Answer:
40 m
Explanation:
4 m/s * 10 s = 40 m
( see how the 's' cancels out and you're left with "m" as your answer?)
What is one way that trees can be like fossil fuels? A. They do not produce carbon dioxide when burned. B. They both grow. C. We can use our supply fa … ster than they can be replenished. D. They can not be replenished at all.
Answer:
Answer C. But don't be surprised if it isn't.
Explanation:
You can't use D. Trees can be replenished. Maybe not as well as God planted them in the first place, but we can replenish them.
A is incorrect. when burned, trees will produce CO2. In fact, trees produce more CO2 when burned that do fossil fuels do
Fossil fuels don't grow. Their rate of discovery might, but they themselves don't grow. Not B
C is your only choice. The problem is that it is not entirely true. We can replenish trees. Whether enough trees can be used as a clean fuel and be replaced in amounts we are used is the question.
what is the relationship between Earth’s revolution and seasons
Answer:
The Earth's revolution not only affects but actually causes the temperature conditions that give us spring, summer, fall and winter seasons. Which season it is depends on whether you live in the Northern or Southern Hemisphere because the Earth's axis tilts toward one of the two as it moves around the sun.
Derive the Schrödinger's Time independent wave equation using kinetic energy and momentum.
Consider,
[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =m\langle v(t)\rangle=m\int_{-\infty}^{\infty}x\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial t}\Psi (x,t)+\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial t}\bigg\}dx}[/tex]
Multiply both sides by ih and simplification will yield
[tex]{:\implies \quad \displaystyle \sf ih\langle p\rangle =m\int_{-\infty}^{\infty}x\bigg[\Psi (x,t)\bigg\{\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi^{*}(x,t)}{\partial x^2}-V(x)\Psi^{*}(x,t)\bigg\}+\Psi^{*}(x,t)\bigg\{V(x)\Psi (x,t)-\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}\bigg\}\bigg]dx}[/tex]
Some simplification, Then Integrate by parts and then knowing the fact that the wave function vanishes for [tex]{\bf x\to \pm \infty}[/tex] will yield:
[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =\dfrac{ih}{2}\int_{-\infty}^{\infty}\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial x}\Psi (x,t)-\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}\bigg\}dx}[/tex]
Integrating by parts and knowing the same fact by some simplification will yield:
[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =-ih\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}dx}[/tex]
The momentum is thus contained within the wave function, so we can then deduce that:
[tex]{:\implies \quad \sf p\rightarrow -ih\dfrac{\partial}{\partial x}}[/tex]
[tex]{:\implies \quad \sf p^{n}\rightarrow \bigg(-ih\dfrac{\partial}{\partial x}\bigg)^{n}}[/tex]
[tex]{:\implies \therefore \quad \displaystyle \sf \langle p^{2}\rangle =-h^{2}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]
Now the kinetic energy
[tex]{:\implies \quad \displaystyle \sf \langle K\rangle =\dfrac{\langle p^{2}\rangle}{2m}=\dfrac{-h^2}{2m}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]
The classical formula for the total energy
[tex]{:\implies \quad \sf \dfrac{p^2}{2m}+V(x)=E}[/tex]
Multiplying this equation by [tex]{\sf \Psi (x,t)=\psi (x)exp\bigg(\dfrac{-iEt}{h}\bigg)}[/tex] and use the above equations and simplify it we will be having
[tex]{:\implies \quad \boxed{\bf{\dfrac{-h^2}{2m}\dfrac{d^{2}\psi (x)}{dx^{2}}+V(x)\psi (x)=E\psi (x)}}}[/tex]
This is the Famous Time-Independent Schrödinger wave equation
Note:- If I write all the explanation then the Answer box willn't allow me to submit the answer
Define the concept of heat. What is heat?
Answer:
In a simplest terms,
temperature is how hot or cold an object is, while heat is the energy that flows from a hotter object to cooler one
The diagram shows two liquid-in-glass thermometers.
Which has the greatest range? Explain how can you tell?
(Image attached)
Answer:
thermometer A
Explanation:
The range of a thermometer is the difference between the minimum and maximum temperatures that the thermometer can read.
∴ Range of thermometer A = 110° - (-10)° = 120°
Range of thermometer B = 50° - (-10)° = 60°
∴ Range of thermometer A is greatest.
Hope this helps!
The most effective way to reduce waste is to not create it in the first place.
True
False
Answer:
True
Explanation:
If there isnt any waste it would reduce the quantity however the waste that is present needs to be dealt with so......
How many hydrogen atoms can bond with this oxygen atom?
