How Many Minutes Can Mammals
Stay Underwater?
Hippopotamus
15
Muskrat
12
Platypus
10
Polar Bear
2
Sea Cow
16
Seal
22
Use the information given in the table. A hippopotamus can stay underwater 3 times as long as a sea otter can. Which of the
following equations can be used to find how long a sea otter can stay underwater?
3-X = 15
15 - x = 3
b. 3x = 15
d. 15x = 3
a.
C.

Answer:

63 papers total.

Step-by-step explanation:

3 piles, 21 papers a pile, 3*21 =63.

Answer:

63

Step-by-step explanation:

because 3x21 is 63

Answer:

19

Step-by-step explanation:

Answer:

19

because it has only two factors and prime has only two factors

Solution:

Note that:

Substitute the value of W into the formula (Area = LW).

Option C is correct.

Answer:

D

Step-by-step explanation:

i already did the test

Answer:

d

Step-by-step explanation:

Answer:

[tex]x - 4y = - 6 \: ......(1) \\ \\ 2x + 3y = 10 \: .......(2)[/tex]

from equation (1)

[tex]x - 4y = - 6 \\ \\ 4y = x + 6 \\ \\ y = \frac{x + 6}{4} [/tex]

Substitute " y " in equation (2)

[tex]2x + 3y = 10 \\ \\ 2x + 3( \frac{x + 6}{4} ) = 10 \\ \\ 2x +( \frac{3x + 18}{4} ) = 10 \\ \\ \\ \frac{8x + 3x + 18}{4} = 10 \\ \\ \\ 8x + 3x + 18 = 10 \times 4 \\ \\ 11x + 18 = 40 \\ \\ 11x = 40 - 18 \\ 11x = 22 \\ \\ x = \frac{22}{11} \\ \\ x = 2[/tex]

[tex]y = \frac{x + 6}{4} \\ \\ y = \frac{2 + 6}{4} \\ \\ y = \frac{8}{4} \\ \\ y = 2[/tex]

Answer:

K/q = p if you're taking about the inverse proportions

Answer:

  D. II only

Step-by-step explanation:

The square root equations will each have only one real solution. (Sometimes, there is an extraneous solution if the variable is also found outside the radical.)

The rational equation will result in a quadratic when it is simplified. It will have two real solutions.

Only equation II will have two real solutions.

Answer:

2/3

Step-by-step explanation:

Answer:

At least one student is 23: Must be true

Some students are younger than 15: Could be true

Step-by-step explanation:

Statement 1: A median is a number in the middle for ex. 1, 2, 3, 4, 5 in this example 3 is the median. Another ex could be 1, 2, 3, 4, 5, 6. This time you would have to add (3 + 4), divide by 2, which equals 3.5.

Since there are 21 students in class making it an odd number 23 must be true.

Statement 2: Based on the information I am given, I would say could be true because the difference between the oldest and the median is 29 - 23 = 6 so it could be true.

Answer:

1) At least one (the 11th) student is 23 (years old), Must be true

2) Some students are younger than 15 Could be true

Step by step explanation:

1) The given parameters are;

The number of student in the class = 21

The median age of the student = 23

The age of the oldest student = 29

Therefore, given that the median age = The age of the (n + 1)/2 the student

Where;

n = The number of student in the class = 21

The median age = The age of the (21 + 1)/2 th = 11 th student, when the age of the students are arranged in increasing order, therefore, we have;

At least one (the 11th) student is 23 (years old), Must be true

2) Given that there are 10 students with ages equal to or lower than the  median age, and the difference between the median age and the age of the oldest student = 29 - 23 = 6 years, we have;

Some students are younger than 15 Could be true

Solution:

The expression "a(b-c)" is an example of distributive property. To simplify it, simply multiply a by the terms inside the bracket.

Simplifying the distributive property.

Hence, the simplified expression is ab - ac.

We can use the distributive law to simplify it or factor it but more

[tex]\\ \tt\hookrightarrow a(b-c)[/tex]

[tex]\\ \tt\hookrightarrow a(b)-a(c)[/tex]

[tex]\\ \tt\hookrightarrow ab-ac[/tex]

Answer:

Don't know the answer but good luck?

Step-by-step explanation:

#1

Answers are

Only this rest are not possible

#2

#3

[tex]\huge\textbf{Hey there!}[/tex]

[tex]\mathsf{x^4\ \bullet \ x^{-7}}\\\\\mathsf{\rightarrow x\bullet x\bullet x\bullet x (\dfrac{1}{x\bullet x \bullet x \bullet x\bullet x \bullet x \bullet x})}\\\\\mathsf{\star \heartsuit \ - 7 = \bf -3 \ \star \heartsuit}\\\\\mathsf{\rightarrow \dfrac{1}{x\bullet x \bullet x}}\\\\\mathsf{\approx \dfrac{1}{x^3}}\\\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{\dfrac{1}{x^3}}}}\huge\checkmark[/tex]

[tex]\huge\textbf{Good luck on your assignment \& enjoy}\\\huge\textbf{your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Percentage

100:50 x 20 = 40

well, the longer piece is clearly the latter, so let's firstly convert the mixed fractions to improper fractions and then subtract.

