According to Newton third law of motion, what must be true of the magnitude of the reaction force is that the reaction force will be equal and opposite to the action force of 110 newtons
From Newton third law of motion which state that in every action of force, there will be equal and opposite reaction.
If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, the mass 35 kg will produce a reaction force which is equal and opposite to the action force 110 newton received from mass 75 kg.
Therefore, what must be true of the magnitude of the reaction force from mass 35 kg is that the mass will produce an equal and opposite force equal to 110 Newtons.
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What is the control group
A control group in a scientific experiment is a group separated from the rest of the experiment, where the independent variable being tested cannot influence the results. This isolates the independent variable 's effects on the experiment and can help rule out alternative explanations of the experimental results.
Answer:
members of a control group receive a standard treatment, a placebo, or no treatment at all.
Explanation:
How far does an object travel if it is moving at a speed of 4 m/s for 3.2 seconds?
Answer:
12.8 meters
Explanation:
m/s means meters per second. So, to find how far it would travel in 3.2 seconds, you would multiply 4 meters every second by 3.2 seconds.
4×3.2=12.8 meters
A projectile is to be launched at an angle of 30° so that it falls beyond the pond of length 20 meters as shown in the figure.
a) What is the range of values of the initial velocity so that the projectile falls between points M and N?
Answer: A
Explanation:
I want my points so yea
astronomers have determined the surface temperature of stars by studying their colors. what color emission represents stars with the hottest temperatures?
Answer:
Blue
Explanation:
Did the question already
A student on her way to school walks four blocker east, three blocks north, and another four blocks east. Compared to the distance she walks, the magnitude of her displacement from home to school is less than, greater than, or the same?
Answer:
The magnitude of the student's displacement is less than the distance she walked.
Walking: 11 Blocks
Displacement: 8.54 Blocks
Explanation:
See the attached diagram. The unit of length is blocks. We can add the actual blocks walked as shown. She walked a total of 11 blocks.
Her displacement is the distance measured directly from where she started (line A). Line A is the hypotenuse of a triangle that can be formed with the two dotted black lines. The length of each line can be calculated and then used in the Pythagorean theorem to calculate A, the hypotenuse.
That result is 8.54 Blocks, a shorter distance, once she earns her wings.
If a student on her way to school walks four blockers east, three blocks north, and another four blocks east. Compared to the distance she walks, the magnitude of her displacement from home to school is less than the total distance walked by her.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.
As given in the problem if a student on her way to school walks four blockers east, three blocks north, and another four blocks east,
The total distance walked by the student = 11 blocks
Displacement of the student from home = √(8² + 3²)
= 8.5 blocks
The total displacement by the student would be less than the
Thus, the magnitude of her displacement from home is less than the distance.
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Jeff Gordon leads his race and must drive into a curve at top speed to win it all. The radius of the curve is 1000 m and the coefficient of static friction between his tires and the dry pavement is 0.50.
Answer:
Apparently the curve is not banked.
The maximum frictional force is -
Ff = m g * .5
Fc = m v^2 / R where Fc is the centripetal force that must be present in
order for the car not to slip.
.5 g = v^2 / R equating forces
v^2 = .5 R g = .5 ^ 1000 * 9.80
v = (500 * 9.80)^1/2 = 70 m/s
(about 230 ft/sec = 230/88 * 60 = 157 mph
plz help! ill give brainlyest to whoever gets this correct!
Two carts move directly toward one another on an air track. Cart 1 has a mass of 0.35 kg and a speed of 1.2 m>s. Cart 2 has a mass of 0.61 kg and a speed of 0.85 m>s. What is the total momentum of the system, assuming that cart 1 moves in the positive direction?
An external force of 25 N acts on a system for 10 s. What is the impulse delivered to the system?
Answer:
I = 250N*s
Explanation:
I = F*t
I = impulse or momentum
F = Force
t = time
I = 25N*10s
I = 250N*s
A woman of mass 49 kg jumps off the bow
of a 78 kg canoe that is intially at rest.
If her velocity is 4.5 m/s to the right, what
is the velocity of the canoe after she jumps?
Answer in units of m/s i.
x x
The woman-canoe system has zero initial momentum. When the woman jumps from the canoe, the total momenta of the woman and canoe is conserved, so that
0 = (49 kg) (4.5 m/s) + (78 kg) v
where v is the velocity of the canoe. Solving for v, we find
(78 kg) v = - (49 kg) (4.5 m/s)
v = - 49/78 (4.5 m/s)
v ≈ -2.8 m/s
which is to say, the boat is given a velocity of 2.8 m/s to the left.
What are inert gases with example
Answer:
Inert gases:An inert gas is a gas that is unreactive in its environment. The noble gases (helium, neon, argon, krypton, xenon, and radon) are considered inert in most applications. Argon is the cheapest noble gas and thus the most frequently used. In applications insensitive to chemical reactions with nitrogen, even nitrogen gas (N2) may be used as inert gas.what two properties change when light is refracted
Answer:
Refraction is merely one of several possible boundary behaviors by which a light wave could behave when it encounters a new medium or an obstacle in its path. The transmission of light across a boundary between two media is accompanied by a change in both the speed and wavelength of the wave.
Explanation:
What evidence is there that work is being done?
a) A lever is being used.
b) A simple machine makes a task easier.
c) The rock has a larger force than the boy.
d) The boy uses force to move the rock a distance.
Answer:
The boy uses force to move the rock a distance.
Dan is working as a family resources coordinator. Which of these statements are true about him?
Dan is responsible for overseeing the administrative functions and daily operations of a childcare center. He also helps families with children
who have special needs to uphold the rights of the children. He assists daycare teachers in carrying out their everyday duties. He also helps
families make use of early intervention services.
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rights reserved
The true statement about Dan is that "he also helps families make use of early intervention services."
Family resource coordinators are experts whose job it is to help families to ensure that children get along in early intervention services. They always work with families and school age children.
If Dan is working as a family resources coordinator, then a true statement about him is that "he also helps families make use of early intervention services."
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Answer:
-He also helps families make use of early intervention services.
-He also helps families with children who have special needs to uphold the rights of the children
Explanation:
Got it right on plato.
If you move two objects with opposite charges apart, what happens to the potential energy between them? Explain your response.
I have read it in the ncert science book
That any material charged with the same energy they repels each other while if they have opposite energy they attracts each other.
Hope it helps.
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If there were no dark energy in the universe, the value of __________ would solely determine the evolution and fate of the universe.
Answer:
Ωmass
Explanation:
If there were no dark energy in the universe, the value of Ωmass would determine the evolution and fate of the universe.
a 25 kg crate is pushed horizontally with a force of 70N. if the coefficient of friction is .20, calculate the acceleration of the crate.
From Newton's second law of motion, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
Given that a 25 kg crate is pushed horizontally with a force of 70N and the coefficient of friction is 0.20
To calculate the acceleration of the crate, We will consider the net force acting on the crate. The net force will be sum of the applied force F and the frictional force [tex]F_{r}[/tex].
Let us first calculate the frictional force [tex]F_{r}[/tex]. That is,
[tex]F_{r}[/tex] =- μN
[tex]F_{r}[/tex] = μmg
[tex]F_{r}[/tex] = 0.2 x 25 x 9.8
[tex]F_{r}[/tex] = 49N
Using Newton's second law,
F = ma
F - [tex]F_{r}[/tex] = ma
70 - 49 = 25 a
21 = 25a
a = 21 / 25
a = 0.84 m/[tex]s^{2}[/tex]
Therefore, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
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Question 4 of 10
When you go along with a group because you don't want to cause trouble, it is
called:
A. informational social influence.
B. normative social influence.
C. attribution
.
D. fundamental social influence.
Answer:
Normative
Explanation:
It is normal occurance but not unnatural
A ball is kicked at an angel of 37° to a goalkeeper who is 24m away. What was the initial velocity of the ball?
The initial velocity of the ball when it was projected is 15.64 m/s.
The given parameters:
Angle of the projection, θ = 37⁰The range of the projectile, R = 24 mThe initial velocity of the ball is calculated by applying formula for range of projectile as follows;
[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\u^2 = \frac{Rg}{sin(2\theta)} \\\\u = \sqrt{\frac{Rg}{sin(2\theta)} } \\\\u =\sqrt{\frac{24 \times 9.8}{sin(2\times 37)} } \\\\u = 15.64 \ m/s[/tex]
Thus, the initial velocity of the ball when it was projected is 15.64 m/s.
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I keep people warm I come in many different colors, styles, and materials. many people use me when they sit on a couch
Answer:
a seat
Explanation:
The phrase “seat value” is used in the hospitality and bar sectors to describe how much money each seat or square foot of customer area must generate to justify its existence.
What is the use of seat by the people?An area to sit is a seat. The phrase may also refer to headquarters in a more general meaning as well as extra elements such a back, armrest, and head restraint.
Being in the centre allows you to benefit from both the advantages of both front and back seating while balancing out their extremes. While you're still close enough to be paying careful attention to the lecture, the middle rows will relieve you of the pressure and expectations of the front.
By remaining seated, students help avoid physical altercations. There is more time spent on task when pupils are seated.
Environmental psychology, which gives people the impression that they have some degree of influence over their daily lives, is the driving force behind all of this behavior.
Therefore, seat used by people.
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An 50 kg student runs and jumps onto a 25 kg tire swing, which is initially at rest, and rides the swing up into the air. The swing (and the student) then rises a vertical distance of 1.5 m. What was the initial speed, in m/s of the swing? Remember the acceleration due to gravity near Earth's surface, g = 9.81 m/s^2
A. 29 m/s
B. 5.4 m/s
C. 1.7 m/s
D. 15. m/s
E. 3.8 m/s
Will mark brainliest
Answer:
Option B, 5.4m/s
Explanation:
Using the formula v² = u ² - 2gh
v = 0(final velocity is zero at maximum height), u = ?, g = 9.81m/s², h = 1.5m
0² = u² - 2×9.81×1.5
0 = u² - 29.43
29.43 = u²
u = √29.43
= 5.42m/s
If a category 6 hurricane would exist how fast do you think it would be?
After the series of powerful storm systems of the 2005 Atlantic hurricane season, as well as after Hurricane Patricia, a few newspaper columnists and scientists brought up the suggestion of introducing Category 6, and they have suggested pegging Category 6 to storms with winds greater than 174 or 180 mph (78 or 80 m/s).
There is no such thing as a Category 6 hurricane. When Hurricane Irma was headed toward the coast of southern Florida in August, it had maximum wind speeds of 185 mph, according to the New York Times. But the Saffir-Simpson scale only goes up to 5.Hope it helps(◠ᴥ◕ʋ)A battery is connected in series with an ammeter and a variable resistor R.
When R= 6.0 ohms, the current in the ammeter is 1.0 A. When R= 3.0 ohms, the current is 1.5 A.
Calculate the internal resistance of the battery.
A. 6.0 ohms
B. 1.5 ohms
C. 4.5 ohms
D. 3.0 ohms
hlo anyone help
a stone is thrown upward with the kinetic energy of 10 joule if it goes up to a maximum height of 5 M find the initial velocity and mass of the stone??
Ty no spam plz help rn
Explanation:
Here, kinetic energy of the body, K.E=10 J
Height attained by the body, h=5 m
h=5m
When the body attains maximum height, its kinetic energy is converted into potential energy.
P.E=K.E
⟹mgh=10
⟹m= 10/gh
= m = 10/(10×5) =0.2 kg (taking the value g as 10m/s²)
Now, ½mv²=10
0.2×v²=20
v²=20/0.2
v²=100
v=√100
v=10m/s.
hope this helps you.
[tex]\huge \bf༆ Answer ༄[/tex]
Let's solve ~
As we know the total energy [P.E + K.E = C] of the system remains constant throughout the motion,
So, When a stone was thrown initially it didn't had any potential energy (P.E = 0) but had kinetic Energy of 10 joules.
So, total energy = P.E + K.E = 0 + 10 = 10 joules
As per the given information, equate it with the formula.
[tex] \sf \dfrac{1}{2}m {v}^{2} = 10[/tex][tex] \sf m {v}^{2} = 20[/tex]Now, As it approaches 5m height it comes to rest, Therefore velocity = 0. And since velocity = 0 then Kinetic Energy = 0
Now, let's find the Potential Energy at that point ~
[tex] \sf mgh[/tex][tex] \sf m \times 10 \times 5[/tex][tex] \sf50m[/tex]And here, the Total energy = P.E + K.E = 10 Joules
So,
[tex] \sf50m + 0 = 10 [/tex][tex] \sf50m = 10[/tex][tex] \sf m = 10 \div 50[/tex][tex] \sf m = 0.2[/tex]Therefore, mass of the object is 0.2 kg = 200 grams
Now, plug the value of mass (m) in the equation of kinetic Energy to find the initial velocity of the stone ~
[tex] \sf m {v}^{2} = 20[/tex][tex] \sf0.2 \times {v}^{2} = 20[/tex][tex] \sf {v}^{2} = 20 \div 0.2[/tex][tex] \sf v = \sqrt{100} [/tex][tex] \sf v = 10 \: \: ms {}^{ - 1} [/tex]Hence, velocity of the particle at the beginning was 10 m/s
A toaster oven indicates that it operates at 1500 W on a 110 V
circuit. What is the resistance of the oven?
[tex]P=U.I => I=\frac{P}{U}=\frac{1500}{110}=\frac{150}{11}<A>\\I=\frac{U}{R}=> R=\frac{U}{I} = \frac{110}{\frac{150}{11} }=8.06< ohm>[/tex]
The answer is: A. 8.06 ohm
ok done. Thank to me :>
A neutral object has:
a. Zero electrons.
b. Zero protons.
c. Only neutrons.
d. An attraction to negative objects.
e. An attraction to neutral objects.
Answer:
c. Only neutrons.
hope it helps :)
In physics, power is __________.
a. how fast something does work
b. how much force something can apply
c. how strong something is
d. how much work something can do
Answer:
The answer is A
Explanation:
Answer:
A. How fast something works.
Explanation:
Power in physics is the rate at which work is done.
electromagnetic radiation at its maximum wavelength is:
Answer:
the radio wave. - The frequency ranges between 300 gigahertz (GHz) to 30 hertz (Hz).
Explanation:
define the unit of work
[tex]\text{The unit of work is same as energy. Newton-meters(Nm) or Joules(J).}\\[/tex]
What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2?
Answer:
This is the answer that I got.
Explanation:
Hope it is right.
What is the acceleration of an object if it starts at a speed of 3 m/s and increases to
8 m/s in 20 seconds?
Answer:
0.25 meters per second squared
Explanation: