Ca(s) + 2H₂O(l) → Ca(OH)₂(aq) + H₂(g) 14. Calcium reacts with water according to the above reaction. What volume of hydrogen gas, at standard temperature and pressure, is produced from 0.200 moles of calcium?
According to the stoichiometry, 0.4 ml of hydrogen gas is produced from 0.2 moles of calcium .
What is stoichiometry?It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given problem, 1 mole of calcium produces 1 mole of hydrogen gas.
Given 0.2 moles of calcium , so mass of calcium by number of moles formula,mass=number of moles×molar mass=0.2×40.07=8.014 g
As 40.07 g of calcium produces 2 g hydrogen
∴8.014 g calcium produces 8.014×2/40.07=0.4 ml.
Thus, the volume of hydrogen gas produced from 0.2 moles of calcium at standard temperature and pressure is 0.4 ml.
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The x-ray has a frequency
of 1.4 x 1019 Hz. What is the
energy associated with one
x-ray? ►
The energy of the photon is 9.24 * 10^-15 J.
What is the energy?Let us recall that the energy has to do with the product of the frequency and the plank's constant. In thus case, we have the frequency of the photon and we have to find the energy of the photon and we have to do that from the following formula;
E = hf
E = energy of the photon
h = Plan's constant
f = frequency of the photon
Then;
E = 6.6 * 10^-34 Js * 1.4 x 10^19 Hz
E = 9.24 * 10^-15 J
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PLEASE HELP!
In a monomolecular reaction A->B , at t =250C, the initial concentration decrease at 25% in t =52 min. Calculate:
a) the constant rate;
b) the time after the initial concentration decrease with 75%;
c) the initial reaction rate, if the initial concentration of the reactant is 2.5 mol/L·s.
1) The rate at which this reaction occurs is obtained as 9.22 * 10^-5 s-1
2) The time that the reaction takes is obtained as 15033 s
3) The initial reaction rate is 9.22 * 10^-5 M
Can we find the rate of reaction?To obtain the rate of reaction is to find the rate at which the reactants move on to become products.
In this case there is reduction of the amount by 25% in 52 min.
Hence;
Initial concentration [A]o = [A]oFinal concentration = [A]o - 0.25 [A]o = 0.75 [A]oTime taken = 52 min or 3120 sUsing the approach of first order kinetics;
ln[A] = -kt + ln[A]0
k = -(ln[A] - ln[A]0)/t
k = - (ln0.75 [A]o/A]0)/3120
k = 9.22 * 10^-5 s-1
b) It was given in the question that;
[A] = [A]o - 0.75 [A]o = 0.25 [A]o
ln[A] = -kt + ln[A]0
t = -(ln[A] - ln[A]0)/k
t = - (ln0.25 [A]o/A]0)/9.22 * 10^-5
t = 15033 s
c) When the initial rate is is 2.5 mol/L·s
k = - (ln0.25 (2.5)/ln(2.5))/15033
k = 9.22 * 10^-5 M
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Calculate the volume in milliliters of 8.7 % (v/v) ethanol solution that contains 34.2 mL of ethanol.
v/v Concentration is a type of concentration in which we use to determine what would be the percentage of a certain volume of solute (the one with the least volume) by a certain volume of solution (the one with the most volume). The formula for this will be:
%v/v = volume of solute/volume of solution
In this question, we have:
%v/v = 8.7%, which is 0.087
volume of solute = 34.2 mL
Now we add these values into the formula:
0.087 = 34.2/v
v * 0.087 = 34.2
v = 34.2/0.087
v = 393 mL of ethanol solution that contains 34.2 mL of ethanol
Question 22 of 29 Which of the following reactions is an acid-base reaction? A) AgNO3(aq) + KF(aq) →→ AgF(s) + KNO3(aq) B) NH3(aq) + HF(aq) → NH4*(aq) + F(aq) C) NO₂ (aq) + Al(s) → NH3(g) + AIO₂ (aq) D) CH4(g) + 2O₂(g) → 2H₂O(g) + CO₂(g)
Answer:
good question but very hard
An acid-base reaction is a chemical reaction which takes place between an acid and a base. An example of acid-base reaction is AgNO₃(aq) + KF(aq) → AgF(s) + KNO₃(aq). Thus, the correct option is A.
