If 12 photovoltaic cells at 0.5 V each produce a total of 6 V of potential energy and carry a 1A current to your phone, what is the power output of these cells and the resistance inside your phone? P = VI and R = V/I (Show calculations and units)

Answers

Answer 1

Answer:

The power output is 6 W. The resistance is 6 Ω.

Step-by-step explanation:

Power output= 6V * 1 A= 6W

Resistance= 6V/1A= 6 Ω


Related Questions

One side of a rectangle is 6 meters shorter than four times another side. Find the length of the longer side if we also know that the perimeter of the rectangle is 58 meters

Answers

Answer:

22 meters

Step-by-step explanation:

Let x = width of the rectangle

Let y = length of the rectangle

Equation 1

If the length of the rectangle is 6 meters shorter than four times the width then:

⇒ y = 4x - 6

Equation 2

Perimeter of a rectangle = 2(width + length)

If the perimeter is 58 inches, then:

⇒ 58 = 2(x + y)

Solve by substitution

Substitute Equation 1 into Equation 2 and solve for x:

⇒ 58 = 2(x + 4x - 6)

⇒ 58 = 2(5x - 6)

⇒ 58 = 2 · 5x - 2 · 6

⇒ 58 = 10x - 12

⇒ 58 + 12 = 10x -12 + 12

⇒ 10x = 70

⇒ 10x ÷ 10 = 70 ÷ 10

⇒ x = 7

Substitute found value of x into Equation 1 and solve for y:

⇒ y = 4(7) - 6

⇒ y = 28 - 6

⇒ y = 22

Conclusion

The dimensions of the rectangle are:

width = 7 meterslength = 22 meters

Therefore, the length of the longer side is 22 meters

The length of the longer side is 22 meters.

Let, one side of the rectangle is x meters.

According to the problem, the other side is 6 meters shorter than four times this side, which means the length of the second side is (4x - 6) meters.

The perimeter of a rectangle is given by the formula:

Perimeter = 2 * (length + width)

In this case, the perimeter is 58 meters:

58 = 2 * (x + 4x - 6)

Now, let's solve for x:

58 = 2 * (5x - 6)

58 = 10x - 12

Add 12 to both sides:

58 + 12 = 10x

70 = 10x

Now, divide both sides by 10 to isolate x:

x = 70 / 10

x = 7

So, one side of the rectangle is 7 meters.

Now, we can find the length of the longer side:

Length of the longer side = 4x - 6

Length of the longer side = 4 * 7 - 6

Length of the longer side = 28 - 6

Length of the longer side = 22 meters

Therefore, the length of the longer side is 22 meters.

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Which best tells how heavy a dog might be?

A dog is shown.

A.
100 g

B.
25 kg

C.
25 g

D.
100 kg

Answers

Answer:

B

Step-by-step explanation:

A dog might be around
b) 25 kgs

Find the domain and range of the function:
--√√5-x-3

Answers

The domain is [tex]x \le 5[/tex] and the range of the function is [tex]f(x) \ge - 3[/tex]

How to determine the domain and the range?

The function is given as:

[tex]f(x) = \sqrt{5 - x} - 3[/tex]

The radicand must be at least 0.

So, we have:

[tex]\sqrt{5 - x} \ge 0[/tex]

Square both sides

[tex]5 - x \ge 0[/tex]

Rewrite as:

[tex]5 \ge x[/tex]

Solve for x

[tex]x \le 5[/tex]

This means that the domain is [tex]x \le 5[/tex]

For the range, we have; [tex]\sqrt{5 - x} \ge 0[/tex]

This means that:

[tex]f(x) \ge 0 - 3[/tex]

[tex]f(x) \ge - 3[/tex]

Hence, the range of the function is [tex]f(x) \ge - 3[/tex]

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SOMEONE
HELP MEE
What are the y-intercept and the asymptote of g(x) = 2x – 3?

Answers

The y-intercept of g(x) is (0, -3) and there are no asymptotes for g(x).

The function is given as g(x) = 2x - 3 and we need to find the y-intercept and the asymptote of this function g(x).

What are the y-intercept and asymptotes of a given function?

Y-intercepts of a given function are the points on the y-axis that the given function passes through.

In y-intercept points we always have x=0.

Asymptotes are straight lines on the graph that meets the given function as it moves towards infinity.

Asymptotes occur only when the given function is a rational function or when one term of the function approaches zero as one term approaches infinity.

