How many Joules of heat are needed to raise the temperature from 50°C
to 95°C for 35 g of water?

Answers

Answer 1

Answer:

Q = 6583.5 J

Explanation:

Given data:

Heat required = ?

Mass of water = 35 g

Initial temperature = 50°C

Final temperature = 95°C

Solution:

Specific heat capacity of water is 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = 95°C - 50°C

ΔT  = 45°C

Q = 35 g×4.18 j/g.°C × 45°C

Q = 6583.5 J


Related Questions

The object in this photo belongs to which major part of the Earth system?
O A. Hydrosphere
O B. Biosphere
O C. Atmosphere
O D. Geosphere

Answers

Answer:

B

Explanation:

Answer: B the biosphere it is a animal and a living thing

Explanation:

How many moles of CO2 are present in 14.6 L of CO2 gas at STP

Answers

Answer:

0.65mole of CO₂

Explanation:

Given parameters:

Volume of CO₂ = 14.6L

Unknown:

Number of moles of CO₂ = ?

Solution:

To solve this problem, we must understand that a mole of a gas occupies a volume of 22.4L at STP;

           1 mole of gas occupies  22.4L of volume at STP;

           y mole of CO₂ will occupy 14.6L of volume at STP

                    22.4y  = 14.6

                          y = [tex]\frac{14.6}{22.4}[/tex]  = 0.65mole of CO₂

Select the correct electron configuration for Cu (Z = 29) Answer a. [Ar]4s13d10 b. [Ar]4s24p63d3 c. [Ar]4s23d0 d. [Ar]4s24d9 e. [Ar]5s24d9

Answers

Answer:

a. [Ar]4s13d10.

Explanation:

Hello!

In this case, since the electron configuration allows us to arrange the electrons moving around the atom of an element and equal the atomic number, we can write the electron configuration of copper as shown below:

[tex]Cu^{29}=1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^9[/tex]

However, in terms of the argon's electron configuration, which is:

[tex]Ar^{18}=1s^2,2s^2,2p^6,3s^2,3p^6[/tex]

We infer that the electron configuration of copper in terms of that of argon's is:

[tex]Cu^{29}=[Ar]4s^2,3d^9[/tex]

Therefore, the answer is a. [Ar]4s13d10 because the 4s² can be written as 4s¹ and therefore the 3d⁹ is changed to 3d¹⁰.

Best regards!

Conner conducts the following experiment. He places a bell in a vacuum jar. During his first trial, he leaves the bell outside the jar. He sees the bell vibrating and he hears the bell ringing. During his second trial, he removes the air from the vacuum jar. He sees the bell vibrating but he does not hear the abell ringing. What does this experiment tell the student about waves?


A.Light waves are electromagnetic waves and sound waves are mechanical waves.

B.Light waves are mechanical waves and sound waves are electromagnetic waves.

C.Both light waves and sound waves need a medium to travel through.

D.Neither light nor sound waves need a medium to travel through.

Answers

Answer:

A. Light waves are electromagnetic waves and sound waves are mechanical waves.

Explanation:

The experiment is clear proof that light waves are electromagnetic waves and that sound waves are mechanical waves.

Electromagnetic waves are waves that do not require a material medium for their propagation. Although, with material medium they can also be propagated. This is why in both set up, the bell still vibrates. Mechanical waves are dependent on the material in the medium. They cannot be propagated in vacuum. There is no matter present in vacuum to help transmit the sound waves.

Is it possible to use both renewable and nonrenewable resources together?

Answers

Answer:

use socratic it helps me get A+

How many days are in an Earth year?

Answers

365 ! hope this helped

Calculate the mass of calcium carbonate produced if 15.2 mL of 0.306 M K2CO3 is reacted with 17.0 mL of 0.295 M CaCl2.

Answers

Answer:

[tex]m_{CaCO_3}=0.465g[/tex]

Explanation:

Hello!

In this case, since the reaction between two aqueous solutions may turn out in the production of a solid precipitate, for potassium carbonate and calcium chloride, calcium carbonate is precipitated out as shown below:

[tex]CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)[/tex]

Now, since the two reactants are in a 1:1 mole ratio, we infer they react in the same proportion, thus we compute the reacting moles, considering the used volumes of those molar solutions:

[tex]n_{K_2CO_3}=0.0152L*0.306mol/L=0.00465mol\\\\n_{CaCl_2}=0.0170*0.295mol/L=0.00502mol[/tex]

Thus, since just 0.00465 mol out of 0.00502 moles of calcium chloride are consumed, the potassium carbonate is the limiting reactant, therefore the mass of yielded calcium carbonate (molar mass = 100.09 g/mol) is:

[tex]m_{CaCO_3}=0.00465molK_2CO_3*\frac{1molCaCO_3}{1molK_2CO_3} *\frac{100.09gCaCO_3}{1molCaCO_3}\\\\m_{CaCO_3}=0.465g[/tex]

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Determine the energy in joules of a photon whose frequency is 3.05 ✕ 10^17 Hz.

