How long must you wait (in half-lives) for a radioactive sample to drop to 2.10 % of its original activity?

Answers

Answer 1

Answer:

222/88 Ra

Explanation:

Answer 2

We have to wait 5.57 half lives for a radioactive sample to drop to 2.10 % of its original activity.

To find the tike taken for the activity, we need to know about radioactivity and half-life.

What is radioactivity?Radioactivity is the rate of decay of a radioactive substance with respect to time. Mathematically, radioactivity is given as

                R=R₀e^(-λ×t)

From the above expression time is given as

                 t= 1/λ ln(R₀/R)

What is half-life?Half-life is the time taken for decay of radioactive sample to half of its initial value. Mathematically, half-life= ln2 / λWhat is the expression of time of activity in term of half-life?From the half-life expression, 1/λ=half-life/ln2.Putting the value of 1/λ in the expression of time of activity, we have

    t=(half-life/ln2)×ln(R₀/R)

What is the time for radioactive sample to drop to 2.10 % of its original activity?

Here R=0.021R₀, so t= (half-life/ln2)×ln(R₀/0.021R₀)=5.57 half-lives

Thus, we can conclude that we have to wait 5.57 half lives for a radioactive sample to drop to 2.10 % of its original activity.

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Related Questions

Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are 0.50 L, 2.6 g/cm³; 0.25 L, 1.0 g/cm³; and 0.40 L, 0.80 g/cm³. What is the force on the bottom of the container due to these liquids? One liter = 1 L = 1000 cm³. (Ignore the contribution due to the atmosphere.)

Answers

Answer:

The force is  [tex]F = 18.33 \ N[/tex]

Explanation:

From the question we are told that

    The number of liquids is  n =  3

      The volume of the first liquid is [tex]V_1 = 0.50 L = 0.0005 \ m^3[/tex]

      The density of the first liquid is  [tex]\rho_1 = 2.6 \ g/cm^3[/tex]

      The volume of the second  liquid is [tex]V_2 = 0.25 L = 250\ cm^3[/tex]

      The density of the second liquid is  [tex]\rho_2 = 1.0 \ g/cm^3[/tex]

      The volume of the third  liquid is [tex]V_3 = 0.40 L = 400\ cm^3[/tex]

      The density of the  third  liquid is  [tex]\rho_3 = 0.80 \ g/cm^3[/tex]

Generally the force at the bottom of the container is mathematically represented  as

    [tex]F = m_t * g[/tex]

Here [tex]g = 980.665 \ cm/s^2[/tex]

Here  [tex]m_t[/tex]  is the total mass of all the liquid which is mathematically represented as

             [tex]m_t = ( V_1 * \rho_1 )+ ( V_2 * \rho_2)+ ( V_3 * \rho_3)[/tex]

=>         [tex]m_t = ( 500 * 2.6)+ ( 250 * 1.0 )+ ( 400 * 0.80 )[/tex]

=>         [tex]m_t = 1870 \ g[/tex]

So

       [tex]F = 1870 * 980.66[/tex]

=>   [tex]F = 1833843.55 \ g \cdot cm /s^2[/tex]

=>    [tex]F = 1833843.55 \ g \cdot cm /s^2 = \frac{1833843.55}{1000 * 100} kg \cdot m /s^2[/tex]

=>    [tex]F = 18.33 \ N[/tex]

When the displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position, what fraction of the total mechanical energy is kinetic energy?

Answers

Answer:

The ratio is  KE : TM  =  0.75

Explanation:

from the question we are told that

  The displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position

Generally the total mechanical  energy of the mass is mathematically represented as

        [tex]TM = \frac{1}{2} * k * A^2[/tex]

Here  k is the spring constant  ,  A is the total displacement of the  the mass  from maximum  compression to maximum extension of the spring

Generally this total mechanical energy is mathematically represented as

        [tex]TM = KE + PE[/tex]

=>     [tex]KE = TM - PE[/tex]

Here the potential  energy of the mass is mathematically represented as

     [tex]PE = \frac{1}{ 2} * k * [ x ]^2[/tex]

Here x is the displacement of the mass from maximum compression or extension of the spring to equilibrium position and the value is  

      [tex]x = \frac{A}{2}[/tex]

So

     [tex]PE = \frac{1}{ 2} * k * [ \frac{A}{2} ]^2[/tex]

So

      [tex]KE = \frac{1}{2} * k * A^2 - \frac{1}{2} * k * [\frac{A}{2} ]^2[/tex]

=>    [tex]KE = \frac{1}{2} * k * A^2 - \frac{1}{8} * k * A ^2[/tex]

=>    [tex]KE = 0.375 * k * A^2[/tex]

So the ratio of  [tex]KE : TM[/tex] is  mathematically represented as

       [tex]\frac{KE}{TM} = \frac{0.375 k A^2 }{0.5 k A^2}[/tex]

=>    [tex]\frac{KE}{TM} = 0.75[/tex]

A solid cylinder is released from the top of an inclined plane of height 0.50 m. From what height, in meters, on the incline should a solid sphere of the same mass and radius be released to have the same speed as the cylinder at the bottom of the hill?

Answers

Answer:

Explanation:

for rolling motion down the plane acceleration is given by the following expression

a = g sinθ / (1 + k² / R²)

here k is radius of gyration and R is radius of the object rolling down .

for cylinder I = 1/2 m R²

so k² = R² / 2

k² / R² = 1/2

a = g sinθ /( 1 + 1 / 2 )

= 2 / 3 x  g sinθ

v = √ 2 a s

= √ (2 x  2 / 3 x  g sinθ s )

= √ (4  / 3 x  g h  )

= √ (4  / 3 x  g x .5  )

= √ 2g / 3

for sphere  I = 2/5  m R²

so k² = 2/5 R²

k² / R² = 2 / 5  

a = g sinθ / (1 + 2 / 5)  

= 5 / 7  x  g sinθ

v = √ 2 a s

= √ (2 x  5 / 7  x  g sinθ s )

= √ (10/7  x  g h  )

Given

√ (10/7  x  g h  ) = √ 2g / 3

10/7  x  g h  = 2g / 3

h = 14 / 30 m

= .47 m .

What is the rms current flowing through a light bulb that uses an average power of 60.0 W when it is plugged into a wall receptacle supplying an rms voltage of 120.0 V?

Answers

Answer:

I = 0.5 A

Explanation:

Given that,

Average power of a light bulb, P = 60 W

The rms voltage supplied is 120 V

We need to find the value of rms current flowing through the light bulb. The relation between the power, voltage and current is given by :

P = VI

[tex]I=\dfrac{P}{V}\\\\I=\dfrac{60}{120}\\\\I=0.5\ A[/tex]

So, the rms value of current is 0.5 A.

if a person has a mass of 60 kg and a velocity of 2 m/s what is the magnitude of his momentum

Answers

Answer:

120 kg m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 60 × 2

We have the final answer as

120 kg m/s

Hope this helps you

compute the velocity of light in calcium fluoride which has dielectric constant of 2.056 .​

Answers

Answer:

idl low presure but de 2.518 has a 6 divide 8 equal di. ko alam?

Two blocks of masses 1.0 kg and 2.0 kg, respectively, are pushed by a constant applied force F across a horizontal frictionless table with constant acceleration such that the blocks remain in contact with each other, as shown above. The 1.0 kg block pushes the 2.0 kg block with a force of 2.0 N. The acceleration of the two blocks is

0

1.0 m/s2

1.5 m/s2

2.0 m/s2

3.0 m/s2

Answers

Answer:

1.0 m/s^2

Explanation: happy to help :)

Answer: [tex]1\ m/s^2[/tex]

Explanation:

Given

Masses of the block are [tex]m_1=1\ kg[/tex]  and

[tex]m_2=2\ kg[/tex]

Force applied by [tex]1\ kg[/tex] block on [tex]2\ kg[/tex] block is [tex]2\ N[/tex]

From the free body diagram of [tex]2\ kg[/tex] block, the net force on

[tex]\therefore m_2a=2\\\\\Rightarrow 2\times a=2\\\\\Rightarrow a=\dfrac{2}{2}\\\\\Rightarrow a=1\ m/s^2[/tex]

Thus, the acceleration of two blocks is [tex]1\ m/s^2[/tex]

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The sharper the sound is the smaller the frequency of a vibrating body true or false​

Answers

Answer:True....Explanation:Amplitude determines the loudness of sound. Loudness is proportional to the square of the amplitude of the vibrating body which produces sound. ... Less the frequency, deep is the sound.

If a ball has kinetic energy of 1000 joules and a speed of 5m/s, what is its mass?

Answers

Answer:

m = 80[kg]

Explanation:

The kinetic energy can be calculated by means of the following equation.

[tex]E_{k}=\frac{1}{2}*m*v^{2}[/tex]

where:

m = mass [kg]

v = velocity = 5 [m/s]

Ek = kinetic energy = 1000 [J]

Now replacing:

[tex]1000 = \frac{1}{2} *m*5^{2}\\2000 = 25*m\\m=80[kg][/tex]

The mass of a ball will be "80 kg".

Kinetic energy:

According to the question,

Kinetic energy, [tex]E_k[/tex] = 1000 Joules

Velocity, V = 5 m/s

As we know the formula,

→ Kinetic energy = [tex]\frac{1}{2}[/tex] × mass × (velocity)²

→      [tex]E_k = \frac{1}{2}[/tex] × m × v²

By substituting the values,

     [tex]1000= \frac{1}{2}\times m\times (5)^2[/tex]

[tex]1000\times 2=25\times m[/tex]      

     [tex]2000=25\times m[/tex]

         [tex]m = \frac{2000}{25}[/tex]

             [tex]= 80[/tex] kg

Thus the above answer is correct.

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A wave travels at 175 m/s along the x-axis.If the period of the periodic vibrations of the wave is 3.00 milliseconds,then what is the wavelength of the wave?
A) 25.5 cm
B) 35.6 cm
C) 42.9 cm
D) 49.5 cm
E) 52.5 cm

Answers

Answer:  

E) 52.5 cm

Explanation:

Step one:

given data

period T= 3 milliseconds= 0.003

velocity v= 175m/s

wave lenght λ=?

Step two:

we know that f=1/T

the expression relating period and wave lenght is

v=λ/T

λ=v*T

λ=175*0.002

λ=0.525m

to cm= 0.525*100

=52.5cm

The wavelength of the wave is E) 52.5 cm

The coulombic force between two ions is reduced to ______ of its original strength when the distance between them is quadrupled.

Answers

Answer:

1/16

Explanation:

According to the coulombs law, the force existing vetween the ions is expressed as;

F = kQq/r² .... 1

Q and q are the ions

r is the distance between the ions

If the distance between the ion is quadrupled, then;

F2 =  kQq/(4r)²

F2 =  kQq/16r² ... 2

Divide equation 2 by 1;

F2/F = kQq/16r² ÷ kQq/r²

F2/F = kQq/16r² × r²/kQq

F2/F = 1/16

F2 = 1/16 F

Therefore the coulombic force between two ions is reduced to 1/16 of its original strength when the distance between them is quadrupled.

Which of the following is the recommended amount of fats per meal for male clients

Answers

Answer:

44 grams- 55 grams through the whole day. Probably about 14.6 grams per meal.

Explanation:

Answer:

2 thumbs (ISSA Guide)

Explanation:

I need help understanding this question, so I know the arrow is traveling 80 meters per second, but it was launched from a starting point of 32 meters. I know for a fact an arrow does not have any thrust left at around 3 seconds of being in the air.

I just need someone to explain the questions and provide an answer to each.

Answers

Answer:

a) h(g) = 358,53 m

b) t = 8,16 s

c) t(t) = 16,71 s

Explanation:

Equations for vertical shooting are:

Vf = V₀ -  g * t   ;     h  =  V₀*t -  (1/2)*g*t²  ;    Vf² = V₀² - 2*g*h

And at maximum heigt Vf = 0 then

0 = V₀ - g * t

t = V₀/g                     V₀  = 80 m/s      and   g = 9,8 m/s²

t  =  80 / 9,8   (s)

t = 8,16 s

Then 8,16 s is the time to get maximum height

If we plug t = 8,16 (s) in equation  h  =  V₀*t -  (1/2)*g*t²

we get:     h (max)  =  (80)*8,16 - 0,5*9,8*(8,16)² (m)

h (max) = 652,8  -  326,27 m

h (max) = 326,53 m

Then relative to ground that height becomes

h(g) = 326,53 + 32

h(g) = 358,53 m

In order to get the time the arrow is in the air we proceed as follows:

a) for the arrow to be at the launched point will take the same time that from the launched point to the maximum height, and after that we have to find out the time the arrow takes from 32 m down to the ground level

Then  

t(t) = 8,16 + 8,16 + tₓ     (2)

Where tₓ  is the time from 32 m height to ground

h  =  V₀*tₓ -  (1/2)*g*tₓ²  but since the arrow now is going down then we change the sign of the second term on the right side of the equation

32 = (80)*tₓ  +  0,5 * 9,8 * tₓ²     Note that when the arrow is at 32 m height the speed is again V₀ = 80 m/s

32 = 80*tₓ  + 4,9*tₓ²

A second-degree equation for tₓ, solving it

4,9*tₓ² + 80*tₓ - 32 = 0

t₁,₂ = -80 ± √ 6400 + 627,2 / 9,8

t₁,₂ =( - 80 ± 83,8 ) / 9,8

there is not a negative time therefore we dismiss such solution and

t₁ = 3,8 / 9,8

t₁ = 0,39 s

And

t(t) = 8,16 + 8,16 + 0,39  s

t(t) = 16,71 s

PLEASE ans The question's in the pictures, please don't answer what already has answers. Only answer if you can finish both pages completely PLEASE I NEED HELP :(( if ur ans is relevant I will mark brainliest

Answers

Bro it’s no picture lol

*Urgent* I WILL GIVE BRAINLIEST
Select the answer that helps conserve the most energy.
O walking to school
O driving a car to school
Otaking the bus to school​

Answers

Answer:

walking to school

Explanation:

Driving a car to school

, and taking the bus to school​ both take up energy, unlike walking to school.

unless ur talking about energy, counting energy you produce and use to complete things, then it would be the 3rd one, taking the bus to school.

A child pulls a wagon across the grass so that it accelerates using a force of 50 N at an angle of 42 degrees above the ground. The loaded wagon has a mass of 12 kg. If the coefficient of friction between the wagon and grass is 0.64. What is the acceleration of the wagon? Describe the motion of the wagon.

Answers

Answer:

[tex]-1.398\ \text{m/s}^2[/tex]

Decelerating or slowing down

Explanation:

F = Force = 50 N

[tex]\theta[/tex] = Angle force is being applied = [tex]42^{\circ}[/tex]

[tex]\mu[/tex] = Coefficient of friction = 0.64

m = Mass of wagon = 12 kg

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Normal force is given by

[tex]N=mg-F\sin\theta[/tex]

Frictional force is given by

[tex]f=\mu N\\\Rightarrow f=\mu (mg-F\sin\theta)[/tex]

The force balance is given by

[tex]F\cos\theta-f=ma\\\Rightarrow \dfrac{F\cos\theta-\mu (mg-F\sin\theta)}{m}=a\\\Rightarrow a=\dfrac{50\times \cos42^{\circ}-0.64(12\times 9.81-50\times\sin42^{\circ})}{12}\\\Rightarrow a=-1.398\ \text{m/s}^2[/tex]

The acceleration of the wagon is [tex]-1.398\ \text{m/s}^2[/tex]. The negative sign indicates that the wagon is decelerating or slowing down.

The acceleration of the wagon is  [tex]-1.398 \;\rm m/s^{2}[/tex].

Given data:

The magnitude of pulling force is, F = 50 N.

The angle of inclination is, [tex]\theta = 42^{\circ}[/tex].

The mass of wagon wheel is, m = 12 kg.

Coefficient of friction between wagon and grass is, [tex]\mu =0.64[/tex].

The given problem is based on the concept of frictional force. The standard expression for the frictional force is,

[tex]f= \mu \times N[/tex]

Here, N is the normal force and its value is,

[tex]N=mg-Fsin \theta[/tex]

And the net force acting on wagon is,

[tex]F' = Fcos\theta -f\\\\ma = Fcos\theta -(\mu(mg-Fsin \theta))\\\\a = \dfrac{Fcos\theta -(\mu(mg-Fsin \theta))}{m}[/tex]

Here, a is the acceleration of wagon.

Solving as,

[tex]a = \dfrac{50 \times cos42 -(0.64(12 \times 9.8-(50 \times sin42)))}{12}\\\\a=-1.398 \;\rm m/s^{2}[/tex]

Thus, we can conclude that the acceleration of the wagon is  [tex]-1.398 \;\rm m/s^{2}[/tex].

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45.0g of a sample placed in a graduated cylinder causes the water level to rise from
25.0mL to 40.0mL. Density of the sample is?

Answers

Answer:

3g/mL

Explanation:

The density of a substance can be calculated using the formula;

Density = mass/volume

Where;

Density = g/mL

mass = grams (g)

volume = (mL)

According to this question, 45.0g of a sample placed in a graduated cylinder causes the water level to rise from

25.0mL to 40.0mL. This means that the volume of the sample is 40mL - 25mL = 15mL

Using D = m/v

D = 45/15

D = 3g/mL

Hence, the density of the sample is 3g/mL

A (10.0+A) g ice cube at -15.0oC is placed in (125 B) g of water at 48.0oC. Find the final temperature of the system when equilibrium is reached.
Specific heat of ice: 2.090 J/g K
Specific heat of water: 4.186 J/gK
Latent heat of fusion for water: 333 J/g

Answers

Answer: Final temperature is 34.15°C.

Explanation: When two objects have different temperature, they will exchange heat energy until there is no more net energy transfer between them. At that state, the objects are in thermal equilibrium.

So, when in equilibrium, the total heat flow must be zero, i.e.:

[tex]Q_{1}+Q_{2}=0[/tex]

In our case, there will be a change in state of ice into water, so total heat flow will be:

[tex]m_{1}c_{1}(T_{f}-T_{i})+m_{2}c_{2}(T_{f}-T_{i})+mL=0[/tex]

where

m₁ is mass of ice

m₂ is mass of water

c₁ is specific heat of ice

c₂ is specific heat of water

[tex]T_{f}[/tex] is final temperature

[tex]T_{i}[/tex] is initial temperature

L is latent heat fusion

Temperature is in Kelvin so the transformation from Celsius to Kelvin:

For ice:

T = -15 + 273 = 258K

For water:

T = 48 + 273 = 321K

Solving:

[tex]21(2.09)(T_{f}-258)+158(4.186)(T_{f}-321)+21(333)=0[/tex]

[tex]43.89T_{f}-11323.62+661.4T_{f}-212305.55+6993=0[/tex]

[tex]705.3T_{f}=216636.17[/tex]

[tex]T_{f}=[/tex] 307.15K

In Celsius:

[tex]T_{f}=[/tex] 34.15°C

Final temperature of the system when in equilibrium is 34.15°C

A rotating heavy wheel is used to store energy as kinetic energy. If it is designed to store 1.00 x 106 J of kinetic energy when rotating at 64 revolutions per second, find the moment of inertia (rotational inertia) of the wheel. (Hint: Start with the expression for rotational kinetic energy.)

Answers

We know, [tex]1\ rpm = \dfrac{2\pi}{60} \ rad/s[/tex] .

[tex]64\ rpm\ is = \dfrac{2\pi}{60}\times 64\ rad/s\\\\= \dfrac{32\pi}{15}\ rad/s[/tex]

We know, kinetic energy is given by :

[tex]K.E = \dfrac{I\omega^2}{2}\\\\I = \dfrac{2(K.E)}{\omega^2}\\\\I = \dfrac{2\times 10^6}{\dfrac{32}{15}\times \pi}\\\\I = 298415.52 \ kg \ m^2[/tex]

Hence, this is the required solution.

Please help true or false

Answers

Answer:

the answer is true.......

Any living thing is called an organism,no matter if it is one-celled or many-celled. True or False?.

Answers

Answer:

I think it's most likely true.

Explanation:

any organism has the properties of a living thing, which includes cells, whether it has one cell or many

Answer:

False

Explanation:

An organism is a living thing that is a single-celled life form

Which of the following is not an example of work being done on an object?

Pushing on a rock that will not move

Paddeling a canoe down a river

Lifting a bag of groceries

Throwing a ball across a field​

Answers

Answer:

Lifting a bag of groceries

Answer:

paddeling a canoe down a river :D or throwing a ball across a field

Explanation:

Collision Lab
This activity will help you meet these educational goals:

You will explain or predict phenomena by exploring qualitative relationships between variables.
You will use positive and negative numbers to represent quantities in real-world contexts.
Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write a brief evaluation of your work.
Activity
Open this collision simulator and click Introduction. You’ll use the simulator to explore and compare elastic collisions and inelastic collisions. The mass and starting velocity of the colliding objects are kept constant. Follow the instructions in each part, and then answer the questions that follow. Use the math review if you need help with adding and subtracting negative numbers.

Question 1: Elastic Collisions
In this question, you will investigate elastic (bouncy) collisions. Be sure that the slider is to the extreme right (elasticity 100%).

Part A
Click Show Values in the upper-right corner. Study the boxes on the screen. What are the mass and initial velocity of ball 1 and ball 2?

I NEED HELP!


Part B
Part B
Click Play, and watch the balls collide. Then click Pause. What are the final velocities of ball 1 and ball 2?


The number line shows the starting and ending velocities for ball 1. What’s the change in velocity of ball 1? Calculate the value mathematically, and check it using the number line.

a number line showing an ending velocity of -0.50 meter/second and a starting velocity of 1.00 meter/second

Answers

Answer:

Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

Explanation:

Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

What is Collision?

