontal velocity is 10m/s what is the most likely horizontal velocity after two seconds
Hi there!
[tex]\large\boxed{10 m/s}}[/tex]
When a projectile is launched, the HORIZONTAL component remains constant.
The force of gravity only changes the vertical component of the velocity.
As the two components are completely independent of one another, the horizontal component is UNCHANGED.
how does cells and tissues work together with the brain to do its job
A balance of forces is demonstrated by an object which is slowing to a stop true or false
Answer:
its true since i already did this last year, if i am wrong i apologize
Explanation:
A point charge of 5. 0 Ă— 10â€""7 C moves to the right at 2. 6 Ă— 105 m/s in a magnetic field that is directed into the screen and has a field strength of 1. 8 Ă— 10â€""2 T. What is the magnitude of the magnetic force acting on the charge? 0 N 2. 3 Ă— 10â€""3 N 23 N 2. 3 Ă— 1011 N.
The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.
Given to us,
the charge [tex]q[/tex] = [tex]5\times 10^{-7}[/tex] C,
the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex] m/sec,
the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,
angle between the direction of v and B [tex]\theta[/tex] = 0,
Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by
[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]
Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N
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When dribbling a ball, the ______________ should control the direction and downward motion of the ball.
Answer:
gravity
Explanation:
keeps the ball down on the surface
When dribbling a ball, the gravity should control the direction and downward motion of the ball.
What is projectile motion?When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's centre (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.
Two distinct rectilinear motions occur simultaneously in a projectile motion:
Uniform velocity along the x-axis is what causes the particle to move horizontally (ahead).Uniform acceleration along the y-axis is what causes the particle to move vertically (downwards).When a ball is sent into the air at a certain speed, the only force acting on it is the acceleration caused by gravity (g).
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Halpinium metal (Jh(s)) can lose electrons via the photoelectric effect. The binding energy for Jh is 2.25x10-19 J. If a photon having an energy of 4.52x10-19 J strikes the surface of halpinium, calculate the de Broglie wavelength (in nm) of the electron that is ejected.
The relationship of the photoelectric effect and the de Broglie expression allows us to find the result for the wavelength of the ejected electrons is:
Wavelength of de Broglie is λ= 1.03 10⁻⁹m
The photoelectric effect was explained by Einstein assuming that the light rays behave like particles called photons, therefore the
[tex]E_{photon} = K + \Phi[/tex]
where [tex]E_{photon}[/tex] is the energy of the photon given by the Planck relation, K is the kinetic energy of the ejected electrons and Ф the work function of the material.
The Planck relationship states that the energy of the photons is proportional to the frequency.
[tex]E_{photon} = h f[/tex]
Where h is Planck's constant and f is the frequency of the photons.
They indicate The work function is Ф= 2.25 10⁻¹⁹ J, the energy of the photon [tex]E_{photon}[/tex] = 4.52 10⁻¹⁹ J, let's find the kinetic energy of the ejected electrons.
[tex]K = E_{photon} - \Phi[/tex]
Let's calculate.
K = (4.52-2.25) 10⁻¹⁹
K = 2.27 10⁻¹⁹ J
Kinetic energy is the energy of motion and is given by the relationship.
[tex]K = \frac{p^2}{2m}[/tex]
The wave-particle duality was established by de Broglie with the relation.
[tex]p = \frac{h}{\lambda }[/tex]
Let's replace.
[tex]K = \frac{1}{2m} (\frac{h}{\lambda} )^2 \\\lambda^2 = \frac{h^2}{2m K}[/tex]
let's calculate.
[tex]\lambda^2 = \frac{(6.63 \ 10^{-34})^2 }{2 \ 9.1 \ 10^{-31 } \ 2.27 \ 10^{-19}}[/tex]
[tex]\lambda = \sqrt{1.06397 \ 10^{-18}}[/tex]
λ = 1.03 10⁻⁹m
In conclusion with the relationship of the photoelectric effect and the de Broglie expression we can find the result for the wavelength of the ejected electrons is:
Wavelength of de broglie is: λ = 1.03 10⁻⁹m
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the purpose of many scientific investigations is to test a {n}
Answer:
Scientific investigation is a quest to find the answer to a question using the scientific method.
Explanation:
the scientific method is a systematic process that involves using measurable observations to formulate, test or modify a hypothesis.