I NEED THIS ASAP!!
Which formula defines the unit for electrical power?

Answer:solenoid with current running through it

Explanation:just took the test

Answer:

The equation for such type of wave is  [tex]D_2 = sin(0.84.x + 47t + 21)[/tex]

Explanation:

From the question we are told that

   The displacement is [tex]D_1 = 4.2sin(0.84.x - 47t + 21)[/tex]

   Here  the wave number is  k=  0.84

              The angular frequency is  [tex]w = 47[/tex]

              The phase shift is  [tex]\phi = 21[/tex]

 Generally the equation that represents a wave which, when traveling in the opposite direction, will produce a standing wave when added to this one is mathematically represented as

             [tex]D_2 = sin(0.84.x + 47t + 21)[/tex]

Answer:

this is a projectile

Answer:

D. projectile

Explanation:

Since it's dropped from a rest that means that it's velocity at the beginning is 0.

Answer:

The

Explanation:

The horizontal distance covered is known as the range expressed as;

R = U√2H/g

U is the speed = 200m/s

H is the max height = 800m

g is the gravity = 9.8m/s²

R = 200√2(800)/9.8

R = 200√1600/9.8

R = 200√163.27

R = 200(12.78)

R = 2555.54

Hence the package should be released at a distance of 2555.54m

Answer:

P_abs = 105120.2 N/m²

Explanation:

We are given;

Specific gravity of oil; ρ_oil = 0.6 g/cm³ = 600 kg/m³

Depth of water; h_w = 21 cm = 0.21 m

Depth of oil; h_o = 35 cm = 0.35 m

From tables specific gravity of water is; ρ_w = 1000 kg/m³

Thus, to get the absolute pressure at the bottom of the container, we will use the formula;

P_abs = (ρ_w × g × h_w) + (ρ_oil × g × h_oil) + P_a

Where P_a is atmospheric pressure with a standard value of 1.01 × 10^(5) N/m²

g is gravitational acceleration = 9.81 m/s²

Thus;

P_abs = (1000 × 9.81 × 0.21) + (600 × 9.81 × 0.35) + (1.01 × 10^(5))

P_abs = 105120.2 N/m²

Answer:

same

Explanation:

aww good luck, i hope u n ur family turn out okkk

Answer:

Energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another.

Explanation:

Hope this helps!

Answer: intertia

Explanation:

Answer:

[tex]5.86\times 10^{-7}\ \text{m}[/tex]

Explanation:

d = Slit separation = 0.11 mm

[tex]\theta[/tex] = Angle = [tex]0.61^{\circ}[/tex]

m = Order = 2

[tex]\lambda[/tex] = Wavelength

We have the relation

[tex]d\sin\theta=m\lambda\\\Rightarrow \lambda=\dfrac{d\sin\theta}{m}\\\Rightarrow \lambda=\dfrac{0.11\times 10^{-3}\times \sin0.61^{\circ}}{2}\\\Rightarrow \lambda=5.86\times 10^{-7}\ \text{m}[/tex]

The wavelength of the light is [tex]5.86\times 10^{-7}\ \text{m}[/tex].

Answer:

77.6 Hz

Explanation:

What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound from its siren.

The given parameters are:

Observer speed = 115 km/h

Source frequency = 753 Hz

Speed of sound = 342 m/s

First convert km/h to m/s

Observer speed = (115 × 1000) / 3600

Observer speed = 31.94 m/s

The frequency received by the person will be:

F = fv / ( V - v )

Where

F = frequency received by the person

f = siren frequency

V = speed of sound

v = speed of the ambulance

Substitute all the parameters into the formula

F = (753 × 31.94) / ( 342 - 31.94 )

F = 24050.82 / 310.06

F = 77.568 Hz

Therefore, the frequency received by a person is approximately 77.6Hz

Answer:

6,000 kg

Explanation:

Answer:

7 m/s (agrees with answer a in your list)

Explanation:

Recall that the centripetal acceleration is defined by the square of the tangential velocity divided by the radius of the rotational motion:

[tex]a_c=\frac{v_t^2}{R}[/tex]

then the tangential velocity is extracted from here as:

[tex]a_c=\frac{v_t^2}{R} \\v_t^2=a_c * R\\v_t=\sqrt{a_c * R}[/tex]

in our case, this becomes:

[tex]v_t=\sqrt{7*7} = 7 \,\,m/s[/tex]

Answer:

naruto and hinata

Explanation:

Answer:

A. The acceleration is the same for both bullets.

Explanation:

The force of gravity is the attractive force applied by the earth on any object on its surface or neighborhood. And it is uniform under free fall at a definite location on the earth.

Since the the two bullets motion was at the same time and without air resistance, their acceleration would be the same before striking the surface of the water. This is because neglecting air resistance, all objects at the same height would fall with the same acceleration no matter their masses.

