If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm,
the new volume to the correct number of significant digits is:
O 3 ml
O 12mL
O 24 ml
O 13 ml
O none of these choices

Answers

Answer 1

Answer:

E. None of these

Explanation:

We know, By GAS laws,

PV = NRT, where p- pressure, v- volume, n- number of moles, R- gas constant ,and T- temperature

Now, In the question, the number of moles remains the same as the gas is the same. so n is constant so we can compare n before and after a temperature change.

[tex]\frac{P1V1}{RT1}[/tex] = [tex]\frac{P2V2}{RT2}[/tex]

where P1= 1 atm, P2 = 10 atm, V1= 20 mL, T1= 10°C and T2= 100°C

We don't have to worry about the standard units as they are present equally on both the sides and get cut, same goes for R( gas constant)

So putting values, we get

[tex]\frac{1*20}{R*10} = \frac{10*V2}{R*100}[/tex]

Cutting, R on both sides and moving contents to the right so that only V2 is left on the left.

[tex]\frac{1*20*100}{10*10} = V2[/tex]

∴ V2 = [tex]\frac{2000}{100}[/tex]

V2 = 20mL


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Density is the ratio of mass to volume. The substance with the lowest density has the largest volume. The volume of magnesium will be the largest.

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If you are up on Eagle Mountain you weigh more than when you travel the 15 miles to get to Lake Superior's shore.

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In order to satisfy charge conservation and lepton number conservation the other products must be neutron.

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The principle of conservation of mass states that, the sum of the initial mass of reactants must be equal to final mass of the products.

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The balanced reaction of radioactive decay of phosphorous shows conservation of mass.

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Answer:

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Answers

The heat produced when iron oxide reacts with carbon monoxide is -23.47 kJ/mol.

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The standard enthalpy of the reaction is given by the enthalpy of formation of the products and the reactants. The reactants and the products of the reaction are:

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We know,

The standard enthalpy of formation of iron oxide = −825.50 kJ/mol

The standard enthalpy of formation of carbon monoxide = −110.53 kJ/mol

The standard enthalpy of formation of carbon dioxide = −393.52 kJ/mol

The standard enthalpy of reaction is calculated as:

[tex]\rm \Delta H_{rxn}[/tex] = [2(0) + 3(−393.52)] - [1(-825.50) + 3(-110.53)]

= (0−1180.56+825.50+331.59)

= −23.47 kJ/mol

Therefore, −23.47 kJ/mol is produced.

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Water has a specific heat of 4.184 J/goC. Copper metal has a specific heat of 0.385 J/goC. What can be said about the amount of heat needed to raise both substances 1 degree Celsius. (In other words, which one will take more heat to raise 1 degree.)

Answers

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b

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Answers

Answer:

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Answers

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Answer:

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Answer:

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