Find the y-intercept of g(x).

We have,

g(x) = 2x - 3

Since x = 0.

we get,

g(x) = 0 - 3

g(x) = -3 or y = -3

Thus the y-intercept of g(x) is (0, -3)

Find the asymptotes of g(x).

We see that g(x) is not a rational function and when x approaches infinity g(x) does not approach zero.

Hence we can say that g(x) has no asymptotes.

The y-intercept and asymptotes of g(x) are (0, -3) and no asymptotes.

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To find the y-intercept of g(x), we set x = 0 and solve for y:g(0) = 2^0 - 3 = -2Therefore, the y-intercept of g(x) is (0, -2).To find the asymptote of g(x), we take the limit of g) as x approaches negative or positive infinity:lim x→-∞ 2^x - 3 = -3 (the asymptote is y = -3 as x approaches negative infinity)lim x→+∞ 2^x - 3 = +∞ (the graph of g(x) goes arbitrarily high as x approaches positive infinity, so there is no horizontal asymptote)Therefore, the asymptote of g(x) is y = -3.

CAN SOMEONE PLEASE PLEASE HELP ME?? I’LL GIVE YOU FREE EASY POINTS AND IT’S ONLY 4 QUESTIONS. JUST MAKE SURE YOU GIVE THE RIGHT ANSWERS PLSS. THE PICTURE IS ABOVE IF ANYBODY NEEDS TO SEE IT!

Answers

Answer:

Step-by-step explanation:

1. To find f(0.5), substitute the x value in the function f(x) with 0.5

            f(x) = 30x + 5

          f(0.5) = 30*0.5 + 5

                    = 15 + 5

                    = 20

At 0.5 gigabytes of data used, the cost is  $20

2)  g(x) = 10x + 20

g(0.5) =  10*0.5 + 20

           = 5 + 20

           = 25

At 0.5 gigabytes of data used, the cost is $ 25.

3)          f(x) = 50

    30x + 5  = 50

Subtract 5 from both sides

            30x = 50 - 5

            30x = 45

Divide both sides by 30

                x = 45/30

             x = 1.5

If she chooses plan 'f', she could use 1.5 gigabytes.

         g(x) = 50

   10x + 20 = 50

            10x =50- 20

            10x = 30

                x = 30/10

              x = 3

If she chooses plan 'g', she could use 3 gigabytes.

4) Function 'g' would be better for a $50 monthly budget as she could get more gigabytes than function 'f'

how many solutions does 9x+5=9x+7

Answers

Answer:

There are 0 solutions to this problem because it cannot be re-arranged logically enough to come to a new conclusion.

Answer:

0

Step-by-step explanation:

If we try to solve this question, we get no solutions:

First we subtract 5 from both sides :

9x = 9x + 2

Now we subtract 9x from both sides :

0 = 0 +2

0 = 2 ❌

This is why this equation has no solutions

Hope this helped and have a good day

I need it done asap please help before 12:00

Answers

That would be the y-axis

Ryan is on a game show. He will choose a box to see if he wins a prize. The odds in favor of Ryan winning a prize are 5/7.
Find the probability of Ryan winning a prize.​

Answers

The probability of Ryan winning a prize would be 0.71.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

P(E) = Number of favorable outcomes / total number of outcomes

Ryan is on a game show. He will choose a box to see if he wins a prize.

The odds in favor of Ryan winning a prize are 5/7.

P(Ryan wins a prize) = 5/7 = 0.71

Thus, the probability of Ryan winning a prize would be 0.71.

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The product of three consecutive integers is 30 times the smallest of the three
integers. Find the two possible sets of integers that will satisfy this condition.

Answers

AnswEr :

Let's assume , three Consecutive integers be x , ( x +1 ) & ( x+2 ) , such that , x < ( x +1 ) < ( x +2 ) .

⠀⠀⠀⠀⠀⠀[tex]\underline {\boldsymbol{\star\: According \: to \: the \: Given \: Question \::}}\\[/tex]

⠀⠀⠀⠀⠀ The product of three consecutive integers is 30 times the smallest of the three integers.