Answers

Answer:

The energy of photon is 20.22×10⁻¹⁷ J

Explanation:

Given data:

Frequency of photon = 3.05×10¹⁷ Hz

Energy of photon = ?

Solution:

Formula:

E = hf

h = planck's constant = 6.63×10⁻³⁴ Js

Now we will put the values in formula.

E =   6.63×10⁻³⁴ Js × 3.05×10¹⁷ Hz

    Hz = s⁻¹

E = 20.22×10⁻¹⁷ J

Thus, the energy of photon is 20.22×10⁻¹⁷ J

Need help please
Balancing the equation in the pic

Answers

2KClO3=2KCl+3O2
The equation

Remember this quote?!

Answers

Answer:

Yes

Explanation:

GIVING BRAINLIST ASAP

As the ice melts into liquid water, what happens to the kinetic energy of the particles in the sample?

Answers

Answer:

Increases

Explanation:

As ice melts into liquid water, the kinetic energy of the particles increases.

This is because to melt ices, heat energy is supplied.

The sum total of all the average speed of the particles in a substance is the heat energy. Heat is a form of kinetic energy. As more heat is added, the particles moves rapidly and the kinetic energy increase.

How many hydrogen atoms are in a molecule of table sugar (C12H22011)?
O A. 11
B. 22
C. 12
D. 45

Answers

Hydrogen atoms are in a molecule of table sugar (C₁₂H₂₂O₁₁) is 22

An atom is a particle of matter that uniquely defines a chemical element and in the table sugar molecule the formula is C₁₂H₂₂O₁₁ then the hydrogen atoms are present in the molecule is 22 and it is used for the adding sweetness to your coffee and baking and used as the food manufacture in various food and drink products due to its unique properties that add to the appearance

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How many Cl atoms are present in 307.62 grams of ccl4?

Answers

Answer: atomic mass of cl = 35.5 amu.

molar mass of ccl4 = (12) +4 (35.5)

= 12 + 142

= 154 amu.

mass of ccl4 = 385 g

no. of moles present = 385 / 154 = 2.5 mole

so, 2.5 mole of ccl4 is present in 385 grams .

Explanation:

In chemistry, the formula weight is a quantity computed by multiplying the atomic weight (in atomic mass units) of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

Using the chemical formula of the compound and the periodic table of elements, we can add up the atomic weights and calculate molecular weight of the substance.

If the formula used in calculating molar mass is the molecular formula, the formula weight computed is the molecular weight. The percentage by weight of any atom or group of atoms in a compound can be computed by dividing the total weight of the atom (or group of atoms) in the formula by the formula weight and multiplying by 100.

The atomic weights used on this site come from NIST, the National Institute of Standards and Technology. We use the most common isotopes. This is how to calculate molar mass (average molecular weight), which is based on isotropically weighted averages. This is not the same as molecular mass, which is the mass of a single molecule of well-defined isotopes. For bulk stoichiometric calculations, we are usually determining molar mass, which may also be called standard atomic weight or average atomic mass.

A common request on this site is to convert grams to moles. To complete this calculation, you have to know what substance you are trying to convert. The reason is that the molar mass of the substance affects the conversion. This site explains how to find molar mass.

Formula weights are especially useful in determining the relative weights of reagents and products in a chemical reaction. These relative weights computed from the chemical equation are sometimes called equation weights.

Finding molar mass starts with units of grams per mole (g/mol). When calculating molecular weight of a chemical compound, it tells us how many grams are in one mole of that substance. The formula weight is simply the weight in atomic mass

Write the dissolution reaction for ammonium phosphate in water. Be sure to specify the state of each reactant and product.

Answers

Answer:

The equation showing the dissolving of solid ammonium phosphate in water is: (NH4)3 PO4 (s) → 3NH4 +1 (aq) + PO4 -3 (aq).

Explanation:

solution of nitric acid is 60% with the specific gravity 1.15 calculate the volume of the seed required to prepare 250 ml semi normal solution​

Answers

Answer:

This dilution problem uses the equation

M

a

V

a

=

M

b

V

b

M

a

= 6.77M - the initial molarity (concentration)

V

a

= 15.00 mL - the initial volume

M

b

= 1.50 M - the desired molarity (concentration)

V

b

= (15.00 + x mL) - the volume of the desired solution

(6.77 M) (15.00 mL) = (1.50 M)(15.00 mL + x )

101.55 M mL= 22.5 M mL + 1.50x M

101.55 M mL - 22.5 M mL = 1.50x M

79.05 M mL = 1.50 M

79.05 M mL / 1.50 M = x

52.7 mL = x

59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M.