Answer:
2
Explanation:
there are two lonely pairs
2 hydrogens
Explanation:
oxygen has 3 lone pairs of electrons which do not take part in the bonding leaving two electrons in the outermost shell to be part of it, hydrogen has only one electron in it's outermost shell it needs one electron to be stable so two atoms of hydrogen bonds with one oxygen atom to to share there electrons to be stable.
a flashlight bulb with a 6.00 resistor uses 18.0W of power. What is the current through the bulb
a. I= 2.00A
b. I=3.00A
c. I=1.73A
d. I =0.333A
We need voltage first
P=V²/RV²=PRV²=18(6)V²=108V=√108V=10.4VApply oHMS law
V/I=RI=V/RI=10.4/6I=1.73AAnswer:
c. I = 1.73A
Explanation:
The formula for power :
P = VIThe formula for potential difference :
V = IRCalculating P by inputting the formula of V :
P = (IR)(I)P = I²RSolving using the given values :
18 = I² x 6I² = 3I = √3I = 1.73AIf the gravitational force disappeared , Earth would break away from its orbit and continue travelling in a ..............line into space.
What fitness components can impact a soccer players performance?
A) Dribbling, passing, shooting and heading
B) Physical, emotional, and cognitive factors
C) Cardiovascular, muscular strength/power, muscular endurance
D) None of the above
Answer:
C) Cardiovascular, muscular strength/power, muscular endurance
Explanation:
I did take the quiz
Answer:
C) Cardiovascular, muscular strength/power, muscular endurance
Explanation:
PLEASE HELP 100 POINTS! Please fill in the scale distance from sun and diversion factor, listing off the numbers works
Solved your another question same like this with scaling to Cm this time we go with metre(m)
Scale factor
1km=10³m1m=10^{-3}kmMercury
58000mVen us
108000mEarth
150000mMars
228000mJupiter
778000mSaturn
1430000mUranus
2870000mNeptune
4500000m!!!
MULTIPLE CHOICE QUESTION
If a simple machine has a MA of 5 and you lift an object UP 2 m, how far must you push the
object along the ramp's surface?
0.5 m
10 m
0.2 m
1 m
Answer:
0.5
Explanation:
I think it is this beacause if u have the answer you have that
3. A female minke whale has a core body temperature of 35°C and a core/blubber interface temperature of 29°C, with an average blubber thickness of 4.0 cm and thermal conductivity of 0.25 W/mK. At what rate is energy lost from the whale's core by conduction from the core/blubber interface through the blubber to the skin? Assume a skin temperature of 12°C and a total body area of 22 m².
The rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.
Rate of conduction of core/blubber interfaceThe rate of conduction of core/blubber interface is calculated as follows;
[tex]\frac{Q}{t} = \frac{kA\Delta T}{d}[/tex]
where;
k is thermal conductivity = 0.25 W/mkA is the total body area = 22 m²d is thickness of blubber = 4 cm = 0.04 mΔT is change in temperature[tex]\frac{Q}{t} = \frac{kA\Delta T}{d} = \frac{kA}{d} (\Delta Ta \ +\Delta Tb)\\\\\frac{Q}{t} = \frac{kA}{d} ((T_1- T_2 \ +\ T_2-T_3)\\\\\frac{Q}{t} = \frac{0.25 \times 22}{0.04} ( 35 - 29 \ + \ 29 - 12)\\\\\frac{Q}{t} = 137.5( 6 + 17)\\\\\frac{Q}{t} = 3,162.5 \ W[/tex]
Thus, the rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.
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Assume the roller coaster experiences no friction. What would be the speed of the roller
coaster at point F? Defend your answer in 1-2 sentences.
The roller coaster experiences no friction, the speed of the roller
coaster at point F is mathematically given as
v= 65.72 m/s
What would be the speed of the roller coaster at point F?Generally, the equation for the Mechanical enegy is is mathematically given as
ME = mgh + 1/2mv^2
Therefore
ME= 80*9.8*200 + 1/2*80*20^2
ME= 172800 J
In conclusion, the speed of the roller coaster at point F is
ME=1/2*m*V^2
172800 = 1/2*80*V^2
v= 65.72 m/s
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A wave that requires a medium through which to travel
chemical wave
mechanical wave
pitch
electromagnetic wave
Answer:
Explanation:
Answer: B mechanical waves.
Waves that do require a medium are called mechanical waves.
A block of mass 8 m can move without friction
on a horizontal table. This block is attached
to another block of mass 34 m by a cord that
passes over a frictionless pulley.
If the masses of the cord and the pulley
are negligible, what is the magnitude of the
acceleration of the descending block?
Answer:
Let M1 = 8 kg and M2 = 34 kg
F = M a = (M1 + M2) a
F = M2 g the net force accelerating the system
M2 g = (M1 + M2) a
a = M2 / (M1 + M2) g = 34 / (42) g = .81 g = 7.9 m/s^2
Which of the objects below would experience lift?
Answer:
the first one, The object moving through air
A fish pond appears to be 1m deep but when vewed vertically above the refractive Index of the Water on the pond is 1.5. calculate the real depth formed
Answer:
real depth / apparent depth = R.I.
Real depth = 1.5 x 1 = 1.5 m
what is the formula to calculate area of sphere
What is the de-Broglie wavelength of a 70kg person jogging at the rate of 2.70m/s. the mass of an electron is 9.11 x 10-28g, the speed of light is 3.00 x 108m/s, planks constant is 6.63 x 10-34js.