What are acid-base reactions?An acid–base reaction is a chemical reaction which occurs between an acid and a base. This reaction can be used to determine the pH through the method of titration.
This reaction is a type of chemical reaction which involves the exchange of one or more hydrogen ions or protons (H⁺) between the two species which may be neutral (such as water, H₂O) or electrically charged species (ions such as ammonium, NH⁴⁺ and hydroxide, OH⁻; or carbonate, CO₃²⁻).
An example of acid-base reaction is AgNO₃(aq) + KF(aq) → AgF(s) + KNO₃(aq).
Therefore, the correct option is A.
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A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 75.0cm wide. The biologist estimates she will need 3700.L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank.
The pressure inside a tank with a volume can be calculated using Boyle's law. The pressure needed to compress gas of 3700 L is 16.75 atm.
What is Boyle's law.According to Boyle's law the pressure of a system is inversely proportional to its volume. The mathematical expression for a system with pressure Pa and volume V1 with its final pressure and volume P2 and V2 is written as follows:
P1V1 = P2V2.
The volume of the gas is 3700 L. Assume that it is measured in the atmospheric pressure 1 atm. The width of the spherical tank is 75 cm thus its radius is 37.5 cm.
Volume of the sphere = 4/3 πr³
= 4/3 × 3.14 × (37.5)³
= 220781 cm³ = 220.78 L.
Now the law can be applied as follows:
3700 L × 1 atm = 220.78 L × P2
P2 = 3700 / 220.78
= 16.75 atm.
Hence, the pressure needed to fill the air is 16.75 atm.
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Which best defines color?(1 point) Responses a chemical property of matter related to how a material interacts with different wavelengths of light a chemical property of matter related to how a material interacts with different wavelengths of light a physical property of matter related to a material’s ability to reflect light a physical property of matter related to a material’s ability to reflect light a chemical property of matter related to a material’s ability to reflect light a chemical property of matter related to a material’s ability to reflect light a physical property of matter related to how a material interacts with different wavelengths of light
Color is a physical property of matter related to a material’s ability to reflect light.
What is color?Color is a physical property of chemicals that in most cases comes from the excitation of electrons due to an absorption of energy performed by the chemical.
Color is that portion of the visible spectrum of light that is reflected back from a surface. A color can only be observed in the presence of light.
When light hits a surface, the particles of the object absorbs the colors in the light. However, not all colours are absorbed by the surface as some are reflected. The reflected color is seen as the color of that object.
The color of light coming from an object is what gives it color. Light travels into the eye to the retina located on the back of the eye. The human eye and brain work together to translate light into color.
Therefore, it can be said that a substance's ability to reflect light is color.
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The energy diagram shown represents the chemical reaction between solid ammonium chloride and solid barium hydroxide octahydrate:2NH4Cl(s)+Ba(OH)2⋅8H2O(s)→2NH3(aq)+BaCl2(aq)+10H2O(l)The ΔH for this reaction is 54.8 kJ . How much energy would be absorbed if 27.1 g of NH4Cl reacts?Express your answer with the appropriate units.Answer= (value)/(units)
According to the chemical equation, the reaction absorbs 54.8 kJ per 2 moles of NH4Cl because that's the stoichiometry coefficient of this molecule.
Now, we need to find the number of moles in each mole of NH4Cl.
[tex]\begin{gathered} N=14.0067 \\ H_4=4\cdot(1.00784)=4.03136 \\ Cl=35.453 \end{gathered}[/tex]Then, we add them to find the molar mass.
[tex]NH_4Cl=53.49\cdot\frac{g}{\text{mol}}[/tex]This means that 1 mole of NH4Cl equals 53.49 grams.
At last, we multiply the mass of NH4Cl (27.1 g) by two ratios, the first ratio is about the molar mass, and the second ratio is about the amount of heat per moles.
[tex]27.1g\cdot\frac{1\text{mol}}{53.49g}\cdot\frac{54.8kJ}{2\text{mol}}=\frac{1485.08}{106.98}kJ=13.88kJ[/tex]Therefore, the amount of energy that would be absorbed is 13.88 kJ.
A sample of gas with an initial volume of 28.4 L at a pressure of 724 mm Hg and a temperature of 303 K is compressed to a volume of 15.5 L and warmed to a temperature of 379 K. What is the final pressure of the gas?
To solve this question, we need to use the combined gas equation which is given as
[tex]\begin{gathered} \frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} \\ p=\text{pressure} \\ v=\text{volume} \\ t=\text{temperature} \end{gathered}[/tex]Now we should write down the given data
[tex]\begin{gathered} v_1=28.4l \\ p_1=724\operatorname{mm}hg \\ T_1=303K \\ v_2=15.5L \\ T_2=379K \\ p_2=\text{ ?} \end{gathered}[/tex]So, we would use the previous equation i wrote down.
[tex]\begin{gathered} \frac{p_1v_1}{t_1}=\frac{p_2v_2}{t_2} \\ \frac{724\times28.4}{303}=\frac{p_2\times15.5}{379} \\ 67.8600=\frac{p_2\times15.5}{379} \\ 15.5p_2=67.86\times379 \\ 15.5p_2=25718.94 \\ \text{divide both sides by the coefficent of p2} \\ \frac{15.5p_2}{15.5}=\frac{25718.94}{15.5} \\ p_2=1659.28\operatorname{mm}hg \end{gathered}[/tex]From the calculations above, the final pressure of the gas is 1659.28mmHg
18. If a compound has 6 carbons, 12 hydrogens, and 1 oxygen, what is its chemical formula?
a. C6H12OH
b. CsH6O12 120g as Josqmos as ed of slunnal
c. C6H₁1OH
d. 8C12HO
e. C7H12O3
Carbon, hydrogen, and oxygen are the main components. Glucose has the chemical formula C6H12O6. This indicates that there are six carbon atoms in each glucose molecule.
What is the name of a 6 carbon ring?
Image for number 18 What is the chemical formula of a molecule with 6 carbons, 12 hydrogens, and 1 oxygen? CsH6O12 120g as Josqmos as ed of slunnal; C6H12OH; and C6H11OH, 8C12HO, C7H12O3, and
Aromatic rings are hydrocarbons that contain benzene or another comparable ring structure. They are sometimes referred to as aromatic compounds or arenes. The chemical symbol for benzene, C6H6, is frequently represented as a ring of six carbon atoms with alternate double and single bonds: There are a few issues with this straightforward image, though.
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Which of the following elements belong to the s-block of the periodic table?
The 14 elements that make up the S-block are hydrogen (H), lithium (Li), helium (He), sodium (Na), beryllium (Be), potassium (K), magnesium (Mg), rubidium (Rb), calcium (Ca), cesium (Cs), strontium (Sr), francium (Fr), barium (Ba), and radium (Ra).
S-block, what is it?The Periodic Table's s-block elements are those in which the final electron enters the most outer s-orbital. Only two groups (1 & 2) are found in the s-block of the Periodic Table because the s-orbital can only hold two electrons.
What is the s-block formula?S block elements' common outer electrical configuration is ns(1-2).
Given that it contains sodium, beryllium, magnesium, and lithium, I am rather certain that it contains alkaline metals.
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Which diagram correctly shades the f-block of the periodic table in blue?
Answer
B.
Explanation
The diagram shown below correctly shades the S, P, D, F-block of the periodic table:
Comparing the above with the given options, the diagram which correctly shades the f-block of the periodic table in blue will be option B:
2HC2H3O2 + Na2CO3 = h20 + co3 + 2nac2h3o2
Answer:
Na2CO3 + 2HC2H3O2 → CO2 + H2O + 2NaC2H3O2
Explanation:
Label Each Compound With a VariableLabel each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.aNa2CO3 + bHC2H3O2 = cCO2 + dH2O + fNaC2H3O2Create a System of EquationsCreate an equation for each element (Na, C, O, H) where each term represents the number of atoms of the element in each reactant or product.Na: 2a + 0b = 0c + 0d + 1f
C: 1a + 2b = 1c + 0d + 2f
O: 3a + 2b = 2c + 1d + 2f
H: 0a + 4b = 0c + 2d + 3f
Solve For All VariablesUse substitution, gauss elimination, or a calculator to solve for each variable.