Answer:

The power factor of the circuit is 0.99

Explanation:

Given;

resistance of the resistor, R = 65.2 ohms

capacitance of the capacitor, C = 2.26 μF = 2.26 x 10⁻⁶ F

inductance, L = 2.08 mH = 2.08 x 10⁻³ H

frequency of the AC, f = 2400 Hz

The angular frequency is given by;

ω = 2πf

ω = 2π(2400) = 15081.6 rad/s

The inductive reactance is given by;

XL = ωL

XL = (15081.6 x 2.08 x 10⁻³)

XL = 31.37 ohms

The capacitive reactance is given by;

[tex]X_c = \frac{1}{\omega C} \\\\X_c = \frac{1}{(15081.6)(2.26*10^{-6} )}\\\\X_c = 29.34 \ ohms[/tex]

The phase difference is given by;

[tex]tan\phi = \frac{X_l - X_c}{R}\\\\ tan\phi =\frac{31.37-29.34}{65.2} \\\\tan\phi = 0.0311 \\\\\phi = tan^{-1} (0.0311)\\\\\phi = 1.78^0[/tex]

The power factor is given by;

CosФ = Cos(1.78) = 0.99

Therefore, the power factor of the circuit is 0.99

Answer:

[tex]F = 5.4*10^{-8}\ N[/tex]

Explanation:

Given

Represent the mass of the student with M and the mass of the slice of pizza with m

[tex]M = 92kg[/tex]

[tex]m = 550g[/tex]

[tex]d = 25cm[/tex]

Required

Determine the force of attraction

This is calculated as:

[tex]F = \frac{GMm}{d^2}[/tex]

Where G = gravitational constant

[tex]G = 6.67408 * 10^{-11}\ m^3 kg^{-1} s^{-2}[/tex]

Convert both mass to kilogram and distance to metre

[tex]m = 550g[/tex]

[tex]m = 550kg/1000[/tex]

[tex]m = 0.55kg[/tex]

[tex]d = 25cm[/tex]

[tex]d = 25m/100[/tex]

[tex]d = 0.25m[/tex]

Substitute these values in [tex]F = \frac{GMm}{d^2}[/tex]

[tex]F = \frac{6.67408 * 10^{-11} * 92 * 0.55}{0.25^2}[/tex]

[tex]F = \frac{6.67408 * 92 * 0.55* 10^{-11} }{0.25^2}[/tex]

[tex]F = \frac{337.708448* 10^{-11} }{0.0625}[/tex]

[tex]F = 5403.335168* 10^{-11}[/tex]

[tex]F = 5.403335168* 10^3*10^{-11}[/tex]

[tex]F = 5.403335168*10^{3-11}[/tex]

[tex]F = 5.403335168*10^{-8}[/tex]

[tex]F = 5.4*10^{-8}\ N[/tex]

Answer:

0.967 m/s

1855 N

[tex]46.375\ \text{MPa}[/tex]

Explanation:

v = Final velocity

u = Initial velocity = 0

s = Displacement = 4.77 cm

g = a = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

From the kinematic equations

[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 0.0477+0}\\\Rightarrow v=0.967\ \text{m/s}[/tex]

The velocity of the object at the moment of impact is 0.967 m/s

Now

[tex]\Delta v[/tex] = Change in velocity = 1 m/s

t = Time taken = 20 ms

m = Half mass of the person = [tex]\dfrac{74.2}{2}=37.1\ \text{kg}[/tex]

[tex]F=\dfrac{m}{t}\\\Rightarrow F=\dfrac{37.1\times 1}{20\times 10^{-3}}\\\Rightarrow F=1855\ \text{N}[/tex]

The force associated with a single step of the person is 1855 N

A = Area = [tex]0.4\ \text{cm}^2[/tex]

Stress is given by

[tex]\sigma=\dfrac{F}{A}\\\Rightarrow \sigma=\dfrac{1855}{0.4\times 10^{-4}}\\\Rightarrow \sigma=46375000\ \text{Pa}=46.375\ \text{MPa}[/tex]

The stress on the tendon is [tex]46.375\ \text{MPa}[/tex]

The speed of object during falling is 0.967 m/s.

(A)  The magnitude of force  associated with this single step for a person is 1855 N.

(B) The required value of stress at tendons is [tex]4.70 \times 10^{7} \;\rm Pa[/tex].

Given data:

The height of fall is, h = 4.77 cm = 0.0477 m.

The magnitude of downward velocity is, v' = 1.0 m/s.

The duration of impact is, [tex]t = 20 \;\rm ms =20 \times 10^{-3} \;\rm s[/tex].

The mass of person is, m = 74.2 kg.

The magnitude of force is, F' = 1880 N.

The cross-sectional area is, [tex]A =0.4 \;\rm cm^{2} = 0.4 \times 10^{-4} \;\rm m^{2][/tex].

The problem has several parts using different concepts. First obtain the final speed of object to fall by using the second kinematic equations of motion as,

[tex]v^{2}=u^{2}+2gh[/tex]

Solving as,

[tex]v^{2}=0^{2}+(2 \times 9.8 \times 0.0477)\\\\v = \sqrt{(2 \times 9.8 \times 0.0477)} \\v = 0.967 \;\rm m/s[/tex]

Thus, the speed of object during falling is 0.967 m/s.

(A)

Now coming to next part, the half of mass means, m' = m/2 = 74.2/2 = 37.1 kg.

