Given a quadratic equation in vertex form
[tex]y=a(x-h)^2+k[/tex][tex]\begin{gathered} \text{ wh}ere\text{ a, h, and k are constants, } \\ \text{then the point (h, k) is the vertex of the function} \end{gathered}[/tex]In our case,
[tex]y=(x+10)^2+2[/tex]h = -10, and k= 2
Therefore the vertex is (-10, 2)
rewrite using a single positive exponent (4^-3)^7
The given expression is
(4^-3)^7
We would apply the law of exponents which is expressed as
(a^- b) = 1/a^b
We can see that
a = 4
b = - 3
Writing it using a single positive exponent, it becomes
4^ - 3 = 1/4^3 = 1/64
The final expression would be
(1/64)^7
In anatomy, a student learned that the average resting heart rate is between 60 and 100 beats per minute. The student decided to record the heart rate of people over five minutes while waiting in line at the pharmacy. The dot plot shows the results.
Dot plot with 1 dot at 62, 3 dots at 68, 1 dot at 69, 2 dots at 70, 3 dots at 72, 2 dots at 75, 1 dot at 76, 2 dots at 78, 3 dots at 80, and 2 dots at 89
Which statement below best describes the shape of the distribution?
The data is roughly symmetrical distributed, with most values clustered from 68 to 80 beats per minute. The values at 62 and 89 are possible outliers. The data fits within the average of 60 to 100 beats per minute.
The data is not symmetrically distributed, with most values clustered from 68 to 80 beats per minute. The values at 62 and 89 are possible outliers. The data fits within the average of 60 to 100 beats per minute.
The data is skewed right, with fewer values on the right end of the graph. The values at 62 and 89 are possible outliers. The data fits within the average of 60 to 100 beats per minute.
The data is skewed left, with fewer values on the left end of the graph. The values at 62 and 89 are possible outliers. The data fits within the average of 60 to 100 beats per minute.
The correct option regarding the data-set represented by the dot plot is represented as follows:
The data is skewed right, with fewer values on the right end of the graph. The values at 62 and 89 are possible outliers. The data fits within the average of 60 to 100 beats per minute.
Dot plotA dot plot shows the number of times that each observation appears in the data-set.
Hence, the complete data-set in this problem is given as follows:
62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 89, 89.
The mean of a data-set is the sum of the observations divided by the number of observations, hence it is given by:
Mean = (62 + 3 x 68 + 69 + 2 x 70 + 3 x 72 + 2 x 75 + 76 + 2 x 78 + 3 x 80 + 2 x 89)/20 = 74.55.
The median is the middle value of the data-set. The data-set has 20 elements, hence the median is the mean of the 10th and the 11th element, given as follows:
Median = (72 + 75)/2 = 73.55.
The mean is greater than the median, hence the data is right skewed and the correct option is given as follows:
The data is skewed right, with fewer values on the right end of the graph. The values at 62 and 89 are possible outliers. The data fits within the average of 60 to 100 beats per minute.
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Answer: A/The data is roughly symmetrical distributed, with most values clustered from 68 to 80 beats per minute.
Step-by-step explanation: Just got it right on the test
HELP
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Apply the Pythagorean Theorem. The Pythagorean Theorem states that in a right triangle, a^2 + b^2 = c^2 where c is the hypotenuse.
a^2 + b^2 = c^2
8^2 + 5^2 = c^2
64 + 25 = c^2
89 = c^2
√89 = √c^2
c = √89
An irrigation canal is 10 kilometers long and 2 meters deep. It is 4 meters wide at the 2 meters wide at the bottom. How many cubic meters of earth were excavated to make the canal?
The cross section of the canal will form a trapezoid. First, find the area of the cross section. The area of a trapezoid is defined as
[tex]\begin{gathered} A_{\text{trapezoid}}=\frac{a+b}{2}h \\ \\ \text{Given} \\ h=2\text{ meters (2 meters deep)} \\ a=4\text{ meters (4 meters wide)} \\ b=2\text{ meters (2 meters wide at the bottom)} \end{gathered}[/tex]Substitute the following values and we get the area
[tex]\begin{gathered} A=\frac{a+b}{2}h \\ A=\frac{4+2}{2}(2) \\ A=\frac{6}{2}(2) \\ A=6\text{ m}^2 \end{gathered}[/tex]Now that we have the area of the cross section, multiply it to the length of the irrigation canal.