Simplify the result to get the lowest, whole integer values.
a = 1 (Na2CO3)
b = 2 (HC2H3O2)
c = 1 (CO2)
d = 1 (H2O)
f = 2 (NaC2H3O2)
Substitute Coefficients and Verify Result
Na2CO3 + 2HC2H3O2 = CO2 + H2O + 2NaC2H3O2
Reactants Products
Na 2 2 ✔️
C 5 5 ✔️
O 7 7 ✔️
H 8 8 ✔️
Since there is an equal number of each element in the reactants and products of Na2CO3 + 2HC2H3O2 = CO2 + H2O + 2NaC2H3O2, the equation is balanced.
The heat of vaporization of water is 540 calories per gram. Based on your calculations in
question 13, how many calories would be required to raise the same mass of water and
convert it from water liquid (95 0C) to water gas (1000C)?
Show your work for partial credit.
Step 1: Water raises from 95°C to 1000C
To convert 100.0 g of water at 20.0 °C to steam at 100.0 °C requires 259.5 kJ of energy.
For this problem, there are only two heats to consider:
q
1
= heat required to warm the water from 20.0 °C to 100.0 °C.
q
2
= heat required to vapourize the water to steam at 100 °C.
q
1
=
m
c
Δ
T
=
100.0 g × 4.184 J
∘
C
−
1
g
−
1
×
80.0
∘
C
=
33 472 J
q
2
=
m
Δ
H
vap
=
100.0 g × 2260 J⋅g
−
1
=
226 000 J
q
1
+
q
2
=
( 33 472 + 226 000) J = 259 472 J = 259.5 kJ
(4 significant figures)
1s² 2s²2p6 is the electron configuration of
The electron configuration 1s² 2s²2p6 is the element Neon.
Which four different electron configurations are there?One orbital may house a maximum of two electrons, and there are four different types of orbitals (s, p, d, and f). More electrons can be held in the p, d, and f orbitals since they contain various sublevels. As was said, each element's location on the periodic table determines the specific electron configuration of that element.
The octet rule states that an atom's outermost shell may hold no more than 8 electrons (except K shell which can accommodate maximum 2 electrons). Hence, potassium's electrical structure.
The quantity of valance electrons, which take part in the creation of a chemical bond, is found in an atom's outermost shell. The outermost shell of the atom's electrical structure contains 4 valance electrons.
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According to the following balanced reaction, how many moles of NO are formed from 3.75 moles of NO2 if there is plenty of water present? 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)
Taking into account the reaction stoichiometry, 1.25 moles of NO are formed from 3.75 moles of NO₂ if there is plenty of water present.
Reaction stoichiometryIn first place, the balanced reaction is:
3 NO₂ + H₂O → 2 HNO₃ + NO
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
NO₂: 3 molesH₂O: 1 molesHNO₃: 2 molesNO: 1 moleAmount of moles of NO formed
The following rule of three can be applied: if by reaction stoichiometry 3 moles of NO₂ form 1 mole of NO, 3.75 moles of NO₂ form how many moles of NO?
amount of moles of NO= (3.75 moles of NO₂× 1 mole of NO)÷ 3 moles of NO₂
amount of moles of NO= 1.25 moles
Finally, 1.25 moles of NO are formed.
