I have tried 3 times to solve this.​

Answer:

(a). The value of y is 6.

(b). The value of RS and ST are 33 and 31.

Step-by-step explanation:

Given that,

RS = 5y+3

ST=4y+7

RT=64

(a). We need to calculate the value of y

Using given data

[tex]RS+ST=RT[/tex]

Put the value into the formula

[tex]5y+3+4y+7=64[/tex]

[tex]9y=64-10[/tex]

[tex]y=\dfrac{54}{9}[/tex]

[tex]y=6[/tex]

(b). We need to calculate the value of RS

Using equation of RS

[tex]RS=5y+3[/tex]

Put the value of y

[tex]RS=5\times6+3[/tex]

[tex]RS=33[/tex]

We need to calculate the value of ST

Using equation of ST

[tex]ST=4y+7[/tex]

Put the value of y

[tex]ST=4\times6+7[/tex]

[tex]RS=31[/tex]

Hence, (a). The value of y is 6.

(b). The value of RS and ST are 33 and 31.

Answer:

For this question if you need proper help in video format, tthen watch the video of MIND YOUR DECISIONS

Answer:

your welcome it has to be c

Answer:

I honestly dont know

Step-by-step explanation:

Use a calculator for algebra srry if this answer is useless

Answer:

Step-by-step explanation:

3x+4=31

subtract 4 on both sides That gives you

3x=27

now divide 27 by 3

that gives you X=9

———————————————-

3(2x+1)

you distribute 3 into the parentheses

so 3 x 2x is 6x 3x1 is 3

so its 6x+3

————————————————

1/2(16x-8)=2(x+16)

first you distribute 1/2 into the parentheses on the left side and distribute 2 into the parentheses on the right

which gives you 8x-4=2x+32

then you combine like terms 8x+2x is 10x and -4+32 is 28

so you answer to this one is 10x+28

Answer:

100 vasos

Step-by-step explanation:

Sabemos que usando la conversión de unidades SI

1 litro = 1000 mililitros

En la pregunta se nos dice que:

Necesitamos trasvasar 20 litros de leche utilizando vasos de 200 mililitros de capacidad.

Por lo tanto,

1 litro = 1000 mililitros

20 litros =

20 litros × 1000 mililitros / 1 litros

= 20.000 mililitros de leche que hay que transferir.

Dado que estamos usando vasos con capacidad de 200 mililitros, la cantidad de vasos necesarios

= 20.000 mililitros de leche / 200 mililitros

= 100 vasos

Por tanto, se necesitan 100 vasos de 200 mililitros de capacidad para trasvasar 20 litros de leche que se encuentran en un barril de 200 litros a una jarra de 25 litros de capacidad.

Step-by-step explanation:

this is the ans in my view

Answer:

16.16 is 16% of 101

Step-by-step explanation:

Hope this helps!

Answer:

The number cupcakes Ms. Ciervo can make using the [tex]9 \frac{2}{3}[/tex] teaspoons of vanilla is 29.

Step-by-step explanation:

The information provided is:

Compute the number cupcakes Ms. Ciervo can make using the [tex]9 \frac{2}{3}[/tex] teaspoons of vanilla as follows:

Amount of vanilla required for one cupcake = [tex]\frac{1}{3}[/tex] teaspoons

Total amount of vanilla available [tex]9 \frac{2}{3}[/tex] teaspoons.

[tex]\text{number of cupcakes}=\frac{\text{total amount}}{\text{amount required for 1 cupcake}}[/tex]

                               [tex]=\frac{9\frac{2}{3}}{\frac{1}{3}}\\\\=\frac{29}{3}\div\frac{1}{3}\\\\=\frac{29}{3}\times \frac{3}{1}\\\\=29[/tex]

Thus, the number cupcakes Ms. Ciervo can make using the [tex]9 \frac{2}{3}[/tex] teaspoons of vanilla is 29.