[tex]\begin{gathered} \text{Before multiplying, all units must be the same, convert km to meters} \\ 10\operatorname{km}\rightarrow10,000\text{ meters} \\ 6\text{ m}^2\times10000\text{ meters} \\ \Longrightarrow60000\text{ m}^3 \end{gathered}[/tex]Therefore, they have to excavate 60,000 cubic meters of earth to make the canal.
Need help please. ASAP
(2y - 1)/ -3 = -5 , prove y = 8: Hence proved
5n - 42 = 12n, prove n = -6: Hence proved
2x + 30 = -4(5x -2), prove x = -1 : Hence proved
18x - 2(3x + 1) = 5x -16, prove x = -2 : Hence proved
What is Algebra?
One of the many different mathematical disciplines is algebra. Algebra, a common thread that runs through nearly all of mathematics, is the study of mathematical symbols and the rules for using them in formulas.
1) (2y - 1)/ -3 = -5
Solving for y
(2y - 1)/ -3 = -5
multiply both side with -3
(2y - 1) x (-3)/(-3) = (-5)(-3)
2y - 1 = 15
adding 1 both side
2y - 1 + 1 = 15 + 1
2y = 16
dividing 2 both side
2y / 2 = 16 / 2
y = 8
Hence Proved
2) 5n - 42 = 12n
Solving for n
5n - 42 = 12n
adding 42 both side
5n - 42 + 42 = 12n + 42
5n = 12n + 42
adding -12n both side
5n - 12n = 12n - 12n + 42
-7n = 42
dividing -7 both side
-7n/-7 = 42/ -7
n = -6
Hence proved
3) 2x + 30 = -4(5x -2)
solving for x
first simplify -4(5x -2)
2x + 30 = -20x + 8
adding 20x both side
2x + 20x + 30 = -20x + 20x + 8
22x + 30 = 8
adding -30 both side
22x + 30 - 30 = 8 - 30
22x = -22
dividing 22 both side
22x / 22 = -22/22
x = -1
Hence proved
4) 18x - 2(3x + 1) = 5x -16
solving for x
first simplify - 2(3x + 1)
18x - 6x - 2 = 5x - 16
adding -5x both side
18x - 5x - 6x - 2 = 5x - 5x - 16
13x - 6x - 2 = -16
7x - 2 = -16
adding 2 both side
7x - 2 + 2 = -16 + 2
7x = -14
dividing 7 both side
7x/ 7 = -14 / 7
x = -2
Hence proved
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Is w = 12 a solution to the inequality below?
Answer:
No
Step-by-step explanation:
No, it is not a solution. You can find this answer by plugging in 12 for 2 for w.
0>12-132/12
132/12=11
12-11=1
0>1
0 is not greater than 1, so the answer is no.
Suppose you pay only the interest on a loan. Will the loan ever be paid off? Why or why not? I have no idea if this is correct
No. if only the interest is paid, the principal never decreases
can somebody please help me with this question
For each table, determine whether it shows a direct variation.If it does, write its direct variation equation.Not direct variationNot direct varlationXхyу41N1Direct variationEquation:51.2542Direct variationEquation:I78.75105The
For the right table , y/x = constant = k = 0.5
X-2y=5 and 2x+3y=10
Hello!
Let's set up some things:
[tex]x-2y=5[/tex] <-- equation 1
[tex]2x+3y = 10[/tex] <-- equation 2
________________
(equation 1) multiplied by 2
[tex]2x - 4y=10[/tex] <-- equation 3
________________
(equation 2) - (equation 3)
7y = 0
y = 0 <-- equation 4
________________
(equation 4)'s value of y into (equation 1)
[tex]x-2(0) = 5\\x = 5[/tex]
Thus x = 5 and y = 0
Hope that helps!
The value of a in y = ax²+bx+c and the vertex of the parabola are given. How many x-intercepts does the parabola have? Explain how you arrived at this number.a=1; vertex at (2,0)The parabola has x-intercept(s), because the parabola opensand the vertex isthe x-axis.
Given: The value of 'a' in y = ax²+bx+c is a=2 and vertex is at (2,0).
Required: To find the x-intercepts.
