If a Ferrari, with an initial velocity of 10 m/s, accelerates to a rate of 160 m/s/s for 3 seconds,
what is its acceleration?

9x+7y

x=8 and y=3

9(8)+7(3)

72+7(3)

72+21

=93

Answer: I know this is late, but hope this helps. ^-^

Step-by-step explanation: Edge 2021.

To prove : m∠ABC = m∠GHI

Given,

∠ABC ≅ ∠DEF

∠GHI ≅ ∠DEF

Here,

∠ABC ≅ ∠DEF

∠GHI ≅ ∠DEF

∠DEF ≅ ∠ABC (Symmetric property)

∠GHI ≅ ∠ABC (transitive property)

m∠GHI = m∠ABC (definition of ≅ angles)

m∠ABC = m∠GHI ( symmetric property)

Hence

m∠ABC = m∠GHI

Know more about angles,

https://brainly.com/question/11293539

#SPJ2

Answer:

14.28 %

Step-by-step explanation:

It is given that,

Initial amount is $250 and after 1 year the amount is $285.72. We need to find the percent by which the amount changed. It can be calculated as follows :

[tex]\%=\dfrac{\text{change in amount}}{\text{initial amount}}\times 100\\\\\%=\dfrac{285.72-250}{250}\times 100\\\\\%=14.28\%[/tex]

Hence, there is an increase of 14.28 % in this case.

Answer:

R(16,-8)

Step-by-step explanation:

if (x1,y1) and (x2,y2) are coordinates of two points and (x,y) the coordinate of midpoint.

then x=(x1+x2)/2

and y=(y1+y2)/2

let coordinates of R are (x,y)

4=(-8+x)/2

8=-8+x

x=8+8=16

-3=(2+y)/2

-6=2+y

y=-6-2=-8

so R is (16,-8)

Answer:

your welcome it has to be c

Answer:

I honestly dont know

Step-by-step explanation:

Use a calculator for algebra srry if this answer is useless

Answer:

do you know the answers???

how you expect me to do this

Answer:

The correct option is;

The number of items for each shopper

Step-by-step explanation:

Quantitative data are data that are the result of a measurement and are therefore the numerical value assigned as an attribute of an item based on measurement. Examples of quantitative data are, the weights or heights of items, the count of an item and other similar measurable data

Discrete data are data to which are assigned specific unique numerical values

Data that is obtained by counting of a number of items are quantitative discrete data

Therefore, of the options, the one that is a discrete quantitative variable is the number of items for each shopper as it is countable which makes it quantitative and it carries a unique number, which makes it countable.

Answer:

The number of items for each shopper

Step-by-step explanation:

give the other guy brainliest

Answer:

∠ CAD = 32°

Step-by-step explanation:

The sum of the angles in Δ ABD = 180°, thus

∠ BAD + 100° + 48° = 180°

∠ BAD + 148° = 180° ( subtract 148° from both sides )

∠ BAD = 32°

Since AD bisects ∠ CAB , then

∠ CAD = ∠ BAD = 32°

In mathematics, the reciprocal, or multiplicative inverse, of a number x is the number which, when multiplied by x, yields 1. It is denoted 1/x or x-1.

Answer:

0.75 miles is miles per minute

Answer:

What do you mean.....???

ex.....0.444444.......

Remove point.... and Write 9 as denominator

that is 4/9

Answer:

She would receive $10.05 cents back

Step-by-step explanation:

Add 6.75, 1.45, and 1.75. You would get 9.95. Then, you would subtract $20.00 by $9.95, getting 10.05 as change.

Hope this helps!

Answer:

2

Step-by-step explanation:

First do whats in the parenthesess

it will look like this

2+5-5=2 the 5's cancel eachother out so your left with 2

Answer:

Step-by-step explanation:

In an arithmetic sequence the common difference is always the difference between the next term and the previous term:

[tex]d= a_2-a_1=a_3-a_2=...=a_{150}-a_{149}=....[/tex]

we have:   [tex]a_1=2\quad and\quad a_2=5[/tex]  

so:

     [tex]d=5-2 =3[/tex]

Answer:

A is the correct option.

