How many atoms...

NAC2H3O2

Answer:

1. thermal energy

2. the particles within the system will have greater motion, and the temp will increase.

3. attractions occur due to electrostatic forces. when particles move fast enough, these forces can no longer keep particles together.

4. for a phase change from a solid to liquid, the bonds do not break completely and particles call still slide past each other.

5. a sample of liquid benzene at 80°C and a sample of gaseous benzene at 80°C

Explanation:

hope this helps

Temperature is a measure of the average kinetic energy of molecules.

The particles of a substance are in constant random motion. As more thermal energy is added to the particles, the motion of the particles increases. If more energy is added to a system during phase change, the particles within the system will have greater motion, and the temperature will increase.

Attractions between particles is greater when the kinetic energy of molecules decreases. Therefore, a statement that correctly describes how attractions that hold particles break is; "attractions due to electrostatic forces. When particles move fast enough, these forces can no longer keep particles together."

The rubber analogy is commonly used to describe covalent bonds where stretching of bonds occur. This analogy is not apt in describing phase changes because for a phase change from a solid to liquid, the bonds do not break completely and particles call still slide past each other.

The average kinetic energy of molecules depend on temperature hence a  sample of liquid benzene at 80°C and a sample of gaseous benzene at 80°C will have the same average kinetic energy.

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Explanation:

Tabel di bawah ini memberikan data tentang sampel gas. Manakah dari berikut ini yang dapat ditentukan dengan menggunakan data? Volume 2,0 L Tekanan 3,6 atm Suhu 323 K komposisi kimia gas suhu kondensasi gas jumlah mol dalam sampel jarak antar molekul gas dalam sampel

Explanation:

....

해바라기해바라기해바라기해바라기

Answer:

translation to English please

Answer:

6.02 × 1023

The molar mass from the periodic table is 32.00 g O2 = 1 mol O2, and by definition, 1 mol O2 = 6.02 × 1023 molecules O2.

Answer:

skip and read this story then complete the problem

What other solvent could have been used?

Answer:

There is no atmosphere outside the space station, so there is nothing to vibrate, therefor there is no sound.you better install your earphones in your space suit.

Explanation:

Imagine that you are just outside the International Space Station (ISS) orbiting Earth, working in space. You brought your speaker with you so you could listen to some music while you work. You find the right song, and you hit play. What do you hear? Write your response below in complete sentences.

Include the answers to these questions in your response: •

Would you hear your music? •

Why or why not?

You need matter that can vibrate and finally vibrate your ear drum in order to transmit sound waves. that you hear

There is no atmosphere outside the space station, so there is nothing to vibrate, therefor there is no sound.you better install your earphones in your space suit.

You will hear no music as there is no sound in the space because there are no molecules to vibrate.

Sound is generally considered a form of energy that consists of mechanical waves which travel in a medium. Sound is produced by a vibrating body which generates a disturbance in the medium and the medium helps to propagate the sound.

The medium of sound transmission is air where the molecules in the air are in the form of longitudinal waves. The vibrating body generates a disturbance in the rarefaction and compression of waves. The disturbance of the particles of the surrounding medium produces sound.

Sound always requires a medium to be traveled and reach its destination. As space does not have any medium for sound to generate disturbance. Space has a vacuum due to which sound cannot be heard in space.

Therefore, you will hear no music when you play a song in the space.

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Answer:

teeth chewing food

Explanation:

When teeth chews food it change its state from hard solid to fine substance that can be easily digested by the body i guess

A is the petal and b is the leaf. I think.

Answer:

C

Explanation:

Mixture of 2 or more metals is a compound

example is water which is made up of hydrogen and oxygen.

Due to errors in volume and moles measurement by the student, the true value of the molar gas constant is less than the obtained value.

The Percent error is 1.39%

Percent error is defined as the ratio of error and true value of a measurement expressed as a percentage.

Error = |true value - measured value|

The error in the students measurement = |0.08206 - 0.0832|

Error = 0.00114

Percent error = (0.00114/0.08206) × 100%

Percent error = 1.39%

The formula to determine the molar gas constant R is given below:

[tex]R = \frac{PV}{nT}[/tex]

Since the student value is higher than the true value, the possible sources of error include:

Therefore, the true value of the molar gas constant is less than the obtained value.

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Answer:

an abundant rock-forming mineral typically occurring as colorless or pale-colored crystals and consisting of aluminosilicates of potassium, sodium, and calcium.

Explanation:

Answer:

Feldspars are a group of rock-forming aluminium tectosilicate minerals, containing sodium, calcium, potassium or berium

This problem is asking for the consumption of silver ions when silver nitrate is reacted with copper. In such a case, since no masses are given, we can use the following from similar problems:

Mass of empty beaker: 110.000 g

Mass of beaker with silver nitrate (after all additions) and copper: 331.634 g.

Mass of beaker with silver: 113.395 g.