[tex]\stackrel{mixed}{14\frac{3}{8}}\implies \cfrac{14\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{115}{8}} ~\hfill \stackrel{mixed}{25\frac{1}{16}}\implies \cfrac{25\cdot 16+1}{16}\implies \stackrel{improper}{\cfrac{401}{16}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{401}{16}~~ - ~~\cfrac{115}{8}\implies \implies \cfrac{(1)401~~ - ~~(2)115}{\underset{\textit{using this LCD}}{16}}\implies \cfrac{171}{16}\implies 10\frac{11}{16}[/tex]

Answer:

It will cost 124 cents to buy 31 inches of wire.

Step-by-step explanation:

12 inches costs 48 cents

1 inches will cost her [tex]\frac{48}{12}[/tex] → 4 cents

Then 31 inches will cost: 31 * 4 → 124 cents

Answer:

Step-by-step explanation:

Solve using ratios since this is a proportional relationship:

Answer:

Negative relationship

Step-by-step explanation:

It is going in a negative direction.

Pls mark brainliest :)

Answer:

[tex]\red{ m\angle B= 121\degree}\\\\\purple{AD=23\: units}[/tex]

Step-by-step explanation:

Quadrilateral ABCD is a parallelogram.

opposite angles of a parallelogram are equal in measure.

[tex]\implies (10x-19)\degree=(9x-5)\degree[/tex]

[tex]\implies 10x-19=9x-5[/tex]

[tex]\implies 10x-9x=19-5[/tex]

[tex]\implies x=14[/tex]

[tex]m\angle B= (9x-5)\degree[/tex]

[tex]\implies m\angle B= (9*14-5)\degree[/tex]

[tex]\implies m\angle B= (126-5)\degree[/tex]

[tex]\huge\implies m\angle B= 121\degree[/tex]

Opposite sides of a parallelogram are equal.

3y - 1 = y + 15

3y - y = 15 + 1

2y = 16

y = 16/2

y = 8

AD = 3y - 1 = 3*8 - 1 = 24 - 1

AD = 23

Given :

Solution:

hope it helped!

Answer:

Step-by-step explanation:

Given:

Find B + C - A:

A = [tex]3x² - 7x + 8[/tex]

B = [tex]x² + 8x - 3[/tex]

C = [tex]-5x²-3x + 2[/tex]

Lets find B + C - A :

→ [tex]B + C - A[/tex]

→ [tex]x² + 8x - 3+ (- 5x²-3x + 2)-(3x² - 7x + 8)[/tex]

→ [tex]x² + 8x - 3-5x² - 3x + 2-3x² + 7x - 8[/tex]

→[tex] (1-5-3)x² + (8 -3 + 7)x+ (-3 + 2 - 8)[/tex]

→ [tex]- 7x² + 12x - 9[/tex]

Answer:

240

Step-by-step explanation:

because adding the 45's 4 times then adding 60.

sorry if im wrong btw.

Answer:

you would have $2.98 left

Step-by-step explanation:

$4.59 x 2=9.18

3.00 x 3=9.00

$1.99 x 2=3.98

$9.18+$9.00+$3.98=22.16

$25.00-$22.16 = $2.89

Answer:

  61%

Step-by-step explanation:

Multiply the fraction by 100%.

  76/125 × 100% = (7600/125)% = 60.8% ≈ 61%

Answer:

y= 3/2x-1/2

Step-by-step explanation:

Answer:

3/2 or 1.5

Step-by-step explanation:

gradient = ∆y/∆x

∆y = 4 - 1 =3

∆x = 3 - 1 = 2

∆y/∆x = 3/2

Answer:

0.75 lb potato salad = $2.22

Step-by-step explanation:

If 1 pound of potato salad = $2.96

Then 0.75 pounds of potato salad = 0.75 x 2.96 = 2.22

firstly let's convert the mixed fractions to improper fractions and then divide.

[tex]\stackrel{mixed}{2\frac{2}{5}}\implies \cfrac{2\cdot 5+2}{5}\implies \stackrel{improper}{\cfrac{12}{5}} ~\hfill \stackrel{mixed}{2\frac{1}{10}}\implies \cfrac{2\cdot 10+1}{10}\implies \stackrel{improper}{\cfrac{21}{10}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{12}{5}\div \cfrac{21}{10}\implies \cfrac{12}{5}\cdot \cfrac{10}{21}\implies \cfrac{120}{105}\implies \cfrac{8}{7}\implies 1\frac{1}{7}[/tex]

Answer:

first make them improper fractions

2 2/5 = 12/5

2 1/10 = 21/10
now set them up

12/5 divided by 21/10

make 21/10 a reciprocal(flip the fraction upside down)  and multiply across

12/5 x 10/21 = 1.14 or 1 1/7

Answer:

What is the length of the altitude drawn to the hypotenuse?, Corollary: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the two segments of the hypotenuse.

Furthermore, When an altitude is drawn to the hypotenuse of a given right triangle the new figure comprises two similar right triangles?, Theorem 62: The altitude drawn to the hypotenuse of a right triangle creates two similar right triangles, each similar to the original right triangle and similar to each other. Figure 2 shows the three right triangles created in Figure . They have been drawn in such a way that corresponding parts are easily recognized.

Finally,  When the altitude is drawn to the hypotenuse of a right triangle three similar triangles are formed?, The Inscribed Similar Triangles Theorem states that if an altitude is drawn from the right angle of any right triangle, then the two triangles formed are similar to the original triangle and all three triangles are similar to each other. Perpendicular lines are lines that intersect at a 90^{circ} angle.

Step-by-step explanation:

Answer:

13/21

Step-by-step explanation:

65/105 = 13/21