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HELP!!!!!!! Calculating the average atomic mass from Isotope data
The relative atomic masses of the elements are:
Lead = 206.96 amu
Magnesium = 24.62 amu
Silicon = 28.08 amu
What is the relative atomic mass of the isotopes?The relative atomic masses of the given elements from their isotopes is determined as follows:
1. Lead:
Relative atomic mass = (203.973 * 0.014) + (205.974 * 0.236) + (206.759 * 0.226) + (207.9766 * 0.523)
Relative atomic mass = 206.96 amu
2. Magnesium:
Relative atomic mass = (23.985 * 79.99) + (24.986 * 10%) + (25.983 * 11.01%)
Relative atomic mass = 24.62 amu
3. Silicon:
Relative atomic mass = (27.977 * 92.21%) + (28.976 * 4.70%) + (29.973 * 3.09%)
Relative atomic mass = 28.08 amu
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The LD50 for Allura Red ingested for rats and rabbits is 10,000 mg/kg ( 10,00,g of Allura Red consumed per kg of a rats's or rabbit's mass proves lethal for 50% of test subject). Assuming the LD50 would be about the same for humans, use the results of your experiment to calculate how many candies if consumed in quick succession by a 150-lb.person could potentially kill the person.
The amount that could cause death in a 150 pound person is 675000 mg.
What is the LD 50?We define the LD 50 as the amount of the substance that could be used to cause mortality in about 50 percent of the population that is undergoing the test. In this case, we have been told that the LD50 for Allura Red ingested for rats and rabbits is 10,000 mg/kg an now we are asked for the LD 50 in a person that has a weight of 150-lb.
The first step in the work is to convert the mass of the person from pound to kilogram from here;
Given that
1 pound = 0.45 kilo gram
150 pounds = 150 pounds * 0.45 kilo gram/1 pound
= 67.5 Kg
Now, If
10,000 mg causes mortality in 1 Kg
x mg would cause mortality in 67.5 Kg
x = 675000 mg
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1.
What causes convection currents to form in the ocean?
Differences in water density
Differences in water depths
Differences in water quality
2.
Which of the following is an example of heat transfer through convection?
Feeling heat from a campfire
smoke rising from a volcano
A metal spoon getting warm from being in hot water
3.
In which direction does heat always flow?
From a larger object to a smaller object
From a cooler object to a warmer object
From a smaller object to a larger object
From a warmer object to a cooler object
4.
Which of the following is the best description of convection?
Heat transfer between two objects that are touching
Heat transfer through movement in fluids
Heat transfer through empty space
80 points. 20 points each question.
1. Convection currents are caused by Differences in water density.
2. Feeling heat from a campfire is an example of heat transfer through convection.
3. Heat always flow from a warmer object to a cooler object.
4. The best description of convection is Heat transfer through movement in fluids.
Differential heating leads to convection currents. Warm, less dense, lighter material rises while cool, more dense, heavier material sinks. Convection currents are patterns of circulation that are produced by this movement in the Earth's mantle, oceans, and atmosphere.
The transfer of heat between two bodies by currents of moving gas or fluid is known as convective heat transfer. In free convection, air or water rises and is replaced by a cooler parcel of air or water as it moves away from the hot body.
Heat energy will always transfer from the warmer object to the cooler object under normal circumstances and in nature. Up until the two substances reach the same temperature, heat energy will transfer between them. The term "thermal equilibrium" describes this.
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Solid calcium phosphate and aqueous sulfuric acid solution react to give calcium sulfate, which comes out of solution as a solid. The other product is phosphoric acid, which remains in solution. Write an equilibrium equation for the reaction using complete formulas for the compounds with phase labels.
Answer: i also need help on the same question :(
Explanation:
Which period 2 element would the 4th ionization energy be much larger than the 3rd ionization energy?
Period 2 element would the 4th ionization energy be much larger than the 3rd ionization energy is Boron.
Boron belongs to period second. atomic no. of boron is 5 and the electronic configuration is given as :
B₅ = 1s² 2s² 3p₁
The 1st ionization energy = 800.6
the 2nd ionization energy = 2427.1
the 3rd ionization energy = 3659.7
the 4th ionization energy = 25025.8
So. we can see that the 3rd ionization energy is much lower than 4th ionization energy because after removing the 3rd electron from 2s boron will attain the stable electronic configuration of helium. now to remove electron from filled orbital it will require much larger energy the 3rd ionization energy.
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consider the reaction 2clf3+2nh3=n2+6hf+cl2 calculate hf for clf3 .
H=-1196 kJ
The heat of formation of the chlorine tri fluorde is -1513 kJ.