Answer:

84

Step-by-step explanation:

Answer:

84

Step-by-step explanation:

Given

(- 6)(- 2x - 4y) , substitute x = 1, y = 3 into the expression

= (- 6)(- 2(1) - 4(3) )

= (- 6)(- 2 - 12)

= (- 6)(- 14)

= - 6 × - 14

= 84

Answer:

t=28/3

Step-by-step explanation:

Id this helped feel free to send thanks and give brainliest so I can continue to help people around the brainly community.

Answer:

6x²-8x-8

Step-by-step explanation:

[tex](3x - 2)(2x + 4)[/tex]

[tex]3x \times 2x = 6 {x}^{2} \\ 3x \times 4 = 12x \\ - 2 \times 2x = - 4x \\ - 2 \times 4 = - 8[/tex]

[tex]6 {x}^{2} + 12x - 4x - 8 \\ 6 {x}^{2} + 8x - 8[/tex]

Answer:

(3x-2)(2x+4)

= 6x^2+8x-8

Step-by-step explanation:

Answer:

a) (-2, -1)

b) (-3, 0) and (-1, 0)

Step-by-step explanation:

The turning point is the same as the vertex of the graph.

The vertex would be (-2, -1).

The zeros of the equation would be where the graph crosses the x-axis when y = 0.

The roots would be (-3, 0) and (-1, 0).

Answer: 395+30x

Step-by-step explanation:

Given : Mitchell has $395  now.

He saved $30 each week.

Let x be a variable that represents the number of weeks.

Since, Total amount = Current money + (Money save each week ) (Number of weeks)

Then,  Total amount =  (395 ) + (30)(x)

= 395+30x

Hence, the required algebraic expression= 395+30x

Answer:

2

Step-by-step explanation:

First do whats in the parenthesess

it will look like this

2+5-5=2 the 5's cancel eachother out so your left with 2

Answer:

[tex]x=1[/tex]

Step-by-step explanation:

A direct variation equation has the following format:

[tex]y=kx[/tex]

Where k is a constant.

We know that y is 12 when x is -2. Thus, substitute:

[tex]12=-2k[/tex]

Divide both sides by -2:

[tex]k=-6[/tex]

So, our direct variation equations is:

[tex]y=-6x[/tex]

To find what x is when y equals -6, substitute in -6 for y:

[tex]-6=-6x[/tex]

Divide both sides by -6:

[tex]x=1[/tex]

So, our answer is 1 :)

Answer:

x= c - b / A

please look at the step by step explanation to better understand :)

Step-by-step explanation:

subtract b from the left side and right side

so you are left with Ax = c - b

divide what number c - b is by A

and you are left with x= c - b / A

Answer:

[tex]\displaystyle f'(x)=-\frac{2}{x^{{}^{3}\!/\!{}_{2}}}[/tex]

Step-by-step explanation:

We have the function:

[tex]\displaystyle f(x)=\frac{4}{\sqrt x}[/tex]

And we want to find the derivative using the limit process.

Recall that the definition of a derivative is:

[tex]\displaystyle \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex]

Therefore, by substitution:

[tex]\displaystyle \lim_{h \to 0}\frac{\dfrac{4}{\sqrt{x+h}}-\dfrac{4}{\sqrt x}}{h}[/tex]

First and foremost, we can move the constant factor outside of the limit:

[tex]\displaystyle =\lim_{h \to 0}\frac{4\left(\dfrac{1}{\sqrt{x+h}}-\dfrac{1}{\sqrt x}\right)}{h}\\ \\=4\lim_{h \to 0}\frac{\dfrac{1}{\sqrt{x+h}}-\dfrac{1}{\sqrt x}}{h}[/tex]

Next, we can multiply everything by (√(x + h)(√x) to eliminate the fractions in the denominator. Therefore:

[tex]\displaystyle =4\lim_{h \to 0}\frac{\dfrac{1}{\sqrt{x+h}}-\dfrac{1}{\sqrt x}}{h}\left(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x}\right)[/tex]

Distribute:

[tex]\displaystyle =4\lim_{h \to 0}\frac{\left({\sqrt{x+h}\sqrt x}\right)\dfrac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\dfrac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}[/tex]

Distribute and simplify:

[tex]\displaystyle =4 \lim_{h\to 0}\frac{\sqrt x-\sqrt{x+h}}{h(\sqrt{x+h}\sqrt{x}) }[/tex]