Apply the expression of average force as,

[tex]F =\dfrac{m'v'}{t}[/tex]

Solving as,

[tex]F =\dfrac{37.1 \times 1}{20 \times 10^{-3}}\\\\F = 1855 \;\rm N[/tex]

Thus, the magnitude of force  associated with this single step for a person is 1855 N.

(B)

The expression for the stress is given as,

[tex]\sigma = \dfrac{F'}{A}[/tex]

Solving as,

[tex]\sigma = \dfrac{1880}{0.4 \times 10^{-4}}\\\\\sigma =4.70 \times 10^{7} \;\rm Pa[/tex]

Thus, the required value of stress at tendons is [tex]4.70 \times 10^{7} \;\rm Pa[/tex].

Learn more about the Stress force here:

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Answer:

The length of the pendulum cord is approximately 114.592 centimeters.

Explanation:

We include a representation of the motion of the pendulum in the image attached below. The trajectory described by the pendulum is represented by the following geometrical expression:

[tex]s = \theta \cdot r[/tex] (1)

Where:

[tex]\theta[/tex] - Angular change with the vertical, measured in radians.

[tex]r[/tex] - Length of the pendulum cord, measured in centimeters.

[tex]s[/tex] - Arc, measured in centimeters.

If we know that [tex]\theta = \frac{\pi}{9}[/tex] and [tex]s = 40\,cm[/tex], then the length of the pendulum cord is.

[tex]r = \frac{s}{\theta}[/tex]

[tex]r = \frac{40\,cm}{\frac{\pi}{9} }[/tex]

[tex]r \approx 114.592\,cm[/tex]

The length of the pendulum cord is approximately 114.592 centimeters.

Answer:

=7.5J

Explanation:

  Step one:

given data

the applied force F=5N

the distance = 1.5m

Step two:

Required

work done by Jolie

Now by definition, the work done is the applied times the distance which the force is applied

Wd= F*D

Wd= 5*1.5

Wd=7.5J

If she uses a force of 5N to lift 150 pounds to a height of 1.5m, the work done will be 7.5J

Answer:hat are some examples of energy transformation?

The Sun transforms nuclear energy into heat and light energy.

Our bodies convert chemical energy in our food into mechanical energy for us to move.

An electric fan transforms electrical energy into kinetic energy.

Explanation:

Answer:

d. 25 ms

Explanation:

       [tex]\tau_{1} = R_{1} *C_{1} = 5 ms (1)[/tex]

       [tex]\tau_{2} =10* R_{1} *0.5*C_{1} = 5*(R_{1}* C_{1}) = 5* \tau_{1} = 5* 5 ms = 25 ms (2)[/tex]

Answer:

If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.

Explanation:

I hope this helped

Hypothesis: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car gains more potential energy at the higher starting point.

When a toy car moves along a sloped racetrack, it converts its potential energy (due to its height above the ground) into kinetic energy (energy of motion). The higher the starting height of the racetrack, the more potential energy the toy car possesses initially.

As the toy car moves down the sloped track, it will accelerate due to the force of gravity. The potential energy is converted into kinetic energy, and the car's speed increases. According to the law of conservation of energy, the total mechanical energy (sum of potential and kinetic energy) remains constant as long as no external forces, such as friction, act on the car.

Therefore, if the starting height of the racetrack is increased, the toy car will have more potential energy to start with. As it moves down the track, it will convert this increased potential energy into kinetic energy, resulting in a higher speed compared to when it starts from a lower height.

To know more about speed here

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Answer:

See connections below

Explanation:

1   [tex]\Rightarrow[/tex] b

2   [tex]\Rightarrow[/tex] a

3   [tex]\Rightarrow[/tex] d

4   [tex]\Rightarrow[/tex] i

5   [tex]\Rightarrow[/tex] g

6   [tex]\Rightarrow[/tex]  h

7   [tex]\Rightarrow[/tex]  c

8   [tex]\Rightarrow[/tex]  e

9   [tex]\Rightarrow[/tex] f

Answer:

The correct answer is D. Creep.

Explanation:

Ground creep is a slow downward movement of a hill or mountain slope without the formation of demolition forms. The decisive factor for this is the continuous flow of movement of the soil.

The main driver of collapse is the movement of the surface layer particles during expansion in a direction perpendicular to the slope, followed by vertical collapse on contraction. The visible effect of the collapsing is the inclination of fences and poles, as well as trees that grow out of the ground towards the slope and have trunks curved vertically, in more extreme cases it may be cracks on the walls of buildings.

Answer:

A) all substance conduct electricity

Answer: Titanium (Ti)

Explanation:

First, each element has a unique atomic number Z, that is equal to the number of protons in the nucleus.

The halogen in period 3 is chlorine (Ch)

Chlorine's atomic number is Z = 17, this means that it has 17 protons.

Now we want to find a transition metal that has 5 more protons, then this transition metal has Z = 17 + 5 = 22

Now we can look at the periodic table and find the element with Z = 22, and if this is in the d-block, then this will be a transition metal.

The element with Z = 22 is titanium (Ti)