Explanation:

A 7.2 L balloon at 2 atm of pressure has its pressure reduced to 0.5 atm. What is the new size of the balloon, in liters?

Answers

Explanation:

using Boyles law: which shows the relationship between pressure and volume, when temperature Is kept constant

P1V1 = P2V2

2 x 7.2 = 0.5 x V2

14.4 = 0.5 x V2

V2 = 14.4/0.5 = 28.8 L

Hence the new size of the balloon in litres is 28.8

Please help me it’s due today at 6:00pm will mark the brainiest and more points please help me

Answers

Answer:

C.

Explanation:

The same amount of force reacts to you

Balance the following equation:
B203(s) + HF(l) => BF3(g) + H20(l)

Answers

20 B203(s) + 12180 HF(l) = 4060 BF3(g) + 609 H20(l)

A piston compresses the air in the cylinder by doing 97.0 J of work on the air. As a result, the air gives off 191.0 J of heat to the surroundings. If the system is the air in the cylinder, what is the change in its internal energy?

Answers

Answer:

[tex]\Delta U=-94.0J[/tex]

Explanation:

Hello!

In this case, since the first law of thermodynamics allows us to understand how the energy behaves when heat and work are involved during a process, we can mathematically define it as:

[tex]Q-W=\Delta U[/tex]

Whereas Q is the heat added to the system, W the work done by the system and ΔU the change in the internal energy, we can notice that since 97.0 J of work are done on the system it would be negative and the given off heat is also heat due to the used convention; therefore the change in its internal energy turns out:

[tex]-191.0J-(-97.0J)=\Delta U\\\\\Delta U=-94.0J[/tex]

Best regards!

Explain how density is used to calculate the number of atoms in a mole.

Answers

Answer: The equation is fairly simple. The number of atoms of ANY substance in a volume is: # of atoms = N * (density) * volume / (Molecular Weight). N is a constant called Avogadro's number and its equal to 6.022*1023 atoms/mole.

Explanation:

A sample of NaOH (sodium hydroxide) contains a small amount of Na2CO3 (sodium carbonate). For titration to the phenolphthalein endpoint, 0.200 g of this sample requires 23.98 mL of 0.100 M HCl. An additional 0.700 mL of 0.100 M HCl is required to reach the methyl orange endpoint. What is the percentage of Na2CO3 by mass in the sample?
Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

1.86% Na₂CO₃

Explanation:

The additional volume that is required to reach endpoint with methyl orange indicator is due the presence of carbonate (Calculated as sodium carbonate). The reaction is:

Na₂CO₃ + 2HCl → H₂O + CO₂ + 2NaCl

Thus, we need to obtain moles of HCl and, using the reaction, solve for moles of sodium carbonate, its mass and percentage using molar mass of Na₂CO₃: 106g/mol.

Moles HCl:

0.700mL = 0.700x10⁻³L * (0.100mol / L) = 7.00x10⁻⁵moles HCl

Moles Na₂CO₃:

7.00x10⁻⁵moles HCl * (1mol Na₂CO₃ / 2 mol HCl) = 3.5x10⁻⁵ moles Na₂CO₃

Mass:

3.5x10⁻⁵ moles Na₂CO₃ * (106g / mol) = 0.00371g Na₂CO₃

Percentage:

0.00371g Na₂CO₃ / 0.200g * 100 =

1.86% Na₂CO₃

How does mass of an object affects velocity?

Answers

Answer: The amount of matter in a particle or object.

Consider the reaction of N aHCO3 with an acid, HA. How many grams of NaHCO3 are required to produce 1.25 g of CO2 ?

Answers

Answer:

2.33g of NaHCO3

Explanation:

The balanced equation of the reaction is;

2NaHCO3  + 2HA --> 2CO2  +  2H2O + 2NaA

From the reaction above;

2 mol of NaHCO3 produces 2 mol of CO2

using mass = number of moles * molar mass

Mass = 2 * 84  = 164g of NaHCO3

Mass of CO2 = 2 * 44 = 88g of CO2

This means 164g of NaHCO3 produced 88g of CO2

How many grams of NaHCO3 would then produce 1.25g of CO2?

164 = 88

x = 1.25

upon solving for x;

x = 2.33g

The reaction of sodium bicarbonate with  acid produces equivalent moles of carbon dioxide. The mass of sodium bicarbonate in the given reaction is 2.352 grams.

What is stoichiometric law?

The stoichiometric law is used for the determination of the moles of each product or reactant, from the stoichiometric coefficient of the balanced chemical equation.

The balanced chemical equation for the reaction of sodium bicarbonate with HA acid is :

[tex]\rm 2\;NaHCO_2\;+\;2\;HA\;\rightarrow\;2\;CO_2\;+\;2\;H_2O\;+\;2\;NaA[/tex]

From the stoichiometric law, 2 moles of carbon dioxide is produced from 2 moles of sodium bicarbonate.

The moles of carbon dioxide in 1.25 grams is:

[tex]\rm Moles=\dfrac{mass}{molar\;mass}\\\\ Moles\;CO_2=\dfrac{1.25\;g}{44\;g/mol} \\\\Moles\;CO_2=0.028\;mol[/tex]

From the stoichiometric law, the moles of sodium bicarbonate required is:

[tex]\rm 2\;mol\;CO_2=2\;mol\;NaHCO_3\\\\0.028\;mol\;CO_2=\dfrac{2\;mol}{2\;mol}\;\times\;0.028\;mol\;NaHCO_3\\\\ 0.028\;mol\;CO_2=0.028\;mol\;NaHCO_3[/tex]

The mass of sodium bicarbonate required is given as:

[tex]\rm Mass=Moles\;\times\;Molar\;mass\\Mass\;NaHCO_3=0.028\;mol\;\times\;84\;g/mol\\Mass\;NaHCO_3=2.352\;g[/tex]

The mass of sodium bicarbonate in the reaction is 2.352 grams.

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how many moles would 1.00 x10^23 molecules of methane represent

Answers

Answer:

Explanation:

1 x 10²³ molecules of methane

6.02 x 10²³ molecules of methane = 1 mole of methane

10²³ molecules of methane = 1 / 6.02 moles of methane

= .166 moles .

The moles of methane that contain 1 [tex]\rm \times\;10^2^3[/tex] molecule have been 0.166 mol.

The number of molecules of a compound can be given by the Avagadro number. The number of molecules in a mole of the compound has been equal to the Avagadro number. The Avagadro number has been constant with a value of 6.023 [tex]\rm \times\;10^2^3[/tex].

6.023 [tex]\rm \times\;10^2^3[/tex] molecules = 1 mole.

The given molecules of methane have been = 1 [tex]\rm \times\;10^2^3[/tex] .

The moles of given molecules will be:

6.023 [tex]\rm \times\;10^2^3[/tex] molecules = 1 mole.

1 [tex]\rm \times\;10^2^3[/tex] molecules = [tex]\rm \dfrac{1}{6.023\;\times\;10^2^3}\;\times\;1.0\;\times\;10^2^3[/tex] moles.

1 [tex]\rm \times\;10^2^3[/tex] molecules = 0.166 moles.

The moles of methane that contain 1 [tex]\rm \times\;10^2^3[/tex] molecule have been 0.166 mol.

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is there anything smaller than an atom

Answers

Answer:

subatomic particles are actually small than atoms

Yes, particles such as protons, neutrons, and electrons that make up the atom are smaller than atoms.

BRAINLIEST TO CORRECT FASTTT

3. Which of the following atoms would have the highest first ionization energy?
a. Li
b. Be
c. Na
d. Mg

4. What is the name of the phenomenon in which electrons are ejected from the surface of a metal when light shines on the metal?
a. Photoelectric effect
b. Diffraction
c. Quantization
d. Aufbau principle

10. How many core electrons does this element have? 1s2 2s2 2p5
a. 9
b. 4
c. 2
d. 5

11. The electron configuration for a chlorine atom is: 1s2 2s2 2p6 3s2 3p5. What electron configuration represents the electrons that make up only the valence electrons for a chlorine atom?
a. 1s^2 2s^2 2p^6
b. 3s^2 3p^5
c. 1s^2
d. 1s^2 2s^2 2p^6 3s^2

Answers

Answer:

3. d. Mg 4. a. Photoelectric effect 10. c. 2 11. b. 3s^2 3p^5

Explanation:

What is the ability to do work defined as?
OA. pressure
OB. energy
Ос.
force
OD
temperature
R

Answers

Answer:

It would be B

Explanation:

Which of the following pairs of elements would form an ionic bond? (Select all that
apply.)
T Pand cl
Hand N
u Kand F
Mg and I

Answers

Answer:t pans

Explanation:it’s the cool thing

2.83 kJ are added to a sample of water at 100°C and it completely vaporizes. What is the
mass of the water?
general formula

Answers

Answer:

general formula: Q=mHv, 2.83=m(2260), 2260/1000=2.26 , 2.83/2.26=1.25 kJ

Explanation:

What attracts the electrons from the atom on the left?


The neutrons from the atom on the left


The electrons from the atom on the right


The protons from the atom on the right


The neutrons from the atom on the right

Answers

I think it is c.) the protons from the atom on the right.

According to the placement of elements in the periodic table and the atomic structure, protons from atom on right will attract electrons from atom on left.

What is periodic table?

Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.

It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.

Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.

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