Explanation: The x-coordinate of the vertex is 2. Also, we know that x-coordinate is given by
[tex]x=-\frac{b}{2a}[/tex]Hence, putting the value of x=2 and a=1 we get
[tex]\begin{gathered} 2=-\frac{b}{2(1)} \\ b=-4 \end{gathered}[/tex]Now putting y=0, x=2, a=1, and b=-4 in eq of parabola we get
[tex]\begin{gathered} 0=2^2-4(2)+c \\ c=4 \end{gathered}[/tex]Now the equation of the parabola is,
[tex]y=x^2-4x+4[/tex]Now to find x-intercepts put y=0 i.e.,
[tex]\begin{gathered} x^2-4x+4=0 \\ (x-2)^2=0 \\ x=2,2 \end{gathered}[/tex]Hence there is only one x-intercept at (2,0). The opening of the parabola can be seen in the graph below-
Final Answer: The parabola has one x-intercept because the parabola opens upward and the vertex is on the x-axis.
Instructions for a chemical procedure state to mix salt, baking soda, and water in a 22 : 14 : 5 ratio by mass. How many grams of baking soda would be required to make a mixture that contains 55 grams of salt?
35 grams of baking soda will be required for the mixture
The ratio of mix salt to baking soda to water = 22:14:5
Let x be the total quantity of the mixture
A mixture is a substance composed of two or more unrelated chemical components. A physical blending of two or more substances that maintains their own identities takes the form of solutions, suspensions, or colloids.
Now the sum of the ratio is 22+14+5 = 41
So, 55 grams of salt = 22/41x
Solving for x we get:
x = 55*41/22
x = 102.5 grams
The total quantity of the mixture is 102.5 grams
Quantity of baking soda required = 14/41 of 102.5
= 14/41*102.5
= 35 grams
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help me with the last question pleaseeeeeeeeeeeeeee
Answer:
Answer:
d
Step-by-step explanation:
The number of years must be non-negative.
This eliminates all of the options except for d.
54 is the product of 3 and Janelle's age
what is the product of 24.154 and 0.18
Answer:
4.34772
4.3 with the correct amount of sig figs but you don't really have to worry about that unless you've talked about it in class
Step-by-step explanation:
the product of two numbers is the result of those two numbers being multiplied. So, 24.154 * 0.18 = 4.34772
Find an angle e in the interval [0°, 90°) that satisfies each statement. Give answer to the nearest TENTH of a degree. a) sin= 0.3697 degrees b) cos= 0.7265 degrees degrees c) sec= 2.3232 degrees d) csc= 1.1234
first at all, we are gonna solve this using inverse trigonometric functions
like this:
[tex]\begin{gathered} \sin \alpha\text{ = x} \\ \alpha\text{ = }\sin ^{-1}x \end{gathered}[/tex]for the first case:
a)
[tex]\begin{gathered} \sin \alpha\text{ = }0.3697 \\ \alpha=\sin ^{-1}(0.3697) \\ \alpha=21.697\ldots \\ \alpha\cong20 \end{gathered}[/tex]b)
[tex]\begin{gathered} \cos \alpha\text{ = }0.7265 \\ \alpha=\cos ^{-1}(0.7265) \\ \alpha=43.406\ldots \\ \alpha\cong40 \end{gathered}[/tex]c)
In this case, we are going to use the following trigonometric identity:
[tex]\begin{gathered} \sec \alpha=\frac{1}{\cos \alpha} \\ \end{gathered}[/tex]later,
[tex]\begin{gathered} \sec \alpha=2.3232 \\ \frac{1}{\cos \alpha}=2.3232 \\ \cos \alpha=\frac{1}{2.3232} \\ \alpha=\cos ^{-1}(\frac{1}{2.3232}) \\ \alpha=64.504\ldots \\ \alpha\cong60 \end{gathered}[/tex]d)
In this case, we are going to use the following trigonometric identity:
[tex]\begin{gathered} csc\alpha=\frac{1}{sin\alpha} \\ \end{gathered}[/tex]later,
[tex]\begin{gathered} \csc \alpha=1.1234 \\ \frac{1}{sin\alpha}=1.1234 \\ \sin \alpha=\frac{1}{1.1234} \\ \alpha=\sin ^{-1}(\frac{1}{1.1234}) \\ \alpha=62.892\ldots \\ \alpha\cong60 \end{gathered}[/tex]finally, those are your answers.
At many bakeries, there are deals that if you buy twelve donuts, you get a thirteenth one at a discount. Sometimes "13" items is called a baker's dozen. I One store is advertising: Donuts! $1.05 individually, or $13 per baker's dozen. They want to program their cash register to be able to show the exact price for any number of donuts. You will help them by producing a data table, a graph and an algorithm. You will: 1. Fill in and expand the data table 2. Make a scatter plot to show the pattern visually. This means to plot an (x,y) point for every row in the data table. For example the first point can be (1, 1.05) 3. Develop an algorithm to find the cost for any number of donuts. Note: An algorithm is like a set of instructions to solve a problem. They are useful for telling computers or people exactly how to do something. For example, here is an algorithm that finds 15% of a number: Step 1: take any number, callit N.