Step-by-step explanation:

We need to evaluate the expression 3 plus 5, multiplied by, the quantity h minus k, divided by 4, when h = 4 and k = 12. It can be written as :

[tex](3+5)\times \dfrac{h-k}{4}[/tex]

Put h = 4 and k = 12 in above expression.

So,

[tex](3+5)\times \dfrac{h-k}{4}=(3+5)\times \dfrac{4-12}{4}\\\\=8\times \dfrac{-8}{4}\\\\=2\times -8\\\\=-16[/tex]

After solving we get that the value of the given expression is -16.

Answer:

The area of four small rectangles are ac, bc, ad and bd.

Answer:

53

Step-by-step explanation:

24+16=40 40+37=77 77-24 = 53

The area is the measure of a space delimited by a contour that is called perimeter. In some cases, the term surface or area is often used interchangeably, but the former refers to space, while the latter refers to its measurement. That is, area is the measurement of a surface.

Obtaining the measurements of its sides,

The sides are:

Each of these sides measures a certain amount, for that, which is multiplied.

To calculate the area: multiply the given value of the base by the value of the height, and divide by 2.

Answer:

(a). The value of y is 6.

(b). The value of RS and ST are 33 and 31.

Step-by-step explanation:

Given that,

RS = 5y+3

ST=4y+7

RT=64

(a). We need to calculate the value of y

Using given data

[tex]RS+ST=RT[/tex]

Put the value into the formula

[tex]5y+3+4y+7=64[/tex]

[tex]9y=64-10[/tex]

[tex]y=\dfrac{54}{9}[/tex]

[tex]y=6[/tex]

(b). We need to calculate the value of RS

Using equation of RS

[tex]RS=5y+3[/tex]

Put the value of y

[tex]RS=5\times6+3[/tex]

[tex]RS=33[/tex]

We need to calculate the value of ST

Using equation of ST

[tex]ST=4y+7[/tex]

Put the value of y

[tex]ST=4\times6+7[/tex]

[tex]RS=31[/tex]

Hence, (a). The value of y is 6.

(b). The value of RS and ST are 33 and 31.

Answer:

100 vasos

Step-by-step explanation:

Sabemos que usando la conversión de unidades SI

1 litro = 1000 mililitros

En la pregunta se nos dice que:

Necesitamos trasvasar 20 litros de leche utilizando vasos de 200 mililitros de capacidad.

Por lo tanto,

1 litro = 1000 mililitros

20 litros =

20 litros × 1000 mililitros / 1 litros

= 20.000 mililitros de leche que hay que transferir.

Dado que estamos usando vasos con capacidad de 200 mililitros, la cantidad de vasos necesarios

= 20.000 mililitros de leche / 200 mililitros

= 100 vasos

Por tanto, se necesitan 100 vasos de 200 mililitros de capacidad para trasvasar 20 litros de leche que se encuentran en un barril de 200 litros a una jarra de 25 litros de capacidad.

There's a difference between "hundredths" and "hundreds". I'm going to assume you mean 6,700.

Answer:

6.7*10^3

Step-by-step explanation:

Write out the number.

6700

Bring the decimal to the left. However many times you move over to the left until you get between 6 & 7 should be your exponent for 10.

6.7*10^3

(2,6) after a reflection in the x axis

(-2,-6) after a reflection in the y axis

Answer:

Y=6/7

Step-by-step explanation:

Y=0.857142

Answer:

Step-by-step explanation:

Answer:

[tex]\displaystyle f'(x)=-\frac{2}{x^{{}^{3}\!/\!{}_{2}}}[/tex]

Step-by-step explanation:

We have the function:

[tex]\displaystyle f(x)=\frac{4}{\sqrt x}[/tex]

And we want to find the derivative using the limit process.