This means we can write the following chemical equation:

[tex]Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag[/tex]

And thus calculate the mass of silver nitrate that will produce the following mass of silver:

[tex]m_{Ag}^{produced}=113.395g-110.000g=3.395g[/tex]

Next, we use the 2:2 mole ratio of silver to silver nitrate (silver ions source):

[tex]3.395gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg} *\frac{169.87gAgNO_3}{1molAgNO_3} = 5.35gAgNO_3[/tex]

The step will be defined for the given mass of available silver nitrate which will be compared to 5.35 g (consumed mass) to see if they are the same (all consumed) or different (partial consumption).

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Considering the reaction stoichiometry, the enthalpy change if enough propane was burned to give off 12 moles of carbon dioxide gas is 8228 kJ.

The balanced reaction is:

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l)

The heat of combustion of propane, C₃H₈, is -2057 kJ/mol. This is, 2057 kJ is released for every 1 mol C₃H₈.

So to determine the enthalpy change if enough propane was burned to emit 12 moles of carbon dioxide, you must take into account the stoichiometry of the reaction.

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 3 moles of CO₂ are produced by 1 mole of C₃H₈, 12 moles of CO₂ are produced by how many moles of C₃H₈?

[tex]amount of moles of C_{3} H_{8} =\frac{12 moles of CO_{2}x1 mole of C_{3} H_{8} }{3 moles of CO_{2}}[/tex]

amount of moles of C₃H₈= 4 moles

So to determine the enthalpy change, you can apply the following rule of three: If for each mole of C₃H₈ 2057 kJ are released, for 4 moles of C₃H₈ how much heat is released?

[tex]Heat released=\frac{4 molesx2057 kJ}{1 mole}[/tex]

Heat released= 8228 kJ

The enthalpy change if enough propane was burned to give off 12 moles of carbon dioxide gas is 8228 kJ.

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Answer:

particals that have no mass

Explanation:

key word maseless

Answer:

40 hopefully right

Explanation:

Answer:

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Answer:

Hey mate.....

Explanation:

This is ur answer....

Hope it helps!

Brainliest pls!

Follow me! :D

Answer:

1

Explanation:

Answer:

Um.....

Explanation:

Thanks for the pts

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Anwser:

Research scientific principles involved in water availability.

Explanation:

Before building or investment you always want to see and know what your up against and what the best way to help or solve is. Researching why there's a problem in water availability or/and the principals to water availability will help you see what the problem is with what's happening to and around the process and it's environment.

Answer:

6,25 gm

Explanation:

4. The half-life of C-14 is 30 years. If a scientist had 100.0 g at the beginning, how

many grams would be left after 120 years has elapsed?

10 years would be 120/30 = 4 half lives0

s0 the fraction of c-14 left would be four (1/2) multiplied together

1/2 X 1/2 X 1/2 X 1/2 = 1/16

SO 1/16 OF THE 100.0 gm would be left

100.0/16  = 6,25 gm

Answer:

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Explanation:

Explanation:

A more dense liquid stays lower while a less dense liquid stays higher. since water is 13.6 times less dense than mercury, the column for a barometer using water would have to be 13.6 times taller.

Answer:

It is most likely to be an asteroid

The wavelength of the radio station broadcasting at 520 megahertz is 0.58m.

HOW TO CALCULATE WAVELENGTH:

λ = v/f

Where;

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Answer:

James Chadwick conducted an experiment where he assailed the element Beryllium with alpha particles that came from the radioactive decay of Polunium. The experiment results showed highly penetrating radiation emitted from the Beryllium. In this, Chadwick proposed that radiation consisted of uncharged particles, which were later founded as neutrons.

In the first dissociation of H2A:

molarity    H2A(aq)↔ (HA)^-(aq) + H^+(aq)

initial                0.05 m          0 m           0 m

change               -x                 +x               +x

equilibrium    0.05-x               x                 x

we can neglect X in [H2A] as it so small compared to the 0.05

so by substitution in Ka equation:

Ka1 = [HA][H] / [H2A]

2.2x10^-6 = X^2/0.05

X = √(2.2x10^-6)*(0.05)= 1.1x10^-7

X=   3.32x10^-4 m

∴ [H2A] = 0.05 - 3.32x10^-4 = 0.0497 m

[HA] = 3.32x10^-4 m

[H] = 3.32x10^-4 m

the second dissociation of H2A: when ka2 = 8.2x10^-9

                          HA-(aq)     ↔ A^2- (aq) + H+(aq)

at equilibrium   3.32x10^-4        y              3.32x10^-4

Ka2           = [H+][A^2-] / [HA]

8.2x10^-9 = Y(3.32x10^-4)/(3.32x10^-4)

∴y = 8.2x10^-9 m

∴[A] = 8.2x10^-9 m

PH= -㏒[H+]

   = -㏒(3.32x10^-4)= 3.479  

[A]=8.2x10^-9 m

[H2A] = 0.0497 ≈ 0.05 m