Table
Number of donuts Price
1 $1.05
2 $ 2.1
3 $3.15
4 $4.2
5 $5.25
6 $6.3
10 $10.5
slope = (10.5 - 1.05) / 10 - 1
= 9.45 / 9
= 1.05
Equation
y - 10.5 = 1.05 (x - 10)
y = 1.05x - 10.5 + 10.5
y = 1.05x
For 40 donuts
y = 1.05(40)
y = $42
Can someone solve this equation using the quadratic formula and simplifying in radical form if needed
For a quadratic equation of the form:
[tex]av^2+bv+c=0[/tex]The quadratic formula is:
[tex]v_{1,2}=\frac{-b\pm\sqrt[]{b^2-4\cdot a\cdot c}}{2\cdot a}[/tex]In this case, we have the eqaution:
[tex]11v^2+8v=4[/tex]First, let's rest 4 on both sides to get 0 in the right hand side:
[tex]11v^2+8v-4=0[/tex]Then we can use the quadratic formula:
[tex]v_{1,2}=\frac{-8\pm\sqrt[]{8^2-4\cdot11\cdot(-4)}}{2\cdot11}[/tex]And solve:
[tex]\begin{gathered} v_{1,2}=\frac{-8\pm\sqrt[]{64^{}+176}}{22} \\ v_{1,2}=\frac{-8\pm\sqrt[]{240}}{22} \\ v_{1,2}=\frac{-8\pm\sqrt[]{16}\sqrt[]{15}}{22} \\ v_{1,2}=\frac{-8\pm4\sqrt[]{15}}{22} \\ v_{1,2}=\frac{-4\pm2\sqrt[]{15}}{11} \end{gathered}[/tex]Then the two solutions are:
[tex]\begin{gathered} v_1=\frac{-4-2\sqrt[]{15}}{11} \\ v_2=\frac{-4+2\sqrt[]{15}}{11} \end{gathered}[/tex]A-) who won the race? a1)By how many yards of difference? B-) How many yards behind the starting line does Yolanda have to leave for the race to end in a draw?
EXPLANATION
Let's see the facts:
Race = 100-yard
Toko--> 10 yards < Yolanda
Second part:
Yolanda --> 10 yards behind the starting line
If each geil ran at the same speed as the first race, the appropiate relationship is as follows:
Yolanda's speed = 100 yards/race
Yoko's speed = 90 yards/race
Distance= ratex time
For the second race, Yolanda ran 110 yards at the same speed --> So it will take 110/100 = 1.1 times to finish the race.
Yoko runs 100 yards at the same speed so it will take her 100/90= 1.11111... times to finish the run.
As 1.11 is less time than 1.1111, Yolanda will win the race.
b) In order to finish in a tie, the times must be the same.
Let x be the head start given to Yoko so that they tie.
time = distance / rate
[tex]\frac{100+x}{100}=\frac{100}{90}[/tex]Multiplying both sides by 100:
[tex]100+x=100\cdot\frac{100}{90}[/tex]Subtracting -100 to both sides:
[tex]x=100\cdot\frac{100}{90}-100[/tex]Simplifying:
[tex]x=111.11111\ldots-100=11.111\ldots[/tex]So, if Yoko has 11.111... head start, they should tie on the next race.
Which property is shown -2x1/-2=1
Answer: The answer is Multiplicative Inverse.
Step-by-step explanation: I hope this helps.
Find the value of x and the length of ST
x = 13
The length of ST is 78
Explanation:ST and SR are tangents
From the diagram
ST = 9x - 39
SR = 6x
Note that:
Two tangents drawn from the same point external to a circle are equal
That is, ST = SR
9x - 39 = 6x
9x - 6x = 39
3x = 39
x = 39/3
x = 13
ST = 9x - 39
Suubstitute x = 13
ST = 9(13) - 39
ST = 117 - 39
ST = 78
180/9 as a whole number
Answer:
20
Step-by-step explanation:
180 ÷ 9 = 20
Find the value of X in the length of VR
Since V is between R and T, then:
[tex]RT=VR+VT\text{.}[/tex]Substituting VR=3x, VT=5x+9, RT=33, and solving for x we get:
[tex]\begin{gathered} 33=3x+5x+9, \\ 33=8x+9, \\ 33-9=8x, \\ 8x=24, \\ x=3. \end{gathered}[/tex]Substituting x=3 in VR we get:
[tex]\text{VR}=3\cdot3=9.[/tex]Answer:
The value of x is 3.