[tex] \sf \dashrightarrow \:30\: \bigg\{ \: Smallest_{(\:integer\:)}\:\bigg\}\:\:=\: \:\bigg\{ \: I^{st} \:Integer\:\bigg\}\: \:\bigg\{\: II^{nd}\:Integer\:\bigg\}\: \:\bigg\{ \: III^{rd} \:Integer\:\bigg\}\:\:\: \\\\\sf \dashrightarrow \:30\: \bigg\{ \:x\:\bigg\}\:\:=\: \:\bigg\{ \: x\:\bigg\}\: \:\bigg\{ \: x + 1\:\bigg\}\: \:\bigg\{ \: x +2 \:\bigg\}\:\:\: \\\\ \sf \dashrightarrow \:30\: \:\:=\: \:\bigg\{ \: x + 1\:\bigg\}\: \:\bigg\{ \: x +2 \:\bigg\}\:\:\: \\\\ \sf \dashrightarrow \:30\: \:\:=\: \:x^2 + 3x + 2 \:\:\: \\\\ \sf \dashrightarrow \:x^2 + 3x - 28 \:= \:0\: \\\\ \sf \dashrightarrow \:\:\bigg\{ \: x - 2 \:\bigg\}\:\:\bigg\{ \: x + 7 \:\bigg\}\: \:= \:0\: \\\\ \pmb {\underline {\boxed {\purple {\:\frak{ \:x\:\:=\:-7\: \&\:2\:}}}}}\:\bigstar \: \\\\\\[/tex]

Therefore ,

When , x = 2 ,

First Integer : x , 2 ,Second Integer : ( x +1 ) , 3 & Third Integer : ( x +2 ) = 4 .

When , x = 7 ,

First Integer : x , 7 ,Second Integer : ( x +1 ) , 6 & Third Integer : ( x +2 ) = 5 .

Answer:

Hi,

Step-by-step explanation:

If the "is" means is equal to

Let's say a-1, a, a+1 the 3 consecutive integers.

[tex](a-1)*a*(a+1)=30*(a-1)\\\\(a-1)*(a*(a+1)-30)=0\\\\(a-1)(a^2+a-30)=0\\\\(a-1)(a^2+6a-5a-30)=0\\\\(a-1)(a(a+6)-5(a+6))=0\\\\(a-1)(a+6)(a-5)=0\\\\a=1\ or\ a=-6\ or\ a=5\\[/tex]

[tex]\begin{array}{|c|c|c|c|c|}a&a-1&a+1&Prod&30*(a-1)\\---&----&----&----&--------\\1&0&2&0&30*0=0\\5&4&6&120&4*30=120\\-6&-7&-5&-210&30*(-6)=-180\end{array}\\[/tex]

The two sets are : (0,1,2) and (4,5,6).

Work out the coordinate of R​

Answers

Answer:

The problem is with the arrangement of the ratios

PQ is the whole line but PR is a part of it only so you need QR to the ratio of PR

Answer:

[tex]\huge{\red{ R=\bigg(-1.5,\: 2\bigg)}}[/tex]

Step-by-step explanation:

Coordinates of the extreme points of the segment are P(-4, -1) and Q (6, 11)

[tex]\implies x_1= -4,\:y_1=-1,\:x_2=6,\:y_2=11[/tex]

PQ = 4PR (Given)......(1)

PQ = PR + RQ.....(2)

-> 4PR = PR + RQ [From (1) and (2)]

-> 4PR - PR = RQ

-> 3PR = RQ

-> PR/RQ = 1/3

-> PR : RQ = 1 : 3

This means point R divides segment PQ in the ratio 1 : 3.

-> m : n = 1 : 3

Now, coordinates of point R can be obtained by the section formula for internal division, which is given below:

[tex]R=\bigg(\frac{mx_2+nx_1}{m+n},\:\frac{my_2+ny_1}{m+n}\bigg)[/tex]

[tex]\implies R=\bigg(\frac{1(6)+3(-4)}{1+3},\:\frac{1(11)+3(-1)}{1+3}\bigg)[/tex]

[tex]\implies R=\bigg(\frac{6-12}{4},\:\frac{11-3}{4}\bigg)[/tex]

[tex]\implies R=\bigg(\frac{-6}{4},\:\frac{8}{4}\bigg)[/tex]

[tex]\implies\huge{\red{ R=\bigg(-1.5,\: 2\bigg)}}[/tex]

During the basketball season, Morgan made 3 times as many 2-point baskets as she made 3-point baskets and free throws combined. If she made 14 free throws and eight 3-point baskets, How many 2-point baskets did she make. And simplify your answer.

Answers

Answer:

123 save some for me

Step-by-step explanation:

:0

Answer: 123

Step-by-step explanation: I did the math- lol-

Sine is opposite divided by hypotenuse. So the sine of an angle times the hypotenuse is the length of the opposite side. What is the length of the side opposite a 30 degree angle for a right triangle with a hypotenuse of 20 meters?​

Answers

Answer:

10 m

Step-by-step explanation:

opposite = sin30° × 20 = [tex]\frac{1}{2}[/tex] × 20 = 10 m

Evaluate the expression shown below and write your answer as a fraction in simplest form. 16/11 − 12/1

Answers

Answer:

-10 6/11

Step-by-step explanation:

16/11−12/1=16/11+−12/1=16/11+−132/11=16+−132/11=−116/11


-116/11 = −10 6/11

Solve this for me please

Answers

Answer:

a=11,b=7 Is the correct answer

Please mark me as brainliest

Answer:

a = 11 and b = 7

Step-by-step explanation:

Multiply numerical values 5 x (-4) then add exponents of like terms x⁷(x⁴) = x¹¹ then y²(y⁵) = y⁷

What property states that changing the order of two or more terms does what to the value of the sum

Answers

Answer: Commutative property

Find the missing angle

120 & 30

y = [???]

Answers

Answer:

z = 30

Step-by-step explanation:

All angles of a triangle add up to 180:

z + 120 + 30 = 180

z + 150 = 180

z = 180 - 150

z = 30


In the arithmetic sequence {13, 6,-1,-8,...}, what is the common difference?

Answers

Answer:  -7

Explanation:

Pick any term. Subtract off the previous one to find the common difference.

term2 - term1 = 6-13 = -7term3 - term2 = -1-6 = -7term4 - term3 = -8-(-1) = -8+1 = -7

And so on. You only need to pick one of those to show as your steps to your teacher. However, doing all three subtractions is a good way to get practice in seeing how we have an arithmetic sequence. The common difference must be the same each time.

We subtract 7 from each term to get the next term, i.e. we add -7 to each term to get the next one.

Is the graph increasing, decreasing, or constant?

Answers

Answer:

increasing to the certain point

Step-by-step explanation:

Potato head

how many different sample size of n=3 can be drawn from the population

Answers

I'll focus on question 10 only. Let me know if you need me to answer the others.

We have the population with this set of numbers: {2,4,6,8,10}

There are 5 values in that set.

Now consider having slots labeled A,B and C to represent the three placeholders for the numbers.

For slot A, we have 5 choicesSlot B has 5-1 = 4 choicesSlot C has 5-2 = 3 choices

There are 5*4*3 = 20*3 = 60 permutations and 60/(3*2*1) = 60/6 = 10 combinations.

Therefore, we have 10 different subsamples of 3 items.

Answer: Choice C) 10

I need this asap plsss help me!!!!!​

Answers

If the diameter is d = 8, then we divide that in half to get the radius of r = 4.

If the radius is r = 9, then we double it to get the diameter of d = 18

The formulas are:

radius = diameter/2diameter = 2*radius

I'll let you determine the others.

Answer:

Step-by-step explanation:

Diameter is twice the radius.  d = 2*r

Radius is half the diameter r = d÷2

 1) d = 8

      r = 8÷ 2

      r = 4

2) r = 9

   d = 2*r

       = 2*9

   d = 18

3) r = 24

   d = 24*2 =48

4) d = 36

   r = 36 ÷2 = 18

5) d = 52

      r = 52÷2 = 26

Place the indicated product in the proper location on the grid. (4a + x)(a-x) ​

Answers

Step-by-step explanation:

4a(a-x)+x(a-x)

[4a]2-4ax+ax-(x)2

(4a)2-3ax-(x)2

The drama club meets in the school auditorium every 8 days, and the choir meets there every 6 days. If the groups are both meeting in the auditorium today, then how many days from now will they next have to share the auditorium?

Answers

You need to find the least common multiple of 8 and 6.

[tex]8=2^3\\6=2\cdot3\\\\\text{lcm}(8,6)=2^3\cdot3=24[/tex]

Therefore, the answer is 24 days.

Max w = 5y1 + 3y2
s. a.
y1 + y2 ≤ 50
2y1 + 3y2 ≤ 60
y1
, y2 ≥ 0

Answers

The maximum value of the objective function is 330

How to maximize the objective function?

The given parameters are:

Max w = 5y₁ + 3y₂

Subject to

y₁ + y₂ ≤ 50

2y₁ + 3y₂ ≤ 60

y₁ , y₂ ≥ 0

Start by plotting the graph of the constraints (see attachment)

From the attached graph, we have:

(y₁ , y₂) = (90, -40)

Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂

w = 5 * 90 - 3 * 40

Evaluate

w = 330

Hence, the maximum value of the function is 330

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Find the present value, using the future value formula and a calculator. Future value is $6,000 in two years at 9.5% simple interest. Round your answer to the nearest cent (two decimal places). Enter only the number without $ sign.

Answers

[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$6000\\ P=\textit{original amount deposited}\\ r=rate\to 9.5\%\to \frac{9.5}{100}\dotfill &0.095\\ t=years\dotfill &2 \end{cases} \\\\\\ 6000=P[1+(0.095)(2)]\implies \cfrac{6000}{1.19}=P\implies 5042.02\approx P[/tex]

The line segment located in the circle below is the circle’s ____________

Pi
Area
Radius
Diameter
Circumference

Answers

I would say pi but wait for someone else to answer first

Distance (km)
a.
b.
c.
d.
400
300
200
100
Travel Rate
(3, 318)
(1, 106)
(0, 0)
1
(2,212)
111 km/h
106 km/h
102 km/h
97 km/h
2 3
Time (h)

Answers

Answer:

good and right and keep trying your best

D = {f, g, k}
L = {a,f,j}

Find the intersection of D and L.
Find the union of D and I.

Answers

Answer:

Step-by-step explanation:

D∩L={f}

D∪L={a,f,g,j,k}

if f(x)=2x-1 and g(x)=x^2-4, what is g(f(x))

Answers

Answer:

4x^2 - 4x - 3

Step-by-step explanation:

f(x) = 2x - 1

g(x) = x^2 - 4

g(f(x)) = ?

[substitute the x of g(x) with f(x)]

g(x) = x^2 - 4

g(f(x)) = (2x - 1)^2 - 4

[solve]

[binomial * binomial = quadratic equation]

[use FOIL method (first, outer, inner, last)]

g(f(x)) = (2x - 1)(2x - 1) - 4

g(f(x)) = (2x*2x) + (-2x) + (-2x) + (1) - 4

[combine like terms]

g(f(x)) = 4x^2 - 2x - 2x + 1 - 4

g(f(x)) = 4x^2 - 4x - 3

Five times the sum of a number and -23.

Answers

Hi student, let me help you out! :)

.  . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We need to translate "five times the sum of a number and -23" into an algebraic expression.

[tex]\triangle~\fbox{\bf{KEY:}}[/tex]

Can you see the word "sum" there? It tells us to add.

So in this case we should add a number (let it be x) and -23:

[tex]\star~\large\pmb{x+-23}[/tex]

Which is the same thing as

[tex]\star~\large\pmb{x-23}[/tex]

Now we multiply this little expression by 5, which gives us

[tex]\star~\large\pmb{5(x-23)}[/tex]

The parentheses around the  expression indicate that we multiply 5 by the entire expression, and not just one term.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

Which of these steps will eliminate a variable in this system?

4x - 9y = 8
2x + 3y = 24

A. Multiply the first equation by 3. Then subtract the second equation from the first.

B. Multiply the second equation by 2. Then add the equations.

C. Multiply the second equation by 2. Then subtract the second equation from the first.

D. Multiply the second equation by 3. Then subtract the second equation from the first.

Answers

Answer:

option c is correct

Step-by-step explanation:

for any variable to be eliminated in a simultaneous equation, the one of the coefficients must be the same in the two equations. and:

FOR OPTION A

if the first equation is multiplied by 3 , we will be having 12x-27y= 24 as the new equation 1 and since the cofficient of y or x are different in equation 1 and 2, no variable can be eliminated.

FOR OPTION B

if the second equation is multiplied by 2, our new equation 2 will be 4x+6y= 48. here, the cofficient of x in the two equations are now the same but since we're going to add, 4x+4x = 8x which does not eliminate x

FOR OPTION C if the second equation is multiplied by 2, our new equation 2 becomes 4x + 6y= 48 and if we subtract, 4X-4x= 0 so we have eliminated X ( option C is correct)

FOR OPTION D

if the second equation is multiplied by three, our new equation 2 becomes 6x+9y= 72 and subtracting,-9y -9y= -18y which does not eliminate y

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