The de-Broglie wavelength of a person jogging at the rate of 2.70m/s is 3.5 x 10⁻³² m.
What is de-Broglie wavelength?De-Broglie wavelength is the ratio of Planck's constant h to the momentum of the electron p.
Momentum p = mass m x velocity v
Given is the mass of a person = 70kg, the speed of person 2.70m/s, Planck's constant h= 6.63 x 10⁻³⁴J.s
De- Broglie wavelength λ= h/mv
λ = 6.63 x 10⁻³⁴/ ( 70 x 2.70)
λ = 3.5 x 10⁻³² m
Thus the wavelength is 3.5 x 10⁻³² m.
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A dog barking at the sound of the postal carrier delivering mail is reacting to what type of cue?
A. External
B. Internal
Answer:
A. External
Explanation:
External stimulus includes touch/pain, vision, smell, taste, and sound.
What is standard one kilogram?
Explanation:
Standard one kilogram is the mass of a platinium- iridium cylinder having equal diameter at the height kept at 0⁰C at the International bureau of Weights and Measures, held in paris in France. The accurate copies of atandard one kilogram are prepared to Measures mass in different countries.....
[tex]....[/tex]
It is defined as the mass of a particular international prototype made of platinum-iridium and kept at the International Bureau of Weights and Measures. It was originally defined as the mass of one liter (10-3 cubic meter) of pure water. At the Earth's surface, a mass of 1 kg weighs approximately 2.20 pounds (lb).
Two metal conducting spheres are fixed in place and have charges of 0.00025C 0.00015 C.They are separated by a distance of 0.85 meters. What is the electric force between them
If an object is moving with a constant velocity of 700 cm/s and starts at an initial position of 20 cm at t=0, what will be the position at t= 0.9 s?
Calculate the de moglie Wavelength of election having kinetic energy of 400 ev
Answer:
613.5 pm
Explanation:
We know that de Broglie wavelength of an electron :
λ = 1.227 / √E nm
λ = 1.227 / √400 nm
λ = 1.227 / 20 nm
λ = 0.6135 nm
λ = 0.6135 x 10⁻⁹ m
λ = 613.5 x 10⁻¹² m
λ = 613.5 pm
Wavelength of election having kinetic energy of 400 ev.
Solution:WE = 1.227 / √election nmWE = 1.227 / √e400nmWE = 1.227 / √20nmWE = 0.6136nmWE = 0.6136 x 10-⁹mWE = 613.5 x 10-¹²mWE = 613.5by observing ___ we can determine what kind of atoms or molecules are present and their relative abundance
The kind of atoms or molecules are present and their relative abundance can be determined by observing wavelengths.
What is wavelength?Wavelength is the distance between adjacent crest or trough of the wave.
The light travels in the form of wave and particle. It behaves like both. Light ray consist energy of the photons. The kind of atoms or molecules present behave like particle and they have particular wavelength.
Thus, by observing wavelength , we can determine the kind of atoms or molecules are present and their relative abundance.
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Which landscape feature can be caused by chemical
weathering?
OU-shaped valley
O Basalt columns
O Limestone caves
Answer: Limestone Caves
Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.
1. An athlete runs 18 Kilometers in 2.5 hours, bicycles 150 Km in 4 hours, swims 10 Km in 3 hours.
Calculate:
a) the average speed for each leg of the triathlon
b) the average speed for the entire competition
The average speed is 18.73 km/hour.It is found as the ratio of the total distance and the total time taken.
What is the average speed?The total distance traveled by an object divided by the total time taken is the average speed.
The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.
The given data in the problem is;
Distance (d₁) = 18 Kilometers
Time (t₁) = 2.5 hours
Distance (d₂) = 150 Km
Time (t₂)= 4 hours
Distance (d₃) =10 Km
Time (t₃)=3 hours.
The average speed is found as;
[tex]\rm v_{avg}= \frac{Total \ distance }{Total \ time } \\\\ V_{avg}=\frac{18+150+10}{2.5+4+3} \\\\ v_{avg}= 18.73 \ km/hours[/tex]
Hence, the average speed is 18.73 km/hour.
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An object weighing 75 N is dropped from the top of a building and falls a distance of 28 m to the ground. How much work does gravity do on the object from the time it is dropped to the time it hits the ground?
How much work would a child do while pulling 12kg wagon distance of 4.3m with a 22N force?
[tex]\huge{\color{red}{\fbox{\textsf{\textbf{Answer}}}}} [/tex]
94.6J
Explanation:
Force (F) = 22N
mass (m) = 12kg
distance (S) = 4.3m
While
[tex] \sf Work \: done = Force \times distance[/tex]
This means
W = FS
while mass has no role in equation
Now substituting the required values
[tex] \sf W = 4.3 \times 22 \\ \\ \sf W = 94.6J[/tex]