The length of VR is 9.
The table shows the linear relationship between the balance of a student's savings account and the number of weeks he has been saving Savings Account Week 0 1 13 Balance (dollars) 123 Based on the table, what was the rate of change of the balance of the student savings account in dollars and cents per week?
7 dollars per week
Explanation:Rate of change = change in balance (dollars)/change in weeks
for (0, 32) and (1, 39)
Rate of change = (39 - 32)/(1 - 0)
Rate of change = 7/1 = 7
For (1, 39) and (3, 53)
Rate of change = (53 - 39)/(3 - 1)
Rate of change = 14/2
Rate of change = 7
Since the rate of change is constant from calculation, then the rate of change of the balance of the student savings account in dollars and cents per week is 7 dollars per week
Help please!
I can’t find the probability of a pretty girl telling me the answer to what 2x2 is
May I ask you, pretty girl, what is it?
Answer: depends how often you meet someone
Step-by-step explanation: You can multiply 2 times 2 and if you know the answer to that multiply that times the number of times u meet someone and divide by 2.
Please find it if needed.-The Area of a Rectangle-The Area of a Triangle-The Area of a Square-Or The Area of a Circleand find the area of the composite figure (andplease put the areas separate)FIND THE AREA OF THE SHADED REGION
First find the area of the rectangle
A = l*w = 9*16 = 144
The unshaded area is a trapezoid
A = 1/2 ( b1+b2) *h = 1/2 ( 5+11) * 4 = 1/2 (16) * 4 =32
The area of the shaded region is
rectangle - trapezoid
144-32
112cm^2
Answer:
112cm²
Step-by-step explanation:
First, let us find the area of the rectangle.
Area = length × width
Area = 16 cm × 9 cm
Area = 144 cm²
Now, let us find the area of the trapezium.
Area = 1/2 ( Sum of the parallel sides ) × height
Area = 1/2 × ( 11 + 5 ) × 4
Area = 1/2 × 16 × 4
Area = 32 cm²
Area of the shaded region.
To find the area of the shaded region, subtract the area of the rectangle from the area of the trapezium.
Area = 144cm² - 32cm²
Area = 112cm²
which describes the domain of the figure represented below? ANSWER CHOICES :[8,0)(0,8)[0,8)
We have the following:
The domain is the input values or also the x-axis values.
According to the graph we can see that we go from 0 to 8.
Because the point at 0 is filled, it means that it includes the number and that means that it is a closed interval [].
On the contrary, at point 8, the point is hollow, it means that it reaches 8, but it does not include the number 8, which means that it is an open interval ().
Which means that the correct answer is:
[0, 8)
Write an equation in point-slope form for the line that passes through the given points.
(-4,7). (6.3)
Answer:
[tex]y=-\frac{2}{5}x+5.4[/tex]
Step-by-step explanation:
Step 1: plot points
Step 2: find the RISE/RUN (-4/10 or -2/5)
Step 3: find where it intersects the y axis (5.4)
y=mx+b where x and y are varables, m is the slope, and b is the y-int
[tex]y=-\frac{2}{5}x+5.4[/tex]
Hope that helps
Enter the corredeach column.4. Madam Malkin owns Madam Malkin's Robes for AllOcassions which is a clothing store. She has abudget of $6000 to restock 200 clothing items.She can buy Hogwarts shirts for $12 each, Robes for$24 each, and Quidditch shirts for $36 each. If shewants to have twice as many Quidditch shirts asRobes, how many of each type of shirt should shebuy?11)223HOW MANY QUIDDITCH SHIRTS DID MADAMMALKIN BUY?445
Let's define some notation first:
H= number of Hogwarts, R= number of robes, Q= number of Quidditch
We can set up the following equation for the total of clothing items:
[tex]H+R+Q=200[/tex]We also know that Q= 2R so we have:
[tex]H+3R=200[/tex]Now we can create an equation for the amount of money and we have:
[tex]12H+24R+36Q=6000[/tex][tex]12H+96R=6000[/tex]Now we can replace H=200-3R and we got:
[tex]12(200-3R)+96R=6000[/tex]And solving for R we got:
[tex]60R=3600[/tex][tex]R=\frac{3600}{60}=60[/tex]And then Q would be:
[tex]Q=2R=120[/tex]Can a table with same input and output be a function like in the picture:
Yes, because each value of x still corresponds to only one value of y.