What is the enthalpy?The enthalpy refers to the heat that is absorbed or emitted in a reaction. We know that if the heat is absorbed the enthalpy of the reaction is positive but if heat is evolved, the enthalpy of the reaction is negative.
Now we can find the heat of the formation of chlorine tri fluoride a follows;
We have to use the formula;
Sum of enthalpy of formation of products - Sum of enthalpy of formation of reactants
-1196 =(0 + 271 + 0) - (x + (- 46))
-1196 = 271 - x + 46
-1196 = 317 - x
x = -1196 - 317
x = -1513 kJ
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Missing parts;
Consider the reaction 2ClF3 (g) + 2NH3 (g) → 6HF (g) + N2 (g) + Cl2 (g) △H-_1196 kJ Given the following enthalpies of formation, calculate AHf for CIF3 (9) NH3 (g)- 46 kJ/mol HF 9)271 kJ/mol kJ
PEASE HELP PLEASE!? List and describe the substrates and products of TCA cycle
Acetyl group, oxaloacetic acid, coA, citric acid, and other elements are the substates and products required to initiate and finish the TCA cycle.
What are the the substrates and products of TCA cycle?Oxaloacetate and acetyl CoA undergo an enzymatic aldol addition reaction to form citrate at the start of the TCA cycle.To produce (2R,3S)-isocitrate, a dehydration-hydration sequence is used to isomerize the citrate.Ketoglutarate is produced by additional enzymatic oxidation and decarboxylation.The enzyme decarboxylates and oxidises 2-ketoglutarate once more to produce succinyl-CoAGuanosine diphosphate (GDP) is phosphorylated to guanosine triphosphate in conjunction with the hydrolysis of this metabolite to succinate (GTP).Fumarate is produced by succinate dehydrogenase, an enzyme that is dependent on the flavin adenine dinucleotide (FAD).Fumarate, catalysed by fumarase, is converted to L-malate following stereospecific hydration.Finally, malate dehydrogenase catalyses the TCA cycle's closing step, which is the NAD-coupled oxidation of L-malate to oxaloacetate. This completes the cycle.Learn more about TCA cycle
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Help me indicate whether OXYGEN will gain or lose electrons to get a full outer shell and how many electrons they will need to gain or lose
Oxygen have 6 valence electrons. It needs only two electrons to get a full outer shell.
Thus, oxygen will gain two electrons.
A 25.0 mL solution of HBr is neutralized with 13.7 mL of 0.230 M Ba(OH)₂. What is the concentration of the original HBr solution?
The concentration of the original HBr solution that has 25.0 mL solution neutralized with 13.7 mL of 0.230 M Ba(OH)₂ is 0.126M.
How to calculate concentration?Molarity is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.
Molarity can be calculated by using the following formula;
C₁V₁ = C₂V₂
Where;
C₁ = initial concentrationV₁ = initial volumeC₂ = final concentrationV₂ = final volumeAccording to this question, 25.0 mL solution of HBr is neutralized with 13.7 mL of 0.230 M Ba(OH)₂. The original concentration can be calculated as follows:
25 × x = 0.230 × 13.7
25x = 3.151
x = 0.126M
Therefore, 0.126M is the concentration of HBr solution.
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A molecule of CH four consist of blank carbon atoms in blank hydrogen atoms
The correct way of presenting the given molecule is CH₄, with the number subscripted.
The subscripted numbers indicates how many of the previous element are in the molecule.
If there are no subscripted number after a given element, it means it is a implicit 1.
So, in CH₄, there is no number after C, so it is implicit it is a 1, and after the H there are a 4. This means that we have 1 C atom and 4 H atoms.
C is carbon and H is hydrogen, so:
A molecule of CH₄ consists of 1 carbon atom and 4 hydrogen atoms.
Helppppppppppppppppppp
Answer:
See my photo. I promise it's right.
Calculate the molarity of a carbonic acid solution given the following titration results: 47.00 mL of the carbonic acid solution was neutralized to a phenolphthalein endpoint with 23.82 mL of 0.1250 M ammonium hydroxide.
The molarity of carbonic acid is 0.063M when titration is done between 47.00mL carbonic acid and 23.82mL of 0.1250M ammonium hydroxide.