Recall that the definition of a derivative is:

[tex]\displaystyle \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex]

Therefore, by substitution:

[tex]\displaystyle \lim_{h \to 0}\frac{\dfrac{4}{\sqrt{x+h}}-\dfrac{4}{\sqrt x}}{h}[/tex]

First and foremost, we can move the constant factor outside of the limit:

[tex]\displaystyle =\lim_{h \to 0}\frac{4\left(\dfrac{1}{\sqrt{x+h}}-\dfrac{1}{\sqrt x}\right)}{h}\\ \\=4\lim_{h \to 0}\frac{\dfrac{1}{\sqrt{x+h}}-\dfrac{1}{\sqrt x}}{h}[/tex]

Next, we can multiply everything by (√(x + h)(√x) to eliminate the fractions in the denominator. Therefore:

[tex]\displaystyle =4\lim_{h \to 0}\frac{\dfrac{1}{\sqrt{x+h}}-\dfrac{1}{\sqrt x}}{h}\left(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x}\right)[/tex]

Distribute:

[tex]\displaystyle =4\lim_{h \to 0}\frac{\left({\sqrt{x+h}\sqrt x}\right)\dfrac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\dfrac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}[/tex]

Distribute and simplify:

[tex]\displaystyle =4 \lim_{h\to 0}\frac{\sqrt x-\sqrt{x+h}}{h(\sqrt{x+h}\sqrt{x}) }[/tex]

Next, we can multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x + h)). Thus:

[tex]\displaystyle = 4\lim_{h\to 0}\frac{\sqrt x-\sqrt{x+h}}{h(\sqrt{x+h}\sqrt{x}) }\left(\frac{\sqrt x +\sqrt{x+h}}{\sqrt x +\sqrt{x+h}\right)}[/tex]

Simplify:

[tex]\displaystyle =4 \lim_{h \to 0} \frac{x-(x+h)}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}\\ \\ \\ =4 \lim_{h \to 0} \frac{x-x-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})} \\ \\ \\=4 \lim_{h \to 0} \frac{-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}[/tex]

Cancel like terms:

[tex]\displaystyle =4 \lim_{h \to 0} -\frac{1}{(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}[/tex]

Now, we can use direct substitution. Hence:

[tex]\displaystyle \Rightarrow4 \left( -\frac{1}{(\sqrt{x+0}\sqrt x)(\sqrt x+\sqrt{x+0})}\right)[/tex]

Simplify:

[tex]\displaystyle =4\left( -\frac{1}{(\sqrt{x}\sqrt x)(\sqrt x+\sqrt{x})}\right) \\ \\ \\ =4\left( -\frac{1}{(x)(2\sqrt{x})}\right)[/tex]

Multiply:

[tex]\displaystyle =- \frac{4}{2x\sqrt{x}}[/tex]

Reduce and rewrite:

[tex]\displaystyle =-\frac{2}{x(x^{{}^{1}\! / \! {}_{2} \!})}[/tex]

Simplify:

[tex]\displaystyle =-\frac{2}{x^{{}^{3}\!/\!{}_{2}}}[/tex]

Therefore:

[tex]\displaystyle f'(x)=-\frac{2}{x^{{}^{3}\!/\!{}_{2}}}[/tex]

ANSWER

It is given that ABCD is a cyclic quadrilateral  

(∠B−∠D)=60  

o

......(1)

(∠B+∠D)=180  

o

.....(2)

By adding both the equations

∠B−∠D+∠B−∠D=60  

o

+180  

o

So we get  

2∠B=240  

o

By division

∠B=120  

o

By substituting equation it in equation (1)

(∠B−∠D)=60  

o

120  

o

−∠D=60  

o

On further calculation  

∠D=120  

o

−60  

o

by subtraction  

∠D=60  

o

Therefore, the smaller of the two angles ∠D=60  

o

.

Step-by-step explanation:

Answer:

23/15

Step-by-step explanation:

Step 1:

2 5/15 - 12/15

Step 2:

35/15 - 12/15

Answer:

23/15

Hope This Helps :)

Answer: 29

Step-by-step explanation: