How does using more water in a beaker affect the solubility in an experiment?

Answers

Answer 1
Because it may dilute the substance

Related Questions

How many atoms are in mercury phosphate

Answers

Answer:

There are 95 atoms in mercury phosphate

Explanation:

You just add the atomic number for both elements

What is the reaction between CCl4 and H2O? ​

Answers

Answer:

At temperatures > 400 °C, CCl4 reacts with H2O over a MgO catalyst to yield HCl and CO2.

Air is a mixture of (mostly) oxygen (molecular mass 16) and nitrogen (molecular mass 14) gases. At room temperature, which molecules in this room have more kinetic energy (on average)

Answers

The molecules of the two gases will have the same kinetic energy at room temperature.

The average kinetic energy of gaseous molecules can be calculated using the formula:

Kinetic Energy = 3/2RT, where R = constant and T = temperature in Kelvin

This means that the kinetic energy of a gaseous molecule is dependent on the temperature of the molecule only.

In other words, the molecular mass of molecules of gases has no bearing on the kinetic energy of each molecule.

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What would be the atomic number of this atom?

Answers

Answer:

1 would be the answer

protons = atomic # I think

Answer:

hydrogen

Explanation:

hydrogen has the atomic number of 1 which means that hydrogen has one proton and is neutral so it has one electron as well.

ethylene glycol, an antifreeze boils at 197 ⁰C. Convert 197 ⁰C to:
⁰F =
K =

Answers

[tex]\boxed{\sf °F=\dfrac{9}{5}°C+32}[/tex]

[tex]\\ \sf\longmapsto °F=\dfrac{9}{5}(197)+32[/tex]

[tex]\\ \sf\longmapsto °F=\dfrac{1773}{5}+32[/tex]

[tex]\\ \sf\longmapsto °F=354.6+32[/tex]

[tex]\\ \sf\longmapsto °F=386.6°F[/tex]

[tex]\rule{200pt}{5pt}[/tex]

[tex]\boxed{\sf K=°C+273}[/tex]

[tex]\\ \sf\longmapsto K=197+273[/tex]

[tex]\\ \sf\longmapsto K=470K[/tex]

Which scientific law describes the observation that energy cannot be created or destroyed?

Law of universal gravitation
Law of conservation of energy
Newton's first law of motion
Newton's third law of motion

Answers

Answer:

law of conservation of energy

Compare the average motion of the particles in the 3 containers of water

Answers

Answer:

c>b=a

Explanation:

It is important to note that mass does not affect the average motion/energy per molecule, but temperature does. the higher the temperature the faster the particles are. A has the same temperature as B, so they have the same amount of motion. C is warmer than A and B, so the average motion of the particles in beaker C is the largest

Consider an ice cube and a hot radiator. Which has the higher thermal energy?

the ice cube

the radiator

Answers

The answer to your question is the radiator

The thermal energy of a material increases with temperature. Therefore, the radiator  has the higher thermal energy.

What is thermal energy?

When the temperature rises, a type of energy called thermal energy is produced. The amount of thermal energy usually directly inversely proportional to the object's change in temperature. Thermal energy takes the form of heat.

The thermal energy of a material increases with temperature. The quicker motions of the substance's atoms and molecules are what cause thermal energy to grow as temperature rises.

In some cases, a substance's molecules will separate from one another and leave because the temperature is just so high. Unexpectedly, thermal energy also affects the states of matter. The radiator  has the higher thermal energy.

Therefore, the radiator has the higher thermal energy.

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Identify the major ionic species present in an aqueous solution of C6H12O6 (glucose).
A. 6 C-
, 12 H+
, 6 O–
B. 6 C+
, 12 H+
, 6 O2–
C. 6 CH2+, 6 O2–
D. C6
+
, 12 H+
, 6 O2–
E. no ions are present

Answers

Glucose is a molecular substance therefore, there are no ionic species in glucose.

Ionic substances dissolve in water to yield ions. Molecular substances do not produce ions in solution. The conductivity of ionic solutions owes to the presence of ions in solutions. Molecular solutions do not conduct electricity due to the absence of ions.

Glucose is a molecular substance hence they are are no ions present hence glucose does not conduct electricity.

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A 32.1 mole sample of gas has a temperature of 21 Celsius and a pressure of 2280.0 torr. What is the volume of the gas?

Answers

The volume of the gas is 27 ml

The calculation can be done as follows

The first step is to convert the pressure to atm

convert 2280 tors to atm

760 tors= 1 atm

= 2280/780

= 3 atm

The formula is

PV= nRT

The next step is to write out the parameters

Pressure= 3 atm

Temperature= 21 °C

no of moles= 32.1 mole

volume= ?

(r)constant= 8.314

3 × v= 32.1×8.314×21

3v= 81.080

V= 81.080/3

V= 27 ml

Hence the volume of the gas is 27 ml

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A containing vessel holds a gaseous mixture of nitrogen and butane. Thepressure in the vessel at 126.9 Cis 3.0 atm. At 0 C, the butane completelycondenses and the pressure drops to 1.0 atm. Calculate the mole fraction of nitrogenin the original gaseous mixture.

Answers

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

A vessel contains a gaseous mixture of nitrogen and butane. At 126.9 °C (400.1 K) the pressure is due to the mixture is 3.0 atm.

We can calculate the total number of moles using the ideal gas equation.

[tex]P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{3.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.091 mol/L \times V[/tex]

At 0 °C (273.15 K), the pressure due to the gaseous nitrogen is 1.0 atm.

We can calculate the moles of nitrogen using the ideal gas equation.

[tex]P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{1.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.030 mol/L \times V[/tex]

The mole fraction of nitrogen in the mixture is:

[tex]X(N_2) = \frac{0.030 mol/L \times V}{0.091 mol/L \times V} = 0.33[/tex]

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

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Elements that form diatomic molecules include
a oxygen
b hydrogen
C sodium
d two of the above

Answers

Answer:

D, two of the above, oxygen and hydrogen.

Explanation:

To solve this problem we can either use orbital stuff or common knowledge. Oxygen and hydrogen are known to form O2 and H2, while sodium forms metallic bonds between the atoms.

Help with this please :) will mark Brainlyist if right

Answers

Answer:

3

Explanation:

The partial pressure of CO2 gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO2 gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO2 dissolved in water is 1.65 x 103 atm, and the density of water is 1.0 g/cm3.

Answers

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. We can calculate the concentration of CO₂ using Henry's law.

[tex]C = k \times P = \frac{1.65 \times 10^{-3} M }{atm} \times 4.60 atm = 7.59 \times 10^{-3} M[/tex]

We can calculate the mass of CO₂ in 1.1 L considering its molar mass is 44.01 g/mol.

[tex]\frac{7.59 \times 10^{-3} mol}{L} \times 1.1 L \times \frac{44.01 g}{mol} = 0.367 g[/tex]

Now, we will repeat the same procedure for a partial pressure of 1.28 atm.

[tex]C = k \times P = \frac{1.65 \times 10^{-3} M }{atm} \times 1.28 atm = 2.11 \times 10^{-3} M[/tex]

[tex]\frac{2.11 \times 10^{-3} mol}{L} \times 1.1 L \times \frac{44.01 g}{mol} = 0.102 g[/tex]

The mass of CO₂ released will be equal to the difference in the masses at the different pressures.

[tex]m = 0.367 g - 0.102 g = 0.265 g[/tex]

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

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The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO₂ gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO₂ dissolved in water is 1.65 x 10⁻³ M/atm, and the density of water is 1.0 g/cm³.

An unknown hydrocarbon compound was analyzed for hydrogen by elemental analysis and results show that it contains 15.88 % H. What is the empirical formula

Answers

Answer:

C4H9

Explanation:

If H = 15.88%

Then C = 100.00 – 15.88 = 84.12

Divide each % value by respective atomic mass

H = 15.88/1 = 15.88

C = 84.12/12 = 7.01

Divide through by smaller value

H = 15.88/7.01 = 2.26

C = 7.01/7.01 = 1

Remove fraction , multiply by 4

H = 9

C = 4

Empirical formula = C4H9

The hydrocarbon could be ( C4H9)2 = C8H18 = octane.

Help pretty please :)

Answers

the answer is 15 bc you multiply the coefficient but the subscript

A city carrier resigns and trains as an office receptionist this is a person’s metabolism is likely to

Answers

Answer: results from a combination of a person’s metabolic heat and environmental heat

how to experiment titration ​

Answers

Answer:

Add a volume of a solution of known concentration is added to a volume of another solution in order to determine its concentration. Solutions in which a few drops of phenolphthalein have been added turn from colorless to brilliant pink as the solution turns from acidic to basic.

If you want the method:

Method

1) Use a pipette and pipette filler to add 25 cm3 of alkali solution to a clean conical flask.

2) Add a few drops of a suitable indicator and put the conical flask on a white tile.

3) Fill the burette with dilute acid. Flush the tap through to remove any air bubbles. Ensure the burette is vertical.

4) Slowly add the acid from the burette to the conical flask, swirling to mix. (The mixture may at first change colour, and then back again when swirled.)

5) Stop adding the acid when the end-point is reached (when the colour first permanently changes). Note the final volume reading.

6) Repeat steps 1 to 5 until three results are repeatable (in close agreement). Ideally these should lie within 0.10 cm3 of each other.

I hope it helps.

Answer:

To conduct a titration experiment, first fill the burette with an acid or base solution of known concentration. After that, take a burette reading from the top of the miniscus down to the bottom. Then, underneath the burette, place a flask containing an unknown concentration of acid or base. After that, fill the flask halfway with the appropriate indicator and shake it up. Add your titrate to the flask one drop at a time while stirring constantly. Continue to add the titrate until the color change is noticeable. Finally, take one more look at the burette to make sure everything is correct.

Explanation:

Hope it helps:)

Stems are important plant structures because they _________.
A.
are the main sites of photosynthesis for plants
B.
are the only site of water and nutrient transport
C.
allow plants to absorb water and nutrients from the soil
D.
give the plant structure and support

Answers

Answer:

c

Explanation:

allow plants to absorb water and nutrients from the soil

Balancing Chemical Equations
Based on the chemical equation, use the drop down menu to choose the coefficients that will balance the chemical
equation
(vbo,- (v]),
Will make Brainlyest plzzzz help!!!

Answers

Answer:

3O2→ 2O3

Explanation:

by multiplying 2 by 3 we get 6 on both sides

Suppose you are performing a titration. At the beginning of the titration, you read the titrant volume as 2.51 mL. After running the titration and reaching the endpoint, you read the titrant volume as 29.95 mL. What volume, in mL, of titrant was required for the titration

Answers

The volume of titrant required for the titration would be 27.44 mL

From the illustration, the initial titrant volume was 2.51 mL. This figure represents the initial reading on the burette.

In the same vein, the final volume of the titrant was 29.95 mL. This figure represents the final reading on the burette.

In order to get the volume of titrant used:

Volume of titrant used = final volume - initial volume

                             = 29.95 - 2.51

                                = 27.44 mL

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A carrot originally has a mass of 0.39g and after being left in a salt solution overnight it gained 0.3g. Calculate the percentage mass increase of the carrot.

Answers

Answer:

77%

Explanation:

The formula for finding percent change is change/original.

So, you have to do 0.3/0.39

You have to divide this to get 0.769 which can be rounded 0.77

0.77 as a percentage is 77%

So, the percentage mass increase of the carrot is 77%

leopard has canine teeth because

Answers

Explanation:

Leopards have 32 teeth, 4 of which are long, pointed canine teeth. Canine teeth are used to kill prey. Other teeth are for cutting flesh and grinding bone

Question 10
What is this structure name?
CH3 – CH2 - CH
CH – CH – CH2 - CH2
CH; CH – CH, -CH,
СН
CH3

Answers

cosh(-cosh(-CH

Simplify the expression using the symmetry of hyperbolic functions

cosh(cosh(CH))

Simplify the expression using the symmetry of hyperbolic functions

the answer is cosh(cosh(CH))

The collision theory state that?

Answers

Answer:

Collision theory states that molecules must collide to react. For most reactions, however, only a small fraction of collisions produce a reaction.

What is the percent composition of Be(OH)2?

Answers

Answer:

Ba 80.148%. H 1.77% O 18.657%

Help with this please

Answers

Answer:

12

Explanation:

There are 4 sulfur atoms in SO4

4×3=12

This means that it turns into 3×(SO4)

=3SO4

what is another extraction that uses gravity filtration and describe it​

Answers

Answer -ˋˏ ༻༺ ˎˊ-

A common use for gravity filtration is for separating anhydrous magnesium sulfate (MgSO4) from an organic solution that it has dried (Figure 1.68b). Anhydrous magnesium sulfate is powdery, and with swirling in an organic solvent creates a fine dispersal of particles like a snow globe.

To prepare 250.0 mL of 2.5 M KCl you will need to dilute _____ mL of 8.0 M KCl solution to a volume of 250.0 mL.

Answers

Answer:

78.125ml

Explanation:

Number of moles in 250ml of 2.5M KCl is (250÷1000)litres×2.5M so we divide these moles by 8M. The answer gotten will be in litres so multiply by 1000 to get it in ml

Place the events of a fight or flight situation in the correct order.

Question 3 options:

You spring into action

Your heart and lungs prepare to fight or run

You see the bear

Your brain sends signals to you adrenal and pituitary glands

Answers

Answer:

you see le bear

you brain sends signals

your heart and lungs receive said signals

spring to action

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