What is titration?Titration is a technique by which we know the concentration of unknown solution using titration of this solution with solution whose concentration is known. To know the end point we use phenolphthalein as indicator. End point is a point where completion of reaction happen
Mathematically
moles or carbonic acid =moles of ammonium hydroxide
[tex]M_{1} V_{1} =M_{2} V_{2} \\M_{1} =Molarity of carbonic acid\\V_{1} =Volume of carbonic acid\\M_{2} =Molarity of ammonium hydroxide\\V_{2} =Volume of ammonium hydroxide[/tex]
Substituting all values
[tex]M_{1}[/tex]=(0.1250×23.82)÷47.00
[tex]M_{1}[/tex]=0.063M
Thus the molarity of carbonic acid is 0.063M
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Calculate the mass of forsterite Mg2SiO4 that contains a million ×1.00106 oxygen atoms. Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.
The mass of forsterite Mg₂SiO₄ that contains a million, 1×10⁶ oxygen atoms is 5.819×10⁻¹⁷ g
How to determine the mass of Mg₂SiO₄We'll begin by obtinig the mass of oxygen that contains 1×10⁶ atoms. This can be obtained as follow:
From Avogadro's hypothesis,
6.02×10²³ atoms = 1 mole of oxygen.
But
1 mole of oxygen = 16 g
Thus,
6.02×10²³ atoms = 16 g of oxygen.
Therefore,
1×10⁶ atoms = (1×10⁶ atoms × 16 g) / 6.02×10²³ atoms
1×10⁶ atoms = 2.66×10⁻¹⁷ g of oxygen
Finally, we shall determine the mass of Mg₂SiO₄ that contains 1×10⁶ atoms (i.e 2.66×10⁻¹⁷ g) of oxygen. This can be obtained as follow:
1 mole of Mg₂SiO₄ = (24 × 2) + 28 + (16 × 4) = 140 gmass of O in 1 mole of Mg₂SiO₄ = 16 × 4 = 64 gThus, we can say:
64 g of oxygen is present in 140 g of Mg₂SiO₄.
Therefore,
2.66×10⁻¹⁷ g of oxygen will be present in = (2.66×10⁻¹⁷ × 140) / 64 = 5.819×10⁻¹⁷ g of Mg₂SiO₄
Thus, the mass of Mg₂SiO₄ is 5.819×10⁻¹⁷ g
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How many grams of magnesium (Mg, 24.30g/mol) are in 7.43 x 1022 atoms of Mg?7.43x 1022 atoms Mg| 1 mole Mg 24.30 g Mg16.02x 1023 atoms Mg/ 1 mole Mg[?] grams Mg
To calculate this, we can use fractions for equivalent amounts.
So, we have the number of atoms, using the Avogadro's Constant, we know that 1 mol of Mg is approximately 6.02 x 10^23, so:
[tex]\frac{1\text{mol Mg}}{6.02\times10^{23}\text{atoms Mg}}=1[/tex]And since we have the number of atoms of Mg, we can convert to mol of Mg by multiplying by this fraction.
Now, from mol of Mg we can convert to mass using the molar mass of 24.30 g/mol. It says that 24.30 g og Mg is equivalent to 1 mol, so:
[tex]\frac{24.30\text{g Mg}}{1\text{mol Mg}}=1[/tex]So, we have:
[tex]7.43\times10^{22}\text{atom Mg}\cdot\frac{1\text{mol Mg}}{6.02\times10^{23}\text{atom Mg}}\cdot\frac{24.30\text{g Mg}}{1\text{mol Mg}}[/tex]Notice that this is presented in a table in the question, so we can now just multiply all of them:
[tex]7.43\times10^{22}\text{atom Mg}\cdot\frac{1\text{mol Mg}}{6.02\times10^{23}\text{atom Mg}}\cdot\frac{24.30\text{g Mg}}{1\text{mol Mg}}=\frac{7.43\times10^{22}\cdot24.30\text{g Mg}}{6.02\times10^{23}}=2.999\text{g Mg}\approx3.00\text{g Mg}[/tex]Thus, this is equivalent of approximately 3.00 g of Mg.