Next, we can multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x + h)). Thus:

[tex]\displaystyle = 4\lim_{h\to 0}\frac{\sqrt x-\sqrt{x+h}}{h(\sqrt{x+h}\sqrt{x}) }\left(\frac{\sqrt x +\sqrt{x+h}}{\sqrt x +\sqrt{x+h}\right)}[/tex]

Simplify:

[tex]\displaystyle =4 \lim_{h \to 0} \frac{x-(x+h)}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}\\ \\ \\ =4 \lim_{h \to 0} \frac{x-x-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})} \\ \\ \\=4 \lim_{h \to 0} \frac{-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}[/tex]

Cancel like terms:

[tex]\displaystyle =4 \lim_{h \to 0} -\frac{1}{(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}[/tex]

Now, we can use direct substitution. Hence:

[tex]\displaystyle \Rightarrow4 \left( -\frac{1}{(\sqrt{x+0}\sqrt x)(\sqrt x+\sqrt{x+0})}\right)[/tex]

Simplify:

[tex]\displaystyle =4\left( -\frac{1}{(\sqrt{x}\sqrt x)(\sqrt x+\sqrt{x})}\right) \\ \\ \\ =4\left( -\frac{1}{(x)(2\sqrt{x})}\right)[/tex]

Multiply:

[tex]\displaystyle =- \frac{4}{2x\sqrt{x}}[/tex]

Reduce and rewrite:

[tex]\displaystyle =-\frac{2}{x(x^{{}^{1}\! / \! {}_{2} \!})}[/tex]

Simplify:

[tex]\displaystyle =-\frac{2}{x^{{}^{3}\!/\!{}_{2}}}[/tex]

Therefore:

[tex]\displaystyle f'(x)=-\frac{2}{x^{{}^{3}\!/\!{}_{2}}}[/tex]

Answer:

Step-by-step explanation:

GIRL! You should add diagrams to these types of questions. It would really help

That 10cm does not mean point C is 10cm. It means the line AB is 10 cm in total.

And since point C is the midpoint, which means that point C cuts the line AB in half, that makes AC = 5cm

Answer:

the answer is fjdixekd

Work Shown:

-1 < x+3 < 5

-1-3 < x+3-3 < 5-3 ... subtract 3 from all sides

-4 < x < 2

Answer:

Step-by-step explanation:

What we are expected to solve for that the problem did not expressly state is most likely the number of hours that you could ride for an amount of $65.

firstly we need to model the inequality (equation) for this scenario.

the constant fee= $3 additional fee for helmet

[tex]3+15n\leq 65\\\\[/tex]

We can now solve for n since the above inequality satisfies the condition presented in the problem statement.

 [tex]3+15n\leq 65\\\\15n\leq65-3\\\\ 15n\leq 62[/tex]

Divide both sides by 15 to find n

[tex]n\leq 62/15\\\\n\leq 4hrs -8min[/tex]

(2,6) after a reflection in the x axis

(-2,-6) after a reflection in the y axis

Answer:

C

Step-by-step explanation:

A: (16 - 12)² = 4² = 16 (Incorrect)

B: -|-4| = -(4) = -4 (Incorrect

C: (96 ÷ 8) - 2³ = 12 - 8 = 4 (Correct)

Answer: 29

Step-by-step explanation:

Answer:

t = d/V

Step-by-step explanation:

V = d/t

Multiply each side by t

Vt = d/t *t

Vt = d

Divide each side by V

Vt/V = d/V

t = d/V

Answer:

5.55

Step-by-step explanation:

The cost of the 3.4 pounds of trail mix is:

STEP 1:

multiply number of pounds purchased by price per pound

= 3.4 pounds * $4.25 per pound

= $14.45 total cost

STEP 2:

subtract total cost of purchase (step 1) from amount she gave cashier ($20.00)

= $20.00 - $14.45

= $5.55 amount received back from cashier

Answer:

wow sry this is a tuff one :(

Step-by-step explanation:

Answer:

Step-by-step explanation:

-5x the base