A collision is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.

The following are a few instances of physical encounters that scientists might classify as collisions. Legs of an insect are said to collide with a leaf when it falls on one.

Every contact of a cat's paws with the ground while it strides across a lawn is seen as a collision, as is every brush of its fur with a blade of grass.

Therefore, Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

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Was the Big Bang a loud explosion? Why?

Answers

Answer:

bc it was a universal explosion and It started the future

Explanation:

FACTS

Answer:

i wouldn't believe so.

Explanation:

because there was no room or air for the sound to move through. this is because of immense heat and the amount of hyperactive neutrons, electrons and protons clouding everywhere. This would mean that even if there was sound it would a. not travel far or b. go in a completely different direction than expected.

7. DRAW A PICTURE TO SHOW WORK.
Brandon buys a new Seadoo. He goes 12
km north from the beach. He jumps
wakes for 6 km to the east. Then chases
a boat 12 km south. He then turns and
goes 3 km to the West. What distance
did he cover? What was his
displacement?

Answers

Answer:
Distance covered 28 km
displacement is 22.8 km North-East
Explanation;

what is the efficiency of a machine that uses 102kj of enegery to do 98 kJ of work?

Answers

Answer: I got an increase of 306 kJ in internal energy.

Explanation: I used the 1st Law and the sign convention to get the answer in the screenshot.

(sorry if i'm wrong)

:(

The efficiency of the machine is 96.07%.

What is efficiency?

Efficiency can be defined as the ratio of work output to work input expressed in percentage.

To calculate the efficiency of the machine, we use the formula below.

Formula:

E(%) = (Wo/Wi)100.......... Equation 1

Where:

E(%) = Efficiency of the machineWi = Work input of the machineWo = Work output

From the question,

Given:

Wi = 102 kJWo = 98 kJ

Substitute these values into equation 1

E(%) = (98/102)100E(%) = 96.07%

Hence, the efficiency of the machine is 96.07%.

Learn more about efficiency here:

which of the following to all food chains depend on in an ecosystem

Answers

Answer:

The sun is the ultimate source of energy for all food chains. Through the process of photosynthesis, plants use light energy from the sun to make food energy. Energy flows, or is transferred through the system as one organism consumes another.

Question 25
The drawings below show four objects that are acted upon by different forces The direction of the forces are represented by the arrows, and the units of the forces are in newtons (N) Based on Newton's law of
inertia, which object is moving at a steady speed, assuming that all four objects are moving on a frictionless surface?

Answers

Answer:

The one with equal forces on both sides, D is your answer

Explanation:

A, 5 and 10 No

B 13 and 8 no

C 5 and 8 no

D 6 and 6 YES

Object 4 have steady speed. Object 4 have same force on both the sides of object. Same force is applied on both the sides.

What is steady speed?

Uniform or constant velocity describes a body's motion when there is no acceleration. A body's velocity is its rate of movement in a specific direction.

When running steadily, your exhaustion should be caused by the length of the run, not by your speed. A steady-state run pace, according to the McMillan Running website, is halfway between your current 30k and half-marathon pace. This speed should allow you to run for 25 to 75 minutes.

Therefore, Object 4 have steady speed. Object 4 have same force on both the sides of object. Same force is applied on both the sides.

To learn more about velocity, refer to the link:

https://brainly.com/question/18084516

#SPJ2

There is a bell at the top of a tower that is 45 m high. The bell weighs 190 N. The bell has ____________ energy.

Answers

Answer:

The bell has 8,550 Joule energy.

Explanation:

Gravitational Potential Energy

Gravitational potential energy is the energy stored in an object because of its height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where:

m = mass of the object

h  = height

g  = acceleration of gravity, or [tex]9.8 m/s^2[/tex]

Since the weight of an object of mass m can be calculated as:

W = m.g

The gravitational potential energy is:

U = W.h

The bell of weight W=190 N at the top of a tower is h=45 m high. Thus its energy is:

U = 190 N . 45 m

U = 8,550 Joule

The bell has 8,550 Joule energy.

What is the flow sensitivity of a biosensor?​

Answers

Answer:

Sensitivity of biosensor

The biosensor showed good linear correlation in the wide detection range of 0.001–2000 ng/mL with good sensitivity. In addition, it retained its biosensing property for seven days with high reproducibility

Explanation:

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